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  • What's wrong with this inner query (MySQL)...

    - by stuboo
    ...besides the fact that I am a total amateur? My table is set up like this: CREATE TABLE `messages` ( `id` int(6) unsigned NOT NULL AUTO_INCREMENT, `patient_id` int(6) unsigned NOT NULL, `message` varchar(255) NOT NULL, `savedate` int(10) unsigned NOT NULL, `senddate` int(10) unsigned NOT NULL, `SmsSid` varchar(40) NOT NULL COMMENT 'where we store the cookies from twilio', `sendorder` tinyint(3) unsigned NOT NULL COMMENT 'the order we want the msg sent in', `sent` tinyint(1) NOT NULL COMMENT '0=queued, 1=sent, 2=sent-unqueued,4=rec-unread,5=recd-read', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=143 ; I need a query that will SELECT * FROM `messages` WHERE `senddate` < $now AND `sent` = 0 (AND LIMIT TO ONLY ONE RECORD PER `patient_id`) I've tried the following: SELECT * FROM `messages` WHERE `senddate` IN (SELECT `patient_id`, max(`senddate`) GROUP by `patient_id`) AND `senddate` < $now AND `sent` = 0 ; But I get this error: MySQL client version: 5.1.37 `#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP by patient_id) AND senddate < 1270093898 AND sent = 0 LIMIT 0, 30' at line 5

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  • How to distribute ranking using MySQL Query and PHP

    - by nkp
    I have to distribute ranking to the 5000 students in an exam. Ranking is based on the score and the time taken (in seconds) to obtain that score. For example is 5 students have same score, then taken will be the criteria to calculate their ranks otherwise score should be the criteria to calculate their ranks. Following is my table tbRank ID StudID Score Time Date Rank 1 11 8 60 09-11-2013 2 22 6 45 09-11-2013 3 33 4 76 09-11-2013 4 44 6 67 09-11-2013 5 55 8 35 09-11-2013 6 66 8 35 08-11-2013 7 77 8 39 08-11-2013 Now rank column in above table should be updated as: ID StudID Score Time Date Rank 1 11 8 60 09-11-2013 2 2 22 6 45 09-11-2013 3 3 33 4 76 09-11-2013 5 4 44 6 67 09-11-2013 4 5 55 8 35 09-11-2013 1 6 66 8 35 08-11-2013 1 7 77 8 39 08-11-2013 2 I want to make a MySQL Query to do this business. Similarly there can be more than 10000 records in the table. So I need an optimized query for this functionality. Note: I am using PHP and MYSQL. Update: Everyday almost 5000 new entries will be created in the table and after all insertions are made, rank column will be updated once in a day. Now please suggest me the best way to do this. If I update rank column in the table, then only once I will have to do it, otherwise everytime while fetching the rank of the student, I will have to make calculations.

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  • MySQL Delete Records Older Than X Minutes?

    - by sajanNOPPIX
    I've searched quite a bit and found a few solutions that didn't end up working for me and can't understand why. I have a table with a timestamp column. The MySQL type for this column is 'datetime'. I insert into this table the following from PHP. date('Y-m-d H:i:s') This enters, what looks like the correct value for the MySQL date time. 2012-06-28 15:31:46 I want to use this column to delete rows that are older than say 10 minutes. I'm running the following query, but it's not working. It affects 0 rows. DELETE FROM adminLoginLog WHERE timestamp < (NOW() - INTERVAL 10 MINUTE); Can anyone shed some light as to what I'm doing wrong and why it's not working properly? Thanks. Update: It looks like my first issue is that I'm using DATETIME when I should be using the TIMESTAMP data type. I'm updating my code to do that now. Thanks.

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  • Cannot Display Data from MySQL table

    - by MxmastaMills
    I've got a pretty standard call to a MySQL database and for some reason I can't get the code to work. Here's what I have: $mysqli = mysqli_connect("localhost","username","password"); if (!$mysqli) { die('Could not connect: ' . mysqli_error($mysqli)); } session_start(); $sql = "SELECT * FROM jobs ORDER BY id DESC"; $result = $mysqli->query($sql); $num_rows = mysqli_num_rows($result); Now, first, I know that it is connecting properly because I'm not getting the die method plus I added an else conditional in there previously and it checked out. Then the page displays but I get the errors: Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 11 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 12 I've double-checked my database and there is a table called jobs with a row of "id" (it's the primary row). The thing that confuses me is this is code that I literally copied and pasted from another site I built and for some reason the code doesn't work on this one (I obviously copy and pasted it and then just changed the table name and rows accordingly). I saw the error and tried: $num_rows = $mysqli_result->num_rows; $row_array = $mysqli_result->fetch_array; and that fixed the errors but resulted in no data being passed (because obviously $mysqli_result has no value). I don't know why the error is calling for that (is it a difference in version of MySQL or PHP from the other site)? Can someone help me track down the problem? Thanks so much. Sorry if it's something super simple that I'm overlooking, I've been at it for a while.

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  • limiting mysql results by range of a specific key INCLUDING DUPLICATES

    - by aVC
    I have a query SELECT p.*, m.*, (SELECT COUNT(*) FROM newPhotoonAlert n WHERE n.userIDfor='$id' AND n.threadID=p.threadID and n.seen='0') AS unReadCount FROM posts p JOIN myMembers m ON m.id = p.user_id LEFT JOIN following f ON (p.user_id = f.user_id AND f.follower_id='$id' AND f.request='0' AND f.status='1') JOIN myMembers searcher ON searcher.id = '$id' WHERE ((f.follower_id = searcher.id) OR m.id='$id') AND p.flagged <'5' ORDER BY p.threadID DESC,p.positionID It brings result as expected but I want to add Another CLAUSE to limit the results. Say a sample (minimal shown) set of data looks like this with the above query. threadID postID positionID url 564 1254 2 a.com 564 1245 1 a1.com 541 1215 3 b1.com 541 1212 2 b2.com 541 1210 1 b3.com 523 745 1 c1.com 435 689 2 d2.com 435 688 1 a4.com 256 345 1 s3.com 164 316 1 f1.com . . I want to get ROWS corresponding to 2 DISTINCT threadIDs starting from MAX, but I want to include duplicates as well. Something like AND p.threadID IN (Select just Two of all threadIDs currently selected, but include duplicate rows) So my result should be threadID postID positionID url 564 1254 2 a.com 564 1245 1 a1.com 541 1215 3 b1.com 541 1212 2 b2.com 541 1210 1 b3.com

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  • Mysql configuration problem

    - by jazzrai
    I have being trying since last night. At first it was working but this morning again its not working. I am installing mysql version 5.0 on vista machine. when i try to configure its says that: The security settings could not be applied to the database because the connnection had failed with the following error: Error Nr. 1045 access denied for user 'root'@'localhost'(using password:yes) if a personal firewall is runnig on your machine plaes make sure you have opened the tcp port 3306 for connections. otherwise no client applicaion can connect to the server. after you have opened the port please press retry to apply the secirity settings. if you are re-installing after you just installed the mysql server please not that the data directory was not removed automatically. therefore the old password from your last installation is still needed to connect to the server. in this case please select skip now and re-run the configuration wizard from the start menu. i tried disabling the wirefall, user accounts but getting the same error. can anyone suggest me something please.

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  • Unable to change two things about a single row in mysql with php

    - by user1624005
    Here's the code: $id = intval($_POST['id']); $score = "'" . $_POST['score'] . "'"; $shares = "'" . $_POST['shares'] . "'"; $conn = new PDO('mysql:host=localhost;dbname=news', 'root', ''); $stmt = $conn->prepare("UPDATE news SET 'shares' = :shares, 'score' = :score WHERE id = :id"); $stmt -> execute(array( 'shares' => $shares, 'score' => $score, 'id' => $id )); And it doesn't work. I am unsure as to how I would see the error that I assume mysql is giving somewhere, and I've tried everything I could think of. Using double quotes and adding the variables into the statement right away. Adding single quotes to shares and score. How am I supposed to be doing this?

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  • A couple PHP/MySQL questions...

    - by Jeff
    I am a college student taking a course in php and mysql progamming and my first question is about the "$variable" variables in the following code: <?php ob_start(); ?> <?php session_start(); if ($_SESSION['auth'] != "true") { header("Location: login.php"); exit; } $uid = $_SESSION['user']; $connection = mysql_connect("localhost", "username", "password"); mysql_select_db("username", $connection); $result = mysql_query ( "SELECT * FROM users where user_id = '$uid'", $connection); $num = mysql_numrows($result); $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"firstname"); $f2=mysql_result($result,$i,"lastname"); ?> <html><body> <p> <td><center><font size = "18" face="Arial"><?php echo "Name: $f1 "; echo $f2; ?> </font></center></td> </p> </body></html> <?php $i++; } ?> <?php $result1 = mysql_query ( "SELECT * FROM phone where user_id = '$uid'", $connection); $num1 = mysql_numrows($result1); $j=0; while ($j < $num1) { $f3=mysql_result($result1,$j,"type"); $f4=mysql_result($result1,$j,"number"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f5: "; echo "($f3) "; echo "$f4 <br />"; ?> </font></center></td> </p> </body></html> <?php $j++; } ?> <?php $result2 = mysql_query ( "SELECT * FROM address where user_id = '$uid'", $connection); $num2 = mysql_numrows($result2); $h=0; while ($h < $num2) { $f6=mysql_result($result2,$h,"type"); $f7=mysql_result($result2,$h,"address"); $f8=mysql_result($result2,$h,"city"); $f9=mysql_result($result2,$h,"state"); $f10=mysql_result($result2,$h,"zip"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f10 Address: $f6, $f7, $f8 $f9"; ?></font></center></td> </p> </body></html> <?php $h++; } ?> <?php include 'navbar.php'; ob_end_flush(); ?> I just don't really understand the $variables at all. Are they user-generated or are they entities in the database? And how does the code know which $result is which? My second question is that, if this was someone else in my class's code and I wanted to modify it to make it my own and substitute my own variables, how would I go about doing that? Do the $variables need to be changed if they are not user-defined and if so, how? I apologize if these are dumb questions, but I am a beginner at this programming language. Thanks in advance for your help. -Jeff

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  • Mysql table data problem?

    - by DaTeNtImE
    I'm new to mysql and was wondering how can I add the users birthdate in the following HTML format to the MYSQL table data listed below? How would the structure look like for example email VARCHAR(80) NOT NULL,? Here is the HTML code below. <li><label>Date of Birth: </label> <label for="month">Month: </label> <select name="month" id="month"> <option value="January">January</option> <option value="February">February</option> <option value="March">March</option> <option value="April">April</option> <option value="May">May</option> <option value="June">June</option> <option value="July">July</option> <option value="August">August</option> <option value="September">September</option> <option value="October">October</option> <option value="November">November</option> <option value="December">December</option> </select> <label for="day">Day: </label> <select id="day" name="day"> <option value="0" selected="selected">Day</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <label for="year">Year: </label><input type="text" name="year" id="year" /></li> Here is the MySQL table data. CREATE TABLE users ( user_id INT UNSIGNED NOT NULL AUTO_INCREMENT, first_name VARCHAR(20) NOT NULL, last_name VARCHAR(40) NOT NULL, email VARCHAR(80) NOT NULL, pass CHAR(40) NOT NULL, user_level TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, active CHAR(32), registration_date DATETIME NOT NULL, PRIMARY KEY (user_id), UNIQUE KEY (email), INDEX login (email, pass) );

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  • MySQL COUNT help

    - by space
    I'm trying to count all the ids form table3 that are related to the first two tables but I think my SQL code is wrong can some one help me fix it? Here is the code: $dbc = mysqli_query($mysqli,"SELECT table1.*, table2.*, COUNT(id) as num, table3.id FROM table1 INNER JOIN table2 ON table1.id = table2.id INNER JOIN table3 ON table2.id = table3.id WHERE table2.id = '$id'"); Here is the error message. Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 4

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  • SQL Joining Two or More from Table B with Common Data in Table A

    - by Matthew Frederick
    The real-world situation is a series of events that each have two or more participants (like sports teams, though there can be more than two in an event), only one of which is the host of the event. There is an Event db table for each unique event and a Participant db table with unique participants. They are joined together using a Matchup table. They look like this: Event EventID (PK) (other event data like the date, etc.) Participant ParticipantID (PK) Name Matchup EventID (FK to Event table) ParicipantID (FK to Participant) Host (1 or 0, only 1 host = 1 per EventID) What I'd like to get as a result is something like this: EventID ParticipantID where host = 1 Participant.Name where host = 1 ParticipantID where host = 0 Participant.Name where host = 0 ParticipantID where host = 0 Participant.Name where host = 0 ... Where one event has 2 participants and another has 3 participants, for example, the third participant column data would be null or otherwise noticeable, something like (PID = ParticipantID): EventID PID-1(host) Name-1 (host) PID-2 Name-2 PID-3 Name-3 ------- ----------- ------------- ----- ------ ----- ------ 1 7 Lions 8 Tigers 12 Bears 2 11 Dogs 9 Cats NULL NULL I suspect the answer is reasonably straightforward but for some reason I'm not wrapping my head around it. Alternately it's very difficult. :) I'm using MYSQL 5 if that affects the available SQL.

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  • Help with SQL Query

    - by djfrear
    With regards to the following statement: Select * From explorer.booking_record booking_record_ Inner Join explorer.client client_ On booking_record_.labelno = client_.labelno Inner Join explorer.tour_hotel tour_hotel_ On tour_hotel_.tourcode = booking_record_.tourrefcode Inner Join explorer.hotelrecord hotelrecord_ On tour_hotel_.hotelcode = hotelrecord_.hotelref Where booking_record_.bookingdate Not Like '0000-00-00' And booking_record_.tourdeparturedate Not Like '0000-00-00' And hotelrecord_.hotelgroup = "LPL" And Year(booking_record_.tourdeparturedate) Between Year(AddDate(Now(), Interval -5 Year)) And Year(Now()) My MySQL skills are certainly not up to scratch, the actual result set I wish to find is "a customer who has been to 5 or more LPL hotels in the past 5 years". So far I havent got as far as dealing with the count as I'm getting a huge number of results with some 250+ per customer. I assume this is to do with the way I'm joining tables. Schema wise the booking_record table contains a tour reference code, which links to tour_hotel which then contains a hotelcode which links to hotelrecord. This hotelrecord table contains the hotelgroup. The client table is joined to the booking_record via a booking reference and a client may have many bookings. If anyone could suggest a way for me to do this I'd be very grateful and hopefully learn enough to do it myself next time! I've been scratching my head over this one for a few hours now! Customers may have many bookings within booking_record Daniel.

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  • How can I track the last location of a shipment effeciently using latest date of reporting?

    - by hash
    I need to find the latest location of each cargo item in a consignment. We mostly do this by looking at the route selected for a consignment and then finding the latest (max) time entered against nodes of this route. For example if a route has 5 nodes and we have entered timings against first 3 nodes, then the latest timing (max time) will tell us its location among the 3 nodes. I am really stuck on this query regarding performance issues. Even on few hundred rows, it takes more than 2 minutes. Please suggest how can I improve this query or any alternative approach I should acquire? Note: ATA= Actual Time of Arrival and ATD = Actual Time of Departure SELECT DISTINCT(c.id) as cid,c.ref as cons_ref , c.Name, c.CustRef FROM consignments c INNER JOIN routes r ON c.Route = r.ID INNER JOIN routes_nodes rn ON rn.Route = r.ID INNER JOIN cargo_timing ct ON c.ID=ct.ConsignmentID INNER JOIN (SELECT t.ConsignmentID, Max(t.firstata) as MaxDate FROM cargo_timing t GROUP BY t.ConsignmentID ) as TMax ON TMax.MaxDate=ct.firstata AND TMax.ConsignmentID=c.ID INNER JOIN nodes an ON ct.routenodeid = an.ID INNER JOIN contract cor ON cor.ID = c.Contract WHERE c.Type = 'Road' AND ( c.ATD = 0 AND c.ATA != 0 ) AND (cor.contract_reference in ('Generic','BP001','020-543-912')) ORDER BY c.ref ASC

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  • Adding one subquery makes query a little slower, adding another makes it way slower

    - by Jason Swett
    This is fast: select ba.name, penamt.value penamt, #address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id #join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 And this is fast: select ba.name, #penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id #join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 But this is slow: select ba.name, penamt.value penamt, address_line4.value address_line4 from account a join customer c on a.customer_id = c.id join branch br on a.branch_id = br.id join bank ba on br.bank_id = ba.id join account_address aa on aa.account_id = a.id join address ad on aa.address_id = ad.id join state s on ad.state_id = s.id join import i on a.import_id = i.id join import_bundle ib on i.import_bundle_id = ib.id join (select * from unused where heading_label = 'PENAMT') penamt ON penamt.account_id = a.id join (select * from unused where heading_label = 'Address Line 4') address_line4 ON address_line4.account_id = a.id where i.active=1 Why is it fast when I include just one of the two subqueries but slow when I include both? I would think it should be twice as slow when I include both, but it takes a really long time. On on MySQL.

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  • I have created a PHP script and I am lacking to extract the primary key, I have given flow below, pl

    - by Parth
    I am using MySQL DB, working for Joomla, My requirement is tracking the activity like insert/update/delete on any table and store it in another audit table using triggers, i.e. I am doing Auditing. DB's table structure: Few tables dont have any PK nor auto increment key Flow of my script is : I fetch out all table from DB. I check whether the table have any trigger or not. If yes then it moves to check nfor next table and so on. If it does'nt find any trigger then it creates the triggers for the table, such that, -it first checks if the table has any primary key or not(for inserting in Tracking audit table for every change made) if it has the primary key then it uses it further in creation of trigger. if it doesnt find any PK then it proceeds further in creating the trigger without inserting any id in audit table Now here, My problem is I need the PK every time so that I can record the id of any particular table in which the insert/update/delete is performed, so that further i can use this audit track table to replicate in production DB.. Now as I haave mentioned earlier that I am not available with PK/auto-incremented in some table, then what should I do get the particular id in which change is done? please guide me...GEEKS!!!

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  • How can I use SQL to select duplicate records, along with counts of related items?

    - by mipadi
    I know the title of this question is a bit confusing, so bear with me. :) I have a (MySQL) database with a Person record. A Person also has a slug field. Unfortunately, slug fields are not unique. There are a number of duplicate records, i.e., the records have different IDs but the same first name, last name, and slug. A Person may also have 0 or more associated articles, blog entries, and podcast episodes. If that's confusing, here's a diagram of the structure: I would like to produce a list of records that match this criteria: duplicate records (i.e., same slug field) for people who also have at least 1 article, blog entry, or podcast episode. I have a SQL query that will list all records with the same slug fields: SELECT id, first_name, last_name, slug, COUNT(slug) AS person_records FROM people_person GROUP BY slug HAVING (COUNT(slug) > 1) ORDER BY last_name, first_name, id; But this includes records for people that may not have at least 1 article, blog entry, or podcast. Can I tweak this to fit the second criteria?

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  • Querying calender events even if they do not have any for the day

    - by StealthRT
    Hey everyone, i am trying to figure out a way of query my mysql server so that even if a company does not have anything posted for the day the user clicks on their logo, it still adds them to the list. That sounds a little confusing so let me try to explain it another way. Say i have 3 company's in my database: Comp1 Comp2 Comp3 And Comp1 & Comp3 have something for today on the calender but Comp2 does not. I still need it to populate and place that company on the page but have something along the lines of "nothing on the calender for today". The other 2 companys (Comp1 & Comp3) would show the calender posting for that day. This is the code i have right now: SELECT clientinfo.id, clientinfo.theCompName, clientinfo.theURL, clientinfo.picURL, clientinfo.idNumber, clientoffers.idNumber, clientoffers.theDateStart, clientoffers.theDateEnd FROM clientinfo, clientoffers WHERE clientinfo.accountStats = 'OPEN' AND clientinfo.idNumber = clientinfo.idNumber AND '2010-05-08' BETWEEN clientoffers.theDateStart AND clientoffers.theDateEnd GROUP BY clientinfo.idNumber ORDER BY clientinfo.theCompName ASC That executes just fine but for Comp2, it just places the calender info from Comp1 into it when it really doesn't have anything. The output looks like this: Comp1 | 2010-05-08 | this is the calender event 1 | etc etc Comp2 | 2010-05-08 | this is the calender event 1 | etc etc comp3 | 2010-05-09 | this is the calender event 2 | etc etc Any help would be great :o) David

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  • Ultra-grand super acts_as_tree rails query

    - by Bloudermilk
    Right now I'm dealing with an issue regarding an intense acts_as_tree MySQL query via rails. The model I am querying is Foo. A Foo can belong to any one City, State or Country. My goal is to query Foos based on their location. My locations table is set up like so: I have a table in my database called locations I use a combination of acts_as_tree and polymorphic associations to store each individual location as either a City, State or Country. (This means that my table consists of the rows id, name, parent_id, type) Let's say for instance, I want to query Foos in the state "California". Beside Foos that directly belong to "California", I should get all Foos that belong every City in "California" like Foos in "Los Angeles" and "San Francisco". Not only that, but I should get any Foos that belong to the Country that "California" is in, "United States". I've tried a few things with associations to no avail. I feel like I'm missing some super-helpful Rails-fu here. Any advice?

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  • Trying to build a dynamic PHP mysql_query string to update a row and getting back the updated row

    - by adardesign
    I have a form that jQuery tracks the onChage .change() event so when something is changed it runs a ajax request and i pass in the column, id, and the values in the url. Here i have the PHP code that should update the data. My question is now how do i build the mySQl string dynamically. and how do i echo back the changes/updates that where just changed on the db. Here is the PHP code i am trying to work with. <?php require_once('Connections/connect.php'); ?> <?php $id = $_GET['id']; $collumn = $_GET['collumn']; $val = $_GET['val']; ?> <?php mysql_select_db($myDB, $connection); // here i try to build the query string and pass in the passed in values $sqlUpdate = 'UPDATE `plProducts`.`allPens` SET `$collumn` = '$val' WHERE `allPens`.`prodId` = '$id' LIMIT 1;'; // here i want to echo back the updated row (or the updated data) $seeResults = mysql_query($sqlUpdate, $connection); echo $seeResults ?>

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  • Database – Beginning with Cloud Database As A Service

    - by Pinal Dave
    I love my weekend projects. Everybody does different activities in their weekend – like traveling, reading or just nothing. Every weekend I try to do something creative and different in the database world. The goal is I learn something new and if I enjoy my learning experience I share with the world. This weekend, I decided to explore Cloud Database As A Service – Morpheus. In my career I have managed many databases in the cloud and I have good experience in managing them. I should highlight that today’s applications use multiple databases from SQL for transactions and analytics, NoSQL for documents, In-Memory for caching to Indexing for search.  Provisioning and deploying these databases often require extensive expertise and time.  Often these databases are also not deployed on the same infrastructure and can create unnecessary latency between the application layer and the databases.  Not to mention the different quality of service based on the infrastructure and the service provider where they are deployed. Moreover, there are additional problems that I have experienced with traditional database setup when hosted in the cloud: Database provisioning & orchestration Slow speed due to hardware issues Poor Monitoring Tools High network latency Now if you have a great software and expert network engineer, you can continuously work on above problems and overcome them. However, not every organization have the luxury to have top notch experts in the field. Now above issues are related to infrastructure, but there are a few more problems which are related to software/application as well. Here are the top three things which can be problems if you do not have application expert: Replication and Clustering Simple provisioning of the hard drive space Automatic Sharding Well, Morpheus looks like a product build by experts who have faced similar situation in the past. The product pretty much addresses all the pain points of developers and database administrators. What is different about Morpheus is that it offers a variety of databases from MySQL, MongoDB, ElasticSearch to Reddis as a service.  Thus users can pick and chose any combination of these databases.  All of them can be provisioned in a matter of minutes with a simple and intuitive point and click user interface.  The Morpheus cloud is built on Solid State Drives (SSD) and is designed for high-speed database transactions.  In addition it offers a direct link to Amazon Web Services to minimize latency between the application layer and the databases. Here are the few steps on how one can get started with Morpheus. Follow along with me.  First go to http://www.gomorpheus.com and register for a new and free account. Step 1: Signup It is very simple to signup for Morpheus. Step 2: Select your database   I use MySQL for my daily routine, so I have selected MySQL. Upon clicking on the big red button to add Instance, it prompted a dialogue of creating a new instance.   Step 3: Create User Now we just have to create a user in our portal which we will use to connect to a database hosted at Morpheus. Click on your database instance and it will bring you to User Screen. Over here you will notice once again a big red button to create a new user. I created a user with my first name.   Step 4: Configure your MySQL client I used MySQL workbench and connected to MySQL instance, which I had created with an IP address and user.   That’s it! You are connecting to MySQL instance. Now you can create your objects just like you would create on your local box. You will have all the features of the Morpheus when you are working with your database. Dashboard While working with Morpheus, I was most impressed with its dashboard. In future blog posts, I will write more about this feature.  Also with Morpheus you use the same process for provisioning and connecting with other databases: MongoDB, ElasticSearch and Reddis. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL

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  • C# 4 Named Parameters for Overload Resolution

    - by Steve Michelotti
    C# 4 is getting a new feature called named parameters. Although this is a stand-alone feature, it is often used in conjunction with optional parameters. Last week when I was giving a presentation on C# 4, I got a question on a scenario regarding overload resolution that I had not considered before which yielded interesting results. Before I describe the scenario, a little background first. Named parameters is a well documented feature that works like this: suppose you have a method defined like this: 1: void DoWork(int num, string message = "Hello") 2: { 3: Console.WriteLine("Inside DoWork() - num: {0}, message: {1}", num, message); 4: } This enables you to call the method with any of these: 1: DoWork(21); 2: DoWork(num: 21); 3: DoWork(21, "abc"); 4: DoWork(num: 21, message: "abc"); and the corresponding results will be: Inside DoWork() - num: 21, message: Hello Inside DoWork() - num: 21, message: Hello Inside DoWork() - num: 21, message: abc Inside DoWork() - num: 21, message: abc This is all pretty straight forward and well-documented. What is slightly more interesting is how resolution is handled with method overloads. Suppose we had a second overload for DoWork() that looked like this: 1: void DoWork(object num) 2: { 3: Console.WriteLine("Inside second overload: " + num); 4: } The first rule applied for method overload resolution in this case is that it looks for the most strongly-type match first.  Hence, since the second overload has System.Object as the parameter rather than Int32, this second overload will never be called for any of the 4 method calls above.  But suppose the method overload looked like this: 1: void DoWork(int num) 2: { 3: Console.WriteLine("Inside second overload: " + num); 4: } In this case, both overloads have the first parameter as Int32 so they both fulfill the first rule equally.  In this case the overload with the optional parameters will be ignored if the parameters are not specified. Therefore, the same 4 method calls from above would result in: Inside second overload: 21 Inside second overload: 21 Inside DoWork() - num: 21, message: abc Inside DoWork() - num: 21, message: abc Even all this is pretty well documented. However, we can now consider the very interesting scenario I was presented with. The question was what happens if you change the parameter name in one of the overloads.  For example, what happens if you change the parameter *name* for the second overload like this: 1: void DoWork(int num2) 2: { 3: Console.WriteLine("Inside second overload: " + num2); 4: } In this case, the first 2 method calls will yield *different* results: 1: DoWork(21); 2: DoWork(num: 21); results in: Inside second overload: 21 Inside DoWork() - num: 21, message: Hello We know the first method call will go to the second overload because of normal method overload resolution rules which ignore the optional parameters.  But for the second call, even though all the same rules apply, the compiler will allow you to specify a named parameter which, in effect, overrides the typical rules and directs the call to the first overload. Keep in mind this would only work if the method overloads had different parameter names for the same types (which in itself is weird). But it is a situation I had not considered before and it is one in which you should be aware of the rules that the C# 4 compiler applies.

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  • Training on Demand Certification Packages for DBAs

    - by Antoinette O'Sullivan
    The demand for Database Administrators continues to grow.*Almost two-thirds of IT hiring managers indicate that they highly value certifications in validatingIT skills and expertise.** * Job satisfaction and DBA work growth rate: CNN Money's 2011 Best Jobs in America survey.** Survey among nearly 1,700 respondents by CompTIA, the nonprofit trade association for the IT industry, cited in Certification Magazine, Feb. 14 th., 2012. Get Certified with Training on DemandAre you an experienced Database professional eager to achieve certification?Is time your most precious resource?Then try our new Training On Demand Certification Value Package with 20% discount. These all-in-one packages give you everything you need to get certified with success: Why Training On Demand:  Expert training from Oracle’s top instructors Sophisticated streaming video recording Available for 90 days, 24 hours a day, 7 days a week White boarding and training labs for hands-on experience Start, stop, pause, jump or rewind sections of the course as needed  Oracle University instructor Q&A  A full-text search leads to the right video fragment in a matter of seconds. Watch this demo to see how it works. Additional Certification resources: Benefits of Oracle Certification Database Certification Paths Available Database Certification Exams Getting certified has never been easier!For assistance contact your local Oracle University Service Desk. Many organizations deploy both Oracle Database and MySQL side by side to serve different needs, and as a database professional you can find training courses on both topics at Oracle University! Check out the upcoming Oracle Database 11g training courses and MySQL training courses. Even if you're only managing Oracle Databases at this point of time, getting familiar with MySQL Database will broaden your career path with growing job demand. These Value Packages are also available with the following training formats: In-Class, Live Virtual Class and Self Study: MySQL Database Administration Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand MySQL Database Administrator Certification Value Package View Package View Package View Package View Package MySQL Developer Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand       MySQL Developer Certification Value Package View Package View Package     Oracle Database 10g Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database 10g Administrator Certified Associate Certification Value Package View Package View Package View Package   Oracle Database 10g Administrator Certified Professional Certification Value Package View Package View Package View Package   Oracle Database 11g Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database 11g Administrator Certified Associate Certification Value Package View Package View Package View Package View Package Oracle Database 11g Administrator Certified Professional Certification Value Package View Package View Package View Package View Package Exam Prep Seminar Value Package: Oracle Database Admin 1       View Package Oracle Database 11g Administrator Certified Professional UPGRADE Certification Value Package       View Package Oracle Real Application Clusters 11g and Grid Infrastructure Administraton Certified Expert Certification Value Package       View Package Exam Prep Seminar Value Package: Oracle Database Admin 2        View Package Exam Prep Seminar Value Package: Oracle RAC 11g and Grid Infrastructure Administration       View Package Exam Prep Seminar Value Package: Upgrade Oracle Certified Professional (OCP) to Oracle Database 11g       View Package SQL and PL/SQL Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database Sql Expert Certification Value Package View Package View Package View Package View Package Exam Prep Seminar Value Package: Oracle Database SQL       View Package View our Certification Value Packages Mention this code at the time of booking: E1245 Connect For a full list of MySQL Training courses and events, go to http://oracle.com/education/mysql.

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  • $.fadeTo/fadeOut() operations on Table Rows in IE fail

    - by Rick Strahl
    Here’s a a small problem that one of customers ran into a few days ago: He was playing around with some of the sample code I’ve put out for one of my simple jQuery demos which deals with providing a simple pulse behavior plug-in: $.fn.pulse = function(time) { if (!time) time = 2000; // *** this == jQuery object that contains selections $(this).fadeTo(time, 0.20, function() { $(this).fadeTo(time, 1); }); return this; } it’s a very simplistic plug-in and it works fine for simple pulse animations. However he ran into a problem where it didn’t work when working with tables – specifically pulsing a table row in Internet Explorer. Works fine in FireFox and Chrome, but IE not so much. It also works just fine in IE as long as you don’t try it on tables or table rows specifically. Applying against something like this (an ASP.NET GridView): var sel = $("#gdEntries>tbody>tr") .not(":first-child") // no header .not(":last-child") // no footer .filter(":even") .addClass("gridalternate"); // *** Demonstrate simple plugin sel.pulse(2000); fails in IE. No pulsing happens in any version of IE. After some additional experimentation with single rows and various ways of selecting each and still failing, I’ve come to the conclusion that the various fade operations in jQuery simply won’t work correctly in IE (any version). So even something as ‘elemental’ as this: var el = $("#gdEntries>tbody>tr").get(0);$(el).fadeOut(2000); is not working correctly. The item will stick around for 2 seconds and then magically disappear. Likewise: sel.hide().fadeIn(5000); also doesn’t fade in although the items become immediately visible in IE. Go figure that behavior out. Thanks to a tweet from red_square and a link he provided here is a grid that explains what works and doesn’t in IE (and most last gen browsers) regarding opacity: http://www.quirksmode.org/js/opacity.html It appears from this link that table and row elements can’t be made opaque, but td elements can. This means for the row selections I can force each of the td elements to be selected and then pulse all of those. Once you have the rows it’s easy to explicitly select all the columns in those rows with .find(“td”). Aha the following actually works: var sel = $("#gdEntries>tbody>tr") .not(":first-child") // no header .not(":last-child") // no footer .filter(":even") .addClass("gridalternate"); // *** Demonstrate simple plugin sel.find("td").pulse(2000); A little unintuitive that, but it works. Stay away from <table> and <tr> Fades The moral of the story is – stay away from TR, TH and TABLE fades and opacity. If you have to do it on tables use the columns instead and if necessary use .find(“td”) on your row(s) selector to grab all the columns. I’ve been surprised by this uhm relevation, since I use fadeOut in almost every one of my applications for deletion of items and row deletions from grids are not uncommon especially in older apps. But it turns out that fadeOut actually works in terms of behavior: It removes the item when the timeout’s done and because the fade is relatively short lived and I don’t extensively test IE code any more I just never noticed that the fade wasn’t happening. Note – this behavior or rather lack thereof appears to be specific to table table,tr,th elements. I see no problems with other elements like <div> and <li> items. Chalk this one up to another of IE’s shortcomings. Incidentally I’m not the only one who has failed to address this in my simplistic plug-in: The jquery-ui pulsate effect also fails on the table rows in the same way. sel.effect("pulsate", { times: 3 }, 2000); and it also works with the same workaround. If you’re already using jquery-ui definitely use this version of the plugin which provides a few more options… Bottom line: be careful with table based fade operations and remember that if you do need to fade – fade on columns.© Rick Strahl, West Wind Technologies, 2005-2010Posted in jQuery  

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  • Master Page: Dynamically Adding Rows in ASP Table on Button Click event

    - by Vincent Maverick Durano
    In my previous post here, I wrote an example that demonstrates how are we going to generate table rows dynamically using ASP Table on click of the Button control. Now based on some comments in my previous example and in the forums they wanted to implement it within Masterpage. Unfortunately the code in my previous example doesn't work in Masterpage for the following main reasons: The Table is dynamically added within the Form tag and so the TextBox control will not be generated correcty in the page. The data will not be retained on each and every postbacks because the SetPreviousData() method is looking for the Table element within the Page and not on the MasterPage. The Request.Form key value should be set correctly since all controls within the master page are prefixed with the naming containter ID to prevent duplicate ids on the final rendered HTML. For example the TextBox control with the ID of TextBoxRow will turn to ID to this ctl00$MainBody$TextBoxRow. In order for the previous example to work within Masterpage then we will have to correct those three main reasons above and this post will guide you how to correct it. Suppose we have this content page declaration below:   <asp:Content ID="Content1" ContentPlaceHolderID="MainHead" Runat="Server"> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainBody" Runat="Server"> <asp:PlaceHolder ID="PlaceHolder1" runat="server"> <asp:Button ID="BTNAdd" runat="server" Text="Add New Row" OnClick="BTNAdd_Click" /> </asp:PlaceHolder> </asp:Content> As you notice I've added a PlaceHolder control within the MainBody ContentPlaceHolder. This is because we are going to generate the Table in the PlaceHolder instead of generating it within the Form element. Now since issue #1 is already corrected then let's proceed to the code beind part. Here are the full code blocks below:     using System; using System.Web.UI; using System.Web.UI.WebControls; public partial class DynamicControlDemo : System.Web.UI.Page { private int numOfRows = 1; protected void Page_Load(object sender, EventArgs e) { //Generate the Rows on Initial Load if (!Page.IsPostBack) { GenerateTable(numOfRows); } } protected void BTNAdd_Click(object sender, EventArgs e) { if (ViewState["RowsCount"] != null) { numOfRows = Convert.ToInt32(ViewState["RowsCount"].ToString()); GenerateTable(numOfRows); } } private void SetPreviousData(int rowsCount, int colsCount) { Table table = (Table)this.Page.Master.FindControl("MainBody").FindControl("Table1"); // **** if (table != null) { for (int i = 0; i < rowsCount; i++) { for (int j = 0; j < colsCount; j++) { //Extracting the Dynamic Controls from the Table TextBox tb = (TextBox)table.Rows[i].Cells[j].FindControl("TextBoxRow_" + i + "Col_" + j); //Use Request object for getting the previous data of the dynamic textbox tb.Text = Request.Form["ctl00$MainBody$TextBoxRow_" + i + "Col_" + j];//***** } } } } private void GenerateTable(int rowsCount) { //Creat the Table and Add it to the Page Table table = new Table(); table.ID = "Table1"; PlaceHolder1.Controls.Add(table);//****** //The number of Columns to be generated const int colsCount = 3;//You can changed the value of 3 based on you requirements // Now iterate through the table and add your controls for (int i = 0; i < rowsCount; i++) { TableRow row = new TableRow(); for (int j = 0; j < colsCount; j++) { TableCell cell = new TableCell(); TextBox tb = new TextBox(); // Set a unique ID for each TextBox added tb.ID = "TextBoxRow_" + i + "Col_" + j; // Add the control to the TableCell cell.Controls.Add(tb); // Add the TableCell to the TableRow row.Cells.Add(cell); } // And finally, add the TableRow to the Table table.Rows.Add(row); } //Set Previous Data on PostBacks SetPreviousData(rowsCount, colsCount); //Sore the current Rows Count in ViewState rowsCount++; ViewState["RowsCount"] = rowsCount; } }   As you observed the code is pretty much similar to the previous example except for the highlighted lines above. That's it! I hope someone find this post usefu! Technorati Tags: Dynamic Controls,ASP.NET,C#,Master Page

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  • Export from EndNote into MySQL database

    - by Tomba
    I would like to export some records from an EndNote (reference management software) library and import into a MySQL database. Does anyone have any experience with this? I've tried creating custom EndNote "output styles" containing either comma-delimited values or even SQL code, but have had mixed results, either because EndNote filters out some characters (like `) or because EndNote doesn't (or I can't work out how to make it) escape text, which might include characters like ' and ". I realize this might be a bit off-topic but any help would be appreciated.

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