Search Results

Search found 4969 results on 199 pages for 'def'.

Page 115/199 | < Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >

  • Python - output from functions?

    - by Seafoid
    Hi I have a very rudimentary question. Assume I call a function, e.g., def foo(): x = 'hello world' How do I get the function to return x in such a way that I can use it as the input for another function or use the variable within the body of a program? When I use return and call the variable within another functions I get a NameError. Thanks, S :-)

    Read the article

  • Overriding initial value in ModelForm

    - by schneck
    Hi, in my Django (1.2) project, I want to prepopulate a field in a modelform, but my new value is ignored. This is the snippet: class ArtefactForm(ModelForm): material = CharField(widget=AutoCompleteWidget('material', force_selection=False)) def __init__(self, *args, **kwargs): super(ArtefactForm, self).__init__(*args, **kwargs) self.fields['material'].initial = 'Test' I also tried with self.base_fields, but no effect: there is always the database-value displaying in the form. Any ideas?

    Read the article

  • how to write or create (when no exist) a file using python and Google AppEngine

    - by zjm1126
    this is my code: f = open('text/a.log', 'wb') f.write('hahaha') f.close() and it is not create a new file when not exist how to do this , thanks updated class MyThread(threading.Thread): def run(self): f = open('a.log', 'w') f.write('hahaha') f.close() error is : Traceback (most recent call last): File "D:\Python25\lib\threading.py", line 486, in __bootstrap_inner self.run() File "D:\zjm_code\helloworld\views.py", line 15, in run f = open('a.log', 'w') File "d:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1188, in __init__ raise IOError('invalid mode: %s' % mode) IOError: invalid mode: w

    Read the article

  • python: how/where to put a simple libary installed in a well-known-place on my computer

    - by Jason S
    I need to put a python script somewhere on my computer so that in another file I can use it. How do I do this and where do I put it? And where in the python documentation do I learn how to do this? I'm a beginner + don't use python much. library file: MyLib.py put in a well-known place def myfunc(): .... other file SourceFile.py located elsewhere, doesn't need to know where MyLib.py is: something = MyLib.myfunc()

    Read the article

  • Specifics of List Membership

    - by phasetwenty
    How does Python (2.6.4, specifically) determine list membership in general? I've run some tests to see what it does: def main(): obj = fancy_obj(arg='C:\\') needle = (50, obj) haystack = [(50, fancy_obj(arg='C:\\')), (1, obj,), needle] print (1, fancy_obj(arg='C:\\'),) in haystack print needle in haystack if __name__ == '__main__': main() Which yields: False True This tells me that Python is probably checking the object references, which makes sense. Is there something more definitive I can look at?

    Read the article

  • reading input file from server and displaying output on client side

    - by tazim
    Hi, I have to read a file from server side . Obtained its contents stored it in a list and sent it to template Now, My question is how to access this list so as to display the contents of files line by line . I am using ajax and jquery to obtain the data on client side def showfiledata(request): f = open("/home/tazim/webexample/test.txt") list = f.readlines() return_dict = {'list':list} json = simplejson.dumps(list) return HttpResponse(json,mimetype="application/json")

    Read the article

  • Python: concatenate generator and item

    - by TarGz
    I have a generator (numbers) and a value (number). I would like to iterate over these as if they were one sequence: i for i in tuple(my_generator) + (my_value,) The problem is, as far as I undestand, this creates 3 tuples only to immediately discard them and also copies items in "my_generator" once. Better approch would be: def con(seq, item): for i in seq: yield seq yield item i for i in con(my_generator, my_value) But I was wondering whether it is possible to do it without that function definition

    Read the article

  • Best way to write an image to a Django HttpResponse()

    - by k-g-f
    I need to serve images securely to validated users only (i.e. they can't be served as static files). I currently have the following Python view in my Django project, but it seems inefficient. Any ideas for a better way? def secureImage(request,imagePath): response = HttpResponse(mimetype="image/png") img = Image.open(imagePath) img.save(response,'png') return response (Image is imported from PIL.)

    Read the article

  • Passing values into regex match function

    - by Tim
    In python (it's a Django filter), I'm doing this: lReturn = re.sub(r'\[usecase:([ \w]+)]', r'EXTEND WITH <a href="/usecase/%s/\1/">\1</a>' % pCurrentProjectName, lReturn) I'd like to use a function instead of a string (so I can check that the usercase is a valid name), so it would change to this: def _match_function(matchobj): lMatch = matchobj.group(1) return "EXTEND WITH <a href='/usecase/%s/%s/'>%s</a>" % (pCurrentProjectName, lMatch, lMatch) lReturn = re.sub(r'\[usecase:([ \w]+)]', _match_function, lReturn) How do I get pCurrentProjectName into the _match_function() function?

    Read the article

  • General question about Ruby Eigenclass/Singleton

    - by Dex
    module MyModule def my_method; 'hello'; end end class MyClass class << self include MyModule end end MyClass.my_method # => "hello I'm unsure why "include MyModule" needs to be in the eigenclass in order to be called using just MyClass. Why can't I go: X = MyClass.new X.my_method How is this type of pattern useful if I can't call it from an instance?

    Read the article

  • Routing error when trying to use same view for update and create flows (Rails 3)

    - by Jamis Charles
    My overall use case: I have a Listing model that has many images. The Listing detail page lists all the fields that can be updated inline (through ajax). I want to be able to use the same view for both update listing and create new listing. My listing controller looks as follows: def detail @listing = Listing.find(params[:id]) @image = Image.new #should this link somewhere else? respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end def create # create a new listing and save it immediately. Assign it to guest, with a status of "draft" @listing = Listing.new(:price_id => 1) # Default price id # save it to db # TODO add validation that it has to have a price ID, on record creation. So the view doesn't break. @listing.save @image = Image.new # redirect_to "/listings/detail/@listing.id" #this didn't work respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end The PROBLEM I'm using a partial that shows the same form for the create view and the detail view. This works perfectly except for one thing: When I pull up http://0.0.0.0:3000/listings/detail/7, it works perfectly. When I pull up http://0.0.0.0:3000/listings/new, I get the following error: Showing /Applications/MAMP/htdocs/rails_testing/feedbackd/app/views/listings/_edit_form.html.erb where line #100 raised: No route matches {:action="show", :controller="images"} Extracted source (around line #100): 97: <!-- Form for new images --> 98: <div class="span-20 append-bottom"> 99: <!-- <%# form_for :image, @image, :url => image_path, :html => { :multipart => true } do |f| %> --> 100: <%= form_for @image, :url => image_path, :html => { :multipart => true } do |f| %> 101: <%= f.text_field :description %><br /> 102: <%= f.file_field :photo %> 103: <%= submit_tag "Upload" %> What I think the issue is: When I upload a new image (I'm using Paperclip), it requires the listing_id to create the image record. Since the listing_id isn't passed in with listings/new it can't find the listing_id. How can I pass in the id? Via a redirect? What's the best way to solve this? Thank you.

    Read the article

  • How to pickle and unpickle objects with self-references and from a class with slots?

    - by EOL
    Is it possible to pickle an object from a class with slots, when this object references itself through one of its attributes? Here is a simple example: import weakref import pickle class my_class(object): __slots__ = ('an_int', 'ref_to_self', '__weakref__') def __init__(self): self.an_int = 42 self.ref_to_self = weakref.WeakKeyDictionary({self: 1}) # __getstate__ and __setstate__ not defined: how should this be done? if __name__ == '__main__': obj = my_class() # How to make the following work? obj_pickled = pickle.dumps(obj) obj_unpickled = pickle.loads(obj_pickled) # Self-references should be kept: print "OK?", obj_unpickled == obj_unpickled.ref_to_self.keys()[0]

    Read the article

  • There is a JavaScript error in my rails application!

    - by Small Wolf
    As the title said, I got a problem! i encountered the "RJS Error:[object error]",the code in my application is page << "#{hidden_print("#{url_for(:controller => 'tables', :action => 'dispatch', :id => id, :pop => true, :print =>true)}")} " the method hidden_print is def hidden_print(url) "window.parent.headFrame.document.all.iframe_helper.src = '#{url}';" end

    Read the article

  • Function pointers in javascript using django

    - by Hulk
    Is this a valid function pointer code below, In views , def change(request): dict={} function_ptr="create()" dict.update({'function_ptr' : function_ptr}) return render_to_response('mpjt/create.html',context_instance=RequestContext(request,{'dict': dict})) In create.html $(document).ready(function() { var a = '{{dict.function_ptr}}' func_ptr(a); function create() { alert('got respponse'); } }); Thanks..

    Read the article

  • Ignore first line on csv parse Rails

    - by Jack
    Hi, I am using the code from this tutorial to parse a CSV file and add the contents to a database table. How would I ignore the first line of the CSV file? The controller code is below: def csv_import @parsed_file=CSV::Reader.parse(params[:dump][:file]) n = 0 @parsed_file.each do |row| s = Student.new s.name = row[0] s.cid = row[1] s.year_id = find_year_id_from_year_title(row[2]) if s.save n = n+1 GC.start if n%50==0 end flash.now[:message] = "CSV Import Successful, #{n} new students added to the database." end redirect_to(students_url) end

    Read the article

  • Catch clearly defined exception from sub.submodule in python

    - by mynthon
    I have 3 files. xxx which imports xxx2 and xxx2 imports xxx3 which one raises OppsError exception. xxx3.py: class OppsError(Exception):pass def go(): raise OppsError() xxx2.py: import xxx3 xxx3.go() xxx.py: try: import xxx2 except xxx3.OppsError: print 'ops' When i run xxx.py i get error NameError: name 'xxx3' is not defined. Is importing xxx3 inside xxx only way to catch OppsError?

    Read the article

  • How to print source code lines in python logger

    - by anon
    Is there some relatively simple way to programmatically include source code lines to python logger report. For example... import logging def main(): something_is_not_right = True logging.basicConfig(level=logging.DEBUG, format=('%(filename)s: ' '%(levelname)s: ' '%(funcName)s(): ' '%(lineno)d:\t' '%(message)s') ) if something_is_not_right == True: logging.debug('some way to get previous line of source code here?') So that output would look like this. example.py: DEBUG: main(): 14: if something_is_not_right == True:

    Read the article

  • RoR custom routing/Method/View problem all methods come back as undefined

    - by Jeff
    I am playing with custom view and routes. I think that I have everything right but obviously not. Essentially I tried to copy the show method and show.html.erb but for some reason it will not work. My controller class fatherController < ApplicationController def show @father = Father.find(params[:id]) respond_to do |format| format.html # show.html.erb format.xml { render :xml => @father } end end def ofmine @father = Father.find(params[:id]) respond_to do |format| format.html # show.html.erb format.xml { render :xml => @father } end end end My routes.rb Parent::Application.routes.draw do resources :fathers do resources :kids end match 'hospitals/:id/ofmine' => 'father#show2' end when I go to 127.0.0.1:/father/1 it works fine but when I try to go to 127.0.0.1:/father/1/ofmine it gives the following error. It doesn't matter what the variable/method that is called; it occurs at the first one to be displayed. Both show.html.erb and show2.html.erb are the exact same files My Error from webserver commandline > Processing by fathersController#show2 > as HTML Parameters: {"id"=>"1"} > Rendered fathers/show2.html.erb within > layouts/application (31.6ms) Completed > in 37ms > > ActionView::Template::Error (undefined > method `name' for nil:NilClass): > 4: <td>Name</td><td></td> > 5: </tr> > 6: <tr> > 7: <td><%= @father.name %></td><td></td> > 8: </tr> > 9: <tr> > 10: <td>City</td><td>State</td> app/views/fathers/show2.html.erb:7:in > `_app_views_fatherss_show__html_erb___709193087__616989688_0' Error as displayed on actual page NoMethodError in Fathers#show2 Showing /var/ruby/chs/app/views/fathers/show2.html.erb where line #7 raised: undefined method `name' for nil:NilClass Extracted source (around line #7): 4: Name 5: 6: 7: <%= @father.name % 8: 9: 10: CityState If anyone could tell me what in the world I am doing wrong I would appreciate it greatly.

    Read the article

  • Do really need a count lock on Multi threads with one CPU core?

    - by MrROY
    If i have some code looks like this(Please ignore the syntax, i want to understand it without a specified language): count = 0 def countDown(): count += 1 if __name__ == '__main__': thread1(countDown) thread2(countDown) thread3(countDown) Here i have a CPU with only one core, do i really need a lock to the variable count in case of it could be over-written by other threads. I don't know, but if the language cares a lot, please explain it under Java?C and Python, So many thanks.

    Read the article

  • next element is (current+1) or 0 (ruby)

    - by Radek
    I have an interval let's say (0..3) where next element is +1 unless the last. Then the next is 0. I solved it by the code below. Just wondering if there is anything else outhere :-) def next(max,current) if current+1 == max return 0 else return current+1 end end

    Read the article

< Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >