Search Results

Search found 14260 results on 571 pages for 'regex group'.

Page 11/571 | < Previous Page | 7 8 9 10 11 12 13 14 15 16 17 18  | Next Page >

  • Match regex from right to left?

    - by Balroq
    Hi! Is there any way of matching a regex from right to left? What Im looking for is a regex that gets MODULE WAS INSERTED EVENT LOST SIGNAL ON E1/T1 LINK OFF CRC ERROR EVENT CLK IS DIFF FROM MASTER CLK SRC OF from this input CLI MUX trap received: (022) CL-B MCL-2ETH MODULE WAS INSERTED EVENT 07-05-2010 12:08:40 CLI MUX trap received: (090) IO-2 ML-1E1 EX1 LOST SIGNAL ON E1/T1 LINK OFF 04-06-2010 09:58:58 CLI MUX trap received: (094) IO-2 ML-1E1 EX1 CRC ERROR EVENT 04-06-2010 09:58:59 CLI MUX trap received: (009) CLK IS DIFF FROM MASTER CLK SRC OFF 07-05-2010 12:07:32 If i could have done the matching from right to left I could have written something like everything to right of (EVENT|OFF) until the second appearance of more than one space [ ]+ The best I managed today is to get everything from (022) to EVENT with the regex CLI MUX trap received: \([0-9]+\)[ ]+(.*[ ]+(EVENT|OFF)) But that is not really what I wanted :)

    Read the article

  • replace characters which do not match with the ones in a regex

    - by Cristian Boariu
    Hi, I have this regex: private static final String SPACE_PATH_REGEX ="[a-z|A-Z|0-9|\\/|\\-|\\_|\\+]+"; I check if my string matches this regex and IF NOT, i want to replace all characters which are not here, with "_". I've tried like: private static final String SPACE_PATH_REGEX_EXCLUDE = "[~a-z|A-Z|0-9|\\/|\\-|\\_|\\+]+"; if (myCompanyName.matches(SPACE_PATH_REGEX)) { myNewCompanySpaceName = myCompanyName; } else{ myNewCompanySpaceName = myCompanyName.replaceAll( SPACE_PATH_REGEX_EXCLUDE, "_"); } but it does not work..., so in the 2nd regex "~" seems to not omit the following chars. Any idea?

    Read the article

  • Regex Problem in PHP

    - by Chris
    I'm attempting to utilize the following Regex pattern: $regex = '/Name: [a-zA-Z ]*] [0-9]/'; When testing it in Rubular, it works fine, but when using PHP the expression never returns true, even when it should. Incidentally, if I remove the "[0-9]" part, it works fine. Is there some difference in PHP's regex syntax that I'm overlooking? Edit: I'm looking for the characters "Name:" then a name containing any number of letters or spaces, then a "]", then a space, then a single number. So "Name: Chris] 5" would return true and "Name: Chris] [lorem ipsum]" should return false. I also tried escaping the second bracket "\[" but this did not fix the problem.

    Read the article

  • Regex Pattern for ignoring a custom escape character

    - by user1517464
    I am trying to find a suitable regex for matching pair of custom characters in an input string. These custom characters are replaced by their corresponding html tags. For e.g. The input string can have underscores in pairs to indicate words in bold. Hence, _Name_ outputs as <b>Name</b> However if there is a genuine underscore in the string, it cannot be replaced by "bold" tags and has to be ignored. The genuine underscore has to be preceded by / (I couldn't find a better character, it could be one more underscore or hyphen or whatever). Any single or paired occurrance of this genuine underscore has to be ignored by regex. So far I could come up with this regex: var pattern = @"(?!/)_(.*?)(?!/)_"; But it fails in below input string: _Tom_Katy/_Richard/_/_Stephan_and many users It outputs as <b>Tom</b>Katy/<b>Richard/_/</b>Stephan_and many users Many Thanks in Advance, Pr

    Read the article

  • Having problems getting a PHP regex to match.

    - by dqhendricks
    Here is my problem. It's probably a simple fix. I have a regex that I am using to replace a url BBCode. What I have right now that is not working looks like this. <?php $input_string = '[url=www.test.com]Test[url]'; $regex = '/\[url=(.+?)](.+?)\[\/url]/is'; $replacement_string = '<a href="$1">$2</a>'; echo preg_replace($regex, $replacement_string, $input_string); ?> This currently outputs the original $input_string, while I would like it to output the following. <a href="www.test.com">Test</a> What am I missing?

    Read the article

  • Regex only retrieves the first necessary element but not all of them

    - by Serge
    Can anybody help me with retrieving some elements from the following example text: sdfaasdflj asdfjl;a AB-12/34 BC-/85 CD-//8 DD-77 DE-78/9 EE-78-98 asdf; asdjf It is necessary to get the following elements: AB-12/34, BC-/85, CD-//8, DD-77, DE-78/9 When I'm using a regular expression like this: \s*(?<elements>\b[A-Z]{2}-[/0-9]+\b) everything works fine - all the necessary elements are being retrieved (except for the EE element are amonth them, but it doesn't matter). The problem is that this line is a part of a more complex regex, so when I'm trying to apply a regex like this: (?s).*\sas.*? \s*(?<elements>\b[A-Z]{2}-[/0-9]+\b)*.* .*as It only returns me just the first AB-12/34 element and nothing else. How to correct the regex to get all the elements? TIA.

    Read the article

  • Which is the correct shorthand - "regex" or "regexp".

    - by Vilx-
    Most of us computer programmers are pretty obsessed about correct terminology. I certainly am, especially because sometimes changing just one character in a word can drastically change its meaning. So... what is the correct shorthand for "regular expression"? Is it "regex" or "regexp"? On the internet I see both uses, although "regex" seems to be more popular, and the tag list here on SO also includes just "regex". But plenty of people also use "regexp" in their questions.

    Read the article

  • RegEx - Indexed\Arrayed Named Capture groups?

    - by Josh
    I have a situation where something can appear in a format as follows: ---id-H-- Header: data Another Header: more data Message: sdasdasdasd Message: asdasdasdasd Message: asdasdasd There may be many messages, or just a couple. I'd prefer not having to step outside of RegEx, because I am using the RegEx to parse some header information above the messages and the messages along with the headers are part of the text I am parsing. The messages attached into the text might be many. I would also like to use named capture groups, so something like Message: (?<Message[index of match]>.+) Where it matches the match as many times as it can with the index filled in. Does anything like this exist in RegEx? (I will eventually be using this in Perl)

    Read the article

  • 301 Redirects, and the correct regex to go with it

    - by Tisch
    Hi Guys, I have several URLs that I want to redirect to the same place, however these are dynamic URLs. The structure is something like this: http://www.mysite.com/declaration/list?[query_string] What I think would be ideal for this situation is to use some regex in my .htaccess file to redirect all these links to the sites home page. I was wondering if someone could help me with the regex for this situation. So far, I have this, but it doesn't work: RewriteCond %{QUERY_STRING} ^(.*)$ RewriteRule ^/declaration/list$ http://www.mysite.com/$ [R=301,L] My regex is weak to say the least, something I want to, and am trying to learn. Thanks in advance. Tom

    Read the article

  • Regex in MySql - replace between Tags including Tags

    - by user998163
    I have a text like: [lang_de]Content in German[/lang_de][lang_en]Content in English[/lang_en]. I want to replace all text between [lang_en] and [/lang_en] including the opening and closing language tag. This is my current regex: UPDATE wp_posts SET post_content = '" . addslashes(preg_replace("/[lang_en](.*)[\/lang_en]/", '', $row['post_content'])) . "' WHERE ID = " . $row['ID'] With this regex, I do not get a valid results. It also replaces in html tags and so on. What would be the correct regex?

    Read the article

  • Javascript regex only matching entire url as typing

    - by dt
    I'm trying to use javascript to find all URLs in a textarea as the person is typing (onkeyup). The problem that I'm having is in finding a regex to match the entire URL, I need it only to match all the URL's in the text area that are complete URLs. All of the existing regex expressions that I find through Google and through my own experiementing seem to match as soon as the user has typed the first part of the pattern. So, for example, if I'm typing and then start to type http://w, all of a sudden, it will match. I need to find a regex that will match and return an array of all the urls that are in the textarea, while also not matching unless the person has completed typing the full URL. Hopefully that makes sense! Thank you!

    Read the article

  • C++0x regex in GCC

    - by rwallace
    The following code: #include <regex> using namespace std; (snippage) regex_search(s, m, re); works in Microsoft C++, but GCC 4.4.3 gives the following error message: /usr/include/c++/4.4/tr1_impl/regex:2255: warning: inline function ‘bool std::regex_search(_Bi_iter, _Bi_iter, std::match_results<_Bi_iter, _Allocator&, const std::basic_regex<_Ch_type, _Rx_traits&, std::regex_constants::match_flag_type) [with _Bi_iter = __gnu_cxx::__normal_iterator, std::allocator , _Allocator = std::allocator, std::allocator , _Ch_type = char, _Rx_traits = std::regex_traits]’ used but never defined Of course it wouldn't surprise me if regex were simply one of the C++0x features still on the to-do list for GCC, but what I'm scratching my head over is, in that case, why does it happily take the include directive, variable declarations etc. and only trip over the function call (which it even seems to understand). Is there something I'm missing?

    Read the article

  • Is it possible to use Regex through Hexadecimal to find email addresses

    - by LukeJenx
    Not sure if this is even possible but I have been looking at using Regex to get an email address that is in Hex. Basically this is to build up some of my automated forensic tools but I am having problems on making a suitable Regex algorithm. Regex for email: /^([a-z0-9_.-]+)@([\da-z.-]+).([a-z.]{2,6})$/ Hex values: @ = 40 . = 2E .com = 636f6d _ = 5f A/a = 41/61 [1] Z/z = 5a/7a - = 2d This is what I have got at the moment (it only takes into account lower case and .com). But it doesn't work! Have I messed something simple up? "/^([61-7a]+)40([61-7a]+)23(636f6d)$/" [1] I know email can only be lower case but I need to take uppercase into account too.

    Read the article

  • smaller date regex

    - by Jeremy
    I have a regex used to validate dates: ^(((0[1-9]|[12]\d|3[01])\/(0[13578]|1[02])\/((19|[2-9]\d)\d{2}))|((0[1-9]|[12]\d|30)\/(0[13456789]|1[012])\/((19|[2-9]\d)\d{2}))|((0[1-9]|1\d|2[0-8])\/02\/((19|[2-9]\d)\d{2}))|(29\/02\/((1[6-9]|[2-9]\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))$ Works really well, but I am using it all over the place with asp.net regex validators and I want to minimize it so I can reduce page size. It works with dd/mm/yyyy format and handles leap years. I'm looking for a more concise regex statement.

    Read the article

  • Define a regex, which matches one digit twice and all others once

    - by Amin
    As part of a larger regex I would like to match the following restrictions: The string has 11 digits All digits are numbers Within the first 10 digits one number [0-9] (and one only!) must be listed twice This means the following should match: 12345678914 12235879600 Whereas these should not: 12345678903 -> none of the numbers at digits 1 to 10 appears twice 14427823482 -> one number appears more than twice 72349121762 -> two numbers appear twice I have tried to use a lookahead, but all I'm managing is that the regex counts a certain digit, i.e.: (?!.*0\1{2}) That does not do what I need. Is my query even possible with regex?

    Read the article

  • Regex - replace only last part of an expression

    I'm attempting to find the best methodology for finding a specific pattern and then replace the ending portion of the pattern. Here is a quick example (in C#): //Find any year value starting with a bracket or underscore string patternToFind = "[[_]2007"; Regex yearFind = new Regex(patternToFind); //I want to change any of these values to x2008 where x is the bracket or underscore originally in the text. I was trying to use Regex.Replace(), but cannot figure out if it can be applied. If all else fails, I can find Matches using the MatchCollection and then switch out the 2007 value with 2008; however, I'm hoping for something more elegant MatchCollections matches = yearFind.Matches(" 2007 [2007 _2007"); foreach (Match match in matches){ //use match to find and replace value }

    Read the article

  • xml regular expression/regex OR operator

    - by Naz Haque
    Hi am trying to use a regeX to read through my document to identify currency types whether they're $,£ or a €. The regex I've created doesn't seem to work, somebody please advise me what it should be. I'd really appreciate the help: The regEX I've created ("\$|£|€]")is in a simpleType within my XSD file used for validating a document. The code is show after the colon, please note to display on stackoverflow I've had to remove the open/close tags (<): xs:simpleType name="currencyType" xs:restriction base="utf8-string" xs:length value="1" / xs:pattern value="[\$|£|€]"/ /xs:restriction /xs:simpleType

    Read the article

  • understanding this regex

    - by DarthVader
    I m trying to understand what the following does. ^([^=]+)(?:(?:\\=)(.+))?$ Any ideas? This is being used here. Obviously it s command line parser but i m trying to understand the syntax so i can actually run the program. This is from commandline-jmxclient , they have no documents on setting JMX properties but in their source code, there is such an option, so i just want to understand how i can invoke that method. Matcher m = Client.CMD_LINE_ARGS_PATTERN.matcher(command); if ((m == null) || (!m.matches())) { throw new ParseException("Failed parse of " + command, 0); } this.cmd = m.group(1); if ((m.group(2) != null) && (m.group(2).length() > 0)) this.args = m.group(2).split(","); else this.args = null;

    Read the article

  • Validate Canadian Postal Code Regex

    - by Alex Block
    I have a script written in JavaScript to Validate Canadian Postal Codes using Regex, however it does not seem to be working. Here is the script: If statement: if (myform.zip.value == "" || myform.zip.value == null || myform.zip.value == "Postal Code" || myform.zip.value.length < 12 ) { alert("Please fill in field Postal Code. You should only enter 7 characters"); myform.zip.focus(); return false; } Function: function okNumber(myform) { var regex = /^[ABCEGHJKLMNPRSTVXY]{1}\d{1}[A-Z]{1} *\d{1}[A-Z]{1}\d{1}$/; if (regex.test(myform.zip.value) == false) { alert("Input Valid Postal Code"); myform.zip.focus(); return false; } return true; }

    Read the article

  • Regex expression is too greedy

    - by alastairs
    I'm writing a regular expression to match data from the IMDb soundtracks data file. My regexes are mostly working, although they are in places slurping too much text into my named groups. Take the following regex for example: "^ Performed by '?(?<performer>.*)('? \(qv\))?$" The performer group includes the string ' (qv) as well as the performer's name. Unfortunately, because the records are not consistently formatted, some performers' names are surrounded by single quotation marks whilst others are not. This means they are optional as far as the regex is concerned. I've tried marking the last group as a greedy group using the ?> group specifier, but this appeared to have no effect on the results. I can improve the results by changing the performer group to match a small range of characters, but this reduces my chances of parsing the name out correctly. Furthermore, if I were to just exclude the apostrophe character, I would then be unable to parse, e.g., band names containing apostrophes, such as Elia's Lonely Friends Band who performed Run For Your Life featured in Resident Evil: Apocalypse.

    Read the article

  • Python finding substring between certain characters using regex and replace()

    - by jCuga
    Suppose I have a string with lots of random stuff in it like the following: strJunk ="asdf2adsf29Value=five&lakl23ljk43asdldl" And I'm interested in obtaining the substring sitting between 'Value=' and '&', which in this example would be 'five'. I can use a regex like the following: match = re.search(r'Value=?([^&>]+)', strJunk) >>> print match.group(0) Value=five >>> print match.group(1) five How come match.group(0) is the whole thing 'Value=five' and group(1) is just 'five'? And is there a way for me to just get 'five' as the only result? (This question stems from me only having a tenuous grasp of regex) I am also going to have to make a substitution in this string such such as the following: val1 = match.group(1) strJunk.replace(val1, "six", 1) Which yields: 'asdf2adsf29Value=six&lakl23ljk43asdldl' Considering that I plan on performing the above two tasks (finding the string between 'Value=' and '&', as well as replacing that value) over and over, I was wondering if there are any other more efficient ways of looking for the substring and replacing it in the original string. I'm fine sticking with what I've got but I just want to make sure that I'm not taking up more time than I have to be if better methods are out there.

    Read the article

  • My Java regex isn't capturing the group

    - by Geo
    I'm trying to match the username with a regex. Please don't suggest a split. USERNAME=geo Here's my code: String input = "USERNAME=geo"; Pattern pat = Pattern.compile("USERNAME=(\\w+)"); Matcher mat = pat.matcher(input); if(mat.find()) { System.out.println(mat.group()); } why doesn't it find geo in the group? I noticed that if I use the .group(1), it finds the username. However the group method contains USERNAME=geo. Why?

    Read the article

< Previous Page | 7 8 9 10 11 12 13 14 15 16 17 18  | Next Page >