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  • Servlet send image from server and save in client

    - by sangi
    Hi, I'm new and just developing on J2EE. I am modifying an existing application (an OpenSource project). I need to save an image on a client sent by the server, but I do not know how. This activity must be done in a transparent manner without affecting the existing operation of the application. From the tests done I get this error: java.lang.IllegalStateException: getWriter () has Already Been Called for this response. How should carry out this task, according to your own opinion? How do I save on the client, locally, the image? Update: Thanks for the answers. My problem is that: the image is generated on the server, but not for direct client request (there is no link to click on web page), the picture is composed using other services on the Internet. reconstruct the image on the server. This image must be sent to the client to be saved locally. so I'd like it to appear a window where you assign the destination image plus I'd like the rest of the application were not affected by this activity. The application is yet on production. Thank you very much for your response.

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  • Google App Engine update an object from servlet not working ?

    - by Frank
    I use the following code to update an object from servlet in Google App Engine : String Time_Stamp=Get_Date_Format(6),query="select from "+Contact_Info_Entry.class.getName()+" where Contact_Id == '"+Contact_Id+"' order by Contact_Id desc"; PersistenceManager pm=null; try { pm=PMF.get().getPersistenceManager(); // note that this returns a list, there could be multiple, DataStore does not ensure uniqueness for non-primary key fields List<Contact_Info_Entry> results=(List<Contact_Info_Entry>)pm.newQuery(query).execute(); Contact_Info_Entry A_Contact_Entry=results.get(0); A_Contact_Entry.Extra_10=Time_Stamp; pm.makePersistent(A_Contact_Entry); } catch (Exception e) { Send_Email(Email_From,Email_To,"Check_License_Servlet Error [ "+Time_Stamp+" ]",new Text(e.toString()+"\n"+Get_Stack_Trace(e)),null); } finally { pm.close(); } The value "[ 2010-05-13 Thu 15:58:31 ]" was in A_Contact_Entry.Extra_10, but it seems "pm.makePersistent(A_Contact_Entry);" was not executed. The object was not updated and there was no error message, why ? How to fix it ?

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  • How to upload files to server using JSP/Servlet?

    - by Thang Pham
    How can I upload files to server using JSP/Servlet? I tried this: <form action="upload" method="post"> <input type="text" name="description" /> <input type="file" name="file" /> <input type="submit" /> </form> However, I only get the file name, not the file content. When I add enctype="multipart/form-data" to the <form>, then request.getParameter() returns null. During research I stumbled upon Apache Common FileUpload. I tried this: FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List items = upload.parseRequest(request); // This line is where it died. Unfortunately, the servlet threw an exception without a clear message and cause. Here is the stacktrace: SEVERE: Servlet.service() for servlet UploadServlet threw exception javax.servlet.ServletException: Servlet execution threw an exception at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:313) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:637)

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  • Java Servlet: getInitParameter not work in Service()

    - by Gabriele
    I've added some parameters in my web.xml config file, as follow: <context-param> <param-name>service1</param-name> <param-value>http://www.example.com/example2.html</param-value> </context-param> <context-param> <param-name>service2</param-name> <param-value>http://www.example.com/example2.html</param-value> </context-param> ... I try to get the parameter in my servlet, in particular in my service method: protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println(this.getServletContext().getInitParameter("service1")); ... but at runtime I have a NullPointerException... How can I get the parameter value included in web.xml? This is the stacktrace: GRAVE: Servlet.service() for servlet DispatcherServlet threw exception java.lang.NullPointerException at javax.servlet.GenericServlet.getServletContext(GenericServlet.java:160) at it.servlethope.DispatcherServlet.service(DispatcherServlet.java:66) at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.tuckey.web.filters.urlrewrite.RuleChain.handleRewrite(RuleChain.java:176) at org.tuckey.web.filters.urlrewrite.RuleChain.doRules(RuleChain.java:145) at org.tuckey.web.filters.urlrewrite.UrlRewriter.processRequest(UrlRewriter.java:92) at org.tuckey.web.filters.urlrewrite.UrlRewriteFilter.doFilter(UrlRewriteFilter.java:381) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Unknown Source) DispatcherServlet.java:66 is the line where I try the getInitParameter()

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  • Maven dependency for Servlet 3.0 API?

    - by deamon
    How can I tell Maven 2 to load the Servlet 3.0 API? I tried: <dependency> <groupId>javax.servlet</groupId> <artifactId>servlet-api</artifactId> <version>3.0</version> <scope>provided</scope> </dependency> I use http://repository.jboss.com/maven2/ but what repository would be correct? Addendum: It works with a dependency for the entire Java EE 6 API and the following settings: <repository> <id>java.net</id> <url>http://download.java.net/maven/2</url> </repository> <dependency> <groupId>javax</groupId> <artifactId>javaee-api</artifactId> <version>6.0</version> <scope>provided</scope> </dependency> I'd prefer to only add the Servlet API as dependency, but "Brabster" may be right that separate dependencies have been replaced by Java EE 6 Profiles. Is there a source that confirms this assumption?

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  • Redirecting the response from a filter throws an IllegalStateException

    - by Ritesh M Nayak
    I am writing a filter that will handle all authentication related tasks. My filter is a standard servlet filter as shown below @Override public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException { UserSession attribute = (UserSession)request.getSession().getAttribute("user_session_key"); if(attribute!=null && attribute.isValid()) { //proceed as usual, chain.doFilter(req, res); return; } else { //means the user is not authenticated, so we must redirect him/her to the login page ((HttpServletResponse)res).sendRedirect("loginpage"); return; } } But when I do this, I get an IllegalStateException thrown by Tomcat's ResponseFacade. How do I acheive this in a filter. I read in other SO threads that in TOmcat this is a problem as the response object is already commited. How do I get past this ?

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  • Download dynamic file with GWT

    - by Maksim
    I have a GWT page where user enter data (start date, end date, etc.), then this data goes to the server via RPC call. On the server I want to generate Excel report with POI and let user save that file on their local machine. This is my test code to stream file back to the client but for some reason I think it does not know how to stream file to the client when I'm using RPC: public class ReportsServiceImpl extends RemoteServiceServlet implements ReportsService { public String myMethod(String s) { File f = new File("/excelTestFile.xls"); String filename = f.getName(); int length = 0; try { HttpServletResponse resp = getThreadLocalResponse(); ServletOutputStream op = resp.getOutputStream(); ServletContext context = getServletConfig().getServletContext(); resp.setContentType("application/octet-stream"); resp.setContentLength((int) f.length()); resp.setHeader("Content-Disposition", "attachment; filename*=\"utf-8''" + filename + ""); byte[] bbuf = new byte[1024]; DataInputStream in = new DataInputStream(new FileInputStream(f)); while ((in != null) && ((length = in.read(bbuf)) != -1)) { op.write(bbuf, 0, length); } in.close(); op.flush(); op.close(); } catch (Exception ex) { ex.printStackTrace(); } return "Server says: " + filename; } } I've red somewhere on internet that you can't do file stream with RPC and I have to use Servlet for that. Is there any example of how to use Servlet and how to call that servlet from ReportsServiceImpl. Do I really need to make a servlet or it is possible to stream it back with my RPC?

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  • Adding gwt project to existing java servlet 3 project

    - by Michael
    I have a standalone gwt project with RPC built with Maven. I also have java servlet 3.0 project. Both the servlet and gwt projects have war packaging but I want to have only one war file so I changed the packaging of the gwt project to jar and included it in my servlet project. Now I have a problem understanding how to wire everything together. Do I need to migrate gwt project's web.xml into the main project web.xml file ? How do I redirect to my gwt project entry index.html ? Thanks.

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  • Where's javax.servlet?

    - by egaga
    I have jdk1.6.0_13 installed, but when I try to find a javax.servlet package, or press ctrl+space in Eclipse after Servlet I cannot get anything. Where can I download this package, and why isn't it included in standard distribution for developers?

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  • javamail api isertion of main class help

    - by bobby
    import javax.servlet.*; import javax.servlet.http.*; import java.io.*; import javax.mail.*; import javax.mail.internet.*; import javax.mail.event.*; import javax.mail.Authenticator; import java.net.*; import java.util.*; public class servletmail extends HttpServlet { public void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException,IOException { PrintWriter out=response.getWriter(); response.setContentType("text/html"); try { Properties props=new Properties(); props.put("mail.transport.protocol", "smtp"); props.put("mail.smtp.host","smtp.googlemail.com"); props.put("mail.smtp.port", "995"); props.put("mail.smtp.auth", "true"); javax.mail.Authenticator authenticator = new javax.mail.Authenticator() { protected javax.mail.PasswordAuthentication getPasswordAuthentication() { return new javax.mail.PasswordAuthentication("[email protected]", "password"); } }; Session sess=Session.getDefaultInstance(props,authenticator); sess.setDebug (true); Transport transport =sess.getTransport ("smtp"); Message msg=new MimeMessage(sess); msg.setFrom(new InternetAddress("[email protected]")); msg.addRecipient(Message.RecipientType.TO, new InternetAddress("[email protected]")); msg.setSubject("Hello JavaMail"); msg.setText("Welcome to JavaMail"); transport.connect(); transport.send(msg); out.println("mail has been sent"); } catch(Exception e) { System.out.println("err"+e); } } } how to insert main class in above java code and how to pass arguments of "from" and "to"

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  • Can't instantiate javax.servlet.ServletException

    - by Denis
    Hello, experts! I am trying to create instance of class javax.servlet.ServletException with following code public class MyTroubleViewer { public static void main(String[] args) { javax.servlet.ServletException servletException = new javax.servlet.ServletException("Hello"); System.out.println(servletException.getMessage()); } } But I get exception on creating: Exception in thread "main" java.lang.ClassFormatError: Absent Code attribute in method that is not native or abstract in class file javax/servlet/ServletException ... Maven helps me with dependecies: <dependency> <groupId>javax</groupId> <artifactId>javaee-api</artifactId> <version>6.0</version> <type>jar</type> <scope>compile</scope> </dependency> What am I doing wrong?

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  • How to pass values from client side to server side ?

    - by manojp1988
    Hi All, I got a situation to transfer values from jsp to servlet's action class. Previously we did it using <input type="hidden" id="name" value="manoj" /> we take this value in action class by request.getParameter("name"). But now we couldn't pass value like "Hi\n i am\n Manoj". Since it has new line included in the string we couldn't take it like this to action. So how I can take value like this to action or is there any way other than hidden input? Thanks .

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  • NullPointerException with Servlet

    - by RonaDona
    I am calling a Servlet using its URL address. This is the URL I am typing http://localhost:7001/ryan/olympics?action=selectCatalog&id=1 This is the Servlet's URL for sure; if I change the address I get page not found This is the code for the Servlet. public class Servlet extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet { private static final long serialVersionUID = 1L; public Servlet() { super(); } public void init(ServletConfig config) throws ServletException { System.out.println("*** initializing controller servlet."); super.init(config); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String action = request.getParameter("action"); if (action.equals("selectCatalog")) { String categoryId = request.getParameter("id"); ProductModelDAO dao4 = new ProductModelDAOImpl("jpac"); if (categoryId != null && !categoryId.trim().equals("")) { CategoryDAO dao1 = new CategoryDAOImpl("jpac"); try { Category category = dao1.getCategoryName(categoryId); request.setAttribute("category", category); } catch (Exception e) { e.printStackTrace(); } } try { @SuppressWarnings("unchecked") List<Product> products = dao4 .getProductsByCategory(categoryId); request.setAttribute("products", products); } catch (Exception e) { e.printStackTrace(); } url = "SelectCatalog.jsp"; RequestDispatcher requestDispatcher = getServletContext().getRequestDispatcher(url); requestDispatcher.forward(request, response); I get the NullPointerException pointing to the RequestDispatcher's line. Any help?

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  • logout code in jsp.

    - by ajay
    I am using basic level authentication. and i need best logout code in JSP / servlet. I am using JSP & servlet and MS-ACCESS as backend. Is it require a session creation in JSP? please reply as soon as possible. Thanking you.....

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  • How to call a javascript function from a servlet?

    - by sunnyj
    I submit a (jsp) form to a Servlet A. Then I handle some logic which would make the submission either a success or a failure. I use jquery's ajaxForm() function to re-direct the user to a different jsp after the Servlet logic is executed. But before this redirection happens I need to show a javascript notification showing whether the submission was successful or not. Can someone tell me how can I do this?

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  • Custom SessionListener, name is not bound in this context, javax.naming.NameNotFoundException

    - by mehmet6parmak
    Hi, I am trying to implement HttpSessionListener so that users of this listener can register implementation of ISessionEvent interface to session Events.code is below: public class MySessionListener implements HttpSessionListener{ @Resource ISessionEvent sessionEvent; public ISessionEvent getSessionEvent() { return sessionEvent; } public void setSessionEvent(ISessionEvent sessionEvent) { this.sessionEvent = sessionEvent; } @Override public void sessionCreated(HttpSessionEvent arg0) { sessionEvent.SessionCreated(arg0.getSession()); } @Override public void sessionDestroyed(HttpSessionEvent arg0) { sessionEvent.SessionDestroyed(arg0.getSession()); } } When user implement ISessionEvent and add as a bean, SessionCreated and SessionDestroyed functions of implementation will be called when these events occured. You can ask why dont you just write inside listeners methods, i dont i'm just trying. When i try the code above i got the following error message: javax.naming.NameNotFoundException: Name com.mehmet6parmak.sessionlistener.MySessionListener is not bound in this Context at org.apache.naming.NamingContext.lookup(NamingContext.java:770) at org.apache.naming.NamingContext.lookup(NamingContext.java:153) at org.apache.catalina.util.DefaultAnnotationProcessor.lookupFieldResource(DefaultAnnotationProcessor.java:278) at org.apache.catalina.util.DefaultAnnotationProcessor.processAnnotations(DefaultAnnotationProcessor.java:187) at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4082) at org.apache.catalina.core.StandardContext.start(StandardContext.java:4630) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045) at org.apache.catalina.core.StandardHost.start(StandardHost.java:785) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045) at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:445) at org.apache.catalina.core.StandardService.start(StandardService.java:519) at org.apache.catalina.core.StandardServer.start(StandardServer.java:710) at org.apache.catalina.startup.Catalina.start(Catalina.java:581) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:289) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:414) Resource annotation causes the error but i could not resolve it. Thanks All... Interface and Implementation @Resource public interface ISessionEvent { public void SessionCreated(HttpSession session); public void SessionDestroyed(HttpSession session); } @Resource public class SessionEvent implements ISessionEvent { @Override public void SessionDestroyed(HttpSession session) { System.out.println("From Session Event Callback(Destroy):" + session.getId()); } @Override public void SessionCreated(HttpSession session) { System.out.println("From Session Event Callback(Create):" + session.getId()); } } Bean Definition <context:annotation-config/> <context:component-scan base-package="com.mehmet6parmak"> </context:component-scan> <bean id="sessionEvent" autowire="byName" class="com.mehmet6parmak.sessionlistener.SessionEvent"></bean> Solution:Using the method used in link works.

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  • Why is parsing a jSON response to a jQUERY ajax request not working

    - by Ankur
    I know there are several similar questions on SO, I have used some of them to get this far. I am trying to list a set of urls that match my input values. I have a servlet which takes some input e.g. "aus" in the example below and returns some output using out.print() e.g. the two urls I have shown below. EXAMPLE Input: "aus" Output: [{"url":"http://dbpedia.org/resource/Stifel_Nicolaus"},{"url":"http://sempedia.org/ontology/object/Australia"}] Which is exactly what I want. I have seen that firebug doesn't seem to have anything in the response section despite having called out.print(jsonString); and it seems that out.print(jsonString); is working as expected which suggests that the variable 'jsonString' contains the expected values. However I am not exactly sure what is wrong. -------- The jQuery --------- $(document).ready(function() { $("#input").keyup(function() { var input = $("#input").val(); //$("#output").html(input); ajaxCall(input); }); }); function ajaxCall(input) { // alert(input); $.ajax({ url: "InstantSearchServlet", data: "property="+input, beforeSend: function(x) { if(x && x.overrideMimeType) { x.overrideMimeType("application/j-son;charset=UTF-8"); } }, dataType: "json", success: function(data) { for (var i = 0, len = datalength; i < len; ++i) { var urlData = data[i]; $("#output").html(urlData.url); } } }); } ------ The Servlet that calls the DAO class - and returns the results ------- public class InstantSearchServlet extends HttpServlet{ private static final long serialVersionUID = 1L; public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { System.out.println("You called?"); response.setContentType("application/json"); PrintWriter out = response.getWriter(); InstantSearch is = new InstantSearch(); String input = (String)request.getParameter("property"); System.out.println(input); try { ArrayList<String> urllist; urllist = is.getUrls(input); String jsonString = convertToJSON(urllist); out.print(jsonString); System.out.println(jsonString); } catch (SQLException e) { // TODO Auto-generated catch block e.printStackTrace(); } } private String convertToJSON(ArrayList<String> urllist) { Iterator<String> itr = urllist.iterator(); JSONArray jArray = new JSONArray(); int i = 0; while (itr.hasNext()) { i++; JSONObject json = new JSONObject(); String url = itr.next(); try { json.put("url",url); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } jArray.put(json); } String results = jArray.toString(); return results; } }

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  • Sending an Email Using Java

    - by user217029
    try{ Properties props = new Properties(); props.put("mail.smtp.host", "ipc-smtp.bits-pilani.ac.in"); Session sess = Session.getInstance(props, null); sess.setDebug(true); Message msg = new MimeMessage(sess); InternetAddress addressFrom = new InternetAddress("[email protected]"); msg.setFrom(addressFrom); msg.setRecipient(Message.RecipientType.TO, new InternetAddress("[email protected]")); msg.addHeader("MyHeaderName", "myHeaderValue"); msg.setSubject("Test"); msg.setContent("Yippe", "text/plain"); Transport.send(msg); }catch(Exception exp){ exp.printStackTrace(); } The error is javax.mail.MessagingException: 554 The mail was blocked due to zen-spamhaus RBL action This is my college's smtp server.

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  • reading html from an inputstream java

    - by randeel wimalagunarathne
    hello everyone, I am reading a html file using an inputstream from a java servlet. But the contents of the original and the read one are in a different format although when displayed in a web browser they are the same. These are the two links for the html files after reading output http://www.fileflyer.com/view/gQREGAe orginal output http://www.fileflyer.com/view/mWXHVAE Is there a way to get the original html when reading? why is this happening? my java code is as follows; InputStreamReader isr = new InputStreamReader(inputStream); BufferedReader br = new BufferedReader(isr); String line = null; while ( (line = br.readLine()) != null) { System.out.println(line); } Any help would be greatly appreciated!! Thank you, rana.

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