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  • Basic regexp help

    - by casben79
    I am new to programming PHP and am trying to validate a field in a form. The field if for a RAL color code and so would look something like : RAL 1001. so the letters RAL and then 4 numbers. Can someone help me set them into a regular expression to validate them. i have tried this with no success: $string_exp = "/^[RAL][0-9 .-]+$/i"; What can I say but sorry for being a complete NOOB at PHP. Cheers Ben

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  • How do I locate a particular word in a text file using .NET

    - by cmrhema
    I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that?

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  • Not-quite-JSON string deserialization in Python

    - by cpharmston
    I get the following text as a string from an XML-based REST API 'd':4 'ca':5 'sen':1 'diann':2,6,8 'feinstein':3,7,9 that I'm looking to deserialize into a pretty little Python dictionary: { 'd': [4], 'ca': [5], 'sen': [1], 'diann': [2, 6, 8], 'feinstein': [3, 7, 9] } I'm hoping to avoid using regular expressions or heavy string manipulation, as this format isn't documented and may change. The best I've been able to come up with: members = {} for m in elem.text.split(' '): m = m.split(':') members[m[0].replace("'", '')] = map(int, m[1].split(',')) return members Obviously a terrible approach, but it works, and that's better than anything else I've got right now. Any suggestions on better approaches?

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  • Problem with Javascript RegExp-mask

    - by OrjanL
    I have a string that looks something like this: {theField} > YEAR (today, -3) || {theField} < YEAR (today, +3) I want it to be replaced into: {theField} > " + YEAR (today, -3) + " || {theField} < " + YEAR (today, +3) + " I have tried this: String.replace(/(.*)(YEAR|MONTH|WEEK|DAY+)(.*[)]+)/g, "$1 \" + $2 $3 + \"") But that gives me: {theField} > YEAR (today, +3) || {theField} > " + YEAR (today, +3) + " Does anyone have any ideas?

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  • Java RegExp ViewState

    - by CDSO1
    I am porting some functionality from a C++ application to java. This involves reading non-modifiable data files that contain regular expressions. A lot of the data files contain regular expressions that look similar to the following: (?<=id="VIEWSTATE".*?value=").*?(?=") These regular expressions produce the following error: "Look-behind group does not have an obvious maximum length near index XX" In C++ the engine being used supported these expressions. Is there another form of regexp that can produce the same result that can be generated using expressions like my example as input?

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  • parse search string

    - by Benjamin Ortuzar
    I have search strings, similar to the one bellow: energy food "olympics 2010" Terrorism OR "government" OR cups NOT transport and I need to parse it with PHP5 to detect if the content belongs to any of the following clusters: AllWords array AnyWords array NotWords array These are the rules i have set: If it has OR before or after the word or quoted words if belongs to AnyWord. If it has a NOT before word or quoted words it belongs to NotWords If it has 0 or more more spaces before the word or quoted phrase it belongs to AllWords. So the end result should be something similar to: AllWords: (energy, food, "olympics 2010") AnyWords: (terrorism, "government", cups) NotWords: (Transport) What would be a good way to do this?

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  • multiline perl search and replace (one-liner)

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with perl. I would prefer to allow for any occurences of white space and/or new lines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> </div>

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  • UPDATE REGEX MYSQL

    - by Simon
    I have a table of contacts and a table of postcode data. I need to match the first part of the postcode and the join that with the postcode table... and then perform an update... I want to do something like this... UPDATE `contacts` LEFT JOIN `postcodes` ON PREG_GREP("/^[A-Z]{1,2}[0-9][0-9A-Z]{0,1}/", `contacts`.`postcode`) = `postcodes`.`postcode` SET `contacts`.`lat` = `postcode`.`lat`, `contacts`.`lng` = `postcode`.`lng` Is it possible?? Or do I need to use an external script? Many thanks.

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  • How can I use Perl regular expressions to parse XML data?

    - by Luke
    I have a pretty long piece of XML that I want to parse. I want to remove everything except for the subclass-code and city. So that I am left with something like the example below. EXAMPLE TEST SUBCLASS|MIAMI CODE <?xml version="1.0" standalone="no"?> <web-export> <run-date>06/01/2010 <pub-code>TEST <ad-type>TEST <cat-code>Real Estate</cat-code> <class-code>TEST</class-code> <subclass-code>TEST SUBCLASS</subclass-code> <placement-description></placement-description> <position-description>Town House</position-description> <subclass3-code></subclass3-code> <subclass4-code></subclass4-code> <ad-number>0000284708-01</ad-number> <start-date>05/28/2010</start-date> <end-date>06/09/2010</end-date> <line-count>6</line-count> <run-count>13</run-count> <customer-type>Private Party</customer-type> <account-number>100099237</account-number> <account-name>DOE, JOHN</account-name> <addr-1>207 CLARENCE STREET</addr-1> <addr-2> </addr-2> <city>MIAMI</city> <state>FL</state> <postal-code>02910</postal-code> <country>USA</country> <phone-number>4014612880</phone-number> <fax-number></fax-number> <url-addr> </url-addr> <email-addr>[email protected]</email-addr> <pay-flag>N</pay-flag> <ad-description>DEANESTATES2BEDS2BATHSAPPLIANCED</ad-description> <order-source>Import</order-source> <order-status>Live</order-status> <payor-acct>100099237</payor-acct> <agency-flag>N</agency-flag> <rate-note></rate-note> <ad-content> MIAMI&#47;Dean Estates&#58; 2 beds&#44; 2 baths&#46; Applianced&#46; Central air&#46; Carpets&#46; Laundry&#46; 2 decks&#46; Pool&#46; Parking&#46; Close to everything&#46;No smoking&#46; No utilities&#46; &#36;1275 mo&#46; 401&#45;578&#45;1501&#46; </ad-content> </ad-type> </pub-code> </run-date> </web-export> PERL So what I want to do is open an existing file read the contents then use regular expressions to eliminate the unnecessary XML tags. open(READFILE, "FILENAME"); while(<READFILE>) { $_ =~ s/<\?xml version="(.*)" standalone="(.*)"\?>\n.*//g; $_ =~ s/<subclass-code>//g; $_ =~ s/<\/subclass-code>\n.*/|/g; $_ =~ s/(.*)PJ RER Houses /PJ RER Houses/g; $_ =~ s/\G //g; $_ =~ s/<city>//g; $_ =~ s/<\/city>\n.*//g; $_ =~ s/<(\/?)web-export>(.*)\n.*//g; $_ =~ s/<(\/?)run-date>(.*)\n.*//g; $_ =~ s/<(\/?)pub-code>(.*)\n.*//g; $_ =~ s/<(\/?)ad-type>(.*)\n.*//g; $_ =~ s/<(\/?)cat-code>(.*)<(\/?)cat-code>\n.*//g; $_ =~ s/<(\/?)class-code>(.*)<(\/?)class-code>\n.*//g; $_ =~ s/<(\/?)placement-description>(.*)<(\/?)placement-description>\n.*//g; $_ =~ s/<(\/?)position-description>(.*)<(\/?)position-description>\n.*//g; $_ =~ s/<(\/?)subclass3-code>(.*)<(\/?)subclass3-code>\n.*//g; $_ =~ s/<(\/?)subclass4-code>(.*)<(\/?)subclass4-code>\n.*//g; $_ =~ s/<(\/?)ad-number>(.*)<(\/?)ad-number>\n.*//g; $_ =~ s/<(\/?)start-date>(.*)<(\/?)start-date>\n.*//g; $_ =~ s/<(\/?)end-date>(.*)<(\/?)end-date>\n.*//g; $_ =~ s/<(\/?)line-count>(.*)<(\/?)line-count>\n.*//g; $_ =~ s/<(\/?)run-count>(.*)<(\/?)run-count>\n.*//g; $_ =~ s/<(\/?)customer-type>(.*)<(\/?)customer-type>\n.*//g; $_ =~ s/<(\/?)account-number>(.*)<(\/?)account-number>\n.*//g; $_ =~ s/<(\/?)account-name>(.*)<(\/?)account-name>\n.*//g; $_ =~ s/<(\/?)addr-1>(.*)<(\/?)addr-1>\n.*//g; $_ =~ s/<(\/?)addr-2>(.*)<(\/?)addr-2>\n.*//g; $_ =~ s/<(\/?)state>(.*)<(\/?)state>\n.*//g; $_ =~ s/<(\/?)postal-code>(.*)<(\/?)postal-code>\n.*//g; $_ =~ s/<(\/?)country>(.*)<(\/?)country>\n.*//g; $_ =~ s/<(\/?)phone-number>(.*)<(\/?)phone-number>\n.*//g; $_ =~ s/<(\/?)fax-number>(.*)<(\/?)fax-number>\n.*//g; $_ =~ s/<(\/?)url-addr>(.*)<(\/?)url-addr>\n.*//g; $_ =~ s/<(\/?)email-addr>(.*)<(\/?)email-addr>\n.*//g; $_ =~ s/<(\/?)pay-flag>(.*)<(\/?)pay-flag>\n.*//g; $_ =~ s/<(\/?)ad-description>(.*)<(\/?)ad-description>\n.*//g; $_ =~ s/<(\/?)order-source>(.*)<(\/?)order-source>\n.*//g; $_ =~ s/<(\/?)order-status>(.*)<(\/?)order-status>\n.*//g; $_ =~ s/<(\/?)payor-acct>(.*)<(\/?)payor-acct>\n.*//g; $_ =~ s/<(\/?)agency-flag>(.*)<(\/?)agency-flag>\n.*//g; $_ =~ s/<(\/?)rate-note>(.*)<(\/?)rate-note>\n.*//g; $_ =~ s/<ad-content>(.*)\n.*//g; $_ =~ s/\t(.*)\n.*//g; $_ =~ s/<\/ad-content>(.*)\n.*//g; } close( READFILE1 ); Is there an easier way of doing this? I don't want to use any modules. I know that it might make this easier but the file I am reading has a lot of data in it.

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  • preg_replace only part of match

    - by Tony Vipros
    Hi, I'm using preg_replace to create urls for modrewrite based paging links. I use: $nextURL = preg_replace('%/([\d]+)/%','/'.($pageNumber+1).'/',$currentURL); which works fine, however I was wondering if there is a better way without having to include the '/' in the replacement parameter. I need to match the number as being between two / as the URLs can sometimes contain numbers other than the page part. These numbers are never only numbers however, so have /[\d]+/ stops them from getting replaced.

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  • strange behavior in vim with negative look-behind

    - by João Portela
    So, I am doing this search in vim: /\(\(unum\)\|\(player\)=\)\@<!\"1\" and as expected it does not match lines that have: player="1" but matches lines that have: unum="1" what am i doing wrong? isn't the atom to be negated all of this: \(\(unum\)\|\(player\)=\) naturally just doing: /\(\(unum\)\|\(player\)=\) matches unum= or player=.

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  • Regexp match in Java

    - by tinti
    Regexp in Java I want to make a regexp who do this verify if a word is like [0-9A-Za-z][._-'][0-9A-Za-z] example for valid words A21a_c32 daA.da2 das'2 dsada ASDA 12SA89 non valid words dsa#da2 34$ Thanks

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  • In Python BeautifulSoup How to move tags

    - by JJ
    I have a partially converted XML document in soup coming from HTML. After some replacement and editing in the soup, the body is essentially - <Text...></Text> # This replaces <a href..> tags but automatically creates the </Text> <p class=norm ...</p> <p class=norm ...</p> <Text...></Text> <p class=norm ...</p> and so forth. I need to "move" the <p> tags to be children to <Text> or know how to suppress the </Text>. I want - <Text...> <p class=norm ...</p> <p class=norm ...</p> </Text> <Text...> <p class=norm ...</p> </Text> I've tried using item.insert and item.append but I'm thinking there must be a more elegant solution. for item in soup.findAll(['p','span']): if item.name == 'span' and item.has_key('class') and item['class'] == 'section': xBCV = short_2_long(item._getAttrMap().get('value','')) if currentnode: pass currentnode = Tag(soup,'Text', attrs=[('TypeOf', 'Section'),... ]) item.replaceWith(currentnode) # works but creates end tag elif item.name == 'p' and item.has_key('class') and item['class'] == 'norm': childcdatanode = None for ahref in item.findAll('a'): if childcdatanode: pass newlink = filter_hrefs(str(ahref)) childcdatanode = Tag(soup, newlink) ahref.replaceWith(childcdatanode) Thanks

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  • Replaceing <a href="mailto: with just email aadress

    - by Lauri
    I want to replace all "mailto:" links in html with plain emails. In: text .... <a href="mailto:[email protected]">not needed</a> text Out: text .... [email protected] text I did this: $str = preg_replace("/\<a.+href=\"mailto:(.*)\".+\<\/a\>/", "$1", $str); But it fails if there are multiple emails in string or html inside "a" tag In: <a href="mailto:[email protected]">not needed</a><a href="mailto:[email protected]"><font size="3">[email protected]</font></a> Out: [email protected]">

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  • Bash: Extract Range with Regular Expressioin (maybe sed?)

    - by sixtyfootersdude
    I have a file that is similar to this: <many lines of stuff> SUMMARY: <some lines of stuff> END OF SUMMARY I want to extract just the stuff between SUMMARY and END OF SUMMARY. I suspect I can do this with sed but I am not sure how. I know I can modify the stuff in between with this: sed "/SUMMARY/,/END OF SUMMARY/ s/replace/with/" fileName (But not sure how to just extract that stuff). I am Bash on Solaris.

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  • How do I locate a particular word in a text file using C#

    - by cmrhema
    Hi, I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that. Kindly do let me know. Thanks.

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  • data in mysql show after barcode split and matches character

    - by klox
    i need some code for the next step..this my first step: <script> $("#mod").change(function() { var barcode; barCode=$("#mod").val(); var data=barCode.split(" "); $("#mod").val(data[0]); $("#seri").val(data[1]); var str=data[0]; var matches=str.matches(/EE|[EJU]).*(D)/i); }); </script> after matches..i want the result can connect to data base then show data from table inside <div id="value">...how to do that?

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  • Where can I get material for learning EBNF?

    - by yesraaj
    Extended Backus–Naur Form: EBNF I'm very new to parsing concepts. Where can I get sufficiently easy to read and follow material for writing a grammar for the boost::spirit library, which uses a grammar similar to EBNF? Currently I am looking into EBNF from Wikipedia.

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  • Find ASCII "arrows" in text

    - by ulver
    I'm trying to find all the occurrences of "Arrows" in text, so in "<----=====><==->>" the arrows are: "<----", "=====>", "<==", "->", ">" This works: String[] patterns = {"<=*", "<-*", "=*>", "-*>"}; for (String p : patterns) { Matcher A = Pattern.compile(p).matcher(s); while (A.find()) { System.out.println(A.group()); } } but this doesn't: String p = "<=*|<-*|=*>|-*>"; Matcher A = Pattern.compile(p).matcher(s); while (A.find()) { System.out.println(A.group()); } No idea why. It often reports "<" instead of "<====" or similar. What is wrong?

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  • C++ type-checking at compile-time

    - by Masterofpsi
    Hi, all. I'm pretty new to C++, and I'm writing a small library (mostly for my own projects) in C++. In the process of designing a type hierarchy, I've run into the problem of defining the assignment operator. I've taken the basic approach that was eventually reached in this article, which is that for every class MyClass in a hierarchy derived from a class Base you define two assignment operators like so: class MyClass: public Base { public: MyClass& operator =(MyClass const& rhs); virtual MyClass& operator =(Base const& rhs); }; // automatically gets defined, so we make it call the virtual function below MyClass& MyClass::operator =(MyClass const& rhs); { return (*this = static_cast<Base const&>(rhs)); } MyClass& MyClass::operator =(Base const& rhs); { assert(typeid(rhs) == typeid(*this)); // assigning to different types is a logical error MyClass const& casted_rhs = dynamic_cast<MyClass const&>(rhs); try { // allocate new variables Base::operator =(rhs); } catch(...) { // delete the allocated variables throw; } // assign to member variables } The part I'm concerned with is the assertion for type equality. Since I'm writing a library, where assertions will presumably be compiled out of the final result, this has led me to go with a scheme that looks more like this: class MyClass: public Base { public: operator =(MyClass const& rhs); // etc virtual inline MyClass& operator =(Base const& rhs) { assert(typeid(rhs) == typeid(*this)); return this->set(static_cast<Base const&>(rhs)); } private: MyClass& set(Base const& rhs); // same basic thing }; But I've been wondering if I could check the types at compile-time. I looked into Boost.TypeTraits, and I came close by doing BOOST_MPL_ASSERT((boost::is_same<BOOST_TYPEOF(*this), BOOST_TYPEOF(rhs)>));, but since rhs is declared as a reference to the parent class and not the derived class, it choked. Now that I think about it, my reasoning seems silly -- I was hoping that since the function was inline, it would be able to check the actual parameters themselves, but of course the preprocessor always gets run before the compiler. But I was wondering if anyone knew of any other way I could enforce this kind of check at compile-time.

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  • regular expression of 0's and 1's

    - by Lopa
    Hello all I got this question which asks me to figure out why is it foolish to write a regular expression for the language that consists of strings of 0's and 1's that are palindromes( they read the same backwards and forwards). part 2 of the question says using any formal mechanism of your choice, show how it is possible to express the language that consists of strings of 0's and 1's that are palindromes?

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