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  • Javascript substrings multiline replace by RegExp

    - by Radek Šimko
    Hi, I'm having some troubles with matching a regular expression in multi-line string. <script> var str="Welcome to Google!\n"; str = str + "We are proud to announce that Microsoft has \n"; str = str + "one of the worst Web Developers sites in the world."; document.write(str.replace(/.*(microsoft).*/gmi, "$1")); </script> http://jsbin.com/osoli3/3/edit As you may see on the link above, the output of the code looks like this: Welcome to Google! Microsoft one of the worst Web Developers sites in the world. Which means, that the replace() method goes line by line and if there's no match in that line, it returns just the whole line... Even if it has the "m" (multiline) modifier...

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  • Lighttpd rewriting files and directories

    - by Ronald
    I'm trying to do url rewriting with Lighttpd. I have what I need partially working. Right now I have this: http://domain.com/name/a/123 which rewrites to http://domain.com/name/a.php?pid=123 I do this with this rewrite-once rule: "^/name/a/([^/]+)"= "/name/a.php?pid=$1" That php page has external resources that are not getting rewritten such as the JavaScript and CSS files. Is there a way I can also have the rewrite do the following? http://domain.com/name/a/js/file.js = http://domain.com/name/js/file.js

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  • regular expression search in python

    - by Richard
    Hello all, I am trying to parse some data and just started reading up on regular Expressions so I am pretty new to it. This is the code I have so far String = "MEASUREMENT 3835 303 Oxygen: 235.78 Saturation: 90.51 Temperature: 24.41 DPhase: 33.07 BPhase: 29.56 RPhase: 0.00 BAmp: 368.57 BPot: 18.00 RAmp: 0.00 RawTem.: 68.21" String = String.strip('\t\x11\x13') String = String.split("Oxygen:") print String[1] String[1].lstrip print String[1] What I am trying to do is to do is remove the oxygen data (235.78) and put it in its own variable using an regular expression search. I realize that there should be an easy solution but I am trying to figure out how regular expressions work and they are making my head hurt. Thanks for any help Richard

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  • Regexp for selecting spaces between digits and decimal char

    - by Tirithen
    I want to remove spaces from strings where the space is preceeded by a digit or a "." and acceded by a digit or ".". I have strings like: "50 .10", "50 . 10", "50. 10" and I want them all to become "50.10" but with an unknown number of digits on either side. I'm trying with lookahead/lookbehind assertions like this: $row = str_replace("/(?<=[0-9]+$)\s*[.]\s*(?=[0-9]+$)/", "", $row); But it does not work...

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  • Replace a div content with PHP

    - by Zakaria
    hi everybody, yesterday, I posted a question about "Hom to change a DIV id with a php function" and someone found the right answer with a regular expression. The problem is that I wanted to use this answer to aplly the method on other same problems. But, as I'm very bad at regular expressions, I couldn't. So the problem is that I upload some videos with FCKEditor and put the video script in my database and the result is like that: <div id="player959093-parent" style="text-align: center;float: left;"> <div style="border-style: none; height: 160px; width: 270px; overflow: hidden; background-color: rgb(220, 220, 220); background-image: url(http://localhost/fckeditor/editor/plugins/flvPlayer/flvPlayer.gif); background-repeat:no-repeat; background-position:center;"><script src="http://localhost/fckeditor/editor/plugins/flvPlayer/swfobject.js" type="text/javascript"></script> <div id="player959093"><a href="http://www.macromedia.com/go/getflashplayer">Get the Flash Player</a> to see this player. <div id="player959093-config" style="display: none;visibility: hidden;width: 0px;height:0px;overflow: hidden;">url=/editeur/images/flash/FOO.flv width=270 height=160 loop=false play=false downloadable=false fullscreen=true displayNavigation=true displayDigits=true align=left dispPlaylist=none playlistThumbs=false</div> </div> <script type="text/javascript"> var s1 = new SWFObject("http://localhost/editeur/javascript/fckeditor/editor/plugins/flvPlayer/mediaplayer.swf","single","270","160","7"); s1.addVariable("width","270"); s1.addVariable("height","160"); s1.addVariable("autostart","false"); s1.addVariable("file","/editeur/images/flash/FOO.flv"); s1.addVariable("repeat","false"); s1.addVariable("image",""); s1.addVariable("showdownload","false"); s1.addVariable("link","/editeur/images/flash/FOO.flv"); s1.addParam("allowfullscreen","true"); s1.addVariable("showdigits","true"); s1.addVariable("shownavigation","true"); s1.addVariable("logo",""); s1.write("player959093"); </script></div> </div> When I echo this content once in my PHP page, It works great. More than once, the videos doesn't appear. Which is obvious because of the unique ID. As you can see, the content has these ids: div id="player959093-parent" div id="player959093" div id="player959093-config s1.write("player959093"); So my question is: Is there a function that can replace the string "player959093" or concatenate it with some other string to resolve the display problem? Thank you very much, Regards.

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  • Backslashes in gsub (escaping and backreferencing)

    - by polygenelubricants
    Consider the following snippet: puts 'hello'.gsub(/.+/, '\0 \\0 \\\0 \\\\0') This prints (as seen on ideone.com): hello hello \0 \0 This was very surprising, because I'd expect to see something like this instead: hello \0 \hello \\0 My argument is that \ is an escape character, so you write \\ to get a literal backslash, thus \\0 is a literal backslash \ followed by 0, etc. Obviously this is not how gsub is interpreting it, so can someone explain what's going on? And what do I have to do to get the replacement I want above?

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  • Validating javascript decimal numbers

    - by Click Upvote
    I'm using the following regexp to validate numbers in my javascript file: var valid = (val.match(/^\d+$/)); It works fine for whole numbers like 100, 200, etc, however for things like 1.44, 4.11, etc, it returns false. How can I change it so numbers with a decimal are also accepted?

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  • Asterisk in eregi

    - by Mihai
    //URL START $urlregex = "^(https?|ftp)\:\/\/"; // USER AND PASS $urlregex .= "([a-z0-9+!*(),;?&=\$_.-]+(\:[a-z0-9+!*(),;?&=\$.-]+)?@)?"; // HOSTNAME OR IP $urlregex .= "[a-z0-9+\$-]+(.[a-z0-9+\$_-]+)*"; // PORT $urlregex .= "(\:[0-9]{2,5})?"; // PATH $urlregex .= "(\/([a-z0-9+\$_-].?)+)*\/?"; // GET Query $urlregex .= "(\?[a-z+&\$.-][a-z0-9;:@/&%=+\$.-]*)?"; // ANCHOR $urlregex .= "(#[a-z_.-][a-z0-9+\$_.-]*)?\$"; // check if (eregi($urlregex, $url)) {echo "good";} else {echo "bad";} but what if I have http://www.example.com/about-me/my-4*-hotel/ That eregi check isn't valid because of the asterisk. What should I do?

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  • Python: using a regular expression to match one line of HTML

    - by skylarking
    This simple Python method I put together just checks to see if Tomcat is running on one of our servers. import urllib2 import re import sys def tomcat_check(): tomcat_status = urllib2.urlopen('http://10.1.1.20:7880') results = tomcat_status.read() pattern = re.compile('<body>Tomcat is running...</body>',re.M|re.DOTALL) q = pattern.search(results) if q == []: notify_us() else: print ("Tomcat appears to be running") sys.exit() If this line is not found : <body>Tomcat is running...</body> It calls : notify_us() Which uses SMTP to send an email message to myself and another admin that Tomcat is no longer runnning on the server... I have not used the re module in Python before...so I am assuming there is a better way to do this... I am also open to a more graceful solution with Beautiful Soup ... but haven't used that either.. Just trying to keep this as simple as possible...

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  • Rails validates_format_of

    - by squids
    Hi, I want to use validates_format_of to validate a comma separated string with only letters (small and caps), and numbers. So. example1, example2, 22example44, ex24 not: ^&*, < , asfasfsdafas<#%$# Basically I want to have users enter comma separated words(incl numbers) without special characters. I'll use it to validate tags from acts_as_taggable_on. (i don't want to be a valid tag for example. Thanks in advance.

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  • pattern for the following condition in java

    - by zahir hussain
    hi i want to know how to write pattern.. for example : the word is "AboutGoogle AdWords Drive traffic and customers to your site. Pay through Cheque, Net Banking or Credit Card. Google Toolbar Add a search box to your browser. Google SMS To find out local information simply SMS to 54664. Gmail Free email with 7.2GB storage and less spam. Try Gmail today. Our ProductsHelp Help with Google Search, Services and ProductsGoogle Web Search Features Translation, I'm Feeling Lucky, CachedGoogle Services & Tools Toolbar, Google Web APIs, ButtonsGoogle Labs Ideas, Demos, ExperimentsFor Site OwnersAdvertising AdWords, AdSenseBusiness Solutions Google Search Appliance, Google Mini, WebSearchWebmaster Central One-stop shop for comprehensive info about how Google crawls and indexes websitesSubmit your content to Google Add your site, Google SitemapsOur CompanyPress Center News, Images, ZeitgeistJobs at Google Openings, Perks, CultureCorporate Info Company overview, Philosophy, Diversity, AddressesInvestor Relations Financial info, Corporate governanceMore GoogleContact Us FAQs, Feedback, NewsletterGoogle Logos Official Logos, Holiday Logos, Fan LogosGoogle Blog Insights to Google products and cultureGoogle Store Pens, Shirts, Lava lamps©2010 Google - Privacy Policy - Terms of Service" I have to search some word... for example "google insights" so how to write the code in java... i just write small code... check my code and answer my question... that code only use for find the search word, where is that. but i need to display some words front of search word and display some words rear of search workd... similar to google search... my code is Pattern p = Pattern.compile("(?i)(.*?)"+search+""); Matcher m = p.matcher(full); String title=""; while (m.find() == true) { title=m.group(1); System.out.println(title); } the full is orignal content, search s search word... thanks and advance

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  • How can I remove HTML span tags with a Perl one liner?

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with Perl. I would prefer to allow for any occurences of whitespace or newlines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> EDIT: It's just the <span>'s and </span>'s that are inbetween <p> and <a> from the "blockDontForget" class </div> that I want to remove (there are lots or these blockDontForget divs with spans inside anchors that I want to keep).

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  • regexp exclusion

    - by Vlad
    Hello everyone! I have regexp to change smileys to images. Here it is (?:(?![0]:\)|:\)\)|:-\)\)))(:\)|:-\)) The point is not to change 0:) and :)) and :-)) while changing :) and :-) It works pretty well with :)) and :-)) but somehow still grabs :) in 0:) Where's my mistake?

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  • Regular Expression to break row with comma separated values into distinct rows

    - by Nick
    I have a file with many rows. Each row has a column which may contain comma separated values. I need each row to be distinct (ie no comma separated values). Here is an example row: AB AB10,AB11,AB12,AB15,AB16,AB21,AB22,AB23,AB24,AB25,AB99 ABERDEEN Aberdeenshire The columns are comma separated (Postcode area, Postcode districts, Post town, Former postal county). So the above row would get turned into: AB AB10 ABERDEEN Aberdeenshire AB AB11 ABERDEEN Aberdeenshire AB AB12 ABERDEEN Aberdeenshire ... ... I tried the following but it didn't work... (.+)\t(([0-9A-Z]+),)+\t(.+)\t(.+)

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  • match at the beginning of any line, including the first

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)?

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  • multi-line pattern matching in pyhon

    - by Horace Ho
    A periodic computer generated message (simplified): Hello user123, - (604)7080900 - 152 - minutes Regards Using python, how can I extract "(604)7080900", "152", "minutes" (i.e. any text following a leading "- " pattern) between the two empty lines (empty line is the \n\n after "Hello user123" and the \n\n before "Regards"). Even better if the result string list are stored in an array. Thanks!

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  • Sanitize Content: removing markup from Amazon's content

    - by StackOverflowNewbie
    I'm using Amazon Web Service to get product descriptions of various items. The problem is that Amazon's content contains mark up that is sometimes destructive to the layout of my web page (e.g. unclosed DIVs, etc.). I want to sanitize the content I get from Amazon. My solution would be to do the following (my initial list so far): Remove unnecessary tags such as div, span, etc. while keeping tags like p, ul, ol, etc. Remove all attributes from all the tags (e.g. seems like there are style attributes in some of the tags) Remove excess white space (e.g. multiple spaces, carriage returns, new lines, tabs, etc.) Etc. Before I go off trying to build my solution, I'm wondering if anyone has a better idea (or an already existing solution). Thanks.

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  • Jetty RewriteHandler and RewriteRegexRule

    - by Justin
    I'm trying to rewrite a URL for a servlet. The URL gets rewritten correctly, but the context doesn't match after that. Any idea how to get this to work? RewriteHandler rewriteHandler = new RewriteHandler(); rewriteHandler.setRewriteRequestURI(true); rewriteHandler.setRewritePathInfo(true); rewriteHandler.setOriginalPathAttribute("requestedPath"); RewriteRegexRule rewriteRegexRule = new RewriteRegexRule(); rewriteRegexRule.setRegex("/r/([^/]*).*"); rewriteRegexRule.setReplacement("/r?z=$1"); rewriteHandler.addRule(rewriteRegexRule); ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection(); Context servletContext = new Context(contextHandlerCollection, "/"); servletContext.addServlet(new ServletHolder(new RedirectServlet()), "/r"); So basically /r/asdf gets rewritten to /r?z=asdf. However, the rewritten /r?z=asdf is now not processed by the servlet. Also, /r?z=asdf does work if called directly.

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  • PostgreSQL String search for partial patterns removing exrtaneous characters

    - by tbrandao
    Looking for a simple SQL (PostgreSQL) regular expression or similar solution (maybe soundex) that will allow a flexible search. So that dashes, spaces and such are omitted during the search. As part of the search and only the raw characters are searched in the table.: Currently using: SELECT * FROM Productions WHERE part_no ~* '%search_term%' If user types UTR-1 it fails to bring up UTR1 or UTR 1 stored in the database. But the matches do not happen when a part_no has a dash and the user omits this character (or vice versa) EXAMPLE search for part UTR-1 should find all matches below. UTR1 UTR --1 UTR 1 any suggestions...

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  • Strange behavior: Dynamic expressions with RegExp Object in RegExp.match (Javascript)

    - by NeDark
    I have detect a strange behavior in regexps created with the RegExp object: With this code: var exp1 = /./; var exp2 = new RegExp('.'); ? var test1 = exp1.test('large\n\ntext..etc.'); var test2 = exp2.test('large\n\ntext..etc.'); ? var match1 = 'large\n\ntext..etc.'.match(exp1); var match2 = 'large\n\ntext..etc.'.match(exp2); ...the result is: test1 = true test2 = true ? match1 = 'l' (first match) match2 = null With the regexp maked with the regexp object from a string it finds nothing... Why does this happends? Thanks!!

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  • How do I find multiple matches with one regular expression?

    - by christian studer
    I've got the following string: response: id="1" message="whatever" attribute="none" world="hello" The order of the attributes is random. There might be any number of other attributes. Is there a way to get the id, message and world attribute in one regular expression instead of applying the following three one after another? / message="(.*?)"/ / world="(.*?)"/ / id="(.*?)"/

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