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  • model not showing up in django admin.

    - by Zayatzz
    Hi. I have ceated several django apps and stuffs for my own fund and so far everything has been working fine. Now i just created new project (django 1.2.1) and have run into trouble from 1st moments. I created new app - game and new model Game. i created admin.py and put related stuff into it. Ran syncdb and went to check into admin. Model did not show up there. I proceeded to check and doublecheck and read through previous similar threads: http://stackoverflow.com/questions/1839927/registered-models-do-not-show-up-in-admin http://stackoverflow.com/questions/1694259/django-app-not-showing-up-in-admin-interface But as far as i can tell, they dont help me either. Perhaps someone else can point this out for me. models.py in game app: # -*- coding: utf-8 -*- from django.db import models class Game(models.Model): type = models.IntegerField(blank=False, null=False, default=1) teamone = models.CharField(max_length=100, blank=False, null=False) teamtwo = models.CharField(max_length=100, blank=False, null=False) gametime = models.DateTimeField(blank=False, null=False) admin.py in game app: # -*- coding: utf-8 -*- from jalka.game.models import Game from django.contrib import admin class GameAdmin(admin.ModelAdmin): list_display = ['type', 'teamone', 'teamtwo', 'gametime'] admin.site.register(Game, GameAdmin) project settings.py: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', ) ROOT_URLCONF = 'jalka.urls' TEMPLATE_DIRS = ( "/home/projects/jalka/templates/" ) INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.admin', 'game', ) urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^jalka/', include('jalka.foo.urls')), (r'^admin/', include(admin.site.urls)), ) Alan.

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  • Limit foreign key choices in select in an inline form in admin

    - by mightyhal
    Edited :-) Hopefully a bit clearer now. The logic is of the model is: A Building has many Rooms A Room may be inside another Room (a closet, for instance--ForeignKey on 'self') A Room can only in inside of another Room in the same building (this is the tricky part) Here's the code I have: #spaces/models.py from django.db import models class Building(models.Model): name=models.CharField(max_length=32) def __unicode__(self): return self.name class Room(models.Model): number=models.CharField(max_length=8) building=models.ForeignKey(Building) inside_room=models.ForeignKey('self',blank=True,null=True) def __unicode__(self): return self.number and: #spaces/admin.py from ex.spaces.models import Building, Room from django.contrib import admin class RoomAdmin(admin.ModelAdmin): pass class RoomInline(admin.TabularInline): model = Room extra = 2 class BuildingAdmin(admin.ModelAdmin): inlines=[RoomInline] admin.site.register(Building, BuildingAdmin) admin.site.register(Room) The inline will display only rooms in the current building (which is what I want). The problem, though, is that for the inside_room drop down, it displays all of the rooms in the Rooms table (including those in other buildings). In the inline of rooms, I need to limit the inside_room choices to only rooms which are in the current building being displayed by the main form. I can't figure out a way to do it with either a limit_choices_to in the model, nor can I figure out how exactly to override the admin's inline formset properly (I feel like I should be somehow create a custom inline form, pass the building_id of the main form to the custom inline, then limit the queryset for the field's choices based on that--but I just can't wrap my head around how to do it). Maybe this is too complex for the admin site, but it seems like something that would be generally useful... Thanks again for your help!

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  • UIActivityIndicator on UITableViewCell not displaying while calling a webService

    - by Yoyi Cheika
    Hi coders, I guess my problem is very simple to solve but I haven been able to do so. Here is my problem: I have a custom table view cell that contains a UIActivityIndicator. When a cell is selected I push another view but this second view makes a call to a web service to bring data. Here is my code // Override to support row selection in the table view. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic may go here -- for example, create and push another view controller. // AnotherViewController *anotherViewController = [[AnotherViewController alloc] initWithNibName:@"AnotherView" bundle:nil]; // [self.navigationController pushViewController:anotherViewController animated:YES]; // [anotherViewController release]; Models *models = [[Models alloc] initWithNibName:@"Models" bundle:nil]; models.make = ((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).make.text; models.year = (int)[self.yearLabel.text doubleValue]; models.logo = [makeLogosName objectAtIndex:indexPath.row]; [((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).activityIndicator startAnimating]; [self.navigationController pushViewController:models animated:YES]; [((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).activityIndicator stopAnimating]; [models release]; } Where MakeCell is my custom cell. If I comment this line [((MakeCell *)[tableView cellForRowAtIndexPath:indexPath]).activityIndicator stopAnimating]; then the indicator appears as expected when going back to the previous view. I feel like the indicator is not being visually updated until the didSelectRowAtIndexPath returns. Does is works ascyncronically. What can be my problem here. Thank you very much Cheika

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  • Moses v1.0 multi language ini file

    - by Milan Kocic
    I was working with mosesserver 0.91 and everything works fine but now there is version 1.0 and nothing is same as before. Here is my situation: I want to have multi language translation from arabic to english and from english to arabic. All data and configuration file I have works with 0.91 version of mosesserver. Here is my config file: ------------------------------------------------- ######################### ### MOSES CONFIG FILE ### ######################### # D - decoding path, R - reordering model, L - language model [translation-systems] ar-en D 0 R 0 L 0 en-ar D 1 R 1 L 1 # input factors [input-factors] 0 # mapping steps [mapping] 0 T 0 1 T 1 # translation tables: table type (hierarchical(0), textual (0), binary (1)), source-factors, target-factors, number of scores, file # OLD FORMAT is still handled for back-compatibility # OLD FORMAT translation tables: source-factors, target-factors, number of scores, file # OLD FORMAT a binary table type (1) is assumed [ttable-file] 1 0 0 5 /mnt/models/ar-en/phrase-table/phrase-table 1 0 0 5 /mnt/models/en-ar/phrase-table/phrase-table # no generation models, no generation-file section # language models: type(srilm/irstlm), factors, order, file [lmodel-file] 1 0 5 /mnt/models/ar-en/language-model/en.qblm.mm 1 0 5 /mnt/models/en-ar/language-model/ar.lm.d1.blm.mm # limit on how many phrase translations e for each phrase f are loaded # 0 = all elements loaded [ttable-limit] 20 # distortion (reordering) files [distortion-file] 0-0 wbe-msd-bidirectional-fe-allff 6 /mnt/models/ar-en/reordering-table/reordering-table.wbe-msd-bidirectional-fe.gz 0-0 wbe-msd-bidirectional-fe-allff 6 /mnt/models/en-ar/reordering-model/reordering-table.wbe-msd-bidirectional-fe.gz # distortion (reordering) weight [weight-d] 0.3 0.3 # lexicalised distortion weights [weight-lr] 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 # language model weights [weight-l] 0.5000 0.5000 # translation model weights [weight-t] 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 0.2 # no generation models, no weight-generation section # word penalty [weight-w] -1 -1 [distortion-limit] 12 --------------------------------------------------------- So please can someone help me and rewrite this config file so it can work in version 1.0. And i need some python sample code of translation. I am using xmlrpc in python and earler I sent http request with: import xmlrpclib client = xmlrpclib.ServerProxy('http://localhost:8080') client.translate({'text': 'some text', 'system': 'en-ar'}) but now seems there is no more 'system' parameter and moses use always default settings.

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  • Using Zend Framework and Doctrine with independend modular structures

    - by stefax
    I've seen a lot of articles about integrating ZF and Doctrine. There is also a proposal for ZF here but they have always two possible structures. Either they put all models into one top level model directory or they put it into a module related model directory. application |-- Bootstrap.php |-- configs |-- controllers |-- models - EITHER HERE |-- modules | -- examplemodule | |-- controllers | |-- models - OR HERE | |-- views |-- views For our projects I see problems for either of the two options: 1. One directory: application/models - in a complex system after a short time there will be hundreds of files, over all when you have the table classes two (e.g. User.php and UserTable.php). 2. Module based model directories: application/modules/examplemodule/models - in many cases we use models in multiple modules at the same time. So the "User" is required e.g. in the modules "game", "administration", ... Is there a way to use some kind of sub directories under the top level directory "models" to get some grouping. It should be completely independent of the module structure. application |-- Bootstrap.php ... |-- models | -- user | |-- User.php | |-- Friend.php | |-- other user related models | -- game | |-- Game.php | |-- Score.php | |-- ... ... Any solution should support autoloading and the class generation from yaml files. Any ideas, links or solutions? Thanks!

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  • how to handle multiple profiles per user?

    - by Scott Willman
    I'm doing something that doesn't feel very efficient. From my code below, you can probably see that I'm trying to allow for multiple profiles of different types attached to my custom user object (Person). One of those profiles will be considered a default and should have an accessor from the Person class. Can this be done better? from django.db import models from django.contrib.auth.models import User, UserManager class Person(User): public_name = models.CharField(max_length=24, default="Mr. T") objects = UserManager() def save(self): self.set_password(self.password) super(Person, self).save() def _getDefaultProfile(self): def_teacher = self.teacher_set.filter(default=True) if def_teacher: return def_teacher[0] def_student = self.student_set.filter(default=True) if def_student: return def_student[0] def_parent = self.parent_set.filter(default=True) if def_parent: return def_parent[0] return False profile = property(_getDefaultProfile) def _getProfiles(self): # Inefficient use of QuerySet here. Tolerated because the QuerySets should be very small. profiles = [] if self.teacher_set.count(): profiles.append(list(self.teacher_set.all())) if self.student_set.count(): profiles.append(list(self.student_set.all())) if self.parent_set.count(): profiles.append(list(self.parent_set.all())) return profiles profiles = property(_getProfiles) class BaseProfile(models.Model): person = models.ForeignKey(Person) is_default = models.BooleanField(default=False) class Meta: abstract = True class Teacher(BaseProfile): user_type = models.CharField(max_length=7, default="teacher") class Student(BaseProfile): user_type = models.CharField(max_length=7, default="student") class Parent(BaseProfile): user_type = models.CharField(max_length=7, default="parent")

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  • Django: Save data from form in DB

    - by Anry
    I have a model: class Cost(models.Model): project = models.ForeignKey(Project) cost = models.FloatField() date = models.DateField() For the model I created a class form: class CostForm(ModelForm): class Meta: model = Cost fields = ['date', 'cost'] view.py: def cost(request, offset): if request.method == 'POST': #HOW save data in DB? return HttpResponseRedirect('/') else: form = CostForm() In the template file determined: <form action="/cost/{{ project }}/" method="post" accept-charset="utf-8"> <label for="date">Date:</label><input type="text" name="date" value={{ current_date }} id="date" /> <label for="cost">Cost:</label><input type="text" name="cost" value="0" id="cost" /> <p><input type="submit" value="Add"></p> </form> How save data from form in DB? P.S. offset = project name Model: class Project(models.Model): title = models.CharField(max_length=150) url = models.URLField() manager = models.ForeignKey(User) timestamp = models.DateTimeField() I tried to write: def cost(request, offset): if request.method == 'POST': form = CostForm(request.POST) if form.is_valid(): instance = form.save(commit=False) instance.project = Project.objects.filter(title=offset) instance.date = request.date instance.cost = request.cost instance.save() return HttpResponseRedirect('/') else: form = CostForm() But it does not work :(

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  • Django ManyToMany Membership errors making associations

    - by jmitchel3
    I'm trying to have a "member admin" in which they have hundreds of members in the group. These members can be in several groups. Admins can remove access for the member ideally in the view. I'm having trouble just creating the group. I used a ManytoManyField to get started. Ideally, the "member admin" would be able to either select existing Users OR it would be able to Add/Invite new ones via email address. Here's what I have: #views.py def membership(request): group = Group.objects.all().filter(user=request.user) GroupFormSet = modelformset_factory(Group, form=MembershipForm) if request.method == 'POST': formset = GroupFormSet(request.POST, request.FILES, queryset=group) if formset.is_valid(): formset.save(commit=False) for form in formset: form.instance.user = request.user formset.save() return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) else: formset= GroupFormSet(queryset=group) return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) #models.py class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(User, related_name='community_members', through='Membership') user = models.ForeignKey(User, related_name='community_creator', null=True) def __unicode__(self): return self.name class Membership(models.Model): member = models.ForeignKey(User, related_name='user_membership', blank=True, null=True) group = models.ForeignKey(Group, related_name='community_membership', blank=True, null=True) date_joined = models.DateField(auto_now=True, blank=True, null=True) class Meta: unique_together = ('member', 'group') Any ideas? Thank you for your help.

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  • Rebuilding old (2010) django project in 2012

    - by birgit
    I am trying to make an old Django project run again. After seemingly having solved issues with old sorl.thumbnail versions and deprecated expressions I now get this error when running python manage.py runserver I also tried to copy & paste my old files into a new Django project and get the exactly same error. Maybe someone here has a clue where the problem lies? Unhandled exception in thread started by <bound method Command.inner_run of <django.contrib.staticfiles.management.commands.runserver.Command object at 0x2a80510>> Traceback (most recent call last): File "/usr/lib/python2.7/dist-packages/django/core/management/commands/runserver.py", line 88, in inner_run self.validate(display_num_errors=True) File "/usr/lib/python2.7/dist-packages/django/core/management/base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "/usr/lib/python2.7/dist-packages/django/core/management/validation.py", line 35, in get_validation_errors for (app_name, error) in get_app_errors().items(): File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 146, in get_app_errors self._populate() File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 61, in _populate self.load_app(app_name, True) File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 78, in load_app models = import_module('.models', app_name) File "/usr/lib/python2.7/dist-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 73, in <module> class Image(models.Model): File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 83, in Image 'large': {'size': (640, 640)}, File "/usr/lib/python2.7/dist-packages/django/db/models/fields/files.py", line 233, in __init__ super(FileField, self).__init__(verbose_name, name, **kwargs) TypeError: __init__() got an unexpected keyword argument 'extra_thumbnails' I need to re-build the project just for visual documentation locally... so also any hints on how to quickly re-run outdated django-projects are very welcome!! Thanks a lot (using Ubuntu 12.04)

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  • Skip subdirectory in python import

    - by jstaab
    Ok, so I'm trying to change this: app/ - lib.py - models.py - blah.py Into this: app/ - __init__.py - lib.py - models/ - __init__.py - user.py - account.py - banana.py - blah.py And still be able to import my models using from app.models import User rather than having to change it to from app.models.user import User all over the place. Basically, I want everything to treat the package as a single module, but be able to navigate the code in separate files for development ease. The reason I can't do something like add for file in __all__: from file import * into init.py is I have circular references between the model files. A fix I don't want is to import those models from within the functions that use them. But that's super ugly. Let me give you an example: user.py ... from app.models import Banana ... banana.py ... from app.models import User ... I wrote a quick pre-processing script that grabs all the files, re-writes them to put imports at the top, and puts it into models.py, but that's hardly an improvement, since now my stack traces don't show the line number I actually need to change. Any ideas? I always though init was probably magical but now that I dig into it, I can't find anything that lets me provide myself this really simple convenience.

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  • O&rsquo;Reilly E-Book of the Day 15/Aug/2014 - Advanced Quantitative Finance with C++

    - by TATWORTH
    Originally posted on: http://geekswithblogs.net/TATWORTH/archive/2014/08/15/orsquoreilly-e-book-of-the-day-15aug2014---advanced-quantitative-finance.aspxToday’s half-price book of the Day offer from O’Reilly at http://shop.oreilly.com/product/9781782167228.do?code=MSDEAL is Advanced Quantitative Finance with C++. “This book will introduce you to the key mathematical models used to price financial derivatives, as well as the implementation of main numerical models used to solve them. In particular, equity, currency, interest rates, and credit derivatives are discussed. In the first part of the book, the main mathematical models used in the world of financial derivatives are discussed. Next, the numerical methods used to solve the mathematical models are presented. Finally, both the mathematical models and the numerical methods are used to solve some concrete problems in equity, forex, interest rate, and credit derivatives.”

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  • Why does the proxy generated code create the wrong class namespace when a MessageContract is in my W

    - by DaleyKD
    I have created two WCF Services (Shipping & PDFGenerator). They both, along with my ClientApp, share an assembly named Kyle.Common.Contracts. Within this assembly, I have three classes: namespace Kyle.Common.Contracts { [MessageContract] public class PDFResponse { [MessageHeader] public string fileName { get; set; } [MessageBodyMember] public System.IO.Stream fileStream { get; set; } } [MessageContract] public class PDFRequest { [MessageHeader] public Enums.PDFDocumentNameEnum docType { get; set; } [MessageHeader] public int? pk { get; set; } [MessageHeader] public string[] emailAddress { get; set; } [MessageBodyMember] public Kyle.Common.Contracts.TrackItResult[] trackItResults { get; set; } } [DataContract(Name = "TrackResult", Namespace = "http://kyle")] public class TrackResult { [DataMember] public int SeqNum { get; set; } [DataMember] public int ShipmentID { get; set; } [DataMember] public string StoreNum { get; set; } } } My PDFGenerator ServiceContract looks like: namespace Kyle.WCF.PDFDocs { [ServiceContract(Namespace="http://kyle")] public interface IPDFDocsService { [OperationContract] PDFResponse GeneratePDF(PDFRequest request); [OperationContract] void GeneratePDFAsync(Kyle.Common.Contracts.Enums.PDFDocumentNameEnum docType, int? pk, string[] emailAddress); [OperationContract] Kyle.Common.Contracts.TrackResult[] Test(); } } If I comment out the GeneratePDF stub, the proxy generated by VS2010 realizes that Test returns an array of Kyle.Common.Contracts.TrackResult. However, if I leave GeneratePDF there, the proxy refuses to use Kyle.Common.Contracts.TrackResult, and instead creates a new class, ClientApp.PDFDocServices.TrackResult, and uses that as the return type of Test. Is there a way to force the proxy generator to use Kyle.Common.Contracts.TrackResult whenever I use a MessageContract? Perhaps there's a better method for using a Stream and File Name as return types? I just don't want to have to create a Copy method to copy from ClientApp.PDFDocServices.TrackResult to Kyle.Common.Contracts.TrackResult, since they should be the exact same class. Thanks in advance, Kyle

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  • Why does the proxy generated code create a new class when a MessageContract is in my WCF Service?

    - by DaleyKD
    I have created two WCF Services (Shipping & PDFGenerator). They both, along with my ClientApp, share an assembly named Kyle.Common.Contracts. Within this assembly, I have three classes: namespace Kyle.Common.Contracts { [MessageContract] public class PDFResponse { [MessageHeader] public string fileName { get; set; } [MessageBodyMember] public System.IO.Stream fileStream { get; set; } } [MessageContract] public class PDFRequest { [MessageHeader] public Enums.PDFDocumentNameEnum docType { get; set; } [MessageHeader] public int? pk { get; set; } [MessageHeader] public string[] emailAddress { get; set; } [MessageBodyMember] public Kyle.Common.Contracts.TrackItResult[] trackItResults { get; set; } } [DataContract(Name = "TrackResult", Namespace = "http://kyle")] public class TrackResult { [DataMember] public int SeqNum { get; set; } [DataMember] public int ShipmentID { get; set; } [DataMember] public string StoreNum { get; set; } } } My PDFGenerator ServiceContract looks like: namespace Kyle.WCF.PDFDocs { [ServiceContract(Namespace="http://kyle")] public interface IPDFDocsService { [OperationContract] PDFResponse GeneratePDF(PDFRequest request); [OperationContract] void GeneratePDFAsync(Kyle.Common.Contracts.Enums.PDFDocumentNameEnum docType, int? pk, string[] emailAddress); [OperationContract] Kyle.Common.Contracts.TrackResult[] Test(); } } If I comment out the GeneratePDF stub, the proxy generated by VS2010 realizes that Test returns an array of Kyle.Common.Contracts.TrackResult. However, if I leave GeneratePDF there, the proxy refuses to use Kyle.Common.Contracts.TrackResult, and instead creates a new class, ClientApp.PDFDocServices.TrackResult, and uses that as the return type of Test. Is there a way to force the proxy generator to use Kyle.Common.Contracts.TrackResult whenever I use a MessageContract? Perhaps there's a better method for using a Stream and File Name as return types? I just don't want to have to create a Copy method to copy from ClientApp.PDFDocServices.TrackResult to Kyle.Common.Contracts.TrackResult, since they should be the exact same class. Thanks in advance, Kyle

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  • Can access maven repository from behind proxy, need help.

    - by Digambar Daund
    I am trying to access maven repository from behind proxy. I configured settings.xml correctly (i guess so...) true http username password 12.34.56.78 8080 But still I am error message like... if i dont configure userid/password gets correct error message which is HTTP response code 407 - saying authentication required. But If I configure correct/incorrect proxy authentication it always prints below error message.... Downloading: http://repo1.maven.org/maven2/org/apache/maven/plugins/maven-clean-plugin/2.2/maven-clean-plugin-2.2.pom [WARNING] Unable to get resource 'org.apache.maven.plugins:maven-clean-plugin:pom:2.2' from repository central (http://repo1.maven.org/maven2): Error trans ferring file: Server redirected too many times (20) Downloading: http://repo1.maven.org/maven2/org/apache/maven/plugins/maven-clean-plugin/2.2/maven-clean-plugin-2.2.pom [WARNING] Unable to get resource 'org.apache.maven.plugins:maven-clean-plugin:pom:2.2' from repository central (http://repo1.maven.org/maven2): Error trans ferring file: Server redirected too many times (20) [INFO] ------------------------------------------------------------------------ [ERROR] BUILD ERROR

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  • How do I get Cabal to bypass my Windows proxy settings?

    - by Brent.Longborough
    When retrieving packages with Cabal, I frequently get errors with this message: user error (Codec.Compression.Zlib: premature end of compressed stream) It looks like Cabal is using my Windows Networking proxy settings (for Privoxy). From digging around Google, Cabal or its libraries appear to have (had) a problem in this area. Possible solutions I can see are: Turn off proxying while using Cabal (not very keen on this one); or Get a patch and start hacking. I'm hesitant to go down this path, as I'm a complete Haskell noob and I'm not yet comfortable with Darcs; or Give it the magic "can I haz no proxy" parameter. Hence the question.

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  • In Magento, is it possible to populate your product models from an external API instead of the Magento DB?

    - by James Pelton
    I currently have Magento 1.7 CE installed. I want to use the Magento Product Models, except I want to get the price for the product from an external API (our pricing exists outside of Magento). I know what I could use the Magento API to import all the prices from our existing database, but our pricing changes very often, and we would then need to maintain two databases. Basically I'm wondering if there is something in Magento I can overwrite to call our API instead of the DB?

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  • rails howto use environment constant in models and views?

    - by fenec
    i have my constants initialized in environment.rb like this : Rails::Initializer.run do |config| ... MAX_BID = 10 end i would like to use this constant in my models and views,what is the correct syntax? if a use it a model its says NameError: uninitialized constant User::MAX_BID i understand that it is looking for the constant inside the model , how can i tell explicitly that this constant is in the environment? thanks

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  • join same rails models twice, eg people has_many clubs through membership AND people has_many clubs through committee

    - by Ben
    Models: * Person * Club Relationships * Membership * Committee People should be able to join a club (Membership) People should be able to be on the board of a club (Committee) For my application these involve vastly different features, so I would prefer not to use a flag to set (is_board_member) or similar. I find myself wanting to write: People has_many :clubs :through = :membership # :as = :member? :foreign_key = :member_id? has_many :clubs :through = :committee # as (above) but I'm not really sure how to stitch this together

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  • is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request?

    - by user1768246
    is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request ? $("#grid").jqGrid({ type: "GET", url: "", var columnNames = $("#grid")[0].p.colNames, var columnModel = $("#grid")[0].p.colNames, var columnData = $("#grid")[0].p.colNames, datatype: 'jsonstring', datastr: columnData, colModel: columnModel, jsonReader: { root: 'innerWrapper.rows', page: "result.gridData.outerWrapper.page", total: "result.gridData.outerWrapper.total", records: "result.gridData.outerWrapper.total", repeatitems: false, }, gridview: true, pager: "pager", height: "auto", rowNum: 10, width:"auto", height:"auto", rowList: [10, 20, 30,40], viewrecords: true, caption:"Graph Data", rownumbers: true, });

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