Search Results

Search found 9016 results on 361 pages for 'regex libraries'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 123/361 | < Previous Page | 119 120 121 122 123 124 125 126 127 128 129 130  | Next Page >

  • Regular Expression :match string containing only non repeating words

    - by nash
    I have this situation(Java code): 1) a string such as : "A wild adventure" should match. 2) a string with adjacent repeated words: "A wild wild adventure" shouldn't match. With this regular expression: .* \b(\w+)\b\s*\1\b.* i can match strings containing adjacent repeated words. How to reverse the situation i.e how to match strings which do not contain adjacent repeat words

    Read the article

  • get city, state or zip from a string in python

    - by Joe
    I'd like to be able to parse out the city, state or zip from a string in python. So, if I entered Boulder, Co 80303 Boulder, Colorado Boulder, Co 80303 ... any variation of these it would return the city, state or zip. This is all going to be user inputted data and inputted in one text field.

    Read the article

  • How to validate hostname in perl?

    - by embedded
    Hi, I need to come up with a regular expression to validate hostname against RFC-1123 and RFC-952. Right now I'm using this: ^(?=.{1,255}$)[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?(?:\.[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?)*\.?$/ but this does not do the trick since it does not catch a. as invalid hostname. How do I enhance the reg expression to comply with those RFCs? Thanks

    Read the article

  • Regular expression for dividing country calling codes

    - by RickiG
    Hi I have a list of calling codes for all countries(the phone number prefixes), I would like to split them up in the country name and the actual code so I can put then into an xml. I have tried back and forth but can not get a regexp going that takes all cases into account. I think it is fairly simple for someone with a bit of experience. The codes have these formats: Afghanistan 93 Anguilla 1 264 Antarctica 6721 Antigua and Barbuda 1 268 Bosnia and Herzegovina 387 Canada 1 Congo, Republic of the 242 Cote d'Ivoire 225 Ireland (Eire) 353 United States of America 1 There are around 235 of them in total, but these are the regulars and the exceptions. ^[a-zA-Z]\s,'()] for between 1 and X words and then it is [0-9\s]{1,5}$ for the numbers: X XX XXX XXXX X XXX So if I should express it as a sentence it would be: "from beginning of a line, take all characters (1) including space,'() until you encounter digits, then take all of these including space(2) until you encounter a line break." I am using TextMate, and the docs says: TextMate uses the Oniguruma regular expression library by K. Kosako. I would appreciate any help given:) Thank you.

    Read the article

  • Is it possible to use re2 from Python?

    - by flow
    i just discovered http://code.google.com/p/re2, a promising library that uses a long-neglected way (Thompson NFA) to implement a regular expression engine that can be orders of magnitudes faster than the available engines of awk, Perl, or Python. so i downloaded the code and did the usual sudo make install thing. however, that action had seemingly done little more than adding /usr/local/include/re2/re2.h to my system. there seemed to be some `*.a file in addition, but then what is it with this *.a extension? i would like to use re2 from Python (preferrably Python 3.1) and was excited to see files like make_unicode_groups.py in the distro (maybe just used during the build process?). those however were not deployed on my machine. how can i use re2 from Python?

    Read the article

  • using regular expression in Java

    - by Mrityunjay
    Hi, i need to check a string that should contain only ABCDEFG characters, in any sequence and with only 7 characters. Please let me know the correct way of using regular expression. as corrently i am using String abs = "ABPID"; if(!Pattern.matches("[[ABCDEFG]", abs)) System.out.println("Error"); i am using the following code which works when i use the String abcdefg but for other cases it fails. please help me out.

    Read the article

  • regular expression for string in c

    - by darkie15
    Hi All, I am working writing a regular expression used to validate string in C. Here is to what I have gone so far '^"[A-Za-z0-9]*[\t\n]*"$' for rules - A string should begin with double quotes - May not contain a newline character However, I am not able to capture the rule for allowing '\' or '"' in a string if preceded with '\'. Here is what I tried: '^"[A-Za-z0-9]*[\t\n]*[\\\|\\"]?"$' But this doesn't seem to work. What might be wrong with the regular expression here? Regards, darkie15

    Read the article

  • Python comparing string against several regular expressions

    - by maerics
    I'm pretty experienced with Perl and Ruby but new to Python so I'm hoping someone can show me the Pythonic way to accomplish the following task. I want to compare several lines against multiple regular expressions and retrieve the matching group. In Ruby it would be something like this: STDIN.each_line do |line| case line when /^A:(.*?)$/ then puts "FOO: #{$1}" when /^B:(.*?)$/ then puts "BAR: #{$1}" # when ... else puts "NO MATCH: #{line}" end end My attempts in Python are turning out pretty ugly because the matching group is returned from a call to match/search on a regular expression and Python has no assignment in conditionals or switch statements. What's the Pythonic way to do (or think!) about this problem?

    Read the article

  • Extracting a string between specified characters in python

    - by Seth
    I'm a newbie to regular expressions and I have the following string: sequence = ["{\"First\":\"Belyuen,NT,0801\",\"Second\":\"Belyuen,NT,0801\"}","{\"First\":\"Larrakeyah,NT,0801\",\"Second\":\"Larrakeyah,NT,0801\"}"] I am trying to extract the text Belyuen,NT,0801 and Larrakeyah,NT,0801 in python. I have the following code which is not working: re.search('\:\\"...\\', ''.join(sequence)) I.e. I want to get the string between characters :\ and \.

    Read the article

  • Redirect visitor with .htaccess

    - by Aaron
    Hi all, I've got an e-shop on a virtual server that's been used as a subdirectory for the last few years, but now I'm finally giving the VS it's own domain name. What I really need is visitors to the old URL to be transparently (and 301) redirected to the new URL with everything after /eshop/ maintained and apended to the new host. I.e. http://www.example.com/eshop/page.php - http://www.newdomain.com/page.php Any help would be greatly appreciated.

    Read the article

  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

    Read the article

  • Algorithm to match natural text in mail

    - by snøreven
    I need to separate natural, coherent text/sentences in emails from lists, signatures, greetings and so on before further processing. example: Hi tom, last monday we did bla bla, lore Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. list item 2 list item 3 list item 3 Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid x ea commodi consequat. Quis aute iure reprehenderit in voluptate velit regards, K. ---line-of-funny-characters-####### example inc. 33 evil street, london mobile: 00 234534/234345 Ideally the algorithm would match only the bold parts. Is there any recommended approach - or are there even existing algorithms for that problem? Should I try approximate regular expressions or more statistical stuff based on number of punctation marks, length and so on?

    Read the article

  • questions on nfa and dfa..

    - by Loop
    Hi Guys... Hope you help me with this one.... I have a main question which is ''how to judge whether a regular expression will be accepted by NFA and/or DFA? For eg. My question says that which of the regular expressions are equivalent? explain... 1.(a+b)*b(a+b)*b(a+b)* 2.a*ba*ba* 3.a*ba*b(a+b)* do we have to draw the NFA and DFA and then find through minimisation algorithm? if we do then how do we come to know that which regular expression is accepted by NFA/DFA so that we can begin with the answer? its so confusing.... Second is a very similar one, the question asks me to show that the language (a^nb^n|n1} is not accepted by DFA...grrrrr...how do i know this? (BTW this is a set of all strings of where a number of a's is followed by the same number of b's).... I hope I explained clearly well....

    Read the article

  • Replacing text node of HTML input in PHP

    - by Aman Kumar Jain
    Hi, I want to replace all the text nodes in a html text. I'll explain with an example: $html = " <div> <p> text2 text2 word text2 <span>abcd</span> text2 text2 word text2 <p> this is a long, very long statement with punctuations. </div> I want to replace "text2 text2 word text2" with "<span>text2 text2 word text2</span>" and "this is a long, very long statement with punctuations." with "<span>this is a long, very long statement with punctuations.</span>" What should be the regular expression for the same?

    Read the article

  • A "smart" (forgiving) date parser?

    - by jdmuys
    I have to migrate a very large dataset from one system to another. One of the "source" column contains a date but is really a string with no constraint, while the destination system mandates a date in the format yyyy-mm-dd. Many, but not all, of the source dates are formatted as yyyymmdd. So to coerce them to the expected format, I do (in Perl): return "$1-$2-$3" if ($val =~ /(\d{4})[-\/]*(\d{2})[-\/]*(\d{2})/); The problem arises when the source dates moves away from the "generic" yyyymmdd. The goal is to salvage as many dates as possible, before giving up. Example source strings include: 21/3/1998, March 2004, 2001, 3/4/97 I can try to match as many of the examples I can find with a succession of regular expressions such as the one above. But is there something smarter to do? Am I not reinventing the wheel? Is there a library somewhere doing something similar? I couldn't find anything relevant googling "forgiving date parser". (any language is OK).

    Read the article

  • Extract a regular expression match in R version 2.10

    - by tovare
    Hi, I'm trying to extract a number from a string. And do something like this [0-9]+ on this string "aaaa12xxxx" and get "12". I thought it would be something like: > grep("[0-9]+","aaa12xxx", value=TRUE) [1] "aaa12xxx" And then I figured... > sub("[0-9]+", "\\1", "aaa12xxxx") [1] "aaa12xxx" But I got some form of response doing: > sub("[0-9]+", "ARGH!", "aaa12xxxx") [1] "aaaARGH!xxx" There's a small detail I'm missing Please advice :-) I'm using R version 2.10.1 (2009-12-14) Thanks ! Comments on the solution The best solution is to ignore the standard functions and install Hadley Wickham's stringr package to get something that actually makes sense. Kudos to Marek for figuring out how the standard library worked.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 119 120 121 122 123 124 125 126 127 128 129 130  | Next Page >