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  • How can join two django querysets in one?

    - by diegueus9
    I need order a Queryset by date in desc order, but i need put in the end the objects at the end, I do this: qs1 = Model.objects.exclude(date=None).order_by('-date') qs2 = Model.objects.filter(date=None).order_by('-date') and my list is: l = list(qs1)+list(qs2) There is a more efficiently way for this?

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  • Reorganizing many to many relationships in Django

    - by Galen
    I have a many to many relationship in my models and i'm trying to reorganize it on one of my pages. My site has videos. On each video's page i'm trying to list the actors that are in that video with links to each time they are in the video(the links will skip to that part of the video) Here's an illustration Flash Video embedded here Actors... Ted smith: 1:25, 5:30 jon jones: 5:00, 2:00 Here are the pertinent parts of my models class Video(models.Model): actor = models.ManyToManyField( Actor, through='Actor_Video' ) # more stuff removed class Actor_Video(models.Model): actor = models.ForeignKey( Actor ) video = models.ForeignKey( Video) time = models.IntegerField() Here's what my Actor_Video table looks like, maybe it will be easier to see what im doing id actor_id video_id time (in seconds) 1 1 3 34 2 1 3 90 i feel like i have to reorganize the info in my view, but i cant figure it out. It doesn't seem to be possible in the template using djangos orm. I've tried a couple things with creating dictionaries/lists but i've had no luck. Any help is appreciated. Thanks.

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  • Making only a part of model field available in Django

    - by Hellnar
    Hello I have a such model: GENDER_CHOICES = ( ('M', 'Male'), ('F', 'Female') ) class Profile(models.Model): user = models.ForeignKey(User) gender = models.CharField(max_length=1, choices=GENDER_CHOICES) class FrontPage(models.Model): female = models.ForeignKey(User,related_name="female") male = models.ForeignKey(User,related_name="male") Once I attempt to add a new FrontPage object via the Admin page, I can select "Female" profiles for the male field of FrontPage, how can I restrict that? Thanks

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  • Changing models in django results in broken database?

    - by Rhubarb
    I have added and removed fields in my models.py file and then run manage.py syncdb. Usually I have to quit out of the shell and restart it before syncdb does anything. And then even after that, I am getting errors when trying to access the admin pages, it seems that certain new fields that I've added still don't show up in the model: Caught an exception while rendering: no such column: mySite_book.Title

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  • Matching 3 out 5 fields - Django

    - by RadiantHex
    Hi folks, I'm finding this a bit tricky! Maybe someone can help me on this one I have the following model: class Unicorn(models.Model): horn_length = models.IntegerField() skin_color = models.CharField() average_speed = models.IntegerField() magical = models.BooleanField() affinity = models.CharField() I would like to search for all similar unicorns having at least 3 fields in common. Is it too tricky? Or is it doable?

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  • Django aggregation query on related one-to-many objects

    - by parxier
    Here is my simplified model: class Item(models.Model): pass class TrackingPoint(models.Model): item = models.ForeignKey(Item) created = models.DateField() data = models.IntegerField() In many parts of my application I need to retrieve a set of Item's and annotate each item with data field from latest TrackingPoint from each item ordered by created field. For example, instance i1 of class Item has 3 TrackingPoint's: tp1 = TrackingPoint(item=i1, created=date(2010,5,15), data=23) tp2 = TrackingPoint(item=i1, created=date(2010,5,14), data=21) tp3 = TrackingPoint(item=i1, created=date(2010,5,12), data=120) I need a query to retrieve i1 instance annotated with tp1.data field value as tp1 is the latest tracking point ordered by created field. That query should also return Item's that don't have any TrackingPoint's at all. If possible I prefer not to use QuerySet's extra method to do this. That's what I tried so far... and failed :( Item.objects.annotate(max_created=Max('trackingpoint__created'), data=Avg('trackingpoint__data')).filter(trackingpoint__created=F('max_created')) Any ideas?

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  • Django: testing get query

    - by Brant
    Okay, so I am sick of writing this... res = Something.objects.filter(asdf=something) if res: single = res[0] else: single = None if single: # do some stuff I would much rather be able to do something like this: single = Something.objects.filter(asdf=something) if single: #do some stuff I want to be able to grab a single object without testing the filtered results. In other words, when i know there is either going to be 1 or 0 matching entries, I would like to jump right to that entry, otherwise just get a 'None'. The DoesNotExist error that goes along with .get does not always work so well when trying to compress these queries into a single line. Is there any way to do what I have described?

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  • Django foreign key error

    - by Hulk
    In models the code is as, class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() In views, p_l=header.objects.filter(id=rid) for rows in row_data: row_query =criteria(details=rows,headerid=p_l) row_query.save() In row_query =criteria(details=rows,headerid=p_l) there is an error saying 'long' object is not callable in models.py in __unicode__, What is wrong in the code Thanks..

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  • django models objects filter

    - by ha22109
    Hello All, I have a model 'Test' ,in which i have 2 foreignkey models.py class Test(models.Model): id =models.Autofield(primary_key=True) name=models.ForeignKey(model2) login=models.ForeignKey(model1) status=models.CharField(max_length=200) class model1(models.Model): id=models.CharField(primary_key=True) . . is_active=models.IntergerField() class model2(model.Model): id=models.ForeignKey(model1) . . status=model.CharField(max_length=200) When i add object in model 'Test' , if i select certain login then only the objects related to that objects(model2) should be shown in field 'name'.How can i achieve this.THis will be runtime as if i change the login field value the objects in name should also change.

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  • Django unable to update model

    - by user292652
    i have the following function to override the default save function in a model match def save(self, *args, **kwargs): if self.Match_Status == "F": Team.objects.filter(pk=self.Team_one.id).update(Played=F('Played')+1) Team.objects.filter(pk=self.Team_two.id).update(Played=F('Played')+1) if self.Winner !="": Team.objects.filter(pk=self.Winner.id).update(Win=F('Win')+1, Points=F('Points')+3) else: return if self.Match_Status == "D": Team.objects.filter(pk=self.Team_one.id).update(Played=F('Played')+1, Draw = F('Draw')+1, Points=F('Points')+1) Team.objects.filter(pk=self.Team_two.id).update(Played=F('Played')+1, Draw = F('Draw')+1, Points=F('Points')+1) super(Match, self).save(*args, **kwargs) I am able to save the match model just fine but Team model does not seem to be updating at all and no error is being thrown. am i missing some thing here ?

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  • How to display total record count against models in django admin

    - by Rog
    Is there a neat way to make the record/object count for a model appear on the main model list in the admin module? I have found techniques for showing counts of related objects within sets in the list_display page (and I can see the total in the pagination section at the bottom of the same), but haven't come across a neat way to show the record count at the model list level.

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  • Modify on-the-fly verbose_name in a model field on django admin

    - by PerroVerd
    Hi I have this sample model working with the admin class Author(models.Model): name = models.CharField(_('Text in here'), max_length=100) with verbose_name set as ugettext_lazy 'Text in here', but sometimes, depending on the site_id i want to present a diferent verbose name, so I modified the init in this way def __init__(self, *args, **kwargs): super(Author, self).__init__(*args, **kwargs) #some logic in here self._meta.get_field('name').verbose_name = _('Other text') It works, displaying the 'Other text' instead the 'Text in here'... except for the very first time the author/add view is used. ¿Is it the right way to do it? ¿How can i fix the first time problem? Thanks in advance

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  • Django: How to set default language in admin on login

    - by lazerscience
    I'm saving an user's default language in his user profile and on login I want to set the admin's default language to it. One possibility I was thinking of is using a middleware, but I think if I do it on process_request I will not see an user object there since this is processed AFTER the middleware, so I could only set it after the next request! Any solutions are highly appreciated!

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  • Manually listing objects in Django (problem with field ordering)

    - by Chris
    I'm having some trouble figuring out the best/Djangoic way to do this. I'm creating something like an interactive textbook. It has modules, which are more or less like chapters. Each module page needs to list the topics in that module, grouped into sections. My question is how I can ensure that they list in the correct order in the template? Specifically: 1) How to ensure the sections appear in the correct order? 2) How to ensure the topics appear in the correct order in the section? I imagine I could add a field to each model purely for the sake of ordering, but the problem with that is that a topic might appear in different modules, and in whatever section they are in there they would again have to be ordered somehow. I would probably give up and do it all manually were it not for the fact that I need to have the Topic as object in the template (or view) so I can mark it up according to how the user has labeled it. So I suppose my question is really to do with whether I should create the contents pages manually, or whether there is a way of ordering the query results in a way I haven't thought of. Thanks for your help!

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  • Custom Sorting on Custom Field in Django

    - by RotaJota
    In my app, I have defined a custom field to represent a physical quantity using the quantities package. class AmountField(models.CharField): def __init__(self, *args, **kwargs): ... def to_python(self, value): create_quantities_value(value) Essentially the way it works is it extends CharField to store the value as a string in the database "12 min" and represents it as a quantities object when using the field in a model array(12) * min Then in a model it is used as such: class MyModel(models.Model): group = models.CharField() amount = AmountField() class Meta: ordering = ['group', 'amount'] My issue is that these fields do not seem to sort by the quantity, but instead by the string. So if I have some objects that contain something like {"group":"A", "amount":"12 min"} {"group":"A", "amount":"20 min"} {"group":"A", "amount":"2 min"} {"group":"B", "amount":"20 min"} {"group":"B", "amount":"1 hr"} they end up sorted something like this: >>> MyModel.objects.all() [{A, 12 min}, {A, 2 min}, {A, 20 min}, {B, 1 hr}, {B, 20 min}] essentially alphabetical order. Can I give my custom AmountField a comparison function so that it will compare by the python value instead of the DB value?

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  • Django model manager didn't work with related object when I do aggregated query

    - by Satoru.Logic
    Hi, all. I'm having trouble doing an aggregation query on a many-to-many related field. Let's begin with my models: class SortedTagManager(models.Manager): use_for_related_fields = True def get_query_set(self): orig_query_set = super(SortedTagManager, self).get_query_set() # FIXME `used` is wrongly counted return orig_query_set.distinct().annotate( used=models.Count('users')).order_by('-used') class Tag(models.Model): content = models.CharField(max_length=32, unique=True) creator = models.ForeignKey(User, related_name='tags_i_created') users = models.ManyToManyField(User, through='TaggedNote', related_name='tags_i_used') objects_sorted_by_used = SortedTagManager() class TaggedNote(models.Model): """Association table of both (Tag , Note) and (Tag, User)""" note = models.ForeignKey(Note) # Note is what's tagged in my app tag = models.ForeignKey(Tag) tagged_by = models.ForeignKey(User) class Meta: unique_together = (('note', 'tag'),) However, the value of the aggregated field used is only correct when the model is queried directly: for t in Tag.objects.all(): print t.used # this works correctly for t in user.tags_i_used.all(): print t.used #prints n^2 when it should give n Would you please tell me what's wrong with it? Thanks in advance.

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  • Django - markup parser in template or view?

    - by Amit Ron
    I am building a website where my pages are written in MediaWiki Markup, for which I have a working parser function in Python. Where exactly do I parse my markup: in the view's code, or in the template? My first guess would be something like: return render_to_response( 'blog/post.html', {'post': post, 'content': parseMyMarkup(post.content) }) Is this the usual convention, or should I do something different?

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  • django admin app error (Model with property field): global name 'full_name' is not defined

    - by rxin
    This is my model: class Author(models.Model): first_name = models.CharField(max_length=200) last_name = models.CharField(max_length=200) middle_name = models.CharField(max_length=200, blank=True) def __unicode__(self): return full_name def _get_full_name(self): "Returns the person's full name." if self.middle_name == '': return "%s %s" % (self.first_name, self.last_name) else: return "%s %s %s" % (self.first_name, self.middle_name, self.last_name) full_name = property(_get_full_name) Everything is fine except when I go into admin interface, I see TemplateSyntaxError at /bibbase2/admin/bibbase2/author/ Caught an exception while rendering: global name 'full_name' is not defined It seems like the built-in admin app doesn't work with a property field. Is there something wrong with my code?

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  • Django many to many annotations and filters

    - by dl8
    So I have two models, Person and Film where they're in a many to many relationship. My goal is to grab a film, and output the persons that have also appeared in at least 10 films. For example I can get the count individually by: >>> Person.objects.get(short__istartswith = "Matt Damon").film_set.count() 71 However, if I try to filter all the actors of a particular film out: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film')).filter(film_count__gte=10) [] it returns an empty set since if I manually look at everyone's film_count it's 1, even though an actor such as Matt Damon (as seen above) has been in 71 films in my db. As you can see with this query, the annotation doesn't work: >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_count 1 >>> Film.objects.get(name__istartswith="Saving Private Ryan").actors.all().annotate(film_count=Count('film'))[0].film_set.count() 7 and I can't seem to figure out a way to filter it by the film_set.count()

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  • Django admin.py missing field error

    - by user782400
    When I include 'caption', I get an error saying EntryAdmin.fieldsets[1][1]['fields']' refers to field 'caption' that is missing from the form In the admin.py; I have imported the classes from joe.models import Entry,Image Is that because my class from models.py is not getting imported properly ? Need help in resolving this issue. Thanks. models.py class Image(models.Model): image = models.ImageField(upload_to='joe') caption = models.CharField(max_length=200) imageSrc = models.URLField(max_length=200) user = models.CharField(max_length=20) class Entry(models.Model): image = models.ForeignKey(Image) mimeType = models.CharField(max_length=20) name = models.CharField(max_length=200) password = models.URLField(max_length=50) admin.py class EntryAdmin(admin.ModelAdmin): fieldsets = [ ('File info', {'fields': ['name','password']}), ('Upload image', {'fields': ['image','caption']})] list_display = ('name', 'mimeType', 'password') admin.site.register(Entry, EntryAdmin) admin.site.register(Image)

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  • Django templates tag error

    - by Hulk
    def _table_(request,id,has_permissions): dict = {} dict.update(get_newdata(request,rid)) return render_to_response('home/_display.html',context_instance=RequestContext(request,{'dict': dict, 'rid' : rid, 'has_permissions' : str(has_permissions)})) In templates the code is as, {% if has_permissions == "1" %} <input type="button" value="Edit" id="edit" onclick="javascript:edit('{{id}}')" style="display:inline;"/>&nbsp;&nbsp;&nbsp;&nbsp; {% endif %} There is a template error in has_permissions line. Can any 1 tell me what is wrong here. has_permissions has the value 1 or 0.

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  • querying for timestamp field in django

    - by Hulk
    In my views i have the date in the following format s_date=20090106 and e_date=20100106 The model is defined as class Activity(models.Model): timestamp = models.DateTimeField(auto_now_add=True) how to query for the timestamp filed with the above info. Activity.objects.filter(timestamp>=s_date and timestamp<=e_date) Thanks.....

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  • Creating a QuerySet based on a ManyToManyField in Django

    - by River Tam
    So I've got two classes; Picture and Tag that are as follows: class Tag(models.Model): pics = models.ManyToManyField('Picture', blank=True) name = models.CharField(max_length=30) # stuff omitted class Picture(models.Model): name = models.CharField(max_length=100) pub_date = models.DateTimeField('date published') tags = models.ManyToManyField('Tag', blank=True) content = models.ImageField(upload_to='instaton') #stuff omitted And what I'd like to do is get a queryset (for a ListView) given a tag name that contains the most recent X number of Pictures that are tagged as such. I've looked up very similar problems, but none of the responses make any sense to me at all. How would I go about creating this queryset?

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