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  • How to skip all the column names in MySQL when the table has auto increment primary key?

    - by Jian Lin
    A table is: mysql> desc gifts; +---------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------+-------------+------+-----+---------+----------------+ | giftID | int(11) | NO | PRI | NULL | auto_increment | | name | varchar(80) | YES | | NULL | | | filename | varchar(80) | YES | | NULL | | | effectiveTime | datetime | YES | | NULL | | +---------------+-------------+------+-----+---------+----------------+ the following is ok: mysql> insert into gifts -> values (10, "heart", "heart_shape.jpg", now()); Query OK, 1 row affected (0.05 sec) but is there a way to not specify the "10"... and just let each one be 11, 12, 13... ? I can do it using mysql> insert into gifts (name, filename, effectiveTime) -> values ("coffee", "coffee123.jpg", now()); Query OK, 1 row affected (0.00 sec) but the column names need to be all specified. Is there a way that they don't have to be specified and the auto increment of primary key still works? thanks.

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  • problem with date returning wrong day although the timestamp is correct!

    - by Spiros
    I have a bizzare problem with php date function. code: $numDays = 8; $date = strtotime('2010-11-06'); for ($i=1; $i<=$numDays; $i++) { $thisDay = date("D, d M Y", $date); print ($thisDay.'<br>'); $date+=86400; // add one day to timestamp } result on my server (local host, windows): Sat, 06 Nov 2010 Sun, 07 Nov 2010 Mon, 08 Nov 2010 Tue, 09 Nov 2010 Wed, 10 Nov 2010 Thu, 11 Nov 2010 Fri, 12 Nov 2010 Sat, 13 Nov 2010 Result on my web server (linux) Sat, 06 Nov 2010 *Sun, 07 Nov 2010 Sun, 07 Nov 2010* Mon, 08 Nov 2010 Tue, 09 Nov 2010 Wed, 10 Nov 2010 Thu, 11 Nov 2010 Fri, 12 Nov 2010 Notice how Sun, 07 Nov 2010 appears twice on the remote server?? Why is this happening? can anyone explain this Behavior?

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  • How do I find the largest factor of an integer in mysql

    - by Bill H
    I am trying to write a select query that will dynamically determine the minimum number of items that can be packaged together. I am having trouble with one part of the query. ... CASE WHEN (pid.product_id) THEN 1 WHEN ((p.case_pack = p.inner_pack) AND (p.inner_pack % 11 = 0)) THEN CEILING(p.inner_pack / 11) WHEN ((p.case_pack = p.inner_pack) AND (p.inner_pack % 7 = 0)) THEN CEILING(p.inner_pack / 7) WHEN ((p.case_pack = p.inner_pack) AND (p.inner_pack % 6 = 0)) THEN CEILING(p.inner_pack / 6) WHEN ((p.case_pack = p.inner_pack) AND (p.inner_pack % 5 = 0)) THEN CEILING(p.inner_pack / 5) WHEN ((p.case_pack = p.inner_pack) AND (p.inner_pack % 4 = 0)) THEN CEILING(p.inner_pack / 4) WHEN ((p.case_pack = p.inner_pack) AND (p.inner_pack % 3 = 0)) THEN CEILING(p.inner_pack / 3) WHEN ((p.case_pack = p.inner_pack) AND (p.inner_pack % 2 = 0)) THEN CEILING(p.inner_pack / 2) ELSE p.inner_pack END AS min_pack ... What I want to do is find the largest factorial of an integer (p.inner_pack) that is under 12. Is there a better way to do this in mysql?

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  • Please help me in creating a update query

    - by Rajesh Rolen- DotNet Developer
    I have got a table which contains 5 column and query requirements: update row no 8 (or id=8) set its column 2, column 3's value from id 9th column 2, column 3 value. means all value of column 2, 3 should be shifted to column 2, 3 of upper row (start from row no 8) and value of last row's 2, 3 will be null For example, with just 3 rows, the first row is untouched, the second to N-1th rows are shifted once, and the Nth row has nulls. id math science sst hindi english 1 11 12 13 14 15 2 21 22 23 24 25 3 31 32 33 34 35 The result of query of id=2 should be: id math science sst hindi english 1 11 12 13 14 15 2 31 32 23 24 25 //value of 3rd row (col 2,3) shifted to row 2 3 null null 33 34 35 This process should run for all rows whose id 2 Please help me to create this update query I am using MS sqlserver 2005

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  • Declaring a C function to return an array

    - by Jaska
    How can I make a function which returns an array? I tried this const int WIDTH=11; const int HEIGHT=11; int main() { char A[WIDTH][HEIGHT]; A=rand_grid(WIDTH,HEIGHT); return 0; } // Initializes a random board. char[][] rand_grid(int i, int k) { char* A[i][k]; for(j=0;j<i;++j) { for(l=0;l<k;++l) { A[j][l]=ran(10); } } return A; } // Returns a random number from the set {0,...,9}. int ran(int i) { srand((unsigned int) time(0)); return(rand()%10); }

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  • fubar'd a ruby installation on ubuntu, need helping purging it for reinstall

    - by tipu
    i originally followed these steps to get a RoR environmentgoing: https://help.ubuntu.com/community/RubyOnRails that worked. then i put 1.9.2 on here. then i decided i want the original setup, did a "whereis ruby" and deleted those directories manually. that fubar'd my ruby installation. i can't use the repository to what i originally had. how can i purge ruby from completely and start fresh? right now the specific error is this: /usr/lib/ruby/1.8/rubygems.rb:11:in `require': no such file to load -- thread (LoadError) from /usr/lib/ruby/1.8/rubygems.rb:11 from /usr/bin/gem1.8:8:in `require' from /usr/bin/gem1.8:8 tipu@tipu_ubuntu:~$

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  • How can I join on a CSV varchar?

    - by mgroves
    I have a varchar field that contains a string like "10,11,12,13". How can I use that CSV string to join to another table with those IDs? Here's the approach I'm taking now: select * from SomeTable a WHERE (',' + @csvString + ',') LIKE '%,' + CONVERT(varchar(25), a.ID) + ',%' Where @csvString is "10,11,12,...". I intend to use this method as a join condition as well. That method works, but it's rather slow (using CAST doesn't improve the speed). I understand that having CSVs in the database like that is usually a very silly idea in most cases, but there's nothing I can do about that.

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  • C Preprocessor: #define in C... advice

    - by vikramtheone
    Hi Guys, I'm making a big C project and I have never come across a situation like this before so, I need your advice. What is your opinion? Is it okay to have the constants defined within conditional preprocessors like I have done below or you advise me to do this some other way? Any drawbacks if I do it this way? Regards Vikram #define NUM_OCTAVES_4 //#define NUM_OCTAVES_5 #ifdef NUM_OCTAVES_4 #define OCTAVES 4 const unsigned char borders [4] = {11, 26, 50, 98}; #elif NUM_OCTAVES_5 #define OCTAVES 5 const unsigned char borders [5] = {11, 26, 50, 98, 194}; #endif

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  • Export products and variants from SQL Server

    - by mickyjtwin
    I have a SQL Server DB that has a table of products, and another table which contains a list of the sku variants of each product if it has one. I want to export all the products and their SKU's into excel. At the moment, I have a helper SQL function which performs the subquery against a product_id and concatenates all the SKU's into a comma-delimited string, e.g: Product Code, Name, SKUs 111 P1 77, 22, 11 Is there an easier way to do this, so that each SKU is a row which the associated product code as well, i.e: Product Code, Name, SKUs 111 P1 77 111 P1 22 111 P1 11

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  • convert String "11-10-10 12:00:00" into Date Object

    - by Mahendra Athneria
    Hi, I want to convert String "11-10-10 12:00:00" into Date object but i am not able to do so. can you please help me out? below is the code snippet. i have the Date obj which has the value = Mon Oct 11 00:00:00 IST 2010 DateFormat newDateFormat = new SimpleDateFormat("dd-MM-yy hh:mm:ss"); String strDate = newDateFormat.format(tempDate); //**i got strDate as strDate is : 11-10-10 12:00:00** DateFormat newDateFormat1 = new SimpleDateFormat("dd-MM-yy hh:mm:ss"); try { tempDate = newDateFormat1.parse(strDate); // **getting tempDate as - Mon Oct 11 00:00:00 IST 2010** } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } Can someone help me to solve this issue? Regards, Mahendra Athneria Mumbai, India

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  • Can Crystal Reports Scale to Fit Page

    - by Jacob Reyes
    Hello , Can a crystal report be scaled to fit page? I'm hoping to achieve something similar to Microsoft Excel's Scale To Fit feature wherein a large spreadsheet can be scaled to fit a 8.5"x 11" page. (On MS Excel 2007 goto Page Layout Scale To Fit). Im searching of a way to make a large report fit into a smaller page during print. for example a report designed in Legal(8.5"x 14") page must be able to shrink when print previewed for Letter(8.5"x 11") page. In my crystal report, it should be scaled to fit the page by default. I was thinking maybe theres a Crystal Report Setting or C# code technique that I missed out. Any hint or link to the right direction is appreciated. Thanks!

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  • Convert a "by" object to a data frame in R

    - by lorin
    I'm using the "by" function in R to chop up a data frame and apply a function to different parts, like this: pairwise.compare <- function(x) { Nright <- ... Nwrong <- ... Ntied <- ... return(c(Nright=Nright, Nwrong=Nwrong, Ntied=Ntied)) } Z.by <- by(rankings, INDICES=list(rankings$Rater, rankings$Class), FUN=pairwise.compare) The result (Z.by) looks something like this: : 4 : 357 Nright Nwrong Ntied 3 0 0 ------------------------------------------------------------ : 8 : 357 NULL ------------------------------------------------------------ : 10 : 470 Nright Nwrong Ntied 3 4 1 ------------------------------------------------------------ : 11 : 470 Nright Nwrong Ntied 12 4 1 What I would like is to have this result converted into a data frame (with the NULL entries not present) so it looks like this: Rater Class Nright Nwrong Ntied 1 4 357 3 0 0 2 10 470 3 4 1 3 11 470 12 4 1 How do I do that?

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  • Polymorphic associations in CakePHP2

    - by Joseph
    I have 3 models, Page , Course and Content Page and Course contain meta data and Content contains HTML content. Page and Course both hasMany Content Content belongsTo Page and Course To avoid having page_id and course_id fields in Content (because I want this to scale to more than just 2 models) I am looking at using Polymorphic Associations. I started by using the Polymorphic Behavior in the Bakery but it is generating waaay too many SQL queries for my liking and it's also throwing an "Illegal Offset" error which I don't know how to fix (it was written in 2008 and nobody seems to have referred to it recently so perhaps the error is due to it not having been designed for Cake 2?) Anyway, I've found that I can almost do everything I need by hardcoding the associations in the models as such: Page Model CREATE TABLE `pages` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `slug` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `created` datetime NOT NULL, `updated` datetime NOT NULL, PRIMARY KEY (`id`) ) <?php class Page extends AppModel { var $name = 'Page'; var $hasMany = array( 'Content' => array( 'className' => 'Content', 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Page'), ) ); } ?> Course Model CREATE TABLE `courses` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `slug` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `created` datetime NOT NULL, `updated` datetime NOT NULL, PRIMARY KEY (`id`) ) <?php class Course extends AppModel { var $name = 'Course'; var $hasMany = array( 'Content' => array( 'className' => 'Content', 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Course'), ) ); } ?> Content model CREATE TABLE IF NOT EXISTS `contents` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `class` varchar(30) COLLATE utf8_unicode_ci NOT NULL, `foreign_id` int(11) unsigned NOT NULL, `title` varchar(100) COLLATE utf8_unicode_ci NOT NULL, `content` text COLLATE utf8_unicode_ci NOT NULL, `created` datetime DEFAULT NULL, `modified` datetime DEFAULT NULL, PRIMARY KEY (`id`) ) <?php class Content extends AppModel { var $name = 'Content'; var $belongsTo = array( 'Page' => array( 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Page') ), 'Course' => array( 'foreignKey' => 'foreign_id', 'conditions' => array('Content.class' => 'Course') ) ); } ?> The good thing is that $this->Content->find('first') only generates a single SQL query instead of 3 (as was the case with the Polymorphic Behavior) but the problem is that the dataset returned includes both of the belongsTo models, whereas it should only really return the one that exists. Here's how the returned data looks: array( 'Content' => array( 'id' => '1', 'class' => 'Course', 'foreign_id' => '1', 'title' => 'something about this course', 'content' => 'The content here', 'created' => null, 'modified' => null ), 'Page' => array( 'id' => null, 'title' => null, 'slug' => null, 'created' => null, 'updated' => null ), 'Course' => array( 'id' => '1', 'title' => 'Course name', 'slug' => 'name-of-the-course', 'created' => '2012-10-11 00:00:00', 'updated' => '2012-10-11 00:00:00' ) ) I only want it to return one of either Page or Course depending on which one is specified in Content.class UPDATE: Combining the Page and Course models would seem like the obvious solution to this problem but the schemas I have shown above are just shown for the purpose of this question. The actual schemas are actually very different in terms of their fields and the each have a different number of associations with other models too. UPDATE 2 Here is the query that results from running $this->Content->find('first'); : SELECT `Content`.`id`, `Content`.`class`, `Content`.`foreign_id`, `Content`.`title`, `Content`.`slug`, `Content`.`content`, `Content`.`created`, `Content`.`modified`, `Page`.`id`, `Page`.`title`, `Page`.`slug`, `Page`.`created`, `Page`.`updated`, `Course`.`id`, `Course`.`title`, `Course`.`slug`, `Course`.`created`, `Course`.`updated` FROM `cakedb`.`contents` AS `Content` LEFT JOIN `cakedb`.`pages` AS `Page` ON (`Content`.`foreign_id` = `Page`.`id` AND `Content`.`class` = 'Page') LEFT JOIN `cakedb`.`courses` AS `Course` ON (`Content`.`foreign_id` = `Course`.`id` AND `Content`.`class` = 'Course') WHERE 1 = 1 LIMIT 1

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  • Rails 3 NameError (cannot remove Object::Version) error

    - by Jeff D
    Can anyone point me at what might be causing this error? There is no ApplicationTrace, and it locks the server hard on my development machine. I think it has something to do with the way rails reloads your classes in development mode, and it appears to have something to do with a Version constant. I can't find a reference to this though. Can anyone point me in the direction of what would cause this? activesupport (3.0.3) lib/active_support/dependencies.rb:645:in `remove_const' activesupport (3.0.3) lib/active_support/dependencies.rb:645:in `remove_constant' activesupport (3.0.3) lib/active_support/dependencies.rb:645:in `instance_eval' activesupport (3.0.3) lib/active_support/dependencies.rb:645:in `remove_constant' activesupport (3.0.3) lib/active_support/dependencies.rb:521:in `remove_unloadable_constants!' activesupport (3.0.3) lib/active_support/dependencies.rb:521:in `each' activesupport (3.0.3) lib/active_support/dependencies.rb:521:in `remove_unloadable_constants!' activesupport (3.0.3) lib/active_support/dependencies.rb:317:in `clear' railties (3.0.3) lib/rails/application/bootstrap.rb:60:in `_callback_after_7' activesupport (3.0.3) lib/active_support/callbacks.rb:419:in `_run_call_callbacks' actionpack (3.0.3) lib/action_dispatch/middleware/callbacks.rb:44:in `call' rack (1.2.1) lib/rack/sendfile.rb:107:in `call' actionpack (3.0.3) lib/action_dispatch/middleware/remote_ip.rb:48:in `call' actionpack (3.0.3) lib/action_dispatch/middleware/show_exceptions.rb:46:in `call' railties (3.0.3) lib/rails/rack/logger.rb:13:in `call' rack (1.2.1) lib/rack/runtime.rb:17:in `call' activesupport (3.0.3) lib/active_support/cache/strategy/local_cache.rb:72:in `call' rack (1.2.1) lib/rack/lock.rb:11:in `call' rack (1.2.1) lib/rack/lock.rb:11:in `synchronize' rack (1.2.1) lib/rack/lock.rb:11:in `call' actionpack (3.0.3) lib/action_dispatch/middleware/static.rb:30:in `call' railties (3.0.3) lib/rails/application.rb:168:in `call' railties (3.0.3) lib/rails/application.rb:77:in `send' railties (3.0.3) lib/rails/application.rb:77:in `method_missing' railties (3.0.3) lib/rails/rack/log_tailer.rb:14:in `call' rack (1.2.1) lib/rack/content_length.rb:13:in `call' rack (1.2.1) lib/rack/handler/webrick.rb:52:in `service' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/httpserver.rb:104:in `service' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/httpserver.rb:65:in `run' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:173:in `start_thread' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:162:in `start' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:162:in `start_thread' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:95:in `start' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:92:in `each' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:92:in `start' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:23:in `start' /Volumes/files/jeffdeville/.rvm/rubies/ree-1.8.7-2010.02/lib/ruby/1.8/webrick/server.rb:82:in `start' rack (1.2.1) lib/rack/handler/webrick.rb:13:in `run' rack (1.2.1) lib/rack/server.rb:213:in `start' railties (3.0.3) lib/rails/commands/server.rb:65:in `start' railties (3.0.3) lib/rails/commands.rb:30 railties (3.0.3) lib/rails/commands.rb:27:in `tap' railties (3.0.3) lib/rails/commands.rb:27 script/rails:6:in `require' script/rails:6

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  • How do I set up a route in rails?

    - by NotDan
    In my routes.rb I have this: map.namespace :admin do |admin| admin.resources :galleries do |galleries| galleries.resources :gallery_images, :as=>'images' end end rake routes shows the route created like this: admin_gallery GET /admin/galleries/:id and when I go to this url in my browser: http://192.168.2.2:3000/admin/galleries/11/ I get this error: Unknown action No action responded to 11 But I would have expected it to use the show action/view, what am I doing wrong?

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  • Month to Date in SQL Server 2008

    - by Aaron Smith
    Hopefully this will be an easy one to answer. I am working on a table that requires MTD data. One of our SQL guys told me to use MONTH (@monthtodate)= 11 Where @monthtodate is set to GetDate() in the parameter list in SQL Server Management Studio. So in "theory", he says, it should select the month (11) and then get today and return all the requested data in between those two dates. But I'm thinking this isn't correct. In looking at my data I'm starting to think that It's just returning data for the whole month of November instead of just MTD. I guess, technically, anything that has 0 won't be calculated. However that just means it's poorly written code correct? In your opinions, would this be the better way to return MTD data: production_date <= @today and Production_Date >= DATEADD(mm, DATEDIFF(mm, 0, @today), 0) Thanks in advance everyone!

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  • How hard is it to create a not-so-random number generator?

    - by Duracell
    Backstory: So I was driving to band practice this evening. My car has a USB port where you can plug in a USB stick with MP3 files on it and the stereo will play them. I have about 100 MP3s on my stick so I pushed the 'Random' button. So from here to band practice, it played: Track 22 Track 45 Track 4 Track 11 Track 87 Track 66 Track 98 Then on the way home, it played Track 16 Track 27 Track 33 And then I stopped at the petrol station. I filled up, got back in the car and the stereo fired up again. It played Track 22 Track 45 Track 4 Track 11 Track 87 I thought, WTF? What's with this 'random' generator? What are they using as a seed, if not time? Is a car stereo so memory-tight that it can't even use the C stdlib? Does anyone know how this kind of thing happens?

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  • Error on Access database: Permission denied: 'CreateObject'

    - by elixireu
    Hi, I am migrating a website over to a new server, its in ASP and uses several Access databases, the site and CMS can read, display the data, and even edit and update existing data entries, but when I want to add a new entry, I get an error... Microsoft VBScript runtime error '800a0046' Permission denied: 'CreateObject' /padp2010d/ads_tradetracker.asp, line 11 There seems to be no passwords on the databases, I have set up and tested the ODBC Data Sources and they are working fine. The code or line that is causing the problem is... <% Dim Mail, strPath, strHost, Upload Set Upload = CreateObject("Persits.Upload") Upload.IgnoreNoPost = True ' Generate unique names Upload.OverwriteFiles = False ' Limit file size to 500000 bytes Upload.SetMaxSize 500000, True ' capture an upload and save uploaded files (if any) in temp directory Upload.SaveVirtual "\pa\images\advertenties" Upload.Save ' Use session ID as the new file name NewName = Session.SessionID The line 11 is Set Upload = CreateObject("Persits.Upload") If anyone could help that would be great. Could it be a Permission setting? Im a complete novice with ASP and Access! Thanks

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  • One to One relationship in MySQL

    - by Botto
    I'm trying to make a one to one relationship in a MySQL DB. I'm using the InnoDB engine and the basic table looks like this: CREATE TABLE `foo` ( `fooID` INT(11) NOT NULL PRIMARY KEY AUTO_INCREMENT, `name` TEXT NOT NULL ) CREATE TABLE `bar` ( `barName` VARCHAR(100) NOT NULL, `fooID` INT(11) NOT NULL PRIMARY KEY, CONSTRAINT `contact` FOREIGN KEY (`fooID`) REFERENCES `foo`(`fooID`) ) Now once I have set up these I alter the foo table so that the fooID also becomes a foreign key to the fooID in bar. The only issue I am facing with this is that there will be a integrity issue when I try to insert into either. I would like some help, thanks.

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  • How to automaticly add a page number to all internal links on the HTML page?

    - by Tomasz
    In print mode, I would like to render such a links: <a href="#targetPage">link</a> like this: <a href="#targetPage">link (page 11)</a> (suppose the target page is on 11. page in print preview). It is possible to add page number using counters to the page footer with plain CSS, but could I use this in more "the way I want it" way? The solution doesn't need to be cross-browser (FF/Chrome is enough), any CSS/Javascript tricks are allowed...

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  • Jenkins and Visual Studio Online integration authentication

    - by user3120361
    right now I am trying to Setup Continuouse Integration - Delivery for a basic WCF Service, which will be hosted on a Microsoft Azure VM. The Project is Version Controlled through Visual Studio Online. So I installed Jenkins (also on the Azure VM), TFS plugin etc. and started the first Test Build: As Server URL I used "[VSO Adress]/DefaultCollection" and for Login purposes my Microsoft Account (I can Access VSO with that). The Problem is, when I run the Build I get the following error: Started by user Developer Building in workspace C:\Program Files (x86)\Jenkins\jobs\test\workspace [workspace] $ "C:\Program Files (x86)\TEE-CLC-11.0.0.1306\TEE-CLC-11.0.0\tf.cmd" workspaces -format:brief -server:[VSO Adress]/DefaultCollection ****" An error occurred: Access denied connecting to TFS server [VSO Adress] (authenticating as har****@*******o.com) FATAL: Executable returned an unexpected result code [100] ERROR: null Finished: FAILURE So my question is, whether it is generally possible to connect Jenkins and VSO that way and if so, which login credentials are needed

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  • How to implement best matching logic in TSQL (SQL Server 2000)

    - by sanjay-kumar1911
    I have two tables X and Y: Table X C1 C2 C3 1 A 13 2 B 16 3 C 8 Table Y C1 C2 C3 C4 1 A 2 N 2 A 8 N 3 A 12 N 4 A 5 N 5 B 7 N 6 B 16 N 7 B 9 N 8 B 5 N 9 C 8 N 10 C 2 N 11 C 8 N 12 C 6 N Records in Table Y can be n number CREATE TABLE X(C1 INT, C2 CHAR(1), C3 INT); CREATE TABLE Y(C1 INT, C2 CHAR(1), C3 INT, C4 CHAR(1)); with following data: INSERT INTO X VALUES (1 'A',13 ); INSERT INTO X VALUES (2 'B',16 ); INSERT INTO X VALUES (3 'C',8 ); INSERT INTO Y VALUES (1,'A', 2,'N'); INSERT INTO Y VALUES (2,'A', 8,'N'); INSERT INTO Y VALUES (3,'A', 12,'N'); INSERT INTO Y VALUES (4,'A', 5,'N'); INSERT INTO Y VALUES (5,'B', 7,'N'); INSERT INTO Y VALUES (6,'B', 16,'N'); INSERT INTO Y VALUES (7,'B', 9,'N'); INSERT INTO Y VALUES (8,'B', 5,'N'); INSERT INTO Y VALUES (9,'C', 8,'N'); INSERT INTO Y VALUES (10,'C', 2,'N'); INSERT INTO Y VALUES (11,'C', 8,'N'); INSERT INTO Y VALUES (12,'C', 6,'N'); EXPECTED RESULT Table Y C1 C2 C3 C4 1 A 2 N 2 A 8 Y 3 A 12 N 4 A 5 Y 5 B 7 N 6 B 16 Y 7 B 9 N 8 B 5 N 9 C 8 Y 10 C 2 N 11 C 8 N 12 C 6 N How do I compare value of column C3 in Table X with all possible matches of column C3 of Table Y and to mark records as matched and unmatched in column C4 of Table Y? Possible matches for A (i.e. value of column C2 in Table X) would be (where R is row number i.e. value of column C1 in Table Y): R1, R2, R3, R4, R1+R2, R1+R3, R1+R4, R2+R3, R2+R4, R3+R4, R4+R5, R1+R2+R3, R1+R2+R4, R2+R3+R4, R1+R2+R3+R4

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  • Help needed in pivoting(SQL SERVER 2005)

    - by Newbie
    I have a table like ID Grps Vals --- ---- ----- 1 1 1 1 1 3 1 1 45 1 2 23 1 2 34 1 2 66 1 3 10 1 3 17 1 3 77 2 1 144 2 1 344 2 1 555 2 2 11 2 2 22 2 2 33 2 3 55 2 3 67 2 3 77 The desired output being ID Record1 Record2 Record3 --- ------- ------- ------- 1 1 23 10 1 3 34 17 1 45 66 77 2 144 11 55 2 344 22 67 2 555 33 77 I have tried(using while loop) but the program is running slow. I have been asked to do so by using SET based approach Can any one please help to solve this.(SQL SERVER 2005)

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  • calculate next line numbers

    - by osomanden
    Weird question I guess.. But I am not very math wiz - soo here goes.. I am trying to create a patterne (or variable patterns based on selection) based on x and y numbers (2 rows and 4 columns) and the direction of the counting of x numbers like: 1-2-3-4 5-6-7-8 That one is easy, when number of x-columns is reached, next line and continue x count. But with eg. this one (still 2 rows and 4 columns): 1-2-3-4 8-7-6-5 upsie.. what if it is eg. 3++ rows and still 4 columns? 1-2-3-4 8-7-6-5 9-10-11-12 what would be the formula for this - or other possible variations (teaser for variations): 9-10-11-12 8-7-6-5 1-2-3-4 or reversed

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