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  • Why doesn't negative values for the second index in a jagged array work in Python?

    - by univerio
    For example, if I have the following (data from Project Euler): s = [[75], [95, 64], [17, 47, 82], [18, 35, 87, 10], [20, 4, 82, 47, 65], [19, 1, 23, 75, 3, 34], [88, 2, 77, 73, 7, 63, 67], [99, 65, 4, 28, 6, 16, 70, 92], [41, 41, 26, 56, 83, 40, 80, 70, 33], [41, 48, 72, 33, 47, 32, 37, 16, 94, 29], [53, 71, 44, 65, 25, 43, 91, 52, 97, 51, 14], [70, 11, 33, 28, 77, 73, 17, 78, 39, 68, 17, 57], [91, 71, 52, 38, 17, 14, 91, 43, 58, 50, 27, 29, 48], [63, 66, 4, 68,89, 53, 67, 30, 73, 16, 69, 87, 40, 31], [4, 62, 98, 27, 23, 9, 70, 98, 73, 93, 38, 53, 60, 4, 23]] Why does s[1:][:-1] give me the same thing as s[1:] instead of (what I want) [s[i][:-1] for i in range(1,len(s))]. In other words, why does Python ignore my second index?

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  • Python Beginner: Selective Printing in loops

    - by Jonathan Straus
    Hi there. I'm a very new python user (had only a little prior experience with html/javascript as far as programming goes), and was trying to find some ways to output only intermittent numbers in my loop for a basic bicycle racing simulation (10,000 lines of biker positions would be pretty excessive :P). I tried in this loop several 'reasonable' ways to communicate a condition where a floating point number equals its integer floor (int, floor division) to print out every 100 iterations or so: for i in range (0,10000): i = i + 1 t = t + t_step #t is initialized at 0 while t_step is set at .01 acceleration_rider1 = (power_rider1 / (70 * velocity_rider1)) - (force_drag1 / 70) velocity_rider1 = velocity_rider1 + (acceleration_rider1 * t_step) position_rider1 = position_rider1 + (velocity_rider1 * t_step) force_drag1 = area_rider1 * (velocity_rider1 ** 2) acceleration_rider2 = (power_rider2 / (70 * velocity_rider1)) - (force_drag2 / 70) velocity_rider2 = velocity_rider2 + (acceleration_rider2 * t_step) position_rider2 = position_rider2 + (velocity_rider2 * t_step) force_drag2 = area_rider1 * (velocity_rider2 ** 2) if t == int(t): #TRIED t == t // 1 AND OTHER VARIANTS THAT DON'T WORK HERE:( print t, "biker 1", position_rider1, "m", "\t", "biker 2", position_rider2, "m"

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  • php : is this if condition correct?

    - by phill
    I have the following if condition statement if ( (strlen($data[70])>0) || ( (remove19((trim($data[29])) == '7135556666')) && isLongDistance($data[8])) ) where $data is a recordset from a database. My goal is to include all rows where $data[70] isn't blank, and also include rows where $data[29] = 713555666 && $data[8] isLongDistance = TRUE My question is, if isLongDistance($data[8]) returns false, will it still return the row since $data[70] is not blank? thanks in advance

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  • Problem in Saving Multi Level Models in YII

    - by Waqar
    My Table structure for user and his adress detail is as follows CREATE TABLE tbl_users ( id bigint(20) unsigned NOT NULL AUTO_INCREMENT, loginname varchar(128) NOT NULL, enabled enum("True","False"), approved enum("True","False"), password varchar(128) NOT NULL, email varchar(128) NOT NULL, role_id int(20) NOT NULL DEFAULT '2', name varchar(70) NOT NULL, co_type enum("S/O","D/O","W/O") DEFAULT "S/O", co_name varchar(70), gender enum("MALE","FEMALE","OTHER") DEFAULT "MALE", dob date DEFAULT NULL, maritalstatus enum("SINGLE","MARRIED","DIVORCED","WIDOWER") DEFAULT "MARRIED", occupation varchar(100) DEFAULT NULL, occupationtype_id int(20) DEFAULT NULL, occupationindustry_id int(20) DEFAULT NULL, contact_id bigint(20) unsigned DEFAULT NULL, signupreason varchar(500), PRIMARY KEY (id), UNIQUE KEY loginname (loginname), UNIQUE KEY email (email), FOREIGN KEY (role_id) REFERENCES tbl_roles (id), FOREIGN KEY (occupationtype_id) REFERENCES tbl_occupationtypes (id), FOREIGN KEY (occupationindustry_id) REFERENCES tbl_occupationindustries (id), FOREIGN KEY (contact_id) REFERENCES tbl_contacts (id) ) ENGINE=InnoDB; CREATE TABLE tbl_contacts ( id bigint(20) unsigned NOT NULL AUTO_INCREMENT, contact_type enum("cres","pres","coff"), address varchar(300) DEFAULT NULL, landmark varchar(100) DEFAULT NULL, district_id int(11) DEFAULT NULL, city_id int(20) DEFAULT NULL, state_id int(20) DEFAULT NULL, pin_id bigint(20) unsigned DEFAULT NULL, area_id bigint(20) unsigned DEFAULT NULL, po_id bigint(20) unsigned DEFAULT NULL, phone1 varchar(20) DEFAULT NULL, phone2 varchar(20) DEFAULT NULL, mobile1 varchar(20) DEFAULT NULL, mobile2 varchar(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (district_id) REFERENCES tbl_districts (id), FOREIGN KEY (city_id) REFERENCES tbl_cities (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; CREATE TABLE tbl_states ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB; CREATE TABLE tbl_districts ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, state_id int(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; CREATE TABLE tbl_cities ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, district_id int(20) DEFAULT NULL, state_id int(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (district_id) REFERENCES tbl_districts (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; The relationship is as follows User has multiple contacts i.e Permanent Address, Current Address, Office Address. Each Contact has state and City. User-Contact-state like this How to save models of this structure in one go. Please provide a reply ASAP

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  • Is there any way to add a MouseListener to a Graphic object ?

    - by Fahad
    Hi, Is there any way to add a MouseListener to a Graphic object. I have this simple GUI that draw an oval. What I want is handling the event when the user clicks on the oval import java.awt.*; import java.awt.event.MouseEvent; import java.awt.event.MouseListener; import javax.swing.*; public class Gui2 extends JFrame { JFrame frame = new JFrame(); MyDrawPanel drawpanel = new MyDrawPanel(); public static void main(String[] args) { Gui2 gui = new Gui2(); gui.go(); } public void go() { frame.getContentPane().add(drawpanel); // frame.addMouseListener(this); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setSize(300, 300); frame.setVisible(true); } } class MyDrawPanel extends JComponent implements MouseListener { public void paintComponent(Graphics g) { int red = (int) (Math.random() * 255); int green = (int) (Math.random() * 255); int blue = (int) (Math.random() * 255); Color startrandomColor = new Color(red, green, blue); red = (int) (Math.random() * 255); green = (int) (Math.random() * 255); blue = (int) (Math.random() * 255); Color endrandomColor = new Color(red, green, blue); Graphics2D g2d = (Graphics2D) g; this.addMouseListener(this); GradientPaint gradient = new GradientPaint(70, 70, startrandomColor, 150, 150, endrandomColor); g2d.setPaint(gradient); g2d.fillOval(70, 70, 100, 100); } @Override public void mouseClicked(MouseEvent e) { if ((e.getButton() == 1) && (e.getX() >= 70 && e.getX() <= 170 && e.getY() >= 70 && e .getY() <= 170)) { this.repaint(); // JOptionPane.showMessageDialog(null,e.getX()+ "\n" + e.getY()); } } @Override public void mouseEntered(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mouseExited(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mousePressed(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mouseReleased(MouseEvent e) { // TODO Auto-generated method stub } } This Works Except it fires when the click is within a virtual box around the oval. Could anyone help me to have it fire when the click is EXACTLY on the oval. Thanks in advance.

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  • SQL only row mapping record fetching

    - by Prasanna
    I have a customer call detail table in which call details of all customer stored. I have to find out the distinct aparty (means our customer ) who only calls our customers (means bparty also be our numbers) . There is no other domestic call , International calls made by A party (our customer) in this case. could you people please help me to find the same data. FILE INPUT oF SAMPLE CDR TABLE ROW NAME VALUES ANUMBER :-any mobile number(Domestic+International); for our customer it must like 70,070,0070,9370) BNUMBER :-any mobile number(Domestic+International); for our customer it must like 70,070,0070,9370 CALLTRANSACTION :-eg: 91,92,93 etc CALLTRANSACTIONTYPEC :-eg: MOC,MTC FILENAME :-MCS_01 etc TIME:- any time value Required Output DISTINCT ANUMBER :-for our customer it mobile number must start with 70 or 070 or 0070 or 9370 BNUMBER :- for our customer it mobile number must start with 70 or 070 or 0070 or 9370 means our customer only calls to our network customer ( No other doestic call or international calls made by our operator)

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  • app can not run on Windows 2003

    - by Carlos_Liu
    I have created a application base on .net framework 2.0 in a windows XP machine, then I copied the app to another Windows 2003 server machine which has installed .net framework 3.5 but the app can't be launched and throught the event view i got the following errors: Event Type: Error Event Source: .NET Runtime 2.0 Error Reporting Event Category: None Event ID: 5000 Date: 5/15/2010 Time: 2:19:39 PM User: N/A Computer: AVCNDAECLIU4 Description: EventType clr20r3, P1 ftacsearchpopup.exe, P2 1.0.0.0, P3 4bee3c42, P4 ftacsearchpopup, P5 1.0.0.0, P6 4bee3c42, P7 11, P8 e, P9 system.io.fileloadexception, P10 NIL. For more information, see Help and Support Center at http://go.microsoft.com/fwlink/events.asp. Data: 0000: 63 00 6c 00 72 00 32 00 c.l.r.2. 0008: 30 00 72 00 33 00 2c 00 0.r.3.,. 0010: 20 00 66 00 74 00 61 00 .f.t.a. 0018: 63 00 73 00 65 00 61 00 c.s.e.a. 0020: 72 00 63 00 68 00 70 00 r.c.h.p. 0028: 6f 00 70 00 75 00 70 00 o.p.u.p. 0030: 2e 00 65 00 78 00 65 00 ..e.x.e. 0038: 2c 00 20 00 31 00 2e 00 ,. .1... 0040: 30 00 2e 00 30 00 2e 00 0...0... 0048: 30 00 2c 00 20 00 34 00 0.,. .4. 0050: 62 00 65 00 65 00 33 00 b.e.e.3. 0058: 63 00 34 00 32 00 2c 00 c.4.2.,. 0060: 20 00 66 00 74 00 61 00 .f.t.a. 0068: 63 00 73 00 65 00 61 00 c.s.e.a. 0070: 72 00 63 00 68 00 70 00 r.c.h.p. 0078: 6f 00 70 00 75 00 70 00 o.p.u.p. 0080: 2c 00 20 00 31 00 2e 00 ,. .1... 0088: 30 00 2e 00 30 00 2e 00 0...0... 0090: 30 00 2c 00 20 00 34 00 0.,. .4. 0098: 62 00 65 00 65 00 33 00 b.e.e.3. 00a0: 63 00 34 00 32 00 2c 00 c.4.2.,. 00a8: 20 00 31 00 31 00 2c 00 .1.1.,. 00b0: 20 00 65 00 2c 00 20 00 .e.,. . 00b8: 73 00 79 00 73 00 74 00 s.y.s.t. 00c0: 65 00 6d 00 2e 00 69 00 e.m...i. 00c8: 6f 00 2e 00 66 00 69 00 o...f.i. 00d0: 6c 00 65 00 6c 00 6f 00 l.e.l.o. 00d8: 61 00 64 00 65 00 78 00 a.d.e.x. 00e0: 63 00 65 00 70 00 74 00 c.e.p.t. 00e8: 69 00 6f 00 6e 00 20 00 i.o.n. . 00f0: 4e 00 49 00 4c 00 0d 00 N.I.L... 00f8: 0a 00 ..

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  • Correlation formula explanation needed d3.js

    - by divakar
    function getCorrelation(xArray, yArray) { alert(xArray); alert(yArray); function sum(m, v) {return m + v;} function sumSquares(m, v) {return m + v * v;} function filterNaN(m, v, i) {isNaN(v) ? null : m.push(i); return m;} // clean the data (because we know that some values are missing) var xNaN = _.reduce(xArray, filterNaN , []); var yNaN = _.reduce(yArray, filterNaN , []); var include = _.intersection(xNaN, yNaN); var fX = _.map(include, function(d) {return xArray[d];}); var fY = _.map(include, function(d) {return yArray[d];}); var sumX = _.reduce(fX, sum, 0); var sumY = _.reduce(fY, sum, 0); var sumX2 = _.reduce(fX, sumSquares, 0); var sumY2 = _.reduce(fY, sumSquares, 0); var sumXY = _.reduce(fX, function(m, v, i) {return m + v * fY[i];}, 0); var n = fX.length; var ntor = ( ( sumXY ) - ( sumX * sumY / n) ); var dtorX = sumX2 - ( sumX * sumX / n); var dtorY = sumY2 - ( sumY * sumY / n); var r = ntor / (Math.sqrt( dtorX * dtorY )); // Pearson ( http://www.stat.wmich.edu/s216/book/node122.html ) var m = ntor / dtorX; // y = mx + b var b = ( sumY - m * sumX ) / n; // console.log(r, m, b); return {r: r, m: m, b: b}; } I have finding correlation between the points i plot using this function which is not written by me. my xarray=[120,110,130,132,120,118,134,105,120,0,0,0,0,137,125,120,127,120,160,120,148] yarray=[80,70,70,80,70,62,69,70,70,62,90,42,80,72,0,0,0,0,78,82,68,60,58,82,60,76,86,82,70] I can t able to understand the function perfectly. Can anybody explain it with the data i pasted here. I also wanted to remove the zeros getting calculated from this function.

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  • ASA 5540 v8.4(3) vpn to ASA 5505 v8.2(5), tunnel up but I cant ping from 5505 to IP on other side

    - by user223833
    I am having problems pinging from a 5505(remote) to IP 10.160.70.10 in the network behind the 5540(HQ side). 5505 inside IP: 10.56.0.1 Out: 71.43.109.226 5540 Inside: 10.1.0.8 out: 64.129.214.27 I Can ping from 5540 to 5505 inside 10.56.0.1. I also ran ASDM packet tracer in both directions, it is ok from 5540 to 5505, but drops the packet from 5505 to 5540. It gets through the ACL and dies at the NAT. Here is the 5505 config, I am sure it is something simple I am missing. ASA Version 8.2(5) ! hostname ASA-CITYSOUTHDEPOT domain-name rngint.net names ! interface Ethernet0/0 switchport access vlan 2 ! interface Ethernet0/1 ! interface Ethernet0/2 ! interface Ethernet0/3 ! interface Ethernet0/4 ! interface Ethernet0/5 ! interface Ethernet0/6 ! interface Ethernet0/7 ! interface Vlan1 nameif inside security-level 100 ip address 10.56.0.1 255.255.0.0 ! interface Vlan2 nameif outside security-level 0 ip address 71.43.109.226 255.255.255.252 ! banner motd ***ASA-CITYSOUTHDEPOT*** banner asdm CITY SOUTH DEPOT ASA5505 ftp mode passive clock timezone EST -5 clock summer-time EDT recurring dns server-group DefaultDNS domain-name rngint.net access-list outside_1_cryptomap extended permit ip host 71.43.109.226 host 10.1.0.125 access-list outside_1_cryptomap extended permit ip 10.56.0.0 255.255.0.0 10.0.0.0 255.0.0.0 access-list outside_1_cryptomap extended permit ip 10.56.0.0 255.255.0.0 10.106.70.0 255.255.255.0 access-list outside_1_cryptomap extended permit ip 10.56.0.0 255.255.0.0 10.106.130.0 255.255.255.0 access-list outside_1_cryptomap extended permit ip host 71.43.109.226 host 10.160.70.10 access-list inside_nat0_outbound extended permit ip host 71.43.109.226 host 10.1.0.125 access-list inside_nat0_outbound extended permit ip 10.56.0.0 255.255.0.0 10.0.0.0 255.0.0.0 access-list inside_nat0_outbound extended permit ip 10.56.0.0 255.255.0.0 10.106.130.0 255.255.255.0 access-list inside_nat0_outbound extended permit ip 10.56.0.0 255.255.0.0 10.106.70.0 255.255.255.0 access-list inside_nat0_outbound extended permit ip host 71.43.109.226 10.106.70.0 255.255.255.0 pager lines 24 logging enable logging buffer-size 25000 logging buffered informational logging asdm warnings mtu inside 1500 mtu outside 1500 icmp unreachable rate-limit 1 burst-size 1 icmp permit any inside no asdm history enable arp timeout 14400 global (outside) 1 interface nat (inside) 0 access-list inside_nat0_outbound nat (inside) 1 0.0.0.0 0.0.0.0 route outside 0.0.0.0 0.0.0.0 71.43.109.225 1 timeout xlate 3:00:00 timeout conn 1:00:00 half-closed 0:10:00 udp 0:02:00 icmp 0:00:02 timeout sunrpc 0:10:00 h323 0:05:00 h225 1:00:00 mgcp 0:05:00 mgcp-pat 0:05:00 timeout sip 0:30:00 sip_media 0:02:00 sip-invite 0:03:00 sip-disconnect 0:02:00 timeout sip-provisional-media 0:02:00 uauth 0:05:00 absolute timeout tcp-proxy-reassembly 0:01:00 timeout floating-conn 0:00:00 dynamic-access-policy-record DfltAccessPolicy aaa-server TACACS+ protocol tacacs+ aaa-server TACACS+ (inside) host 10.106.70.36 key ***** aaa authentication http console LOCAL aaa authentication ssh console LOCAL aaa authorization exec authentication-server http server enable http 192.168.1.0 255.255.255.0 inside http 10.0.0.0 255.0.0.0 inside http 0.0.0.0 0.0.0.0 outside snmp-server host inside 10.106.70.7 community ***** no snmp-server location no snmp-server contact snmp-server community ***** snmp-server enable traps snmp authentication linkup linkdown coldstart crypto ipsec transform-set ESP-3DES-SHA esp-3des esp-sha-hmac crypto ipsec transform-set ESP-AES-128-SHA esp-aes esp-sha-hmac crypto ipsec transform-set ESP-AES-128-MD5 esp-aes esp-md5-hmac crypto ipsec transform-set ESP-AES-192-SHA esp-aes-192 esp-sha-hmac crypto ipsec transform-set ESP-AES-192-MD5 esp-aes-192 esp-md5-hmac crypto ipsec transform-set ESP-AES-256-SHA esp-aes-256 esp-sha-hmac crypto ipsec transform-set ESP-AES-256-MD5 esp-aes-256 esp-md5-hmac crypto ipsec transform-set ESP-3DES-MD5 esp-3des esp-md5-hmac crypto ipsec transform-set ESP-DES-SHA esp-des esp-sha-hmac crypto ipsec transform-set ESP-DES-MD5 esp-des esp-md5-hmac crypto ipsec security-association lifetime seconds 28800 crypto ipsec security-association lifetime kilobytes 4608000 crypto map outside_map 1 match address outside_1_cryptomap crypto map outside_map 1 set pfs group1 crypto map outside_map 1 set peer 64.129.214.27 crypto map outside_map 1 set transform-set ESP-3DES-SHA crypto map outside_map interface outside crypto isakmp enable outside crypto isakmp policy 1 authentication pre-share encryption des hash md5 group 2 lifetime 86400 telnet timeout 5 ssh 10.0.0.0 255.0.0.0 inside ssh 0.0.0.0 0.0.0.0 outside ssh timeout 5 console timeout 0 management-access inside dhcpd auto_config outside ! dhcpd address 10.56.0.100-10.56.0.121 inside dhcpd dns 10.1.0.125 interface inside dhcpd auto_config outside interface inside ! dhcprelay server 10.1.0.125 outside dhcprelay enable inside dhcprelay setroute inside dhcprelay timeout 60 threat-detection basic-threat threat-detection statistics access-list no threat-detection statistics tcp-intercept tftp-server inside 10.1.1.25 CITYSOUTHDEPOT-ASA-Confg webvpn tunnel-group 64.129.214.27 type ipsec-l2l tunnel-group 64.129.214.27 ipsec-attributes pre-shared-key ***** ! ! prompt hostname context

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  • Update: Super Hero

    While I was looking for a completely different article back in 2007, I came across my Super Hero & Super Villain rating... Well, it was time for an update: Your Super Hero results: You are Spider-Man Spider-Man 75% Supergirl 70% Green Lantern 70% Robin 57% The Flash 55% Hulk 50% Catwoman 50% Superman 45% Batman 40% Wonder Woman 40% Iron Man 40% You are intelligent, witty, a bit geeky and have great power and responsibility. Click here to take the Superhero Personality Test

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  • StyleCop 4.7.32.0 has been released

    - by TATWORTH
    StyleCop 4.7.32.0 was released, 21/June at http://stylecop.codeplex.com/releases/view/79972This version is compatible with the Visual Studio 2012 RC (11.0.50522).Install order should be : VS2010VS2012 RCR#6.1.1 msi (for VS2010)R#7.0 (tested with daily build 7.0.70.189)StyleCop  This version is now compatible with R# 5.1 (5.1.3000.12), R# 6.0 (6.0.2202.688), R# 6.1 (6.1.37.86), R# 6.1.1 (6.1.1000.82) and R# 7.0 (7.0.70.189).

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  • Project Euler 11: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 11.  As always, any feedback is welcome. # Euler 11 # http://projecteuler.net/index.php?section=problems&id=11 # What is the greatest product # of four adjacent numbers in any direction (up, down, left, # right, or diagonally) in the 20 x 20 grid? import time start = time.time() grid = [\ [8,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,8],\ [49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00],\ [81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65],\ [52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91],\ [22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80],\ [24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50],\ [32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70],\ [67,26,20,68,02,62,12,20,95,63,94,39,63,8,40,91,66,49,94,21],\ [24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72],\ [21,36,23,9,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95],\ [78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,9,53,56,92],\ [16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57],\ [86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58],\ [19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40],\ [04,52,8,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66],\ [88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69],\ [04,42,16,73,38,25,39,11,24,94,72,18,8,46,29,32,40,62,76,36],\ [20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16],\ [20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54],\ [01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48]] # left and right max, product = 0, 0 for x in range(0,17): for y in xrange(0,20): product = grid[y][x] * grid[y][x+1] * \ grid[y][x+2] * grid[y][x+3] if product > max : max = product # up and down for x in range(0,20): for y in xrange(0,17): product = grid[y][x] * grid[y+1][x] * \ grid[y+2][x] * grid[y+3][x] if product > max : max = product # diagonal right for x in range(0,17): for y in xrange(0,17): product = grid[y][x] * grid[y+1][x+1] * \ grid[y+2][x+2] * grid[y+3][x+3] if product > max: max = product # diagonal left for x in range(0,17): for y in xrange(0,17): product = grid[y][x+3] * grid[y+1][x+2] * \ grid[y+2][x+1] * grid[y+3][x] if product > max : max = product print max print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • SharePoint 2013 Certifications - MCSE

    - by KunaalKapoor
    Microsoft Certified Solutions Expert (MCSE): SharePoint.Yes you read it right :) SharePoint 2013 Certifications are here... The two certifications mentioned below are expected to be published on February 05, 2013. And will count as credit to the new MCSE certificate. Exams Details:70-331 (Core Solutions of Microsoft SharePoint Server 2013)70-332 (Advanced Solutions of Microsoft SharePoint Server 2013)Classroom Trainings:Course 40028A: First Look Clinic: What’s New for IT Professionals in Microsoft SharePoint Server 2013Course 40027A: First Look Clinic: What’s New for Developers in Microsoft SharePoint 2013Time to prep... Next Stop MCSE...  :)

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  • algorithm for project euler problem no 18

    - by Valentino Ru
    Problem number 18 from Project Euler's site is as follows: By starting at the top of the triangle below and moving to adjacent numbers on the row below, the maximum total from top to bottom is 23. 3 7 4 2 4 6 8 5 9 3 That is, 3 + 7 + 4 + 9 = 23. Find the maximum total from top to bottom of the triangle below: 75 95 64 17 47 82 18 35 87 10 20 04 82 47 65 19 01 23 75 03 34 88 02 77 73 07 63 67 99 65 04 28 06 16 70 92 41 41 26 56 83 40 80 70 33 41 48 72 33 47 32 37 16 94 29 53 71 44 65 25 43 91 52 97 51 14 70 11 33 28 77 73 17 78 39 68 17 57 91 71 52 38 17 14 91 43 58 50 27 29 48 63 66 04 68 89 53 67 30 73 16 69 87 40 31 04 62 98 27 23 09 70 98 73 93 38 53 60 04 23 NOTE: As there are only 16384 routes, it is possible to solve this problem by trying every route. However, Problem 67, is the same challenge with a triangle containing one-hundred rows; it cannot be solved by brute force, and requires a clever method! ;o) The formulation of this problems does not make clear if the "Traversor" is greedy, meaning that he always choosed the child with be higher value the maximum of every single walkthrough is asked The NOTE says, that it is possible to solve this problem by trying every route. This means to me, that is is also possible without! This leads to my actual question: Assumed that not the greedy one is the max, is there any algorithm that finds the max walkthrough value without trying every route and that doesn't act like the greedy algorithm? I implemented an algorithm in Java, putting the values first in a node structure, then applying the greedy algorithm. The result, however, is cosidered as wrong by Project Euler. sum = 0; void findWay(Node node){ sum += node.value; if(node.nodeLeft != null && node.nodeRight != null){ if(node.nodeLeft.value > node.nodeRight.value){ findWay(node.nodeLeft); }else{ findWay(node.nodeRight); } } }

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  • JPA ManyToMany problem...

    - by Parhs
    Hello i have an Entity Exam @Id @GeneratedValue(strategy=GenerationType.TABLE) private Long id; ..... ...... @ManyToMany private List<Exam> exams; @ManyToMany(mappedBy="id") private List<Exam> parentExams; The problem is that @ManyToMany private List<Exam> exams; is ok works great... but this doesnt validate?! @ManyToMany(mappedBy="id") private List<Exam> parentExams; Any idea what to do ? I just want to get the exams that are parents of the current exam. ??e???? ??µ?sµat??? ?aµe??

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  • VLAN Through Switch Doesn't Work

    - by vcsjones
    I have the following scenario: I have a Cisco Aironet 1040 access point. I have it configured with two SSIDs, each going to a different VLAN. So: SSID internal : VLAN 90 SSID guest : VLAN 70 On the router side, I have a Cisco RV220W (with the radios now turned off) and have setup VLANs with like VLAN IDs. VLAN 90 : 192.168.90.0/24 VLAN 70 : 192.168.70.0/24 As far as DHCP is concerned, each VLAN has a "DHCP Server" in the router's configuration: So with the access point connected directly to the router, everything works great. I connect to the internal network, and I get a 192.168.90.x address, and the guest network gets a 70.xxx address. Next I introduced a Cisco SG200-50 PoE switch between the router and the access point. The port is configured as a trunk port, so the VLAN tags should go right through the switch back to the router. However, when something is connected to the access point, nothing works. It isn't able to get an IP address, and manually assigning one doesn't seem to let any traffic route. Given that the access point works correctly when connected to the router directly, I believe the switch is misconfigured. What am I missing here? What can I use to better diagnose what the problem might be? It's small business equipment, so CLI access is not available. Below are screenshots of the switch's config. The access point is connected to GE2.

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  • Intermittent FTP login issues (Microsoft IIS FTP Service)

    - by JaggenSWE
    I've got a somewhat weird problem which I'm not sure how to troubleshoot. We have a FTP running on a Windows Server 2003 machine using the IIS FTP Service, this is for our clients and is configured with IP-restrictions. However, now ONE of the clients starts complaining that they can't log in to the server from time to time. This is just ONE of 10+ clients that have this issue, which makes me think it's a problem on their side. Just to be on the safe side I had a peek into the FTP logs and found something strange. Whenever succeed in loggin in this is what I can find in the logs: nnn.nnn.nnn.70, userxxx, 2012-06-11, 09:22:32, MSFTPSVC1, SERVERNAME, nnn.nn.nn.11, 0, 0, 0, 331, 0, [191747]USER, userxxx, -, nnn.nnn.nnn.70, userxxx, 2012-06-11, 09:22:32, MSFTPSVC1, SERVERNAME, nnn.nn.nn.11, 0, 0, 0, 230, 0, [191747]PASS, -, -, However, if the login fails I see the following events: nnn.nnn.nnn.70, userxxx, 2012-06-11, 09:16:33, MSFTPSVC1, SERVERNAME, nnn.nn.nn.11, 0, 0, 0, 331, 0, [191739]USER, userxxx, -, nnn.nnn.nnn.70, -, 2012-06-11, 09:16:33, MSFTPSVC1, SERVERNAME, nnn.nn.nn.11, 0, 0, 0, 530, 1326, [191739]PASS, -, -, When you look at the event where the clients sends the PASS in the successful login it seems to know that it is infact "userxxx" that is coupled to that PASS, but when it fails it seems to be lost since user in the PASS event is set to "-". Anyone have any ideas around this, any help would be appreciated. :) //JaggenSWE

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  • Oracle Launches New Oracle Database 12c Administrator Certifications

    - by Brandye Barrington
    Today Oracle University announces the release of new Oracle Database 12c Administrator certifications. The new Oracle Database 12c certifications emphasize the foundational and advanced skills needed by Database Administrators and will prepare DBAs to leverage powerful new management and consolidation capabilities, resulting in an even more valuable credential for customers and partners. ORACLE CERTIFIED ASSOCIATE (OCA)  The Oracle Certified Associate (OCA) for Oracle Database 12c objectives measure IT professionals' mastery of day-to-day administration skills and their ability to manage the challenges they're likely to encounter on the job. This credential focuses on SQL skills, operational administration of the Oracle Database including performance and space management, and installing, patching and upgrading the Oracle Database. Earning the OCA credential requires successful completion of two exams: 1Z0-061 - Oracle Database 12c: SQL Fundamentals and 1Z0-062 - Oracle Database 12c: Installation and Administration. The OCA certification track also allows for several alternate exams which can be substituted for 1Z0-061. ORACLE CERTIFIED PROFESSIONAL (OCP) Building on the competencies in the Oracle Database 12c OCA certification, the Oracle Certified Professional (OCP) for Oracle Database 12c certification includes advanced knowledge and skills required of top-performing database administrators. The OCP credential focuses on developing and implementing backup and recovery strategies, designing consolidation strategies to exploit multitenant container and pluggable databases, and thorough understanding how CDB/PDBs fit into the DBaaS cloud-computing model. Today, Oracle is releasing 1Z0-060 - Upgrade to Oracle Database 12c, which allows Oracle Certified Professionals with credentials in Oracle 9i, Oracle Database 10g or Oracle Database 11g to upgrade to Oracle Database 12c with a single exam. The upgrade exam focuses on designing consolidation strategies to exploit multitenant container and pluggable databases, implementing Oracle 12c feature-rich ILM support, optimizing SQL execution using dynamic swapping of sub plans, implementing real-time data redaction within databases, as well as exploiting many additional performance, backup and recovery, security and partitioning enhancements. The exam also includes a thorough review of core DBA skills. Visit the OCP certification track for more details on the new upgrade exam as well as alternate certification paths. ORACLE CERTIFIED MASTER (OCM) The Oracle Certified Master (OCM) for Oracle Database 12c - a very challenging and elite top-level certification - certifies the most highly skilled and experienced database experts. Further information on the 12c OCM level will be announced as exam development concludes. To date, there have been more than 1.6 million Oracle certifications granted worldwide. Explore these certification tracks, exam requirements and objectives, and start toward earning your exciting new Oracle Database 12c certification credentials from Oracle.

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  • NEW: Oracle Practice Exams

    - by Harold Green
    The Oracle University team continues to strive to make high-quality certification preparation tools available to our candidates. In support of this effort, we have expanded our relationship with Kaplan SelfTest.   Kaplan SelfTest is now an Oracle Authorized Practice Test Provider delivering a new feature-rich and fully authorized series of certification practice exams. Practice tests are one of the most effective ways candidates can prepare for an Oracle certification exam. Authorized practice exams help candidates to self assess their knowledge using realistic exam simulations. These practice exams utilize best-in-class practice exam tools including: Learning Mode (fully customize your own practice exam preferences), Certification Mode (simulates a real, timed testing situation) and Flash Cards (self check on key topical concepts). Customers may purchase practice exams from Oracle, with 30-day or 12-month access, or from Kaplan SelfTest directly. As an added benefit, Oracle University Learning Credits may be applied to purchases made from Oracle. View a current list of available practice tests.

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  • Two Sun Certification Exams To Retire August 1, 2010

    - by Paul Sorensen
    Effective August 1, 2010, Exam CX-310-400 ("Sun Certified Integrator for Identity Manager 7.1"), currently part of the "Sun Certified Integrator for Identity Manager 7.1" certification track, will be retired. We will also retire Exam CX-310-502 ("Sun Certified Java CAPS Integrator"), currently within the "Sun Certified Java CAPS Integrator" certification track. Both exams will remain available for registration and testing at Prometric Testing Centers through July 31, 2010.CREDENTIAL VALIDITYPlease note that that these credentials remain valid indefinitely for those holding the certifications. These retirements therefore have no effect on those who complete the certification requirements before August 1, 2010.QUICK LINKSRetiring Exams:Exam CX-310-400 "Sun Certified Integrator for Identity Manager 7.1"Exam CX-310-502 "Sun Certified Java CAPS Integrator" Certification Tracks:Sun Certified Integrator for Identity Manager 7.1Sun Certified Java CAPS IntegratorLearn more: Oracle Certification Retirements

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  • NEW CERTIFICATION: Oracle Certified Expert, Oracle Database 11g Release 2 SQL Tuning

    - by Brandye Barrington
    Oracle Certification announces the release of the new Oracle Certified Expert, Oracle Database 11g Release 2 SQL Tuning certification. This certification is designed forDevelopers, Database Administrators and SQL developers who are proficient at tuning efficient SQL statements. This certification covers topics on core elements such as: identifying and tuning inefficient SQL statements, using automatic SQL tuning, managing optimizer statistics on database objects, implementing partitioning and analyizing queries. Beta testing for the Oracle Database 11g Release 2: SQL Tuning exam (1Z1-117) is now underway and thus is available at the greatly discounted rate of $50 USD. Visit pearsonvue.com/oracle and register for exam 1Z1-117. You can get all preparation details on the Oracle Certification website, including exam objectives, number of questions, time allotments, and pricing. QUICK LINKS: Certification Track: Oracle Certified Expert, Oracle Database 11g Release 2 SQL Tuning Certification Exam: Oracle Database 11g Release 2: SQL Tuning (1Z0-117) Certification Website: About Beta Exams Register Now: Pearson VUE

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  • Why isn't reflection on the SCJP / OCJP?

    - by Nick Rosencrantz
    I read through Kathy Sierra's SCJP study guide and I will read it again more throughly to improve myself as a Java programmer and be able to take the certification either Java 6 or wait for the Java 7 exam (I'm already employed as Java developer so I'm in no hurry to take the exam.) Now I wonder why reflection is not on the exam? The book it seems covers everything that should be on the exam and AFAIK reflection is at least as important as threads if not more used inpractice since many frameworks use reflection. Do you know why reflection is not part of the SCJP? Do you agree that it's at least important to know reflection as threads? Thanks for any answer

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  • Do you want to be an officially certified Oracle ADF Developer?

    - by Grant Ronald
    We have just released an official certification exam for Oracle ADF Development.  This exam is aimed that those who are already getting hands-on with ADF and would like an official certification of their development skills. I was involved in writing some of the exam questions and this was an interesting experience.  We were looking to test not only a knowledge of the framework, but also a practical application of that knowledge.  Trying to do that in a clear question which related to multiple choice questions was sometimes difficult but I think we’ve produced a testing exam which, if you pass, shows a strong practical knowledge of ADF. Enjoy!

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  • Beta Opportunity Soon to Close on "Oracle Database 12c: Installation and Administration" (1Z0-062)

    - by Brandye Barrington
    This is your last opportunity to take the "Oracle Database 12c: Installation and Administration" (1Z1-062) beta exam at the greatly discounted rate of $50 USD, as well as be one of the first to hold this new OCA certification. Earning the Oracle Database 12c Administrator Certified Associate credential gives you the foundational knowledge and skills needed to administer the Oracle Database and sets the stage for your future progression to Oracle Database 12c Administrator Certified Professional.  You can get all preparation details, including exam objectives, number of questions, time allotments, and pricing on the Oracle Certification website. Visit pearsonvue.com/oracle and register for exam 1Z1-062. QUICK LINKS: Certification Track: Oracle Database 12c Administrator Certified Associate Certification Exam: "Oracle Database 12c: Installation and Administration" (1Z1-062) Recommended Training: Oracle Database 12c: Admin, Install and Upgrade Accelerated, Oracle Database 12c: Install and Upgrade Workshop, or Oracle Database 12c: Administration Workshop Certification Website: About Beta Exams Register Now: Pearson VUE

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  • The Real Value Of Certification

    - by Brandye Barrington
    I read a quote recently by Rich Hein of CIO.com "Certifications are, like most things in life: The more you put into them, the more you will get out." This is what we tell candidates all the time. The real value in obtaining a certification is the time spent preparing for the exam. All the hours spent reading books, practicing in hands-on environments, asking questions and searching for answers is valuable. It's valuable preparation for the exam, but it's also valuable preparation for your future job role and for your career. If your goal is just to pass an exam, you've missed a very important part of the value of certification.We receive so many questions through different forms of social media on whether or not certification will help candidates get jobs or get better jobs. Surveys conducted by us and by independent entities all point to the job and salary benefits of certification. However, a key part of that equation is whether a candidate can actually perform successfully in a job role. If preparation time was used to practice and learn and master new skills rather than to memorize a brain dump, the candidate will probably perform successfully in their job role, and job opportunities and higher salary will likely follow. Candidates who do not show that initiative, will not likely reap the full benefits of certification.Keep this in mind as you approach your next certification exam. You are preparing for a career, not an exam. This may help you to be more appreciative of the long hours spent studying!

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