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  • 3 Monitor PCI-e Graphics card on Linux (without tremendous pain)?

    - by N Rahl
    As we are all painfully aware, the only way to get multiple monitors AND compositing (Compiz) on Linux is to use a single graphics card that can drive both (or in my case all three) screens. I bought a Radeon 5750 specifically because it claims to able to drive 3 monitors. I can plug in 3 monitors (2 DVI, 1 HDMI) and the Catalyst Control Center shows all 3, but only 2 can be enabled at a time. The exact message is: The current settings cannot be applied. Possible issues may include: - Display(s) cannot be enabled. - Setting(s) cannot be applied due to insufficient video memory. So I'm going to assume that either the 5750 doesn't support 3 monitors, OR, more likely, ATI couldn't be bothered to add that support to their Linux drivers. So this is a multipart question: First, can anyone suggest a PCI Express Graphics card that can run 3 screens on linux without tremendous pain? I'm looking for something where you install the driver and all three screens "just work". Does such a card exist? Second, if you have a 5750, have you been able to get it to do 3 monitors? I'm running Ubuntu 10.04 at the moment.

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  • Linux: 3 Monitor PCI-e Graphics card (without tremendous pain)?

    - by N Rahl
    As we are all painfully aware, the only way to get multiple monitors AND compositing (Compiz) on Linux is to use a single graphics card that can drive both (or in my case all three) screens. I bought a Radeon 5750 specifically because it claims to able to drive 3 monitors. I can plug in 3 monitors (2 DVI, 1 HDMI) and the Catalyst Control Center shows all 3, but only 2 can be enabled at a time. I'll post the exact error message here soon, but it's very useless. So I'm going to assume that either the 5750 doesn't support 3 monitors, OR, more likely, ATI couldn't be bothered to add that support to their Linux drivers. So this is a multipart question: First, can anyone suggest a PCI Express Graphics card that can run 3 screens on linux without tremendous pain? I'm looking for something where you install the driver and all three screens "just work". Does such a card exist? Second, if you have a 5750, have you been able to get it to do 3 monitors? I'm running Ubuntu 10.04 at the moment. Thanks, Nick

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  • Why Are SPF Records Failing?

    - by robobobobo
    Ok I've been going through various different sites, resources and topics here trying to figure out what is wrong with my SPF records but no matter what I do they don't seem to pass. Here's what I have "v=spf1 +a +mx +ip4:217.78.0.92 +ip4:217.78.0.95 -all" I've tried multiple different tools to check my spf records, some give me a pass, some don't. But I can't send mail to certain google app accounts, they just bounce back all the time which is very annoying. Anyone got any ideas? I have noticed that the source IP address is not the IPV4 addresses I've defined, but Cpanel wouldn't let me add that address into it.. And here's the result of tests I'm getting back from port25.com. I'm running WHM by the way and have enabled spf and dkim. Summary of Results SPF check: fail DomainKeys check: neutral DKIM check: pass Sender-ID check: fail SpamAssassin check: ham Details: HELO hostname: server1.viralbamboo.com Source IP: 2a01:258:f000:6:216:3eff:fe87:9379 mail-from: ###@viralbamboo.com SPF check details: Result: fail (not permitted) ID(s) verified: smtp.mailfrom=###@viralbamboo.com DNS record(s): viralbamboo.com. SPF (no records) viralbamboo.com. 13180 IN TXT "v=spf1 +a +mx +ip4:217.78.0.92 +ip4:217.78.0.95 -all" viralbamboo.com. AAAA (no records) viralbamboo.com. 13180 IN MX 0 viralbamboo.com. viralbamboo.com. AAAA (no records) DomainKeys check details: Result: neutral (message not signed) ID(s) verified: header.From=###@viralbamboo.com DNS record(s): DKIM check details: Result: pass (matches From: ###@viralbamboo.com). ID(s) verified: header.d=viralbamboo.com Canonicalized Headers: content-type:multipart/alternative;'20'boundary="4783D1BE-5685-41CF-B91B-1F15E91DD1E3"'0D''0A' date:Mon,'20'1'20'Jul'20'2013'20'21:30:47'20'+0000'0D''0A' subject:=?utf-8?Q?test?='0D''0A' to:"[email protected]?="'20''0D''0A' from:=?utf-8?Q?Rob_Boland_-_Viralbamboo?='20'<###@viralbamboo.com'0D''0A' mime-version:1.0'0D''0A' dkim-signature:v=1;'20'a=rsa-sha256;'20'q=dns/txt;'20'c=relaxed/relaxed;'20'd=viralbamboo.com;'20's=default;'20'h=Content-Type:Date:Subject:To:From:MIME-Version;'20'bh=CJMO7HYeyNVGvxttf/JspIMoLUiWNE6nlQUg5WjTGZQ=;'20'b=;

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  • 3 Monitor PCI-e Graphics card (without tremendous pain)?

    - by N Rahl
    As we are all painfully aware, the only way to get multiple monitors AND compositing (Compiz) on Linux is to use a single graphics card that can drive both (or in my case all three) screens. I bought a Radeon 5750 specifically because it claims to able to drive 3 monitors. I can plug in 3 monitors (2 DVI, 1 HDMI) and the Catalyst Control Center shows all 3, but only 2 can be enabled at a time. The exact message is: The current settings cannot be applied. Possible issues may include: - Display(s) cannot be enabled. - Setting(s) cannot be applied due to insufficient video memory. So I'm going to assume that either the 5750 doesn't support 3 monitors, OR, more likely, ATI couldn't be bothered to add that support to their Linux drivers. So this is a multipart question: First, can anyone suggest a PCI Express Graphics card that can run 3 screens on linux without tremendous pain? I'm looking for something where you install the driver and all three screens "just work". Does such a card exist? Second, if you have a 5750, have you been able to get it to do 3 monitors? I'm running Ubuntu 10.04 at the moment.

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  • Display database content which is last inserted using last inserted ID

    - by user2330772
    What i am doing is i am displaying last inserted data when form data is submitted,the form is multipart/form-data. I am getting this form data using jquery,here i am sending this data to php file using Ajax POST.In that php file i am inserting that data in db table..where i am getting the id of inserted data..on success of Ajax call i am sending that id to another PHP file..where using that id i am displaying the last inserted data... My form is: <form method="post" enctype="multipart/form-data" name="upload_form" id="data"> <select id="sel"> <option>Select the Project Stream</option> <option value="1">Computer Science</option> <option value="2">Mechanical</option> <option value="3">IT</option> <option value="4">Web Development</option> <option value="5">MCA</option> <option value="6">Civil</option> </select><br /> <input type="text" id="title" placeholder="Project Title"/><br /> <input type="text" id="vurl" placeholder="If You have any video about project write your video url path here" style="width:435px;"/><br /> <textarea id="prjdesc" name="prjdesc" rows="20" cols="80" style="border-style:groove;box-shadow: 10px 10px 10px 10px #888888;"placeholder="Please describe Your Project"></textarea> <label for="file">Filename:</label> <input type="file" name="file" id="file"/><br /> <button>Submit</button> </form> My js file: $("form#data").submit(function() { alert("update"); var sid=$("#sel").val(); alert(sid); var ttle = $("#title").val(); alert(ttle); var text = $("#prjdesc").val(); var vurl = $("#vurl").val(); /*var dataString = 'param='+text+'&param1='+vurl+'&param2='+ttle+'&param3='+id;*/ var formData = new FormData($(this)[0]); formData.append('param',text); formData.append('param1',vurl); formData.append('param2',ttle ); formData.append('param3',sid ); $.ajax({ type:'POST', data:formData, url:'insert.php', success:function(id) { alert(id); window.location ="another.php?id="+id; }, cache: false, contentType: false, processData: false }); return false; }); insert.php: <?php print_r($_FILES); $desc = $_POST['param']; echo $desc; $video = $_POST['param1']; echo $video ; $title = $_POST['param2']; echo $title; $tech_id=$_POST['param3']; echo $tech_id; $host="localhost"; $username="root"; $password=""; $db_name="geny"; $tbl_name="project_details"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $allowedExts = array("gif", "jpeg", "jpg", "png"); $extension = end(explode(".", $_FILES["file"]["name"])); $url_dir = "C:/wamp/www/WebsiteTemplate4/upload/"; if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/jpg") || ($_FILES["file"]["type"] == "image/pjpeg") || ($_FILES["file"]["type"] == "image/x-png") || ($_FILES["file"]["type"] == "image/png")) && ($_FILES["file"]["size"] < 50000) && in_array($extension, $allowedExts)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br>"; } else { if (file_exists($url_dir . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"],$url_dir. $_FILES["file"]["name"]); // echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; $tmp = "C:/wamp/www/WebsiteTemplate4/upload/" . $_FILES["file"]["name"]; $sql="INSERT INTO $tbl_name (title, content, img_path, video_url, project_tech_Id) VALUES ('$title','$desc','$tmp','$video','$tech_id')"; if(mysql_query($sql)) { echo mysql_insert_id(); } else { echo "Cannot Insert"; } } } } else { echo "Invalid file"; } ?> another.php: <?php $temp=$_GET['id']; echo $temp; $host="localhost"; $username="root"; $password=""; $db_name="geny"; $tbl_name="project_details"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $query = mysql_query("SELECT content FROM project_details WHERE id=". $temp); if (!$query) { echo 'Could not run query: ' . mysql_error(); exit; } $row = mysql_fetch_row($query); echo "<div id='uprjct' style='background:#336699;'> <p>$row[0]</p> </div>"; ?> but the ID what i am returning in insert.php containg array of elements...i dont want all these thing i want only ID(which is number).. please tell me what is wrong in my code...

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  • Form File Upload with other TextBox Inputs + Creating Custom Form Action attribute

    - by Jonathan Stowell
    Hi All, I am attempting to create a form where a user is able to enter your typical form values textboxes etc, but also upload a file as part of the form submission. This is my View code it can be seen that the File upload is identified by the MCF id: <% using (Html.BeginForm("Create", "Problem", FormMethod.Post, new { id = "ProblemForm", enctype = "multipart/form-data" })) {%> <p> <label for="StudentEmail">Student Email (*)</label> <br /> <%= Html.TextBox("StudentEmail", Model.Problem.StudentEmail, new { size = "30", maxlength=26 })%> <%= Html.ValidationMessage("StudentEmail", "*") %> </p> <p> <label for="Type">Communication Type (*)</label> <br /> <%= Html.DropDownList("Type") %> <%= Html.ValidationMessage("Type", "*") %> </p> <p> <label for="ProblemDateTime">Problem Date (*)</label> <br /> <%= Html.TextBox("ProblemDateTime", String.Format("{0:d}", Model.Problem.ProblemDateTime), new { maxlength = 10 })%> <%= Html.ValidationMessage("ProblemDateTime", "*") %> </p> <p> <label for="ProblemCategory">Problem Category (* OR Problem Outline)</label> <br /> <%= Html.DropDownList("ProblemCategory", null, "Please Select...")%> <%= Html.ValidationMessage("ProblemCategory", "*")%> </p> <p> <label for="ProblemOutline">Problem Outline (* OR Problem Category)</label> <br /> <%= Html.TextArea("ProblemOutline", Model.Problem.ProblemOutline, 6, 75, new { maxlength = 255 })%> <%= Html.ValidationMessage("ProblemOutline", "*") %> </p> <p> <label for="MCF">Mitigating Circumstance Form</label> <br /> <input id="MCF" type="file" /> <%= Html.ValidationMessage("MCF", "*") %> </p> <p> <label for="MCL">Mitigating Circumstance Level</label> <br /> <%= Html.DropDownList("MCL") %> <%= Html.ValidationMessage("MCL", "*") %> </p> <p> <label for="AbsentFrom">Date Absent From</label> <br /> <%= Html.TextBox("AbsentFrom", String.Format("{0:d}", Model.Problem.AbsentFrom), new { maxlength = 10 })%> <%= Html.ValidationMessage("AbsentFrom", "*") %> </p> <p> <label for="AbsentUntil">Date Absent Until</label> <br /> <%= Html.TextBox("AbsentUntil", String.Format("{0:d}", Model.Problem.AbsentUntil), new { maxlength = 10 })%> <%= Html.ValidationMessage("AbsentUntil", "*") %> </p> <p> <label for="AssessmentID">Assessment Extension</label> <br /> <%= Html.DropDownList("AssessmentID") %> <%= Html.ValidationMessage("AssessmentID", "*") %> <%= Html.TextBox("DateUntil", String.Format("{0:d}", Model.AssessmentExtension.DateUntil), new { maxlength = 16 })%> <%= Html.ValidationMessage("DateUntil", "*") %> </p> <p> <label for="Details">Assessment Extension Details</label> <br /> <%= Html.TextArea("Details", Model.AssessmentExtension.Details, 6, 75, new { maxlength = 255 })%> <%= Html.ValidationMessage("Details", "*") %> </p> <p> <label for="RequestedFollowUp">Requested Follow Up</label> <br /> <%= Html.TextBox("RequestedFollowUp", String.Format("{0:d}", Model.Problem.RequestedFollowUp), new { maxlength = 16 })%> <%= Html.ValidationMessage("RequestedFollowUp", "*") %> </p> <p> <label for="StaffEmail">Staff</label> <br /> <%= Html.ListBox("StaffEmail", Model.StaffEmail, new { @class = "multiselect" })%> <%= Html.ValidationMessage("StaffEmail", "*")%> </p> <p> <input class="button" type="submit" value="Create Problem" /> </p> This is my controller code: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create(Problem problem, AssessmentExtension assessmentExtension, Staff staffMember, HttpPostedFileBase file, string[] StaffEmail) { if (ModelState.IsValid) { try { Student student = studentRepository.GetStudent(problem.StudentEmail); Staff currentUserStaffMember = staffRepository.GetStaffWindowsLogon(User.Identity.Name); var fileName = Path.Combine(Request.MapPath("~/App_Data"), Path.GetFileName(file.FileName)); file.SaveAs(@"C:\Temp\" + fileName); if (problem.RequestedFollowUp.HasValue) { String meetingName = student.FirstName + " " + student.LastName + " " + "Mitigating Circumstance Meeting"; OutlookAppointment outlookAppointment = new OutlookAppointment(currentUserStaffMember.Email, meetingName, (DateTime)problem.RequestedFollowUp, (DateTime)problem.RequestedFollowUp.Value.AddMinutes(30)); } problemRepository.Add(problem); problemRepository.Save(); if (assessmentExtension.DateUntil != null) { assessmentExtension.ProblemID = problem.ProblemID; assessmentExtensionRepository.Add(assessmentExtension); assessmentExtensionRepository.Save(); } ProblemPrivacy problemPrivacy = new ProblemPrivacy(); problemPrivacy.ProblemID = problem.ProblemID; problemPrivacy.StaffEmail = currentUserStaffMember.Email; problemPrivacyRepository.Add(problemPrivacy); if (StaffEmail != null) { for (int i = 0; i < StaffEmail.Length; i++) { ProblemPrivacy probPrivacy = new ProblemPrivacy(); probPrivacy.ProblemID = problem.ProblemID; probPrivacy.StaffEmail = StaffEmail[i]; problemPrivacyRepository.Add(probPrivacy); } } problemPrivacyRepository.Save(); return RedirectToAction("Details", "Student", new { id = student.Email }); } catch { ModelState.AddRuleViolations(problem.GetRuleViolations()); } } return View(new ProblemFormViewModel(problem, assessmentExtension, staffMember)); } This form was working correctly before I had to switch to using a non-AJAX file upload, this was due to an issue with Flash when enabling Windows Authentication which I need to use. It appears that when I submit the form the file is not sent and I am unsure as to why? I have also been unsuccessful in finding an example online where a file upload is used in conjunction with other input types. Another query I have is that for Create, and Edit operations I have used a PartialView for my forms to make my application have higher code reuse. The form action is normally generated by just using: Html.BeginForm() And this populates the action depending on which Url is being used Edit or Create. However when populating HTML attributes you have to provide a action and controller value to pass HTML attributes. using (Html.BeginForm("Create", "Problem", FormMethod.Post, new { id = "ProblemForm", enctype = "multipart/form-data" })) Is it possible to somehow populate the action and controller value depending on the URL to maintain code reuse? Thinking about it whilst typing this I could set two values in the original controller action request view data and then just populate the value using the viewdata values? Any help on these two issues would be appreciated, I'm new to asp.net mvc :-) Thanks, Jon

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  • Zend form and dynamic file upload

    - by DoomStone
    Hello there i'm trying to create a form with Zend_Form that will enable my user to upload a unlited number of files to my site, witch is done by javascript. Something like <script type="text/javascript"> $(document).ready(function(){ var image_uploade_i = 0; $('#upload_more').click(function() { image_uploade_i++; $('#upload_list').append('<div id="image_uploade_id_'+image_uploade_i+'" style="display: none;"><input type="file" name="image[]" /><br /></a>'); $('#image_uploade_id_'+image_uploade_i).slideDown('slow'); }); }); </script> <?=$this->translate('Add images')?> <form action="" method="post" enctype="multipart/form-data"> <div id="upload_list"> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> </div> <a href="#" id="upload_more"><?=$this->translate('Upload another image')?></a><br /> <input type="submit" name="image_uploade" value="<?=$this->translate('Upload images')?>" /> </form> But i'm am unable to find out how i can create something like this with Zend_From, the only reason i want to use Zend_Form on this thoug is for validation of the uploadet files. $element = new Zend_Form_Element_File('image'); $element->setRequired(true) ->setLabel('Profile image') ->setDestination($store) ->setValueDisabled(true) ->addValidator(new Zend_Validate_File_ImageSize(array( 'minheight' => 100, 'minwidth' => 150, 'maxheight' => 1920, 'maxwidth' => 1200))) // File must be below 1.5 Mb ->addValidator(new Zend_Validate_File_FilesSize(array('max' => 1572864))) ->addValidator(new Zend_Validate_File_IsImage()); If any 1 can help me set this up would i be verry great full :D

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  • jQuery upload file using jQuery's ajax method (without plugins)

    - by Daniil Harik
    Hello, At moment I want to implement picture upload without using any plug-ins. My upload form looks like this <form action="/Member/UploadPicture" enctype="multipart/form-data" id="uploadform" method="post"> <span style="display: none;"> <div class="upload" id="imgUpl"> <h3>Upload profile picture</h3> <div class="clear5"></div> <input type="file" name="file" id="file" /> <button class="btn-bl" id="upComplete"><span>Upload</span></button> </div> </span> </form> And my jQuery code is: $('#upComplete').click(function () { $('#up').hide(); $('#upRes').show(); var form = $("#uploadform"); $.ajax({ type: "POST", url: "/Member/UploadPicture", data: form.serialize(), success: function (data) { alert(data); } }); $.fancybox.close(); return false; }); If I open firebug, I can see that ajax() method does simple form post (not multi-part) and POST content is empty Is it possible to do files upload using jQuery ajax() method or should I do this in any other way? Thank You very much

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  • Uploadify plugin doesn't call Java Servlet

    - by sergionni
    Hello,i just started using Uploadify flash plugin instead of standard HTML UI. And met the next problem: when I click "Upload Files" link,that progress is shown and "completed" status is appeared, but in reality - it didn't happened anything,Java Servlet isn't called from backend. There is upload servlet and uploading performed next way earlier: < form enctype="multipart/form-data" method="post" target="uploadFrame" action="<%= request.getContextPath() %>/uploadFile?portletId=${portletId}&remoteFolder=${remoteFolder}">... After providing Uploadify plugin, UI now looks like: plugin part(configuration): <script> ... oScript.text+= "$j('#uploadify').uploadify({"; oScript.text+= "'uploader' : 'kne-portlets/js/lib/uploadify/scripts/uploadify.swf',"; oScript.text+= "'script' : '<%= request.getContextPath() %>/uploadFile?portletId=${portletId}&remoteFolder=<%= decodedString %>',"; oScript.text+= "'cancelImg': 'kne-portlets/js/lib/uploadify/cancel.png',"; oScript.text+= "'folder' : '<%= decodedString %>',"; oScript.text+= "'queueID' : 'fileQueue',"; oScript.text+= "'auto' : false,"; oScript.text+= "'multi' : false,"; //oScript.text+= "'sizeLimit' : 1000"; oScript.text+= "});"; oScript.text+= "});"; ... </script> 'scripts' parameter here points to Java Servlet on backend <%= decodedString %> is folder path, which value is \\file-srv\demo part for uploading: <input type="file" name="uploadify" id="uploadify" /> <a href="javascript:$j('#uploadify').uploadifyUpload();">Upload Files</a> Where is my fault? 'Script' param in plugin config points to Java Servlet on backend and it's done,but Servlet isn't triggered. error, when 'script' param isn't correct:http://img190.imageshack.us/i/errormm.png/ Thank you for assistance.

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  • java.lang.NoClassDefFoundError: javax/servlet/http/HttpServletRequest

    - by pAkY88
    I'm developing a servlet that receives a multipart request with content of multiple files, and I'm using apache commons file upload libraries. When I call parseRequest(request); method servlet throws following exception: GRAVE: Servlet.service() for servlet DiffOntology threw exception java.lang.NoClassDefFoundError: javax/servlet/http/HttpServletRequest at org.apache.commons.fileupload.servlet.ServletRequestContext.getContentType(ServletRequestContext.java:73) at org.apache.commons.fileupload.FileUploadBase$FileItemIteratorImpl.(FileUploadBase.java:882) at org.apache.commons.fileupload.FileUploadBase.getItemIterator(FileUploadBase.java:331) at org.apache.commons.fileupload.FileUploadBase.parseRequest(FileUploadBase.java:349) at org.apache.commons.fileupload.servlet.ServletFileUpload.parseRequest(ServletFileUpload.java:126) at DiffOntology.doPost(DiffOntology.java:38) at javax.servlet.http.HttpServlet.service(HttpServlet.java:637) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.tuckey.web.filters.urlrewrite.UrlRewriteFilter.doFilter(UrlRewriteFilter.java:738) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:619) I put all libraries in WEB-INF/lib.

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  • Parse MIME messages

    - by Abhimanyu
    Hi, For my new project which has email module.i need to show all the email information on web.when i m making a call to server i m getting the base64 encoded mime data. after applying base64 decoding technique i m getting the mime data as follows: /*****************Mime data start *******************************/ From [email protected] Tue Jun 23 12:01:02 2009 Date: Tue, 23 Jun 2009 12:01:02 +0530 From: Prashant R Naik <[email protected]> To: [email protected] Subject: This is a test mail Message-ID: <[email protected]> Reply-To: Prashant R Naik <[email protected]> MIME-Version: 1.0 Content-Type: multipart/mixed; boundary="ReaqsoxgOBHFXBhH" Content-Disposition: inline User-Agent: Mutt/1.5.18 (2008-05-17) Status: RO Content-Length: 1912 Lines: 52 --ReaqsoxgOBHFXBhH Content-Type: text/plain; charset=us-ascii Content-Disposition: inline Test mail. Initiated by prashant Regards, -- Prashant R Naik Principal Technologist | Symbian & Web2.0 Geodesic Limited | www.geodesic.com Tel: +91-80-66551000 --ReaqsoxgOBHFXBhH Content-Type: image/gif Content-Disposition: attachment; filename="trash.gif" Content-Transfer-Encoding: base64 R0lGODlhEAAQANUoADJ8wTqU2DmR1TqV2DN9wTSBxTWFyTaGyTJ9wTWGyTaKzjmS1TOAxTuV 2DaFyTN8wDiN0jiO0jSAxTeKzjqS1DN8wTqR1TWFyjB4vTOBxTmO0TmS1DaKzTeJzTqV1zSA xDJ8wDqS1TeKzTF4vDF4vTiO0f///zuX2gAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAACH5BAEAACgALAAA AAAQABAAAAaDQNRpSCwWhcakcsk8mZ5Qpik5pUKvT2W1uDVWp+BiYNAImAZmz/lcDoQEFoFp QTFtTPKFQLCAREolJiURJhCCJhqAJRMiIhwmjSYdJgqUjQoODgkJJgecBp0mBgYXBx8ZBQxY UAUSDAUACLEPDwgEAAAEIBUEtygkIyMkwMMYw8EjKEEAOw== --ReaqsoxgOBHFXBhH Content-Type: image/jpeg Content-Disposition: attachment; filename="bx.jpg" Content-Transfer-Encoding: base64 /9j/4AAQSkZJRgABAQEASABIAAD/2wBDAAEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEB AQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQH/2wBDAQEBAQEBAQEBAQEBAQEB AQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQEBAQH/wAAR CAAUAAoDAREAAhEBAxEB/8QAFQABAQAAAAAAAAAAAAAAAAAAAAn/xAAYEAEAAwEAAAAAAAAA AAAAAAAAGWen5//EABQBAQAAAAAAAAAAAAAAAAAAAAD/xAAUEQEAAAAAAAAAAAAAAAAAAAAA /9oADAMBAAIRAxEAPwCb4AJHym0Vp3PQJTaK07noJHgA/9k= --ReaqsoxgOBHFXBhH Content-Type: image/png Content-Disposition: attachment; filename="day_bg.png" Content-Transfer-Encoding: base64 iVBORw0KGgoAAAANSUhEUgAAAGQAAAApCAYAAADDJIzmAAAABmJLR0QA/wD/AP+gvaeTAAAA CXBIWXMAAAsTAAALEwEAmpwYAAAAB3RJTUUH2AwCCS0kTriU2QAAAB10RVh0Q29tbWVudABD cmVhdGVkIHdpdGggVGhlIEdJTVDvZCVuAAAAXElEQVR42u3bQQEAMAgDMZiqiZtP5AwbfeQk NO/WvPtLMR0TABEQIAICRECACAgQAREQIAICRECACAgQAREQIAICRECACAgQAREQIAICRECA CAgQARGQ7NpPPasFT+0FZPjBRwYAAAAASUVORK5CYII= --ReaqsoxgOBHFXBhH-- /*****************Mime data end *******************************/ now the problem is i have to parse this data and use it in my application.since this data is not a xml so it difficult to parse it (because parsing with some tag is easy).so any one who knows how to parse mime data help be.i m using erlang to parse this data. Thank you in advance

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  • HTTP POST to Imageshack

    - by Brandon Schlenker
    I am currently uploading images to my server via HTTP POST. Everything works fine using the code below. NSString *UDID = md5([UIDevice currentDevice].uniqueIdentifier); NSString *filename = [NSString stringWithFormat:@"%@-%@", UDID, [NSDate date]]; NSString *urlString = @"http://taptation.com/stationary_data/index.php"; request= [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:urlString]]; [request setHTTPMethod:@"POST"]; NSString *boundary = @"---------------------------14737809831466499882746641449"; NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary]; [request addValue:contentType forHTTPHeaderField: @"Content-Type"]; NSMutableData *postbody = [NSMutableData data]; [postbody appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]]; [postbody appendData:[[NSString stringWithFormat:@"Content-Disposition: form-data; name=\"userfile\"; filename=\"%@.jpg\"\r\n", filename] dataUsingEncoding:NSUTF8StringEncoding]]; [postbody appendData:[[NSString stringWithString:@"Content-Type: application/octet-stream\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [postbody appendData:[NSData dataWithData:imageData]]; [postbody appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]]; [request setHTTPBody:postbody]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; NSLog(returnString); However, when I try to convert this to work with Image Shacks XML API, it doesn't return anything. The directions from ImageShack are below. Send the following variables via POST to imageshack. us /index.php fileupload; (the image) xml = "yes"; (specifies the return of XML) cookie; (registration code, optional) Does anyone know where I should go from here?

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  • File Upload with HttpWebRequest doesn't post the file

    - by Sri Kumar
    Hello All, Here is my code to post the file. I use asp fileupload control to get the file stream. HttpWebRequest requestToSender = (HttpWebRequest)WebRequest.Create("http://localhost:2518/Web/CrossPage.aspx"); requestToSender.Method = "POST"; requestToSender.ContentType = "multipart/form-data"; requestToSender.KeepAlive = true; requestToSender.Credentials = System.Net.CredentialCache.DefaultCredentials; requestToSender.ContentLength = BtnUpload.PostedFile.ContentLength; BinaryReader binaryReader = new BinaryReader(BtnUpload.PostedFile.InputStream); byte[] binData = binaryReader.ReadBytes(BtnUpload.PostedFile.ContentLength); Stream requestStream = requestToSender.GetRequestStream(); requestStream.Write(binData, 0, binData.Length); requestStream.Close(); HttpWebResponse responseFromSender = (HttpWebResponse)requestToSender.GetResponse(); string fromSender = string.Empty; using (StreamReader responseReader = new StreamReader(responseFromSender.GetResponseStream())) { fromSender = responseReader.ReadToEnd(); } XMLString.Text = fromSender; In the page load of CrossPage.aspx i have the following code NameValueCollection postPageCollection = Request.Form; foreach (string name in postPageCollection.AllKeys) { Response.Write(name + " " + postPageCollection[name]); } HttpFileCollection postCollection = Request.Files; foreach (string name in postCollection.AllKeys) { HttpPostedFile aFile = postCollection[name]; aFile.SaveAs(Server.MapPath(".") + "/" + Path.GetFileName(aFile.FileName)); } string strxml = "sample"; Response.Clear(); Response.Write(strxml); I don't get the file in Request.Files. The byte array is created. What was wrong with my HttpWebRequest?

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  • PHP file form question

    - by Jordan Pagaduan
    My Code : <?php function dbAdd($first_name , $image) { //mysql connect database code... mysql_query("INSERT INTO users SET first_name = '".$first_name."', image = '".$image."'"); $mysql_close($sql); } if($_SERVER['REQUEST_METHOD']=='POST') { dbAdd($_POST['first_name'], $_POST['image']); } ?> <form enctype="multipart/form-data" method="post" action=""> First Name : <input type="text" name="first_name" > Image : <input type="file" name="image"> <input type="submit"> </form> The form "file" is to upload. I know that. But I wonder how to get the values so I can put the path of image in the database. The code is already working. The $first_name can already save to the database. Thank you for the answers. Jordan Pagaduan

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  • Django Upload form to S3 img and form validation

    - by citadelgrad
    I'm fairly new to both Django and Python. This is my first time using forms and upload files with django. I can get the uploads and saves to the database to work fine but it fails to valid email or check if the users selected a file to upload. I've spent a lot of time reading documentation trying to figure this out. Thanks! views.py def submit_photo(request): if request.method == 'POST': def store_in_s3(filename, content): conn = S3Connection(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY) bucket = conn.create_bucket(AWS_STORAGE_BUCKET_NAME) mime = mimetypes.guess_type(filename)[0] k = Key(bucket) k.key = filename k.set_metadata("Content-Type", mime) k.set_contents_from_file(content) k.set_acl('public-read') if imghdr.what(request.FILES['image_url']): qw = request.FILES['image_url'] filename = qw.name image = filename content = qw.file url = "http://bpd-public.s3.amazonaws.com/" + image data = {image_url : url, user_email : request.POST['user_email'], user_twittername : request.POST['user_twittername'], user_website : request.POST['user_website'], user_desc : request.POST['user_desc']} s = BeerPhotos(data) if s.is_valid(): #import pdb; pdb.set_trace() s.save() store_in_s3(filename, content) return HttpResponseRedirect(reverse('photos.views.thanks')) return s.errors else: return errors else: form = BeerPhotoForm() return render_to_response('photos/submit_photos.html', locals(),context_instance=RequestContext(request) forms.py class BeerPhotoForm(forms.Form): image_url = forms.ImageField(widget=forms.FileInput, required=True,label='Beer',help_text='Select a image of no more than 2MB.') user_email = forms.EmailField(required=True,help_text='Please type a valid e-mail address.') user_twittername = forms.CharField() user_website = forms.URLField(max_length=128,) user_desc = forms.CharField(required=True,widget=forms.Textarea,label='Description',) template.html <div id="stylized" class="myform"> <form action="." method="post" enctype="multipart/form-data" width="450px"> <h1>Photo Submission</h1> {% for field in form %} {{ field.errors }} {{ field.label_tag }} {{ field }} {% endfor %} <label><span>Click here</span></label> <input type="submit" class="greenbutton" value="Submit your Photo" /> </form> </div>

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  • Paperclip wont save image in rails app

    - by Micke
    Hello stackoverflow. I am trying to use Paperclip with my rails app to add an avatar to a user but it wont save my image when creating the user. This is what the model looks like: class User < ActiveRecord::Base has_attached_file :avatar And the registerform in haml: - form_for :user, @user, :url => { :action => "signup" }, :html => { :multipart => true } do |f| ... ... %li %div{:class => "header"} Profilepicture %div{:class => "input"} = f.file_field :avatar And when i look in the log this is what is being passet to the "signup" action: Parameters: {"commit"=>"Save", "action"=>"signup", "controller"=>"user/register", "user"=>{"name"=>"Micke Lisinge", "birthmonth"=>"07", "password_confirmation"=>"[FILTERED]", "nickname"=>"lisinge", "avatar"=>#<File:/tmp/RackMultipart20100426-3076-1x04oxy-0>, "gen"=>"m", "birthday"=>"23", "password"=>"[FILTERED]", "birthyear"=>"1992", "email"=>"[email protected]"}} [paperclip] Saving attachments. Paperclip says it is saving the template but when i look in the public folder in my app it has created a system but the system folder is empty. So it seems like it isnt saving the picture to the folder. It gets handled by the form and saved in my /tmp folder. Maybe you guys have any tips or know what this problem might be? Thanks in advance, Micke.

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  • Ideas on C# DSL syntax

    - by Dmitriy Nagirnyak
    Hi, I am thinking about implementing a templating engine using only the plain C#/.NET 4 syntax with the benefit of static typing. Then on top of that templating language we could create Domain Specific Languages (let's say HTML4, XHTML, HTML5, RSS, Atom, Multipart Emails and so on). One of the best DSLs in .NET 4 (if not only one) is SharpDOM. It implements HTML-specific DSL. Looking at SharpDOM, I am really impressed of what you can do using .NET (4). So I believe there are some not-so-well-known ways for implementing custom DSLs in .NET 4. Possibly not as well as in Ruby, but still. So my the question would be: what are the C# (4) specific syntax features that can be used for implementing custom DSLs? Examples I can think of right now: // HTML - doesn't look tooo readable :) div(clas: "head", ul(clas: "menu", id: "main-menu", () => { foreach(var item in allItems) { li(item.Name) } }) // See how much noise it has with all the closing brackets? ) // Plain text (Email or something) - probably too simple Line("Dear {0}", user.Name); Line("You have been kicked off from this site"); For me it is really hard to come up with the syntax with least amount of noise. Please NOTE that I am not talking about another language (Boo, IronRuby etc), neither I am not talking about different templating engines (NHaml, Spark, StringTemplate etc). Thanks, Dmitriy.

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  • jQuery AJAX call not working in Webkit

    - by Brian
    I've run into a strange issue with Webkit based browsers (both Safari and Chrome - I'm testing on a Mac) and I am not sure what is causing it. Here's a small script I've created that replicates the issue: <html> <head> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript" language="javascript"> function doRequest() { document.test.submit(); $.ajax({ type: "GET", cache: false, url: 'ajax.php?tmp=1', success: doSuccess }); } function doSuccess(t_data,t_status,req) { alert('Data is: '+ t_data +', XMLHTTPRequest status is: '+ req.status); } </script> </head> <body> <form name="test" method="post" action="ajax.html" enctype="multipart/form-data"> <input type="file" name="file_1"> <br><input type="button" value="upload" onclick="doRequest();"> </form> </body> </html> ajax.php is: <?php echo $_REQUEST['tmp']; ?> This works as is on Firefox, but the XMLHTTPRequest status is always "0" on both Safari and Chrome. If I remove this line: document.test.submit(); then it works, but of course the form is not submitted. I've tried changing the form submit button from "button" to "submit", but that also prevents it from working on Safari or Chrome. What I am trying to accomplish is: submit the form call another script to get status on the file being uploaded via the form (it's for a small upload progress meter). Any help is really appreciated - I'm hopeful it is just a quirk I'm not familiar with. Thanks! Brian

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  • How to upload a file with watir and IE?

    - by karlthorwald
    I am writing a watir script to test an upload form. But the script does not automatically choose the file that is to be uploaded from my harddrive. Instead IE stops with the file chooser dialog open. As soon as I manually select the to be uploaded file in the dialog and click ok, watir continues as desired. I wonder why it stops. This is from my watir script: ie.file_field(:name, 'upload').set("s:\\localwatir\\Test_Pdf.pdf") ie.button(:name, 'submit').click I got the code from this page: http://wiki.openqa.org/display/WTR/File+Uploads This is the form: <form name="form1" enctype="multipart/form-data" method="post" action="uploadlegacy.php"> <input type="file" name="upload" size="30"> <input type="submit" name="submit" value="upload"> </form> I have found this manual http://svn.openqa.org/svn/watir/trunk/watir/unittests/filefield_test.rb also, but as I do not know what $htmlRoot stands for, I cannot really follow it. Does that mean, I have to put some "file///" into the parameter for set()? If so, how exactly? I am using IE 6 for the testing.

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  • RedirectToAction and validate MVC 2

    - by Dan
    Hi, my problem is the View where the user typed, the validation. I have to take RedirectToAction on the site because on the site upload a file. Thats my code. My model class public class Person { [Required(ErrorMessage= "Please enter name")] public string name { get; set; } } My View <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<MvcWebRole1.Models.Person>" %> Name <h2>Information Data</h2> <%= Html.ValidationSummary() %> <%using (Html.BeginForm ("upload","Home", FormMethod.Post, new{ enctype ="multipart/form-data" })) {%> <fieldset> <legend>Fields</legend> <p> <label for="name">name:</label> <%= Html.TextBox("name") %> <%= Html.ValidationMessage("name", "*") %> </p> </fieldset> <% } %> and the Controller [AcceptVerbs(HttpVerbs.Post)] public ActionResult upload(FormCollection form) { Person lastname = new Person(); lastname.name = form["name"]; return RedirectToAction("Index"); } Thx for answer my question In advance

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  • JQuery Validation Plugin: Prevent validation issue on nested form

    - by Majid
    I have a form on which I use validation. This form has a section for photo upload. Initially this section contains six elements with the following code: <img class="photo_upload" src="image/app/photo_upload.jpg"> I have bound a function to the click event for the class of photo_upload. This function replaces the image with a minimal form with this code: Copy code <form onsubmit="startUploadImage();" target="control_target" enctype="multipart/form-data" method="post" action="index.php"> <input type="hidden" value="add_image" name="service"> <input type="hidden" value="1000000" name="MAX_FILE_SIZE"> <input type="file" size="10" name="photo" id="photo_file_upload"><br> <button onclick="javascript:cancel_photo_upload();return false;">Cancel</button> </form> So, essentially, after the image is clicked, I'd have a new form nested in my original, validated form. Now, when I use this new form and upload an image, I receive an error (repeated three times) saying: validator is undefined http://host.com/path/index.php Line 286 What is going on here? My guess is this Submit event bubbles up to the outer form As we have validation on that form, validation is triggered, Validation tries to find the form triggering it, Since we have not bound validation to the inner form it returns 'undefined' Now, is my assessment correct? Whether it is or not, how can I solve this issue?

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  • Django Form Preview

    - by Mark Kecko
    I'm trying to use django's FormPreview and I can't get it to work properly. Here's my code: forms.py class MyForm(forms.ModelForm): status = forms.TypedChoiceField( coerce=int, choices=LIST_STATUS, label="type", widget=forms.RadioSelect ) description = forms.CharField(widget = forms.Textarea) stage = forms.CharField() def __init__(self, useradd=None, *args, **kwargs): super(MyForm, self).__init__(*args, **kwargs) self.fields['firm'].label = "Firm" class Meta: model = MyModel fields = ['status', 'description', 'stage'] class MyFormPreview(FormPreview): form_template = 'templates/post.html' preview_template = 'templates/review.html' def process_preview(self, request, cleaned_data): print "processed" def done(self, request, cleaned_data): print "done" # Do something with the cleaned_data, then redirect # to a "success" page. return HttpResponseRedirect('/') urls.py (r'^post/$', MyFormPreview(MyForm)), post.html <form id = "post_ad" action = "" method = "POST" enctype="multipart/form-data"> <table> {{form.as_table}} </table> <input type="submit" name="save" value="Post" /> </form> When I go to /post/ I get the correct form and I fill it out. When I submit the form it goes right back to /post/ but but there are no errors (I've tried displaying {{errors}}) and the form is empty. None of my print statements execute. I'm not sure what I'm missing. Can anyone help me out? I can't find any documentation besides what's on the django site. Also, what's the "preview" variable called that I should use in my preview.html template? {{preview}} or do I just do {{form}} again? -- Answered below. I tried adding 'django.contrib.formtools' to my installed_apps in settings and I tried using the code from the default form templates from django.contrib as suggested below. Still, when I submit the form I go right back to the post template, none of my print statements execute :(

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  • ActionMailer sent with body unavailable in view

    - by yelvert
    So ive got a ActionMailer mailer class ReportMailer < ActionMailer::Base def notify_doctor_of_updated_document(document) recipients document.user.email_id from "(removed for privacy)" subject "Document #{document.document_number} has been updated and saved as #{document.status}" sent_on Time.now body :document => document end end and the view is Document <%= @document.class %> but when running >> d = Document.last => #<Document id: "fff52d70-7ba2-11de-9b70-001ec9e252ed", document_number: "ABCD1234", procedures_count: 0, user_id: "630", created_at: "2009-07-28 18:18:07", updated_at: "2009-08-30 20:59:41", active: false, facility_id: 94157, status: "incomplete", staff_id: nil, transcriptionist_id: nil, job_length: nil, work_type: nil, transcription_date: nil, non_trans_edit_date: nil, pervasync_flag: true, old_id: nil> >> ReportMailer.deliver_notify_doctor_of_updated_document(d) => #<TMail::Mail port=#<TMail::StringPort:id=0x8185326c> bodyport=#<TMail::StringPort:id=0x8184d6b4>> from the console this is printed in the log Sent mail to (removed for privacy) Date: Tue, 11 May 2010 20:45:14 -0500 From: (removed for privacy) To: (removed for privacy) Subject: Document ABCD1234 has been updated and saved as incomplete Mime-Version: 1.0 Content-Type: multipart/alternative; boundary=mimepart_4bea082ab4ae8_aa4800b81ac13f5 --mimepart_4bea082ab4ae8_aa4800b81ac13f5 Content-Type: text/plain; charset=iso-8859-1 Content-Transfer-Encoding: Quoted-printable Content-Disposition: inline Document NilClass= --mimepart_4bea082ab4ae8_aa4800b81ac13f5--

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  • Custom .NET DSL

    - by Dmitriy Nagirnyak
    Hi, I am thinking about implementing a templating engine using only the plain C#/.NET 4 syntax with the benefit of static typing. Then on top of that templating language we could create Domain Specific Languages (let's say HTML4, XHTML, HTML5, RSS, Atom, Multipart Emails and so on). One of the best DSLs in .NET 4 (if not only one) is SharpDOM. It implements HTML-specific DSL. Looking at SharpDOM, I am really impressed of what you can do using .NET (4). So I believe there are some not-so-well-known ways for implementing custom DSLs in .NET 4. Possibly not as well as in Ruby, but still. So my the question would be: what are the C# (4) specific syntax features that can be used for implementing custom DSLs? Examples I can think of right now: // HTML - doesn't look tooo readable :) div(clas: "head", ul(clas: "menu", id: "main-menu", () => { foreach(var item in allItems) { li(item.Name) } }) // See how much noise it has with all the closing brackets? ) // Plain text (Email or something) - probably too simple Line("Dear {0}", user.Name); Line("You have been kicked off from this site"); For me it is really hard to come up with the syntax with least amount of noise. Please NOTE that I am not talking about another language (Boo, IronRuby etc), neither I am not talking about different templating engines (NHaml, Spark, StringTemplate etc). Thanks, Dmitriy.

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  • There is no attachment in the sent mail by iPhone

    - by naruhodo
    I'm trying to send a recorded sound file as attachment with MFMailComposeViewController. The sound file is OK. The picker shows the correct file name, shows the audio file icon as attachment, sends the mail, but there is no attachment in the result. I attached below the source of the sent mail. There is a "text/plain" content type part instead of "Content-Disposition: attachment;" as expected. This is my code code to define the path and attach the audio file. What could be wrong? #define DOCUMENTS_FOLDER [NSHomeDirectory() stringByAppendingPathComponent:@"Documents"] #define FILEPATH [DOCUMENTS_FOLDER stringByAppendingPathComponent:[self dateString]] ... NSURL *url = [NSURL fileURLWithPath:FILEPATH]; self.recorder = [[AVAudioRecorder alloc] initWithURL:url settings:settings error:&error]; ... MFMailComposeViewController *picker = [[MFMailComposeViewController alloc] init]; picker.mailComposeDelegate = self; NSURL *url = [NSURL fileURLWithPath: [NSString stringWithFormat:@"%@", [self.recorder url]]]; NSData *audioData = [NSData dataWithContentsOfFile:[url path]]; [picker addAttachmentData:audioData mimeType:@"audio/wav" fileName:[[url path] lastPathComponent]]; and the source of the sent mail: Content-type: multipart/mixed; boundary=Apple-Mail-1-614960740 Content-transfer-encoding: 7bit MIME-version: 1.0 (iPod Mail 7E18) Subject: Sound message: Date: Sun, 11 Apr 2010 11:58:56 +0200 X-Mailer: iPod Mail (7E18) --Apple-Mail-1-614960740 Content-Type: text/plain;     charset=us-ascii;     format=flowed Content-Transfer-Encoding: 7bit It is a text here --Apple-Mail-1-614960740 Content-Type: text/plain;     charset=us-ascii;     format=flowed Content-Transfer-Encoding: 7bit Sent from my iPod --Apple-Mail-1-614960740--

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