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  • Make the Time

    - by WonderOfItAll
    Took the little one to the pool tonight for swim lessons. Okay, Okay. They're not really lessons so much as they are "Hey, here's a few bucks, let me rent out a small section of your pool to swim around with my little one" Saw a dad at the pool. Bluetooth on, iPad in hand, and two year old somewhere around there. Saw a mom at the pool. Arguing with her five year old to NOT take a shower after swimming. Bluetooth on, iPad in hand, work laptop open on stadium seats. Her reasoning for not wanting the child to shower "Look, I have to get this stuff to the office by 6:30, we don't have time for you to shower. Let's go" Wait, isn't the whole point of this little experience called Mommy and Me (or, as in my case, Daddy and Me). Wherein Mommy/Daddy is supposed to spend time with little one. Not with the Bluetooth. Not with the work laptop. Dad (yeah, the same dad from earlier), in the pool. Bluetooth off (it's not waterproof or I'm sure he would've had it on), two year old in hand and iPad somewhere put away. Getting frustrated with kid because he won't 'perform' on command. Here's a little exchange Kid: "I don't wanna get in the water" Dad: "Well, we're here for 30 minutes, get in the water" Kid: "No, don't wanna" Dad: "Fine, I'm getting in" and, true to his word, in he goes, off to swim. Kid: Crying Dad: "Well, c'mon" Kid: Walking to stands Dad: Ignoring kid Kid: At stands Dad: Out of pool, drying off. Frustrated. Grabs bag, grabs kid, leaves How sad. It really seems like I am living in a generation of parents who view their children as one big scheduled distraction to another. It's almost like the dad was saying "Look, little 2 year old boy, I have a busy scheduled. Right now my Outlook Calendar tells me that I have 30 mins to spend with you, so, let's go kid: PERFORM because I have the time" Really? Can someone please tell me when the hell this happened? When did spending time with your kid, spending time with your family, spending time with your spouse, etc... become a distraction? I've seen people at work all day Tweeting throughout the day, checked in with Four Square, IM up and running constantly so they can 'stay in touch' only to see these same folks come home and be irritated because their kids or their spouse wants to connect with the. I've seen these very same people leave the house, go to the corner bar/store/you-name-the-place to be 'alone' only to find them there, plugged in, tweeting away, etc, etc, etc I LOVE technology. I love working with technology. But I also know that I am a human being. A person who, by very definition, is a social being. I needed social interactions and contact--and, no, I'm not talking about the Social Graph kind of connections, I'm talking about those interactions which, *GASP* involve eye to eye contact and human contact. A recent study found that the number one complaint of kids is that they feel they have to compete with technology for their parents time and attention. The number one wish from high school kids? That there parents would turn off the computer/tv/cell phone at dinner. This, coming from high school kids. Shouldn't that tell you a whole helluva lot? So, do yourself a favor tomorrow. Plug into technology all day. Throw yourself into it. Be passionate about what you do. When you walk through the door to your family, turn it all off for 30 mins and be there with your loved ones. If you can manage to play Angry Birds, I'm sure you can handle being disconnected for 30 minutes. Make the time

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  • Drive

    - by erikanollwebb
    Picking up where we left off, let's summarize.  People have both intrinsic motivation and extrinsic motivation, and whether reward works depends a bit on what you are rewarding.  Rewards don't decreased intrinsic motivation provided you know what you are getting and why, and when you reward high performance.  But as anyone who has watched the great animation of Dan Pink's TED talk knows, even that doesn't tell the whole story.  Although people may not be less intrinsically motivated by rewards, the impact of rewards on actual performance is a really odd questions.  Larger rewards don't necessarily lead to better performance and in fact, some times lead to worse performance.  Pink argues that people are driven and engaged when they have autonomy, mastery and purpose.  If they can self-direct and can be good at what they do and have a sense of purpose for what they are doing, they show the highest engagement.   (Personally, I would add progress to the list.  My experience is that if you have autonomy, mastery and a sense of purpose but don't get a feeling that you are making any progress day to day, your level of engagement will drop rapidly.) So Pink is arguing if we could set up work so that people have a sense of purpose in what they do, have some autonomy and the ability to build mastery, you'll have better companies.  And that's probably true in a lot of ways, but there's a problem.  Sometimes, you have things you need to do but maybe you don't really want to do.  Or that you don't really see the point of.  Or that doesn't have a lot of value to you at the end of the day.  Then what does a company do?  Let me give you an example.  I've worked on some customer relationship management (CRM) tools over the years and done user research with sales people to try and understand their world.  And there's a funny thing about sales tools in CRM.  Sometimes what the company wants a sales person to do is at odds with what a sales person thinks is useful to them.  For example, companies would like to know who a sales person talked to at the company and the person level.  They'd like to know what they talked about, when, and whether the deals closed.  Those metrics would help you build a better sales force and understand what works and what does not.  But sales people see that as busy work that doesn't add any value to their ability to sell.  So you have a sales person who has a lot of autonomy, they like to do things that improve their ability to sell and they usually feel a sense of purpose--the group is trying to make a quota!  That quota will help the company succeed!  But then you have tasks that they don't think fit into that equation.  The company would like to know more about what makes them successful and get metrics on what they do and frankly, have a record of what they do in case they leave, but the sales person thinks it's a waste of time to put all that information into a sales application. They have drive, just not for all the things the company would like.   You could punish them for not entering the information, or you could try to reward them for doing it, but you still have an imperfect model of engagement.  Ideally, you'd like them to want to do it.  If they want to do it, if they are motivated to do it, then the company wins.  If *something* about it is rewarding to them, then they are more engaged and more likely to do it.  So the question becomes, how do you create that interest to do something?

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  • Freetts problem in Java

    - by manugupt1
    I am trying to run a program using freetts. I am able to compile the program however I am not able to use kevin or mbrola voices I get the follwing o/p msgs at the end System property "mbrola.base" is undefined. Will not use MBROLA voices. LINE UNAVAILABLE: Format is pcm_signed 16000.0 Hz 16 bits 1 channel big endian

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  • MAC address need to add colons

    - by nan
    Kevin your response was helpful with the MAC address question. I wanted to ask you if you have like 2600 MAC address the formula you provided =LEFT(A2,2)&":"&MID(A2,3,2)&":"&MID(A2,5,2)&":"&MID(A2,7,2)&":"&MID(A2,9,2)&":"&RIGHT(A2,2) how do I replace A1 with blank so all of column A gets converted

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  • Javascript: find array by name

    - by Kin
    Hi, I have some js arrays and I want to find the arrays by name. for example: arr1 = [1,2,3]; arr2 = [3,4,5]; And access them like this: var intNum = 2; var arrName = 'arr' + intNum; arrName[0]; // equals 3 Is this possible? Thanks, Kevin

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  • jQuery $.ajax Not Working in IE8 but it works on FireFox & Chrome

    - by Sam3k
    I have the following ajax call which works perfectly in Firefox and Chrome but not IE: function getAJAXdates( startDate, numberOfNights, opts ) { var month = startDate.getMonth() + 1; var day = startDate.getDate(); var year = startDate.getFullYear(); var d = new Date(); var randNum = Math.floor(Math.random()*100000000); $.ajax({ type : "GET", dataType : "json", url : "/availability/ajax/bookings?rand="+randNum, cache : false, data : 'month='+month+'&day='+day+'&year='+year+'&nights='+numberOfNights, contentType : 'application/json; charset=utf8', success : function(data) { console.log('@data: '+data); insertCellData(data, opts, startDate); }, error:function(xhr, status, errorThrown) { console.log('@Error: '+errorThrown); console.log('@Status: '+status); console.log('@Status Text: '+xhr.statusText); } }); } I know for a fact that all the variables are passing the right content and $.ajax is indeed passing all the paramater/values. This is what I get on error: LOG: @Error: undefined LOG: @Status: parsererror LOG: @Status Text: OK I'm aware of the cache issue on IE and implemented a random paramater to clear it up. Finally these are the headers that are sent back from the backend: header('Content-Type: application/json; charset=utf8'); header("Cache-Control: no-cache"); header("Expires: 0"); header('Access-Control-Max-Age: 3628800'); header('Access-Control-Allow-Methods: GET, POST, PUT, DELETE');

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  • mongodb: insert if not exists

    - by LeMiz
    Hello, Every day, I receive a stock of documents (an update). What I want to do is inserting each of them if it does not exists. I also want to keep track of the first time I inserted them, and the last time I saw them in an update. I don't want to have duplicate documents. I don't want to remove a document which has previously been saved, but is not in my update. 95% (estimated) of the records are unmodified from day to day. I am using the python driver (pymongo), for that matter. What I currently do is (pseudo-code): for each document in update: existing_document = collection.find_one(document) if not existing_document: document['insertion_date'] = now else: document = existing_document document['last_update_date'] = now my_collection.save(document) My problem is that it is very slow (40 mins for less than 100 000 records, and I have millions of them in the update). I am pretty sure there is something builtin for doing this, but the document for update() is mmmhhh.... a bit terse.... ( http://www.mongodb.org/display/DOCS/Updating ) Can someone give an advice on doing it faster ?

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  • Highlighting dates between two selected dates jQuery UI Datepicker

    - by Ralph
    I have one datepicker with numberOfMonths set to 2. Arrival Date and Departure Date are determined using this logic (within onSelect): if ((count % 2)==0) { depart = $("#datepicker-1").datepicker('getDate'); if (arriv depart) { temp=arriv; arriv=depart; depart=temp; } $("#check-in").val($.datepicker.formatDate("DD, MM d, yy",arriv)); $("#check-out").val($.datepicker.formatDate("DD, MM d, yy",depart)); } else { arriv = $("#datepicker-1").datepicker('getDate'); depart = null; if ((arriv depart)&&(depart!=null)) { temp=arriv; arriv=depart; depart=temp; } $("#day-count").val(''); $("#check-in").val($.datepicker.formatDate("DD, MM d, yy",arriv)); $("#check-out").val($.datepicker.formatDate("DD, MM d, yy",depart)); } if(depart!=null) { diffDays = Math.abs((arriv.getTime() - depart.getTime())/(oneDay)); if (diffDays == 0) { $("#day-count").val((diffDays+1)+' Night/s'); } else { $("#day-count").val(diffDays+' Night/s'); } } Getting the number of days within these 2 dates has no problem What I want now is highlight those dates starting from the Arrival to Departure I tried working around the onSelect but had no luck. I am now using beforeShowDay to highlight these dates but I can't seem to figure it out Got a sample from here Basically, it is customized to highlight 11 or 12 days after the selected date (Here's the code from that link). $('#datePicker').datepicker({beforeShowDay: function(date) { if (selected != null && date.getTime() selected.getTime() && (date.getTime() - selected.getTime()) Since I am new to using the UI, and the logic is not clear to me yet, I can't seem to figure this out. Any ideas on how I can make this highlight dates between the Arrival and Departure using my aforementioned logic used in determining the two?

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  • Schedule multiple events with NSTimer?

    - by AWright4911
    I have a schedule cache stored in a pList. For the example below, I have a schedule time of April 13, 2010 2:00PM and Aril 13, 2010 2:05PM. How can I add both of these to a queue to fire on their own? item 0 -Hour --14 -Minute --00 -Month --04 -Day --13 -Year --2010 item 1 -Hour --14 -Minute --05 -Month --04 -Day --13 -Year --2010 this is how I am attempting to schedule multiple events to fire at specific date / time. -(void) buildScheduleCache { MPNotifyViewController *notifier = [MPNotifyViewController alloc] ; [notifier setStatusText:@"Rebuilding schedule cache, this will only take a moment."]; [notifier show]; NSCalendarDate *now = [NSCalendarDate calendarDate]; NSFileManager *manager = [[NSFileManager defaultManager] autorelease]; path = @"/var/mobile/Library/MobileProfiles/Custom Profiles"; theProfiles = [manager directoryContentsAtPath:path]; myPrimaryinfo = [[NSMutableArray arrayWithCapacity:6] retain]; keys = [NSArray arrayWithObjects:@"Profile",@"MPSYear",@"MPSMonth",@"MPSDay",@"MPSHour",@"MPSMinute",nil]; for (NSString *profile in theProfiles) { plistDict = [[[NSMutableDictionary alloc] initWithContentsOfFile:[NSString stringWithFormat:@"%@/%@",path,profile]] autorelease]; [myPrimaryinfo addObject:[NSDictionary dictionaryWithObjects: [NSArray arrayWithObjects: [NSString stringWithFormat:@"%@",profile], [NSString stringWithFormat:@"%@",[plistDict objectForKey:@"MPSYear"]], [NSString stringWithFormat:@"%@",[plistDict objectForKey:@"MPSMonth"]], [NSString stringWithFormat:@"%@",[plistDict objectForKey:@"MPSDay"]], [NSString stringWithFormat:@"%@",[plistDict objectForKey:@"MPSHour"]], [NSString stringWithFormat:@"%@",[plistDict objectForKey:@"MPSMinute"]], nil]forKeys:keys]]; profileSched = [NSCalendarDate dateWithYear:[plistDict objectForKey:@"MPSYear"] month:[plistDict objectForKey:@"MPSMonth"] day:[plistDict objectForKey:@"MPSDay"] hour:[plistDict objectForKey:@"MPSHour"] minute:[plistDict objectForKey:@"MPSMinute"] second:01 timeZone:[now timeZone]]; [self rescheduleTimer]; } NSString *testPath = @"/var/mobile/Library/MobileProfiles/Schedules.plist"; [myPrimaryinfo writeToFile:testPath atomically:YES]; } -(void) rescheduleTimer { timer = [[NSTimer alloc] initWithFireDate:profileSched interval:0.0f target:self selector:@selector(theFireEvent) userInfo:nil repeats:YES]; NSRunLoop *runLoop = [NSRunLoop currentRunLoop]; [runLoop addTimer:timer forMode:NSDefaultRunLoopMode]; }

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  • Debugger ignores me.

    - by atch
    Having code: Date::Date(const char* day, const char* month, const char* year):is_leap__(false) { my_day_ = lexical_cast<int>(day); my_month_ = static_cast<Month>(lexical_cast<int>(month)); /*Have to check month here, other ctor assumes month is correct*/ if (my_month_ < 1 || my_month_ > 12) { throw std::exception("Incorrect month."); } my_year_ = lexical_cast<int>(year); if (!check_range_year_(my_year_)) { throw std::exception("Year out of range."); } if (check_leap_year_(my_year_))//SKIPS THIS LINE { is_leap__ = true; } if (!check_range_day_(my_day_, my_month_)) { throw std::exception("Day out of range."); } } bool Date::check_leap_year_(int year)const//IF I MARK THIS LINE WITH BREAKPOINT I'M GETTING MSG THAT THERE IS NO EXECUTABLE CODE IS ASSOSIATED WITH THIS LINE { if (!(year%400) || (year%100 && !(year%4))) { return true; } else { return false; } } Which is very strange in my opinion. There is call to this fnc in my code, why compiler ignores that. P.S. I'm trying to debug in release.

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  • SQL - Count grouped entries and then get the max values grouped by date

    - by Marcus
    hello, I am out of any logic how to write the right sql statment. I've got a sqlite table holding every played track in a row with played date/time Now I will count the plays of all artists, grouped by day and then find the artist with the max playcount per day. I used this Query SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname to get this result "93"|"The Skygreen Leopards"|"2010-06-16" "2" |"Arcade Fire" |"2010-06-15" "2" |"Dead Kennedys" |"2010-06-15" "2" |"Wolf People" |"2010-06-15" "3" |"16 Horsepower" |"2010-06-15" "3" |"Alela Diane" |"2010-06-15" "46"|"Motorama" |"2010-06-15" "1" |"Ariel Pink's Haunted" |"2010-06-14" I tried then to query this virtual table but I always get false results in artistname. SELECT MAX(artistcount), artistname , day_played FROM ( SELECT COUNT(ARTISTID) AS artistcount, ARTIST AS artistname,strftime('%Y-%m-%d', playtime) AS day_played FROM playcount GROUP BY artistname ) GROUP BY strftime('%Y-%m-%d',day_played) result in this "93"|"lilium" |"2010-06-16" "46"|"Wolf People"|"2010-06-15" "30"|"of Montreal"|"2010-06-14" but the artist name is false. I think through the grouping by day, it just use the last artist, or so. I tested stuff like INNER JOIN or GROUP BY ... HAVING in trial and error, I read examples of similar issues but always get lost in columnnames and stuff (I am a bit burned out) I hope someone can give me a hint. thanks m

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  • Substitute values (for specific dates) from a second data frame to the first data frame

    - by user1665355
    I have two time series data frames: The first one: head(df1) : GMT MSCI ACWI DJGlbl Russell 1000 Russell Dev S&P GSCI Industrial S&P GSCI Precious 1999-03-01 -0.7000000 0.2000000 -0.1000000 -1.5000000 -1.0000000 -0.4000000 1999-03-02 -0.5035247 0.0998004 -0.7007007 -0.2030457 0.4040404 -0.3012048 1999-03-03 -0.2024291 0.2991027 0.0000000 -0.6103764 0.1006036 -0.1007049 1999-03-04 0.7099391 0.2982107 1.5120968 -0.1023541 0.5025126 0.4032258 1999-03-05 2.4169184 0.8919722 2.1847071 2.7663934 -1.2000000 0.0000000 1999-03-08 0.3933137 0.3929273 0.5830904 -0.0997009 -0.2024291 1.1044177 tail(df1) : GMT MSCI ACWI DJGlbl Russell 1000 Russell Dev S&P GSCI Industrial S&P GSCI Precious 2011-12-23 0.68241470 0.84790673 0.9441385 0.6116208 0.5822862 -0.2345300 2011-12-26 -0.05213764 0.00000000 0.0000000 0.0000000 0.0000000 0.0000000 2011-12-27 0.20865936 0.05254861 0.3117693 0.2431611 0.0000000 -0.7233273 2011-12-28 -0.62467465 -1.20798319 -1.1655012 -0.9702850 -2.0414381 -2.4043716 2011-12-29 0.52383447 0.47846890 0.8647799 0.5511329 -0.0933126 -1.2504666 2011-12-30 0.26055237 1.03174603 -0.4676539 1.2180268 1.9613948 1.7388017 The second one: head(df2) : GMT MSCI.ACWI DJGlbl Russell.1000 Russell.Dev S.P.GSCI.Industrial S.P.GSCI.Precious 1999-06-01 0.00000000 0.24438520 0.0000000 0 -0.88465521 0.008522842 1999-07-01 0.12630441 0.06755621 0.0000000 0 0.29394697 0.000000000 1999-08-02 0.07441812 0.18922829 0.0000000 0 0.02697299 -0.107155063 1999-09-01 -0.36952701 0.08684107 0.1117509 0 0.24520976 0.000000000 1999-10-01 0.00000000 0.00000000 0.0000000 0 0.00000000 1.941266205 1999-11-01 0.41879925 0.00000000 0.0000000 0 0.00000000 -0.197897901 tail(df2) : GMT MSCI.ACWI DJGlbl Russell.1000 Russell.Dev S.P.GSCI.Industrial S.P.GSCI.Precious 2011-07-01 0.00000000 0.0000000 0.0000000 0.0000000 0.00000000 -0.1141162 2011-08-01 0.00000000 0.0000000 0.0000000 0.0000000 0.02627347 0.0000000 2011-09-01 -0.02470873 0.2977585 -0.0911891 0.6367605 0.00000000 0.2830977 2011-10-03 0.42495188 0.0000000 0.4200743 -0.4420027 -0.41012646 0.0000000 2011-11-01 0.00000000 0.0000000 0.0000000 -0.6597739 0.00000000 0.0000000 2011-12-01 0.50273034 0.0000000 0.0000000 0.6476393 0.00000000 0.0000000 The first df cointains daily observations. The second df contains only the "first day of each month" forecasted values. I would like to substitute the values from the second df into the first one. In other words, the "first day of each month" values in the first df will be substituted for the "first day of each month" values from the second df. I tried to write an lapply loop that substitutes the values and was only trying to use match function. But I failed. I could not find the similar question at StackOverflow either... Greatful for any suggestions!

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  • DATE lookup table (1990/01/01:2041/12/31)

    - by Frank Developer
    I use a DATE's master table for looking up dates and other values in order to control several events, intervals and calculations within my app. It has rows for every single day begining from 01/01/1990 to 12/31/2041. One example of how I use this lookup table is: A customer pawned an item on: JAN-31-2010 Customer returns on MAY-03-2010 to make an interest pymt to avoid forfeiting the item. If he pays 1 months interest, the employee enters a "1" and the app looks-up the pawn date (JAN-31-2010) in date master table and puts FEB-28-2010 in the applicable interest pymt date. FEB-28 is returned because FEB-31's dont exist! If 2010 were a leap-year, it would've returned FEB-29. If customer pays 2 months, MAR-31-2010 is returned. 3 months, APR-30... If customer pays more than 3 months or another period not covered by the date lookup table, employee manually enters the applicable date. Here's what the date lookup table looks like: { Copyright 1990:2010, Frank Computer, Inc. } { DBDATE=YMD4- (correctly sorted for faster lookup) } CREATE TABLE datemast ( dm_lookup DATE, {lookup col used for obtaining values below} dm_workday CHAR(2), {NULL=Normal Working Date,} {NW=National Holiday(Working Date),} {NN=National Holiday(Non-Working Date),} {NH=National Holiday(Half-Day Working Date),} {CN=Company Proclamated(Non-Working Date),} {CH=Company Proclamated(Half-Day Working Date)} {several other columns omitted} dm_description CHAR(30), {NULL, holiday description or any comments} dm_day_num SMALLINT, {number of elapsed days since begining of year} dm_days_left SMALLINT, (number of remaining days until end of year} dm_plus1_mth DATE, {plus 1 month from lookup date} dm_plus2_mth DATE, {plus 2 months from lookup date} dm_plus3_mth DATE, {plus 3 months from lookup date} dm_fy_begins DATE, {fiscal year begins on for lookup date} dm_fy_ends DATE, {fiscal year ends on for lookup date} dm_qtr_begins DATE, {quarter begins on for lookup date} dm_qtr_ends DATE, {quarter ends on for lookup date} dm_mth_begins DATE, {month begins on for lookup date} dm_mth_ends DATE, {month ends on for lookup date} dm_wk_begins DATE, {week begins on for lookup date} dm_wk_ends DATE, {week ends on for lookup date} {several other columns omitted} ) IN "S:\PAWNSHOP.DBS\DATEMAST"; Is there a better way of doing this or is it a cool method?

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  • Fuzzy Date algorithm in Objective-C

    - by Brock Woolf
    I would like to write a fuzzy date method for calculating dates in Objective-C for iPhone. There is a popular explanation here: http://stackoverflow.com/questions/11/how-do-i-calculate-relative-time However it contains missing arguments. How could this be used in Objective-C?. Thanks. const int SECOND = 1; const int MINUTE = 60 * SECOND; const int HOUR = 60 * MINUTE; const int DAY = 24 * HOUR; const int MONTH = 30 * DAY; if (delta < 1 * MINUTE) { return ts.Seconds == 1 ? "one second ago" : ts.Seconds + " seconds ago"; } if (delta < 2 * MINUTE) { return "a minute ago"; } if (delta < 45 * MINUTE) { return ts.Minutes + " minutes ago"; } if (delta < 90 * MINUTE) { return "an hour ago"; } if (delta < 24 * HOUR) { return ts.Hours + " hours ago"; } if (delta < 48 * HOUR) { return "yesterday"; } if (delta < 30 * DAY) { return ts.Days + " days ago"; } if (delta < 12 * MONTH) { int months = Convert.ToInt32(Math.Floor((double)ts.Days / 30)); return months <= 1 ? "one month ago" : months + " months ago"; } else { int years = Convert.ToInt32(Math.Floor((double)ts.Days / 365)); return years <= 1 ? "one year ago" : years + " years ago"; }

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  • Parsing a complicated array with GetJSON Jquery

    - by Ozaki
    TLDR: Started with this question simplified it after got some of it working and continuing it here. I need to 'GET' the JSON array Format it correctly and for each within the array place it in the corresponding DIV. ?? It works. This is a followup from this question to simplify and continue. I need to some complicated JSON data from an array. With it I need the title and it's value. The reason why I am doing this is because I will know what the array is called but not the data that is being generated inside it. Lets say this new array looks as follows: {"Days": ["Sunday":"10.00", "Monday":"12.00", "Tuesday":"09.00", "Wednesday":"10.00", "Thursday":"02.00", "Friday":"05.00", "Saturday":"08.00"] } I would need it to get Sunday & 10.00 as well as the same for all of the others. My code to parse this at the moment is as follows: $.getJSON(url, function(data){ $.each(data, function(i,item){ $('.testfield').append('<p>' + item + '</p>'); }); }); Without the added times on each date it will parse the data as follows: Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday With the times added to the days in the array Firebug no longer recognizes it as a JSON string. So I am guessing I have formatted something wrong here. Also, I need each day & time to be on a new line I thought that $('.testfield').append('<p>' + item + '</p>' + '<br />'); Would have applied each one to a new line but that did not work. How do I get each day or item to be on a new line? How do I get the $getjson to parse the data correctly day and its value, into a div?

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  • New Perl user: using a hash of arrays

    - by Zach H
    I'm doing a little datamining project where a perl script grabs info from a SQL database and parses it. The data consists of several timestamps. I want to find how many of a particular type of timestamp exist on any particular day. Unfortunately, this is my first perl script, and the nature of perl when it comes to hashes and arrays is confusing me quite a bit. Code segment: my %values=();#A hash of the total values of each type of data of each day. #The key is the day, and each key stores an array of each of the values I need. my @proposal; #[drafted timestamp(0), submitted timestamp(1), attny approved timestamp(2),Organiziation approved timestamp(3), Other approval timestamp(4), Approved Timestamp(5)] while(@proposal=$sqlresults->fetchrow_array()){ #TODO: check to make sure proposal is valid #Increment the number of timestamps of each type on each particular date my $i; for($i=0;$i<=5;$i++) $values{$proposal[$i]}[$i]++; #Update rolling average of daily #TODO: To check total load, increment total load on all dates between attourney approve date and accepted date for($i=$proposal[1];$i<=$proposal[2];$i++) $values{$i}[6]++; } I keep getting syntax errors inside the for loops incrementing values. Also, considering that I'm using strict and warnings, will Perl auto-create arrays of the right values when I'm accessing them inside the hash, or will I get out-of bounds errors everywhere? Thanks for any help, Zach

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  • Merging two Regular Expressions to Truncate Words in Strings

    - by Alix Axel
    I'm trying to come up with the following function that truncates string to whole words (if possible, otherwise it should truncate to chars): function Text_Truncate($string, $limit, $more = '...') { $string = trim(html_entity_decode($string, ENT_QUOTES, 'UTF-8')); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)~su', '$1', $string); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{' . intval($limit) . '}).*~su', '$1', $string); } $string .= $more; } return trim(htmlentities($string, ENT_QUOTES, 'UTF-8', true)); } Here are some tests: // Iñtërnâtiônàlizætiøn and then the quick brown fox... (49 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn and then the quick brown fox jumped overly the lazy dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); // Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_... (50 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); They both work as it is, however if I drop the second preg_replace() I get the following: Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.... I can't use substr() because it only works on byte level and I don't have access to mb_substr() ATM, I've made several attempts to join the second regex with the first one but without success. Please help S.M.S., I've been struggling with this for almost an hour. EDIT: I'm sorry, I've been awake for 40 hours and I shamelessly missed this: $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)?~su', '$1', $string); Still, if someone has a more optimized regex (or one that ignores the trailing space) please share: "Iñtërnâtiônàlizætiøn and then " "Iñtërnâtiônàlizætiøn_and_then_" EDIT 2: I still can't get rid of the trailing whitespace, can someone help me out?

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  • Use of clone() and appendTo() with draggable - unexpected results with dragging

    - by Matt Gutting
    I'm constructing a UI for a doctor scheduling app. We have several doctors, each of whom can go in one of several locations on a scheduled day (M - F). I have the main day/location grid (table) in the center of the screen. At the left is a table for the doctor names. On loading, each table cell contains a span (outlined) with the doctor name. The doctor name can go in one slot for each day. I didn't want to just put 5 copies of the doctor name, because the doctor might not be available all 5 days of the week. The idea was: Drag the span and drop into the calendar table. On the drag "start" event, clone the span and append it to the table cell. Now there is another span ready to be dropped into the calendar table. One line of code does the work: $(ui.helper).clone(true).prependTo(ui.helper.parent()); This works. But when I move the cloned span, the original one moves in sync - preserving the spatial relationships as I move the clone around (no doubt there's a "position:relative;left=XX;top=YY" inserted somewhere). I'm sure there's a way to do what I'm thinking of, while keeping the two spans independent. But I'm not thinking of one. Does anyone have an idea? Thanks! Matt I posted this identical question to the jQuery forum as well.

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  • R: How to remove outliers from a smoother in ggplot2?

    - by John
    I have the following data set that I am trying to plot with ggplot2, it is a time series of three experiments A1, B1 and C1 and each experiment had three replicates. I am trying to add a stat which detects and removes outliers before returning a smoother (mean and variance?). I have written my own outlier function (not shown) but I expect there is already a function to do this, I just have not found it. I've looked at stat_sum_df("median_hilow", geom = "smooth") from some examples in the ggplot2 book, but I didn't understand the help doc from Hmisc to see if it removes outliers or not. Is there a function to remove outliers like this in ggplot, or where would I amend my code below to add my own function? library (ggplot2) data = data.frame (day = c(1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7), od = c( 0.1,1.0,0.5,0.7 ,0.13,0.33,0.54,0.76 ,0.1,0.35,0.54,0.73 ,1.3,1.5,1.75,1.7 ,1.3,1.3,1.0,1.6 ,1.7,1.6,1.75,1.7 ,2.1,2.3,2.5,2.7 ,2.5,2.6,2.6,2.8 ,2.3,2.5,2.8,3.8), series_id = c( "A1", "A1", "A1","A1", "A1", "A1", "A1","A1", "A1", "A1", "A1","A1", "B1", "B1","B1", "B1", "B1", "B1","B1", "B1", "B1", "B1","B1", "B1", "C1","C1", "C1", "C1", "C1","C1", "C1", "C1", "C1","C1", "C1", "C1"), replicate = c( "A1.1","A1.1","A1.1","A1.1", "A1.2","A1.2","A1.2","A1.2", "A1.3","A1.3","A1.3","A1.3", "B1.1","B1.1","B1.1","B1.1", "B1.2","B1.2","B1.2","B1.2", "B1.3","B1.3","B1.3","B1.3", "C1.1","C1.1","C1.1","C1.1", "C1.2","C1.2","C1.2","C1.2", "C1.3","C1.3","C1.3","C1.3")) > data day od series_id replicate 1 1 0.10 A1 A1.1 2 3 1.00 A1 A1.1 3 5 0.50 A1 A1.1 4 7 0.70 A1 A1.1 5 1 0.13 A1 A1.2 6 3 0.33 A1 A1.2 7 5 0.54 A1 A1.2 8 7 0.76 A1 A1.2 9 1 0.10 A1 A1.3 10 3 0.35 A1 A1.3 11 5 0.54 A1 A1.3 12 7 0.73 A1 A1.3 13 1 1.30 B1 B1.1 This is what I have so far and is working nicely, but outliers are not removed: r <- ggplot(data = data, aes(x = day, y = od)) r + geom_point(aes(group = replicate, color = series_id)) + # add points geom_line(aes(group = replicate, color = series_id)) + # add lines geom_smooth(aes(group = series_id)) # add smoother, average of each replicate

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  • Linq Getting Customers group by date and then by their type

    - by Nitin varpe
    I am working on generating report for showing customer using LINQ in C#. I want to show no. of customers of each type. There are 3 types of customer registered, guest and manager. I want to group by customers by registered date and then by type of customer. i.e If today 3 guest, 4 registered and 2 manager are inserted. and tomorrow 4,5 and 6 are registered resp. then report should show Number of customers registerd on the day . separate row for each type. DATE TYPEOF CUSTOMER COUNT 31-10-2013 GUEST 3 31-10-2013 REGISTERED 4 31-10-2013 MANAGER 2 30-10-2013 GUEST 5 30-10-2013 REGISTERED 10 30-10-2013 MANAGER 3 LIKE THIS . var subquery = from eat in _customerRepo.Table group eat by new { yy = eat.CreatedOnUTC.Value.Year, mm = eat.CreatedOnUTC.Value.Month, dd = eat.CreatedOnUTC.Value.Day } into g select new { Id = g.Min(x => x.Id) }; var query = from c in _customerRepo.Table join cin in subquery.Distinct() on c.Id equals cin.Id select c; By above query I get minimum cutomers registerd on that day Thanks in advance

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  • CSS - Which method is better?

    - by Joe
    Which is better in regards to processing time but also taking into account ease of use for a developer? .font_small{ font-size:10px; } .font_blue{ color:blue; } .font_red{ color:red; } <span class="font_small font_blue">Hello World!</span><br /> <span class="font_small font_red">Today's the day!</span> OR .font_blue_small{ color:blue; } .font_red_small{ color:red; } .font_blue_small .font_red_small { font-size:10px; } <span class="font_blue_small">Hello World!</span><br /> <span class="font_red_small">Today's the day!</span> OR .font_blue_small{ color:blue; font-size:10px; } .font_red_small{ color:red; font-size:10px; } <span class="font_blue_small">Hello World!</span><br /> <span class="font_red_small">Today's the day!</span> OR Another option I haven't though of yet...?

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  • Which view will be resolved, code from spring's docs

    - by Blankman
    So when you go to /appointments the get() action is called, so then would the view be get.jsp (assuming you are using .jsp, and assuming you are mapping action names to views)? And what about the getnewform? It seems to be returning an object? Is that basically passed into the view? @Controller @RequestMapping("/appointments") public class AppointmentsController { private final AppointmentBook appointmentBook; @Autowired public AppointmentsController(AppointmentBook appointmentBook) { this.appointmentBook = appointmentBook; } @RequestMapping(method = RequestMethod.GET) public Map<String, Appointment> get() { return appointmentBook.getAppointmentsForToday(); } @RequestMapping(value="/{day}", method = RequestMethod.GET) public Map<String, Appointment> getForDay(@PathVariable @DateTimeFormat(iso=ISO.DATE) Date day, Model model) { return appointmentBook.getAppointmentsForDay(day); } @RequestMapping(value="/new", method = RequestMethod.GET) public AppointmentForm getNewForm() { return new AppointmentForm(); } @RequestMapping(method = RequestMethod.POST) public String add(@Valid AppointmentForm appointment, BindingResult result) { if (result.hasErrors()) { return "appointments/new"; } appointmentBook.addAppointment(appointment); return "redirect:/appointments"; } } In the example, the @RequestMapping is used in a number of places. The first usage is on the type (class) level, which indicates that all handling methods on this controller are relative to the /appointments path. The get() method has a further @RequestMapping refinement: it only accepts GET requests, meaning that an HTTP GET for /appointments invokes this method. The post() has a similar refinement, and the getNewForm() combines the definition of HTTP method and path into one, so that GET requests for appointments/new are handled by that method.

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  • SQL Server 2008 - Shrinking the Transaction Log - Any way to automate?

    - by Albert
    I went in and checked my Transaction log the other day and it was something crazy like 15GB. I ran the following code: USE mydb GO BACKUP LOG mydb WITH TRUNCATE_ONLY GO DBCC SHRINKFILE(mydb_log,8) GO Which worked fine, shrank it down to 8MB...but the DB in question is a Log Shipping Publisher, and the log is already back up to some 500MB and growing quick. Is there any way to automate this log shrinking, outside of creating a custom "Execute T-SQL Statement Task" Maintenance Plan Task, and hooking it on to my log backup task? If that's the best way then fine...but I was just thinking that SQL Server would have a better way of dealing with this. I thought it was supposed to shrink automatically whenever you took a log backup, but that's not happening (perhaps because of my log shipping, I don't know). Here's my current backup plan: Full backups every night Transaction log backups once a day, late morning (maybe hook the Log shrinking onto this...doesn't need to be shrank every day though) Or maybe I just run it once a week, after I run a full backup task? What do you all think?

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  • How to represent and insert into an ordered list in SQL?

    - by Travis
    I want to represent the list "hi", "hello", "goodbye", "good day", "howdy" (with that order), in a SQL table: pk | i | val ------------ 1 | 0 | hi 0 | 2 | hello 2 | 3 | goodbye 3 | 4 | good day 5 | 6 | howdy 'pk' is the primary key column. Disregard its values. 'i' is the "index" that defines that order of the values in the 'val' column. It is only used to establish the order and the values are otherwise unimportant. The problem I'm having is with inserting values into the list while maintaining the order. For example, if I want to insert "hey" and I want it to appear between "hello" and "goodbye", then I have to shift the 'i' values of "goodbye" and "good day" (but preferably not "howdy") to make room for the new entry. So, is there a standard SQL pattern to do the shift operation, but only shift the elements that are necessary? (Note that a simple "UPDATE table SET i=i+1 WHERE i=3" doesn't work, because it violates the uniqueness constraint on 'i', and also it updates the "howdy" row unnecessarily.) Or, is there a better way to represent the ordered list? I suppose you could make 'i' a floating point value and choose values between, but then you have to have a separate rebalancing operation when no such value exists. Or, is there some standard algorithm for generating string values between arbitrary other strings, if I were to make 'i' a varchar? Or should I just represent it as a linked list? I was avoiding that because I'd like to also be able to do a SELECT .. ORDER BY to get all the elements in order.

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  • Check on every page to ensure user has validated as being over 18

    - by liquilife
    Hi Guys and Girls. I'm working on a website (tobacco related) that requires all visitors to validate they are over 18 before they can view the site. I have a form in place that validates the age but I'm at a dead end. How can I use this to store a cookie that they've passed the test and do a check on all pages to see if this check has already been passed or not? Any suggestions and help would be hugely appreciated! Below is my validation form: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Validate</title> <script type="text/javascript" src="http://jqueryjs.googlecode.com/files/jquery-1.3.2.js"></script> <script language="javascript"> function checkAge() { var min_age = 18; var year = parseInt(document.forms["age_form"]["year"].value); var month = parseInt(document.forms["age_form"]["month"].value) - 1; var day = parseInt(document.forms["age_form"]["day"].value); var theirDate = new Date((year + min_age), month, day); var today = new Date; if ( (today.getTime() - theirDate.getTime()) < 0) { alert("You are too young to enter this site!"); return false; } else { return true; } } </script> </head> <body> <form action="index.html" name="age_form" method="get" id="age_form"> <select name="day" id="day"> <option value="0" selected>DAY</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <select name="month" id="month"> <option value="0" selected>MONTH</option> <option value="1">January</option> <option value="2">February</option> <option value="3">March</option> <option value="4">April</option> <option value="5">May</option> <option value="6">June</option> <option value="7">July</option> <option value="8">August</option> <option value="9">September</option> <option value="10">October</option> <option value="11">November</option> <option value="12">December</option> </select> <select name="year" id="year"> <option value="0" selected>YEAR</option> <option value="1920">1920</option> <option value="1921">1921</option> <option value="1922">1922</option> <option value="1923">1923</option> <option value="1924">1924</option> <option value="1925">1925</option> <option value="1926">1926</option> <option value="1927">1927</option> <option value="1928">1928</option> <option value="1929">1929</option> <option value="1930">1930</option> <option value="1931">1931</option> <option value="1932">1932</option> <option value="1933">1933</option> <option value="1934">1934</option> <option value="1935">1935</option> <option value="1936">1936</option> <option value="1937">1937</option> <option value="1938">1938</option> <option value="1939">1939</option> <option value="1940">1940</option> <option value="1941">1941</option> <option value="1942">1942</option> <option value="1943">1943</option> <option value="1944">1944</option> <option value="1945">1945</option> <option value="1946">1946</option> <option value="1947">1947</option> <option value="1948">1948</option> <option value="1949">1949</option> <option value="1950">1950</option> <option value="1951">1951</option> <option value="1952">1952</option> <option value="1953">1953</option> <option value="1954">1954</option> <option value="1955">1955</option> <option value="1956">1956</option> <option value="1957">1957</option> <option value="1958">1958</option> <option value="1959">1959</option> <option value="1960">1960</option> <option value="1961">1961</option> <option value="1962">1962</option> <option value="1963">1963</option> <option value="1964">1964</option> <option value="1965">1965</option> <option value="1966">1966</option> <option value="1967">1967</option> <option value="1968">1968</option> <option value="1969">1969</option> <option value="1970">1970</option> <option value="1971">1971</option> <option value="1972">1972</option> <option value="1973">1973</option> <option value="1974">1974</option> <option value="1975">1975</option> <option value="1976">1976</option> <option value="1977">1977</option> <option value="1978">1978</option> <option value="1979">1979</option> <option value="1980">1980</option> <option value="1981">1981</option> <option value="1982">1982</option> <option value="1983">1983</option> <option value="1984">1984</option> <option value="1985">1985</option> <option value="1986">1986</option> <option value="1987">1987</option> <option value="1988">1988</option> <option value="1989">1989</option> <option value="1990">1990</option> <option value="1991">1991</option> <option value="1992">1992</option> <option value="1993">1993</option> <option value="1994">1994</option> <option value="1995">1995</option> <option value="1996">1996</option> <option value="1997">1997</option> <option value="1998">1998</option> <option value="1999">1999</option> </select> </form> </body> </html>

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