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  • What's the best way to customize / add pages to the admin generator?

    - by Guillaume Flandre
    I'm using Symfony 1.4 and Doctrine. My application's backend was built using Symfony's admin generator. It works great when I want to display basic stuff. But tehre's not a lot of documentation on how to enhance it and add new pages. Let's take an example: I want to list published items on one page and to-be-published items on another one. I've used several ways to that in my application but can't figure out what the best way is: playing with filters and then modify templates depending on where you are? creating another module calling a different table_method? some other technique I don't know about? What's the best practice here? How do you guys usually do to customize your admin?

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  • How do I flag only one of the formsets in django admin ?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). My first solution was to override the validation of the formset but did understand how to do this. (is_correct is displayed as checkbox, and I'd display an error that only one is_correct should be selected.)

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  • How can I call model methods or properties from Django Admin?

    - by kg
    Is there a natural way to display model methods or properties in the Django admin site? In my case I have base statistics for a character that are part of the model, but other things such as status effects which affect the total calculation for that statistic: class Character(models.Model): base_dexterity = models.IntegerField(default=0) @property def dexterity(stat_name): total = self.base_dexterity total += sum(s.dexterity for s in self.status.all()]) return total It would be nice if I could display the total calculated statistic alongside the field to change the base statistic in the Change Character admin page, but it is not clear to me how to incorporate that information into the page.

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  • How to allow sorting in the Django admin by a custom list_display field, which doesn't have a DB fie

    - by Gj
    I have a custom list_display field which is responsible for a column of integers in one of my admin pages. I need to allow staff members to sort according to it. There's a solution for how to acheive that if the integer represents a count/average/etc of some DB field, which is not the case for me. [ the solution for that case is here: http://stackoverflow.com/questions/2168475/django-admin-how-to-sort-by-one-of-the-custom-list-display-fields-that-has-no-da ] Any ideas how I can achieve this sorting without actually creating and maintaining a DB field for the values?

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  • Showing custom model validation exceptions in the Django admin site.

    - by Guy Bowden
    I have a booking model that needs to check if the item being booked out is available. I would like to have the logic behind figuring out if the item is available centralised so that no matter where I save the instance this code validates that it can be saved. At the moment I have this code in a custom save function of my model class: def save(self): if self.is_available(): # my custom check availability function super(MyObj, self).save() else: # this is the bit I'm stuck with.. raise forms.ValidationError('Item already booked for those dates') This works fine - the error is raised if the item is unavailable, and my item is not saved. I can capture the exception from my front end form code, but what about the Django admin site? How can I get my exception to be displayed like any other validation error in the admin site?

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  • How To Collapse Just One Field in Django Admin?

    - by Apreche
    The django admin allows you to specify fieldsets. You properly structure a tuple that groups different fields together. You can also specify classes for certain groups of fields. One of those classes is collapse, which will hide the field under a collapsable area. This is good for hiding rarely used or advanced fields to keep the UI clean. However, I have a situation where I want to hide just one lonesome field on many different apps. This will be a lot of typing to create a full fieldset specification in every admin.py file just to put one field into the collapsed area. It also creates a difficult maintenance situation because I will have to edit the fieldset every time I edit the associated model. I can easily exclude the field entirely using the exclude option. I want something similar for collapse. Is this possible?

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  • Inserting default "admin" user into database during Rails App startup

    - by gbc
    I'm building my first real rails application for a little in-house task. Most of the application tasks require authentication/authorization. The first time the app starts up (or starts with a wiped db), I'd like the process to be: User logs into the admin panel using "admin" & "admin" for authentication info. User navigates to admin credentials editing page and changes name and password to something safer so that "admin" & "admin" is no longer a valid login. To achieve this result, I'd like to stuff a default username & password combination into the database on if the application starts up and detects that there are no user credentials in the 'users' table. For example: if User.count == 0 User.create(:name => "admin", :password => "admin") end However, I'm unsure where to place that code. I tried adding an initializer script in the config/initializers, but the error I received appeared to indicate that the model classes weren't yet loaded into the application. So I'm curious to know at what point I can hook into the application startup cycle and insert data into the database through ActiveRecord before requests are dispatched.

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  • Regain Sudo rights after removing from admin group

    - by berkes
    Hello, I accidentally removed myself from the admin group when editing the user. Now I can no longer use sudo. The error says: ber is not in the sudoers file. This incident will be reported. I booted up in rescue mode, but, when going into root prompt, it asks me for the root password. I don't have one, and providing with my own (first and only ubuntu-user) password, it won't allow entrance. My harddisk is encrypted, but only the /home/user part, not the entire disk, afaik. What can I do?

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  • Windows : Désactiver les privilèges d'admin sécuriserait les ordinateurs, en empêchant l'installatio

    Désactiver les privilèges d'admin sécuriserait les ordinateurs, en empêchant l'installation de malwares Une étude orchestrée par BeyondTrust s'est penchée sur les failles de sécurité atteignant les systèmes Microsoft. Elle montre que les dangers des vulnérabilités peuvent être minimisés si les utilisateurs concernés attendent que les administrateurs des systèmes y appliquent les patchs mensuels fournis par Microsoft. La découverte clé de ce travail est le fait qu'un système soit plus sûr si les droits d'administrateur sont supprimés. Ces droits permettent à un individu d'endosser le rôle de responsable du système, et de l'administrer. Il peut alors contrôler quels logiciels et composants peuvent être ...

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  • Admin user runs slower than the guest account

    - by Mykid
    My user is the Admin, it runs fine, not bugs or anything, I used Ubuntu Tweak for a few things like logging options and the sidebar and Unity Tweak for hotcornes and minimize window and that's about it. My second user (for my mother) is faster. I don't know how or why. Let me know what I need to enter on the terminal to give you more info, if you think it's normal also let me know. I have a Compaq Presario CQ56, Ubuntu 14.04 64bit dual boot with Windows 7 Premium, 3GB of ram DDR3, Celeron(R) Dual-Core CPU T3500 @ 2.10GHz × 2.

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  • How to change Windows admin password from guest user

    - by John Smiith
    How to gain access of admin account of Windows, I activated a guest user and I want to change the admin password from the command line. When I type: net user administrator password the response is System error 5 has occurred. Access is denied I am using winxp pro sp2 I am running this command from cdm.exe and I am running this command from guest user. I actually want to change my admin password from guest user.

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  • Problems Running Cherokee Web Server Admin - config_reader.c:249 - Parsing error

    - by Sebastian
    I'm running Cherokee web server 0.99.30 on (Ubuntu Hardy) and I have been having some issues getting the admin to run property. When I run sudo cherokee-admin -b Login: User: admin One-time Password: {password} Web Interface: URL: http://localhost:9090/ [20/11/2009 22:57:29.733] (error) config_reader.c:249 - Parsing error Cherokee Web Server 0.99.30 (Nov 20 2009): Listening on port ALL:9090, TLS disabled, IPv6 disabled, using epoll, 4096 fds system limit, max. 2041 connections, caching I/O, single thread When I go to the admin page I get a 503 Service Unavailable error page. Any idea about how I could fix this? Thanks

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  • how to login as admin in safemode?

    - by Peter
    My sister has forgotten her password to vista, however i have installed that system so should know the admin password. However I do not know how to log in as admin. i tried to press ctrl+alt+delete twice in safemode to switch to normal login mode, but its not working. I heard that admin account is by default turned off in vista, so it might not work.

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  • How to filter queryset in changelist_view in django admin?

    - by minder
    Let's say I have a site where Users can add Entries through admin panel. Each User has his own Category he is responsible for (each Category has an Editor assigned through ForeingKey/ManyToManyField). When User adds Entry, I limit the choices by using EntryAdmin like this: class EntryAdmin(admin.ModelAdmin): (...) def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == 'category': if request.user.is_superuser: kwargs['queryset'] = Category.objects.all() else: kwargs['queryset'] = Category.objects.filter(editors=request.user) return db_field.formfield(**kwargs) return super(EntryAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs) This way I can limit the categories to which a User can add Entry and it works perfect. Now the tricky part: On the Entry changelist/action page I want to show only those Entries which belong to current User's Category. I tried to do this using this method: def changelist_view(self, request, extra_context=None): if not request.user.is_superuser: self.queryset = self.queryset.filter(editors=request.user) But I get this error: AttributeError: 'function' object has no attribute 'filter' This is strange, because I thought it should be a typical QuerySet. Basically such methods are not well documented and digging through tons of Django code is not my favourite sport. Any ideas how can I achieve my goal?

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  • Can Django admin handle a one-to-many relationship via related_name?

    - by Mat
    The Django admin happily supports many-to-one and many-to-many relationships through an HTML <SELECT> form field, allowing selection of one or many options respectively. There's even a nice Javascript filter_horizontal widget to help. I'm trying to do the same from the one-to-many side through related_name. I don't see how it's much different from many-to-many as far as displaying it in the form is concerned, I just need a multi-select SELECT list. But I cannot simply add the related_name value to my ModelAdmin-derived field list. Does Django support one-to-many fields in this way? My Django model something like this (contrived to simplify the example): class Person(models.Model): ... manager = models.ForeignKey('self', related_name='staff', null=True, blank=True, ) From the Person admin page, I can easily get a <SELECT> list showing all possible staff to choose this person's manager from. I also want to display a multiple-selection <SELECT> list of all the manager's staff. I don't want to use inlines, as I don't want to edit the subordinates details; I do want to be able to add/remove people from the list. (I'm trying to use django-ajax-selects to replace the SELECT widget, but that's by-the-by.)

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  • Joomla 1.6 site cannot add a new extension through admin interface

    - by Ghlouw
    I'm having a very frustrating problem with my Joomla 1.6 site. I cannot add any new extensions through the admin interface. I have tried to upload the extension, or to use the search folder option or even the direct link. Neither of these options work, and all that happens is that the page tries to load forever until it finally timesout with a blank white page (no further error messages). I have tried this with multiple browsers (Chrome,FF,IE) and I have tried it with different extensions (modules, components, templates - all the same result). So I don't think it has anything to do with what I am uploading, but more likely the problem is something with the post action. I have also seen the exact same error occur when I try to update menu items or even create new menu items. I am not getting this error with a duplicate of the site in the dev environment, but only get this on my shared web hosting live server. This is on a Windows IIS / PHP / mySQL environment. Any help would be much appreciated!

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  • Is it possible to change the model name in the django admin site?

    - by luc
    Hello, I am translating a django app and I would like to translate also the homepage of the django admin site. On this page are listed the application names and the model class names. I would like to translate the model class name but I don't find how to give a user-friendly name for a model class. Does anybody know how to do that?

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  • Django admin breaking with non-default primary_key for model with a m2m relationship ?

    - by Gj
    I have a simple Post model with a m2m field to a Tag model. The Tag had for some reason to use a non default primary key. Inside the admin page for a Post, the labels for the multiple selection field for Tags appear, but not the input field itself. I also tried using the filter_horizontal for the tags, but still only the labels appear without the actual field. Any ideas why it breaks and/or workarounds? Thanks!

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  • Rational Application Developer (RAD) 7.5+ and websphere runtime will not pick up jars from projects

    - by Berlin Brown
    With RAD Version: 7.5.3, Java 1.5. I have a couple of different projects. I needed to break out the java code and turn the *.class files into a jar. So basically, same *.class files I just removed the code and then jarred the class files into a jar. I broke the classes into a jar and then included the jar in the project. And I also did an order/export on the jar so that other projects can see the jar. At this point, ideally my project should not have changed because I am using class files in a jar instead of the java code. When I visit my web application in websphere, I get class not found errors on the classes that are now in the jar. Project Structure: A. Project earApp -- will need the webapp B. Project webapp -- will need the project (no jar files or *.java files are found in this project) C. Project javasrc -- the java source and the NEW JAR file are found here. I don't think websphere is acknowledging the jar. Here is the error: java.lang.NoClassDefFoundError: com.MyApp at java.lang.ClassLoader.defineClassImpl(Native Method) at java.lang.ClassLoader.defineClass(ClassLoader.java:258) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:151) at com.ibm.ws.classloader.CompoundClassLoader._defineClass(CompoundClassLoader.java:675) at com.ibm.ws.classloader.CompoundClassLoader.findClass(CompoundClassLoader.java:614) at com.ibm.ws.classloader.CompoundClassLoader.loadClass(CompoundClassLoader.java:431) at java.lang.ClassLoader.loadClass(ClassLoader.java:597) at java.lang.Class.getDeclaredMethodsImpl(Native Method) at java.lang.Class.getDeclaredMethods(Class.java:664) at com.ibm.ws.webcontainer.annotation.data.ScannedAnnotationData.collectMethodAnnotations(ScannedAnnotationData.java:130) at com.ibm.ws.webcontainer.annotation.data.ScannedAnnotationData.<init>(ScannedAnnotationData.java:47) at com.ibm.ws.webcontainer.annotation.AnnotationScanner.scanClass(AnnotationScanner.java:61) at com.ibm.ws.wswebcontainer.webapp.WebApp.processRuntimeAnnotationHelpers(WebApp.java:711) at com.ibm.ws.wswebcontainer.webapp.WebApp.populateJavaNameSpace(WebApp.java:624) at com.ibm.ws.wswebcontainer.webapp.WebApp.initialize(WebApp.java:289) at com.ibm.ws.wswebcontainer.webapp.WebGroup.addWebApplication(WebGroup.java:93) at com.ibm.ws.wswebcontainer.VirtualHost.addWebApplication(VirtualHost.java:162) at com.ibm.ws.wswebcontainer.WebContainer.addWebApp(WebContainer.java:671) at com.ibm.ws.wswebcontainer.WebContainer.addWebApplication(WebContainer.java:624) at com.ibm.ws.webcontainer.component.WebContainerImpl.install(WebContainerImpl.java:395) at com.ibm.ws.webcontainer.component.WebContainerImpl.start(WebContainerImpl.java:611) at com.ibm.ws.runtime.component.ApplicationMgrImpl.start(ApplicationMgrImpl.java:1274) at com.ibm.ws.runtime.component.DeployedApplicationImpl.fireDeployedObjectStart(DeployedApplicationImpl.java:1165) at com.ibm.ws.runtime.component.DeployedModuleImpl.start(DeployedModuleImpl.java:587) at com.ibm.ws.runtime.component.DeployedApplicationImpl.start(DeployedApplicationImpl.java:832) at com.ibm.ws.runtime.component.ApplicationMgrImpl.startApplication(ApplicationMgrImpl.java:921) at com.ibm.ws.runtime.component.ApplicationMgrImpl$AppInitializer.run(ApplicationMgrImpl.java:2124) at com.ibm.wsspi.runtime.component.WsComponentImpl$_AsynchInitializer.run(WsComponentImpl.java:342) at com.ibm.ws.util.ThreadPool$Worker.run(ThreadPool.java:1497) What do you think I need to do?

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  • Some OBI EE Tricks and Tips in the Admin Tool By Gerry Langton

    - by hamsun
    How to set the log level from a Session variable Initialization block As we know it is normal to set the log level non-zero for a particular user when we wish to debug problems. However sometimes it is inconvenient to go into each user’s properties in the Admin tool and update the log level. So I am showing a method which allows the log level to be set for all users via a session initialization block. This is particularly useful for anyone wanting an alternative way to set the log level. The screen shots shown are using the OBIEE 11g SampleApp demo but are applicable to any environment. Open the appropriate rpd in on-line mode and navigate to Manage Variables. Select Session Initialization Blocks, right click in the white space and create a New Initialization Block. I called the Initialization block Set_Loglevel . Now click on ‘Edit Data Source’ to enter the SQL. Chose the ‘Use OBI EE Server’ option for the SQL. This means that the SQL provided must use tables which have been defined in the Physical layer of the RPD, and whilst there is no need to provide a connection pool you must work in On-Line mode. The SQL can access any of the RPD tables and is purely used to return a value of 2. The ‘Test’ button confirms that the SQL is valid. Next, click on the ‘Edit Data Target’ button to add the LOGLEVEL variable to the initialization block. Check the ‘Enable any user to set the value’ option so that this will work for any user. Click OK and the following message will display as LOGLEVEL is a system session variable: Click ‘Yes’. Click ‘OK’ to save the Initialization block. Then check in the On-LIne changes. To test that LOGLEVEL has been set, log in to OBIEE using an administrative login (e.g. weblogic) and reload server metadata, either from the Analysis editor or from Administration > Reload Files and Metadata link. Run a query then navigate to Administration > Manage Sessions and click ‘View Log’ for the query just issued (which should be approximately the last in the list). A log file should exist and with LOGLEVEL set to 2 should include both logical and physical sql. If more diagnostic information is required then set LOGLEVEL to a higher value. If logging is required only for a particular analysis then an alternative method can be used directly from the Analysis editor. Edit the analysis for which debugging is required and click on the Advanced tab. Scroll down to the Advanced SQL clauses section and enter the following in the Prefix box: SET VARIABLE LOGLEVEL = 2; Click the ‘Apply SQL’ button. The SET VARIABLE statement will now prefix the Analysis’s logical SQL. So that any time this analysis is run it will produce a log. You can find information about training for Oracle BI EE products here or in the OU Learning Paths. Please send me an email at [email protected] if you have any further questions. About the Author: Gerry Langton started at Siebel Systems in 1999 working as a technical instructor teaching both Siebel application development and also Siebel Analytics (which subsequently became Oracle BI EE). From 2006 Gerry has worked as Senior Principal Instructor within Oracle University specialising in Oracle BI EE, Oracle BI Publisher and Oracle Data Warehouse development for BI.

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