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  • Can I attach data gathered by a form to a file that is being uploaded?

    - by Jacob
    I need customers to upload files to my website and I want to gather their name or company name and attach it to the file name or create a folder on the server with that as the name so we can keep the files organized. Using PHP to upload file PHP: if(isset($_POST['submit'])){ $target = "upload/"; $file_name = $_FILES['file']['name']; $tmp_dir = $_FILES ['file']['tmp_name']; try{ if(!preg_match('/(jpe?g|psd|ai|eps|zip|rar|tif?f|pdf)$/i', $file_name)) { throw new Exception("Wrong File Type"); exit; } move_uploaded_file($tmp_dir, $target . $file_name); $status = true; } catch (Exception $e) { $fail = true; } } Other PHPw/form: <form enctype="multipart/form-data" action="" method="post"> input type="hidden" name="MAX_FILE_SIZE" value="1073741824" /> label for="file">Choose File to Upload </label> <br />input name="file" type="file" id="file" size="50" maxlength="50" /><br /> input type="submit" name="submit" value="Upload" /> php if(isset($status)) { $yay = "alert-success"; echo "<div class=\"$yay\"> <br/> <h2>Thank You!</h2> <p>File Upload Successful!</p></div>"; } if(isset($fail)) { $boo = "alert-error"; echo "<div class=\"$boo\"> <br/> <h2>Sorry...</h2> <p>There was a problem uploading the file.</p><br/><p>Please make sure that you are trying to upload a file that is less than 50mb and an acceptable file type.</p></div>"; }

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  • C# ...extract email address from inside 100's of text files

    - by Developer
    My SMTP server got 100's of errors when sending lots of emails. Now have lots of .BAD files each one containing an error message and somewhere in the middle, the actual email address it was supposed to be sent to. What is the easiest way to extract from each file "just" the "email address", so that I can have a list of the actual failed emails? I can code in C# and any suggestion will be truly welcomed. BAD SAMPLE TEXT: From: [email protected] To: [email protected] Date: Tue, 25 Sep 2012 12:12:09 -0700 MIME-Version: 1.0 Content-Type: multipart/report; report-type=delivery-status; boundary="9B095B5ADSN=_01CD9B35032DF58000000066my.server.co" X-DSNContext: 7ce717b1 - 1386 - 00000002 - C00402D1 Message-ID: Subject: Delivery Status Notification (Failure) This is a MIME-formatted message. Portions of this message may be unreadable without a MIME-capable mail program. --9B095B5ADSN=_01CD9B35032DF58000000066my.server.co Content-Type: text/plain; charset=unicode-1-1-utf-7 This is an automatically generated Delivery Status Notification. Unable to deliver message to the following recipients, due to being unable to connect successfully to the destination mail server. [email protected] --9B095B5ADSN=_01CD9B35032DF58000000066my.server.com Content-Type: message/delivery-status Reporting-MTA: dns;my.server.com Received-From-MTA: dns;Social Arrival-Date: Tue, 25 Sep 2012 11:45:15 -0700 Final-Recipient: rfc822;[email protected] Action: failed Status: 4.4.7 --9B095B5ADSN=_01CD9B35032DF58000000066my.server.com Content-Type: message/rfc822 Received: from Social ([127.0.0.1]) by my.server.com with Microsoft SMTPSVC(7.5.7601.17514); Tue, 25 Sep 2012 11:45:15 -0700 ====================================== ...and lots more text after ===================== Mainly I want to find the "[email protected]" email right in the middle...

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  • How to run perl script with a few arguments from php

    - by Cristalla
    My html webpage calls php script to upload files to the server from a local computer as follows. <form enctype="multipart/form-data" action="upload.php" method="POST"> <p><b><h3> <font color="#003366"> (1) Upload your reading text file. </font> </h3> </b> </p> <INPUT type="file" name="uploaded" size="50" > <br/> <input type="submit" name="files" value="upload"> </form> In order to process with an uploaded file, my php script calls shell script $output=system('/bin/sh connector_0.sh'); and my shell script is composed of a series of python/perl scripts. #!/bin/sh python main_senselearner_final_0.py senseLearner.pl -i Uploaded_Files/slinput_0.txt -o Uploaded_Files/presloutput_0 .txt -model modelNNCollocations -model modelJJCollocations -model modelVBColloc ations -pos python smutngslout_0.py python genhtml_0.py Now, the problem is the following: all python scripts in shell script worked fine through php. But perl script didn't work. When I run shell script by myself in my server, all four scripts in shell worked perfectly. However, when I run shell script from php, only perl script doesn't work. Would you please give me any tips to solve this problem? Many thanks!!!

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  • Upload file using jquery dialog not working

    - by kandroid
    i want to upload file using jquery dialog. I have created a partial view and showing that partial view in the dialog. The problem is, when I directly browse the partial view and upload a file, it works perfect. BUT when I put the partial view inside a jquery dialog, it submits the form, but don't submits the file. So i have null value. I really dont understand what is the difference here!! Hope someone can help me to identify the problem. here is some codes; jquery codes: $('#UploadDialog').dialog({ autoOpen: false, width: 580, resizable: false, modal: true, open: function (event, ui) { $(this).load('@Url.Action("Upload","Notes")'); }, buttons: { "Upload": function () { $("#upload-message").html(''); $("#noteUploadForm").submit(); }, "Cancel": function () { $(this).dialog("close"); } } }); $(".uploadLink").click(function () { $('#UploadDialog').dialog('open'); }); return false; }); partial view: @using (Ajax.BeginForm("Upload", "Notes", null, new AjaxOptions { UpdateTargetId = "upload-message", InsertionMode = InsertionMode.Replace, HttpMethod = "POST", OnSuccess = "uploadSuccess" }, new { id = "noteUploadForm" , enctype="multipart/form-data"})) { <div> <div id="upload-message"></div> <div class="editLabel"> @Html.LabelFor(m => m.Notes.NoteTitle) </div> <div class="editText"> @Html.TextBoxFor(m => m.Notes.NoteTitle) </div> <div class="clear"></div> <div class="editLabel"> @Html.Label("Upload file") </div> <div class="editText"> <input type="file" name="file" />(100MB max size) </div> </div> }

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  • Uploading File Problem in PHP on Drupal

    - by Nitz
    I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

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  • how to read uploaded files from xampp

    - by user225269
    I have this code for uploading files on the server: <tr> <td> <form enctype="multipart/form-data" action="uploadaction.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> </td> </tr> <tr> <td> Select the image: <input name="uploadedfile" type="file" /> </td> <tr> <td> <input type="submit" value="Upload File" /> </form> </td> </tr> And here's the action form: <?php $target_path = "uploads/"; $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } ?> What php function will I use? Can you give me an example on how to read the file back and display it in the browser? Please help, thanks.

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  • rails 3 actionmailer cannot send email

    - by lkahtz
    I am following Ryan Bates's tutorial on Rails 3 ActionMailer. I generate the mailer in terminal and then establish a setup_mail.rb under config/initializers. I keyed in the following code: ActionMailer::Base.smtp_settings={ :address => "smtp.gmail.com", :port => 587, :domail => "gmail.com", :user_name => "my_account_at_gmail", :password => "my_password", :authentication => "plain" , :enable_starttls_auto => true } My user_mailer.rb file goes like: class UserMailer < ActionMailer::Base default :from => "[email protected]" def registration_confirmation(user) mail(:to => user.email,:subject => "registered") end end I tested in rails console: u=User.first UserMailer.registration_confirmation(u).deliver it displays: #<Mail::Message:2194479560, Multipart: false, Headers: <Date: Sat, 26 Feb 2011 14:42:06 +0800>, <From: [email protected]>, <To: [email protected]>, <Message-ID: <[email protected]>>, <Subject: registered>, <Mime-Version: 1.0>, <Content-Type: text/plain>, <Content-Transfer-Encoding: 7bit>> BUT I never received the email here... Why? How can I solve this? I guess it is some problem on send_mail.rb file..

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  • <input type="file"> reads only file name not full path

    - by Deep
    I am using Glassfish Server.I have seen the apache file upload to solve it...but i want to implement it in glassfish server. image.html <form action="" method="post" enctype="multipart/form-data"> Select a file: <input type="file" name="first" id="first"/> <br /> <input type="button" name="button" value="upload" id="button" /> <p id="test"></p> <img src='Unknown.png' id="profile_img" height="200px" width="150px"/> </form> test.js $(document).ready(function() { var filepath= $("#first"); $('#button').click(function() { $.ajax({ type: "post", url: "imageservlet", data: "user="+filepath.val(), success: function(msg) { $("#profile_img").attr('src',msg); $("#test").html(msg) .fadeIn("fast"); } }); }); }); imageservlet.java String user=request.getParameter("user"); out.print(user); the output is file name not full path.

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  • Post valuse and upload Image to php server in android

    - by lawat
    I am trying to upload image from android phone to php server with additional values,the method is post my php file look like this if($_POST['val1']){ if($_POST['val2']){ if($_FILE['image']){ ...... } } }else{ echo "Value not found"; } I am doing is URL url=new URL("http://www/......../myfile.php"); HttpURLConnection con=(HttpURLConnection) url.openConnection(); con.setDoInput(true); con.setDoOutput(true); con.setUseCaches(false); con.setRequestMethod("POST");//Enable http POST con.setRequestProperty("Connection", "Keep-Alive"); con.setRequestProperty("Content-Type", "multipart/form-data;boundary="+"****"); connection.setRequestProperty("uploaded_file", imagefilePath); DataOutputStream ostream = new DataOutputStream( con.getOutputStream()); String res=("Content-Disposition: form-data; name=\"val1\""+val1+"****"+ "Content-Disposition: form-data; name=\"val2\""+val2+"****" "Content-Disposition: form-data; name=\"image\";filename=\"" + imagefilePath +"\""+"****"); outputStream.writeBytes(res); my actual problem is values are not posting so first if condition get false and else section is executed that is it give value not found please help me

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  • multiple form submission with one submit

    - by skylab
    I've been trying to think this through and figure out if it is possible or not. I'm using zen-cart as shopping cart software, but what I'd like to do, is hard code a page that is basically a list of 7-9 products, next to each product is a checkbox, so I'd like to figure out a way, via html,javascript or jquery to submit whichever forms(products) are checked to the cart. The typical form submission for a product looks something like this(sometimes there may be one or two additional hidden fields): <form name="cart_quantity" action="index.php?action=add_product" method="post" enctype="multipart/form-data"> <input type="hidden" name="cart_quantity" value="1"> <input type="hidden" name="products_id" value="7"> <input type="hidden" name="id[6]" value="9" id="attrib-6-9"> <input type="image" src="buy_button.png" alt="Add to Cart" title="Instructional Video Part 1: Add to Cart"> </form> There would be 7-9 of these on the page, each with a checkbox, so I'm assuming a script would need to figure out which ones where checked and submit them via the form action? Maybe there is a better way of going about this that I'm not thinking of because a)it's over my head or b)just haven't figured it out yet. Anyway is something like this possible?

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  • How can I measure the time it takes a file to upload to a PHP script?

    - by Gustav Bertram
    I am trying to measure the time a script takes to upload a file to a PHP script, inside the receiving script. Here's a short example: <form action="#" enctype="multipart/form-data" method="post"> Upload: <input type="file" name="datafile" size="40"> <input type="submit" value="Send"> </form> <?php $upload_time = time() - $_SERVER['REQUEST_TIME']; echo $upload_time . " seconds."; I've submitted 4MB, 25MB, 100MB and 1.4GB files. They took anything from a fraction of a second, to almost a minute, yet the script above always yielded 0 seconds. NOTE: I know that this is a duplicate question, but the accepted answer on the other question did not work for me (at least, initially): Detect how long it takes for a file to upload (PHP) I've tried it using PHP 5.3.3 with Apache 2.2.16 on Ubuntu 10.4. UPDATE: I've discovered that both the Apache header and Ajax solutions work. In fact, the solution on the duplicate question also works. The critical element to making these solutions work is to ensure that the following values in the php.ini are sufficiently high: memory_limit = 1000M upload_max_filesize = 1000M post_max_size = 1000M I am accepting the Apache header solution, since it only uses PHP.

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  • XCode Obj-C: Make new NSArray from one key each out of an Array of Dictionaries

    - by user323772
    This actually could be a multipart question. But here's the first part ... I have an array (actually in a plist) of dictionaries. Each dictionary has 3 keys in it: (title), (points), and (description). I am trying to make a NEW array with the values of the key "title" from each dictionary in that first array. Let me explain WHY I am doing this and maybe that will provide a better all around explanation. I am trying to let people pick from a pre-determined list. Heck, if this was a web page it would be very simple since all I really care about are the "points" and the "Title". On a web site I could simply do a drop down combo-box with the "points" being the value and the title being the text for each row. But this is not a web page. So what I am trying to do here is pop out a modal picker when they click the text field. The modal picker shows the alphabetical ordered "titles" from our new array. And whichever one they select, it closes the modal view and assigns that "title" text to the UITextField which cannot be edited by the user. I have some code to get my modal picker to pop out. But I need to feed it an array of just the "titles" of each dictionary in my real array. Thanks in advance (and yes I am a newbie)

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  • Upload to a PHP Server, using Ajax ( XMLHttp POST)

    - by Krishnanunni
    Right now i'm using the below method to Upload a file to PHP <form enctype="multipart/form-data" action="http://sserver.com/fileupload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="30000000" /> <input type="hidden" name="filename" value="file_uploaded.gif" /> <input type="hidden" name="username" value="foobar"/> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> I read the $_POST and $_FILE in php to complete upload like this. $target = $_SERVER['DOCUMENT_ROOT']."/test/upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; echo $target; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } My questions is , can i change the above said code (HTML) to an Ajax XMLHttpRequest without changes in PHP.

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  • ThickBox - update inside without redirect

    - by Alex Maslakov
    ASP.NET MVC and jQuery ThickBox. I show some content in ThickBox. It includes file upload form The view multi-media.apsx (it's strange, the this editor doesn't allow start the line with "<" in the code) form action="/upload/multi-media" method="post" enctype="multipart/form-data" label for="file"File name: input type="file" name="file" id="file" / input type="submit" value="Upload" / <% if (Model.Count > 0) { foreach (FileInfo mediaFile in Model) { <img width="100px" height="100px" src="<%: ResolveUrl("~/audio.png") %>" border="0" alt="<%: mediaFile.Name %>" / //................ After file upload I redirect to /upload/multi-media action and content shows in normal window, not in ThickBox. [ActionName("multi-media"), HttpPost] public ActionResult MultiMedia(HttpPostedFileBase file) { if (file.ContentLength > 0) { file.SaveAs(GenerateNewFileName(fullFileName)); return View("multi-media", model); } } How can I stay into ThickBox after file upload? I need show content in ThickBox all the time, even after the file upload.

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  • Error while sending image through ajax to WCF

    - by Samar Rizvi
    Here is my form: <form id="register" enctype="multipart/form-data"> <input type="text" name="first_name" placeholder="First Name" id="first_name" /> <input type="text" name="last_name" placeholder="Last Name" id="last_name" /> <input type="text" name="input_email" placeholder="Confirm your email" id="input_email" class="loginEmail" /> <input type="password" name="input_password" placeholder="Password" id="input_password" class="loginPassword" /> <input type="password" name="repeat_password" placeholder="Repeat password" id="repeat_password" class="loginPassword" /> <input type="file" name="image_file" id="image_file" /> <div class="logControl"> <div class="memory"></div> <input type="submit" name="submit" value="Register" class="buttonM bBlue" id="register_submit"/> <div class="clear"></div> </div> <p><h3>Or click <a href="login.html">here</a> to login</h3></p> </form> Here is jquery call that I make: function WCFJSON() { $(".memory").html('<img src="images/elements/loaders/7s.gif" />'); Data = new FormData($('form')[0]); $.ajax({ type: 'POST', //GET or POST or PUT or DELETE verb url: "WCFService/Service.svc/Register", // Location of the service data: Data, //Data sent to server async:false, cache:false, contentType: false, // content type sent to server dataType: DataType, //Expected data format from server processdata: false, //True or False success: function(msg) {//On Successfull service call ... }, error: ...// When Service call fails }); } $(document).ready(function(){ $("#register").submit(function(){ $('#input_password').val(CryptoJS.MD5($('#input_password').val())); $('#repeat_password').val(CryptoJS.MD5($('#repeat_password').val())); WCFJSON(); return false; }); }); Now when I submit the form , page refreshes with get elements in the url. But if I remove the file input from the form, jquery works fine.

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  • Forms blank when rendering a partial when using a collection of objects. Help!

    - by dustmoo
    Alright, I know my title is a little obscure but it best describes the problem I am having. Essentially, I have a list of users, and want to be able to edit their information in-line using AJAX. Since the users are showing up in rows, I am using a partial to render the data and the forms (which will be hidden initially by the ajax), however, when the rows are rendered currently only the last item has it's form's fields populated. I suspect this has something to do with the fact that all the form fields have the same id's and it is confusing the DOM. But I don't know how to make sure the id's are unique. Here is a small example: In my view: <%= render :partial => 'shared/user', :collection => @users %> My partial (broke down to just the form) note that I am using the local variable "user" <% form_for user, :html => {:multipart => true} do |f| -%> <%= f.label :name, "Name*" %> <%= f.text_field :title, :class => "input" %> <%= f.label :Address, "Address" %> <%= f.text_field :address, :class => "input" %> <%= f.label :description, "Description*" %> <%= f.text_area :description, :class => "input" %> <% end -%> When the html is rendered each form has a unique id (for the id of the user) but the elements themselves all have the same id, and only the last user form is actually getting populated with values. Does anyone have any ideas?? :) Thanks in advance!

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  • Uploadin Image - Objective C

    - by Sammaeliv
    Hi, i have this code the i find on youtube xD my cuestion is , how do i add an extra parameter NSData *imageData = UIImageJPEGRepresentation(imagen.image,0.0); NSString *urlString = @"http://urlexample.com/upload.php"; NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:urlString]]; [request setHTTPMethod:@"POST"]; NSString *boundary = [NSString stringWithString:@"---------------------------14737809831466499882746641449"]; NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@", boundary]; [request addValue:contentType forHTTPHeaderField:@"Content-Type"]; NSMutableData *body = [NSMutableData data]; [body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"userfile\"; filename=\".jpg\"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[[NSString stringWithString:@"Content-Type: application/octet-stream\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[NSData dataWithData:imageData]]; [body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n", boundary] dataUsingEncoding:NSUTF8StringEncoding]]; [request setHTTPBody:body]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; NSLog(returnString); I try [body appendData:[[NSString stringWithFormat:@"extra=%@",info] dataUsingEncoding:NSUTF8StringEncoding]; hehehe im 100% new on this as you can see... please help me xD

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  • can't upload greater 50MB

    - by Syom
    i want to upload two files. here is the script <? ini_set('memory_limit', "400M"); ini_set('file_uploads', "5"); ini_set('max_execution_time', "900"); ini_set('upload_max_filesize', "400M"); ini_set('post_max_size', "400M"); ?> <form action="form.php" method="post" enctype="multipart/form-data" /> <input type="file" name="video" /> <input type="file" name="picture" > <input type="submit" class="input" value="?????" /> </form> form.php: <? ini_set('memory_limit', "400M"); ini_set('file_uploads', "5"); ini_set('max_execution_time', "900"); ini_set('upload_max_filesize', "400M"); ini_set('post_max_size', "400M"); print_r($_FILES); //returns Array ( ) ?> i've asked about this question here , and i've set ini_set(...) as you see, but when i try to upload the file greater than 50MB, it doesn't happen. could you tell me why?

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  • Can you target Google Chrome? (Yes, you can)

    - by Kyle Sevenoaks
    Hi, I need to position this update button on www.euroworker.no/order (you'll have to add an item to the cart, use the Kjøp button to add and Handlevogn to view the cart). Works in FF and IE. (Although there is another alignment problems with IE) but not in Chrome or Safari. I had it working before, but the only thing I can think of to do is target safari and Chrome. Is this possible? Here's the CSS and HTML(Smarty) for you. HTML(Smarty): {capture assign="cartUpdate"} <div id="cartUpdate"><!--<input type="submit" class="submit" value="{tn _update}" />--> <button type="submit" class="submit" id="oppdatersubmit" name="saveFields" title="Oppdater" value="">&nbsp;</button> </div> {/capture} {assign var="cartUpdate" value=$cartUpdate|@str_split:10000} {php}$GLOBALS['cartUpdate'] = $this->get_template_vars('cartUpdate'); $this->assign_by_ref('GLOBALS', $GLOBALS);{/php} {form action="controller=order action=update" method="POST" enctype="multipart/form-data" handle=$form id="cartItems"} CONTENT {/form} And the CSS: #oppdatersubmit { background-image:url(../../upload/oppdater.png); background-repeat:no-repeat; background-position:left; background-color:none; border:none; overflow:hidden; outline:none; white-space: nowrap; width:77px; height:25px; cursor:pointer; position:absolute; } #cartUpdate { position:absolute; width:160px; height:30px; left:580px; bottom:130px; } Need to change these for Chrome and Safari. Thanks.

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  • Multi-model form problem

    - by raphael_turtle
    (I'm just learning rails so....) I have a photo model and a gallery model, habtm associations and a join table. I'm making a photo gallery. The gallery page has a title field and description field. User creates gallery title, then goes to the photo page and checkboxes each image they want in that gallery. I get the error "undefined method `to_i' for ["1", {"title"="1"}]:Array" when trying to save/update a photo with a gallery title(with the checkbox) <% form_for @photo, :html => {:multipart => true } do |f| %> <%= f.error_messages %> <p> <%= f.label :title %> <%= f.text_field :title %> </p> <p> <%= f.label :description %> <%= f.text_area :description %> </p> <p> <%= f.label :image %> <%= f.file_field :image %> </p> <% for gallery in @photo.galleries %> <% fields_for "painting[gallery_attributes][]", gallery do |g| %> <div> <%= g.check_box :title %> <%= gallery.title %> </div> <% end %> <% end %> <p><%= submit_tag 'Update' %></p> <% end %> How much of this is horribly wrong? Can someone point me in the right direction?, I can't find any tutorials relating to this for 2.3 and above.

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  • Import Excel into Rails app

    - by Jack
    Hi, I am creating a small rails app for personal use and would like to be able to upload excel files to later be validated and added to the database. I had this working previously with csv files, but this has since become impractical. Does anyone know of a tutorial for using the roo or spreadsheet gem to upload the file, display the contents to the user and then add to the database (after validating)? I know this is quite specific, but I want to work through this step by step. All I have so far is an 'import' view: <% form_for :dump, :url=>{:controller=>"students", :action=>"student_import"}, :html => { :multipart => true } do |f| -%> Select an Excel File : <%= f.file_field :excel_file -%> <%= submit_tag 'Submit' -%> <% end -%> But have no idea how to access this uploaded file in the controller. Any suggestions/help would be welcomed. Thanks

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  • Adding a Click event to a submit button and then submitting the form

    - by Abs
    Hello all, I have a form with a submit button. I have attached a click event to that submit button using JQuery. Once I did this my form wasn't submitting, I thought this was because of the event I added- if I remove that click event it submits the form successfully. I have tried giving my form an id and calling the submit function but this was not successful either. What can I do? $('#submit_gen').click(function() { $('#genbtn').html('<img src="images/ajax-loader.gif" alt="loading" />'); $('#action_form').submit(); }); The HTML: <form id="action_form" action="generate.php" method="post" enctype="multipart/form-data"> <input id="file_upload" type="file" name="upload" onchange="file_select();"/> <input type="text" id="overlay_input"> <div id="genbtn" class="genbtn"> <input id="submit_gen" type="submit" value="Upload"> </div> </form> Thanks all

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  • problem when uploading file

    - by Syom
    i have the form, and i want to upload two files. here is the script <form action="form.php" method="post" enctype="multipart/form-data" /> <input type="file" name="video" /> <input type="file" name="picture" > <input type="submit" class="input" value="?????" /> <input type="hidden" name="MAX_FILE_SIZE" value="100000000" /> </form> form.php: <? print_r($_FILES); $video_name = $_FILES["video"]["name"]; $image_name = $_FILES["picture"]["name"]; echo "video",$video_name; echo "image",$image_name; //returns Array ( ) videoimage ?> when i try to upload the file greater than 10MB, it doesn't happen. i try in many browsers. maybe i must change some field in php.ini? but i haven't permission to change them on the server. so what can i do? thanks

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  • how to arrange the checkboxes in 3/3 format on a layout of a form

    - by anwaar
    hi there can anyone plz tell me how to arrange the list of checkboxes of cuisines label which is retrived from the data base and when it is displaying it is not in the order coming side by side all together i want it to be displayed in a 3 by 3 format.here is the code for that: <div id="frmform"> <form name="frmrestaurant" id="frmrestaurant" method="post" onsubmit="" enctype="multipart/form-data"> <p class="msgsignup">Add Restaurant</p> <div id="iderror"></div> <div class="topinputs"> <div> <label for="restaurant_name" class="name">Restaurant Name :</label><input type="text" name="restaurant_name" size="32" id="restaurant_name" value="<?php echo $row->restaurant_name; ?>" class="validate[required,custom[onlyLetter],length[0,100]] text-input" /> </div> </div> <div> <label for="website" class="name">Website :</label><input size="32" type="text" name="website" id="website" value="<?php echo $row->website; ?>" class="validate[required,length[0,100]] text-input" /> </div> <div> <label for="budget" class="name">Budget :</label> <?php echo $this->lists['budget'];?> </div> <div> <label for="idcuisine" class="cuisine" >Cuisine:</label> <?php echo $this->lists['cuisine'] ;?> <div> <label for="idcategory" class="category">Category:</label> <?php echo $this->lists['category'];?> </div> the lists of cuisine and category is not displaying properly. thanks.

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  • Rails Form Submission, User can't be blank

    - by pmanning
    I'm trying to create an event through an event form and I keep getting a form error that says "User can't be blank". The event needs a user_id to post a feed_item showing who created the event. Why can't this event get created? event.rb class Event < ActiveRecord::Base attr_accessible :description, :location, :title, :category_id, :start_date, :start_time, :end_date, :end_time, :image belongs_to :user belongs_to :category has_many :rsvps has_many :users, through: :rsvps, dependent: :destroy mount_uploader :image, ImageUploader validates :title, presence: true, length: { maximum: 60 } validates :user_id, presence: true create_events.rb (database) class CreateEvents < ActiveRecord::Migration def change create_table :events do |t| t.string :title t.date :start_date t.time :start_time t.date :end_date t.time :end_time t.string :location t.string :description t.integer :category_id t.integer :user_id t.timestamps end add_index :events, [:user_id, :created_at] end end events_controller.rb def new @event = Event.new @user = current_user end def create @event = current_user.events.build(params[:event]) if @event.save flash[:success] = "Sesh created!" redirect_to root_url else @feed_items = [] render 'static_pages/home' end end routes.rb SampleApp::Application.routes.draw do resources :users do member do get :following, :followers, :events end end resources :events do member do get :members end end root to: 'static_pages#home' events/new.html.erb <%= form_for @event, :html => {:multipart => true} do |f| %> <%= render 'shared/error_messages', object: @event %>

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