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  • Sanitize Content: removing markup from Amazon's content

    - by StackOverflowNewbie
    I'm using Amazon Web Service to get product descriptions of various items. The problem is that Amazon's content contains mark up that is sometimes destructive to the layout of my web page (e.g. unclosed DIVs, etc.). I want to sanitize the content I get from Amazon. My solution would be to do the following (my initial list so far): Remove unnecessary tags such as div, span, etc. while keeping tags like p, ul, ol, etc. Remove all attributes from all the tags (e.g. seems like there are style attributes in some of the tags) Remove excess white space (e.g. multiple spaces, carriage returns, new lines, tabs, etc.) Etc. Before I go off trying to build my solution, I'm wondering if anyone has a better idea (or an already existing solution). Thanks.

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  • Validating javascript decimal numbers

    - by Click Upvote
    I'm using the following regexp to validate numbers in my javascript file: var valid = (val.match(/^\d+$/)); It works fine for whole numbers like 100, 200, etc, however for things like 1.44, 4.11, etc, it returns false. How can I change it so numbers with a decimal are also accepted?

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  • pattern for the following condition in java

    - by zahir hussain
    hi i want to know how to write pattern.. for example : the word is "AboutGoogle AdWords Drive traffic and customers to your site. Pay through Cheque, Net Banking or Credit Card. Google Toolbar Add a search box to your browser. Google SMS To find out local information simply SMS to 54664. Gmail Free email with 7.2GB storage and less spam. Try Gmail today. Our ProductsHelp Help with Google Search, Services and ProductsGoogle Web Search Features Translation, I'm Feeling Lucky, CachedGoogle Services & Tools Toolbar, Google Web APIs, ButtonsGoogle Labs Ideas, Demos, ExperimentsFor Site OwnersAdvertising AdWords, AdSenseBusiness Solutions Google Search Appliance, Google Mini, WebSearchWebmaster Central One-stop shop for comprehensive info about how Google crawls and indexes websitesSubmit your content to Google Add your site, Google SitemapsOur CompanyPress Center News, Images, ZeitgeistJobs at Google Openings, Perks, CultureCorporate Info Company overview, Philosophy, Diversity, AddressesInvestor Relations Financial info, Corporate governanceMore GoogleContact Us FAQs, Feedback, NewsletterGoogle Logos Official Logos, Holiday Logos, Fan LogosGoogle Blog Insights to Google products and cultureGoogle Store Pens, Shirts, Lava lamps©2010 Google - Privacy Policy - Terms of Service" I have to search some word... for example "google insights" so how to write the code in java... i just write small code... check my code and answer my question... that code only use for find the search word, where is that. but i need to display some words front of search word and display some words rear of search workd... similar to google search... my code is Pattern p = Pattern.compile("(?i)(.*?)"+search+""); Matcher m = p.matcher(full); String title=""; while (m.find() == true) { title=m.group(1); System.out.println(title); } the full is orignal content, search s search word... thanks and advance

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  • Python: using a regular expression to match one line of HTML

    - by skylarking
    This simple Python method I put together just checks to see if Tomcat is running on one of our servers. import urllib2 import re import sys def tomcat_check(): tomcat_status = urllib2.urlopen('http://10.1.1.20:7880') results = tomcat_status.read() pattern = re.compile('<body>Tomcat is running...</body>',re.M|re.DOTALL) q = pattern.search(results) if q == []: notify_us() else: print ("Tomcat appears to be running") sys.exit() If this line is not found : <body>Tomcat is running...</body> It calls : notify_us() Which uses SMTP to send an email message to myself and another admin that Tomcat is no longer runnning on the server... I have not used the re module in Python before...so I am assuming there is a better way to do this... I am also open to a more graceful solution with Beautiful Soup ... but haven't used that either.. Just trying to keep this as simple as possible...

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  • Rails validates_format_of

    - by squids
    Hi, I want to use validates_format_of to validate a comma separated string with only letters (small and caps), and numbers. So. example1, example2, 22example44, ex24 not: ^&*, < , asfasfsdafas<#%$# Basically I want to have users enter comma separated words(incl numbers) without special characters. I'll use it to validate tags from acts_as_taggable_on. (i don't want to be a valid tag for example. Thanks in advance.

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  • Jetty RewriteHandler and RewriteRegexRule

    - by Justin
    I'm trying to rewrite a URL for a servlet. The URL gets rewritten correctly, but the context doesn't match after that. Any idea how to get this to work? RewriteHandler rewriteHandler = new RewriteHandler(); rewriteHandler.setRewriteRequestURI(true); rewriteHandler.setRewritePathInfo(true); rewriteHandler.setOriginalPathAttribute("requestedPath"); RewriteRegexRule rewriteRegexRule = new RewriteRegexRule(); rewriteRegexRule.setRegex("/r/([^/]*).*"); rewriteRegexRule.setReplacement("/r?z=$1"); rewriteHandler.addRule(rewriteRegexRule); ContextHandlerCollection contextHandlerCollection = new ContextHandlerCollection(); Context servletContext = new Context(contextHandlerCollection, "/"); servletContext.addServlet(new ServletHolder(new RedirectServlet()), "/r"); So basically /r/asdf gets rewritten to /r?z=asdf. However, the rewritten /r?z=asdf is now not processed by the servlet. Also, /r?z=asdf does work if called directly.

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  • match at the beginning of any line, including the first

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)?

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  • Regular Expression to break row with comma separated values into distinct rows

    - by Nick
    I have a file with many rows. Each row has a column which may contain comma separated values. I need each row to be distinct (ie no comma separated values). Here is an example row: AB AB10,AB11,AB12,AB15,AB16,AB21,AB22,AB23,AB24,AB25,AB99 ABERDEEN Aberdeenshire The columns are comma separated (Postcode area, Postcode districts, Post town, Former postal county). So the above row would get turned into: AB AB10 ABERDEEN Aberdeenshire AB AB11 ABERDEEN Aberdeenshire AB AB12 ABERDEEN Aberdeenshire ... ... I tried the following but it didn't work... (.+)\t(([0-9A-Z]+),)+\t(.+)\t(.+)

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  • Basic Profanity Filter in Objective C for iPhone

    - by David van Dugteren
    How have you like minded individuals tackled the basic challenge of filtering profanity, obviously one can't possibly tackle every scenario but it would be nice to have one at the most basic level as a first line of defense. In Obj-c I've got NSString *tokens = [text componentsSeparatedByString:@" "]; And then I loop through each token to see if any of the keywords (I've got about 400 in a list) are found within each token. Realising False positives are also a problem, if the word is a perfect match, its flagged as profanity otherwise if more than 3 words with profanity are found without being perfect matches it is also flagged as profanity. Later on I will use a webservice that tackles the problem more precisely, but I really just need something basic. So if you wrote the word penis it would go yup naughty naughty, bad word written.

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  • How can I remove HTML span tags with a Perl one liner?

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with Perl. I would prefer to allow for any occurences of whitespace or newlines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> EDIT: It's just the <span>'s and </span>'s that are inbetween <p> and <a> from the "blockDontForget" class </div> that I want to remove (there are lots or these blockDontForget divs with spans inside anchors that I want to keep).

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  • regexp exclusion

    - by Vlad
    Hello everyone! I have regexp to change smileys to images. Here it is (?:(?![0]:\)|:\)\)|:-\)\)))(:\)|:-\)) The point is not to change 0:) and :)) and :-)) while changing :) and :-) It works pretty well with :)) and :-)) but somehow still grabs :) in 0:) Where's my mistake?

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  • PostgreSQL String search for partial patterns removing exrtaneous characters

    - by tbrandao
    Looking for a simple SQL (PostgreSQL) regular expression or similar solution (maybe soundex) that will allow a flexible search. So that dashes, spaces and such are omitted during the search. As part of the search and only the raw characters are searched in the table.: Currently using: SELECT * FROM Productions WHERE part_no ~* '%search_term%' If user types UTR-1 it fails to bring up UTR1 or UTR 1 stored in the database. But the matches do not happen when a part_no has a dash and the user omits this character (or vice versa) EXAMPLE search for part UTR-1 should find all matches below. UTR1 UTR --1 UTR 1 any suggestions...

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  • Strange behavior: Dynamic expressions with RegExp Object in RegExp.match (Javascript)

    - by NeDark
    I have detect a strange behavior in regexps created with the RegExp object: With this code: var exp1 = /./; var exp2 = new RegExp('.'); ? var test1 = exp1.test('large\n\ntext..etc.'); var test2 = exp2.test('large\n\ntext..etc.'); ? var match1 = 'large\n\ntext..etc.'.match(exp1); var match2 = 'large\n\ntext..etc.'.match(exp2); ...the result is: test1 = true test2 = true ? match1 = 'l' (first match) match2 = null With the regexp maked with the regexp object from a string it finds nothing... Why does this happends? Thanks!!

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  • multi-line pattern matching in pyhon

    - by Horace Ho
    A periodic computer generated message (simplified): Hello user123, - (604)7080900 - 152 - minutes Regards Using python, how can I extract "(604)7080900", "152", "minutes" (i.e. any text following a leading "- " pattern) between the two empty lines (empty line is the \n\n after "Hello user123" and the \n\n before "Regards"). Even better if the result string list are stored in an array. Thanks!

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  • Regular expression to remove all text except...

    - by Barryman9000
    There may be an easier way, and if there is I'm all for it. However - my ASP.NET page has a TON of controls on it, and I've given them all ID's that start with underscore. I copied all the markup into Notepad++ and I'm trying to find a regular expression that will find everything but the controls and replace it with whitespace. that way I'll have a text file that has all my control names which I'll probably throw into Excel and do some string manipulation to add ".Text = " etc. Any suggestions?

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  • Match groups in Python

    - by Curd
    Is there a way in Python to access match groups without explicitely creating a match object (or another way to beautify the example below)? Here is an example to clarify my motivation for the question: Following perl code if ($statement =~ /I love (\w+)/) { print "He loves $1\n"; } elsif ($statement =~ /Ich liebe (\w+)/) { print "Er liebt $1\n"; } elsif ($statement =~ /Je t\'aime (\w+)/) { print "Il aime $1\n"; } translated into Python m = re.match("I love (\w+)", statement) if m: print "He loves",m.group(1) else: m = re.match("Ich liebe (\w+)", statement) if m: print "Er liebt",m.group(1) else: m = re.match("Je t'aime (\w+)", statement) if m: print "Il aime",m.group(1) looks very awkward (if-else-cascade, match object creation).

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  • Finding an open and closing tag in Regexp

    - by Rixius
    Is there a way to find custom tags in regexp I.e. match {a}sometext{/a} As well as {c=#fff}sometext{/c} So that it finds the entire block of inner content? The problem is the sometext could have another tag as in: {a=http://www.google.com}{b}Hello, world{/b}{/a} The only solutions I can come up with would match from {a... to .../b} when I want {a... to .../a} is there a single regexp solution, or would it be best to match the start, and then use another method to find the end from the back up, and grab it out that way? I'm using PHP 5.2 so I have all the options that entails.

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  • How do I find multiple matches with one regular expression?

    - by christian studer
    I've got the following string: response: id="1" message="whatever" attribute="none" world="hello" The order of the attributes is random. There might be any number of other attributes. Is there a way to get the id, message and world attribute in one regular expression instead of applying the following three one after another? / message="(.*?)"/ / world="(.*?)"/ / id="(.*?)"/

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  • This regx does not work only in Chrome

    - by Deeptechtons
    Hi i just put up a validation function in jScript to validate filename in fileupload control[input type file]. The function seems to work fine in FF and sometimes in ie but never in Chrome. Basically the function tests if File name is atleast 1 char upto 25 characters long.Contains only valid characters,numbers [no spaces] and are of file types in the list. Could you throw some light on this function validate(Uploadelem) { var objRgx = new RegExp(/^[\w]{1,25}\.*\.(jpg|gif|png|jpeg|doc|docx|pdf|txt|rtf)$/); objRgx.ignoreCase = true; if (objRgx.test(Uploadelem.value)) { document.getElementById('moreUploadsLink').style.display = 'block'; } else { document.getElementById('moreUploadsLink').style.display = 'none'; } }

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  • How can I replace only the last occurence of an number in a string with php?

    - by Shawn
    How would you change this: a-10-b-19-c into something like this: a-10-b-20-c using regular expressions in PHP? The only solution I've found so far is: reverse the original string - "c-91-b-01-a" find the first number - "91" reverse it - "19" turn in into a number (parseInt) - 19 add 1 to it (+1) - 20 turn it into a string again (toString) - "20" reverse it again - "02" replace the original match with this new number - "c-02-b-01-a" reverse the string - "a-10-b-20-c" I was hoping someone on SO would have a simpler way to do this... Anyone?

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