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  • How can I replace only the last occurence of an number in a string with php?

    - by Shawn
    How would you change this: a-10-b-19-c into something like this: a-10-b-20-c using regular expressions in PHP? The only solution I've found so far is: reverse the original string - "c-91-b-01-a" find the first number - "91" reverse it - "19" turn in into a number (parseInt) - 19 add 1 to it (+1) - 20 turn it into a string again (toString) - "20" reverse it again - "02" replace the original match with this new number - "c-02-b-01-a" reverse the string - "a-10-b-20-c" I was hoping someone on SO would have a simpler way to do this... Anyone?

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  • pattern for the following condition in java

    - by zahir hussain
    hi i want to know how to write pattern.. for example : the word is "AboutGoogle AdWords Drive traffic and customers to your site. Pay through Cheque, Net Banking or Credit Card. Google Toolbar Add a search box to your browser. Google SMS To find out local information simply SMS to 54664. Gmail Free email with 7.2GB storage and less spam. Try Gmail today. Our ProductsHelp Help with Google Search, Services and ProductsGoogle Web Search Features Translation, I'm Feeling Lucky, CachedGoogle Services & Tools Toolbar, Google Web APIs, ButtonsGoogle Labs Ideas, Demos, ExperimentsFor Site OwnersAdvertising AdWords, AdSenseBusiness Solutions Google Search Appliance, Google Mini, WebSearchWebmaster Central One-stop shop for comprehensive info about how Google crawls and indexes websitesSubmit your content to Google Add your site, Google SitemapsOur CompanyPress Center News, Images, ZeitgeistJobs at Google Openings, Perks, CultureCorporate Info Company overview, Philosophy, Diversity, AddressesInvestor Relations Financial info, Corporate governanceMore GoogleContact Us FAQs, Feedback, NewsletterGoogle Logos Official Logos, Holiday Logos, Fan LogosGoogle Blog Insights to Google products and cultureGoogle Store Pens, Shirts, Lava lamps©2010 Google - Privacy Policy - Terms of Service" I have to search some word... for example "google insights" so how to write the code in java... i just write small code... check my code and answer my question... that code only use for find the search word, where is that. but i need to display some words front of search word and display some words rear of search workd... similar to google search... my code is Pattern p = Pattern.compile("(?i)(.*?)"+search+""); Matcher m = p.matcher(full); String title=""; while (m.find() == true) { title=m.group(1); System.out.println(title); } the full is orignal content, search s search word... thanks and advance

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  • regular expression search in python

    - by Richard
    Hello all, I am trying to parse some data and just started reading up on regular Expressions so I am pretty new to it. This is the code I have so far String = "MEASUREMENT 3835 303 Oxygen: 235.78 Saturation: 90.51 Temperature: 24.41 DPhase: 33.07 BPhase: 29.56 RPhase: 0.00 BAmp: 368.57 BPot: 18.00 RAmp: 0.00 RawTem.: 68.21" String = String.strip('\t\x11\x13') String = String.split("Oxygen:") print String[1] String[1].lstrip print String[1] What I am trying to do is to do is remove the oxygen data (235.78) and put it in its own variable using an regular expression search. I realize that there should be an easy solution but I am trying to figure out how regular expressions work and they are making my head hurt. Thanks for any help Richard

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  • How can I replace a plus sign in JavaScript?

    - by William Calleja
    I need to make a replace of a plus sign in a javascript string. there might be multiple occurrence of the plus sign so I did this up until now: myString= myString.replace(/+/g, "");# This is however breaking up my javascript and causing glitches. How do you escape a '+' sign in a regular expression?

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  • Help me to split string with Regular Expression

    - by Lu Lu
    Hello, I have a string: CriteriaCondition={FieldName={*EPS}*$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)} Help me to get the first word which ends with the first word "={" & get the next following word which ends with "}". The result must be: Word1 = "CriteriaCondition" Word2 = "FieldName={EPS}$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)" And with the string "FieldName=(EPS)$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)", help me to split to pairs: FieldName EPS MinValue -201 MaxValue 304 TradingPeriod -1 Thanks.

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  • Backslashes in gsub (escaping and backreferencing)

    - by polygenelubricants
    Consider the following snippet: puts 'hello'.gsub(/.+/, '\0 \\0 \\\0 \\\\0') This prints (as seen on ideone.com): hello hello \0 \0 This was very surprising, because I'd expect to see something like this instead: hello \0 \hello \\0 My argument is that \ is an escape character, so you write \\ to get a literal backslash, thus \\0 is a literal backslash \ followed by 0, etc. Obviously this is not how gsub is interpreting it, so can someone explain what's going on? And what do I have to do to get the replacement I want above?

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  • "string" != "string"

    - by Misiur
    Hi. I'm doing some kind of own templates system. I want to change <title>{site('title')}</title> Into function "site" execution with parameter "title". Here's private function replaceFunc($subject) { foreach($this->func as $t) { $args = explode(", ", preg_replace('/\{'.$t.'\(\'([a-zA-Z,]+)\'\)\}/', '$1', $subject)); $subject = preg_replace('/\{'.$t.'\([a-zA-Z,\']+\)\}/', call_user_func_array($t, $args), $subject); } return $subject; } Here's site: function site($what) { global $db; $s = $db->askSingle("SELECT * FROM ".DB_PREFIX."config"); switch($what) { case 'title': return 'Title of page'; break; case 'version': return $s->version; break; case 'themeDir': return 'lolmao'; break; default: return false; } } I've tried to compare $what (which is for this case "title") with "title". MD5 are different. strcmp gives -1, "==", and "===" return false. What is wrong? ($what type is string. You can't change call_user_func_array into call_user_func, because later I'll be using multiple arguments)

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  • RewriteCond and Full QUERY_STRING

    - by Tim
    I'm having hard time getting my head wrapped around this one - and it should be trivial. I would like to redirect one URL with a specific query string to another URL. I want to send any requests that contain the query string in the URL http://mysite.com/index.php?option=com_user&view=register To: http://mysite.com/index.php?option=com_regme&view=form&regme=4&random=0&Itemid=6 If they add anything to the end of the first URL, it should still go to the second URL so that they cannot bypass the redirection. Nothing in the first query string needs to be preserved and passed to the second - all I want to do is change the URL completely. I'm tearing my hair out trying to get this to work yet it should be trivial. Suggestions? Thanks, -Tim

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  • Regular expression to match empty HTML tags that may contain embedded JSTL?

    - by Keith Bentrup
    I'm trying to construct a regular expression to look for empty html tags that may have embedded JSTL. I'm using Perl for my matching. So far I can match any empty html tag that does not contain JSTL with the following? /<\w+\b(?!:)[^<]*?>\s*<\/\w+/si The \b(?!:) will avoid matching an opening JTSL tag but that doesn't address the whether JSTL may be within the HTML tag itself (which is allowable). I only want to know if this HTML tag has no children (only whitespace or empty). So I'm looking for a pattern that would match both the following: <div id="my-id"> </div> <div class="<c:out var="${my.property}" />"></div> Currently the first div matches. The second does not. Is it doable? I tried several variations using lookahead assertions, and I'm starting to think it's not. However, I can't say for certain or articulate why it's not. Edit: I'm not writing something to interpret the code, and I'm not interested in using a parser. I'm writing a script to point out potential issues/oversights. And at this point, I'm curious, too, to see if there is something clever with lookaheads or lookbehinds that I may be missing. If it bothers you that I'm trying to "solve" a problem this way, don't think of it as looking for a solution. To me it's more of a challenge now, and an opportunity to learn more about regular expressions. Also, if it helps, you can assume that the html is xhtml strict.

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  • Jetty RewriteHandler and RewriteRegexRule

    - by Justin
    I'm trying to rewrite a URL for a servlet. The URL gets rewritten correctly, but the context doesn't match after that. Any idea how to get this to work? RewriteHandler rewriteHandler = new RewriteHandler(); rewriteHandler.setRewriteRequestURI(true); rewriteHandler.setRewritePathInfo(true); rewriteHandler.setOriginalPathAttribute("requestedPath"); RewriteRegexRule rewriteRegexRule = new RewriteRegexRule(); rewriteRegexRule.setRegex("/r/([^/]*).*"); rewriteRegexRule.setReplacement("/r?z=$1"); rewriteHandler.addRule(rewriteRegexRule); ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection(); Context servletContext = new Context(contextHandlerCollection, "/"); servletContext.addServlet(new ServletHolder(new RedirectServlet()), "/r"); So basically /r/asdf gets rewritten to /r?z=asdf. However, the rewritten /r?z=asdf is now not processed by the servlet. Also, /r?z=asdf does work if called directly.

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  • Regexp for selecting spaces between digits and decimal char

    - by Tirithen
    I want to remove spaces from strings where the space is preceeded by a digit or a "." and acceded by a digit or ".". I have strings like: "50 .10", "50 . 10", "50. 10" and I want them all to become "50.10" but with an unknown number of digits on either side. I'm trying with lookahead/lookbehind assertions like this: $row = str_replace("/(?<=[0-9]+$)\s*[.]\s*(?=[0-9]+$)/", "", $row); But it does not work...

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  • Lighttpd rewriting files and directories

    - by Ronald
    I'm trying to do url rewriting with Lighttpd. I have what I need partially working. Right now I have this: http://domain.com/name/a/123 which rewrites to http://domain.com/name/a.php?pid=123 I do this with this rewrite-once rule: "^/name/a/([^/]+)"= "/name/a.php?pid=$1" That php page has external resources that are not getting rewritten such as the JavaScript and CSS files. Is there a way I can also have the rewrite do the following? http://domain.com/name/a/js/file.js = http://domain.com/name/js/file.js

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  • The Definition of Regular Languages

    - by AraK
    Good Day, I have tried, and burned my brain to understand the definition of Regular Languages in Discrete Mathematics and its Applications(Rosen) without reaching the goal of understanding why the definition is like that in this book. On page(789), I am rephrasing the definition: Type 3 grammars are defined as: w1 --> w2 Where w1 is a non-terminal, and w2 is of the form: w2 = aB w2 = a Where B is a non-terminal, and a is a terminal. A special case is when w1 is the starting symbol and w2 is lambda(the empty string): w1 = S S --> lambda Two questions I couldn't find an answer for. First, Why can't w2 be of the form Ba. Second, Why lambda is only allowed for the starting symbol only. The book states that, regular languages are equivalent to Finite State Automaton, and we can easily see that a we can build FSA for both cases. I took a look at other resources, and these restrictions don't exist in these resources. Thanks,

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  • Strange behavior: Dynamic expressions with RegExp Object in RegExp.match (Javascript)

    - by NeDark
    I have detect a strange behavior in regexps created with the RegExp object: With this code: var exp1 = /./; var exp2 = new RegExp('.'); ? var test1 = exp1.test('large\n\ntext..etc.'); var test2 = exp2.test('large\n\ntext..etc.'); ? var match1 = 'large\n\ntext..etc.'.match(exp1); var match2 = 'large\n\ntext..etc.'.match(exp2); ...the result is: test1 = true test2 = true ? match1 = 'l' (first match) match2 = null With the regexp maked with the regexp object from a string it finds nothing... Why does this happends? Thanks!!

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  • How do I find multiple matches with one regular expression?

    - by christian studer
    I've got the following string: response: id="1" message="whatever" attribute="none" world="hello" The order of the attributes is random. There might be any number of other attributes. Is there a way to get the id, message and world attribute in one regular expression instead of applying the following three one after another? / message="(.*?)"/ / world="(.*?)"/ / id="(.*?)"/

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  • preg_match problem

    - by Biroka
    I'm trying to get some stuff from a string in php. In RegexBuddy and Regular expression tester (firefox addon) it works good, but php gives me the following: Warning: preg_match() [function.preg-match]: Compilation failed: unmatched parentheses at offset 34 in D:\path\example.php on line 62 my pattern is "/.{4}_tmp\\([A-Za-z0-9.\\]*)\(([0-9]*)\) : (.*)/i" an example string: C:\Temp\browseide\projects\32\821C_tmp\SourceFiles\main.c(8) : error C2143: syntax error : missing ';' before 'for' what RegexBuddy gets: 821C_tmp\SourceFiles\main.c(8) : error C2143: syntax error : missing ';' before 'for' Group 1: SourceFiles\main.c Group 2: 8 Group 3: error C2143: syntax error : missing ';' before 'for'

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  • Finding an open and closing tag in Regexp

    - by Rixius
    Is there a way to find custom tags in regexp I.e. match {a}sometext{/a} As well as {c=#fff}sometext{/c} So that it finds the entire block of inner content? The problem is the sometext could have another tag as in: {a=http://www.google.com}{b}Hello, world{/b}{/a} The only solutions I can come up with would match from {a... to .../b} when I want {a... to .../a} is there a single regexp solution, or would it be best to match the start, and then use another method to find the end from the back up, and grab it out that way? I'm using PHP 5.2 so I have all the options that entails.

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  • Python: using a regular expression to match one line of HTML

    - by skylarking
    This simple Python method I put together just checks to see if Tomcat is running on one of our servers. import urllib2 import re import sys def tomcat_check(): tomcat_status = urllib2.urlopen('http://10.1.1.20:7880') results = tomcat_status.read() pattern = re.compile('<body>Tomcat is running...</body>',re.M|re.DOTALL) q = pattern.search(results) if q == []: notify_us() else: print ("Tomcat appears to be running") sys.exit() If this line is not found : <body>Tomcat is running...</body> It calls : notify_us() Which uses SMTP to send an email message to myself and another admin that Tomcat is no longer runnning on the server... I have not used the re module in Python before...so I am assuming there is a better way to do this... I am also open to a more graceful solution with Beautiful Soup ... but haven't used that either.. Just trying to keep this as simple as possible...

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  • Regexp for handling recursive arguments

    - by Matt
    Hi all, I'm a regexp novice, so I'm wondering what the regexp for the following: function {function arg1, arg2}, arg3 I'm looking to be able to just select the top-level arguments: {function arg1, arg2} & arg3 Ideally the response would be using preg_match in PHP, but almost any regexp would work fine. Thanks! Matt

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  • How to with extract url from tweet using Regular Expressions

    - by neutreno
    Ok so i'm executing the following line of code in javascript RegExp('(http:\/\/t.co\/)[a-zA-Z0-9\-\.]{8}').exec(tcont); where tcont is equal to some string like 'Test tweet to http://t.co/GXmaUyNL' (the content of a tweet obtained by jquery). However it is returning, in the case above for example, 'http://t.co/GXmaUyNL,http://t.co/'. This is frustracting because I want the url without the bit on the end - after and including the comma. Any ideas why this is appearing? Thanks

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  • Python regex on list

    - by Peter Nielsen
    Hi there I am trying to build a parser and save the results as an xml file but i have problems.. For instance i get a TypeError: expected string or buffer when i try to run the code.. Would you experts please have a look at my code ? import urllib2, re from xml.dom.minidom import Document from BeautifulSoup import BeautifulSoup as bs osc = open('OSCTEST.html','r') oscread = osc.read() soup=bs(oscread) doc = Document() root = doc.createElement('root') doc.appendChild(root) countries = doc.createElement('countries') root.appendChild(countries) findtags1 = re.compile ('<h1 class="title metadata_title content_perceived_text(.*?)</h1>', re.DOTALL | re.IGNORECASE).findall(soup) findtags2 = re.compile ('<span class="content_text">(.*?)</span>', re.DOTALL | re.IGNORECASE).findall(soup) for header in findtags1: title_elem = doc.createElement('title') countries.appendChild(title_elem) header_elem = doc.createTextNode(header) title_elem.appendChild(header_elem) for item in findtags2: art_elem = doc.createElement('artikel') countries.appendChild(art_elem) s = item.replace('<P>','') t = s.replace('</P>','') text_elem = doc.createTextNode(t) art_elem.appendChild(text_elem) print doc.toprettyxml()

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