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  • Excel data range - to sum series within date range

    - by Mark
    I have a set of data that I would like to manipulate but my problem is not straight forward. In this data I have date ranges that include multiple entries of the same date on some days and not on others. What I need to accomplish is to manage a trading account so that no more than 1% of the account is put at risk on any given day (retrospectively). To do this, when a series of trades falls on the same day, I need to total the risk associated with each of those trades so that I can limit the total risk of the combined trades by limiting the position size I take in each. Here is a sample set of the data I am working with. As you can see, there are 5 trades on Jan 3. Each of these trades comes with a risk value. I need to add the risk values of these 5 trades so that I can compare it to an account value and then determine if I should take more than 1 position in each trade. As you can see there are different numbers of trades that occur on the 4th, 5th 6th and 9th. I need the values returned in each row so that I can further manipulate them in the spreadsheet. I am not new to Excel, but cannot come up with a solution here - your input is much appreciated. Forgive the presentation below - I cannot upload a pic (new user) and the format does not carry across from excel. I have aligned the first several lines manually. Thx. Date ............. Pair ....... L/S ...... Initial Risk .......Win ......Loss ....BE. ....Avg Gain Avg Loss pips/swing 1/3/2012 ....EUR/USD ....S .............15 ................1 ..................................10 ..........................15. .. 1/3/2012 ....USD/CHF .....L ............15 ..........................................1 ..........0 1/3/2012 ....AUD/USD ....S .............15 ................1 .................................16 ...........................18 1/3/2012 ....NZD/USD ....S .............15 ................1 ...................................7 .............................8 1/3/2012 ....AUD/JPY .... S .............10 ................1 .................................25 ............................20 1/4/2012 ....EUR/USD ....L .............20 ................1 .................................19 ...........................19 1/4/2012 ....USD/CHF ....S ............ 15 ................1 .................................17 ...........................20 1/4/2012 EUR/JPY L 20 1 0 1/5/2012 EUR/USD L 15 1 10 20 1/5/2012 GBP/USD L 20 1 15 20 1/5/2012 USD/CHF S 15 1 0 1/5/2012 USD/JPY S 10 1 7 10 1/5/2012 USD/CAD S 15 1 28 36 1/5/2012 AUD/USD L 15 1 20 20 1/6/2012 USD/CAD S 15 1 5 -10 1/6/2012 EUR/JPY L 15 1 7 7 1/9/2012 AUD/USD S 15 1 22 30 1/9/2012 NZD/USD S 15 1 10 15

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  • Reversing a number in c++

    - by Marcel Bujnowski
    I created a program to show the sum and show the reversed number a person has typed. The sum function works but the revers function is not. Can anyone give me any tips on how to fix it. I created a program to show the sum and show the reversed number a person has typed. The sum function works but the revers function is not. Can anyone give me any tips on how to fix it. #include<iostream> #include<iomanip> using namespace std; void printSum(int n, bool reverse); int sm(int n); int reverseInt(int n); void printAddTable(int n); int main() { int reverse; int sum=0; int n; cout<<"Enter N value:"<<endl; cin>>n; if(n>0) { reverse = true; printSum( n, reverse); // calls the printSum Method } else { //cout<<"enter positive Number only:"<<endl; } sum = sm(n); //err // calls the sum Method reverse = reverseInt(n); // calls the reverseInt Method cout<<"The reverse value is:"<<reverse; printAddTable(n); // calls the printAddTable Method //getch() } //end of main() void printSum(int n, bool reverse) { int sum=0; // print sum of reverse numbers for(int i=n; i>=1; i--) { sum=sum+i; cout<<i<< " "<<"+"<<" "; } cout<<sum; } int sm(int n) {int sum =0; for(int i=1; i<=n; i++) { sum = sum + i ; cout << endl; cout<<i<<" "<<"+"<<" "<<endl; // print n positive integers cout << endl; } cout<< "Are " <<n<< " positive integers"<<endl; cout<< "Sum is "<<sum <<endl; return sum; } int reverseInt(int n) { int reminder=0; int sum =0; while(n<=0) { reminder = n/10; sum = (sum * 10) + reminder; // it returns the reverse number n = n % 10; } return sum; } void printAddTable(int n) { for(int i=1; i<=n; i++) { cout<<i<<endl; for(int j=1; j<=n; j++) // print n X n add table { cout<<i+j<<endl; } } } {

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  • New Skool Crosstabbing

    - by Tim Dexter
    A while back I spoke about having to go back to BIP's original crosstabbing solution to achieve a certain layout. Hok Min has provided a 'man' page for the new crosstab/pivot builder for 10.1.3.4.1 users. This will make the documentation drop but for now, get it here! The old, hand method is still available but this new approach, is more efficient and flexible. That said you may need to get into the crosstab code to tweak it where the crosstab dialog can not help. I had to do this, this week but more on that later. The following explains how the crosstab wizard builds the crosstab and what the fields inside the resulting template structure are there for. To create the crosstab a new XDO command "<?crosstab:...?>" has been created. XDO Command: <?crosstab: ctvarname; data-element; rows; columns; measures; aggregation?> Parameter Description Example Ctvarname Crosstab variable name. This is automatically generated by the Add-in. C123 data-element This is the XML data element that contains the data. "//ROW" Rows This contains a list of XML elements for row headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the row header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "Region{,o=a,t=t}, District{,o=a,t=t}" In the example, the first row header is "Region". It is sort by "Region", order is ascending, and type is text. The second row header is "District". It is sort by "District", order is ascending, and type is text. Columns This contains a list of XML elements for columns headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the column header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" In the example, the first column header is "ProductsBrand". It is sort by "ProductsBrand", order is ascending, and type is text. The second column header is "PeriodYear". It is sort by "District", order is ascending, and type is text. Measures This contains a list of XML elements for measures. "Revenue, PrevRevenue" Aggregation The aggregation function name. Currently, we only support "sum". "sum" Using the Oracle BI Publisher Template Builder for Word add-in, we are able to construct the following Pivot Table: The generated XDO command for this Pivot Table is as follow: <?crosstab:c547; "//ROW";"Region{,o=a,t=t}, District{,o=a,t=t}"; "ProductsBrand{,o=a,t=t},PeriodYear{,o=a,t=t}"; "Revenue, PrevRevenue";"sum"?> Running the command on the give XML data files generates this XML file "cttree.xml". Each XPath in the "cttree.xml" is described in the following table. Element XPath Count Description C0 /cttree/C0 1 This contains elements which are related to column. C1 /cttree/C0/C1 4 The first level column "ProductsBrand". There are four distinct values. They are shown in the label H element. CS /cttree/C0/C1/CS 4 The column-span value. It is used to format the crosstab table. H /cttree/C0/C1/H 4 The column header label. There are four distinct values "Enterprise", "Magicolor", "McCloskey" and "Valspar". T1 /cttree/C0/C1/T1 4 The sum for measure 1, which is Revenue. T2 /cttree/C0/C1/T2 4 The sum for measure 2, which is PrevRevenue. C2 /cttree/C0/C1/C2 8 The first level column "PeriodYear", which is the second group-by key. There are two distinct values "2001" and "2002". H /cttree/C0/C1/C2/H 8 The column header label. There are two distinct values "2001" and "2002". Since it is under C1, therefore the total number of entries is 4 x 2 => 8. T1 /cttree/C0/C1/C2/T1 8 The sum for measure 1 "Revenue". T2 /cttree/C0/C1/C2/T2 8 The sum for measure 2 "PrevRevenue". M0 /cttree/M0 1 This contains elements which are related to measures. M1 /cttree/M0/M1 1 This contains summary for measure 1. H /cttree/M0/M1/H 1 The measure 1 label, which is "Revenue". T /cttree/M0/M1/T 1 The sum of measure 1 for the entire xpath from "//ROW". M2 /cttree/M0/M2 1 This contains summary for measure 2. H /cttree/M0/M2/H 1 The measure 2 label, which is "PrevRevenue". T /cttree/M0/M2/T 1 The sum of measure 2 for the entire xpath from "//ROW". R0 /cttree/R0 1 This contains elements which are related to row. R1 /cttree/R0/R1 4 The first level row "Region". There are four distinct values, they are shown in the label H element. H /cttree/R0/R1/H 4 This is row header label for "Region". There are four distinct values "CENTRAL REGION", "EASTERN REGION", "SOUTHERN REGION" and "WESTERN REGION". RS /cttree/R0/R1/RS 4 The row-span value. It is used to format the crosstab table. T1 /cttree/R0/R1/T1 4 The sum of measure 1 "Revenue" for each distinct "Region" value. T2 /cttree/R0/R1/T2 4 The sum of measure 1 "Revenue" for each distinct "Region" value. R1C1 /cttree/R0/R1/R1C1 16 This contains elements from combining R1 and C1. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand". Therefore, the combination is 4 X 4 è 16. T1 /cttree/R0/R1/R1C1/T1 16 The sum of measure 1 "Revenue" for each combination of "Region" and "ProductsBrand". T2 /cttree/R0/R1/R1C1/T2 16 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "ProductsBrand". R1C2 /cttree/R0/R1/R1C1/R1C2 32 This contains elements from combining R1, C1 and C2. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand", and two distinct values of "PeriodYear". Therefore, the combination is 4 X 4 X 2 è 32. T1 /cttree/R0/R1/R1C1/R1C2/T1 32 The sum of measure 1 "Revenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". T2 /cttree/R0/R1/R1C1/R1C2/T2 32 The sum of measure 2 "PrevRevenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". R2 /cttree/R0/R1/R2 18 This contains elements from combining R1 "Region" and R2 "District". Since the list of values in R2 has dependency on R1, therefore the number of entries is not just a simple multiplication. H /cttree/R0/R1/R2/H 18 The row header label for R2 "District". R1N /cttree/R0/R1/R2/R1N 18 The R2 position number within R1. This is used to check if it is the last row, and draw table border accordingly. T1 /cttree/R0/R1/R2/T1 18 The sum of measure 1 "Revenue" for each combination "Region" and "District". T2 /cttree/R0/R1/R2/T2 18 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "District". R2C1 /cttree/R0/R1/R2/R2C1 72 This contains elements from combining R1, R2 and C1. T1 /cttree/R0/R1/R2/R2C1/T1 72 The sum of measure 1 "Revenue" for each combination of "Region", "District" and "ProductsBrand". T2 /cttree/R0/R1/R2/R2C1/T2 72 The sum of measure 2 "PrevRevenue" for each combination of "Region", "District" and "ProductsBrand". R2C2 /cttree/R0/R1/R2/R2C1/R2C2 144 This contains elements from combining R1, R2, C1 and C2, which gives the finest level of details. M1 /cttree/R0/R1/R2/R2C1/R2C2/M1 144 The sum of measure 1 "Revenue". M2 /cttree/R0/R1/R2/R2C1/R2C2/M2 144 The sum of measure 2 "PrevRevenue". Lots to read and digest I know! Customization One new feature I discovered this week is the ability to show one column and sort by another. I had a data set that was extracting month abbreviations, we wanted to show the months across the top and some row headers to the side. As you may know XSL is not great with dates, especially recognising month names. It just wants to sort them alphabetically, so Apr comes before Jan, etc. A way around this is to generate a month number alongside the month and use that to sort. We can do that in the crosstab, sadly its not exposed in the UI yet but its doable. Go back up and take a look a the initial crosstab command. especially the Rows and Columns entries. In there you will find the sort criteria. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" Notice those leading commas inside the curly braces? Because there is no field preceding them it means that the crosstab should sort on the column before the brace ie PeriodYear. But you can insert another column in the data set to sort by. To get my sort working how I needed. <?crosstab:c794;"current-group()";"_Fund_Type_._Fund_Type_Display_{_Fund_Type_._Fund_Type_Sort_,o=a,t=n}";"_Fiscal_Period__Amount__._Amt_Fm_Disp_Abbr_{_Fiscal_Period__Amount__._Amt_Fiscal_Month_Sort_,o=a,t=n}";"_Execution_Facts_._Amt_";"sum"?> Excuse the horribly verbose XML tags, good ol BIEE :0) The emboldened columns are not in the crosstab but are in the data set. I just opened up the field, dropped them in and changed the type(t) value to be 'n', for number, instead of the default 'a' and my crosstab started sorting how I wanted it. If you find other tips and tricks, please share in the comments.

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  • Algorithm: Removing as few elements as possible from a set in order to enforce no subsets.

    - by phimuemue
    Hello, I got a problem which I do not know how to solve: I have a set of sets A = {A_1, A_2, ..., A_n} and I have a set B. The target now is to remove as few elements as possible from B (creating B'), such that, after removing the elements for all 1 <= i <= n, A_i is not a subset of B'. For example, if we have A_1 = {1,2}, A_2 = {1,3,4}, A_3={2,5}, and B={1,2,3,4,5}, we could e.g. remove 1 and 2 from B (that would yield B'={3,4,5}, which is not a superset of one of the A_i). Does anybody know an algorithm for determining the (minimal number of) elements to be removed?

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  • Can't get Sum() working in Northwind example

    - by Vince
    Hi, The following code is generating a runtime error and I have no idea why. from o in Orders group o by o.Employee into employeeOrders select new { employeeOrders.Key.EmployeeID, employeeOrders.Key.FirstName, Orders = from eord in employeeOrders orderby eord.OrderID select new { eord.OrderID, eord.OrderDate, OrderTotal=eord.OrderDetails.Sum (od => od.UnitPrice) } } The error is Member access 'System.Decimal UnitPrice' of 'LINQPad.User.OrderDetails' not legal on type 'LINQPad.User.Orders I've also tried this in VS2010 with a standard drag and drop data context and same thing. Thanks in advance

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  • sum of Times in SQL

    - by LIX
    Hello all, I have some records like this: ID Personel_Code Time --- ------------- ------ 1 0011 05:50 3 0011 20:12 4 0012 00:50 I want to have the sum of times for each person. in this example I want to have the result like this : Personel_Code Time ------------- ----- 0011 26:02 0012 00:50 Thank you.

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  • excel sum if string

    - by user1834348
    I have table similar to this: 102938 bob 038128 Marc 398401 Tom 298421 Jim 102938 Alex 102938 Junior 209381 Rex 398401 Oby I want to make sometthing like =sumif(A:A, 102938,B:B) and to get "bobAlexJunior" as result. But this is not working becouse sum works with numbers not strings. If i go with lookup, it works with strings but finds only first line, not all lines. Do you have an Idea on how to fix this issue? Thanx

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  • Smallest sum of graph weight, where each node are connceted (like a network)

    - by Svisstack
    Hello, What algorithm I can use for problem like this: Have a graph positive weighted, i want to know a smallest possible sum of weights where each node are connected (connected like a network, where each node is a eg. network device). In this network each node can be connected with other node by some other other nodes in way. But all nodes from input graph must be in a network. Any one can help me with this?

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  • How to implement "select sum()" in Grails

    - by xain
    I have a relationship like this: class E { string name hasMany = [me:ME] } class M { float price } class ME { E e M m int quantity } And I'd hate to iterate to achieve this: "obtain the sum of the quantity in ME times the price of the corresponding M for a given E". Any hints on how to implement it using GORM/HQL ? Thanks in advance

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  • how do i get the sum of the 4th column

    - by every_answer_gets_a_point
    this statement will generate a 4 column table: SELECT shipped.badguy AS badguy, shipped.sdate AS LineDate, 'Delivery' AS Legend, -price*quantity AS amount FROM product JOIN shipped ON (product.id = shipped.product) UNION SELECT receipt.badguy, receipt.rdate,notes, amount FROM how do i get the total sum of the 4th of column of what the above generates?

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  • MYSQL Order By Sum of Columns

    - by djs22
    Hi all, Any idea on how to order the results of a MYSQL query by the sum of two columns rather than by a single column? Select * FROM table ORDER BY (col1+col2) desc I know that won't work., but I hope it conveys what I want to do fairly well. Thanks!

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  • Calculate the sum of a datagrid's rows

    - by chchrist
    I have this datagrid which has columns with a NumericStepper as an itemEditor where the user can change the number of items he wants to buy. How can I calculate the sum of all cells when the user updates datagrid's values? Thanks in advance

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  • script to sum all numbers in a file (linux)

    - by Mark Roberts
    I have a file which contains several thousand numbers, each on it's own line: 34 42 11 6 2 99 ... I'm looking to write a script which will print the sum of all numbers in the file. I've got a solution, but it's not very efficient. (It takes several minutes to run.) I'm looking for a more efficient solution. Any suggestions?

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  • Can get Sum() working in Northwind example

    - by Vince
    Hi, The following code is generating a runtime error and I have no idea why. from o in Orders group o by o.Employee into employeeOrders select new { employeeOrders.Key.EmployeeID, employeeOrders.Key.FirstName, Orders = from eord in employeeOrders orderby eord.OrderID select new { eord.OrderID, eord.OrderDate, OrderTotal=eord.OrderDetails.Sum (od => od.UnitPrice) } } The error is Member access 'System.Decimal UnitPrice' of 'LINQPad.User.OrderDetails' not legal on type 'LINQPad.User.Orders Thanks in advance

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  • Defining the hash of an object as the sum of hashes of its members

    - by Space_C0wb0y
    I have a class that represents undirected edges in a graph. Every edge has two members vertex1 and vertex2 representing the vertices it connects. The problem is, that an edge can be specified two directions. My idea was now to define the hash of an edge as the sum of the hashes of its vertices. This way, the direction plays no role anymore, the hash would be the same. Are there any pitfalls with that?

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  • MySQL: SUM in WHERE clause

    - by checcco
    Hi guys, I've got this table CREATE TABLE `subevents` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(150) DEFAULT NULL, `content` text, `class` tinyint(4) NOT NULL DEFAULT '1', PRIMARY KEY (`id`) ) ENGINE=MyISAM Each row can have a different value in the 'class' field. I'd like to select any number of rows, ordered randomly, as long as the sum of the values in the 'class' field is equal to 100. How could I accomplish it directly in the MySQL query without doing it later in PHP? Thanks everybody!

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  • Sum Values in Multidimensional Array

    - by lemonpole
    Hello all. I'm experimenting with arrays in PHP and I am setting up a fake environment where a "team's" record is held in arrays. $t1 = array ( "basicInfo" => array ( "The Sineps", "December 25, 2010", "lemonpole" ), "overallRecord" => array ( 0, 0, 0, 0 ), "overallSeasons" => array ( "season1.cs" => array (0, 0, 0), "season2.cs" => array (0, 0, 0) ), "matches" => array ( "season1.cs" => array ( "week1" => array ("12", "3", "1"), "week2" => array ("8", "8" ,"0"), "week3" => array ("8", "8" ,"0") ), "season2.cs" => array ( "week1" => array ("9", "2", "5"), "week2" => array ("12", "2" ,"2") ) ) ); What I am trying to achieve is to add all the wins, loss, and draws, from each season's week to their respective week. So for example, the sum of all the weeks in $t1["matches"]["season1.cs"] will be added to $t1["overallSeasons"]["season1.cs"]. The result would leave: "overallSeasons" => array ( "season1.cs" => array (28, 19, 1), "season2.cs" => array (21, 4, 7) ), I tried to work this out on my own for the past hour and all I have gotten is a little more knowledge of for-loops and foreach-loops :o... so I think I now have the basics down such as using foreach loops and so on; however, I am still fairly new to this so bear with me! I can get the loop to point to $t1["matches"] key and go through each season but I can't seem to figure out how to add all of the wins, loss, and draw, for each individual week. For now, I'm only looking for answers concerning the overall seasons sum since I can work from there once I figure out how to achieve this. Any help will be much appreciated but please, try and keep it simple for me... or comment the code accordingly please! Thanks!

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  • T-SQL Query to Get SUM(COUNT())

    - by Ted
    Hi, I am planning to get a report for a table with following table structure: ID RequestDate ----------------------------- 1 2010/01/01 2 2010/02/14 3 2010/03/20 4 2010/01/07 5 2009/03/31 I want the results as: I D_Count RequestDate Sum ----------------------------------------- 2 2010/01 2 1 2010/02 3 2 2010/03 5 Pls help.

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  • how to have the right sum of type Time with sql

    - by kawtousse
    hi , i have 2 fields called Timefrom and TimeUntill the duration is calculated in TimeSpent. The colonne timeFrom is like the followine: 10:00:00 the colonne timeUntill is like the following: 12:00:00 the time spent colonne has the value: 02:00:00. My goal is to calculate the sum of timeSpent. PLease help.

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  • sum up value from textfile - bash

    - by user3493435
    I am trying to sum up the values in a textfile try.txt firstNumber,1 secondNumber,2 I tried with this script #!/bin/bash while IFS, read -r -a array; do printf "%s %s\n" "${array[0]} ${array[1]}" for n in "${array[1]}"; do ((total += n)) echo "total =" $total done done < try.txt and I landed up with this output firstNumber 1 total = 1 secondNumber 2 total = 3 expected output firstNumber 1 secondNumber 2 total = 3 Thanks in advance

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