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• Custom XML Serialization, how to write custom root element?

  - by Beta033

  I'm probably just doing this wrong, i know. i'm using custom serialization and when the xml is generated it's putting the class name as the root element Example: <MyClassName> <MyIntendedRootNode> <ObjectType> <Property1/> <Property2/> ... I'm inoking the serialization by calling xmlserializer.Serialize(writer,Me) so i'm sure that has something to do with it. I've tried putting XMLRoot onto the class, but i think as vb is compiling this partial class with it's aspx page, it's either overwriting this property or ignoring it entirely. ideally i'd like to just tell it to either throw away everything it has and use a different root element. Anybody else do this except me? Thanks

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• how to get namespace prefixes from XML document, using MSXML ?

  - by KaluSingh Gabbar

  For example, In this document < ?xml version="1.0" ? > < SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:ns1="http://opcfoundation.org/webservices/XMLDA/1.0/" xmlns:ns2="Service"> < SOAP-ENV:Body id="_0" > if I need to select the element "Body", I need to know the prefix "SOAP-ENV". How can I get that? getting a root element and slicing the colon (:) off seems a dirty idea to me, I am sure there should be a neat way to do that. Google does not help (may be I am not searching for the right thing).

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• Blog Engine .NET with XML Data Storage How is it so fast ?

  - by Kubi

  I am looking for a way to embed a blog engine into my own application and I am too curious about Blog Engine algorithm. This may not be the correct place to ask but, How is that possible to store blog entry data in an XML file like BlogEngine.Net with Default Configuration. It must be getting slower everyday while the file is getting larger and larger. I am wondering the algorithm behind that. Is it loading with a different way ? Or Am I wrong with the time estimation ? I know it is open source but I thought it would be better to see a discussion here for some others might be thinking the same and this thread can be a reference.

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• How can I convert convert docx or wordml xml files to xsl-fo?

  - by Jon Pastore

  I've been looking for a method to convert docx or wordml xml to xsl-fo. I read this post: http://stackoverflow.com/questions/156683/what-is-the-best-xslt-engine-for-perl but I'm having exceptional problems getting apache-fop going. I was able to download the bins and run it locally but the formatting was a little off and it didn't maintain the headers and footers or section 1 or section 3 (17 page doc 3 sections) it also overlapped the text over the outline numbers and did not maintain the font used. trying a more simple test caused fop to fail completely. I would like to find a way to create a PDF that is at least close to 100% accurate reproduction of the original doc.

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• SOAP, REST or just XML for Objective-C/iPhone vs. server solution

  - by Nicsoft

  Hello, We are going to set up a solution where the iPhone is requesting data from the server. We have the option to decide what kind of solution to put in place and we are not sure about which way to go. Regarding SOAP I think I have the answer, there are no really stable solution for doing this (I know there are solutions, but I want something stable). How about REST? Or is it better to just create our own XML? It's not going to be so complicated reguest/respons-flow. Thanks in advance!

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• What is resource-ref in web.xml used for?

  - by Denise

  Hi everyone, I'm just wondering when/why you would define a resource-ref element in your web.xml file? I would have thought that it would be defined in your web/app server using JNDI and then look up the JNDI reference in your Java code? The resource-ref definition seems a bit redundant to me and I can't think of when it might be useful. Example: <resource-ref> <description>Primary database</description> <res-ref-name>jdbc/primaryDB</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>CONTAINER</res-auth> </resource-ref> Thanks!

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• How to deal with presence or not of xml namespaces using xslt.

  - by Mycol

  I have some XML/TEI documents, and i'm writing an XSLT 2.0 to extract their content. Almost all TEI documents has no namespace, but one has the default namespace (xmlns="http://www.tei-c.org/ns/1.0"). So all documents has the same aspect, with unqulified tags like <TEI> or <teiHeader>, but if I try to extract the content, all works with "non-namespaced-documents", but nothing (of course) is extracted from the namespaced-document. So i used the attribute xpath-default-namespace="http://www.tei-c.org/ns/1.0" and now (of course) the only document working is the namespaced one. I can't edit documents at all, so what I'm asking is if there's a way to change dynamically the xpath-default-namespace in order to make work xpaths like //teiHeader both with namespaced and non-namespaced documents

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• Creating a list of integers in XML for android.

  - by Leif Andersen

  I would like to create a list of Integers in the /res folder of an android project. However, I want those integers to point resources in /res/raw. So for example, I would like something like this: <?xml version="1.0" encoding="utf-8"?> <resources> <integer-array name="built_in_sounds"> <item>@raw/sound</item> </integer-array> </resources> But id doesn't look like I can do that, is there any way to do this? Or should I just create the list in a java class? Thank you

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• how to specify in xml schema that either one of two fields must be present?

  - by matti

  i want to specify that either fieldname or freetext is always present in xml files that apply to xsd. is there a way to define it? <xs:complexType name="tSome"> <xs:sequence> <!-- either of 2 below have 2 be present. --> <xs:element name="fieldname" type="xs:string" minOccurs="0" /> <xs:element name="freetext" type="xs:string" minOccurs="0" /> <xs:element name="dbtablename" type="xs:string" minOccurs="0" /> </xs:sequence> </xs:complexType> thanks & best regards: Matti

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• A reasonable way to add attributes to an xml root element.

  - by DrLazer

  The function "WriteStartElement" does not return anything. I find this a little bizzare. So up until now I have been doing it like this. XmlDocument xmlDoc = new XmlDocument(); XmlTextWriter xmlWriter = new XmlTextWriter(m_targetFilePath, System.Text.Encoding.UTF8); xmlWriter.Formatting = Formatting.Indented; xmlWriter.WriteProcessingInstruction("xml", "version='1.0' encoding='UTF-8'"); xmlWriter.WriteStartElement("client"); xmlWriter.Close(); xmlDoc.Load(m_targetFilePath); XmlElement root = xmlDoc.DocumentElement; Saving the doc, then reloading it to get hold of the start element so i can write attributes to it. Does anybody know the correct way of doing this because I'm pretty sure what I'm doing isn't right. I tried to use xmlWriter.AppendChild() but it doesnt seem to write out anything. :(

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• How to access exception/stacktrace in Velocity template resolved by web.xml's error-page?

  - by kermit

  I would like to print the cause of the HTTP Error 500 on my Velocity template but am having difficulty figuring out how this can be done. My web.xml is configured with: <error-page> <error-code>500</error-code> <location>/error/500.vm</location> </error-page> My 500.vm page is resolving as expected but how do I access the exception which resulted in this error page? Thanks~

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• How to efficiently replace characters in XML document in Java?

  - by Pregzt

  I'm looking for a neat and efficient way to replace characters in XML document. There is a replacement table defined for almost 12.000 UTF-8 characters, most of them are to be replaced by single characters, but some must be replaced by two or even three characters (e.g. Greek theta should become TH). The documents can be bulky (100MB+). How to do it in Java? I came up with the idea of using XSLT, but I'm not too sure if this is the best option.

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• LINQ-to-XML to DataGridView: Cannot edit fields -- How to fix?

  - by Pretzel

  I am currently doing LINQ-to-XML and populating a DataGridView with my query just fine. The trouble I am running into is that once loaded into the DataGridView, the values appear to be Un-editable (ReadOnly). Here's my code: var barcodes = (from src in xmldoc.Descendants("Container") where src.Descendants().Count() > 0 select new { Id = (string)src.Element("Id"), Barcode = (string)src.Element("Barcode"), Quantity = float.Parse((string)src.Element("Quantity").Attribute("value")) }).Distinct(); dataGridView1.DataSource = barcodes.ToList(); I read somewhere that the "DataGridView will be in ReadOnly mode when you use Anonymous types." But I couldn't find an explanation why or exactly what to do about it. Any ideas?

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• In Log4Net XML configuration is Priority the same thing as Level?

  - by Michael Levy

  I inherited some code that uses the priority element under the root in its xml configuraiton. This is just like the example at http://iserialized.com/log4net-for-noobs/ which shows: <root> <priority value="ALL" /> <appender-ref ref="LogFileAppender" /> <appender-ref ref="ConsoleAppender"/> </root> However, the log4net configuration examples at http://logging.apache.org/log4net/release/manual/configuration.html always show it using the level element: <root> <level value="DEBUG" /> <appender-ref ref="A1" /> </root> In this type of configuration is <priority> the same as <level> ? Can someone point me to somewhere in the docs where this is explained?

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• XSL: Parsing XML to HTML - How do I use value-of an element data as an html attribute?

  - by AtomR

  <input src="LOGO.JPG" type="image" name="imagem"> I have an xml element that contains the image path that needs to be displayed in HTML after the parse. <xsl:value-of select="image"/> returns the string that is stored in the image element but how can I use it to make that string be the src atribute value in an html tag? I tried <input src="<xsl:value-of select="image"/>" type="image" name="imagem"> but obviously that doesn't work so how can it be done? I hope I was clear in my question. Please help!

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• What are the advantages to use StringBuilder versus XmlDocument or related to create XML documetns?

  - by Rob

  This might be a bit of a code smell, but I have seen it is some production code, namely the use of StringBuilder as opposed to XmlDocument when creating XML documents. In some cases these are write once operations (e.g. create the document and save it to disk) where as others are passing the built string to an XmlDocument to preform an XslTransform to a document that is returned to the client. So obvious question: is there merit to doing things this way, is it something that should be done on a case-by-case basis, or is this the wrong way of doing things?

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• XML multiline comments in C# - what am I doing wrong?

  - by Dave

  According to this article, it's possible to get multiline XML comments -- instead of using ///, use /** */. This is my interpretation of what multiline comments are, and what I want to have happen: /** * <summary> * this comment is on line 1 in the tooltip * this comment is on line 2 in the tooltip * </summary> */ However, when I use this form, the tooltip that pops up when I hover over my class name in my code is single-line, i.e. it looks exactly as if I had written my comment like this: /// <summary> /// this comment is on line 1 in the tooltip /// this comment is on line 2 in the tooltip /// </summary> Is this behavior actually possible still in VS2008?

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• Get variable value from XML to JavaScript. Pure way.

  - by kalininew

  I have XML: <point> ... <longitude>34.123123</longitude> </point> <point> ... <longitude>11.12534534</longitude> </point> <point> ... <longitude>32.567653</longitude> </point> <point> ... <longitude>33.345345</longitude> </point> ... Task: get values of <longitude> in javascript (in variable). Which is purest way? It is possible to do it without XSLT (without making dummy elements)?

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• A reasonable way to add attributes to an xml root element in C#.

  - by DrLazer

  The function "WriteStartElement" does not return anything. I find this a little bizzare. So up until now I have been doing it like this. XmlDocument xmlDoc = new XmlDocument(); XmlTextWriter xmlWriter = new XmlTextWriter(m_targetFilePath, System.Text.Encoding.UTF8); xmlWriter.Formatting = Formatting.Indented; xmlWriter.WriteProcessingInstruction("xml", "version='1.0' encoding='UTF-8'"); xmlWriter.WriteStartElement("client"); xmlWriter.Close(); xmlDoc.Load(m_targetFilePath); XmlElement root = xmlDoc.DocumentElement; Saving the doc, then reloading it to get hold of the start element so i can write attributes to it. Does anybody know the correct way of doing this because I'm pretty sure what I'm doing isn't right. I tried to use xmlWriter.AppendChild() but it doesnt seem to write out anything. :(

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• building objects from xml file at runtime and intializing, in one pass?

  - by KaluSingh Gabbar

  I have to parse the XML file and build objects representation based on that, now once I get all these data I create entries in various database for these data objects. I have to do second pass over that for value as in the first pass all I could do is build the assets in various databases. and in second pass I get the values for all the data and put it in the database. I have a feeling that this can be done in a single pass but I just want to see what are your opinions. As I am just a student who started with professional work, experienced ppl please help. Can someone who have ideas or done similar work, please provide some light on the topic so that I can think over the possibility of the work and get the prototype going based on your suggestion. Thanks a lot for your precious time, I honestly appreciate it.

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• Fastest way of creating XML from parent-child table in c#?

  - by rudnev

  Assume we have some DataTable or IEnumerable with ChildID, ParentID and Title. We need to serialize it to XML like <Entity title=""> <Entity title=""></Entity> <Entity title=""></Entity> </Entity> As i found out, standard DataTable.GetXML() returns something different. I thought about initializing class tree like Entity e = new Entity(ID, Title, ParentEntityID) and then serializing it. Table is about 3000 elems. Is there faster way?

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• Is it possible to query a XML file with SQL?

  - by Monty

  Currently I'm working on a case where we don't want to change to much on a c#/wpf program, but like to add a feature. Currently we allow certain users to add sql queries to a database to retrieve customer data, hereby a custom connection string/ provider name must be specified. With this information it's possible to create the connection and obtain the data with c#. However we like to add the possibility to allow that user group to query XML files too, with a certain connection string/ provider name. I just had a look for possibities in .net to do that, but can't seem to find a decent way... Is something like this possible? (OleDb/ODBC way maybe?) Thanks in advance.

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• How to write to an XML file from the iPad OS?

  - by user345474

  I am developing an app for IPad, and I need to modify several attributes in a XML file at runtime. I found the class NSXMLDocument, http://developer.apple.com/mac/library/documentation/cocoa/reference/foundation/Classes/NSXMLDocument_Class/Reference/Reference.html But I haven't been able to import it to my project. Is this class not available for IPhone/IPad development? Is there some other approach I can consider? I read about libxml library. Is it my answer or there is a better approach?

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• can i write a schema that all XML are valid to it ?

  - by Gady

  Hi, i need to write a schema that all xml instances are valid to it. i tried: <xs:element name="Arguments"> <xs:complexType> <xs:sequence> <xs:any namespace="##any" minOccurs="0" maxOccurs="unbounded" processContents="lax" /> </xs:sequence> </xs:complexType> but it enforces a root element named Arguments. is there a way for the root to be Any ?

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• how do i grab text of multiple tags in an xml feed using one xpath expression?

  - by Incognito

  Im trying to parse an xml feed that looks something like this: <item> <title>item title</title> <link>item link</link> <description>item description</description> </item> I'm trying to find an xpath expression that will retrieve all the details of each item so that each item in the feed is contained within its own array or grouped in some way. I tried using //item/* but the tags are not grouped, although they are correctly ordered. Is there anyway of doing that? edit: [ [title1, link1, desc1], [title2, link2, desc2], [title3, link3, desc3] ]

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