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  • ASP.NET MVC 2 Client Side Validation doesn't work as advertised in VS2010

    - by Daniel Crenna
    In VS2010 and ASP.NET MVC 2, it seems that client-side validation (JQuery Futures or the stock option) doesn't quite work as advertised. I'm noticing that "tabbing off" a validated element will not invoke the client-side validation as promised. For a required field, you have to tab into the element, enter something, then remove it completely, in order to trigger the required validation. That's not really what I'm after here, and I'm hoping it's just a configuration issue on my side. How do I get the validation effects from previous versions so that a previous value isn't necessary (without having to modify the client-side scripts if possible)?

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  • Controls on main window using Visual C++ designer?

    - by PatrickBateman
    Is is possible to draw controls using Visual C++ designer on the main window, in the same way you can design dialogs? I'd preferably like to be able to design the main window controls this way without using MFC, rather than creating them on WM_CREATE. EDIT: I don't want a dialog-based app, just to be able to design the main window graphically similar to what can be done using Windows Forms Designer in .NET?

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  • a potentially dangerous request.form value was detected but validateinput(false) not working

    - by tonybolding
    I have installed VS2010 and MVC2 and testing a simple form using tinyMCE. When I post the contents of the textarea in tinyMCE I get the dreaded YSD and the message "a potentially dangerous....." No problem I thought - seen this before so I put the ValidateInput(false) on the controller but no joy - I still get the error. page code in edit.aspx is: <% using (Html.BeginForm()){ % <!-- Gets replaced with TinyMCE, remember HTML in a textarea should be encoded --> <textarea id="elm1" name="mceText" rows="15" cols="80" style="width: 80%"> &lt;p&gt; This is some example text that you can edit inside the &lt;strong&gt;TinyMCE editor&lt;/strong&gt;. </textarea> <br /> <input type="submit" name="save" value="Submit" /> <input type="reset" name="reset" value="Reset" /> <%} % and Controller action is: [AcceptVerbs(HttpVerbs.Post)] [ValidateInput(false)] public ActionResult Edit(string mceText) { return View(); } Any thoughts - (I know the code is not complete) been trying this for hours but everyone just says to use ValidateInput(false)

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  • HTML columns or rows for form layout?

    - by Valera
    I'm building a bunch of forms that have labels and corresponding fields (input element or more complex elements). Labels go on the left, fields go on the right. Labels in a given form should all be a specific width so that the fields all line up vertically. There are two ways (maybe more?) of achieving this: Rows: Float each label and each field left. Put each label and field in a field-row div/container. Set label width to some specific number. With this approach labels on different forms will have different widths, because they'll depend on the width of the text in the longest label. Columns: Put all labels in one div/container that's floated left, put all fields in another floated left container with padding-left set. This way the labels and even the label container don't need to have their widths set, because the column layout and the padding-left will uniformly take care of vertically lining up all the fields. So approach #2 seems to be easier to implement (because the widths don't need to be set all the time), but I think it's also less object oriented, because a label and a field that goes with that label are not grouped together, as they are in approach #1. Also, if building forms dynamically, approach #2 doesn't work as well with functions like addRow(label, field), since it would have to know about the label and the field containers, instead of just creating/adding one field-row element. Which approach do you think is better? Is there another, better approach than these two?

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  • zend form check record no exists in database

    - by Yafa Su
    I have a form that check if email exists in the database within 2 tables. I'm using Zend_Validate_Db_NoRecordExists for both validate, but it only check the second one. Any idea why it's not working? class Application_Form_ReferUser extends Zend_Form { public $email, $freeDownload, $buyNow; public function init() { $this->setName('referUser'); $EmailExists = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'referrals', 'field' => 'email' ) ); $EmailExists2 = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'users', 'field' => 'email' ) ); $EmailExists->setMessage('This e-mail is already taken'); $EmailExists2->setMessage('This e-mail is already taken'); $this->email = $this->createElement('text', 'email') ->setLabel('Email') ->addValidator($EmailExists) ->addValidator($EmailExists2) ->addValidator('EmailAddress') ->setRequired(true); $this->freeDownload = $this->createElement('button', 'btn_free_download') ->setLabel('Free Download') ->setAttrib('type', 'submit'); $this->buyNow = $this->createElement('button', 'btn_buy_now') ->setLabel('Buy Now') ->setAttrib('type', 'submit'); $this->addElements(array($this->email, $this->freeDownload, $this->buyNow)); $elementDecorators = array( 'ViewHelper' ); $this->setElementDecorators($elementDecorators); } }

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  • Change post form data function into curl

    - by QLiu
    Hello Guys, In the old way in our website, when users clicks “logout” button. It runs a post form function; which will pass parameters (logout, sn) to external sites to execute “logout” function. Like: I do not want the users jump to the external site, therefore, i use curl to post data. (because we are in different domain, i guess Ajax request doesnot work ) Post the same data to execute logout function in external site. // create cURL resource $URL = "http://bswi.development.intra.local/"; //Initl curl $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $URL); // Load in the destination URL curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_BASIC); //Normal HTTP request, not SSL curl_setopt($ch, CURLOPT_POSTFIELDS, "logout=1"); // receive server response ... curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_exec ($ch); echo $content; curl_close ($ch); Do u think i am going in the right direction?

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  • PHP & form validation

    - by user887515
    I have a form that I'm submitting via ajax, and I want to return a message of the list of fields that were empty. I've got that all done and dusted, but it just seems really long winded on the PHP side of things. How can I do the below in a less convoluted way? <?php if(empty($_POST["emailaddress"])){ $error = 'true'; $validation_msg = 'Country missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["password"])){ $error = 'true'; $validation_msg = 'Country missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["firstname"])){ $error = 'true'; $validation_msg = 'First name missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["lastname"])){ $error = 'true'; $validation_msg = 'Last name missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if($error){ header('HTTP/1.1 500 Internal Server Error'); header('Content-Type: application/json'); die($error_msg); } ?>

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  • Generating a zend form with dynamic data?

    - by meder
    I need to access my session and based on the session property I need to grab stuff from the database to use as options in my dropdown. $_SESSION is: [sess_name] => Array( [properties] => Array( 1=> Hotel A, 2=> Hotel B ), [selected] => 1 ) I need to grab Hotel A from selected, and then access all accounts under Hotel A from the database: id title hotel_id ------------------------------ 1 Hotel A Twitter Account 1 2 Hotel B Facebook Account 2 3 Hotel A Facebook Account 1 I need ids 1 and 3 because my hotel_id is 1 in the context of: $this->addElement( 'select', 'account', array( 'multioptions' => $NEED_IT_HERE )); Here's my query / session grabbing code: $cs = new Zend_Session_Namespace( SESS_NAME ); $model = new Model_DbTable_Social; $s = " SELECT social_accounts.* FROM social_accounts LEFT JOIN social_media_outlets ON social_media_outlets.id = social_accounts.property WHERE social_accounts.property=".(int)$cs->selectedclient; I have this code in my form page, but I need to move it into my model now.

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  • How do I clear MVC client side validation errors when a cancel button is clicked when a user has inv

    - by Sci-fi
    I have a partial view that is rendered within a main view. The partial view takes advantage of System.ComponentModel.DataAnnotations and Html.EnableClientValidation(). A link is clicked, and div containing the partial view is displayed within a JQuery.Dialog(). I then click the save button without entering any text in my validated input field. This causes the client side validation to fire as expected, and display the '*required' message beside the invalid field. When the cancel button is clicked, I want to reset the client side MVC validation back to it's default state and remove any messages, ready for when the user opens the dialog again. Is there a recommended way of doing this?

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  • Creating dynamic icons based on data entered into database from django forms

    - by John Hoke
    So I'm using Django to create a projects page with multiple forms for each project. Let's call them form 1, 2, 3, and 4. Once you create a project you can fill out any of these forms. I want to create "buttons" or links for each one of the forms that would show up on the main page. Now this is the part I need help with: Step 1. I want it so that if you click on a button for a form (say form 1) and none exists for that project yet a pop up would come up saying "This form does not exist yet, are you sure you want to create one?". And if you'd answer yes you would be directed to the form page. Step 2. But if that form does exist, I don't want any pop up to open and I want the link to take the user directly to that page. Step 3. My next problem is this. These forms are in order, so if you didn't create form 1 but created form 2, I don't want to give the user access to form 1. So in this scenario, if you click on form 1 I want a pop up to open and say "This form can no longer be created", and the link wouldn't function anymore. Basically the button will have 3 function. First it should look at the database and if data for that specific form exists it should do "Step 2", if data for that form and the proceeding forms don't exist it should do "Step 1", and if data for that form doesn't exist but data for proceeding form's does exist is should do "Step 3". Is this possible? Please help as I need to find a solution to this soon. Any help would be highly appreciated. Thank you

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  • Send form with jQuery using keypress()

    - by kexxcream
    What I have so far: I have a form in PHP that contain the following: <input type="submit" id="0" name="0" value="This button"> <input type="submit" id="1" name="1" value="This button"> <input type="hidden" id="response" name="response" value="150"> The problem: I would like to send the response value together with either name=1 or name=0, depending on which button the user submit. However, this should be done using the keyboard letters A and S. If a user press the letter A then the value 0 should be submitted, and if S is pressed then the value 1 should be sent. The jQuery code: $(document).ready(function() { // listens for any navigation keypress activity $(document).keypress(function(e) { switch(e.which) { // user presses the "a" case 97: submitViaKeypress("0"); break; // user presses the "s" key case 115: submitViaKeypress("1"); break; } }); }); // shows a given element and hides all others function submitViaKeypress(element_id) { var response = $('#response').attr('value'); $.ajax({ type: "POST", url: "initiate.php", data: "response=" + response + "&" + element_id + "=" + element_id }); } Goal: That "initiate.php receive two POST variables (response and either 0 or 1).

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  • Get Form Input via Ajax

    - by user3651491
    I have a jqgrid plugin which I call via Ajax. I have index.php and a getGridData.php. How will I pass form input in getGridData.php via ajax and use it in getGridData.php? I tried serialize but I can't pass or access it on getGridData.php. I need it as parameters for mysql. Here's my code. <script language="javascript" type="text/javascript"> function jgGrid() { $(document).ready(function () { $("#grid").jqGrid({ url: "inc/Controller/getGridData.php"+$("#thisForm").serialize(), data : formData, datatype: "json", mtype: "POST", colNames: ["SiteID", "TerminalID", "TransactionType", "Amount", "ServiceStatus"], colModel: [ { name: "SiteID"}, { name: "TerminalID"}, { name: "TransactionType"}, { name: "Amount"}, { name: "ServiceStatus"}, ], pager: "#pager", rowNum: 10, rowList: [10,20], sortname: "SiteID", sortorder: "asc", height: 'auto', viewrecords: true, gridview: true, caption: "" }); }); } </script> getGridData.php include('../Model/Queries.php'); $cardnumber = $_POST['cardnumber']; $transact_type = $_POST['transact_type']; $fromdate = $_POST['fromdate']; $todate = $_POST['todate']; $loyalty = new Queries(); $get_mid = $loyalty->loyaltyConn($cardnumber); $somedata = json_encode($loyalty->nposConn($get_mid, $transact_type, $fromdate, $todate)); echo $somedata;

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  • Picture Box and Form Transparency

    - by Qu1nncunxIV
    Maybe I am missing something, but is it the case that when you set a pictureboxes background to transparent, all it really does is set it to the same color as the forms background? What I am trying to do is draw an animation for the benefit of this, a bouncing ball - which I paint on the form, then overlay that with a picture frame. End result should be a bouncing ball in a picture frame, I should mention that the picture frame does not have a straight edge, so it is not possible to arrange 4 picture boxes in a frame. The ball needs to vanish behind the frame to change color and then magically bounce back out. I have tried: 1.Setting the picture box background to pink and then key out the same pink, this basically cuts away everything, including that which is behind the picture box 2.Setting the picture box to transparent, this just displays the picture box background as the same color as the forms background. 3.I have tried painting the image in a rectangle, this had the same effect as drawing it in a picture box. I am not sure what I am doing wrong, I am wondering if there is any other ways I could try or if someone has made a custom control or library that supports transparency?

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  • form validation with jquery and livevalidation

    - by ImpY
    I'm trying to do some form validation with livevaldation & jquery. I've a formular with an input field like that: <div id="prenameDiv" class="control-group"> `<input id="prename" name="prename" class="input-large" placeholder="Max" >` </div> So if there's an error on validation 'livevalidaton' adds the class 'LV_invalid_field' to the input - it looks like that: <div id="prenameDiv" class="control-group"> <input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" > </div> That's ok, but now I'll add another class 'error' to the div 'prenameDiv' when the DOM changes that it looks like that: <div id="prenameDiv" class="control-group error"> `<input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" ` </div> I tried it that way: if ($("#prenameDiv").bind("DOMSubtreeModified")){ `if ($("#prename").hasClass("LV_invalid_field")) {` $("#prenameDiv").addClass("error"); } } But nothing changes? Do you have some ideas?

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  • saving value selected in a list when submit button is cliked

    - by kawtousse
    Hi everyone, In my JSP I have a dropdownlist and a submit button when clicking the submit button I loose the value already selected in my list. I am using the jstl because i need to construct other table corresponding the value selected in my list.For that I must call a submit button but the problem; it reset the value selected I want to know if there is a way to save the value selected in my list even I click a submit button. I work with JSP and eclipse environment. Think you for your help.

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  • Unwanted Retriggering of Textbox Events

    - by user348917
    This is one of those "seems obvious" as how to do, but came across interesting side effect in implementing. I'm trying to keep two text boxes syncronized when information is updated. In this example, I will be using txtStartDate and txtEndDate. If the txtStartDate is changed, then the txtEndDate should should be updated. Likewise, if the txtEndDate changes, I want the txtSartDate to be updated. The side effect I'm comming across is that when I set them up under the TextChanged event for both, the events seem to retrigger against each other indefinately (endless loop?). Am I using the wrong event? Is this a task for a delegate?

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  • PHP form validation function

    - by Barbs
    I am currently writing some PHP form validation (I have already validated clientside) and have some repetitive code that I think would work well in a nice little PHP function. However I have having trouble getting it to work. I'm sure it's just a matter of syntax but I just can't nail it down. Any help appreciated. //Validate phone number field to ensure 8 digits, no spaces. if(0 === preg_match("/^[0-9]{8}$/",$_POST['Phone']) { $errors['Phone'] = "Incorrect format for 'Phone'"; } if(!$errors) { //Do some stuff here.... } I found that I was writing the validation code a lot and I could save some time and some lines of code by creating a function. //Validate Function function validate($regex,$index,$message) { if(0 === preg_match($regex,$_POST[$index],$message) { $errors[$index] = $message; } And call it like so.... validate("/^[0-9]{8}$/","Phone","Incorrect format for Phone"); Can anyone see why this wouldn't work? Note I have disabled the client side validation while I work on this to try to trigger the error, so the value I am sending for 'Phone' is invalid.

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  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

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  • Cannot translate date formats from rails form to mysql db

    - by Steve
    I have a simple search form in rails 3 that has two date fields. I'm having a problem getting these dates into my mysql db. I've tried using the american_date gem, specifying date formats in my initializers, in the config/locales/en.yml file, and directly on the date on the date fields themselves. Currently, I'm setting the rails-approved date format in the view - <%= f.text_field :depart_date, :value=> Date.today.strftime('%Y-%m-%d') %> The dateformat in my DB is also YYYY-mm-dd, so things should be going smoothly. The console tells me that the two date fields are both class = "Date" I think I've found the disconnect. From the logs - Started POST "/searches" for 127.0.0.1 at 2013-10-30 17:43:26 -0400 Processing by SearchesController#create as HTML Parameters: {"utf8"=>"v","search"=>{"depart_date"=>"2013-10-30", "return_date"=>"2013-11-09"} ?[1m?[35m (0.0ms)?[0m BEGIN ?[1m?[36mSQL (0.0ms)?[0m ?[1mINSERT INTO `searches` (`depart_date`,`return_date`) VALUES ('2013-30-10','2013-09-11')?[0m ?[1m?[35m (2.0ms)?[0m COMMIT Note that the month and day values are switched in the insert statement. How can I prevent this from happenening?

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  • Configure Forms based authentication in SharePoint 2010

    - by sreejukg
      Configuring form authentication is a straight forward task in SharePoint. Mostly public facing websites built on SharePoint requires form based authentication. Recently, one of the WCM implementation where I was included in the project team required registration system. Any internet user can register to the site and the site offering them some membership specific functionalities once the user logged in. Since the registration open for all, I don’t want to store all those users in Active Directory. I have decided to use Forms based authentication for those users. This is a typical scenario of form authentication in SharePoint implementation. To implement form authentication you require the following A data store where you are storing the users – technically this can be active directory, SQL server database, LDAP etc. Form authentication will redirect the user to the login page, if the request is not authenticated. In the login page, there will be controls that validate the user inputs against the configured data store. In this article, I am going to use SQL server database with ASP.Net membership API’s to configure form based authentication in SharePoint 2010. This article assumes that you have SQL membership database available. I already configured the membership and roles database using aspnet_regsql command. If you want to know how to configure membership database using aspnet_regsql command, read the below blog post. http://weblogs.asp.net/sreejukg/archive/2011/06/16/usage-of-aspnet-regsql-exe-in-asp-net-4.aspx The snapshot of the database after implementing membership and role manager is as follows. I have used the database name “aspnetdb_claim”. Make sure you have created the database and make sure your database contains tables and stored procedures for membership. Create a web application with claims based authentication. This article assumes you already created a web application using claims based authentication. If you want to enable forms based authentication in SharePoint 2010, you must enable claims based authentication. Read this post for creating a web application using claims based authentication. http://weblogs.asp.net/sreejukg/archive/2011/06/15/create-a-web-application-in-sharepoint-2010-using-claims-based-authentication.aspx  You make sure, you have selected enable form authentication, and then selected Membership provider and Role manager name. To make sure you are done with the configuration, navigate to central administration website, from central administration, navigate to the Web Applications page, select the web application and click on icon, you will see the authentication providers for the current web application. Go to the section Claims authentication types, and make sure you have enabled forms based authentication. As mentioned in the snapshot, I have named the membership provider as SPFormAuthMembership and role manager as SPFormAuthRoleManager. You can choose your own names as you need. Modify the configuration files(Web.Config) to enable form authentication There are three applications that needs to be configured to support form authentication. The following are those applications. Central Administration If you want to assign permissions to web application using the credentials from form authentication, you need to update Central Administration configuration. If you do not want to access form authentication credentials from Central Administration, just leave this step.  STS service application Security Token service is the service application that issues security token when users are logging in. You need to modify the configuration of STS application to make sure users are able to login. To find the STS application, follow the following steps Go to the IIS Manager Expand the sites Node, you will see SharePoint Web Services Expand SharePoint Web Services, you can see SecurityTokenServiceApplication Right click SecuritytokenServiceApplication and click explore, it will open the corresponding file system. By default, the path for STS is C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\WebServices\SecurityToken You need to modify the configuration file available in the mentioned location. The web application that needs to be enabled with form authentication. You need to modify the configuration of your web application to make sure your web application identifies users from the form authentication.   Based on the above, I am going to modify the web configuration. At end of each step, I have mentioned the expected output. I recommend you to go step by step and after each step, make sure the configuration changes are working as expected. If you do everything all together, and test your application at the end, you may face difficulties in troubleshooting the configuration errors. Modifications for Central Administration Web.Config Open the web.config for the Central administration in a text editor. I always prefer Visual Studio, for editing web.config. In most cases, the path of the web.config for the central administration website is as follows C:\inetpub\wwwroot\wss\VirtualDirectories\<port number> Make sure you keep a backup copy of the web.config, before editing it. Let me summarize what we are going to do with Central Administration web.config. First I am going to add a connection string that points to the form authentication database, that I created as mentioned in previous steps. Then I need to add a membership provider and a role manager with the corresponding connectionstring. Then I need to update the peoplepickerwildcards section to make sure the users are appearing in search results. By default there is no connection string available in the web.config of Central Administration. Add a connection string just after the configsections element. The below is the connection string I have used all over the article. <add name="FormAuthConnString" connectionString="Initial Catalog=yourdatabasename;data source=databaseservername;Integrated Security=SSPI;" /> Once you added the connection string, the web.config look similar to Now add membership provider to the code. In web.config for CA, there will be <membership> tag, search for it. You will find membership and role manager under the <system.web> element. Under the membership providers section add the below code… <add name="SPFormAuthMembership" type="System.Web.Security.SqlMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> After adding memberhip element, see the snapshot of the web.config. Now you need to add role manager element to the web.config. Insider providers element under rolemanager, add the below code. <add name="SPFormAuthRoleManager" type="System.Web.Security.SqlRoleProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> After adding, your role manager will look similar to the following. As a last step, you need to update the people picker wildcard element in web.config, so that the users from your membership provider are available for browsing in Central Administration. Search for PeoplePickerWildcards in the web.config, add the following inside the <PeoplePickerWildcards> tag. <add key="SPFormAuthMembership" value="%" /> After adding this element, your web.config will look like After completing these steps, you can browse the users available in the SQL server database from central administration website. Go to the site collection administrator’s page from central administration. Select the site collection you have created for form authentication. Click on the people picker icon, choose Forms Auth and click on the search icon, you will see the users listed from the SQL server database. Once you complete these steps, make sure the users are available for browsing from central administration website. If you are unable to find the users, there must be some errors in the configuration, check windows event logs to find related errors and fix them. Change the web.config for STS application Open the web.config for STS application in text editor. By default, STS web.config does not have system.Web or connectionstrings section. Just after the System.Webserver element, add the following code. <connectionStrings> <add name="FormAuthConnString" connectionString="Initial Catalog=aspnetdb_claim;data source=sp2010_db;Integrated Security=SSPI;" /> </connectionStrings> <system.web> <roleManager enabled="true" cacheRolesInCookie="false" cookieName=".ASPXROLES" cookieTimeout="30" cookiePath="/" cookieRequireSSL="false" cookieSlidingExpiration="true" cookieProtection="All" createPersistentCookie="false" maxCachedResults="25"> <providers> <add name="SPFormAuthRoleManager" type="System.Web.Security.SqlRoleProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> </providers> </roleManager> <membership userIsOnlineTimeWindow="15" hashAlgorithmType=""> <providers> <add name="SPFormAuthMembership" type="System.Web.Security.SqlMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> </providers> </membership> </system.web> See the snapshot of the web.config after adding the required elements. After adding this, you should be able to login using the credentials from SQL server. Try assigning a user as primary/secondary administrator for your site collection from Central Administration and login to your site using form authentication. If you made everything correct, you should be able to login. This means you have successfully completed configuration of STS Configuration of Web Application for Form Authentication As a last step, you need to modify the web.config of the form authentication web application. Once you have done this, you should be able to grant permissions to users stored in the membership database. Open the Web.config of the web application you created for form authentication. You can find the web.config for the application under the path C:\inetpub\wwwroot\wss\VirtualDirectories\<port number> Basically you need to add connection string, membership provider, role manager and update the people picker wild card configuration. Add the connection string (same as the one you added to the web.config in Central Administration). See the screenshot after the connection string has added. Search for <membership> in the web.config, you will find this inside system.web element. There will be other providers already available there. You add your form authentication membership provider (similar to the one added to Central Administration web.config) to the provider element under membership. Find the snapshot of membership configuration as follows. Search for <roleManager> element in web.config, add the new provider name under providers section of the roleManager element. See the snapshot of web.config after new provider added. Now you need to configure the peoplepickerwildcard configuration in web.config. As I specified earlier, this is to make sure, you can locate the users by entering a part of their username. Add the following line under the <PeoplePickerWildcards> element in web.config. See the screenshot of the peoplePickerWildcards element after the element has been added. Now you have completed all the setup for form authentication. Navigate to the web application. From the site actions -> site settings -> go to peope and groups Click on new -> add users, it will popup the people picker dialog. Click on the icon, select Form Auth, enter a username in the search textbox, and click on search icon. See the screenshot of admin search when I tried searching the users If it displays the user, it means you are done with the configuration. If you add users to the form authentication database, the users will be able to access SharePoint portal as normal.

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  • Nginx settings are screwing up my Drupal form submissions, how do I fix?

    - by bflora
    How do I tell Nginx to "ignore" specific URLS or pages on my web site? I run a Drupal site where anonymous visitors get served via NGINX while logged in users get served via Apache. We do this to keep the load down and scale better. It works great, except, since we set up nginx, a good number of Drupal forms no longer work. For example, before installing Nginx, if you created a new article, then clicked "edit" and edited the article. You could click "save" and your changes to the article would be saved. After setting up nginx, when you make edits and then click "save," the page simple refreshes, but now with "nginx-index.php" inserted into the URL. And your changes to the form were not actually saved to the database. So if you go to edit an article, you'll be on domain.com/node/##/edit or something like that. When you try to save your changes to the form, you'll wind up at domain.com/nginx-index.php?q=node/##/edit. And your changes will not be saved. There is a way around this, but only for administrative users. If you go to a form where this problem is happening, then comment or comment-out three lines in our settings.php file, the form will save properly. Those three lines are: // 'cache_form' = array( // 'engine' = 'db', // ), If they're commented, you uncomment them, them save the form. If they're uncommented, you comment them out and save the form. Obviously, this sucks. My friend who set up our server (and then left the country) told me that there are some Nginx settings that can tell it to "ignore" certain URLs or pages which could work here. How do I do this and where do I do it?

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  • MVC - Ajax form - return partial view doesnt update in <div> target

    - by Jack
    I have an index view that I want to update automatically as the user types in a client id. I got something similiar to work (only it was updating just a label) - but this will not work. What happens is the partial is just rendered by itself (not in place of the UpdateTargetID). So the data is rendered on a new page. Here is my code: Controller: public ActionResult ClientList(string queryText) { var clients = CR.GetClientLike(queryText); return PartialView("ClientIndex", clients); } Partial View: <table> <thead> <tr> <td>Client ID</td> <td>Phone1</td> <td>Phone2</td> <td>Phone3</td> <td>Phone4</td> </tr> </thead> <tbody> <% if (Model != null) { foreach (Client c in Model) { %> <tr> <td><%= Html.Encode(c.ClientID)%></td> <td><%= Html.Encode(c.WorkPhone)%></td> <td><%= Html.Encode(c.WorkPhone1)%></td> <td><%= Html.Encode(c.WorkPhone2)%></td> <td><%= Html.Encode(c.WorkPhone3)%></td> </tr> <% } } %> </tbody> Main View: Insert code messed up, so this is just copy/pasted: $(function() { $("#queryText").keyup(function() { $('#sForm').submit(); }); }); <% using (Ajax.BeginForm("ClientList", /* new { queryText = Form.Controls[2] ?? }*/"", new AjaxOptions { UpdateTargetId = "status", InsertionMode = InsertionMode.Replace }, new { @id = "sForm" })) { % <% } % <div id="status" class="status" name="status"> <%--<% Html.RenderPartial("ClientIndex", ViewData["clients"]); %> Should this be here???? --%> </div>

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  • javascript - multiple dependent/cascading/chained select boxes on same form

    - by Aaron
    I'm populating select box options via jquery and json but I'm not sure how to address multiple instances of the same chained select boxes within my form. Because the select boxes are only rendered when needed some records will have ten sets of chained select boxes and others will only need one. How does one generate unique selects to support the auto population of secondary select options? Here's the code I'm using, and I thank you in advance for any insight you may provide. <script type="text/javascript" src="jquery.js"></script> <script type="text/javascript"> function populateACD() { $.getJSON('/acd/acd2json.php', {acdSelect:$('#acdSelect').val()}, function(data) { var select = $('#acd2'); var options = select.attr('options'); $('option', select).remove(); $.each(data, function(index, array) { options[options.length] = new Option(array['ACD2']); }); }); } $(document).ready(function() { populateACD(); $('#acdSelect').change(function() { populateACD(); }); }); </script> <?php require_once('connectvars.php'); $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $squery = "SELECT ACD1ID, ACD1 from ACD1"; $sdata = mysqli_query($dbc, $squery); // Loop through the array of ACD1s, placing them into an option of a select echo '<select name="acdSelect" id="acdSelect">'; while ($row = mysqli_fetch_array($sdata)) { echo "<option value=" . $row['ACD1ID'] . ">" . $row['ACD1'] . "</option>\n"; } echo '</select><br /><br />'; <select name="acd2" id="acd2"> </select> acd2json.php <?php $dsn = "mysql:host=localhost;dbname=wfn"; $user = "acd"; $pass = "***************"; $pdo = new PDO($dsn, $user, $pass); $rows = array(); if(isset($_GET['acdSelect'])) { $stmt = $pdo->prepare("SELECT ACD2 FROM ACD2 WHERE ACD1ID = ? ORDER BY ACD2"); $stmt->execute(array($_GET['acdSelect'])); $rows = $stmt->fetchAll(PDO::FETCH_ASSOC); } echo json_encode($rows); ?>

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