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  • How to stream pdf document from servlet?

    - by Kumar
    Hi,I am creating pdf document using jasper report and i need to stream that pdf document from servlet.Can anyone help me where i did mistake.This is the code snippet which i am using in my application. ServletOutputStream servletOutputStream = response.getOutputStream(); String fileName="test.pdf"; response.setContentType("application/pdf"); response.setHeader("Content-Disposition","attachment; filename=\"" + fileName + "\""); response.setHeader("Cache-Control", "no-cache"); try { Map parameters = new HashMap(); parameters.put("SUBREPORT_DIR", JasperReportFilepath); parameters.put("TestId", testID); JasperPrint jprint=JasperFillManager.fillReport(filePath, parameters, conn); byte[] output=JasperExportManager.exportReportToPdf(jprint); System.out.println("Size====>"+output.length); servletOutputStream.write(output); servletOutputStream.flush(); servletOutputStream.close(); System.out.println("===============>Streaming perfectly"); } catch(Exception e) { System.out.println("===============>+JasperException"+e.getMessage()); } and i could not get any error message also.Everything is working fine but document is not streaming. Please help me to sort out the problem.

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  • Servlet send image from server and save in client

    - by sangi
    Hi, I'm new and just developing on J2EE. I am modifying an existing application (an OpenSource project). I need to save an image on a client sent by the server, but I do not know how. This activity must be done in a transparent manner without affecting the existing operation of the application. From the tests done I get this error: java.lang.IllegalStateException: getWriter () has Already Been Called for this response. How should carry out this task, according to your own opinion? How do I save on the client, locally, the image? Update: Thanks for the answers. My problem is that: the image is generated on the server, but not for direct client request (there is no link to click on web page), the picture is composed using other services on the Internet. reconstruct the image on the server. This image must be sent to the client to be saved locally. so I'd like it to appear a window where you assign the destination image plus I'd like the rest of the application were not affected by this activity. The application is yet on production. Thank you very much for your response.

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  • Java Servlet: getInitParameter not work in Service()

    - by Gabriele
    I've added some parameters in my web.xml config file, as follow: <context-param> <param-name>service1</param-name> <param-value>http://www.example.com/example2.html</param-value> </context-param> <context-param> <param-name>service2</param-name> <param-value>http://www.example.com/example2.html</param-value> </context-param> ... I try to get the parameter in my servlet, in particular in my service method: protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println(this.getServletContext().getInitParameter("service1")); ... but at runtime I have a NullPointerException... How can I get the parameter value included in web.xml? This is the stacktrace: GRAVE: Servlet.service() for servlet DispatcherServlet threw exception java.lang.NullPointerException at javax.servlet.GenericServlet.getServletContext(GenericServlet.java:160) at it.servlethope.DispatcherServlet.service(DispatcherServlet.java:66) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.tuckey.web.filters.urlrewrite.RuleChain.handleRewrite(RuleChain.java:176) at org.tuckey.web.filters.urlrewrite.RuleChain.doRules(RuleChain.java:145) at org.tuckey.web.filters.urlrewrite.UrlRewriter.processRequest(UrlRewriter.java:92) at org.tuckey.web.filters.urlrewrite.UrlRewriteFilter.doFilter(UrlRewriteFilter.java:381) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Unknown Source) DispatcherServlet.java:66 is the line where I try the getInitParameter()

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  • Read media stream from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\TEMP\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using or tag to read the media stream from the response. Thank you very much. Regards K.

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  • Sending an Email Using Java

    - by user217029
    try{ Properties props = new Properties(); props.put("mail.smtp.host", "ipc-smtp.bits-pilani.ac.in"); Session sess = Session.getInstance(props, null); sess.setDebug(true); Message msg = new MimeMessage(sess); InternetAddress addressFrom = new InternetAddress("[email protected]"); msg.setFrom(addressFrom); msg.setRecipient(Message.RecipientType.TO, new InternetAddress("[email protected]")); msg.addHeader("MyHeaderName", "myHeaderValue"); msg.setSubject("Test"); msg.setContent("Yippe", "text/plain"); Transport.send(msg); }catch(Exception exp){ exp.printStackTrace(); } The error is javax.mail.MessagingException: 554 The mail was blocked due to zen-spamhaus RBL action This is my college's smtp server.

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  • Spring MVC, forward

    - by aauser
    Is there any difference between public class Controller1 extends AbstractController { @Override protected ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception { return new AnotherController().handleRequest(request, response); } } and @Controller public class Controller1 { @RequestMapping ... public String handleRequest() { return "forward:/path_to_my_another_controller"; } }

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  • Strange IP addresses in tomcat

    - by mdev
    Some where I have this in some generic class. public static String getRequestIp (HttpServletRequest request){ String ipaddr = request.getHeader("X-FORWARDED-FOR"); if (ipaddr == null)ipaddr = request.getRemoteAddr(); return ipaddr; } For every request i call that method and in a certain moment i insert a record in a mysql database. In most cases it works normally and i can see a record for every request with a valid ip address in the right field. But sometimes where the IP should be there is something like this. "unknown, 93.186.30.120" or "10.0.1.169, 186.38.84.3" Apache is at the front listening at port 80 and used as proxy to Tomcat that listens at port 8081. My router config would not allow to pass any conection that come by any port other than 80. Any Help? Thanks in advance.

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  • spring mvc forward to jsp

    - by jerluc
    I currently have my web.xml configured to catch 404s and send them to my spring controller which will perform a search given the original URL request. The functionality is all there as far as the catch and search go, however the trouble begins to arise when I try to return a view. <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver" p:order="1"> <property name="mediaTypes"> <map> <entry key="json" value="application/json" /> <entry key="jsp" value="text/html" /> </map> </property> <property name="defaultContentType" value="application/json" /> <property name="favorPathExtension" value="true" /> <property name="viewResolvers"> <list> <bean class="org.springframework.web.servlet.view.BeanNameViewResolver" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value="" /> </bean> </list> </property> <property name="defaultViews"> <list> <bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" /> </list> </property> <property name="ignoreAcceptHeader" value="true" /> </bean> This is a snippet from my MVC config file. The problem lies in resolving the view's path to the /WEB-INF/jsp/ directory. Using a logger in my JBoss setup, I can see that when I test this search controller by going to a non-existent page, the following occurs: Server can't find the request Request is sent to 404 error page (in this case my search controller) Search controller performs search Search controller returns view name (for this illustration, we'll assume test.jsp is returned) Based off of server logger, I can see that org.springframework.web.servlet.view.JstlView is initialized once my search controller returns the view name (so I can assume it is being picked up correctly by the InternalResourceViewResolver) Server attempts to return content to browser resulting in a 404! A couple things confuse me about this: I'm not 100% sure why this isn't resolving when test.jsp clearly exists under the /WEB-INF/jsp/ directory. Even if there was some other problem, why would this result in a 404? Shouldn't a 404 error page that results in another 404 theoretically create an infinite loop? Thanks for any help or pointers! Controller class [incomplete]: @Controller public class SiteMapController { //-------------------------------------------------------------------------------------- @Autowired(required=true) private SearchService search; @Autowired(required=true) private CatalogService catalog; //-------------------------------------------------------------------------------------- @RequestMapping(value = "/sitemap", method = RequestMethod.GET) public String sitemap (HttpServletRequest request, HttpServletResponse response) { String forwardPath = ""; try { long startTime = System.nanoTime() / 1000000; String pathQuery = (String) request.getAttribute("javax.servlet.error.request_uri"); Scanner pathScanner = new Scanner(pathQuery).useDelimiter("\\/"); String context = pathScanner.next(); List<ProductLightDTO> results = new ArrayList<ProductLightDTO>(); StringBuilder query = new StringBuilder(); String currentValue; while (pathScanner.hasNext()) { currentValue = pathScanner.next().toLowerCase(); System.out.println(currentValue); if (query.length() > 0) query.append(" AND "); if (currentValue.contains("-")) { query.append("\""); query.append(currentValue.replace("-", " ")); query.append("\""); } else { query.append(currentValue + "*"); } } //results.addAll(this.doSearch(query.toString())); System.out.println("Request: " + pathQuery); System.out.println("Built Query:" + query.toString()); //System.out.println("Result size: " + results.size()); long totalTime = (System.nanoTime() / 1000000) - startTime; System.out.println("Total TTP: " + totalTime + "ms"); if (results == null || results.size() == 0) { forwardPath = "home.jsp"; } else if (results.size() == 1) { forwardPath = "product.jsp"; } else { forwardPath = "category.jsp"; } } catch (Exception ex) { System.err.println(ex); } System.out.println("Returning view: " + forwardPath); return forwardPath; } }

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  • JSP doGet not called from form

    - by RadnaOdela
    I have this code on my JSP page <form action="LoginServlet" method="get"> <input type="text" name="username" /> <input type="text" name="password" /> <input type="submit" value="Submit" /> </form> and when I press Submit I get: The page cannot be displayed The page you are looking for is currently unavailable. The Web site might be experiencing technical difficulties, or you may need to adjust your browser settings. and LoginServlet.doGet method doesn't get called. But then when I press Enter again (in address bar) my doGet method gets called. What is wrong? I am using JEE eclipse and Tomcat

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  • Cookie questions in Java

    - by user220201
    Hi, How do I differentiate between multiple cookies set through my site? I am setting two kinds of cookies one to see if the user has visited the site or not and an other one for authentication. How do I differentiate between these two? I get both of them when someone accesses a page after authentication. Do I add extra information to the Cookie Value or is there some other way? I understand the setName() function will change the name (from jsessionid) for every cookie from then on. Am I correct? Pav

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  • "session" bean scope in a web application - reliable ?

    - by EugeneP
    Can you rely on this scope and be sure that every time 1) a new session starts, the Spring bean will be initialized with default values 2) while session is kept alive, the current object will store its state during session life, will never be lost or corrupted and can always be got with [webappcontext].getBean ?

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  • Google App Engine update an object from servlet not working ?

    - by Frank
    I use the following code to update an object from servlet in Google App Engine : String Time_Stamp=Get_Date_Format(6),query="select from "+Contact_Info_Entry.class.getName()+" where Contact_Id == '"+Contact_Id+"' order by Contact_Id desc"; PersistenceManager pm=null; try { pm=PMF.get().getPersistenceManager(); // note that this returns a list, there could be multiple, DataStore does not ensure uniqueness for non-primary key fields List<Contact_Info_Entry> results=(List<Contact_Info_Entry>)pm.newQuery(query).execute(); Contact_Info_Entry A_Contact_Entry=results.get(0); A_Contact_Entry.Extra_10=Time_Stamp; pm.makePersistent(A_Contact_Entry); } catch (Exception e) { Send_Email(Email_From,Email_To,"Check_License_Servlet Error [ "+Time_Stamp+" ]",new Text(e.toString()+"\n"+Get_Stack_Trace(e)),null); } finally { pm.close(); } The value "[ 2010-05-13 Thu 15:58:31 ]" was in A_Contact_Entry.Extra_10, but it seems "pm.makePersistent(A_Contact_Entry);" was not executed. The object was not updated and there was no error message, why ? How to fix it ?

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  • java servlet:response.sendRedirect() not giving illegal state exception if called after commit of re

    - by sahil garg
    after commit of response as here redirect statement should give exception but it is not doing so if this redirect statemnet is in if block.but it does give exception in case it is out of if block.i have shown same statement(with marked stars ) at two places below.can u please tell me reason for it. protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub synchronized (noOfRequests) { noOfRequests++; } PrintWriter pw=null; response.setContentType("text/html"); response.setHeader("foo","bar"); //response is commited because of above statement pw=response.getWriter(); pw.print("hello : "+noOfRequests); //if i remove below statement this same statement is present in if block.so statement in if block should also give exception as this one do, but its not doing so.why? ***response.sendRedirect("http://localhost:8625/ServletPrc/login% 20page.html"); if(true) { //same statement as above ***response.sendRedirect("http://localhost:8625/ServletPrc/login%20page.html"); } else{ request.setAttribute("noOfReq", noOfRequests); request.setAttribute("name", new Name().getName()); request.setAttribute("GmailId",this.getServletConfig().getInitParameter("GmailId") ); request.setAttribute("YahooId",this.getServletConfig().getInitParameter("YahooId") ); RequestDispatcher view1=request.getRequestDispatcher("HomePage.jsp"); view1.forward(request, response); } }

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  • Change div backgroung color base on result from servlet using jquery

    - by Both FM
    Java Script Code Snippet $(document).ready(function() { $("#button").click(function(){ $cityName = document.getElementById("name").value; $.post("AddServlet", { name:$cityName }, function(xml) { $("#feedback").html( $("result", xml).text() ); }); }); }); In Servlet String name= request.getParameter("name"); if (name.equals("shahid")) { response.setContentType("text/xml"); out.println("<result>You are shahid</result>"); } else{ response.setContentType("text/xml"); out.println("<result>You are not shahid</result>"); } This is working fine! but I want to change the background color of div (feedback) accordingly , means if condition true, background color should be Green otherwise background color should be Red (else)

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  • Embedding XSL Stylesheet into XML

    - by user700996
    I have the following XML: <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="http://www.fakedomain.com/sally.xsl"?> And the following content in sally.xsl: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <xsl:for-each select="documentcollection/document"> <p> <xsl:for-each select="rss/channel/item"> <xsl:value-of select="title"/><br /> <xsl:value-of select="description"/><br /> <xsl:value-of select="link"/><br /> </xsl:for-each> </p> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> However, the browser displays the XML as though the XSL line is not present. Do you know why the browser is ignoring the XSL stylesheet? Is the style sheet wrong? Thanks

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  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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  • Maven dependency for Servlet 3.0 API?

    - by deamon
    How can I tell Maven 2 to load the Servlet 3.0 API? I tried: <dependency> <groupId>javax.servlet</groupId> <artifactId>servlet-api</artifactId> <version>3.0</version> <scope>provided</scope> </dependency> I use http://repository.jboss.com/maven2/ but what repository would be correct? Addendum: It works with a dependency for the entire Java EE 6 API and the following settings: <repository> <id>java.net</id> <url>http://download.java.net/maven/2</url> </repository> <dependency> <groupId>javax</groupId> <artifactId>javaee-api</artifactId> <version>6.0</version> <scope>provided</scope> </dependency> I'd prefer to only add the Servlet API as dependency, but "Brabster" may be right that separate dependencies have been replaced by Java EE 6 Profiles. Is there a source that confirms this assumption?

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  • Servlet receiving data both in ISO-8859-1 and UTF-8. How to URL-decode?

    - by AJPerez
    I've a web application (well, in fact is just a servlet) which receives data from 3 different sources: Source A is a HTML document written in UTF-8, and sends the data via <form method="get">. Source B is written in ISO-8859-1, and sends the data via <form method="get">, too. Source C is written in ISO-8859-1, and sends the data via <a href="http://my-servlet-url?param=value&param2=value2&etc">. The servlet receives the request params and URL-decodes them using UTF-8. As you can expect, A works without problems, while B and C fail (you can't URL-decode in UTF-8 something that's encoded in ISO-8859-1...). I can make slight modifications to B and C, but I am not allowed to change them from ISO-8859-1 to UTF-8, which would solve all the problems. In B, I've been able to solve the problem by adding accept-charset="UTF-8" to the <form>. So the <form> sends the data in UTF-8 even with the page being ISO. What can I do to fix C? Alternatively, is there any way to determine the charset on the servlet, so I can call URL-decode with the right encoding in each case?

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  • How can a servlet always perform the same task?

    - by membersound
    I want a Servlet to perform always the same tasks. Regardless of if it is a GET or POST. At the moment I just call the doGet() from doPost(), which works fine. Then I tried overriding the service() method, and I thought it would just work the same way. But it does not! The code somehow gets executed, but the response does not generate the webpage: response.getWriter(); response.println(string); This code works for the doGet/doPost methods, but not for the service. Why? Servlet: class MyWebServlet extends HttpServlet { @Override public void service(ServletRequest request, ServletResponse response) { response.setContentType("text/html"); PrintWriter out = response.getWriter(); String string = "teststring"; out.println(string); } }

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  • Spring import runs hibernate persistence twice

    - by Jaanus
    I have 2 spring configurations : spring-servlet.xml spring-security.xml needed to add this line to security: <beans:import resource="spring-servlet.xml"/> Now hibernate is ran twice, this is log screenshot : my web.xml: <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/spring-security.xml </param-value> </context-param>

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  • logout code in jsp.

    - by ajay
    I am using basic level authentication. and i need best logout code in JSP / servlet. I am using JSP & servlet and MS-ACCESS as backend. Is it require a session creation in JSP? please reply as soon as possible. Thanking you.....

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  • Download dynamic file with GWT

    - by Maksim
    I have a GWT page where user enter data (start date, end date, etc.), then this data goes to the server via RPC call. On the server I want to generate Excel report with POI and let user save that file on their local machine. This is my test code to stream file back to the client but for some reason I think it does not know how to stream file to the client when I'm using RPC: public class ReportsServiceImpl extends RemoteServiceServlet implements ReportsService { public String myMethod(String s) { File f = new File("/excelTestFile.xls"); String filename = f.getName(); int length = 0; try { HttpServletResponse resp = getThreadLocalResponse(); ServletOutputStream op = resp.getOutputStream(); ServletContext context = getServletConfig().getServletContext(); resp.setContentType("application/octet-stream"); resp.setContentLength((int) f.length()); resp.setHeader("Content-Disposition", "attachment; filename*=\"utf-8''" + filename + ""); byte[] bbuf = new byte[1024]; DataInputStream in = new DataInputStream(new FileInputStream(f)); while ((in != null) && ((length = in.read(bbuf)) != -1)) { op.write(bbuf, 0, length); } in.close(); op.flush(); op.close(); } catch (Exception ex) { ex.printStackTrace(); } return "Server says: " + filename; } } I've red somewhere on internet that you can't do file stream with RPC and I have to use Servlet for that. Is there any example of how to use Servlet and how to call that servlet from ReportsServiceImpl. Do I really need to make a servlet or it is possible to stream it back with my RPC?

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  • How to call a javascript function from a servlet?

    - by sunnyj
    I submit a (jsp) form to a Servlet A. Then I handle some logic which would make the submission either a success or a failure. I use jquery's ajaxForm() function to re-direct the user to a different jsp after the Servlet logic is executed. But before this redirection happens I need to show a javascript notification showing whether the submission was successful or not. Can someone tell me how can I do this?

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  • How to pass values from client side to server side ?

    - by manojp1988
    Hi All, I got a situation to transfer values from jsp to servlet's action class. Previously we did it using <input type="hidden" id="name" value="manoj" /> we take this value in action class by request.getParameter("name"). But now we couldn't pass value like "Hi\n i am\n Manoj". Since it has new line included in the string we couldn't take it like this to action. So how I can take value like this to action or is there any way other than hidden input? Thanks .

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  • Error with connection in my database servlet

    - by Zerobu
    Hello, I am writing a Database servlet, all seems well except that there seems to be an error in my connection import java.io.IOException; import java.sql.Connection; import java.sql.DriverManager; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import java.sql.Statement; import java.util.ArrayList; import javax.servlet.RequestDispatcher; import javax.servlet.ServletContext; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public class DBServlet3 extends HttpServlet { private static final long serialVersionUID = 1L; @Override public void init() throws ServletException { super.init(); try { String jdbcDriverClass= getServletContext().getInitParameter( "jdbcDriverClass" ); if (jdbcDriverClass == null) throw new ServletException( "Could not find jdbcDriverClass initialization parameter" ); Class.forName( jdbcDriverClass ); } catch (ClassNotFoundException e) { throw new ServletException( "Could not load JDBC driver class", e ); } } @Override protected void doGet( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { RequestDispatcher dispatcher= request.getRequestDispatcher( "/db.jsp" ); ServletContext application= getServletContext(); ArrayList<String> names= new ArrayList<String>(); try { Connection connection= null; Statement statement= null; ResultSet results= null; try { String jdbcUrl= application.getInitParameter( "jdbcUrl" ); String jdbcUser= application.getInitParameter( "jdbcUser" ); String jdbcPassword= application.getInitParameter( "jdbcPassword" ); connection= DriverManager.getConnection( jdbcUrl, jdbcUser, jdbcPassword ); statement= connection.createStatement(); results= statement.executeQuery( "SELECT * FROM students" ); while (results.next()) { String name= results.getString( "name" ); names.add( name ); } } finally { if (results != null) results.close(); if (statement != null) statement.close(); if (connection != null) connection.close(); } } catch (SQLException e) { throw new ServletException( e ); } request.setAttribute( "names", names ); dispatcher.forward( request, response ); } @Override protected void doPost( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { String sql= "INSERT INTO students VALUES (" + request.getParameter( "id" ) + ", '" + request.getParameter( "name" ) + "')"; sql= "INSERT INTO students VALUES (?, ?, ?, ?)"; PreparedStatement statement= connection.prepareStatement( sql ); //error on this line statement.setString( 1, request.getParameter( "id" ) ); statement.setString( 2, request.getParameter( "name" ) ); } }

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