Search Results

Search found 12077 results on 484 pages for 'node js'.

Page 115/484 | < Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >

  • Preoder traversal of a Btree

    - by Phenom
    I'm trying to figure out how to do a preorder traversal of a Btree. I know that generally preorder traversal works like this: preorder(node) { print value in node preorder(left child) preorder(right child) } What's confusing to me is how to make this work with a Btree, since in each node there are multiple values and multiple child pointers. When printing values, do all the values in the node get printed before descending into the left child? Each node looks like this: child1 value1 child2 value2 child3 value3 child4 Also, why would anyone want to do a preorder traversal of a Btree, since an inorder traversal is what will display the values in ascending order?

    Read the article

  • Parsing prototype AJAX.response XML in IE

    - by adam
    Hi I have an xml webservice which I'm fetching using PrototypeJS. The xml has the correct content type and is well-formed, and looks like this: <GetTokenResponse xmlns="http://tempuri.org/"> <GetTokenResult>F655100D64F098F0AC33AFF414A4A0D5</GetTokenResult> </GetTokenResponse> The AJAX request is completing successfully, and I can access the GetTokenResult node in both IE and FF but can only get the text content of the node in FF. My code is below: node = transport.responseXML.documentElement.getElementsByTagName('GetTokenResult')[0]; rawToken = (document.all) ? node.innerText : node.textContent; I've tried innerText and innerHTML, as well as children[0] and a few other chance guesses but IE returns 'undefined' when I access rawToken. Anyone able to lend a hand? Thanks, Adam

    Read the article

  • How do I know an array of structures was allocated in the Large Object Heap (LOH) in .NET?

    - by AMissico
    After some experimenation using CLR Profiler, I found that: Node[,] n = new Node[100,23]; //'84,028 bytes, is not placed in LOH Node[,] n = new Node[100,24]; //'86,428 bytes, is public struct Node { public int Value; public Point Point; public Color Color; public bool Handled; public Object Tag; } During run-time, how do I know an array of structures (or any array) was allocated in the Large Object Heap (LOH)?

    Read the article

  • Reading train stop display names from a resource bundle

    - by Frank Nimphius
    v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} Normal 0 false false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Times New Roman","serif";} In Oracle JDeveloper 11g R1, you set the display name of a train stop of an ADF bounded task flow train model by using the Oracle JDeveloper Structure Window. To do so Double-click onto the bounded task flow configuration file (XML) located in the Application Navigator so the task flow diagram open In the task flow diagram, select the view activity node for which you want to define the display name. In the Structure Window., expand the view activity node and then the train-stop node therein Add the display name element by using the right-click context menu on the train-stop node, selecting Insert inside train-stop > Display Name Edit the Display Name value with the Property Inspector Following the steps outlined above, you can define static display names – like "PF1" for page fragment 1 shown in the image below - for train stops to show at runtime. In the following, I explain how you can change the static display string to a dynamic string that reads the display label from a resource bundle so train stop labels can be internationalized. There are different strategies available for managing message bundles within an Oracle JDeveloper project. In this blog entry, I decided to build and configure the default properties file as indicated by the projects properties. To learn about the suggested file name and location, open the JDeveloper project properties (use a right mouse click on the project node in the Application Navigator and choose Project Properties. Select the Resource Bundle node to see the suggested name and location for the default message bundle. Note that this is the resource bundle that Oracle JDeveloper would automatically create when you assign a text resource to an ADF Faces component in a page. For the train stop display name, we need to create the message bundle manually as there is no context menu help available in Oracle JDeveloper. For this, use a right mouse click on the JDeveloper project and choose New | General | File from the menu and in the opened dialog. Specify the message bundle file name as the name looked up before in the project properties Resource Bundle option. Also, ensure that the file is saved in a directory structure that matches the package structure shown in the Resource Bundle dialog. For example, you would save the properties file in the View Project's src > adf > sample directory if the package structure was "adf.sample" (adf.sample.ViewControllerBundle). Edit the properties file and define key – values pairs for the train stop component. In the sample, such key value pairs are TrainStop1=Train Stop 1 TrainStop2=Train Stop 2 TrainStop3=Train Stop 3 Next, double click the faces-config.xml file and switch the opened editor to the Overview tab. Select the Application category and press the green plus icon next to the Resource Bundle section. Define the resource bundle Base Name as the package and properties file name, for example adf.sample.ViewControllerBundle Finally, define a variable name for the message bundle so the bundle can be accessed from Expression Language. For this blog example, the name is chosen as "messageBundle". <resource-bundle>   <base-name>adf.sample.ViewControllerBundle</base-name>   <var>messageBundle</var> </resource-bundle> Next, select the display-name element in the train stop node (similar to when creating the display name) and use the Property Inspector to change the static display string to an EL expression referencing the message bundle. For example: #{messageBundle.TrainStop1} At runtime, the train stops now show display names read from a message bundle (the properties file).

    Read the article

  • Implement Tree/Details With Taskflow Regions Using EJB

    - by Deepak Siddappa
    This article describes on Display Tree/Details using taskflow regions.Use Case DescriptionLet us take scenario where we need to display Tree/Details, left region contains category hierarchy with items listed in a tree structure (ex:- Region-Countries-Locations-Departments in tree format) and right region contains the Employees list.In detail, Here User may drills down through categories using a tree until Employees are listed. Clicking the tree node name displays Employee list in the adjacent pane related to particular tree node. Implementation StepsThe script for creating the tables and inserting the data required for this application CreateSchema.sql Lets create a Java EE Web Application with Entities based on Regions, Countries, Locations, Departments and Employees table. Create a Stateless Session Bean and data control for the Stateless Session Bean. Add the below code to the session bean and expose the method in local/remote interface and generate a data control for that.Note:- Here in the below code "em" is a EntityManager. public List<Employees> empFilteredByTreeNode(String treeNodeType, String paramValue) { String queryString = null; try { if (treeNodeType == "null") { queryString = "select * from Employees emp ORDER BY emp.employee_id ASC"; } else if (Pattern.matches("[a-zA-Z]+[_]+[a-zA-Z]+[_]+[[0-9]+]+", treeNodeType)) { queryString = "select * from employees emp INNER JOIN departments dept\n" + "ON emp.department_id = dept.department_id JOIN locations loc\n" + "ON dept.location_id = loc.location_id JOIN countries cont\n" + "ON loc.country_id = cont.country_id JOIN regions reg\n" + "ON cont.region_id = reg.region_id and reg.region_name = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.contains("regionsFindAll_bc_countriesList_1")) { queryString = "select * from employees emp INNER JOIN departments dept \n" + "ON emp.department_id = dept.department_id JOIN locations loc \n" + "ON dept.location_id = loc.location_id JOIN countries cont \n" + "ON loc.country_id = cont.country_id and cont.country_name = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.contains("regionsFindAll_bc_locationsList_1")) { queryString = "select * from employees emp INNER JOIN departments dept ON emp.department_id = dept.department_id JOIN locations loc ON dept.location_id = loc.location_id and loc.city = '" + paramValue + "' ORDER BY emp.employee_id ASC"; } else if (treeNodeType.trim().contains("regionsFindAll_bc_departmentsList_1")) { queryString = "select * from Employees emp INNER JOIN Departments dept ON emp.DEPARTMENT_ID = dept.DEPARTMENT_ID and dept.DEPARTMENT_NAME = '" + paramValue + "'"; } } catch (NullPointerException e) { System.out.println(e.getMessage()); } return em.createNativeQuery(queryString, Employees.class).getResultList(); } In the ViewController project, create two ADF taskflow with page Fragments and name them as FirstTaskflow and SecondTaskflow respectively. Open FirstTaskflow,from component palette drop view(Page Fragment) name it as TreeList.jsff. Open SeconfTaskflow, from component palette drop view(Page Fragment) name it as EmpList.jsff and create two paramters in its overview parameters tab as shown in below image. Open TreeList.jsff , from data control palette drop regionsFindAll->Tree as ADF Tree. In Edit Tree Binding dialog, for Tree Level Rules select the display attributes as follows:-model.Regions - regionNamemodel.Countries - countryNamemodel.Locations - citymodel.Departments - departmentName In structure panel, click on af:Tree - t1 and select selectionListener with edit property. Create a "TreeBean" managed bean with scope as "session" as shown in below Image. Create new method as getTreeNodeSelectedValue and click ok. Open TreeBean managed bean and add the below code: private String treeNodeType; private String paramValue; public void getTreeNodeSelectedValue(SelectionEvent selectionEvent) { RichTree tree = (RichTree)selectionEvent.getSource(); RowKeySet addedSet = selectionEvent.getAddedSet(); Iterator i = addedSet.iterator(); TreeModel model = (TreeModel)tree.getValue(); model.setRowKey(i.next()); JUCtrlHierNodeBinding node = (JUCtrlHierNodeBinding)tree.getRowData(); //oracle.jbo.Row Row rw = node.getRow(); Object selectedTreeNode = node.getAttribute(0); Object treeListType = node.getBindings(); String treeNodeType = treeListType.toString(); this.setParamValue(selectedTreeNode.toString()); this.setTreeNodeType(treeNodeType); } public void setTreeNodeType(String treeNodeType) { this.treeNodeType = treeNodeType; } public String getTreeNodeType() { return treeNodeType; } public void setParamValue(String paramValue) { this.paramValue = paramValue; } public String getParamValue() { return paramValue; }<br /> Open EmpList.jsff , from data control palette drop empFilteredByTreeNode->Employees->Table as ADF Read-only Table. After selecting the  Employees result set, in Edit Action Binding dialog window pass the pageFlowScope parameters as shown in below Image. In empList.jsff page, click Binding tab and click on Create Executable binding and select Invoke action and follow as shown in below image. Edit executeEmpFiltered invoke action properties and set the Refresh to ifNeeded, So when ever the page needs the method will be executed. Create Main.jspx page with page template as Oracle Three Column Layout. Drop FirstTaskflow as Region in start facet and drop SecondTaskflow as Region in center facet, Edit task Flow Binding dialog window pass the Input Paramters as shown in below Image. Run the Main.jspx, tree will be displayed in left region and emp details will displyaed on the right region. Click on the Americas in tree node, all emp related to the Americas related will be displayed. Click on Americas->United States of America->South San Francisco->Accounting, only employee belongs to the Accounting department will be displayed.

    Read the article

  • FIFO implementation

    - by Narek
    While implementing a FIFO I have used the following structure: struct Node { T info_; Node* link_; Node(T info, Node* link=0): info_(info), link_(link) {} }; I think this a well known trick for lots of STL containers (for example for List). Is this a good practice? What it means for compiler when you say that Node has a member with a type of it's pointer? Is this a kind of infinite loop? And finally, if this is a bad practice, how I could implement a better FIFO. EDIT: People, this is all about implemenation. I am enough familiar with STL library, and know a plenty of containers from several libraries. Just I want to discuss with people who can gave a good implementation or a good advice.

    Read the article

  • jsTree: Prevent before and after TYPE, only use inside

    - by Nic Hubbard
    I am using jsTree which is very nice. When dragging and dropping, I don't really care for the before and after types, I only want to use inside. Meaning, I am only concerned about that parent that a child is dropped into, rather than where the order is with other elements INSIDE the parent. So, I wanted to build my callback, so it always refers to the parent node that it is inside. But, it is not fool proof, yet. onmove : function (NODE,REF_NODE,TYPE,TREE_OBJ,RB) { if (TYPE == 'inside') { alert('Item to move:'+$(NODE).attr('rel')+' to '+$(REF_NODE).attr('rel')+' '+TYPE); } else if (TYPE == 'after') { alert('Item to move:'+$(NODE).attr('rel')+' to '+$(REF_NODE).parent().parent('li').attr('rel')+' '+TYPE); } }, Does anyone have suggestions, how I can change my callback, so that the REF_NODE is always the parent that the NODE is moved into? Rather than a sibling of, which is a child of the parent?

    Read the article

  • Trees and macros with tikz

    - by Tsf
    I am trying to build my trees using macros but I don't get the result I want. Here is a minimal example: \documentclass{article} \usepackage{tikz} \usetikzlibrary{trees} \newcommand{\LeafNode}[1]{% child {node {#1}} } \newcommand{\InnerNode}[3]{% child {node {#3} #1 #2 } } \begin{document} \begin{tikzpicture} \node (A) {A} \LeafNode{B} \LeafNode{C} ; \end{tikzpicture}% \hspace{2cm}% \begin{tikzpicture} \node (A) {A} \InnerNode{\LeafNode{D}}{\LeafNode{E}}{B} \LeafNode{C} ; \end{tikzpicture} \end{document} I expected this to produce two trees: A A / \ / \ B C B C / \ D E but I am getting: A | A B | | B D | | C C Am I missing something or there is no way to do it? BTW, if I omit the label on my root node, I get a PGF error: ! Package pgf Error: No shape named is known. -- Tsf

    Read the article

  • got a question about Linked-List in java code.

    - by glacier89
    Linked-List: Mirror Consider the following private class for a node of a singly-linked list of integers: private class Node{ public int value; public Node next; } A wrapper-class, called, ListImpl, contains a pointer, called start to the first node of a linked list of Node. Write an instance-method for ListImpl with the signature: public void mirror(); That makes a reversed copy of the linked-list pointed to by start and appends that copy to the end of the list. So, for example the list: start 1 2 3 after a call to mirror, becomes: start 1 2 3 3 2 1 Note: in your answer you do not need to dene the rest of the class for ListImpl just the mirror method.

    Read the article

  • Test, if object was deleted

    - by justik
    Look to the following code, please: class Node { private: double x, y; public: Node (double xx, double yy): x(xx), y(yy){} }; int main() { Node *n1 = new Node(1,1); Node *n2 = n1; delete n2; n2 = NULL; if (n1 != NULL) //Bad test { delete n1; //throw an exception } } There are two pointers n1, n2 pointed to the same object. I would like to detect whether n2 was deleted using n1 pointer test. But this test results in exception. Is there any way how to determine whether the object was deleted (or was not deleted) using n1 pointer ? Thanks for your help.

    Read the article

  • c# hierarchy collection library? - anyone know of one (e.g. GetDirectChildren, GetAllChildren, GetPa

    - by Greg
    Hi, Does anyone know of a solid C# library / approach to manage a hierarchy/web type collection? This would be a library that would basic consist of the concept of nodes & relationships, for example to model web pages/files linked under a URL, or modeling IT infrastructure. It would have key methods such as: Node.GetDirectParents() Node.GetRootParents() Node.GetDirectChildren() Node.GetAllChildren() So it's smarts would include the ability to "walk the tree" of nodes based on the relationships when someone does ask for "give me all the children under this node" for example. It ideally include a persistence layer, to save/retrieve such data to/from a databases (e.g. with a Nodes and Relationships table). Thanks

    Read the article

  • What is the best way to convert a doctrine nested set to an li-structure?

    - by murze
    Hi, I'm using Doctrine NestedSet behavior. I'd like to render the tree using php to <ul>'s and <li>'s Here's an example of what the output might be: <ul> <li>Node 1</li> <li>Node 2 <ul> <li>Child 1 of Node 2</li> <li>Child 2 of Node 2 <ul> <li>Another Child</li> <li>Yet Another Child</li> </ul> </li> </ul> </li> <li>Node 3</li> </ul> What is the best way to do this?

    Read the article

  • Height of a binary tree

    - by Programmer
    Consider the following code: public int heightOfBinaryTree(Node node) { if (node == null) { return 0; } else { return 1 + Math.max(heightOfBinaryTree(node.left), heightOfBinaryTree(node.right)); } } I want to know the logical reasoning behind this code. How did people come up with it? Does some have an inductive proof? Moreover, I thought of just doing a BFS with the root of the binary tree as the argument to get the height of the binary tree. Is the previous approach better than mine?Why?

    Read the article

  • fastest way to search through this data object? (python)

    - by victor
    I have a data object that looks like this: { 'node-16': { 'tags': ['cuda'], 'localNodes': [ { 'name': 'nC', 'consumesFrom': ['nA', 'nB'], 'classType': 'VectorAdder.VectorAdder' }, { 'name': 'nB', 'consumesFrom': None, 'classType': 'RandomVector' } ] }, 'node-17': { 'tags': ['boring'], 'localNodes': [ { 'name': 'nA', 'consumesFrom': None, 'classType': 'RandomVector' } ] } } Notice that node nA is a producer for nC. What's the fastest way to find out if a given localNode is a producer for another localnode in the data structure (and not within the same list)? For example, I would like to know that nA (node-17) produces for nC (exists on node-16). But I don't need to know that nB produces for nC, since they exist in the same localNodes list.

    Read the article

  • What is the problem with my LinkedList class?

    - by user258367
    class LinkedList { private: int data; LinkedList *ptr; public: LinkedList(int i_data) { data = i_data; ptr = 0; { ~LinkedList() { delete ptr ; } void insert(LinkedList *node) { while(this->next != 0) this = this->next; this->next = node; } } I will be creating a head node like head = new LinkedList(4) and then will be calling like head->insert(new LinkedList(5)) and subsequently . Can you please tell me does above class represent a linkedlist . i think yes it has node which contain address of next node . Please correct me if i am wrong

    Read the article

  • How to create file of files?

    - by TheMachineCharmer
    class Node { FooType Data; // I can save Data to file with extension .foo void Save() { // save Data to .foo file } } Now , class Graph { List<Node> Nodes; void Save() { foreach(Node node in Nodes) { node.Save(); } } } Now when I invoke someGraph.Save(); then it creates Nodes.Count number of files. I would like to appear those files as one file with extension somename.graph and be able to read it again as Nodes. How can I do this? Is there a way to bundle files into a single different file?

    Read the article

  • Searching custom nodes' by field in Drupal?

    - by Airjoe
    Hello- Using Drupal on a project which I made custom node types in using the CCK. I want to be able to search the specific node based on a custom field the node has. So let's say I have this node type Article which has a field "myfield", I want to be able to search for Articles based on the myfield field. I understand the default search module allows for searching of node types using the type:MyNodeType in the search, but I did not see any way to limit which fields are searched. Any tips? Is this something that is going to get crazy? Appreciate the help.

    Read the article

  • using jquery to parse XML export in drupal

    - by gables20
    I need to use jquery to parse a drupal xml export that was created with views datasource module. The format of the xml export is shown below and on the browser, its access by entering, say for example, http://mydomain/test.xml, where test.xml represents the path of the xml export. <node> <node> <nothing> Lorem ipsum </nothing> </node> <node> The jquery to parse xml is shown below. But, it does nothing, which is kind of the main problem. $(document).ready(function(){ $.ajax({ type: "GET", url: "http://mydomain/test.xml", dataType: "xml", success: function(xml){ $(xml).find('node').each(function(){ var title = $(this).find('nothing').text(); $('#output').append($(this).find('nothing').text()); }); } }); });

    Read the article

  • Trouble creating a makefile

    - by catia
    Hi everyone! I'm having some trouble making a Makefile. Write now I just compile everything every time. Although, the professor is ok with that, I do want to get it working faster and to avoid unnecessary compiling. Here's what I have. FILES= p6.cpp SetIter.cpp Node.cpp Set.cpp CFLAGS= -ansi -pendantic -Wall -Wextra CC= g++ MakePg6: p6.cpp SetIter.cpp Node.cpp Set.cpp $(CC) $(CFLAGS) $(FILES) -o pg6 Node.cpp - node class Set.cpp - uses nodes. Friend of Node. SetIter.cpp - gets a set and uses a pointer to iterator through I'm confused with some of the depencies arising from the friends thing and the point of lib.o being included in the Makefile as some sites have. Any help is greatly appreciated. Thanks in advance.

    Read the article

  • Drupal 6: pre-defined variable for amount [count] of custom type items...

    - by artmania
    Hi friends, I'm a drupal newbie... I researched but couldnot find :/ is there any predefined variable that gives my CCK field value count? for example; I have field_logo_sponsor and I need to display all logo items. Now I have 5 item <?php print $node->field_logo_sponsor[0]['view'] ?> <?php print $node->field_logo_sponsor[1]['view'] ?> <?php print $node->field_logo_sponsor[2]['view'] ?> <?php print $node->field_logo_sponsor[3]['view'] ?> <?php print $node->field_logo_sponsor[4]['view'] ?> it is stupid to use it that way :/ if there is any count variable for that, I will just create a loop for that and display them in a for or while loop Appreciate helps! thanks a lot!

    Read the article

  • iphone app store rss failed to open

    - by suvendu
    I write this, $opts = array( 'http' = array( 'user_agent' = 'PHP libxml agent', ) ); $context = stream_context_create($opts); libxml_set_streams_context($context); $doc = new DOMDocument(); $doc-load("http://ax.itunes.apple.com/WebObjects/MZStoreServices.woa/ws/RSS/toppaidapplications/limit=25/xml"); foreach ($doc-getElementsByTagName('item') as $node) { $title = $node-getElementsByTagName('title')-item(0)-nodeValue; $desc = $node-getElementsByTagName('description')-item(0)-nodeValue; $link = $node-getElementsByTagName('link')-item(0)-nodeValue; $date = $node-getElementsByTagName('pubDate')-item(0)-nodeValue; echo $title; echo '<br>'; echo $desc; } ?

    Read the article

  • Store address dynamic array in c

    - by user280642
    I'm trying to save the address of a dynamic array index. struct sstor *dlist; struct node *q; q->item = &(dlist->item[(dlist->sz)-1]); // Problem? This is my node struct node { char **item; struct node *next; struct node *prev; }; This is my array struct sstor { int sz; int maxsz; char item[][1024]; }; I'm still new to pointers. The line below gives the error: assignment from incompatible pointer type q->item = &(dlist->item[(dlist->sz)-1]);

    Read the article

  • c# display DB table structure

    - by user3529643
    I have a question. My code is the following : public partial class Form1 : Form { public OleDbConnection datCon; public string MyDataFile; public ArrayList tblArray; public ArrayList fldArray; public Form1() { InitializeComponent(); lvData.Clear(); lvData.View = View.Details; lvData.LabelEdit = false; lvData.FullRowSelect = true; lvData.GridLines = true; } private void DataConnection() { MyDataFile = Application.StartupPath + @"\studenti.mdb"; string MyCon = @"provider=microsoft.jet.oledb.4.0;data source=" + MyDataFile; try { datCon = new OleDbConnection(MyCon); } catch (Exception ex) { MessageBox.Show(ex.Message); } FillTreeView(); } private void GetTables(OleDbConnection cnn) { try { cnn.Open(); DataTable schTable = cnn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables, new Object[] { null, null, null, "TABLE" }); tblArray = new ArrayList(); foreach (DataRow datrow in schTable.Rows) { tblArray.Add(datrow["TABLE_NAME"].ToString()); } cnn.Close(); } catch (Exception ex) { MessageBox.Show(ex.Message); } } private void GetFields(OleDbConnection cnn, string tabNode) { string tabName; try { tabName = tabNode; cnn.Open(); DataTable schTable = cnn.GetOleDbSchemaTable(OleDbSchemaGuid.Columns, new Object[] { null, null, tabName }); fldArray = new ArrayList(); foreach (DataRow datRow in schTable.Rows) { fldArray.Add(datRow["COLUMN_NAME"].ToString()); } cnn.Close(); } catch (Exception ex) { MessageBox.Show(ex.Message); } } private void FillTreeView() { tvData.Nodes.Clear(); tvData.Nodes.Add("Database"); tvData.Nodes[0].Tag = "RootDB"; GetTables(datCon); // add table node for (int i = 0; i < tblArray.Count; i++) { tvData.Nodes[0].Nodes.Add(tblArray[i].ToString()); tvData.Nodes[0].Nodes[i].Tag = "Tables"; } // add field node for (int i = 0; i < tblArray.Count; i++) { GetFields(datCon, tblArray[i].ToString()); for (int j = 0; j < fldArray.Count; j++) { tvData.Nodes[0].Nodes[i].Nodes.Add(fldArray[j].ToString()); tvData.Nodes[0].Nodes[i].Nodes[j].Tag = "Fields"; } } this.tvData.ContextMenuStrip = contextMenuStrip1; contextMenuStrip1.ItemClicked +=contextMenuStrip1_ItemClicked; } public void FillListView(OleDbConnection cnn, string tabName) { OleDbCommand cmdRead; OleDbDataReader datReader; string strField; lblTableName.Text = tabName; strField = "SELECT * FROM [" + tabName + "]"; // Initi cmdRead obiect cmdRead = new OleDbCommand(strField, cnn); cnn.Open(); datReader = cmdRead.ExecuteReader(); // fill ListView while (datReader.Read()) { ListViewItem objListItem = new ListViewItem(datReader.GetValue(0).ToString()); for (int c = 1; c < datReader.FieldCount; c++) { objListItem.SubItems.Add(datReader.GetValue(c).ToString()); } lvData.Items.Add(objListItem); } datReader.Close(); cnn.Close(); } private void ViewToolStripMenuItem_Click(object sender, EventArgs e) { DataConnection(); } public void tvData_AfterExpand(object sender, System.Windows.Forms.TreeViewEventArgs e) { string tabName; int fldCount; if (e.Node.Tag.ToString() == "Tables") { fldCount = e.Node.GetNodeCount(false); //column headers. int n = lvData.Width; double wid = n / fldCount; // width columnn for (int c = 0; c < fldCount; c++) { lvData.Columns.Add(e.Node.Nodes[c].Text, (int)wid, HorizontalAlignment.Left); } // gett table name tabName = e.Node.Text; FillListView(datCon, tabName); } } public void button1_Click(object sender, EventArgs e) { //TO DO?? } } I have a treeview populated with tables (nodes) from my database, and a listview which is populated with the data from my tables when I click on a table. As you can see I have a button1 on my form. When I click it I want it to display to me the structure of the table I selected in my treeview (a treeview node). Not too many details, just the name of the columns in my table, type of columns, primary keys. I've tried to follow many tutorials but I can t seem to manage it.

    Read the article

  • Java: PriorityQueue returning incorrect ordering from custom comparator??

    - by Michael Simpson
    I've written a custom comparator to compare my node classes, but the java priority queue is not returning my items in the correct order. Here is my comparator: public int compare(Node n1, Node n2){ if (n1.getF() > n2.getF()){ return +1; } else if (n1.getF() < n2.getF()){ return -1; } else { // equal return 0; } } Where getF returns a double. However after inserting several Nodes into the priority queue, I print them out using: while(open.size() > 0) { Node t = (Node)(open.remove()); System.out.println(t.getF()); } Which results in: 6.830951894845301 6.830951894845301 6.0 6.0 5.242640687119285 7.4031242374328485 7.4031242374328485 8.071067811865476 Any ideas why this is so? Is my comparator wrong? Thanks. Mike

    Read the article

  • scala xml rewrite rule (or, simple pattern help)

    - by williamstw
    I'm missing some fairly simple syntax I gather. I'm trying to rewrite an element label to something else and keep everything else intact. object htmlRule extends RewriteRule { override def transform(n: Node): Seq[Node] = n match { case Elem(prefix, "document", attribs, scope, child@_*) => Elem(prefix, "html", attribs, scope, child) case other => other } } Now, I ask for an explanation of two things: 1) What exactly does "child@_*" mean in plain English? 2) How can I capture the value of "child@_*" and just let it pass right through to the new element? Currently, I get the following error, which makes sense. [error] found : Seq[scala.xml.Node] [error] required: scala.xml.Node [error] Elem(prefix, "html", attribs, scope, child) I'm not wedded to this either, so if there's a better way to simply change the element name of a specific node, let's here it... Thanks, --tim

    Read the article

< Previous Page | 111 112 113 114 115 116 117 118 119 120 121 122  | Next Page >