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  • remove multiple training slashes mod_rewrite

    - by Boyan
    I know this question was asked a number of times on this site alone, but browsing through the relevant posts I couldn't find a solution. Trying to remove multiple trailing slashes after domain. The following mod_rewrite expressions seem to work for URLs such as http://www.domain.com//path1///path2////, but do not work for domain// DirectorySlash Off RewriteEngine on # Canonical fix RewriteCond %{HTTP_HOST} !^www.domain.com$ [NC] RewriteRule ^(.*)$ http://www.domain.com/$1 [R=301] RewriteRule ^/main.do http://www.domain.com/ [R=301,L] RewriteRule ^/index.jsp http://www.domain.com/ [R=301,L] # Remove bogus query strings RewriteCond %{query_string} q= [NC] RewriteRule (.*) http://www.domain.com/$1? [R=301,L] # Remove multiple slashes after domain - DOESN'T WORK!!! #RewriteCond %{REQUEST_URI} ^//+(.*)$ [OR] #RewriteCond %{REQUEST_URI} ^(.*/)/+$ #RewriteRule / http://www.domain.com/%1 [R=301,L] # Remove multiple slashes anywhere in URL RewriteCond %{REQUEST_URI} ^(.*)//(.*)$ RewriteRule . %1/%2 [R=301,L] # Externally redirect to get rid of trailing slash except for home page, ads RewriteCond %{REQUEST_URI} !^/ads/ RewriteRule ^(.+)/$ $1 [R=301,L] Your help is appreciated.

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  • Porblem with remove trailing slash and non-www to www - using .htaccess

    - by HoanNguyen
    I'm facing an issue with .htacess when combining 2 mod_rewrite at the same time: remove trailing slash redirect non-www to www Here is my .htaccess file Options +FollowSymLinks RewriteEngine On RewriteBase / # Redirect non-www to www RewriteCond %{HTTP_HOST} !^www\.domain\.com$ [NC] RewriteRule ^(.+)/$ http://www.domain.com/$1 [R=301,L] # Remove trailing slash RewriteCond %{HTTP_HOST} ^domain.com RewriteRule (.*) http://www.domain.com/$1 [R=301,L] They worked perfectly when I just used one of them, but when i put them together, the page just keep loading like forever. Please help me to find a way that can use both of them in the same .htaccess :( Many thanks :)

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  • support for rewriteRule in cookie flag

    - by kookadjou
    I'd like to use $1 in the [cookie] flag of rewriteRule. I want to create a cookie with a part of the request url as in the following: RewriteRule ([0-9])/. - [CO=cookieName:$1:example.com] for example: If the request url is: http://www.example.com/1234, i want to set a cookie name "cookieName" with the value "1234" it seems no cookie is add when a dollar sign ($1) is between the cookie directive. Is this something possible ? Thank you

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  • cgi.FieldStorage always empty - never returns POSTed form Data

    - by Dan Carlson
    This problem is probably embarrassingly simple. I'm trying to give python a spin. I thought a good way to start doing that would be to create a simple cgi script to process some form data and do some magic. My python script is executed properly by apache using mod_python, and will print out whatever I want it to print out. My only problem is that cgi.FieldStorage() is always empty. I've tried using both POST and GET. Each trial I fill out both form fields. <form action="pythonScript.py" method="POST" name="ARGH"> <input name="TaskName" type="text" /> <input name="TaskNumber" type="text" /> <input type="submit" /> </form> If I change the form to point to a perl script it reports the form data properly. The python page always gives me the same result: number of keys: 0 #!/usr/bin/python import cgi def index(req): pageContent = """<html><head><title>A page from""" pageContent += """Python</title></head><body>""" form = cgi.FieldStorage() keys = form.keys() keys.sort() pageContent += "<br />number of keys: "+str(len(keys)) for key in keys: pageContent += fieldStorage[ key ].value pageContent += """</body></html>""" return pageContent I'm using Python 2.5.2 and Apache/2.2.3. This is what's in my apache conf file (and my script is in /var/www/python): <Directory /var/www/python/> Options FollowSymLinks +ExecCGI Order allow,deny allow from all AddHandler mod_python .py PythonHandler mod_python.publisher </Directory>

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  • Clean URLs mod_rewrite & wildcard subdomains

    - by Søren Zet
    I got this url http://domain.com/blogs/directory-param with this rule RewriteBase /blogs/directory/ RewriteRule ^/blogs/directory-([A-Za-z0-9-]+)$ /blogs/directory/index.php?cat=$1 [L] so I get /blogs/directory/index.php?cat=param now my problem is the following: I use wildcards subdomains so every *.domain.com is mapped to domain.com/blogs/ for example soeren.domain.com is mapped to domain.com/blogs and so on... My problem now is I want a rule for soeren.domain.com/directory-param which points to domain.com/blogs/directory?index.php?cat=param Do you have any ideas?

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  • Apache rewrite URL replace characters

    - by Tim Cooper
    It's been a while since I've done anything with mod_write, so I was hoping I could help some help on this. I would like a URL like this: http://example.com/qwerty/xyz/ to be directed to querty.xyz.php, where the number of slashes and alpha characters between the slashes is not explicitly set.

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  • Apache Rewrite - put parts of query string in replacement string

    - by Rangi Robinson
    Hello, I'd like to rewrite: www.example.com/file.html?username=john&number=1234 To: www.example.com/users/john But I can't figure out how to extract the "username" value from the query string. I've been Googling this all morning and reading the official docs but no luck. I need to solve this problem with a rewrite, rather than changing the application. Any help much appreciated! Rangi

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  • url rewriting index.php

    - by bean
    i have urls like http://mysite.com/index.php?p=resources http://mysite.com/index.php?p=resources&s=view&id=938 but i want urls like http://mysite.com/resources http://mysite.com/resources/view/938 instead of making hundreds of rewrite rules i wonder if it would be possible to just have one? Ive head this is possible by "getting the uri and splitting it into parts" and then just add a rewrite rule for index.php but how? could someone give an example or link a tutorial

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  • remove multiple trailing slashes mod_rewrite

    - by Boyan
    I know this question was asked a number of times on this site alone, but browsing through the relevant posts I couldn't find a solution. Trying to remove multiple trailing slashes after domain. The following mod_rewrite expressions seem to work for URLs such as http://www.domain.com//path1///path2////, but do not work for domain// DirectorySlash Off RewriteEngine on # Canonical fix RewriteCond %{HTTP_HOST} !^www.domain.com$ [NC] RewriteRule ^(.*)$ http://www.domain.com/$1 [R=301] RewriteRule ^/main.do http://www.domain.com/ [R=301,L] RewriteRule ^/index.jsp http://www.domain.com/ [R=301,L] # Remove bogus query strings RewriteCond %{query_string} q= [NC] RewriteRule (.*) http://www.domain.com/$1? [R=301,L] # Remove multiple slashes after domain - DOESN'T WORK!!! #RewriteCond %{REQUEST_URI} ^//+(.*)$ [OR] #RewriteCond %{REQUEST_URI} ^(.*/)/+$ #RewriteRule / http://www.domain.com/%1 [R=301,L] # Remove multiple slashes anywhere in URL RewriteCond %{REQUEST_URI} ^(.*)//(.*)$ RewriteRule . %1/%2 [R=301,L] # Externally redirect to get rid of trailing slash except for home page, ads RewriteCond %{REQUEST_URI} !^/ads/ RewriteRule ^(.+)/$ $1 [R=301,L] Your help is appreciated.

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  • Subdomain URL Rewriting and Web Apps

    - by Igor K
    So a lot of web apps have the customer choose their own subdomain, ie mycompany.webapp.com Presumably, every subdomain works off the same set of files and the unique subdomain is perhaps stored as a session object. So how does the URL rewriting work? If someone goes to mycompany.webapp.com, you have to rewrite their unique address to a dynamic page to set the session variable, ie webapp.com/mypage.php?cusomer=mycompany But then when you redirected, you'd be at webapp.com/theappdirectory/ and not mycompany.webapp.com/ So how do they do it?

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  • Rewrite only external requests to a certain URL

    - by Cyclone
    I want to rewrite from http://example.com/blah/<something>/<somethingelse> to http://<something>.example.com/<somethingelse>, but only if the request is not an internal redirect. How can I achieve this effect? I know I can use %{THE_REQUEST}, but I can't seem to find any good examples. Thanks for the help!

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  • .htaccess with public folder

    - by ninumedia
    I have a directory structure with the following on localhost: http://localhost/testing/ A directory structure exists inside of testing as follows: /testing/public /testing/public/index.php /testing/public/img /testing/public/css ..etc for the js and swf directories A .htaccess file is inside the testing folder and the contents are as follows: Options +FollowSymLinks RewriteEngine on RewriteBase /testing/ RewriteRule ^public$ public/ [R,QSA] RewriteRule ^public/$ public/index.php?state=public [L,QSA] RewriteRule ^stackoverflow$ stackoverflow/ [R,QSA] RewriteRule ^stackoverflow/$ public/index.php?state=stackoverflow[L,QSA] I am using PHP and inside of the /testing/public/index.php file I wanted to test that the $_GET['state'] is indeed saving the variable. When I try to test out: http://localhost/testing/public $_GET['state'] is not found at all BUT http://localhost/testing/stackoverflow does indeed echo out that $_GET['state'] equals 'stackoverflow'. What am I missing here??? Why is it that I cannot get the state=public in the first link? Thanks for the help!

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  • mod_wsgi | linux installation error

    - by MMRUser
    I'm getting the following error when I try to install mod_wsgi ./configure checking for apxs2... no checking for apxs... /usr/sbin/apxs checking Apache version... 2.2.3 configure: creating ./config.status config.status: creating Makefile make /usr/sbin/apxs -c -I/usr/local/include/python2.6 -DNDEBUG mod_wsgi.c -L/usr/local/lib -L/usr/local/lib/python2.6/config -lpython2.6 -lpthread -ldl -lutil -lm /apr-1/build/libtool --silent --mode=compile gcc -prefer-pic -O2 -g -pipe -Wall -Wp,-D_FORTIFY_SOURCE=2 -fexceptions -fstack-protector --param=ssp-buffer-size=4 -m32 -march=i386 -mtune=generic -fasynchronous-unwind-tables -fno-strict-aliasing -DLINUX=2 -D_REENTRANT -D_GNU_SOURCE -D_LARGEFILE64_SOURCE -pthread -I/usr/include/httpd -I/usr/include/apr-1 -I/usr/include/apr-1 -I/usr/local/include/python2.6 -DNDEBUG -c -o mod_wsgi.lo mod_wsgi.c && touch mod_wsgi.slo sh: /apr-1/build/libtool: No such file or directory apxs:Error: Command failed with rc=8323072 . make: *** [mod_wsgi.la] Error 1 libtool is installed on my system.. mod_wsgi 3.2 *Apache 2.2* *Python 2.6*

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  • Mod_rewrite shortening url .htaccess

    - by Peter
    is there any way to hide redirected url, here is what I think: RewriteEngine On RewriteCond %{REQUEST_FILENAME} -f RewriteRule ^(.*)$ http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://%{HTTP_HOST}%{REQUEST_URI}&force So the long redirected url http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://%{HTTP_HOST}%{REQUEST_URI} to something shorter like /mintedomain.com/track/ It is possible? Adrian edit: Andrew: This is a stats software Mint (haveamint.com) with File Download tracker plugin. The File Download tracker works in this way: in .htaccess every file (zip, rar, txt,...) is redirected to the tracker.php file (because the stats): http://mydomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://%{HTTP_HOST}%{REQUEST_URI} So the redirected url look like this for a zip file: http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://mydomain/downloads/apple.zip This redirected URL is very long and ugly. The best for me would be to redirect this redirected URL to something shorter URL: example: http://mydomain.com/track/downloads/apple.zip.. So the http://mydomain.com/track would be the http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php

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  • Rewrite Query String

    - by Virgil
    Hello, I am trying to write some mod_rewrite rules to generate thumbnails on the fly. So when this url example.com/media/myphoto.jpg?width=100&height=100 the script should rewrite it to example.com/media/myphoto-100x100.jpg and if the file exists on the disk it gets served by Apache and if it doesn't exist it is called a script to generate the file. I wrote this RewriteCond %{QUERY_STRING} ^width=(\d+)&height=(\d+) RewriteRule ^media/([a-zA-Z0-9_\-]+)\.([a-zA-Z0-9]+)$ media/$1-%1x%2.$2 [L] RewriteCond %{QUERY_STRING} ^(.+)? RewriteRule ^media/([a-zA-Z0-9_\-\._]+)$ media/index.php?file=$1&%1 [L] and I get infinite internal redirects. The first condition is matched and the rule is executed and right after that I get an internal redirect. I need advice to finish this script. Thank you.

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  • django setup with Apache, mod_wsgi and cx_Oracle

    - by pablo
    Hi, I need to setup the same django project on several identical servers. Details: - os - free edition of oracle enterprise linux 5 - Apache / mod_wsgi - python - custom python2.6 installation - oracle db with cx_Oracle What is the simplest way to set it up? Would you recommend creating a system user for the django project and use daemon mode? What type of user and what privileges does it need? Can I set ORACLE_HOME, LD_LIBRARY_PATH, PATH=$ORACLE_HOME/bin:$PATH for this user? Would you use a virtualenv for cx_Oracle? Can I somehow put the python2.6 inside the virtualenv so it will portable to other servers? Thanks

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  • Apache - "dynamic" rewrite rule

    - by Christian A. Rasmussen
    Hi there. I'm working on a Zend Framework project where I've stumbled across a bit of a problem. The problem originates from the fact that modules are 2nd class citizens in Zend Framework. In my project, I'd like for each module to have a folder containing files which are to be accessed from the outside - files such as stylesheets, javascripts and images. Now, how is this to be done. With a Zend Framework project I have a folder structure which looks like this: application/ modules/ moduleOne/ public/ stylesheet.css moduleTwo/ moduleThree/ public/ index.php The standard .htaccess file located in the public/ folder holds this: SetEnv APPLICATION_ENV development RewriteEngine On RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] The way it works, is that the project's apache DocumentRoot is the public/ folder. All requests gets redirected through the index.php file where Zend Framework's router component takes over. Now, I'm by no means an expert with Apache nor mod_rewrite so pardon me if this is just silly. I imagine that I implement an extra step in the existing rewrite rule so that if I request http://project/public/moduleOne/stylesheet.css it will for instance resolve to /var/www/project/application/modules/moduleOne/public/stylesheet.css. So the steps which need to be done is to check if the first element in the URI is public/ if it is, we take the next segment as the modules name and use that in the path we're trying to resolve to and attempt to serve the file. Is this at all possible or does anyone have a better suggestion? Thank you for your time Christian Rasmussen

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  • Apache rewrite with many slash not working?

    - by Daok
    I have modified a website with a redirection to a single page: RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] It works as it suppose to be. Everything is redirected to index.php. Here is a working example that display index.php with all images and css: http://.....com/section1 The problem occur when I try : http://....com/section1/subsection The page is redirected to index.php, BUT no images, no css, no javascript. Inside the PHP script everything is like this directly linked to the images or css or javascript like: <img src="images/images1.png> ... <img src="images2.png"> Why does url with many slash like .com../123/123/whatever does not work with images, css or javascript when .com/no_slash_url works?

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  • django+mod_wsgi on virtualenv not working

    - by jwesonga
    I've just finished setting up a django app on virtualenv, deployment went smoothly using a fabric script, but now the .wsgi is not working, I've tried every variation on the internet but no luck. My .wsgi file is: import os import sys import django.core.handlers.wsgi # put the Django project on sys.path root_path = os.path.abspath(os.path.dirname(__file__) + '../') sys.path.insert(0, os.path.join(root_path, 'kcdf')) sys.path.insert(0, root_path) os.environ['DJANGO_SETTINGS_MODULE'] = 'kcdf.settings' application = django.core.handlers.wsgi.WSGIHandler() I keep getting the same error: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] mod_wsgi (pid=16938): Exception occurred processing WSGI script '/home/kcdfweb/webapps/kcdf.web/releases/current/kcdf/apache/kcdf.wsgi'. [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] Traceback (most recent call last): [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 230, in __call__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self.load_middleware() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 33, in load_middleware [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] for middleware_path in settings.MIDDLEWARE_CLASSES: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 269, in __getattr__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._setup() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 40, in _setup [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._wrapped = Settings(settings_module) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 75, in __init__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] ImportError: Could not import settings 'kcdf.settings' (Is it on sys.path? Does it have syntax errors?): No module named kcdf.settings my virtual environment is on /home/user/webapps/kcdfweb my app is /home/user/webapps/kcdf.web/releases/current/project_name my wsgi file home/user/webapps/kcdf.web/releases/current/project_name/apache/project_name.wsgi

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  • How to disable mod_security2 rule (false positive) for one domain on centos 5

    - by nicholas.alipaz
    Hi I have mod_security enabled on a centos5 server and one of the rules is keeping a user from posting some text on a form. The text is legitimate but it has the words 'create' and an html <table> tag later in it so it is causing a false positive. The error I am receiving is below: [Sun Apr 25 20:36:53 2010] [error] [client 76.171.171.xxx] ModSecurity: Access denied with code 500 (phase 2). Pattern match "((alter|create|drop)[[:space:]]+(column|database|procedure|table)|delete[[:space:]]+from|update.+set.+=)" at ARGS:body. [file "/usr/local/apache/conf/modsec2.user.conf"] [line "352"] [id "300015"] [rev "1"] [msg "Generic SQL injection protection"] [severity "CRITICAL"] [hostname "www.mysite.com"] [uri "/node/181/edit"] [unique_id "@TaVDEWnlusAABQv9@oAAAAD"] and here is /usr/local/apache/conf/modsec2.user.conf (line 352) #Generic SQL sigs SecRule ARGS "((alter|create|drop)[[:space:]]+(column|database|procedure|table)|delete[[:space:]]+from|update.+set.+=)" "id:1,rev:1,severity:2,msg:'Generic SQL injection protection'" The questions I have are: What should I do to "whitelist" or allow this rule to get through? What file do I create and where? How should I alter this rule? Can I set it to only be allowed for the one domain, since it is the only one having the issue on this dedicated server or is there a better way to exclude table tags perhaps? Thanks guys

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  • CodeIgniter - How to hide index.php from the URL

    - by kapil.israni
    This is what my .htaccess looks like. The .htaccess is sitting in /www/scripts directory which is the parent of codeigniter's "system" directory and which also contains index.php. I have enabled mod_rewrite in my Apache 2.2.x. This is on Ubuntu 9.10 server. I followed this link, but it does not work. Is there anything i need to do in apache2, any specific configuration so that this works?? RewriteEngine on RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [QSA,L]

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  • Django: TypeError: 'str' object is not callable, referer: http://xxx

    - by user705415
    I've been wondering why when I set the settings.py of my django project 'arvindemo' debug = Flase and deploy it on Apache with mod_wsgi, I got the 500 Internal Server Error. Env: Django 1.4.0 Python 2.7.2 mod_wsgi 2.8 OS centOS Here is the recap: Visit the homepage, go to sub page A/B/C/D, and fill some forms, then submit it to the Apache server. Once click 'submit' button, I will get the '500 Internal Server Error', and the error_log listed below(Traceback): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] Traceback (most recent call last): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.get_response(request) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 179, in get_response [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.handle_uncaught_exception(request, resolver, sys.exc_info()) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 224, in handle_uncaught_exception [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] if resolver.urlconf_module is None: [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/urlresolvers.py", line 323, in urlconf_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] self._urlconf_module = import_module(self.urlconf_name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] __import__(name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/web/django/arvindemo/arvindemo/../arvindemo/urls.py", line 23, in <module> [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] url(r'^submitPage$', name=submitPage), [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] TypeError: url() takes at least 2 arguments (2 given) When using django runserver, I set arvindemo.settings debug = True, everything is OK. But things changed once I set debug = Flase. Here is my views.py from django.http import HttpResponseRedirect from django.http import HttpResponse, HttpResponseServerError from django.shortcuts import render_to_response import datetime, string from user_info.models import * from django.template import Context, loader, RequestContext import settings def hello(request): return HttpResponse("hello girl") def helpPage(request): return render_to_response('kktHelp.html') def server_error(request, template_name='500.html'): return render_to_response(template_name, context_instance = RequestContext(request) ) def page404(request): return render_to_response('404.html') def submitPage(request): post = request.POST Mall = 'goodsName' Contest = 'ojs' Presentation = 'addr' WeatherReport = 'city' Habit = 'task' if Mall in post: return submitMall(request) elif Contest in post: return submitContest(request) elif Presentation in post: return submitPresentation(request) elif Habit in post: return submitHabit(request) elif WeatherReport in post: return submitWeather(request) else: return HttpResponse(request.POST) return HttpResponseRedirect('404') def submitXXX(): ..... def xxxx(): .... Here comes the urls.py from django.conf.urls import patterns, include, url from views import * from django.conf import settings handler500 = 'server_error' urlpatterns = patterns('', url(r'^hello/$', hello), # hello world url(r'^$', homePage), url(r'^time/$', getTime), url(r'^time/plus/(\d{1,2})/$', hoursAhead), url(r'^Ttime/$', templateGetTime), url(r'^Mall$', templateMall), url(r'^Contest$', templateContest), url(r'^Presentation$', templatePresentation), url(r'^Habit$', templateHabit), url(r'^Weather$', templateWeather), url(r'^Help$', helpPage), url(r'^404$', page404), url(r'^500$', server_error), url(r'^submitPage$', submitPage), url(r'^submitMall$', submitMall), url(r'^submitContest$', submitContest), url(r'^submitPresentation$', submitPresentation), url(r'^submitHabit$', submitHabit), url(r'^submitWeather$', submitWeather), url(r'^terms$', terms), url(r'^privacy$', privacy), url(r'^thanks$', thanks), url(r'^about$', about), url(r'^static/(?P<path>.*)$','django.views.static.serve',{'document_root':settings.STATICFILES_DIRS}), ) I'm sure there is no syntax error in my django project,cause when I use django runserver, everything is fine. Anyone can help ? Best regards

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