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  • django views question

    - by Hulk
    In my django views i have the following def create(request): query=header.objects.filter(id=a)[0] a=query.criteria_set.all() logging.debug(a.details) I get an error saying 'QuerySet' object has no attribute 'details' in the debug statement .What is this error and what should be the correct statemnt to query this.And the model corresponding to this is as follows where as the models has the following: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() Thanks..

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  • Django Formset management-form validation error

    - by gramware
    I have a form and a formset on my template. The problem is that the formset is throwing validation error claiming that the management form is "missing or has been tampered with". Here is my view @login_required def home(request): user = UserProfile.objects.get(pk=request.session['_auth_user_id']) blogz = list(blog.objects.filter(deleted='0')) delblog = modelformset_factory(blog, exclude=('poster','date' ,'title','content')) if request.user.is_staff== True: staff = 1 else: staff = 0 staffis = 1 if request.method == 'POST': delblogformset = delblog(request.POST) if delblogformset.is_valid(): delblogformset.save() return HttpResponseRedirect('/home') else: delblogformset = delblog(queryset=blog.objects.filter( deleted='0')) blogform = BlogForm(request.POST) if blogform.is_valid(): blogform.save() return HttpResponseRedirect('/home') else: blogform = BlogForm(initial = {'poster':user.id}) blogs= zip(blogz,delblogformset.forms) paginator = Paginator(blogs, 10) # Show 25 contacts per page # Make sure page request is an int. If not, deliver first page. try: page = int(request.GET.get('page', '1')) except ValueError: page = 1 # If page request (9999) is out of range, deliver last page of results. try: blogs = paginator.page(page) except (EmptyPage, InvalidPage): blogs = paginator.page(paginator.num_pages) return render_to_response('home.html', {'user':user, 'blogform':blogform, 'staff': staff, 'staffis': staffis, 'blog':blogs, 'delblog':delblogformset}, context_instance = RequestContext( request )) my template {%block content%} <h2>Home</h2> {% ifequal staff staffis %} {% if form.errors %} <ul> {% for field in form %} <H3 class="title"> <p class="error"> {% if field.errors %}<li>{{ field.errors|striptags }}</li>{% endif %}</p> </H3> {% endfor %} </ul> {% endif %} <h3>Post a Blog to the Front Page</h3> <form method="post" id="form2" action="" class="infotabs accfrm"> {{ blogform.as_p }} <input type="submit" value="Submit" /> </form> <br> <br> {% endifequal %} <div class="pagination"> <span class="step-links"> {% if blog.has_previous %} <a href="?page={{ blog.previous_page_number }}">previous</a> {% endif %} <span class="current"> Page {{ blog.number }} of {{ blog.paginator.num_pages }}. </span> {% if blog.has_next %} <a href="?page={{ blog.next_page_number }}">next</a> {% endif %} </span> <form method="post" action="" class="usertabs accfrm"> {{delblog.management_form}} {% for b, form in blog.object_list %} <div class="blog"> <h3>{{b.title}}</h3> <p>{{b.content}}</p> <p>posted by <strong>{{b.poster}}</strong> on {{b.date}}</p> {% ifequal staff staffis %}<p>{{form.as_p}}<input type="submit" value="Delete" /></p>{% endifequal %} </div> {% endfor %} </form> {%endblock%}

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  • Django url parameters

    - by Hulk
    How to pass two paramters in urls in django <script> url=/toolbox/display/" + id + "2"; window.location=url; </script> Also how is this handeled in urls.py (r'^display/(?P<rid>\d+)/(?P<param>\d+)/$', 'table_display'), In views, def table_display(request,rid,param): print param //This should print 2

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  • Extended Django base-class with multiple instances

    - by Gijs
    I'm modeling a simple movie database using Django. models.py defines a base model Person. I extend Person into Actor and Director, which works as I imagined. Persons must be unique. When (in the Admin) I create an instance of Actor, and this person is also a Director, it won't save because of the unique = True. Any ideas how to solve this problem? (generic foreign keys?) Thx

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  • Django template-printing variables

    - by Hulk
    In django views def add(request): dict{} co_data = optarr dict.update({'co_data' : co_data}) logging.debug(co_data) return render_to_response('scheme/create.html',context_instance=RequestContext(request,{'dict': dict})) And data has the following string 1##2##3##4## And in the template when i say {{co_data}} it doesnt display the values.Please point out whats wrong in the code. Thanks..

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  • Django filter vs exclude

    - by Enrico
    Is there a difference between filter and exclude in django? If I have self.get_query_set().filter(modelField=x) and I want to add another criteria, is there a meaningful difference between to following two lines of code? self.get_query_set().filter(user__isnull=False, modelField=x) self.get_query_set().filter(modelField=x).exclude(user__isnull=True) is one considered better practice or are they the same in both function and performance?

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  • Django User model, adding function

    - by Hellnar
    Hello, I want to add a new function to the default User model of Django for retrieveing a related list of Model type. Such Foo model: class Foo(models.Model): owner = models.ForeignKey(User, related_name="owner") likes = models.ForeignKey(User, related_name="likes") ........ #at some view user = request.user foos= user.get_related_foo_models() Hwo can this be achieved ?

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  • How to store an integer leaded by zeros in django

    - by Oscar Carballal
    Hello, I'm trying to store a number in django that looks like this: 000001 My problem is that if I type this inside an IntegerField it gets converted to "1" without the leading zeros. I've tried also with a DecimalField with the same result. How can I store the leading zeros whithout using a CharField? (I need to manipulate that number in it's integer form)

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  • How to make custom join query with Django ?

    - by xRobot
    I have these 2 models: genre = ( ('D', 'Dramatic'), ('T', 'Thriller'), ('L', 'Love'), ) class Book(models.Model): title = models.CharField(max_length=100) genre = models.CharField(max_length=1, choices=genre) class Author(models.Model): user = models.ForeignKey(User, unique=True) born = models.DateTimeField('born') book = models.ForeignKey(Book) I need to retrieve first_name and last_name of all authors of dramatic's books. How can I do this in django ?

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  • Django: name of many to many items in the admin interface

    - by Adam
    I have a many to many field, which I'm displaying in the django admin panel. When I add multiple items, they all come up as "ASGGroup object" in the display selector. Instead, I want them to come up as whatever the ASGGroup.name field is set to. How do I do this? My models looks like: class Thing(Model): read_groups = ManyToManyField('ASGGroup', related_name="thing_read", blank=True) class ASGGroup(Model): name = CharField(max_length=63, null=True) But what I'm seeing the m2m widget display is:

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  • Django: Inherit Permssions from abstract models?

    - by lazerscience
    Is it possible to inherit permissions from an abstract model in Django? I can not really find anything about that. For me this doesn't work! class PublishBase(models.Model): class Meta: abstract = True get_latest_by = 'created' permissions = (('change_foreign_items', "Can change other user's items"),) EDIT: Not working means it fails silently. Permission is not created, as it wouldn't exist on the models inheriting from this class.

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  • Django - problem with {% url facebook_xd_receiver %}

    - by Gaurav
    I'm using {% url facebook_xd_receiver %} in one of my HTML files. This works just fine when I run my project using the command python manage.py runserver But the same project stops running and gives me a "TemplateSyntaxError" at the line {% url facebook_xd_receiver %} Can anyone please tell me what could be the difference between the dev server run through the command line and the apache server. Is there anything I'm missing out on while configuring the Apache server? Or is it a Django problem?

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  • django manage.py syncdb not working?

    - by Diego
    Trying to learn Django, I closed the shell and am getting this problem now when I call python manage.py syncdb, any idea what happened?: I've already set up a db. I have manage.py set up in the folder django_bookmarks. What's up here? Traceback (most recent call last): File "manage.py", line 2, in from django.core.management import execute_manager ImportError: No module named django.core.management my-computer:~/Django-1.1.1/django_bookmarks mycomp$ export PATH=/Users/mycomp/bin:$PATH my-computer:~/Django-1.1.1/django_bookmarks mycomp$ python manage.py syncdb Traceback (most recent call last): File "manage.py", line 2, in from django.core.management import execute_manager ImportError: No module named django.core.management my-computer:~/Django-1.1.1/django_bookmarks mycomp$

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  • Django admin urls return INVALID REQUEST! - Django

    - by RadiantHex
    Hi folks, my admin urls are sat behind a prefix by doing the following. 1# (r'^admin/', include(admin.site.urls)), is placed within urls_core.py 2# (r'^api/', include('project.urls_core')), is palced within urls.py All admin URLs work fine except app indexes. If I go to any URL such as: /api/admin/core/ /api/admin/registration/ /api/admin/users/ /api/admin/filters/ I receive 'INVALID REQUEST' as my response. Status code is 200 (OK) though. I have never received this error message before. Does anyone have a clue? Thanks guys!

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  • Accessing django choice field

    - by Hulk
    there is a module as header , from test.models import SEL_VALUES class rubrics_header(models.Model): sel_values = models.IntegerField(choices=SEL_VALUES) So when SEL_VALUES is imported from test.modules.What is the code that has to go in views to get the choices in sel_values . And the test.modules has the following, class SEL_VALUES: vaue = 0 value2 = 1 class Entries(forms.Form) : models.IntegerField(choices=SEL_VALUES) SEL_VALUES = ((ACCESS.value,'NAME'),(ACCESS.value2,'DESIGNATION'))

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  • Django: customizing the message after a successful form save

    - by chiurox
    Hello, whenever I save a model in my Admin interface, it displays the usual "successfully saved message." However, I want to know if it's possible to customize this message because I have a situation where I want to warn the user about what he just saved and the implications of these actions. class PlanInlineFormset(forms.models.BaseInlineFormset): def clean(self): ### How can I detect the changes? ### (self.changed_data doesn't work because it's an inline) ### and display what he/she just changed at the top AFTER the successful save? class PlanInline(admin.TabularInline): model = Plan formset = PlanInlineFormset

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  • django form ModelChoiceField loads all state names while needed states which are mapped with current selected country

    - by Sonu
    I am using modelChoiceField to display country and state into address form class StateSelectionwidget(forms.Select): """ custom widget to state selection""" class Media: js = ('media/javascript/public/jquery-1.5.2.min.js', 'media/javascript/public/countrystateselection.js', ) class AddressForm(forms.Form): name = forms.CharField(max_length=30) country = forms.ModelChoiceField(queryset=[]) state = forms.ModelChoiceField(CountryState.objects, widget=StateSelectionwidget) def __init__(self, *args, **kwargs): super(AddressForm, self).__init__(*args, **kwargs) self.fields['country'].queryset = Country.objects.all() Country model is used to store country names. CountryState model is used to store all states which is foreign key to Country model At the time of form loading i am getting all state names in dropdown while i want field to be blank by default. If name field is empty at the time of form save i am getting error that name can not be empty but also getting all states into dropdown list while i want only the states which are mapped with current selected country.

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  • Django templates onchange data

    - by Hulk
    In the following code, i have a drop down box and a multi select box. My question is that using javascript and django .how will i changes the designation with changes in names from drop down box. <tr><td> name:</td><td><select id="name" name="name">{% for name in names %} <option value="{{name.id}}" {% for selected_id in names %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.name}}</option>{% endfor %} </select> </td></tr> {% for desg in designation %} <tr><td><p>Topics:</td><td> <select id="desg" name="desg" multiple="multiple"> <option value="{{desg.id}}" >{{desg.desg}}</option> </select></p></td></tr> {% endfor %} Thanks..

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  • Sort list of items in Django

    - by mridang
    Hi Guys, I have a Django view called change_priority. I'm posting a request to this view with a commas separated list of values which is basically the order of the items in my model. The data looks like this: 1,4,11,31,2,4,7 I have a model called Items which has two values - id and priority. Upon getting this post request, how can I set the priority of the Item depending upon the list order. So my data in the db would look like. 1,1 4,2 11,3 31,4 2,5 4,6 7,7 Thanks guys.

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  • Django Managers

    - by owca
    I have the following models code : from django.db import models from categories.models import Category class MusicManager(models.Manager): def get_query_set(self): return super(MusicManager, self).get_query_set().filter(category='Music') def count_music(self): return self.all().count() class SportManager(models.Manager): def get_query_set(self): return super(MusicManager, self).get_query_set().filter(category='Sport') class Event(models.Model): title = models.CharField(max_length=120) category = models.ForeignKey(Category) objects = models.Manager() music = MusicManager() sport = SportManager() Now by registering MusicManager() and SportManager() I am able to call Event.music.all() and Event.sport.all() queries. But how can I create Event.music.count() ? Should I call self.all() in count_music() function of MusicManager to query only on elements with 'Music' category or do I still need to filter through them in search for category first ?

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  • django-admin formfield_for_* change default value per/depending on instance

    - by Nick Ma.
    Hi, I'm trying to change the default value of a foreignkey-formfield to set a Value of an other model depending on the logged in user. But I'm racking my brain on it... This: Changing ForeignKey’s defaults in admin site would an option to change the empty_label, but I need the default_value. #Now I tried the following without errors but it didn't had the desired effect: class EmployeeAdmin(admin.ModelAdmin): ... def formfield_for_foreignkey(self, db_field, request=None, **kwargs): formfields= super(EmployeeAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs) if request.user.is_superuser: return formfields if db_field.name == "company": #This is the RELEVANT LINE kwargs["initial"] = request.user.default_company return db_field.formfield(**kwargs) admin.site.register(Employee, EmployeeAdmin) ################################################################## # REMAINING Setups if someone would like to know it but i think # irrelevant concerning the problem ################################################################## from django.contrib.auth.models import User, UserManager class CompanyUser(User): ... objects = UserManager() company = models.ManyToManyField(Company) default_company= models.ForeignKey(Company, related_name='default_company') #I registered the CompanyUser instead of the standard User, # thats all up and working ... class Employee(models.Model): company = models.ForeignKey(Company) ... Hint: kwargs["default"] ... doesn't exist. Thanks in advance, Nick

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  • Can django's auth_user.username be varchar(75)?

    - by perrierism
    Django's auth_user.username field is 30 characters. That means you can't have auth_user.username store an email address. If you want to have users authenticate based on their email address it would seem you have to do some wonky stuff like writing your own authentication backend which authenticates based on (email, password) instead of (username, password) and furthermore, figuring out what you're going to put in the username field since it is required and it is a primary key. Do you put a hash in there, do you try to put the id in there... bleh! Why should you have to write all this code and consider edge cases simply because username is too small for your (farily common) purposes? Is there anything wrong with running alter table on auth_user to make username be varchar(75) so it can fit an email? What does that break if anything?

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  • Can't set up image upload in Django

    - by culebrón
    I can't understand what's not working here: 1) settings MEDIA_ROOT = '/var/www/satel/media' MEDIA_URL = 'http://media.satel.culebron' ADMIN_MEDIA_PREFIX = '/media/' 2) models class Photo(models.Model): id = models.AutoField(primary_key=True) name = models.CharField(max_length = 200) desc = models.TextField(max_length = 1000) img = models.ImageField(upload_to = 'upload') 3) access rights: drwxr-xrwx 3 culebron culebron 4.0K 2010-04-14 21:13 media drwxr-xrwx 2 culebron culebron 4.0K 2010-04-14 19:04 upload 4) SQL: CREATE TABLE "photos_photo" ( "id" integer NOT NULL PRIMARY KEY, "name" varchar(200) NOT NULL, "desc" text NOT NULL, "img" varchar(100) NOT NULL ); 4) run Django test server as myself. 5) result: SuspiciousOperation at /admin/photos/author/add/ Attempted access to '/var/www/satel/upload/OpenStreetMap.png' denied. Not a PIL & jpeg issue, seems not to be access rights issue. But what's wrong?

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