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  • strange behavior in vim with negative look-behind

    - by João Portela
    So, I am doing this search in vim: /\(\(unum\)\|\(player\)=\)\@<!\"1\" and as expected it does not match lines that have: player="1" but matches lines that have: unum="1" what am i doing wrong? isn't the atom to be negated all of this: \(\(unum\)\|\(player\)=\) naturally just doing: /\(\(unum\)\|\(player\)=\) matches unum= or player=.

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  • parse search string

    - by Benjamin Ortuzar
    I have search strings, similar to the one bellow: energy food "olympics 2010" Terrorism OR "government" OR cups NOT transport and I need to parse it with PHP5 to detect if the content belongs to any of the following clusters: AllWords array AnyWords array NotWords array These are the rules i have set: If it has OR before or after the word or quoted words if belongs to AnyWord. If it has a NOT before word or quoted words it belongs to NotWords If it has 0 or more more spaces before the word or quoted phrase it belongs to AllWords. So the end result should be something similar to: AllWords: (energy, food, "olympics 2010") AnyWords: (terrorism, "government", cups) NotWords: (Transport) What would be a good way to do this?

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  • Regexp match in Java

    - by tinti
    Regexp in Java I want to make a regexp who do this verify if a word is like [0-9A-Za-z][._-'][0-9A-Za-z] example for valid words A21a_c32 daA.da2 das'2 dsada ASDA 12SA89 non valid words dsa#da2 34$ Thanks

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  • Replaceing <a href="mailto: with just email aadress

    - by Lauri
    I want to replace all "mailto:" links in html with plain emails. In: text .... <a href="mailto:[email protected]">not needed</a> text Out: text .... [email protected] text I did this: $str = preg_replace("/\<a.+href=\"mailto:(.*)\".+\<\/a\>/", "$1", $str); But it fails if there are multiple emails in string or html inside "a" tag In: <a href="mailto:[email protected]">not needed</a><a href="mailto:[email protected]"><font size="3">[email protected]</font></a> Out: [email protected]">

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  • multiline perl search and replace (one-liner)

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with perl. I would prefer to allow for any occurences of white space and/or new lines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> </div>

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  • Bash: Extract Range with Regular Expressioin (maybe sed?)

    - by sixtyfootersdude
    I have a file that is similar to this: <many lines of stuff> SUMMARY: <some lines of stuff> END OF SUMMARY I want to extract just the stuff between SUMMARY and END OF SUMMARY. I suspect I can do this with sed but I am not sure how. I know I can modify the stuff in between with this: sed "/SUMMARY/,/END OF SUMMARY/ s/replace/with/" fileName (But not sure how to just extract that stuff). I am Bash on Solaris.

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  • how to match a regulas expresion like (%i1) in python pexpect

    - by mike
    I want to use maxima from python using pexpect, whenever maxima starts it will print a bunch of stuff of this form: $ maxima Maxima 5.27.0 http://maxima.sourceforge.net using Lisp SBCL 1.0.57-1.fc17 Distributed under the GNU Public License. See the file COPYING. Dedicated to the memory of William Schelter. The function bug_report() provides bug reporting information. (%i1) i would like to start up pexpect like so: import pexpect cmd = 'maxima' child = pexpect.spawn(cmd) child.expect (' match all that stuff up to and including (%i1)') child.sendline ('integrate(sin(x),x)') chil.expect( match (%o1 ) ) print child.before how do i match the starting banner up to the prompt (%i1)? and so on, also maxima increments the (%i1)'s by one as the session goes along, so the next expect would be: child.expect ('match (%i2)') child.sendline ('integrate(sin(x),x)') chil.expect( match (%o2 ) ) print child.before how do i match the (incrementing) integers?

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  • UPDATE REGEX MYSQL

    - by Simon
    I have a table of contacts and a table of postcode data. I need to match the first part of the postcode and the join that with the postcode table... and then perform an update... I want to do something like this... UPDATE `contacts` LEFT JOIN `postcodes` ON PREG_GREP("/^[A-Z]{1,2}[0-9][0-9A-Z]{0,1}/", `contacts`.`postcode`) = `postcodes`.`postcode` SET `contacts`.`lat` = `postcode`.`lat`, `contacts`.`lng` = `postcode`.`lng` Is it possible?? Or do I need to use an external script? Many thanks.

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  • Regular Expression With Mask

    - by Kumar
    I have a regular expression for phone numbers as follows: ^[01]?[- .]?(\([2-9]\d{2}\)|[2-9]\d{2})[- .]?\d{3}[- .]?\d{4}$ I have a mask on the phone number textbox in the following format: (___)___-____ How can I modify the regular expression so that it accommodates the mask?

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  • Combine regular expressions for splitting camelCase string into words

    - by stou
    I managed to implement a function that converts camel case to words, by using the solution suggested by @ridgerunner in this question: Split camelCase word into words with php preg_match (Regular Expression) However, I want to also handle embedded abreviations like this: 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' I came up with this solution: <?php function camelCaseToWords($camelCaseStr) { // Convert: "TestASAPTestMore" to "TestASAP TestMore" $abreviationsPattern = '/' . // Match position between UPPERCASE "words" '(?<=[A-Z])' . // Position is after group of uppercase, '(?=[A-Z][a-z])' . // and before group of lowercase letters, except the last upper case letter in the group. '/x'; $arr = preg_split($abreviationsPattern, $camelCaseStr); $str = implode(' ', $arr); // Convert "TestASAP TestMore" to "Test ASAP Test More" $camelCasePattern = '/' . // Match position between camelCase "words". '(?<=[a-z])' . // Position is after a lowercase, '(?=[A-Z])' . // and before an uppercase letter. '/x'; $arr = preg_split($camelCasePattern, $str); $str = implode(' ', $arr); $str = ucfirst(trim($str)); return $str; } $inputs = array( 'oneTwoThreeFour', 'StartsWithCap', 'hasConsecutiveCAPS', 'ALLCAPS', 'ALL_CAPS_AND_UNDERSCORES', 'hasABREVIATIONEmbedded', ); echo "INPUT"; foreach($inputs as $val) { echo "'" . $val . "' translates to '" . camelCaseToWords($val). "'\n"; } The output is: INPUT'oneTwoThreeFour' translates to 'One Two Three Four' 'StartsWithCap' translates to 'Starts With Cap' 'hasConsecutiveCAPS' translates to 'Has Consecutive CAPS' 'ALLCAPS' translates to 'ALLCAPS' 'ALL_CAPS_AND_UNDERSCORES' translates to 'ALL_CAPS_AND_UNDERSCORES' 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' It works as intended. My question is: Can I combine the 2 regular expressions $abreviationsPattern and camelCasePattern so i can avoid running the preg_split() function twice?

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  • In Python BeautifulSoup How to move tags

    - by JJ
    I have a partially converted XML document in soup coming from HTML. After some replacement and editing in the soup, the body is essentially - <Text...></Text> # This replaces <a href..> tags but automatically creates the </Text> <p class=norm ...</p> <p class=norm ...</p> <Text...></Text> <p class=norm ...</p> and so forth. I need to "move" the <p> tags to be children to <Text> or know how to suppress the </Text>. I want - <Text...> <p class=norm ...</p> <p class=norm ...</p> </Text> <Text...> <p class=norm ...</p> </Text> I've tried using item.insert and item.append but I'm thinking there must be a more elegant solution. for item in soup.findAll(['p','span']): if item.name == 'span' and item.has_key('class') and item['class'] == 'section': xBCV = short_2_long(item._getAttrMap().get('value','')) if currentnode: pass currentnode = Tag(soup,'Text', attrs=[('TypeOf', 'Section'),... ]) item.replaceWith(currentnode) # works but creates end tag elif item.name == 'p' and item.has_key('class') and item['class'] == 'norm': childcdatanode = None for ahref in item.findAll('a'): if childcdatanode: pass newlink = filter_hrefs(str(ahref)) childcdatanode = Tag(soup, newlink) ahref.replaceWith(childcdatanode) Thanks

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  • Transforming a string to a valid PDO_MYSQL DSN

    - by Alix Axel
    What is the most concise way to transform a string in the following format: mysql:[/[/]][user[:pass]@]host[:port]/db[/] Into a usuable PDO connection/instance (using the PDO_MYSQL DSN), some possible examples: $conn = new PDO('mysql:host=host;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user'); $conn = new PDO('mysql:host=host;port=3307;dbname=db', 'user', 'pass'); I've been trying some regular expressions (preg_[match|split|replace]) but they either don't work or are too complex, my gut tells me this is not the way to go but nothing else comes to my mind. Any suggestions?

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  • Building a Hashtag in Javascript without matching Anchor Names, BBCode or Escaped Characters

    - by Martindale
    I would like to convert any instances of a hashtag in a String into a linked URL: #hashtag - should have "#hashtag" linked. This is a #hashtag - should have "#hashtag" linked. This is a [url=http://www.mysite.com/#name]named anchor[/url] - should not be linked. This isn&#39;t a pretty way to use quotes - should not be linked. Here is my current code: String.prototype.parseHashtag = function() { return this.replace(/[^&][#]+[A-Za-z0-9-_]+(?!])/, function(t) { var tag = t.replace("#","") return t.link("http://www.mysite.com/tag/"+tag); }); }; Currently, this appears to fix escaped characters (by excluding matches with the amperstand), handles named anchors, but it doesn't link the #hashtag if it's the first thing in the message, and it seems to grab include the 1-2 characters prior to the "#" in the link. Halp!

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  • Intersection of two regular expressions

    - by Henry
    Hi, Im looking for function (PHP will be the best), which returns true whether exists string matches both regexpA and regexpB. Example 1: $regexpA = '[0-9]+'; $regexpB = '[0-9]{2,3}'; hasRegularsIntersection($regexpA,$regexpB) returns TRUE because '12' matches both regexps Example 2: $regexpA = '[0-9]+'; $regexpB = '[a-z]+'; hasRegularsIntersection($regexpA,$regexpB) returns FALSE because numbers never matches literals. Thanks for any suggestions how to solve this. Henry

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  • Cleaning strings in R: add punctuation w/o overwriting last character

    - by spearmint
    I'm new to R and unable to find other threads with a similar issue. I'm cleaning data that requires punctuation at the end of each line. I am unable to add, say, a period without overwriting the final character of the line preceding the carriage return + line feed. Sample code: Data1 <- "%trn: dads sheep\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Data2 <- gsub("[^[:punct:]]\r\n\\*", ".\r\n\\*", Data1) The contents of Data2: [1] "%trn: dads shee.\r\n*MOT: hunn.\r\n%trn: yes.\r\n*MOT: ana mu\r\n%trn: where is it?" Notice the "p" of sheep was overwritten with the period. Any thoughts on how I could avoid this?

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  • How to remove a tab attribute in ASP .NET AJAX Toolkit using Regular Expression

    - by Nassign
    I have tried to remove the following tag generated by the AJAX Control toolkit. The scenario is our GUI team used the AJAX control toolkit to make the GUI but I need to move them to normal ASP .NET view tag using MultiView. I want to remove all the __designer: attributes Here is the code <asp:TextBox ID="a" runat="server" __designer:wfdid="w540" /> <asp:DropdownList ID="a" runat="server" __designer:wfdid="w541" /> ..... <asp:DropdownList ID="a" runat="server" __designer:wfdid="w786" /> I tried to use the regular expression find replace in Visual Studio using: Find: :__designer\:wfdid="w{([0-9]+)}" Replace with empty space Can any regular expression expert help?

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  • How do I locate a particular word in a text file using .NET

    - by cmrhema
    I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that?

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  • Invert regexp in vim

    - by Chris J
    There's a few "how do I invert a regexp" questions here on stackoverflow, but I can't find one for vim (if it does exist, by goggle-fu is lacking today). In essence I want to match all non-printable characters and delete them. I could write a short script, or drop to a shell and use tr or something similar to delete, but a vim solution would be dandy :-) Vim has the atom \p to match printable characters, however trying to do this :s/[^\p]//g to match the inverse failed and just left me with every 'p' in the file. I've seen the (?!xxx) sequence in other questions, and vim seems to not recognise this sequence. I've not found seen an atom for non-printable chars. In the interim, I'm going to drop to external tools, but if anyone's got any trick up their sleeve to do this, it'd be welcome :-) Ta!

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