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  • OpenSL ES decode 24bit FLAC

    - by yano
    I am trying to decode a FLAC file with 24bit sample format using OpenSL ES on Android. Originally, I had my SLDataFormat_PCM for the SLDataSink setup like this. _pcm.formatType = SL_DATAFORMAT_PCM; _pcm.numChannels = 2; _pcm.samplesPerSec = SL_SAMPLINGRATE_44_1; _pcm.bitsPerSample = SL_PCMSAMPLEFORMAT_FIXED_16; _pcm.containerSize = SL_PCMSAMPLEFORMAT_FIXED_16; _pcm.channelMask = SL_SPEAKER_FRONT_LEFT | SL_SPEAKER_FRONT_RIGHT; _pcm.endianness = SL_BYTEORDER_LITTLEENDIAN; This is working well for basically any data format. Luckily the samplesPerSec is not respected (I don't want resampling). Now I want to support the full bit-depth of a FLAC file with 24bit samples. When using this format, it apparently performs a bit-depth conversion, because once I load the file, and then check the ANDROID_KEY_PCMFORMAT_BITSPERSAMPLE info, it is 16. When I put bitsPerSample = SL_PCMSAMPLEFORMAT_FIXED_24; or SL_PCMSAMPLEFORMAT_FIXED_32, then OpenSL ES rejects it E/libOpenSLES(22706): pAudioSnk: bitsPerSample=32 W/libOpenSLES(22706): Leaving Engine::CreateAudioPlayer (SL_RESULT_CONTENT_UNSUPPORTED) Any idea how this is meant to work? Is Android currently restricted to 16 bit int only? I would also accept 32bit float, but I don't suppose that will work either.

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  • Are there any configurable parameters to the gpsd?

    - by danatel
    I use the gpsd daemon with my application. Sometimes, the gpsd ceases to work with no apparent reason (clean sky). Even the gpsmon monitor shows no fix. Are there any parameters which must be set? Or is it a hardware problem? I am surprissed that many satellites are visible but the "Stat" bitmap does not contain the bit 7 - ephemeris data available. Should i somewhat pre-configure my position to allow for correct ephemeris data? Here is my gpsmon screen: 127.0.0.1:2947:/dev/ttyS3 SiRF binary> ^[[4~ -¦¦¦¦¦¦¦¦¦¦¦ X ¦¦¦¦¦¦ Y ¦¦¦¦¦¦ Z ¦¦¦¦¦¦¦¦¦¦ North ¦¦¦¦ East ¦¦¦¦¦ Alt ¦¦¦¦¦¦¦¦¦¬ -Pos: 3949260 1166016 4856299 m 49.89411° 16.44920° 1379 m - -Vel: 0.0 0.0 0.0 m/s 0.0 0.0 0.0 climb m/s- -Week+TOW:1578+224837.06 Day: 2 14:27:17.06 Heading: 0.0° 0.0 speed m/s- -Skew: -13.025817 TZ: -7200 HDOP: 0.0 M1:00 M2: 00 - -Fix: 0 = - L¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦ Packet type 2 (0x02) ¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦- -¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¬-¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¬ -Ch PRN Az El Stat C/N ? A --Version: - - 0 2 243 19 003f 40.4 -L¦¦¦¦¦¦¦ Packet Type 6 (0x06) ¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦- - 1 10 249 68 003f 43.0 --¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¬ - 2 13 90 30 003f 40.9 --SVs: 0 Drift: 96506 Bias: 135976716 - - 3 7 66 67 003f 39.8 --Estimated GPS Time: 224837059 - - 4 5 295 49 003d 39.7 -L¦¦¦¦¦¦¦ Packet type 7 (0x07) ¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦- - 5 8 210 69 003f 41.0 --¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¬ - 6 23 96 5 002d 28.0 --Max: 167.570Lat: 132.129Time: 0.075 MS: 02 - - 7 6 43 3 002d 23.1 -L¦¦¦¦¦¦¦ Packet type 9 (0x09) ¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦- - 8 28 163 16 003f 39.8 --¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¬ - 9 0 0 0 0000 0.0 --SVs: 11 = 8 10 7 5 13 2 28 23 3 6 4 - -10 3 55 4 002d 24.7 -L¦¦¦¦¦¦¦ Packet type 13 (0x0D) ¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦- -11 0 0 0 0000 0.0 --¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¬ L¦¦¦ Packet Type 4 (0x04) ¦¦¦--DGPS source: 1 (SBAS) Corrections: 12 - L¦¦¦¦¦¦¦ Packet type 27 (0x1B) ¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦-q

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  • Filling a byte array in Java

    - by Corleone
    Hey all! For part of a project I'm working on I am implementing a RTPpacket where I have to fill the header array of byte with RTP header fields. //size of the RTP header: static int HEADER_SIZE = 12; // bytes //Fields that compose the RTP header public int Version; // 2 bits public int Padding; // 1 bit public int Extension; // 1 bit public int CC; // 4 bits public int Marker; // 1 bit public int PayloadType; // 7 bits public int SequenceNumber; // 16 bits public int TimeStamp; // 32 bits public int Ssrc; // 32 bits //Bitstream of the RTP header public byte[] header = new byte[ HEADER_SIZE ]; This was my approach: /* * bits 0-1: Version * bit 2: Padding * bit 3: Extension * bits 4-7: CC */ header[0] = new Integer( (Version << 6)|(Padding << 5)|(Extension << 6)|CC ).byteValue(); /* * bit 0: Marker * bits 1-7: PayloadType */ header[1] = new Integer( (Marker << 7)|PayloadType ).byteValue(); /* SequenceNumber takes 2 bytes = 16 bits */ header[2] = new Integer( SequenceNumber >> 8 ).byteValue(); header[3] = new Integer( SequenceNumber ).byteValue(); /* TimeStamp takes 4 bytes = 32 bits */ for ( int i = 0; i < 4; i++ ) header[7-i] = new Integer( TimeStamp >> (8*i) ).byteValue(); /* Ssrc takes 4 bytes = 32 bits */ for ( int i = 0; i < 4; i++ ) header[11-i] = new Integer( Ssrc >> (8*i) ).byteValue(); Any other, maybe 'better' ways to do this?

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  • How does an NSTextField know that it's value has changed?

    - by Brian Postow
    I have a textfield that can either be edited by hand, or set through another control. (It's a page number, so you can jump to page 16 by typing in 16, or you can page up and down with the next/prev buttons) I have the value of the text field bound to an int page variable. It seems to work correctly, when you type a page number in, it jumps, when you page up and down, the page number in the text box changes appropriately. However, at some level, when I page up and down, the text box doesn't seem to know that it's value has changed, because if I type 1 it doesn't do anything. It doesn't call the bound set-method or anything. It looks like the textfield is thinking "I'm already 1, so I don't need to do anything." Even though it was 5 because I hit next 4 times. If I type an number other than 1, it goes there. If I THEN type 1, it goes to page 1, because now it thinks it's on that other page. The problem seems to be that I'm changing the value of the textfield programatically, but some part isn't getting the message. Does this seem like a reasonable explanation? And either way, any ideas on what's causing it? thanks

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  • Trouble with applying a nested loop on a list

    - by user1665355
    I have a list consisting of 3 elements: datalist=list(a=datanew1,b=datanew2,c=datanew3) datalist$a : Inv_ret Firm size leverage Risk Liquidity Equity 17 0.04555968 17.34834 0.1323199 0.011292273 0.02471489 0 48 0.01405835 15.86315 0.6931730 0.002491093 0.12054914 0 109 0.04556252 16.91602 0.1714068 0.006235836 0.01194579 0 159 0.04753472 14.77039 0.3885720 0.007126830 0.06373028 0 301 0.03941040 16.94377 0.1805346 0.005450653 0.01723319 0 datalist$b : Inv_ret Firm size leverage Risk Liquidity Equity 31 0.04020832 18.13300 0.09326265 0.015235240 0.01579559 0.005025379 62 0.04439078 17.84086 0.11016402 0.005486982 0.01266566 0.006559096 123 0.04543250 18.00517 0.12215307 0.011154742 0.01531451 0.002282790 173 0.03960613 16.45457 0.10828643 0.011506857 0.02385191 0.009003780 180 0.03139643 17.57671 0.40063094 0.003447233 0.04530395 0.000000000 datalist$c : Inv_ret Firm size leverage Risk Liquidity Equity 92 0.03081029 19.25359 0.10513159 0.01635201 0.025760806 0.000119744 153 0.03280746 19.90229 0.11731517 0.01443786 0.006769735 0.011999005 210 0.04655847 20.12543 0.11622403 0.01418010 0.003125632 0.003802365 250 0.03301018 20.67197 0.13208234 0.01262499 0.009418828 0.021400052 282 0.04355975 20.03012 0.08588316 0.01918129 0.004213846 0.023657440 I am trying to create a cor.test on the datalist above : Cor.tests=sapply(datalist,function(x){ for(h in 1:length(names(x))){ for(i in 1:length(names(x$h[i]))){ for(j in 1:length(names(x$h[j]))){ cor.test(x$h[,i],x$h[,j])$p.value }}}}) But I get an error : Error in cor.test.default(x$h[, i], x$h[, j]) : 'x' must be a numeric vector Any suggestions about what I am doing wrong? P.S. If I simply have one dataframe, datanew1 : Inv_ret Firm size leverage Risk Liquidity Equity 17 0.04555968 17.34834 0.1323199 0.011292273 0.02471489 0 48 0.01405835 15.86315 0.6931730 0.002491093 0.12054914 0 109 0.04556252 16.91602 0.1714068 0.006235836 0.01194579 0 159 0.04753472 14.77039 0.3885720 0.007126830 0.06373028 0 301 0.03941040 16.94377 0.1805346 0.005450653 0.01723319 0 I use this loop : results=matrix(NA,nrow=6,ncol=6) for(i in 1:length(names(datanew1))){ for(j in 1:length(names(datanew1))){ results[i,j]<-cor.test(datanew1[,i],datanew1[,j])$p.value }} And the output is: results : [,1] [,2] [,3] [,4] [,5] [,6] [1,] 0.000000e+00 7.085663e-09 3.128975e-10 3.018239e-02 4.806400e-10 0.475139526 [2,] 7.085663e-09 0.000000e+00 2.141581e-21 0.000000e+00 2.247825e-20 0.454032499 [3,] 3.128975e-10 2.141581e-21 0.000000e+00 2.485924e-25 2.220446e-16 0.108643838 [4,] 3.018239e-02 0.000000e+00 2.485924e-25 0.000000e+00 5.870007e-15 0.006783324 [5,] 4.806400e-10 2.247825e-20 2.220446e-16 5.870007e-15 0.000000e+00 0.558827862 [6,] 4.751395e-01 4.540325e-01 1.086438e-01 6.783324e-03 5.588279e-01 0.000000000 Which is exactly what I want. But I want to get 3 matrices, one for each element of the datalist above.

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  • Modeling objects with multiple table relationships in Zend Framework

    - by andybaird
    I'm toying with Zend Framework and trying to use the "QuickStart" guide against a website I'm making just to see how the process would work. Forgive me if this answer is obvious, hopefully someone experienced can shed some light on this. I have three database tables: CREATE TABLE `users` ( `id` int(11) NOT NULL auto_increment, `email` varchar(255) NOT NULL, `username` varchar(255) NOT NULL default '', `first` varchar(128) NOT NULL default '', `last` varchar(128) NOT NULL default '', `gender` enum('M','F') default NULL, `birthyear` year(4) default NULL, `postal` varchar(16) default NULL, `auth_method` enum('Default','OpenID','Facebook','Disabled') NOT NULL default 'Default', PRIMARY KEY (`id`), UNIQUE KEY `email` (`email`), UNIQUE KEY `username` (`username`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `user_password` ( `user_id` int(11) NOT NULL, `password` varchar(16) NOT NULL default '', PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `user_metadata` ( `user_id` int(11) NOT NULL default '0', `signup_date` datetime default NULL, `signup_ip` varchar(15) default NULL, `last_login_date` datetime default NULL, `last_login_ip` varchar(15) default NULL, PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 I want to create a User model that uses all three tables in certain situations. E.g., the metadata table is accessed if/when the meta data is needed. The user_password table is accessed only if the 'Default' auth_method is set. I'll likely be adding a profile table later on that I would like to be able to access from the user model. What is the best way to do this with ZF and why?

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  • How can I get a static URL to a map image using the Google Static Maps API?

    - by Argote
    === BACKGROUND === Hello, so I've published a Web-App (still in "Beta") which uses the Flickr API to get information for the photos of a particular Flickr user and generates IPB code to post any of his/her images. While Flickr now gives you the IPB code to show the image and link back to the photo site directly on its site, my App also has the option of embeding the title, description, select EXIF data, location information, etc. into the post for the IPB forum. === PROBLEM === I've most recently added the option to integrate a Google Maps image of the photo's geolocation data into the post by using the Google Static Maps API. The problem is that the image URL I have is in the following form (including IPB [IMG] tags): [IMG]http://maps.google.com/maps/api/staticmap?zoom=16&size=600x600&maptype=hybrid&markers=19.387687,-99.251732&sensor=false[/IMG] Which shows this example image (In practice the image size is user selectable): However, some IPB forums seem to not support dyamic image URLs which gives me a broken image, I'd like to replace the [IMG]http://maps.google.com/maps/api/staticmap?zoom=16&size=600x600&maptype=hybrid&markers=19.387687,-99.251732&sensor=false[/IMG] with something like [IMG]http://maps.google.com/maps/api/staticmap/map0000001.png[/IMG] which should be supported by all IPB forums. Thanks in advance for your help. In case you're interested, the most recent "released" version of my Web-App can be found here: http://flickr.argote.mx/ (The changes I mention here are still on local development server).

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  • SQL Server 2008 need just like crosstab query on XML column?

    - by user1332896
    <abc id="abc1"> <def id="def1"> <ghi att='ghi1'> <mn id="0742d2ea" name="RF" dt="0" df="3" ty="0" /> <mn id="64d9a11b" name="CJ" dt="0" df="3" ty="0" /> <mn id="db72d154" name="FJ" dt="2" df="4" ty="0" /> <mn id="39af9fa1" name="BS" dt="0" df="2" ty="0" /> </ghi> <jkl att='jkl1'> <mn id="0742d2ea" name="RF" dt="1" gl="19" /> <mn id="64d9a11b" name="CJ" dt="0" gl="6" /> <mn id="db72d154" name="FJ" dt="0" gl="0" /> <mn id="39af9fa1" name="BS" dt="0" gl="12" /> <mn id="ac4f566f" name="DJ" dt="0" gl="9" /> <mn id="4bf3ba2f" name="RP" dt="0" gl="16" /> <mn id="db1af021" name="SC" dt="1" gl="10" /> <mn id="c4c93a2d" name="DN" dt="1" gl="15" /> </jkl> </def> </abc> I need this output. Is this possible in SQL Server 2008? id name ghiDT ghiDF ghiTY jklDT jklGL 0742d2ea RF 0 3 0 1 19 64d9a11b CJ 0 3 0 0 6 db72d154 FJ 2 4 0 0 0 39af9fa1 BS 0 2 0 0 12 ac4f566f DJ 0 0 0 0 9 4bf3ba2f RP 0 0 0 0 16 db1af021 SC 0 0 0 1 10 c4c93a2d DN 0 0 0 1 15

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  • Adding an ADO.NET Entity Data Model throws build errors

    - by user3726262
    I am using Visual Studio 2013 express. I create a new project and then I add a database to that project. But, when I add an ADO.NET Entity Framework model to that project and then run the program, I get the following four build errors listed below. To try to remedy this myself, I added the namespaces 'System.Data.Entity' and 'System.Data.Entity.Design', but that didn't help. Also, I uninstalled and re-installed the Nuget package. I also uninstalled and re-installed Visual Studio 2013 Express for Windows Desktop. But these measures didn't help the situation either. Please note that I used to use the Entity Data model just fine. But it was around the time that I did a system restore on my computer, and when I updated VS 2013 with an update offered on the start page, and finally, when I signed up for MS Azure, that I started running into the problem described above. Now I would think that uninstalling and reinstalling Visual Studio 2013, and then installing the 'Nuget' Package would solve all problems. What am I missing here? The errors mentioned above are: Error 1 The type or namespace name 'Infrastructure' does not exist in the namespace 'System.Data.Entity' (are you missing an assembly reference?) C:\Users\John\documents\visual studio 2013\Projects\Riches\Riches\RichesModel.Context.cs 14 30 DataLayer Error 2 The type or namespace name 'DbContext' could not be found (are you missing a using directive or an assembly reference?) C:\Users\John\documents\visual studio 2013\Projects\Riches\Riches\RichesModel.Context.cs 16 52 DataLayer Error 3 The type or namespace name 'DbModelBuilder' could not be found (are you missing a using directive or an assembly reference?) C:\Users\John\documents\visual studio 2013\Projects\Riches\Riches\RichesModel.Context.cs 23 49 DataLayer Error 4 The type or namespace name 'DbSet' could not be found (are you missing a using directive or an assembly reference?) C:\Users\John\documents\visual studio 2013\Projects\Riches\Riches\RichesModel.Context.cs 28 16 DataLayer Thank you and I realize that my last attempt at this question was rather rough-draftish, John

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  • iPhone Localization: simple project not working

    - by gonso
    Hello Im doing my first localized project and I've been fighting with it for several hours with no luck. I have to create an app that, based on the user selection, shows texts and images in different languages. I've read most of Apple's documents on the matter but I cant make a simple example work. This are my steps so far: 1) Create a new project. 2) Manually create a "en.lproj" directory in the projects folder. 3) Using TexEdit create file called "Localizable.strings" and store it in Unicode UTF-16. The file looks like this: /* Localizable.strings Multilanguage02 Created by Gonzalo Floria on 5/6/10. Copyright 2010 __MyCompanyName__. All rights reserved. */ "Hello" = "Hi"; "Goodbye" = "Bye"; 4) I drag this file to the Resources Folder on XCode and it appear with the "subdir" "en" underneath it (with the dropdown triangle to the left). If I try to see it on XCode it looks all wrong, whit lots of ? symbols, but Im guessing thats because its a UTF-16 file. Right? 5) Now on my view did load I can access this strings like this: NSString *translated; translated = NSLocalizedString(@"Hello", @"User greetings"); NSLog(@"Translated text is %@",translated); My problem is allowing the user to switch language. I have create an es.lproj with the Localizable.strings file (in Spanish), but I CANT access it. I've tried this line: [[NSUserDefaults standardUserDefaults] setObject: [NSArray arrayWithObjects:@"es", nil] forKey:@"AppleLanguages"]; But that only works the NEXT time you load the application. Is there no way to allow the user to switch languages while running the application?? Do I have to implement my own Dictionary files and forget all about NSLocalizableString family? Thanks for ANY advice or pointers. Gonso

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  • XPath - get parent node

    - by chris.shi
    //* [ local-name()='component' and namespace-uri()='urn:hl7-org:v3' ] using thispath ,I can get a node like this: <component xmlns="urn:hl7-org:v3"> <structuredBody> <component> <section> <code code="10164-2" codeSystem="2.16.840.1.113883.6.1" codeSystemName="LOINC"/> <title>History of Present Illness</title> <text> </text> </section> </component> <component> ...... </component> <component> ...... </component> <structuredBody/> <component/> in order to get the node as below: <component> <section> <code code="10164-2" codeSystem="2.16.840.1.113883.6.1" codeSystemName="LOINC"/> <title>History of Present Illness</title> <text> </text> </section> </component> I change the path to : //* [ local-name()='component' and namespace-uri()='urn:hl7-org:v3' and position()=1] but ,how can I get the same result by using [code="10164-2"] as a qualification. ( I do not know how to describe this question ,as a result ,the title of this question is a little simple ,sorry .) thanks

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  • Parsing data with Clojure, interval problem.

    - by Andrea Di Persio
    Hello! I'm writing a little parser in clojure for learning purpose. basically is a TSV file parser that need to be put in a database, but I added a complication. The complication itself is that in the same file there are more intervals. The file look like this: ###andreadipersio 2010-03-19 16:10:00### USER COMM PID PPID %CPU %MEM TIME root launchd 1 0 0.0 0.0 2:46.97 root DirectoryService 11 1 0.0 0.2 0:34.59 root notifyd 12 1 0.0 0.0 0:20.83 root diskarbitrationd 13 1 0.0 0.0 0:02.84` .... ###andreadipersio 2010-03-19 16:20:00### USER COMM PID PPID %CPU %MEM TIME root launchd 1 0 0.0 0.0 2:46.97 root DirectoryService 11 1 0.0 0.2 0:34.59 root notifyd 12 1 0.0 0.0 0:20.83 root diskarbitrationd 13 1 0.0 0.0 0:02.84 I ended up with this code: (defn is-header? "Return true if a line is header" [line] (> (count (re-find #"^\#{3}" line)) 0)) (defn extract-fields "Return regex matches" [line pattern] (rest (re-find pattern line))) (defn process-lines [lines] (map process-line lines)) (defn process-line [line] (if (is-header? line) (extract-fields line header-pattern)) (extract-fields line data-pattern)) My idea is that in 'process-line' interval need to be merged with data so I have something like this: ('andreadipersio', '2010-03-19', '16:10:00', 'root', 'launchd', 1, 0, 0.0, 0.0, '2:46.97') for every row till the next interval, but I can't figure how to make this happen. I tried with something like this: (def process-line [line] (if is-header? line) (def header-data (extract-fields line header-pattern))) (cons header-data (extract-fields line data-pattern))) But this doesn't work as excepted. Any hints? Thanks!

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  • Why does iOS 5 fail to connect to a server running JDK 1.6, but not JDK 1.5

    - by KC Baltz
    We have a Java Socket Server listening on an SSLSocket (port 443) and an iOS application that connects with it. When running on iOS 5.1, the application stopped working when we upgraded the Java version of the server from JDK 1.5 to 1.6 (or 1.7). The app connects just fine to JDK 5 and 6 when running on iOS 6. The iOS app is reporting an error: -9809 = errSSLCrypto. On the Java side, we get javax.net.ssl.SSLException: Received fatal alert: close_notify. On the Java server side, we have enabled all the available cipher suites. On the client side we have tested enabling several different suites, although we have yet to complete a test involving each one individually enabled. Right now, it is failing when we use TLS_DH_anon_WITH_AES_128_CBC_SHA although it has failed with others and we are starting to think it's not the suite. Here is the debug output. It makes it all the way to ServerHelloDone and then fails shortly thereafter: Is secure renegotiation: false [Raw read]: length = 5 0000: 16 03 03 00 41 ....A [Raw read]: length = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . URT-, READ: Unknown-3.3 Handshake, length = 65 *** ClientHello, Unknown-3.3 RandomCookie: GMT: 1333992971 bytes = { 86, 25, 37, 101, 200, 242, 175, 2, 173, 72, 254, 226, 146, 207, 184, 215, 166, 163, 234, 197, 255, 93, 116, 15, 27, 193, 153, 24 } Session ID: {} Cipher Suites: [TLS_EMPTY_RENEGOTIATION_INFO_SCSV, TLS_DH_anon_WITH_AES_128_CBC_SHA, SSL_DH_anon_WITH_3DES_EDE_CBC_SHA, SSL_DH_anon_WITH_RC4_128_MD5] Compression Methods: { 0 } Unsupported extension signature_algorithms, data: 00:06:05:01:04:01:02:01 *** [read] MD5 and SHA1 hashes: len = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . %% Created: [Session-1, TLS_DH_anon_WITH_AES_128_CBC_SHA] *** ServerHello, TLSv1 RandomCookie: GMT: 1333992972 bytes = { 100, 3, 56, 153, 7, 2, 251, 64, 41, 32, 66, 240, 227, 181, 55, 190, 2, 237, 146, 0, 73, 119, 70, 0, 160, 9, 28, 207 } Session ID: {80, 131, 30, 12, 241, 73, 52, 38, 46, 41, 237, 226, 199, 246, 156, 45, 3, 247, 182, 43, 223, 8, 49, 169, 188, 63, 160, 41, 102, 199, 50, 190} Cipher Suite: TLS_DH_anon_WITH_AES_128_CBC_SHA Compression Method: 0 Extension renegotiation_info, renegotiated_connection: <empty> *** Cipher suite: TLS_DH_anon_WITH_AES_128_CBC_SHA *** Diffie-Hellman ServerKeyExchange DH Modulus: { 233, 230, 66, 89, 157, 53, 95, 55, 201, 127, 253, 53, 103, 18, 11, 142, 37, 201, 205, 67, 233, 39, 179, 169, 103, 15, 190, 197, 216, 144, 20, 25, 34, 210, 195, 179, 173, 36, 128, 9, 55, 153, 134, 157, 30, 132, 106, 171, 73, 250, 176, 173, 38, 210, 206, 106, 34, 33, 157, 71, 11, 206, 125, 119, 125, 74, 33, 251, 233, 194, 112, 181, 127, 96, 112, 2, 243, 206, 248, 57, 54, 148, 207, 69, 238, 54, 136, 193, 26, 140, 86, 171, 18, 122, 61, 175 } DH Base: { 48, 71, 10, 213, 160, 5, 251, 20, 206, 45, 157, 205, 135, 227, 139, 199, 209, 177, 197, 250, 203, 174, 203, 233, 95, 25, 10, 167, 163, 29, 35, 196, 219, 188, 190, 6, 23, 69, 68, 64, 26, 91, 44, 2, 9, 101, 216, 194, 189, 33, 113, 211, 102, 132, 69, 119, 31, 116, 186, 8, 77, 32, 41, 216, 60, 28, 21, 133, 71, 243, 169, 241, 162, 113, 91, 226, 61, 81, 174, 77, 62, 90, 31, 106, 112, 100, 243, 22, 147, 58, 52, 109, 63, 82, 146, 82 } Server DH Public Key: { 8, 60, 59, 13, 224, 110, 32, 168, 116, 139, 246, 146, 15, 12, 216, 107, 82, 182, 140, 80, 193, 237, 159, 189, 87, 34, 18, 197, 181, 252, 26, 27, 94, 160, 188, 162, 30, 29, 165, 165, 68, 152, 11, 204, 251, 187, 14, 233, 239, 103, 134, 168, 181, 173, 206, 151, 197, 128, 65, 239, 233, 191, 29, 196, 93, 80, 217, 55, 81, 240, 101, 31, 119, 98, 188, 211, 52, 146, 168, 127, 127, 66, 63, 111, 198, 134, 70, 213, 31, 162, 146, 25, 178, 79, 56, 116 } Anonymous *** ServerHelloDone [write] MD5 and SHA1 hashes: len = 383 0000: 02 00 00 4D 03 01 50 83 1E 0C 64 03 38 99 07 02 ...M..P...d.8... 0010: FB 40 29 20 42 F0 E3 B5 37 BE 02 ED 92 00 49 77 .@) B...7.....Iw 0020: 46 00 A0 09 1C CF 20 50 83 1E 0C F1 49 34 26 2E F..... P....I4&. 0030: 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B DF 08 31 A9 BC ).....-...+..1.. 0040: 3F A0 29 66 C7 32 BE 00 34 00 00 05 FF 01 00 01 ?.)f.2..4....... 0050: 00 0C 00 01 26 00 60 E9 E6 42 59 9D 35 5F 37 C9 ....&.`..BY.5_7. 0060: 7F FD 35 67 12 0B 8E 25 C9 CD 43 E9 27 B3 A9 67 ..5g...%..C.'..g 0070: 0F BE C5 D8 90 14 19 22 D2 C3 B3 AD 24 80 09 37 ......."....$..7 0080: 99 86 9D 1E 84 6A AB 49 FA B0 AD 26 D2 CE 6A 22 .....j.I...&..j" 0090: 21 9D 47 0B CE 7D 77 7D 4A 21 FB E9 C2 70 B5 7F !.G...w.J!...p.. 00A0: 60 70 02 F3 CE F8 39 36 94 CF 45 EE 36 88 C1 1A `p....96..E.6... 00B0: 8C 56 AB 12 7A 3D AF 00 60 30 47 0A D5 A0 05 FB .V..z=..`0G..... 00C0: 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 C5 FA CB AE CB ..-............. 00D0: E9 5F 19 0A A7 A3 1D 23 C4 DB BC BE 06 17 45 44 ._.....#......ED 00E0: 40 1A 5B 2C 02 09 65 D8 C2 BD 21 71 D3 66 84 45 @.[,..e...!q.f.E 00F0: 77 1F 74 BA 08 4D 20 29 D8 3C 1C 15 85 47 F3 A9 w.t..M ).<...G.. 0100: F1 A2 71 5B E2 3D 51 AE 4D 3E 5A 1F 6A 70 64 F3 ..q[.=Q.M>Z.jpd. 0110: 16 93 3A 34 6D 3F 52 92 52 00 60 08 3C 3B 0D E0 ..:4m?R.R.`.<;.. 0120: 6E 20 A8 74 8B F6 92 0F 0C D8 6B 52 B6 8C 50 C1 n .t......kR..P. 0130: ED 9F BD 57 22 12 C5 B5 FC 1A 1B 5E A0 BC A2 1E ...W"......^.... 0140: 1D A5 A5 44 98 0B CC FB BB 0E E9 EF 67 86 A8 B5 ...D........g... 0150: AD CE 97 C5 80 41 EF E9 BF 1D C4 5D 50 D9 37 51 .....A.....]P.7Q 0160: F0 65 1F 77 62 BC D3 34 92 A8 7F 7F 42 3F 6F C6 .e.wb..4....B?o. 0170: 86 46 D5 1F A2 92 19 B2 4F 38 74 0E 00 00 00 .F......O8t.... URT-, WRITE: TLSv1 Handshake, length = 383 [Raw write]: length = 388 0000: 16 03 01 01 7F 02 00 00 4D 03 01 50 83 1E 0C 64 ........M..P...d 0010: 03 38 99 07 02 FB 40 29 20 42 F0 E3 B5 37 BE 02 .8....@) B...7.. 0020: ED 92 00 49 77 46 00 A0 09 1C CF 20 50 83 1E 0C ...IwF..... P... 0030: F1 49 34 26 2E 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B .I4&.).....-...+ 0040: DF 08 31 A9 BC 3F A0 29 66 C7 32 BE 00 34 00 00 ..1..?.)f.2..4.. 0050: 05 FF 01 00 01 00 0C 00 01 26 00 60 E9 E6 42 59 .........&.`..BY 0060: 9D 35 5F 37 C9 7F FD 35 67 12 0B 8E 25 C9 CD 43 .5_7...5g...%..C 0070: E9 27 B3 A9 67 0F BE C5 D8 90 14 19 22 D2 C3 B3 .'..g......."... 0080: AD 24 80 09 37 99 86 9D 1E 84 6A AB 49 FA B0 AD .$..7.....j.I... 0090: 26 D2 CE 6A 22 21 9D 47 0B CE 7D 77 7D 4A 21 FB &..j"!.G...w.J!. 00A0: E9 C2 70 B5 7F 60 70 02 F3 CE F8 39 36 94 CF 45 ..p..`p....96..E 00B0: EE 36 88 C1 1A 8C 56 AB 12 7A 3D AF 00 60 30 47 .6....V..z=..`0G 00C0: 0A D5 A0 05 FB 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 .......-........ 00D0: C5 FA CB AE CB E9 5F 19 0A A7 A3 1D 23 C4 DB BC ......_.....#... 00E0: BE 06 17 45 44 40 1A 5B 2C 02 09 65 D8 C2 BD 21 ...ED@.[,..e...! 00F0: 71 D3 66 84 45 77 1F 74 BA 08 4D 20 29 D8 3C 1C q.f.Ew.t..M ).<. 0100: 15 85 47 F3 A9 F1 A2 71 5B E2 3D 51 AE 4D 3E 5A ..G....q[.=Q.M>Z 0110: 1F 6A 70 64 F3 16 93 3A 34 6D 3F 52 92 52 00 60 .jpd...:4m?R.R.` 0120: 08 3C 3B 0D E0 6E 20 A8 74 8B F6 92 0F 0C D8 6B .<;..n .t......k 0130: 52 B6 8C 50 C1 ED 9F BD 57 22 12 C5 B5 FC 1A 1B R..P....W"...... 0140: 5E A0 BC A2 1E 1D A5 A5 44 98 0B CC FB BB 0E E9 ^.......D....... 0150: EF 67 86 A8 B5 AD CE 97 C5 80 41 EF E9 BF 1D C4 .g........A..... 0160: 5D 50 D9 37 51 F0 65 1F 77 62 BC D3 34 92 A8 7F ]P.7Q.e.wb..4... 0170: 7F 42 3F 6F C6 86 46 D5 1F A2 92 19 B2 4F 38 74 .B?o..F......O8t 0180: 0E 00 00 00 .... [Raw read]: length = 5 0000: 15 03 01 00 02 ..... [Raw read]: length = 2 0000: 02 00 .. URT-, READ: TLSv1 Alert, length = 2 URT-, RECV TLSv1 ALERT: fatal, close_notify URT-, called closeSocket() URT-, handling exception: javax.net.ssl.SSLException: Received fatal alert: close_notify FYI, this works in iOS 6.0

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  • Print an array elements

    - by 1ace1
    Hello guys, this is my first post and im still a beginner in the programming world so bare with me. I just created an array with 100 initialized values and i want to print out 10 elements on each line so it would be somthing like this 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 ...26 this is the code i used and i managed to do it for the first 10 elements but i couldnt figure out how to do it for the rest public static void main(String[] args) { int[] numbers = { 0,1,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17}; int i, count = 0; for (i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); count++; if (count == 9) for (i = 9; i < numbers.length; i++) System.out.println(numbers[i] + " "); } } thanks!

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  • Send C++ Structure to MSMQ Message

    - by Gobalakrishnan
    Hi, I am trying to send the below structure through MSMQ Message typedef struct { char cfiller[7]; short MsgCode; char cfiller1[11]; short MsgLength; char cfiller2[2]; } MESSAGECODE; typedef struct { MESSAGECODE Header; char DealerId[16]; char GroupId[16]; long Token; short Periodicity; double Deposit; double GrossExposureLimit; double NetExposureLimit; double NetSaleExposureLimit; double NetPositionLimit; double TurnoverLimit; double PendingOrdersLimit; double MTMLossLimit; double MaxSingleTransValue; long MaxSingleTransQty; double IMLimit; long NetQuantityLimit; } LIMITUPDATE; void main() { // // create queue // open queue // send message // OleInitialize(NULL); // have to init OLE // // declare some variables // IMSMQQueueInfoPtr qinfo("MSMQ.MSMQQueueInfo"); IMSMQQueuePtr qSend; IMSMQMessagePtr m("MSMQ.MSMQMessage"); LIMITUPDATE l1; l1.Header.MsgCode=26001; l1.Header.MsgLength=150; qinfo->PathName = ".\\private$\\q99"; m->Body = l1; qSend = qinfo->Open(MQ_SEND_ACCESS, MQ_DENY_NONE); m->Send(qSend); qSend->Close(); } while compiling i am getting the following error. Error 2 error C2664: 'IMSMQMessage::PutBody' : cannot convert parameter 1 from 'LIMITUPDATE' to 'const _variant_t &' c:\temp\msmq\msmq.cpp 58 msmq thank you.

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  • Byte-Pairing for data compression

    - by user1669533
    Question about Byte-Pairing for data compression. If byte pairing converts two byte values to a single byte value, splitting the file in half, then taking a gig file and recusing it 16 times shrinks it to 62,500,000. My question is, is byte-pairing really efficient? Is the creation of a 5,000,000 iteration loop, to be conservative, efficient? I would like some feed back on and some incisive opinions please. Dave, what I read was: "The US patent office no longer grants patents on perpetual motion machines, but has recently granted at least two patents on a mathematically impossible process: compression of truly random data." I was not inferring the Patent Office was actually considering what I am inquiring about. I was merely commenting on the notion of a "mathematically impossible process." If someone has, in some way created a method of having a "single" data byte as a placeholder of 8 individual bytes of data, that would be a consideration for a patent. Now, about the mathematically impossibility of an 8 to 1 compression method, it is not so much a mathematically impossibility, but a series of rules and conditions that can be created. As long as there is the rule of 8 or 16 bit representation of storing data on a medium, there are ways to manipulate data that mirrors current methods, or creation by a new way of thinking.

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  • asp.net jquery how to use Plugin/Validation with web content

    - by Eyla
    I have a asp.net web content from that have a asp.net textbox and I want to use Plugin/Validation but it is not working with me here is my code: <%@ Page Title="" Language="C#" MasterPageFile="~/Master.Master" AutoEventWireup="true" CodeBehind="WebForm1.aspx.cs" Inherits="IMAM_APPLICATION.WebForm1" %> <%@ Register assembly="AjaxControlToolkit" namespace="AjaxControlToolkit" tagprefix="asp" %> <asp:Content ID="Content1" ContentPlaceHolderID="head" runat="server"> <script src="js/jquery-1.4.1.js" type="text/javascript"></script> <script src="js/jquery.validate.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function() { $.validator.addMethod("#<%=TextBox1.ClientID %>", function(value, element) { return this.optional(element) || /^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{8,16}$/i.test(value); }, "Passwords are 8-16 characters with uppercase letters, lowercase letters and at least one number."); }); </script> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="ContentPlaceHolder1" runat="server"> </asp:Content> <asp:Content ID="Content3" ContentPlaceHolderID="ContentPlaceHolder2" runat="server"> <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox> </asp:Content>

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  • asp.net jquery how to use Plugin/Validation wormith web content

    - by Eyla
    I have a asp.net web content from that have a asp.net textbox and I want to use Plugin/Validation but it is not working with me here is my code: <%@ Page Title="" Language="C#" MasterPageFile="~/Master.Master" AutoEventWireup="true" CodeBehind="WebForm1.aspx.cs" Inherits="IMAM_APPLICATION.WebForm1" %> <%@ Register assembly="AjaxControlToolkit" namespace="AjaxControlToolkit" tagprefix="asp" %> <asp:Content ID="Content1" ContentPlaceHolderID="head" runat="server"> <script src="js/jquery-1.4.1.js" type="text/javascript"></script> <script src="js/jquery.validate.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function() { $.validator.addMethod("#<%=TextBox1.ClientID %>", function(value, element) { return this.optional(element) || /^(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{8,16}$/i.test(value); }, "Passwords are 8-16 characters with uppercase letters, lowercase letters and at least one number."); </script> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="ContentPlaceHolder1" runat="server"> </asp:Content> <asp:Content ID="Content3" ContentPlaceHolderID="ContentPlaceHolder2" runat="server"> <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox> </asp:Content>

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  • imageconvolution leaves black dot in the upper left corner

    - by Peter O.
    I'm trying to sharp resized images using this code: imageconvolution($imageResource, array( array( -1, -1, -1 ), array( -1, 16, -1 ), array( -1, -1, -1 ), ), 8, 0); When the transparent PNG image is sharpened, using code above, it appears with a black dot in the upper left corner (I have tried different convolution kernels, but the result is the same). After resizing the image looked OK. 1st image is the original one 2nd image is the sharpened one EDIT: What am I going wrong? I'm using the color retrieved from pixel. $color = imagecolorat($imageResource, 0, 0); imageconvolution($imageResource, array( array( -1, -1, -1 ), array( -1, 16, -1 ), array( -1, -1, -1 ), ), 8, 0); imagesetpixel($imageResource, 0, 0, $color); Is imagecolorat the right function? Or is the position correct? EDIT2: I have changed coordinates, but still no luck. I've check the transparency given by imagecolorat (according to this post). This is the dump: array(4) { red => 0 green => 0 blue => 0 alpha => 127 } Alpha 127 = 100% transparent. Those zeroes might cause the problem...

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  • Creating multiple csv files from data within a csv file.

    - by S1syphus
    System OSX or Linux I'm trying to automate my work flow at work, each week I receive an excel file, which I convert to a csv. An example is: ,,L1,,,L2,,,L3,,,L4,,,L5,,,L6,,,L7,,,L8,,,L9,,,L10,,,L11, Title,r/t,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,neede d,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst,needed,actual,Inst EXAMPLEfoo,60,6,6,6,0,0,0,0,0,0,6,6,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 EXAMPLEbar,30,6,6,12,6,7,14,6,6,12,6,6,12,6,8,16,6,7,14,6,7.5,15,6,6,12,6,8,16,6,0,0,6,7,14 EXAMPLE1,60,3,3,3,3,5,5,3,4,4,3,3,3,3,6,6,3,4,4,3,3,3,3,4,4,3,8,8,3,0,0,3,4,4 EXAMPLE2,120,6,6,3,0,0,0,6,8,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0 EXAMPLE3,60,6,6,6,6,8,8,6,6,6,6,6,6,0,0,0,0,0,0,6,8,8,6,6,6,0,0,0,0,0,0,0,10,10 EXAMPLE4,30,6,6,12,6,7,14,6,6,12,6,6,12,3,5.5,11,6,7.5,15,6,6,12,6,0,0,6,9,18,6,0,0,6,6.5,13 And so you can get a picture of how it looks in excel: What I need to do, is create multiple csv files for each instance in row 1, so L1, L2, L3, L4... And within that each csv file it needs to contain the title, r/t, needed So for L1 an example out put would look like: EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 And for L2: EXAMPLEfoo,60,0 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,0 EXAMPLE3,60,6 EXAMPLE4,30,6 And so on. I have tried playing around with sed and awk and hit google but I have found nothing that really solves the issue. I'd imagine perl would be particular suited to this or maybe python, so I would be more than happy to accept suggestions from users. So, any suggestions? Thanks in advance.

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  • what is meant by normalization in huge pointers

    - by wrapperm
    Hi, I have a lot of confusion on understanding the difference between a "far" pointer and "huge" pointer, searched for it all over in google for a solution, couldnot find one. Can any one explain me the difference between the two. Also, what is the exact normalization concept related to huge pointers. Please donot give me the following or any similar answers: "The only difference between a far pointer and a huge pointer is that a huge pointer is normalized by the compiler. A normalized pointer is one that has as much of the address as possible in the segment, meaning that the offset is never larger than 15. A huge pointer is normalized only when pointer arithmetic is performed on it. It is not normalized when an assignment is made. You can cause it to be normalized without changing the value by incrementing and then decrementing it. The offset must be less than 16 because the segment can represent any value greater than or equal to 16 (e.g. Absolute address 0x17 in a normalized form would be 0001:0001. While a far pointer could address the absolute address 0x17 with 0000:0017, this is not a valid huge (normalized) pointer because the offset is greater than 0000F.). Huge pointers can also be incremented and decremented using arithmetic operators, but since they are normalized they will not wrap like far pointers." Here the normalization concept is not very well explained, or may be I'm unable to understand it very well. Can anyone try explaining this concept from a beginners point of view. Thanks, Rahamath

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  • No Debug information of an iPhone app

    - by Markus Pilman
    Hi all, I wrote an iPhone app which uses a third party library. I crosscompiled this library successfully and everything works smoothly. But when I want to debug the application, it would make sense to also be able to debug the library. So I compiled also the external library with debuging information (usign the gcc option -ggdb). But when I want to debug it, I get the correct symbol names, but the positions are always wrong/extremly wierd (locale_facets.tcc:2505 or iostream:76). For example a stack trace could look like this: #0 0x000045e8 in zorba::serialization::SerializeBaseClass::SerializeBaseClass () at iostream:76 #1 0x0001d990 in zorba::RCObject::RCObject () at iostream:76 #2 0x00025187 in zorba::xqpStringStore::xqpStringStore () at iostream:76 #3 0x000719e4 in zorba::String::String () at locale_facets.tcc:2505 #4 0x00030513 in iphone::iLabelModule::getURI (this=0x533f710) at /Users/sausalito/eth/izorba/sandbox/ilabel.cpp:19 #5 0x00356766 in zorba::static_context::bind_external_module () at locale_facets.tcc:2505 #6 0x0006139d in zorba::StaticContextImpl::registerModule () at locale_facets.tcc:2505 #7 0x000333e5 in -[ZorbaCaller init] (self=0x53405c0, _cmd=0x95583398) at /Users/sausalito/eth/izorba/sandbox/ZorbaCaller.mm:61 #8 0x00033180 in +[ZorbaCaller instance] (self=0x11dc2bc, _cmd=0x93679591) at /Users/sausalito/eth/izorba/sandbox/ZorbaCaller.mm:37 #9 0x0003d998 in -[testOne execute:] (self=0x530d560, _cmd=0x9366b126, sender=0x5121da0) at /Users/sausalito/eth/izorba/sandbox/generator/testOne.mm:13 #10 0x01a21405 in -[UIApplication sendAction:to:from:forEvent:] () #11 0x01a84b4e in -[UIControl sendAction:to:forEvent:] () #12 0x01a86d6f in -[UIControl(Internal) _sendActionsForEvents:withEvent:] () #13 0x01a85abb in -[UIControl touchesEnded:withEvent:] () #14 0x01a3addf in -[UIWindow _sendTouchesForEvent:] () #15 0x01a247c8 in -[UIApplication sendEvent:] () #16 0x01a2b061 in _UIApplicationHandleEvent () #17 0x03b6fd59 in PurpleEventCallback () #18 0x034a8b80 in CFRunLoopRunSpecific () #19 0x034a7c48 in CFRunLoopRunInMode () #20 0x03b6e615 in GSEventRunModal () #21 0x03b6e6da in GSEventRun () #22 0x01a2bfaf in UIApplicationMain () #23 0x0002dd7e in main (argc=1, argv=0xbffff044) at /Users/sausalito/eth/izorba/sandbox/main.m:16 Does anybody have an idea, where these wrong locations come from?

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  • OUTPUT DID NOT REDIRECT TO THE INTENDED FILE OPENED FOR..

    - by rockyurock
    HELLO ALL, I USED THE BELOW CODE FOR CAPTURING THE OUTPUT (BELOW IN lines) IN A FILE "my_output.txt" BUT FAILED TO CAPTURE. **************output*************** inside value loop ------------------------------------------------------------ Server listening on UDP port 5001 Receiving 1470 byte datagrams UDP buffer size: 108 KByte (default) ------------------------------------------------------------ [ 3] local 192.168.16.2 port 5001 connected with 192.168.16.1 port 3189 [ ID] Interval Transfer Bandwidth Jitter Lost/Total Datagrams [ 3] 0.0- 5.0 sec 2.14 MBytes 3.61 Mbits/sec 0.369 ms 0/ 1528 (0%) inside value loop3 clue1 clue2 inside value loop4 one iperf completed *************************************** however when i enabled the local *STDOUT; in below code then i could see the above output on command prompt display (ofcourse server is sending some data). could anybody suggest me how can i capture the o/p in a file intended? below is the code i am using .. my $file = 'my_output.txt'; use Win32::Process; print"inside value loop\n"; # redirect stdout to a file #local *STDOUT; open STDOUT, '>', $file or die "can't redirect STDOUT to <$file> $!"; Win32::Process::Create(my $ProcessObj, "D:\\IOT_AUTOMATION_UTILITY\\_SATURDAY_09-04-10\\adb_cmd.bat", "adb shell /data/app/iperf -u -s -p 5001", 0, NORMAL_PRIORITY_CLASS, ".") || die ErrorReport(); #$alarm_time = $IPERF_RUN_TIME+10; #20sec #$ProcessObj->Wait(40); #print"inside value loop2\n"; #sleep $alarm_time; sleep 40; $ProcessObj->Kill(0); sub ErrorReport{ print Win32::FormatMessage( Win32::GetLastError() ); } /rocky

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  • SSL over TDS, SQL Server 2005 Express

    - by reuvenab
    I capture packets sent/received by Win Xp machine when connecting to SQL Server 2005 Express using TLS encryption. Server and Client exchange Hello messages Server and Client send ChangeCipherSpec message Then Server and Client server send strange message that is not described in TLS protocol What is the message and if SSL over TDS is standard compliant at all? Server side capture: 16 **SSL Handshake** 03 01 00 4a 02 ServerHello 00 00 46 03 01 4b dd 68 59 GMT 33 13 37 98 10 5d 57 9d ff 71 70 dc d6 6f 9e 2c Random[00..13] cb 96 c0 2e b3 2f 9b 74 67 05 cc 96 Random[14..27] 20 72 26 00 00 0f db 7f d9 b0 51 c2 4f cd 81 4c Session ID 3f e3 d2 d1 da 55 c0 fe 9b 56 b7 6f 70 86 fe bb Session ID 54 Session ID 00 04 Cipher Suite 00 Compression 14 03 01 00 01 01 **ChangeCipherSpec** 16 03 01 ???? Finished ??? 00 20 d0 da cc c4 36 11 43 ff 22 25 8a e1 38 2b ???? ??? 71 ce f3 59 9e 35 b0 be b2 4b 1d c5 21 21 ce 41 ???? ??? 8e 24

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  • How to run OpenGL code with out compiling?

    - by Ole Jak
    So I have some openGL code (such code for example) /* FUNCTION: YCamera :: CalculateWorldCoordinates ARGUMENTS: x mouse x coordinate y mouse y coordinate vec where to store coordinates RETURN: n/a DESCRIPTION: Convert mouse coordinates into world coordinates */ void YCamera :: CalculateWorldCoordinates(float x, float y, YVector3 *vec) { // START GLint viewport[4]; GLdouble mvmatrix[16], projmatrix[16]; GLint real_y; GLdouble mx, my, mz; glGetIntegerv(GL_VIEWPORT, viewport); glGetDoublev(GL_MODELVIEW_MATRIX, mvmatrix); glGetDoublev(GL_PROJECTION_MATRIX, projmatrix); real_y = viewport[3] - (GLint) y - 1; // viewport[3] is height of window in pixels gluUnProject((GLdouble) x, (GLdouble) real_y, 1.0, mvmatrix, projmatrix, viewport, &mx, &my, &mz); /* 'mouse' is the point where mouse projection reaches FAR_PLANE. World coordinates is intersection of line(camera->mouse) with plane(z=0) (see LaMothe 306) Equation of line in 3D: (x-x0)/a = (y-y0)/b = (z-z0)/c Intersection of line with plane: z = 0 x-x0 = a(z-z0)/c <=> x = x0+a(0-z0)/c <=> x = x0 -a*z0/c y = y0 - b*z0/c */ double lx = fPosition.x - mx; double ly = fPosition.y - my; double lz = fPosition.z - mz; double sum = lx*lx + ly*ly + lz*lz; double normal = sqrt(sum); double z0_c = fPosition.z / (lz/normal); vec->x = (float) (fPosition.x - (lx/normal)*z0_c); vec->y = (float) (fPosition.y - (ly/normal)*z0_c); vec->z = 0.0f; } I want to run It but with out precompiling. Is there any way to do such thing

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