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  • how can convert bitmap to byte array

    - by narasimha
    hi sir i am implementing image upload in sdcard image converting bitmap in bitmap convert in bytearray i am implementing this code import java.io.ByteArrayOutputStream; import java.io.DataInputStream; import java.io.EOFException; import java.io.File; import java.io.FileDescriptor; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import android.R.array; import android.app.Activity; import android.graphics.Bitmap; import android.graphics.BitmapFactory; import android.os.Bundle; import android.util.Log; import android.widget.ImageView; public class Photo extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); File f = new File("/sdcard/DCIM/1.jpg"); FileInputStream is = null; try { is = new FileInputStream(f); Bitmap bm; bm = BitmapFactory.decodeStream(is,null,null); ByteArrayOutputStream baos = new ByteArrayOutputStream(1000); bm.compress(Bitmap.CompressFormat.JPEG,75, baos); System.out.println("3........................"+bm); ImageView pic=(ImageView)this.findViewById(R.id.picview); pic.setImageBitmap(bm); } catch (Exception e) { // TODO: handle exception e.printStackTrace(); } } }this code is i am implementing how can convert bitmap in byte array INFO/System.out(12658): 3........................android.graphics.Bitmap@4358e3d0 in debug this will be displayed how can retrieve bitmap to byte array

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  • how to implement bitmap to byte array in android

    - by satyamurthy
    hi sir i am implementing image upload in sdcard image converting bitmap in bitmap convert in bytearray i am implementing this code import java.io.ByteArrayOutputStream; import java.io.DataInputStream; import java.io.EOFException; import java.io.File; import java.io.FileDescriptor; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import android.R.array; import android.app.Activity; import android.graphics.Bitmap; import android.graphics.BitmapFactory; import android.os.Bundle; import android.util.Log; import android.widget.ImageView; public class Photo extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); File f = new File("/sdcard/DCIM/1.jpg"); FileInputStream is = null; try { is = new FileInputStream(f); Bitmap bm; bm = BitmapFactory.decodeStream(is,null,null); ByteArrayOutputStream baos = new ByteArrayOutputStream(1000); bm.compress(Bitmap.CompressFormat.JPEG,75, baos); System.out.println("3........................"+bm); ImageView pic=(ImageView)this.findViewById(R.id.picview); pic.setImageBitmap(bm); } catch (Exception e) { // TODO: handle exception e.printStackTrace(); } } }this code is i am implementing how can convert bitmap in byte array INFO/System.out(12658): 3........................android.graphics.Bitmap@4358e3d0 in debug this will be displayed how can retrieve bitmap to byte array

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  • Jenkins slave jobs failing on "Unexpected termination of channel"

    - by Clark Wright
    I am currently seeing a set of errors across my builds. Is this expected behaviour if you loose Jenkins (say to a box crash, or a kill -9)? Or is there something worse going on (like a bad network connection)? The stack and error is: FATAL: hudson.remoting.RequestAbortedException: java.io.IOException: Unexpected termination of the channel hudson.remoting.RequestAbortedException: hudson.remoting.RequestAbortedException: java.io.IOException: Unexpected termination of the channel at hudson.remoting.Request.call(Request.java:149) at hudson.remoting.Channel.call(Channel.java:681) at hudson.remoting.RemoteInvocationHandler.invoke(RemoteInvocationHandler.java:158) at $Proxy175.join(Unknown Source) at hudson.Launcher$RemoteLauncher$ProcImpl.join(Launcher.java:861) at hudson.Launcher$ProcStarter.join(Launcher.java:345) at hudson.tasks.CommandInterpreter.perform(CommandInterpreter.java:82) at hudson.tasks.CommandInterpreter.perform(CommandInterpreter.java:58) at hudson.tasks.BuildStepMonitor$1.perform(BuildStepMonitor.java:19) at hudson.model.AbstractBuild$AbstractRunner.perform(AbstractBuild.java:703) at hudson.model.Build$RunnerImpl.build(Build.java:178) at hudson.model.Build$RunnerImpl.doRun(Build.java:139) at hudson.model.AbstractBuild$AbstractRunner.run(AbstractBuild.java:473) at hudson.model.Run.run(Run.java:1410) at hudson.model.FreeStyleBuild.run(FreeStyleBuild.java:46) at hudson.model.ResourceController.execute(ResourceController.java:88) at hudson.model.Executor.run(Executor.java:238) Caused by: hudson.remoting.RequestAbortedException: java.io.IOException: Unexpected termination of the channel at hudson.remoting.Request.abort(Request.java:273) at hudson.remoting.Channel.terminate(Channel.java:732) at hudson.remoting.Channel$ReaderThread.run(Channel.java:1157) Caused by: java.io.IOException: Unexpected termination of the channel at hudson.remoting.Channel$ReaderThread.run(Channel.java:1133) Caused by: java.io.EOFException at java.io.ObjectInputStream$BlockDataInputStream.peekByte(ObjectInputStream.java:2554) at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1297) at java.io.ObjectInputStream.readObject(ObjectInputStream.java:351) at hudson.remoting.Channel$ReaderThread.run(Channel.java:1127)

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  • Makefile : Build in a separate directory tree

    - by Simone Margaritelli
    My project (an interpreted language) has a standard library composed by multiple files, each of them will be built into an .so dynamic library that the interpreter will load upon user request (with an import directive). Each source file is located into a subdirectory representing its "namespace", for instance : The build process has to create a "build" directory, then when each file is compiling has to create its namespace directory inside the "build" one, for instance, when compiling std/io/network/tcp.cc he run an mkdir command with mkdir -p build/std/io/network The Makefile snippet is : STDSRC=stdlib/std/hashing/md5.cc \ stdlib/std/hashing/crc32.cc \ stdlib/std/hashing/sha1.cc \ stdlib/std/hashing/sha2.cc \ stdlib/std/io/network/http.cc \ stdlib/std/io/network/tcp.cc \ stdlib/std/io/network/smtp.cc \ stdlib/std/io/file.cc \ stdlib/std/io/console.cc \ stdlib/std/io/xml.cc \ stdlib/std/type/reflection.cc \ stdlib/std/type/string.cc \ stdlib/std/type/matrix.cc \ stdlib/std/type/array.cc \ stdlib/std/type/map.cc \ stdlib/std/type/type.cc \ stdlib/std/type/binary.cc \ stdlib/std/encoding.cc \ stdlib/std/os/dll.cc \ stdlib/std/os/time.cc \ stdlib/std/os/threads.cc \ stdlib/std/os/process.cc \ stdlib/std/pcre.cc \ stdlib/std/math.cc STDOBJ=$(STDSRC:.cc=.so) all: stdlib stdlib: $(STDOBJ) .cc.so: mkdir -p `dirname $< | sed -e 's/stdlib/stdlib\/build/'` $(CXX) $< -o `dirname $< | sed -e 's/stdlib/stdlib\/build/'`/`basename $< .cc`.so $(CFLAGS) $(LDFLAGS) I have two questions : 1 - The problem is that the make command, i really don't know why, doesn't check if a file was modified and launch the build process on ALL the files no matter what, so if i need to build only one file, i have to build them all or use the command : make path/to/single/file.so Is there any way to solve this? 2 - Any way to do this in a "cleaner" way without have to distribute all the build directories with sources? Thanks

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  • Reuse Client java Socket in a Java Server

    - by user1394983
    I'm devoloping an Java server two control an android online game. It's possible save the client socket of myserversocket.accept() in a variable in Client class? This are very util because this way, server can communicate with client when server wants and no when client contact server. My actual code are: import java.io.IOException; import java.io.ObjectInputStream; import java.io.ObjectOutputStream; import java.net.ServerSocket; import java.net.Socket; import java.util.ArrayList; import java.util.UUID; import sal.app.shared.Packet; public class Server { private ArrayList<GameSession> games = new ArrayList<GameSession>(); private ArrayList<Client> pendent_clients = new ArrayList<Client>(); private Packet read_packet= new Packet(); private Packet sent_packet = new Packet(); private Socket clientSocket = null; public static void main(String[] args) throws ClassNotFoundException{ ServerSocket serverSocket = null; //DataInputStream dataInputStream = null; //DataOutputStream dataOutputStream = null; ObjectOutputStream oos=null; ObjectInputStream ois=null; Server myServer = new Server(); try { serverSocket = new ServerSocket(7777); System.out.println("Listening :7777"); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } while(true){ try { myServer.clientSocket = new Socket(); myServer.clientSocket = serverSocket.accept(); myServer.read_packet = new Packet(); myServer.sent_packet = new Packet(); oos = new ObjectOutputStream(myServer.clientSocket.getOutputStream()); ois = new ObjectInputStream(myServer.clientSocket.getInputStream()); //dataInputStream = new DataInputStream(clientSocket.getInputStream()); //dataOutputStream = new DataOutputStream(clientSocket.getOutputStream()); //System.out.println("ip: " + clientSocket.getInetAddress()); //System.out.println("message: " + ois.read()); //dataOutputStream.writeUTF("Hello!"); /*while ((myServer.read_packet = (Packet) ois.readObject()) != null) { myServer.handlePacket(myServer.read_packet); break; }*/ myServer.read_packet=(Packet) ois.readObject(); myServer.handlePacket(myServer.read_packet); //oos.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } finally{ if( myServer.clientSocket!= null){ /*try { //myServer.clientSocket.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ } /*if( ois!= null){ try { ois.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } if( oos!= null){ try { oos.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } }*/ } } } public void handlePacket(Packet hp) throws IOException { if(hp.getOpCode() == 1) { registPlayer(hp); } } public void registPlayer(Packet p) throws IOException { Client registClient = new Client(this.clientSocket); this.pendent_clients.add(registClient); if(pendent_clients.size() == 2) { initAGame(); } else { ObjectOutputStream out=null; Packet to_send = new Packet(); to_send.setOpCode(4); out = new ObjectOutputStream(registClient.getClientSocket().getOutputStream()); out.writeObject(to_send); } } public void initAGame() throws IOException { Client c1 = pendent_clients.get(0); Client c2 = pendent_clients.get(1); Packet to_send = new Packet(); ObjectOutputStream out=null; GameSession incomingGame = new GameSession(c1,c2); games.add(incomingGame); to_send.setGameId(incomingGame.getGameId()); to_send.setOpCode(5); out = new ObjectOutputStream(c1.getClientSocket().getOutputStream()); out.writeObject(to_send); out = new ObjectOutputStream(c2.getClientSocket().getOutputStream()); out.writeObject(to_send); pendent_clients.clear(); } public Client getClientById(UUID given_id) { for(GameSession gs: games) { if(gs.getClient1().getClientId().equals(given_id)) { return gs.getClient1(); } else if(gs.getClient2().getClientId().equals(given_id)) { return gs.getClient2(); } } return null; } } With this code i got this erros: java.net.SocketException: Broken pipe at java.net.SocketOutputStream.socketWrite0(Native Method) at java.net.SocketOutputStream.socketWrite(SocketOutputStream.java:92) at java.net.SocketOutputStream.write(SocketOutputStream.java:136) at java.io.ObjectOutputStream$BlockDataOutputStream.drain(ObjectOutputStream.java:1847) at java.io.ObjectOutputStream$BlockDataOutputStream.setBlockDataMode(ObjectOutputStream.java:1756) at java.io.ObjectOutputStream.writeNonProxyDesc(ObjectOutputStream.java:1257) at java.io.ObjectOutputStream.writeClassDesc(ObjectOutputStream.java:1211) at java.io.ObjectOutputStream.writeOrdinaryObject(ObjectOutputStream.java:1395) at java.io.ObjectOutputStream.writeObject0(ObjectOutputStream.java:1158) at java.io.ObjectOutputStream.writeFatalException(ObjectOutputStream.java:1547) at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:333) at Server.initAGame(Server.java:146) at Server.registPlayer(Server.java:120) at Server.handlePacket(Server.java:106) at Server.main(Server.java:63) This error ocurre when second client connect and server try to send an Packet to previous client 1 in function initGame() in this code: out = new ObjectOutputStream(c1.getClientSocket().getOutputStream()); out.writeObject(to_send); my android code is this: package sal.app; import java.io.DataInputStream; import java.io.DataOutputStream; import java.io.IOException; import java.io.ObjectInputStream; import java.io.ObjectOutputStream; import java.net.Socket; import java.net.UnknownHostException; import sal.app.logic.DataBaseManager; import sal.app.shared.Packet; import android.app.Activity; import android.os.Bundle; import android.view.Window; import android.view.WindowManager; public class MultiPlayerWaitActivity extends Activity{ private DataBaseManager db; public void onCreate(Bundle savedInstanceState) { super.requestWindowFeature(Window.FEATURE_NO_TITLE); super.getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,WindowManager.LayoutParams.FLAG_FULLSCREEN); super.onCreate(savedInstanceState); setContentView(R.layout.multiwaitlayout); db=DataBaseManager.getSalDatabase(this); db.teste(); try { db.createDataBase(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } Socket socket = null; ObjectOutputStream outputStream = null; ObjectInputStream inputStream = null; //System.out.println("dadadad"); try { socket = new Socket("192.168.1.4", 7777); //Game = new MultiPlayerGame(new ServerManager("192.168.1.66"),new Session(), new Player("")); outputStream = new ObjectOutputStream(socket.getOutputStream()); inputStream = new ObjectInputStream(socket.getInputStream()); //dataOutputStream.writeUTF(textOut.getText().toString()); //textIn.setText(dataInputStream.readUTF()); Packet p = new Packet(); Packet r = new Packet(); p.setOpCode(1); outputStream.writeObject(p); /*try { r=(Packet)inputStream.readObject(); } catch (ClassNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ //while(true){ //dataInputStream = new DataInputStream(clientSocket.getInputStream()); //dataOutputStream = new DataOutputStream(clientSocket.getOutputStream()); //System.out.println("ip: " + clientSocket.getInetAddress()); //System.out.println("message: " + ois.read()); //dataOutputStream.writeUTF("Hello!"); /*while ((r= (Packet) inputStream.readObject()) != null) { handPacket(r); break; }*/ r=(Packet) inputStream.readObject(); handPacket(r); //oos.close(); //} /*System.out.println(r.getOpCode()); if(r.getOpCode() == 5) { this.finish(); }*/ } catch (UnknownHostException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /*finally{ if (socket != null){ try { socket.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } if (outputStream != null){ try { outputStream.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } if (inputStream != null){ try { inputStream.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }*/ //catch (ClassNotFoundException e) { // TODO Auto-generated catch block //e.printStackTrace(); //} catch (ClassNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } } public void handPacket(Packet hp) { if(hp.getOpCode() == 5) { this.finish(); } this.finish(); } } Regards

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  • OS Missing? Messed up the MBR on Win7 64-bit

    - by hom3lesshom3boy
    I have a Windows 7 machine with two hard drives: a 1TB C: drive and 500GB J:. I had Windows XP installed on C: and Windows 7 installed on J:. I installed Windows 7 after Windows XP from an installer .exe I (legally) bought and downloaded. It, and all of my other files, are sitting on my J: drive intact. While under my Windows 7 install, a few days ago I decided to use Priform's CCleaner and use its DriveWipe utility to wipe the C: drive. 1% into the process, I cancelled and attempted to use it again. It gives me an error saying it can't format the drive, so I poke around the Internet a bit, give up, and restart my computer. I first get an "OS is missing" error after the computer boots past the BIOS. I downloaded and put UBCD on a bootable USB to use another drivewiping tool to completely erase the C: drive, hoping it'll take the problem with it. No luck. I try to use TestDisk to make my J: my primary active drive, but no luck. I still get the "OS is missing" error. Or sometimes it'll hang at Verifying DMI Pool. Or sometimes I'll get the "NTLDR is missing" error. I get hold of Hiren's and put it on another bootable USB. I first I tried the Boot Windows 7 from Hard Drive option, and I get "Error 15: File Not Found". I tried the "Fix 'NTLDR is Missing'" option (I'm not quite sure why this is even showing up, since I'm trying to get into a HDD with Windows 7 installed. Probably messed up somewhere when I used TestDisk) and I get this list: I'll run through the error messages I get: 1st Try - Windows could not start because the following file is missing or corrupt: \system32\hal.dll 2nd Try - Windows could not start because the following file is missing or corrupt: \system32\ntoskrnl.exe 3rd Try - Windows could not start because of a computer disk hardware configuration problem. Could not read from the selected boot disk. Check boot path and disk hardware. 4th - 8th Try - Same as #3 9th Try - I/O Error accessing boot sector file multi(0)disk(0)fdisk(0)\BOOTSEC.DOS. And computer freezes. 10th Try - computer restarts Needless to say, not a single one of those works. I then tried to open up the Windows 7 exe I have sitting on my J: from the Mini-XP OS on Hiren's, but it won't run because I'm trying to run a 64-bit file from a 32-bit exe. At least, that's the problem according to these guys: http://social.technet.microsoft.com/...-b2f54e9c7d18/ I then borrowed a 64-bit Windows Home Premium CD from a friend to get to the recovery options. But I get the error message: This version of System Recovery Options is not compatible with the version of Windows you are trying to repair. Try using a recovery disc that is compatible with this version of Windows. I pressed Shift + F10 to get to the Command Prompt directly. These are the exact steps I took from there (paraphrased a little): X:\Sources>bootrec /Fixmbr The operation completed successfully. X:\Sources>bootrec /Fixboot The operation completed successfully. I restarted my computer, but it still didn't work. I unplugged the C: drive, then tried bootrec and Diskpart: X:\Sources> bootrec.exe X:\Sources> bootrec /RebuildBcd Total identified Windows installations: 1 [1] \\?\GLOBALROOT\Device\HarddiskVolume1\Windows Add installation to bootlist? Yes(Y)/No(N)/All(A):y The requested system device cannot be found. X:\Sources>DiskPart DISKPART> List Disk Disk # Status Size Free Dyn Gpt Disk 0_Online_465GB_0B_______* Disk 1 Online 1000MB 0B (this is Hiren's on a bootable usb) DISKPART> Select Disk 0 Disk 0 is now the selected disk. DISKPART> List Partition Partition # Type Size Offset Partition 1 System 465GB 31KB DISKPART> Select Partition 1 Partition 1 is now the selected partition DISKPART> Active The selected disk is not a fixed MBR disk. The ACTIVE command can only be used on fixed MBR disks. DISKPART> exit Leaving Diskpart... X:\Sources>bootrec /Fixmbr The operation completed successfully. X:\Sources>bootrec /Fixboot The operation completed successfully. Before I go any further, is there anything I'm overlooking/doing wrong? All I care about is making the J: and Windows 7 bootable again. SPECS: Windows 7 Professional 64-Bit GIGABYTE - Motherboard - Socket 775 - GA-P35-DS3R (rev. 2.1) Crucial Ballistix 2048MB PC6400 DDR2 800MHz (2x2GB) Intel Core 2 Duo E6700 Processor (2.6 (6GHZ) I think... not sure anymore C: HDD - SAMSUNG HD103UJ (1TB, not plugged in) J: HDD - WDC WD5000AKS-00V1A0 (500GB)

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  • e2fsck extremly slow, although enough memory exists

    - by kaefert
    I've got this external USB-Disk: kaefert@blechmobil:~$ lsusb -s 2:3 Bus 002 Device 003: ID 0bc2:3320 Seagate RSS LLC As can be seen in this dmesg output, there are some problems that prevents that disk from beeing mounted: kaefert@blechmobil:~$ dmesg | grep sdb [ 114.474342] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.475089] sd 5:0:0:0: [sdb] Write Protect is off [ 114.475092] sd 5:0:0:0: [sdb] Mode Sense: 43 00 00 00 [ 114.475959] sd 5:0:0:0: [sdb] Write cache: enabled, read cache: enabled, doesn't support DPO or FUA [ 114.477093] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.501649] sdb: sdb1 [ 114.502717] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.504354] sd 5:0:0:0: [sdb] Attached SCSI disk [ 116.804408] EXT4-fs (sdb1): ext4_check_descriptors: Checksum for group 3976 failed (47397!=61519) [ 116.804413] EXT4-fs (sdb1): group descriptors corrupted! So I went and fired up my favorite partition manager - gparted, and told it to verify and repair the partition sdb1. This made gparted call e2fsck (version 1.42.4 (12-Jun-2012)) e2fsck -f -y -v /dev/sdb1 Although gparted called e2fsck with the "-v" option, sadly it doesn't show me the output of my e2fsck process (bugreport https://bugzilla.gnome.org/show_bug.cgi?id=467925 ) I started this whole thing on Sunday (2012-11-04_2200) evening, so about 48 hours ago, this is what htop says about it now (2012-11-06-1900): PID USER PRI NI VIRT RES SHR S CPU% MEM% TIME+ Command 3704 root 39 19 1560M 1166M 768 R 98.0 19.5 42h56:43 e2fsck -f -y -v /dev/sdb1 Now I found a few posts on the internet that discuss e2fsck running slow, for example: http://gparted-forum.surf4.info/viewtopic.php?id=13613 where they write that its a good idea to see if the disk is just that slow because maybe its damaged, and I think these outputs tell me that this is not the case in my case: kaefert@blechmobil:~$ sudo hdparm -tT /dev/sdb /dev/sdb: Timing cached reads: 3562 MB in 2.00 seconds = 1783.29 MB/sec Timing buffered disk reads: 82 MB in 3.01 seconds = 27.26 MB/sec kaefert@blechmobil:~$ sudo hdparm /dev/sdb /dev/sdb: multcount = 0 (off) readonly = 0 (off) readahead = 256 (on) geometry = 364801/255/63, sectors = 5860533160, start = 0 However, although I can read quickly from that disk, this disk speed doesn't seem to be used by e2fsck, considering tools like gkrellm or iotop or this: kaefert@blechmobil:~$ iostat -x Linux 3.2.0-2-amd64 (blechmobil) 2012-11-06 _x86_64_ (2 CPU) avg-cpu: %user %nice %system %iowait %steal %idle 14,24 47,81 14,63 0,95 0,00 22,37 Device: rrqm/s wrqm/s r/s w/s rkB/s wkB/s avgrq-sz avgqu-sz await r_await w_await svctm %util sda 0,59 8,29 2,42 5,14 43,17 160,17 53,75 0,30 39,80 8,72 54,42 3,95 2,99 sdb 137,54 5,48 9,23 0,20 587,07 22,73 129,35 0,07 7,70 7,51 16,18 2,17 2,04 Now I researched a little bit on how to find out what e2fsck is doing with all that processor time, and I found the tool strace, which gives me this: kaefert@blechmobil:~$ sudo strace -p3704 lseek(4, 41026998272, SEEK_SET) = 41026998272 write(4, "\212\354K[_\361\3nl\212\245\352\255jR\303\354\312Yv\334p\253r\217\265\3567\325\257\3766"..., 4096) = 4096 lseek(4, 48404766720, SEEK_SET) = 48404766720 read(4, "\7t\260\366\346\337\304\210\33\267j\35\377'\31f\372\252\ffU\317.y\211\360\36\240c\30`\34"..., 4096) = 4096 lseek(4, 41027002368, SEEK_SET) = 41027002368 write(4, "\232]7Ws\321\352\t\1@[+5\263\334\276{\343zZx\352\21\316`1\271[\202\350R`"..., 4096) = 4096 lseek(4, 48404770816, SEEK_SET) = 48404770816 read(4, "\17\362r\230\327\25\346//\210H\v\311\3237\323K\304\306\361a\223\311\324\272?\213\tq \370\24"..., 4096) = 4096 lseek(4, 41027006464, SEEK_SET) = 41027006464 write(4, "\367yy>x\216?=\324Z\305\351\376&\25\244\210\271\22\306}\276\237\370(\214\205G\262\360\257#"..., 4096) = 4096 lseek(4, 48404774912, SEEK_SET) = 48404774912 read(4, "\365\25\0\21|T\0\21}3t_\272\373\222k\r\177\303\1\201\261\221$\261B\232\3142\21U\316"..., 4096) = 4096 ^CProcess 3704 detached around 16 of these lines every second, so 4 read and 4 write operations every second, which I don't consider to be a lot.. And finally, my question: Will this process ever finish? If those numbers from fseek (48404774912) represent bytes, that would be something like 45 gigabytes, with this beeing a 3 terrabyte disk, which would give me 134 days to go, if the speed stays constant, and he scans the disk like this completly and only once. Do you have some advice for me? I have most of the data on that disk elsewhere, but I've put a lot of hours into sorting and merging it to this disk, so I would prefer to getting this disk up and running again, without formatting it anew. I don't think that the hardware is damaged since the disk is only a few months and since I can't see any I/O errors in the dmesg output. UPDATE: I just looked at the strace output again (2012-11-06_2300), now it looks like this: lseek(4, 1419860611072, SEEK_SET) = 1419860611072 read(4, "3#\f\2447\335\0\22A\355\374\276j\204'\207|\217V|\23\245[\7VP\251\242\276\207\317:"..., 4096) = 4096 lseek(4, 43018145792, SEEK_SET) = 43018145792 write(4, "]\206\231\342Y\204-2I\362\242\344\6R\205\361\324\177\265\317C\334V\324\260\334\275t=\10F."..., 4096) = 4096 lseek(4, 1419860615168, SEEK_SET) = 1419860615168 read(4, "\262\305\314Y\367\37x\326\245\226\226\320N\333$s\34\204\311\222\7\315\236\336\300TK\337\264\236\211n"..., 4096) = 4096 lseek(4, 43018149888, SEEK_SET) = 43018149888 write(4, "\271\224m\311\224\25!I\376\16;\377\0\223H\25Yd\201Y\342\r\203\271\24eG<\202{\373V"..., 4096) = 4096 lseek(4, 1419860619264, SEEK_SET) = 1419860619264 read(4, ";d\360\177\n\346\253\210\222|\250\352T\335M\33\260\320\261\7g\222P\344H?t\240\20\2548\310"..., 4096) = 4096 lseek(4, 43018153984, SEEK_SET) = 43018153984 write(4, "\360\252j\317\310\251G\227\335{\214`\341\267\31Y\202\360\v\374\307oq\3063\217Z\223\313\36D\211"..., 4096) = 4096 So this number of the lseeks before the reads, like 1419860619264 are already a lot bigger, standing for 1.29 terabytes if the numbers are bytes, so it doesn't seem to be a linear progress on a big scale, maybe there are only some areas that need work, that have big gaps in between them. (times are in CET)

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  • Why Are Minimized Programs Often Slow to Open Again?

    - by Jason Fitzpatrick
    It seems particularly counterintuitive: you minimize an application because you plan on returning to it later and wish to skip shutting the application down and restarting it later, but sometimes maximizing it takes even longer than launching it fresh. What gives? Today’s Question & Answer session comes to us courtesy of SuperUser—a subdivision of Stack Exchange, a community-driven grouping of Q&A web sites. The Question SuperUser reader Bart wants to know why he’s not saving any time with application minimization: I’m working in Photoshop CS6 and multiple browsers a lot. I’m not using them all at once, so sometimes some applications are minimized to taskbar for hours or days. The problem is, when I try to maximize them from the taskbar – it sometimes takes longer than starting them! Especially Photoshop feels really weird for many seconds after finally showing up, it’s slow, unresponsive and even sometimes totally freezes for minute or two. It’s not a hardware problem as it’s been like that since always on all on my PCs. Would I also notice it after upgrading my HDD to SDD and adding RAM (my main PC holds 4 GB currently)? Could guys with powerful pcs / macs tell me – does it also happen to you? I guess OSes somehow “focus” on active software and move all the resources away from the ones that run, but are not used. Is it possible to somehow set RAM / CPU / HDD priorities or something, for let’s say, Photoshop, so it won’t slow down after long period of inactivity? So what is the deal? Why does he find himself waiting to maximize a minimized app? The Answer SuperUser contributor Allquixotic explains why: Summary The immediate problem is that the programs that you have minimized are being paged out to the “page file” on your hard disk. This symptom can be improved by installing a Solid State Disk (SSD), adding more RAM to your system, reducing the number of programs you have open, or upgrading to a newer system architecture (for instance, Ivy Bridge or Haswell). Out of these options, adding more RAM is generally the most effective solution. Explanation The default behavior of Windows is to give active applications priority over inactive applications for having a spot in RAM. When there’s significant memory pressure (meaning the system doesn’t have a lot of free RAM if it were to let every program have all the RAM it wants), it starts putting minimized programs into the page file, which means it writes out their contents from RAM to disk, and then makes that area of RAM free. That free RAM helps programs you’re actively using — say, your web browser — run faster, because if they need to claim a new segment of RAM (like when you open a new tab), they can do so. This “free” RAM is also used as page cache, which means that when active programs attempt to read data on your hard disk, that data might be cached in RAM, which prevents your hard disk from being accessed to get that data. By using the majority of your RAM for page cache, and swapping out unused programs to disk, Windows is trying to improve responsiveness of the program(s) you are actively using, by making RAM available to them, and caching the files they access in RAM instead of the hard disk. The downside of this behavior is that minimized programs can take a while to have their contents copied from the page file, on disk, back into RAM. The time increases the larger the program’s footprint in memory. This is why you experience that delay when maximizing Photoshop. RAM is many times faster than a hard disk (depending on the specific hardware, it can be up to several orders of magnitude). An SSD is considerably faster than a hard disk, but it is still slower than RAM by orders of magnitude. Having your page file on an SSD will help, but it will also wear out the SSD more quickly than usual if your page file is heavily utilized due to RAM pressure. Remedies Here is an explanation of the available remedies, and their general effectiveness: Installing more RAM: This is the recommended path. If your system does not support more RAM than you already have installed, you will need to upgrade more of your system: possibly your motherboard, CPU, chassis, power supply, etc. depending on how old it is. If it’s a laptop, chances are you’ll have to buy an entire new laptop that supports more installed RAM. When you install more RAM, you reduce memory pressure, which reduces use of the page file, which is a good thing all around. You also make available more RAM for page cache, which will make all programs that access the hard disk run faster. As of Q4 2013, my personal recommendation is that you have at least 8 GB of RAM for a desktop or laptop whose purpose is anything more complex than web browsing and email. That means photo editing, video editing/viewing, playing computer games, audio editing or recording, programming / development, etc. all should have at least 8 GB of RAM, if not more. Run fewer programs at a time: This will only work if the programs you are running do not use a lot of memory on their own. Unfortunately, Adobe Creative Suite products such as Photoshop CS6 are known for using an enormous amount of memory. This also limits your multitasking ability. It’s a temporary, free remedy, but it can be an inconvenience to close down your web browser or Word every time you start Photoshop, for instance. This also wouldn’t stop Photoshop from being swapped when minimizing it, so it really isn’t a very effective solution. It only helps in some specific situations. Install an SSD: If your page file is on an SSD, the SSD’s improved speed compared to a hard disk will result in generally improved performance when the page file has to be read from or written to. Be aware that SSDs are not designed to withstand a very frequent and constant random stream of writes; they can only be written over a limited number of times before they start to break down. Heavy use of a page file is not a particularly good workload for an SSD. You should install an SSD in combination with a large amount of RAM if you want maximum performance while preserving the longevity of the SSD. Use a newer system architecture: Depending on the age of your system, you may be using an out of date system architecture. The “system architecture” is generally defined as the “generation” (think generations like children, parents, grandparents, etc.) of the motherboard and CPU. Newer generations generally support faster I/O (input/output), better memory bandwidth, lower latency, and less contention over shared resources, instead providing dedicated links between components. For example, starting with the “Nehalem” generation (around 2009), the Front-Side Bus (FSB) was eliminated, which removed a common bottleneck, because almost all system components had to share the same FSB for transmitting data. This was replaced with a “point to point” architecture, meaning that each component gets its own dedicated “lane” to the CPU, which continues to be improved every few years with new generations. You will generally see a more significant improvement in overall system performance depending on the “gap” between your computer’s architecture and the latest one available. For example, a Pentium 4 architecture from 2004 is going to see a much more significant improvement upgrading to “Haswell” (the latest as of Q4 2013) than a “Sandy Bridge” architecture from ~2010. Links Related questions: How to reduce disk thrashing (paging)? Windows Swap (Page File): Enable or Disable? Also, just in case you’re considering it, you really shouldn’t disable the page file, as this will only make matters worse; see here. And, in case you needed extra convincing to leave the Windows Page File alone, see here and here. Have something to add to the explanation? Sound off in the the comments. Want to read more answers from other tech-savvy Stack Exchange users? Check out the full discussion thread here.     

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  • OMAP 3530: How fast can I toggle an IO?

    - by raj.tiwari
    I am putting together an application for OMAP 3530 SoC. This application will run some user interface code on embedded linux and invoke waveform generation code on the DSP. The DSP and Linux sides will interact over DSP/BIOS link. My questions are: What is the highest frequency at which my DSP-side code can toggle a GPIO line? If I want to toggle multiple GPIO lines at this hight rate, how fast can I go? Thanks for any insights. -Raj

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  • I need to write a program that reads angles in radians from an input disk and converts them in degre

    - by Amadou
    Write a program that reads angles in radians from an input disk le and converts them into degrees, minutes, and seconds. Output should be written into another le. A sample input le could be: # this is a comment # your program should be able to skip comment lines # and blank lines # input radian numbers could be seperated by blanks 0.0 1.0 # or by a newline 3.141593 6.0

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  • Is it possible to gzip and upload this string to Amazon S3 without ever being written to disk?

    - by BigJoe714
    I know this is probably possible using Streams, but I wasn't sure the correct syntax. I would like to pass a string to the Save method and have it gzip the string and upload it to Amazon S3 without ever being written to disk. The current method inefficiently reads/writes to disk in between. The S3 PutObjectRequest has a constructor with InputStream input as an option. import java.io.*; import java.util.zip.GZIPOutputStream; import com.amazonaws.auth.PropertiesCredentials; import com.amazonaws.services.s3.AmazonS3; import com.amazonaws.services.s3.AmazonS3Client; import com.amazonaws.services.s3.model.PutObjectRequest; public class FileStore { public static void Save(String data) throws IOException { File file = File.createTempFile("filemaster-", ".htm"); file.deleteOnExit(); Writer writer = new OutputStreamWriter(new FileOutputStream(file)); writer.write(data); writer.flush(); writer.close(); String zippedFilename = gzipFile(file.getAbsolutePath()); File zippedFile = new File(zippedFilename); zippedFile.deleteOnExit(); AmazonS3 s3 = new AmazonS3Client(new PropertiesCredentials( new FileInputStream("AwsCredentials.properties"))); String bucketName = "mybucket"; String key = "test/" + zippedFile.getName(); s3.putObject(new PutObjectRequest(bucketName, key, zippedFile)); } public static String gzipFile(String filename) throws IOException { try { // Create the GZIP output stream String outFilename = filename + ".gz"; GZIPOutputStream out = new GZIPOutputStream(new FileOutputStream(outFilename)); // Open the input file FileInputStream in = new FileInputStream(filename); // Transfer bytes from the input file to the GZIP output stream byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); // Complete the GZIP file out.finish(); out.close(); return outFilename; } catch (IOException e) { throw e; } } }

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  • Writing Device Drivers for Microcontrollers, where to define IO Port pins?

    - by volting
    I always seem to encounter this dilemma when writing low level code for MCU's. I never know where to declare pin definitions so as to make the code as reusable as possible. In this case Im writing a driver to interface an 8051 to a MCP4922 12bit serial DAC. Im unsure how/where I should declare the pin definitions for The CS(chip select) and LDAC(data latch) for the DAC. At the moment there declared in the header file for the driver. Iv done a lot of research trying to figure out the best approach but havent really found anything. Im basically want to know what the best practices... if there are some books worth reading or online information, examples etc, any recommendations would be welcome. Just a snippet of the driver so you get the idea /** @brief This function is used to write a 16bit data word to DAC B -12 data bit plus 4 configuration bits @param dac_data A 12bit word @param ip_buf_unbuf_select Input Buffered/unbuffered select bit. Buffered = 1; Unbuffered = 0 @param gain_select Output Gain Selection bit. 1 = 1x (VOUT = VREF * D/4096). 0 =2x (VOUT = 2 * VREF * D/4096) */ void MCP4922_DAC_B_TX_word(unsigned short int dac_data, bit ip_buf_unbuf_select, bit gain_select) { unsigned char low_byte=0, high_byte=0; CS = 0; /**Select the chip*/ high_byte |= ((0x01 << 7) | (0x01 << 4)); /**Set bit to select DAC A and Set SHDN bit high for DAC A active operation*/ if(ip_buf_unbuf_select) high_byte |= (0x01 << 6); if(gain_select) high_byte |= (0x01 << 5); high_byte |= ((dac_data >> 8) & 0x0F); low_byte |= dac_data; SPI_master_byte(high_byte); SPI_master_byte(low_byte); CS = 1; LDAC = 0; /**Latch the Data*/ LDAC = 1; }

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  • Java MapReduce read data

    - by Tatiana
    Hi I am having following map-reduce code by which I am trying to read records from my database. There's code: import java.io.*; import java.util.ArrayList; import java.util.List; import org.apache.hadoop.fs.*; import org.apache.hadoop.io.*; import org.apache.hadoop.mapred.*; import org.apache.hadoop.mapred.lib.db.DBConfiguration; import org.apache.hadoop.mapred.lib.db.DBInputFormat; import org.apache.hadoop.mapred.lib.db.DBWritable; import org.apache.hadoop.util.*; import org.apache.hadoop.conf.*; public class Connection extends Configured implements Tool { public int run(String[] args) throws IOException { JobConf conf = new JobConf(getConf(), Connection.class); conf.setInputFormat(DBInputFormat.class); DBConfiguration.configureDB(conf, "com.sun.java.util.jar.pack.Driver", "jdbc:postgresql://localhost:5432/polyclinic", "postgres", "12345"); String[] fields = { "name" }; DBInputFormat.setInput(conf, MyRecord.class, "doctors", null, null, fields); conf.setMapOutputKeyClass(LongWritable.class); conf.setMapOutputValueClass(MyRecord.class); conf.setOutputKeyClass(LongWritable.class); conf.setOutputValueClass(TextOutputFormat.class); TextOutputFormat.setOutputPath(conf, new Path(args[0])); JobClient.runJob(conf); return 0; } public static void main(String[] args) throws Exception { int exitCode = ToolRunner.run(new Connection(), args); System.exit(exitCode); } } Class Mapper: import java.io.IOException; import org.apache.hadoop.io.IntWritable; import org.apache.hadoop.io.LongWritable; import org.apache.hadoop.io.Text; import org.apache.hadoop.mapred.MapReduceBase; import org.apache.hadoop.mapred.Mapper; import org.apache.hadoop.mapred.OutputCollector; import org.apache.hadoop.mapred.Reporter; public class MyMapper extends MapReduceBase implements Mapper<LongWritable, MyRecord, Text, IntWritable> { public void map(LongWritable key, MyRecord val, OutputCollector<Text, IntWritable> output, Reporter reporter) throws IOException { output.collect(new Text(val.name), new IntWritable(1)); } } Class Record: import java.io.DataInput; import java.io.DataOutput; import java.io.IOException; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import org.apache.hadoop.io.Text; import org.apache.hadoop.io.Writable; import org.apache.hadoop.mapred.lib.db.DBWritable; class MyRecord implements Writable, DBWritable { String name; public void readFields(DataInput in) throws IOException { this.name = Text.readString(in); } public void readFields(ResultSet resultSet) throws SQLException { this.name = resultSet.getString(1); } public void write(DataOutput out) throws IOException { } public void write(PreparedStatement stmt) throws SQLException { } } After this I got error: WARN mapred.JobClient: No job jar file set. User classes may not be found. See JobConf(Class) or JobConf#setJar(String). Can you give me any suggestion how to solve this problem?

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  • SCJP Book, IO section: Is this a typo or is there a reason it would look like this?

    - by iamchuckb
    My question is about line 4, where the new PrintWriter is created with the constructor taking the FileWriter fw as a parameter. I don't understand the use of chaining the BufferedWriter bw to FileWriter if it isn't used later on in the actual writing. Can Java apply chaining in a way that bw still somehow affects the rest of the program? 16. try { 17. FileWriter fw = new FileWriter(test); 18. BufferedWriter bw = new BufferedWriter(fw, 1024); 19. PrintWriter out = new PrintWriter(fw); 20. out.println("<html><body><h1>"); 21. out.println(args[0]); 22. out.println("</h1></body></html>"); 23. out.close(); 24. bw.close(); 25. fw.close(); 26. }catch(IOException e) { 27. e.printStackTrace(); 28. } I think it is probably a typo and they meant to use bw as the parameter for PrintWriter out but like the title says, I'm new to this. Thanks to all in advance.

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  • Java/Groovy File IO Replacing an Image File with it's own Contents - Why Does This Work?

    - by jboyd
    I have some JPG files that need to be replaced at runtime with a JFIF standardized version of themselves (we are using a vendor that gives us JPG that do not have proper headers so they don't work in certain applications)... I am able to create a new file from the existing image, then get a buffered image from that file and write the contents right back into the file without having to delete it and it works... imageSrcFolder.eachFileMatch ( ~/.*\.jpg/, { BufferedImage bi = ImageIO.read( it ) ImageIO.write( bi, "jpg", it ) }); The question I have is why? Why doesn't the file end up doubled in size? Why don't I have to delete it first? Why am I able to take a file object to an existing file and then treat it as if it were a brand new one? It seems that what I consider to be a "file" is not what the File object in java actually is, or else this wouldn't work at all. My code does exactly what I want it to do, but I'm not convinced it always will... it just seems way too easy

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  • C++ to python communication. Multiple io streams?

    - by Dennis Kempin
    A python program opens a new process of the C++ program and is reading the processes stdout. No problem so far. But is it possible to have multiple streams like this for communication? I can get two if I misuse stderr too, but not more. Easy way to hack this would be using temporary files. Is there something more elegant that does not need a detour to the filesystem? PS: *nix specific solutions are welcome too

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  • Io exception: There is no process to read data written to a pipe.

    - by Srikanth
    I'm using Hibernate3.2+Websphere6.0+struts1.3.. After deploying ,application works fine. After some idle time ,i will get this type of error repeatedly,am not able to login at all. Im not using any connection pooling. i feel after idle time its not able to connect to the database again..if i restart the server everything works fine for some time...after that same story.. please help me out

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