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  • unable to compile a servlet in ubuntu

    - by codeomnitrix
    I am newbie to j2ee. I have download and installed j2eesdk-1_4_03-linux.bin in my ubuntu 10.04 distribution. and then i tried to code my first servlet in it as: import java.io.*; import javax.servelet.*; import javax.servelet.http.*; public class HowdyServelet extends HttpServelet{ public void doGet(HttpServeletRequest request, HttpServeletResponse response) throws IOException, ServeletException{ PrintWriter out = response.getWriter(); response.setContentType("text/html"); out.println("<html>"); out.println("<head><title>howdy</title></head>"); out.println("<body>"); out.println("<center><h1>Howdy</h1></center>"); out.println("</body>"); out.println("</html>"); } } and here are the environment variables i set after installation: 1. J2EE_HOME=/home/vinit/SUNWappserver 2. JAVA_HOME=/home/vinit/SUNWappserver/jdk 3. CLASSPATH=/home/vinit/SUNWappserver/lib and now i tried to compile the servlet using javac HowdyServelet.java But i got following errors: HowdyServelet.java:2: package javax.servelet does not exist import javax.servelet.*; ^ HowdyServelet.java:3: package javax.servelet.http does not exist import javax.servelet.http.*; ^ HowdyServelet.java:5: cannot find symbol symbol: class HttpServelet public class HowdyServelet extends HttpServelet{ ^ HowdyServelet.java:6: cannot find symbol symbol : class HttpServeletRequest location: class HowdyServelet public void doGet(HttpServeletRequest request, HttpServeletResponse response) throws IOException, ServeletException{ ^ HowdyServelet.java:6: cannot find symbol symbol : class HttpServeletResponse location: class HowdyServelet public void doGet(HttpServeletRequest request, HttpServeletResponse response) throws IOException, ServeletException{ ^ HowdyServelet.java:6: cannot find symbol symbol : class ServeletException location: class HowdyServelet public void doGet(HttpServeletRequest request, HttpServeletResponse response) throws IOException, ServeletException{ ^ 6 errors So how to compile this servlet. Thanks in advance.

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  • get string from outside run programm

    - by Alex Berd
    Hello I have jsp page with text field and button. Also i have jar of another project. When i click on the button the MAIN.class of the jar is called and program is running in independent window(JFrame). After user is finished with the program and exits, I need to get the String of program that is generated on exit and paste it into the textbox (The String is HTML code) Is anyone else having this problem and has a solution? Thanks Alex

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  • How to save, retrieve and draw an image in webapplication using Java and PostgreSQL?

    - by spderosso
    Given an object X; I want this object to have an image. The image must be stored in the database. I can't store the path, the actual image must be in the database. My question can be answered by answering the following subquestions: a). What type of field should I put in the database? (e.g VARCHAR) b) What type of object should I use for storing and manipulating the image (at an object layer)? (e.g java.awt.Image) c) How do I create an object of the type selected (answer of question b) from the data obtained from the database? d) How do I save an object of the type selected (answer of question b) to the database? e) How do I draw the image on a web page? I am using PostgreSQL, Java and it is a web application. Thanks!

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  • Get status of servlet request before the response is returned

    - by Alex
    Good evening, I am in the process of writing a Java Servlet (Struts 2, Tomcat, JSP etc) which is capable of doing some fairly complex simulations. These can take up to 2 minutes to complete on the and will return a graph of the results. It is trivial to calculate the percentage of the simulation completed because the process works by repeating the same calculations 1000s of times. I would be interested to know if anyone has ever tried to use client side technology to provide any estimate of the percentage complete. I.e query the servlet processing to get the number of cycles completed at various point throughout the simulation. This could then be displayed as a bar in the client browser. Any thoughts, advice, resources would be much appreciated. Thanks, Alex

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  • How to handle security constraints using GWT 2.1's RequestFactory?

    - by Marc
    I am currently developing a GWT 2.1 application that is to be deployed on Google App Engine. I would like to realise the server communication using the new RequestFactory. Now my question is how to handle fine-grained security issues in this context? Some server actions (of those declared in the RequestContext stubs) shall be restricted to certain users (possibly depending on the parameters of the remote call). If a call is unauthorised, I would like the client to show a login page (so that one may log in as a different user, for example). From the Expenses example, I know how to implement an automatic redirection to a login page, but in this example, the security model is quite simple: A client is allowed to access the servlet if and only if a user is logged in. Shall I raise a custom UnAuthorizedException in my server-side service? Where should I intercept this exception? (Can I do this in a servlet filter like the GaeAuthFilter of the Expenses example?)

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  • Using a Filter to serve a specific page?

    - by user246114
    Hi, I am using a class which implements Filter for my jsp stuff. It looks like this: public class MyFilter implements Filter { public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { request.getRequestDispatcher("mypage.jsp").forward(request, response); } } So the target, "mypage.jsp", is just sitting in my top-level directory. The filter works fine if I'm entering urls like: http://www.mysite.com/foo http://www.mysite.com/boo but if I enter a trailing slash, I'll get a 404: http://www.mysite.com/foo/ http://www.mysite.com/boo/ HTTP ERROR: 404 /foo/mypage.jsp RequestURI=/foo/mypage.jsp it seems if I enter the trailing slash, then the filter thinks I want it to look for mypage.jsp in subfolder foo or boo, but I really always want it to just find it at: http://www.mysite.com/mypage.jsp how can I do that? Thank you

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  • HTTP status 405 - HTTP method POST is not supported by this URL

    - by Wont Say
    I am getting this "HTTP method POST is not supported by this URL" error when I run my project. The funny thing is, it was running perfectly fine two days ago. After I made a few changes to my code but then restored my original code and its giving me this error. Could you please help me? Here is my index.html: <form method="post" action="login.do"> <div> <table> <tr><td>Username: </td><td><input type="text" name="e_name"/> </td> </tr> <tr><td> Password: </td><td><input type="password" name="e_pass"/> </td> </tr> <tr><td></td><td><input type="submit" name ="e_submit" value="Submit"/> Here is my Login servlet: public class Login extends HttpServlet { /** * Processes requests for both HTTP * <code>GET</code> and * <code>POST</code> methods. * * @param request servlet request * @param response servlet response * @throws ServletException if a servlet-specific error occurs * @throws IOException if an I/O error occurs */ protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, SQLException { response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); try { /* * TODO output your page here. You may use following sample code. */ int status; String submit = request.getParameter("e_submit"); String submit2 = request.getParameter("a_submit"); out.println("Here1"); String e_name = request.getParameter("e_name"); String e_password = request.getParameter("e_pass"); String a_name = request.getParameter("a_name"); String a_password = request.getParameter("a_pass"); out.println(e_name+e_password+a_name+a_password); Author author = new Author(a_name,a_password); Editor editor = new Editor(e_name,e_password); // If it is an AUTHOR login: if(submit==null){ status = author.login(author); out.println("Author Login"); //Incorrect login details if(status==0) { out.println("Incorrect"); RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- AUTHOR else { out.println("Correct login details"); HttpSession session = request.getSession(); session.setAttribute(a_name, "a_name"); RequestDispatcher view = request.getRequestDispatcher("index_S.jsp"); view.forward(request, response); } } //If it is an EDITOR login else if (submit2==null){ status = editor.login(editor); //Incorrect login details if(status==0) { RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- EDITOR else { out.println("correct"); HttpSession session = request.getSession(); session.setAttribute(e_name, "e_name"); session.setAttribute(e_password, "e_pass"); RequestDispatcher view = request.getRequestDispatcher("index_S_1.html"); view.forward(request, response); } } out.println("</body>"); out.println("</html>"); } finally { out.close(); } } @Override protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doPost(req, resp); } @Override protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doGet(req, resp); }} And my web.xml looks like this: <?xml version="1.0" encoding="UTF-8"?> <servlet> <servlet-name>action</servlet-name> <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> <init-param> <param-name>config</param-name> <param-value>/WEB-INF/struts-config.xml</param-value> </init-param> <init-param> <param-name>debug</param-name> <param-value>2</param-value> </init-param> <init-param> <param-name>detail</param-name> <param-value>2</param-value> </init-param> <load-on-startup>2</load-on-startup> </servlet> <servlet> <servlet-name>Login</servlet-name> <servlet-class>controller.Login</servlet-class> </servlet> <servlet-mapping> <servlet-name>action</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Login</servlet-name> <url-pattern>/login.do</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.html</welcome-file> </welcome-file-list> I use Glassfish v3 server - let me know anything else you need to know

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  • Servlet unit test

    - by Thomman
    Currently I'm using TestNG framework for testing application business logic, i added some Servlet classes recently. How do I unit test these Servlet classes in TestNg framework?

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  • Logic for controll concurrent in block/method

    - by Hlex
    1)My environment is web application, I develop servlet to receive request. A) In some block/method i want to control concurrent to not greater than 5 B) if there are 5 request in that block , the new coming must wait up to 60 second then throws error C) if there are sleep/waiting request more then 30, the 31th request will be throwed an error How I do this? 2)(Optional Question) from above I have to distribute control logic to all clustered host. I plan to use hazelcast to share the control logic (e.g. current counter) I see they provide BlockingQueue & ExectorService but I have no idea how to use in my case. Please recommend if you have idea.

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  • web.xml : URL mapping

    - by Devashish Dixit
    I have these two lines in my web.xml <url-pattern>/</url-pattern> : Index Servletand <url-pattern>/login</url-pattern> : Login Servlet but whem I open http://localhost:8084/login/, it goes to Index Servlet and when I open http://localhost:8084/login, it goes to Login Servlet. Is there any difference in http://localhost:8084/login/ and http://localhost:8084/login? My web.xml <servlet> <servlet-name>Index</servlet-name> <servlet-class>Index</servlet-class> </servlet> <servlet> <servlet-name>Login</servlet-name> <servlet-class>Login</servlet-class> </servlet> and <servlet-mapping> <servlet-name>Index</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Login</servlet-name> <url-pattern>/login</url-pattern> </servlet-mapping>

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  • View Body not showing in Spring 3.2

    - by Dennis Röttger
    I'm currently trying to get into Java Web Development in general in Spring more specifically. I've set up my project as follows - hello.jsp: <html> <head> <title>Spring 3.0 MVC Series: Hello World - ViralPatel.net</title> </head> <body> <p>ABC ${message}</p> </body> </html> HelloWorldController.java: package controllers; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; System.out.println(message); return new ModelAndView("hello", "message", message); } } web.xml: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> </web-app> spring-servlet.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <context:component-scan base-package="controllers" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> </beans> I can start up the Server just fine and navigate to hello.html, which is resolved by the servlet to give me hello.jsp, the title of the .jsp shows (Spring 3.0 MVC Series: etc. etc.), alas, the body does not. Not the JSTL-Variable and not the "ABC" either. I've implemented jstl-1.2 in my lib-folder.

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  • Hidden features of JSP/Servlet

    - by mkoryak
    I am interested in your tricks etc used when writing JSP/Servlet. I will start: I somewhat recently found out how you can include the output of one JSP tag in an attribute of another tag: <c:forEach items="${items}"> <jsp:attribute name="var"> <mytag:doesSomething/> </jsp:attribute> <jsp:body> <%-- when using jsp:attribute the body must be in this tag --%> </jsp:body> </c:forEach>

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  • Detecting client disconnect in tomcat servlet?

    - by Seth
    How can I detect that the client side of a tomcat servlet request has disconnected? I've read that I should do a response.getOutputStream().print(), then a response.getOutputStream().flush() and catch an IOException, but is there a way I can detect this without writing any data?

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  • Java NIO Servlet to File

    - by Gandalf
    Is there a way (without buffering the whole Inputstream) to take the HttpServletRequest from a Java Servlet and write it out to a file using all NIO? Is it even worth trying? Will it be any faster reading from a normal java.io stream and writing to a java.nio Channel or do they both really need to be pure NIO to see a benefit? Thanks.

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  • Servlet request getparameter's performance

    - by Bob
    Hi, I noticed that my app is very slow sometimes, so I've done some tests. It's a very simple web app. One servlet gets some parameters than stores them. Everything's fine except one thing. It takes too long to get a parameter for the first time. It doesn't matter which parameter I try to get, but for the first time it is very slow. The strange thing is this doesn't happen always. Sometimes getting a parameter for the first time is not slow. My code looks like this request.getParameter("paramName"); request.getParameter("paramName2"); request.getParameter("paramName3"); Getting "paramName" is slow. Getting the others is very fast. By slow I mean : 200-800 millisec By very fast I mean: ~0 millisec (in the code snippet, I didn't write the performance test, but I'm using System.currentTimeMillis())

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  • http streaming using java servlet

    - by Shamik
    I have a servlet based web application which produces two sets of data. One set of data in the webpage which is essential and other set which is optional. I would like to render the essential data as fast as possible and then stream the optional data. I was thinking of writing the essential data to the output stream of HttpServletRequest and then call HttpServletRequest.flushBuffer() to commit the response to the client, but do not return from the servlet code, but instead create the optional data , write that to the outputstream again and then return from servlet code. What are the things that could go wrong in this scheme ? Is this a standard practice to achieve this goal?

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  • Servlet xxx is not available

    - by hguser
    In the web.xml of my web app I have configed the server as following: The web.xml However when I request this servlet ,I got a error which tells me "Servlet SOS is not available",but I am sure this servlet do exist in the WEB-INFO/lib/sos.jar. And I have seen the initialization work under the servelt from the logs. I wonder why can not tomcat find the sevlet?

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  • how to ouput text to java console from servlet

    - by mithun1538
    I have a servlet. But it is not working as desired. Hence for debugging purposes, I want to print statements to the java console(the one that can be opened using the java icon in taskbar). However, if I use System.out.println("message"), it doesnt display in java console. Is there any alternative way where I can display messages to the console from the servlet? Or can anyone suggest me an alternative way to display messages to any other console?

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  • EOFException in ObjectInputStream Only happens with Webstart not by java(w).exe ?!

    - by Houtman
    Hi, Anyone familiar with the differences in starting with Webstart(javaws.exe) compared to starting the app. using java.exe or javaw.exe regarding streams ? This is the exception which i ONLY get when using Webstart : java.io.EOFException at java.io.ObjectInputStream$PeekInputStream.readFully(Unknown Source) at java.io.ObjectInputStream$BlockDataInputStream.readShort(Unknown Source) at java.io.ObjectInputStream.readStreamHeader(Unknown Source) at java.io.ObjectInputStream.<init>(Unknown Source) at fasttools.jtools.dss.api.core.remoting.thinclient.RemoteSocketChannel.<init>(RemoteSocketChannel.java:77) This is how i setup the connections on both sides //==Server side== //Thread{ Socket mClientSocket = cServSock.accept(); new DssServant(mClientSocket).start(); //} DssServant(Socket socket) throws DssException { try { OutputStream mOutputStream = new BufferedOutputStream( socket.getOutputStream() ); cObjectOutputStream = new ObjectOutputStream(mOutputStream); cObjectOutputStream.flush(); //publish streamHeader InputStream mInputStream = new BufferedInputStream( socket.getInputStream() ); cObjectInputStream = new ObjectInputStream(mInputStream); .. } catch (IOException e) { .. } .. } //==Client side== public RemoteSocketChannel(String host, int port, IEventDispatcher eventSubscriptionHandler) throws DssException { cHost = host; port = (port == 0 ? DssServer.PORT : port); try { cSocket = new Socket(cHost, port); OutputStream mOutputStream = new BufferedOutputStream( cSocket.getOutputStream() ); cObjectOut = new ObjectOutputStream(mOutputStream); cObjectOut.flush(); //publish streamHeader InputStream mInputStream = new BufferedInputStream( cSocket.getInputStream() ); cObjectIn = new ObjectInputStream(mInputStream); } catch (IOException e) { .. } .. } Thanks [EDIT] Webstart console says: Java Web Start 1.6.0_19 Using JRE version 1.6.0_19-b04 Java HotSpot(TM) Client VM Server is running same 1.6u19

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  • Getting parameter sent via html form and saving in my db

    - by Wesley
    I have error in my code i don't know to solve it please help me: My Servlet: package br.com.cad.servlet; import java.io.IOException; import java.io.PrintWriter; import java.util.Date; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Calendar; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import br.com.cad.dao.Cadastro; import br.com.cad.basica.Contato; public class AddDados extends HttpServlet{ protected void service(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { PrintWriter out = response.getWriter(); String nome = request.getParameter("nome"); String sobrenome = request.getParameter("sobrenome"); String rg = request.getParameter("rg"); String cpf = request.getParameter("cpf"); String sexo = request.getParameter("sexo"); StringBuilder finalDate = new StringBuilder("DataNascimento1") .append("/"+request.getParameter("DataNascimento??2")) .append("/"+request.getParameter("DataNascimento3")); try { SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy"); finalDate.toString(); } catch(ParseException e) { out.println("Erro de conversão da data"); return; } Contato contato = new Contato(); contato.setNome(nome); contato.setSobrenome(sobrenome); contato.setRg(rg); contato.setCpf(cpf); contato.setSexo(sexo); if ("Masculino".equals(contato.getSexo())) { contato.setSexo("M"); } else { contato.setSexo("F"); } contato.setDataNascimento1(dataNascimento1); //error here ????? contato.setDataNascimento2(dataNascimento2); //error here ????? contato.setDataNascimento3(dataNascimento3); //error here ????? Cadastro dao = new Cadastro(); dao.adiciona(contato); out.println("<html>"); out.println("<body>"); out.println("Contato " + contato.getNome() + " adicionado com sucesso"); out.println("</body>"); out.println("</html>"); } } My object dao package br.com.cad.dao; import java.sql.Connection; import java.sql.PreparedStatement; import java.sql.SQLException; import java.sql.Date; import br.com.cad.dao.ConnectDb; import br.com.cad.basica.Contato; public class Cadastro { private Connection connection; public Cadastro() { this.connection = new ConnectDb().getConnection(); } public void adiciona(Contato contato) { String sql = "INSERT INTO dados_cadastro(pf_nome, pf_ultimonome, pf_rg, pf_cpf, pf_sexo,pf_dt_nasc) VALUES(?,?,?,?,?,?,?,?)"; try { PreparedStatement stmt = connection.prepareStatement(sql); stmt.setString(1, contato.getNome()); stmt.setString(2, contato.getSobrenome()); stmt.setString(3, contato.getRg()); stmt.setString(4, contato.getCpf()); stmt.setString(5, contato.getSexo()); stmt.setDate(6, new Date( contato.getDataNascimento1().getTimeInMillis()) ); // i think there are error here i don't know to solve it ????? stmt.execute(); stmt.close(); System.out.println("Cadastro realizado com sucesso!."); } catch(SQLException sqlException) { throw new RuntimeException(sqlException); } } } My class cadastro package br.com.cad.basica; import java.util.Calendar; public class Contato { private Long id; private String nome; private String sobrenome; private String email; private String endereco; private Calendar dataNascimento1; private Calendar dataNascimento2; private Calendar dataNascimento3; private String rg; private String cpf; private String sexo; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getNome() { return nome; } public void setNome(String nome) { this.nome = nome; } ...getters and setters I need to saving data in my mysql db, but i have some doubt about this code main how to get parameter send form html combobox( 1 for day, 2 for month, 3 for year of birth) i concatened with StringBuilder finalDate ... so i have some problem in my code please help me!!!

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  • HttpPost request unsuccessful

    - by The Thom
    I have written a web service and am now writing a tester to perform integration testing from the outside. I am writing my tester using apache httpclient 4.3. Based on the code here: http://hc.apache.org/httpcomponents-client-4.3.x/quickstart.html and here: http://hc.apache.org/httpcomponents-client-4.3.x/tutorial/html/fundamentals.html#d5e186 I have written the following code. Map<String, String> parms = new HashMap<>(); parms.put(AirController.KEY_VALUE, json); postUrl(SERVLET, parms); ... protected String postUrl(String servletName, Map<String, String> parms) throws AirException{ String url = rootUrl + servletName; HttpPost post = new HttpPost(url); List<NameValuePair> nvps = new ArrayList<NameValuePair>(); for(Map.Entry<String, String> entry:parms.entrySet()){ BasicNameValuePair parm = new BasicNameValuePair(entry.getKey(), entry.getValue()); nvps.add(parm); } try { post.setEntity(new UrlEncodedFormEntity(nvps)); } catch (UnsupportedEncodingException use) { String msg = "Invalid parameters:" + parms; throw new AirException(msg, use); } CloseableHttpResponse response; try { response = httpclient.execute(post); } catch (IOException ioe) { throw new AirException(ioe); } String result; if(HttpStatus.SC_OK == response.getStatusLine().getStatusCode()){ result = processResponse(response); } else{ String msg = MessageFormat.format("Invalid status code {0} received from query {1}.", new Object[]{response.getStatusLine().getStatusCode(), url}); throw new AirException(msg); } return result; } This code successfully reaches my servlet. In my servlet, I have (using Spring's AbstractController): protected ModelAndView post(HttpServletRequest request, HttpServletResponse response) { String json = String.valueOf(request.getParameter(KEY_VALUE)); if(json.equals("null")){ log.info("Received null value."); response.setStatus(406); return null; } And this code always falls into the null parameter code and returns a 406. I'm sure I'm missing something simple, but can't see what it is.

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  • applet communication using post method

    - by mithun1538
    I have an applet that is communicating with a servlet. I am communicating with the servlet using POST method. My problem is how do I send parameters to the servlet. Using GET method, this is fairly simple ( I just append the parameters to the URL after a ?). But using POST method how do I send the parameters, so that in the servlet side, I can use the statement : message = req.getParameter("msg"); In the applet side, I establish POST method connection as follows : URL url = new URL(getCodeBase(), "servlet"); URLConnection con = url.openConnection(); con.setDoInput(true); con.setDoOutput(true); con.setUseCaches(false); con.setRequestProperty("Content-Type","application/octet-stream");

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  • Second level cache for java web app and its alternatives

    - by EugeneP
    Between the transitions of the web app I use a Session object to save my objects in. I've heard there's a program called memcached but there's no compiled version of it on the site, besides some people think there are real disadvantages of it. Now I wanna ask you. What are alternatives, pros and cons of different approaches? Is memcached painpul for sysadmins to install? Is it difficult to embed it to the existing infrastructure from the perspective of a sysadmin? What about using a database to hold temporary data between web app transitions? Is it a normal practice?

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