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  • MacOSX: remove write-protect flag from file in Terminal

    - by Albert
    Hi, I have a file on a FAT32 volume which is shown as write-protected in Finder (so I cannot move it). Removing that write-protected flag in the information dialog works just fine. However, I have many more such files and I thus want to do it via Terminal. I already tried via 'chmod +w' but that didn't worked. 'ls -la' showed me that they are already just fine ("-rwxrwxrwx 1 az az " where az is my user account). Then I thought this might be stored in some xattr properties but 'xattr -l' didn't gave me any entry. Then I thought this might be some ACL setting (whereby I thought they would be stored as xattr but let's try it anyway) - and some Google search returned me something with 'chmod -a' or 'chmod -i' or so. All these tries only give me chmod: No ACL currently associated with file" or chmod: Failed to set ACL on file...: Operation not permitted". But I definitly have no write access to the file because I cannot move it or do any other change to it (in Terminal). Removing the write-access flag in Finder solves that.

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  • Protect Gnome Screen Saver Settings

    - by Jared Brown
    By default in Gnome standard users can access their screensaver preferences and change settings such as the idle time and whether or not it locks the screen. I desire to set the screensaver settings as the root user for each user and only allow the root user to adjust them. What is the best (read: simplest + fool proof) way to accomplish this?

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  • Mac OS X: remove write-protect flag from file in Terminal

    - by Albert
    Hi, I have a file on a FAT32 volume which is shown as write-protected in Finder (so I cannot move it). Removing that write-protected flag in the information dialog works just fine. However, I have many more such files and I thus want to do it via Terminal. I already tried via 'chmod +w' but that didn't worked. 'ls -la' showed me that they are already just fine ("-rwxrwxrwx 1 az az " where az is my user account). Then I thought this might be stored in some xattr properties but 'xattr -l' didn't gave me any entry. Then I thought this might be some ACL setting (whereby I thought they would be stored as xattr but let's try it anyway) - and some Google search returned me something with 'chmod -a' or 'chmod -i' or so. All these tries only give me chmod: No ACL currently associated with file" or chmod: Failed to set ACL on file...: Operation not permitted". But I definitly have no write access to the file because I cannot move it or do any other change to it (in Terminal). Removing the write-access flag in Finder solves that.

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  • How to protect ejabberd from bruteforce attacks?

    - by Sergey
    It writes this in logs: =INFO REPORT==== 2012-03-14 17:48:54 === I(<0.467.0>:ejabberd_listener:281) : (#Port<0.4384>) Accepted connection {{10,254,239,2},51986} -> {{10,254,239,1},5222} =INFO REPORT==== 2012-03-14 17:48:54 === I(<0.1308.0>:ejabberd_c2s:784) : ({socket_state,tls,{tlssock,#Port<0.4384>,#Port<0.4386>},<0.1307.0>}) Failed authentication for USERNAME =INFO REPORT==== 2012-03-14 17:48:54 === I(<0.1308.0>:ejabberd_c2s:649) : ({socket_state,tls,{tlssock,#Port<0.4384>,#Port<0.4386>},<0.1307.0>}) Failed authentication for USERNAME It doesn't write IP with a failure. And strings "Accepted connection" and "Failed auth.." may even not stand nearby (as I think on heavily loaded servers) to be able to use fail2ban. What to do? And how jabber servers (using ejabberd) are protected?

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  • Using .htaccess to protect direct access of files

    - by claydough
    We need to prevent direct access of files on our site from someone just entering a URL in their browser. I got this to work by using an htaccess file and it is fine in IE & Safari, but for some reason Firefox doesn't cooperate. I think it has something to do with the way Firefox reports referrers. Here is my code in the .htaccess file. RewriteEngine On RewriteBase / RewriteCond %{HTTP_REFERER} !^http://(my\.)?bigtimbermedia\.com/.*$ [NC] RewriteRule \.(swf|gif|png|jpg|doc|xls|pdf|html|htm|xlsx|docx)$ http://my.bigtimbermedia.com/ [R,L] If you want to see an example of this, try accessing this first... http://my.bigtimbermedia.com/books/bpGreyWolvesflip/index.html It blocks it properly in all browsers. Now if you go to this URL and click on the link, it works in IE and Safari, but Firefox chokes and seems like it is in a loop. Any ideas how I can get this to work in Firefox? Thanks!

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  • Protect me from this perl syn flood script [closed]

    - by Luka
    Possible Duplicate: How to best defend against a “slowloris” DOS attack against an Apache web server? As everybody here I was interested in hacking in a period of time, using a perl scripts. CSF is protecting me from every perl script which can make damage. But not from this one here: http://pastebin.com/CfRiSVkQ It's Syn Flood script, when I attack my dedicated server from another dedicated with 100MBPS link csf is detecting the attack and he always block attackers address but I am flooded and sites are down, I get email from csf, but attack is still damaging sites! Then I need to restart httpd, csf and sites are online again...

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  • Protect apache2 server-status handler by password

    - by Shiplu
    In my apache2 server I access /server-status to check my current status of the web-server. I found that mods-available/status.conf contains the snippets that is responsible for showing status. <Location /server-status> SetHandler server-status Order deny,allow Deny from all Allow from localhost ip6-localhost </Location> My question is how can i make it available not only for localhost but also for remote host with authentication?

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  • How to Protect Apache server from this attack

    - by 501496270
    Is there a .htaccess solution against this attack 188.165.198.65 - - [17/Apr/2010:15:46:49 -0500] "GET /blog/2009/04/12/shopping-cart/?cart=../../../../../../../../../../../../../../../../etc/passwd%00 HTTP/1.1" 200 28114""Mozilla/4.0 (compatible; MSIE 7.0;Windows NT 5.1; .NET CLR 1" my WordPress .htaccess is # BEGIN WordPress <IfModule mod_rewrite.c> RewriteEngine On RewriteBase /blog/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule . /blog/index.php [L] </IfModule> # END WordPress

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  • Virtual firewall to protect hypervisor

    - by manutenfruits
    I am running an Ubuntu Server 12.10 as a single host connected to a NATed router connected using PPPoE to a optical fiber modem. This server is meant to be accessed from the Internet, but also to be used from the LAN as a SVN, MySQL and what not... The issue is that the router is not customizable enough to serve, so I was thinking about creating a virtual pfSense firewall using KVM inside of the server itself, removing the need of the router. Is this possible? Can the host ignore and block all traffic coming to itself, but not for the firewall? I am aware this is not the most desirable environment, I accept suggestions based on budget!

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  • How to protect myself from promiscuous mode?

    - by Rivari
    I have read that some network adapters can switch to promiscuous mode and get all the packets sent by my router. We have multiple computers here connected to the same router. They all have the WEP key for authentification. So basicaly, this means that anyone of them, using the promiscuous mode, can see all the packets destined to others computers? That's frightening. How can I prevent this?

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  • Protect apache pages by URL

    - by Thomas
    Is it possible to allow access to specific URLs only to certain networks? Basically, I would like to restrict access to the admin area only to the local network This area's pages are prefixed by /admin Essentially, I would like all /admin/* to be forbidden from public access. Can apache handle such a case? Thanks UPDATE Using your suggestions I came up to <LocationMatch admin> Order allow,deny deny from all Allow From 192.168.11.0/255.255.255.0 </LocationMatch> However, I get 403 even though I am on the network. Additionally, if I put apache behind haproxy, is this going to work? Because the traffic will be coming from 127.0.0.1 to apache

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  • password protect apache user directory using system passwords

    - by Jeff
    I have set up Apache to check user passwords using these modules: LoadModule authz_user_module modules/mod_authz_user.so LoadModule authn_file_module modules/mod_authn_file.so LoadModule auth_basic_module modules/mod_auth_basic.so However, these modules require me to manually add everyone to a new password file (which requires every user to type in their password). Is there a way to have Apache check the system passwords, so that anyone who can ssh can use the same password for web login?

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  • Manually start screensaver with password protect

    - by gibberish
    Windows 7 I wish to manually lock the computer so I placed a shortcut to scrnsave.exe on the desktop. (I do not want the user to use Ctrl+Alt+Del -- Lock This Computer for various reasons) Problem is that when double-clicked, the screen saver starts but it's not password protected. However, in Personalization -- Screen Saver, that same screen saver is the selected one and it IS configured to display logon screen upon resume. And that works when Windows starts the screen saver. So how can I cause "On resume, display logon screen" behavior by manually starting a screen saver? (Scripting is an option if I know what to do.)

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  • Protect all XML-RPC calls with HTTP basic auth but one

    - by bodom_lx
    I set up a Django project for smartphone serving XML-RPC methods over HTTPS and using basic auth. All XML-RPC methods require username and password. I would like to implement a XML-RPC method to provide registration to the system. Obviously, this method should not require username and password. The following is the Apache conf section responsible for basic auth: <Location /RPC2> AuthType Basic AuthName "Login Required" Require valid-user AuthBasicProvider wsgi WSGIAuthUserScript /path/to/auth.wsgi </Location> This is my auth.wsgi: import os import sys sys.stdout = sys.stderr sys.path.append('/path/to/project') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.contrib.auth.models import User from django import db def check_password(environ, user, password): """ Authenticates apache/mod_wsgi against Django's auth database. """ db.reset_queries() kwargs = {'username': user, 'is_active': True} try: # checks that the username is valid try: user = User.objects.get(**kwargs) except User.DoesNotExist: return None # verifies that the password is valid for the user if user.check_password(password): return True else: return False finally: db.connection.close() There are two dirty ways to achieve my aim with current situation: Have a dummy username/password to be used when trying to register to the system Have a separate Django/XML-RPC application on another URL (ie: /register) that is not protected by basic auth Both of them are very ugly, as I would also like to define a standard protocol to be used for services like mine (it's an open Dynamic Ridesharing Architecture) Is there a way to unprotect a single XML-RPC call (ie. a defined POST request) even if all XML-RPC calls over /RPC2 are protected?

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  • Protect individual sites on Ubuntu/Apache server

    - by Christoffer
    Hi,?? I need to set up a Apache server configuration for some client sites that run under the same Ubuntu 9.10 machine. All sites are allowed to run PHP, Python and Ruby on Rails. I do not control the source code of these sites and so I need to set up a filter in order to prevent one user to reach files on another users account.?? If I run a script to list files in "/" from one account, I can browse some files and directories in the actual server root. I want to set the root for each account to /var/usersite.com/www/ instead so that listing files in "/" shows the files in the client's root. ??How is this most easily configured??? Cheers!? /Christoffer

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  • Protect all XML-RPC calls with HTTP basic auth but one

    - by bodom_lx
    I set up a Django project for smartphone serving XML-RPC methods over HTTPS and using basic auth. All XML-RPC methods require username and password. I would like to implement a XML-RPC method to provide registration to the system. Obviously, this method should not require username and password. The following is the Apache conf section responsible for basic auth: <Location /RPC2> AuthType Basic AuthName "Login Required" Require valid-user AuthBasicProvider wsgi WSGIAuthUserScript /path/to/auth.wsgi </Location> This is my auth.wsgi: import os import sys sys.stdout = sys.stderr sys.path.append('/path/to/project') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.contrib.auth.models import User from django import db def check_password(environ, user, password): """ Authenticates apache/mod_wsgi against Django's auth database. """ db.reset_queries() kwargs = {'username': user, 'is_active': True} try: # checks that the username is valid try: user = User.objects.get(**kwargs) except User.DoesNotExist: return None # verifies that the password is valid for the user if user.check_password(password): return True else: return False finally: db.connection.close() There are two dirty ways to achieve my aim with current situation: Have a dummy username/password to be used when trying to register to the system Have a separate Django/XML-RPC application on another URL (ie: /register) that is not protected by basic auth Both of them are very ugly, as I would also like to define a standard protocol to be used for services like mine (it's an open Dynamic Ridesharing Architecture) Is there a way to unprotect a single XML-RPC call (ie. a defined POST request) even if all XML-RPC calls over /RPC2 are protected?

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  • Password protect a folder

    - by Lee Treveil
    What are the available options for password protecting a folder? I'm talking about requiring a password to actually access the folder, not just user access rights. Is the third-party software out there secure and stable? What are the recommendations?

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  • Password protect app in jetty

    - by JohnW
    I am testing a webapp (.war) running in Jetty 7. For demo purposes I want to run this on a public URL, however I would like not to have the whole world (if they happen to come across the URL) be able to see it. Is there a way to make Jetty require a basic-auth type of authentication when accessing the webapp (without modifying anything inside the war, i.e. no edits on the web.xml file)? Or if not the webapp, then any part of what Jetty provides at port 8080?

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  • Protect foreach loop when empty list

    - by SteB
    Using Powershell v2.0 I want to delete any files older than X days: $backups = Get-ChildItem -Path $Backuppath | Where-Object {($_.lastwritetime -lt (Get-Date).addDays(-$DaysKeep)) -and (-not $_.PSIsContainer) -and ($_.Name -like "backup*")} foreach ($file in $backups) { Remove-Item $file.FullName; } However, when $backups is empty I get: Remove-Item : Cannot bind argument to parameter 'Path' because it is null. I've tried: Protecting the foreach with if (!$backups) Protecting the Remove-Item with if (Test-Path $file -PathType Leaf) Protecting the Remove-Item with if ([IO.File]::Exists($file.FullName) -ne $true) None of these seem to work, what if the recommended way of preventing a foreach loop from being entered if the list is empty?

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  • Sockets: Transport endpoint is not connected on send

    - by TheoretiCAL
    I'm trying to learn socket programming from http://beej.us/guide/bgnet/output/html/singlepage/bgnet.html and am attempting to build a SOCK_STREAM client/server. My client: #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <errno.h> #include <string.h> #include <sys/types.h> #include <sys/socket.h> #include <netinet/in.h> #include <arpa/inet.h> #include <netdb.h> #define SERVERPORT "4951" // the port users will be connecting to int main(int argc, char *argv[]) { int sockfd; struct addrinfo hints, *servinfo, *p; int rv; int numbytes; if (argc != 3) { fprintf(stderr,"usage: talker hostname message\n"); exit(1); } memset(&hints, 0, sizeof hints); hints.ai_family = AF_UNSPEC; hints.ai_socktype = SOCK_STREAM; if ((rv = getaddrinfo(argv[1], SERVERPORT, &hints, &servinfo)) != 0) { fprintf(stderr, "getaddrinfo: %s\n", gai_strerror(rv)); return 1; } // loop through all the results and make a socket for(p = servinfo; p != NULL; p = p->ai_next) { if ((sockfd = socket(p->ai_family, p->ai_socktype, p->ai_protocol)) == -1) { perror("talker: socket"); continue; if (connect(sockfd, p->ai_addr, p->ai_addrlen) == -1) { close(sockfd); perror("client: connect"); continue; } } break; } if (p == NULL) { fprintf(stderr, "talker: failed to bind socket\n"); return 2; } if ((numbytes = send(sockfd, argv[2], strlen(argv[2]), 0) == -1)) { perror("talker: send"); exit(1); } freeaddrinfo(servinfo); printf("talker: sent %d bytes to %s\n", numbytes, argv[1]); close(sockfd); return 0; } Server: #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <errno.h> #include <string.h> #include <sys/types.h> #include <sys/socket.h> #include <netinet/in.h> #include <arpa/inet.h> #include <netdb.h> #define MYPORT "4951" // the port users will be connecting to #define MAXBUFLEN 100 static int backlog = 10; // get sockaddr, IPv4 or IPv6: void *get_in_addr(struct sockaddr *sa) { if (sa->sa_family == AF_INET) { return &(((struct sockaddr_in*)sa)->sin_addr); } return &(((struct sockaddr_in6*)sa)->sin6_addr); } int main(void) { int sockfd; struct addrinfo hints, *servinfo, *p; int rv; int numbytes; int new_fd; socklen_t addr_size; struct sockaddr_storage their_addr; char buf[MAXBUFLEN]; char s[INET6_ADDRSTRLEN]; memset(&hints, 0, sizeof hints); hints.ai_family = AF_UNSPEC; // set to AF_INET to force IPv4 hints.ai_socktype = SOCK_STREAM; hints.ai_flags = AI_PASSIVE; // use my IP if ((rv = getaddrinfo(NULL, MYPORT, &hints, &servinfo)) != 0) { fprintf(stderr, "getaddrinfo: %s\n", gai_strerror(rv)); return 1; } // loop through all the results and bind to the first we can for(p = servinfo; p != NULL; p = p->ai_next) { if ((sockfd = socket(p->ai_family, p->ai_socktype, p->ai_protocol)) == -1) { perror("listener: socket"); continue; } int yes=1; // lose the pesky "Address already in use" error message if (setsockopt(sockfd,SOL_SOCKET,SO_REUSEADDR,&yes,sizeof(int)) == -1) { perror("setsockopt"); exit(1); } if (bind(sockfd, p->ai_addr, p->ai_addrlen) == -1) { close(sockfd); perror("listener: bind"); continue; } if (listen(sockfd,backlog) == -1){ close(sockfd); perror("listener:listen"); continue; } break; } if (p == NULL) { fprintf(stderr, "listener: failed to bind socket\n"); return 2; } freeaddrinfo(servinfo); printf("listener: waiting to recv..\n"); while(1){ addr_size = sizeof their_addr; if ((new_fd = accept(sockfd, (struct sockaddr *)&their_addr, &addr_size))==-1){ perror("accept"); exit(1); } if ((numbytes = recv(new_fd, buf, MAXBUFLEN-1 , 0) == -1)) { perror("recv"); exit(1); } printf("listener: got packet from %s\n", inet_ntop(their_addr.ss_family, get_in_addr((struct sockaddr *)&their_addr), s, sizeof s)); printf("listener: packet is %d bytes long\n", numbytes); buf[numbytes] = '\0'; printf("listener: packet contains \"%s\"\n", buf); close(sockfd); } return 0; } Upon executing the client, I get " send: Transport endpoint is not connected" and I'm not sure where I went wrong. Thanks.

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  • How to protect critical section in PHP?

    - by Morgan Cheng
    I did some search about this topic but found nothing valuable. If I don't use PHP default session handler, there is no session lock at request level. So, I have to protect critical section by myself. In Java, we have synchronized. In C#, we have lock. In PHP, how to do that?

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  • Protect .NET code from reverse engineering?

    - by Priyank Bolia
    Obfuscation is one way, but it can't protect from breaking the piracy protection security of the application. How to make sure that the application is not tampered with, and how to make sure that the registration mechanism can't be reverse engineered. Also it is possible to make to convert C# app in native code, Xenocode is too costly. C# provides lot of features, and is the ideal language for my code, so writing in C++ again the whole codebase is out of question. Secure certificates can be easily removed from the signed assemblies in .NET

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