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• Simple but efficient way to store a series of small changes to an image?

  - by finnw

  I have a series of images. Each one is typically (but not always) similar to the previous one, with 3 or 4 small rectangular regions updated. I need to record these changes using a minimum of disk space. The source images are not compressed, but I would like the deltas to be compressed. I need to be able to recreate the images exactly as input (so a lossy video codec is not appropriate.) I am thinking of something along the lines of: Composite the new image with a negative of the old image Save the composited image in any common format that can compress using RLE (probably PNG.) Recreate the second image by compositing the previous image with the delta. Although the images have an alpha channel, I can ignore it for the purposes of this function. Is there an easy-to-implement algorithm or free Java library with this capability?

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• Flat File Connection Manager in SSIS package shows "Valid File Name Must be Selected"

  - by Traples

  (Flat File Location) Samba Share | Windows Share (SSIS) _______________________________ | | XP 32bit | Works | Works | | 2003 Serv 32bit | Works | Works | | Vista 64bit | ERROR | Works | | Win 7 64bit | ERROR | Works | | 2008 Serv 64bit | ERROR | Works I created an SSIS package in VS 2008 that parses a flat file from a shared folder and puts the records into a SQL Server db. I recently installed Windows 7 and VS 2008 on a new workstation. When I import the package from TFS and open it, I get the error Validation error. Parse and Import Catalog Flat File: MySSISPackage: The file name "\\shared\flatfile.txt" specified in the connection was not valid. When I open the Flat File Connection Manager Editor, there is an error stating: A valid file name must be selected I can browse to and select the file from inside the editor, but I cannot change any properties, or move away from the General tab because of this error. If I go back to my laptop (Windows XP), where the package was first created, there is no error. Both workstations are on the same domain, and I'm logging in using the same credentials. Any ideas as to why I would receive this error from one workstation and not another? UPDATE: If I take the .dtsx package from the running workstation and load it into SSIS on the server, I get the following errors when it tries to run: Error: The file name "\\shared\flatfile.txt" specified in the connection was not valid. and... Error: Connection "MySSISPackage" failed validation. and... Error: The file name property is not valid. The file name is a device or contains invalid characters. UPDATE 2: a) The Shared folder I'm trying to pull the flat file from is a Samba share on a Unix box. b) If I access the file using SSIS on any 64-bit platform (Windows 7 64-bit, Vista 64-bit, Windows Server 2008) I get the error "A valid file name must be selected." c) Accessing the file using SSIS from 32-bit environments (Windows XP 32-bit, Windows Server 2003 32-bit) there is no problem. d) If I move the file to a shared folder on a Windows server, 64-bit SSIS recognizes the file.

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• How to specify file permission when putting a file using OpenSSH sftp command

  - by Adi Roiban

  I am using various SFTP clients for uploading files to an SFTP server and I have a problem with default permission used when putting files. When requesting to put a file, SFTP client like WinSCP or Filezilla will send the SSH_OPEN command without requesting any explicit file permission. On the other side, it looks like the OpenSSH sftp command on Linux (Red Hat and Ubuntu) is pending the SSH_OPEN command together with the '640' mode. How can I configure the OpenSSH command to not explictly set the file mode or how can I configure it to send a mode, other than 640? Many thanks! Update: I checked the OpenSSH sftp client source code and it looks like OpenSSH sftp will always tries to preserve file mode even if -P is not set: http://www.koders.com/c/fidD3B20680F615B33ACCB42398FAAFEE1C007DF942.aspx?s=rsa#L986 To solve this problem I used Putty SFTP client.

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• File and Printer Sharing, in 10.0.0.x

  - by bubbles2

  Hi, I have a strange problem: When I assign addresses of the form 10.0.0.x to my computers, file sharing (smb) does not work. When I assign them addresse of the form 192.168.1.x it works... OS is XP SP3, for subnetmasks i tried both 255.255.255.0 and 255.0.0.0 Any ideas what I can do? [EDIT] I forgot to add: pinging doesn't work either

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• Clipboard: Copy image, get path back when pasting in file input.

  - by disown

  Hi All. First question here on superuser. I sometimes get ad-hoc bug reports from customers, which I need to transfer to our online bug tracker. Works fine for text, but pictures are tedious. I'm looking for a solution to copy-paste images from documents (like excel sheets) in a way that if you paste an image to a file input (or text input) on a html page, the file will automatically be written to disk (tmp dir), and the path written to the file input field. This question is related to Directly paste clipboard image into gmail message, but I would like to ask if there is a solution using a local program only. I'm interested in solutions for all OS's.

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• C# .NET : Is using the .NET Image Conversion enough?

  - by contactmatt

  I've seen a lot of people try to code their own image conversion techniques. It often seems to be very complicated, and ends up using GDI+ funciton calls, and manipulating bits of the image. This has got me wondering if I am missing something in the simplicity of .NET's image conversion call when saving an image. Here's the code I have Bitmap tempBmp = new Bitmap("c:\temp\img.jpg"); Bitmap bmp = new Bitmap(tempBmp, 800, 600); bmp.Save(c:\temp\img.bmp, //extension depends on format ImageFormat.Bmp) //These are all the ImageFormats I allow conversion to within the program. Ignore the syntax for a second ;) ImageFormat.Gif) //or ImageFormat.Jpeg) //or ImageFormat.Png) //or ImageFormat.Tiff) //or ImageFormat.Wmf) //or ImageFormat.Bmp)//or ); This is all I'm doing in my image conversion. Just setting the location of where the image should be saved, and passing it an ImageFormat type. I've tested it the best I can, but I'm wondering if I am missing anything in this simple format conversion, or if this is suffice?

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• How many file descriptors accessing a given file?

  - by pythonic metaphor

  On linux, is there a way to count the number of file descriptors open to a some file?

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• How to center align background image in JPanel

  - by Jaguar

  I wanted to add background image to my JFrame. Background image means I can later add Components on the JFrame or JPanel Although I coudn't find how to add background image to a JFrame, I found out how to add background image to a JPanel from here: How to set background image in Java? This solved my problem, but now since my JFrame is resizable I want to keep the image in center. The code I found uses this method public void paintComponent(Graphics g) { //Draw the previously loaded image to Component. g.drawImage(img, 0, 0, null); //Draw image } Can anyone say how to align the image to center of the JPanel. As g.drawImage(img, 0, 0, null); provides x=0 and y=0 Also if there is a method to add background image to a JFrame then I would like to know. Thanks.

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• Shared block device file system (cluster file system without networking)

  - by fungs

  Is there any file system that can be mounted multiple times and supports concurrent file access for Linux? Basically I want something like a cluster file system but without the need to have a running network for a distributed lock manager. That can be very handy in connection with virtual machines that can share data with the host or another VM without the need to create a network link. This I want to avoid to keep the network architecture secure (virtual machine in DMZ) but share large files. No need to scale it up, just two machines that mount the same block device. Shouldn't it be possible to have file locking information right on the disk?

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• Using glReadBuffer returns black image instead of the actual image only on Intel cards

  - by cloudraven

  I have this piece of code glReadBuffer( GL_FRONT ); glReadPixels( 0, 0, width, height, GL_RGB, GL_UNSIGNED_BYTE, buffer ); Which works just perfectly in all the Nvidia and AMD GPUs I have tried, but it fails in almost every single Intel built-in video that I have tried. It actually works in a very old 945GME, but fails in all the others. Instead of getting a screenshot I am actually getting a black screen. If it helps, I am working with the Doom3 Engine, and that code is derived from the built-in screen capture code. By the way, even with the original game I cannot do screen capture on those intel devices anyway. My guess is that they are not implementing the standard correctly or something. Is there a workaround for this?

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• Using glReadBuffer/glReadPixels returns black image instead of the actual image only on Intel cards

  - by cloudraven

  I have this piece of code glReadBuffer( GL_FRONT ); glReadPixels( 0, 0, width, height, GL_RGB, GL_UNSIGNED_BYTE, buffer ); Which works just perfectly in all the Nvidia and AMD GPUs I have tried, but it fails in almost every single Intel built-in video that I have tried. It actually works in a very old 945GME, but fails in all the others. Instead of getting a screenshot I am actually getting a black screen. If it helps, I am working with the Doom3 Engine, and that code is derived from the built-in screen capture code. By the way, even with the original game I cannot do screen capture on those intel devices anyway. My guess is that they are not implementing the standard correctly or something. Is there a workaround for this?

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• how to display a image in java application

  - by Nubkadiya

  i want to display a image in my java application. i found a code to download the image from the webserver. what that code do is it takes the image and show it in the jframe. i want to use a label to show the image or soemthing else. so i can put it in my java application. can someone help me. it shouldnt be JFrame please help me here is my code Image image = null; try { URL url = new URL("http://www.personal.psu.edu/acr117/blogs/audrey/images/image-2.jpg"); image = ImageIO.read(url); } catch (IOException e) { } // Use a label to display the image JFrame frame = new JFrame(); JLabel lblimage = new JLabel(new ImageIcon(image)); frame.getContentPane().add(lblimage, BorderLayout.CENTER); frame.setSize(300, 400); frame.setVisible(true); } can someone help me

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• Windows Server 08 R2 file share File locking, OSX clients

  - by Keith Loughnane

  I've spent the last two weeks banging my head against this wall. I think I'm starting to understand the problem though. I manage a design company and they have 5 macs (OSX 10.5/.6/.7) connected over SMB to a Windows 2008 R2 file server, another machine functions as Domain Controller (that might not matter). All the macs can connect ok, no issues finding the server or logging in. For the most part things are ok. The problem is files locking up. I thought it was a permissions issue at first but it seems to be file locking. The users open a file; .ind, .pdf etc the file opens, the software reads it and closes it. That's fine, but the folder above the folder locks, it can't be moved and it can't be renamed. Eg: /Working/Project01/Imagefiles/image.pdf /Finished/ The user opens image.pdf, closes it and wants to move the whole Project01 folder into Finished. It gives a username/pass dialogue and then does nothing, no error, or just does nothing. Trying to rename gives a dialogue that says you don't have permission. It looks like it's looking for permission locally, which is why I spent about a week looking at that. Eventually I found that Finder on the macs seems to be keeping the folders open. I can work around it by Killing finder, remounting the shared drive or closing the file through the server manager but this just proves the theory it's not a solution. Has anyone dealt with this problem?

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• CMD Command to create folder for each file and move file into folder

  - by Tom

  I need a command that can be run from the command line to create a folder for each file (based on the file-name) in a directory and then move the file into the newly created folders. Example : Starting Folder: Dog.jpg Cat.jpg The following command works great at creating a folder for each filename in the current working directory. for %i in (*) do md "%~ni" Result Folder: \Dog\ \Cat\ Dog.jpg Cat.jpg I need to take this one step further and move the file into the folder. What I want to achieve is: \Dog\Dog.jpg \Cat\Cat.jpg Can someone help me with one command to do all of this?

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• Image Magic - Image Levels using Custom Controls

  Drop in WPF custom leveling controls and logic

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• CMD file time not always matching windows explorer file time

  - by skyrail

  I have a set of file I need to set the created, modified and last access date to exif date taken value, after a copy between 2 folders (might be fat32 on memory card or ntfs on fixed or usb disk). When I copy a file, the date and time switch to the current date. Then I change all 3 dates manually, either with change attributes in windows explorer or far manager on the command line. To make it faster I wrote a batch script getting original file dates (with php and function stat), building a batch script that invoke nircmd setfiletime for each file. Then I apply this batch to the copied version. The operation is relatively fast and reliable. Unfortunately, a bunch of files have last access and created time different in cmd and windows explorer (1H difference). Very strangely, it happens with dates between november and february, which make the operation unreliable. Why is this happening, and how can I fix it?

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• Outlook 2010 + Move IMAP PST file = Outlook data file cannot be accessed

  - by GWB

  I set up a new IMAP account in Outlook 2010. It works but creates IMAP PST file in C:\Users\User\AppData\Local\Microsoft\Outlook. I want the file on my data drive in D:\Users\User\Documents\Outlook Files (the same folder where outlook automatically creates the local Outlook PST. I followed the instructions here to move the IMAP PST. Testing the account (send/receive) works fine, but if I try to manually send an email I get error 0x8004010F Outlook data file cannot be accessed. I've tried repairing the PST using SCANPST (it always finds errors), and deleting and recreating the account but I get the same error. If I move the PST file back, it works again, but this is not ideal. Note: I don't think this is a duplicate of this question as the cause is different and the solution does not help.

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• Windows File I/O Reading

  - by eyeanand

  Currently working on open/read images in VC++. Some examples i came across on the internet use Windows.h I/O routines like ReadFile...but there seems to be inconsistency in there declaration. Here's what i have got. //So i have this function to load file BYTE* LoadFile ( int* width, int* height, long* size, LPCWSTR bmpfile ) { BITMAPFILEHEADER bmpheader; BITMAPINFOHEADER bmpinfo; DWORD bytesread = 0; HANDLE file = CreateFile ( bmpfile , GENERIC_READ, FILE_SHARE_READ,NULL, OPEN_EXISTING, FILE_FLAG_SEQUENTIAL_SCAN, NULL ); if ( NULL == file ) return NULL; if ( ReadFile ( file, &bmpheader, sizeof ( BITMAPFILEHEADER ),&bytesread, NULL ) == false ) { CloseHandle ( file ); return NULL; } . . . return appropriate value; } Now the ReadFile API function is declared as follows in WinBase.h WINBASEAPI BOOL WINAPI ReadFile( In HANDLE hFile, Out LPVOID lpBuffer, In DWORD nNumberOfBytesToRead, _Out_opt_ LPDWORD lpNumberOfBytesRead, _Inout_opt_ LPOVERLAPPED lpOverlapped ); And in MSDN examples... They call this function like this. ReadFile(hFile, chBuffer, BUFSIZE, &dwBytesRead, NULL) Which expects that "bytesRead" is sort of out parameter. so it gives me number of bytes read. But in my code ..it is giving error message. 'ReadFile' : cannot convert parameter 4 from 'LPDWORD *' to 'LPDWORD' so i just initialized bytesRead to 0 and passed by value.( which is wrong..but just to check if it works ). then it gives this exception Unhandled exception at 0x774406ae in ImProc.exe: 0xC0000005: Access violation writing location 0x00000000. Kindly suggest . Kindly tell if any code i missed out....including while forming the question itself. Thanks.

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• close file with fopen() but file still in use

  - by Marco

  Hi all, I've got a problem with deleting/overwriting a file using my program which is also being used(read) by my program. The problem seems to be that because of the fact my program is reading data from the file (output.txt) it puts the file in a 'in use' state which makes it impossible to delete or overwrite the file. I don't understand why the file stays 'in use' because I close the file after use with fclose(); this is my code: bool bBool = true while(bBool){ //Run myprogram.exe tot generate (a new) output.txt //Create file pointer and open file FILE* pInputFile = NULL; pInputFile = fopen("output.txt", "r"); // //then I do some reading using fscanf() // //And when I'm done reading I close the file using fclose() fclose(pInputFile); //The next step is deleting the output.txt if( remove( "output.txt" ) == -1 ){ //ERROR }else{ //Succesfull } } I use fclose() to close the file but the file remains in use by my program until my program is totally shut down. What is the solution to free the file so it can be deleted/overwrited? In reality my code isn't a loop without an end ; ) Thanks in advance! Marco

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• Problems saving a photo to a file

  - by Peter vdL

  Man, I am still not able to save a picture when I send an intent asking for a photo to be taken. Here's what I am doing: Make a URI representing the pathname android.content.Context c = getApplicationContext(); String fname = c.getFilesDir().getAbsolutePath()+"/parked.jpg"; java.io.File file = new java.io.File( fname ); Uri fileUri = Uri.fromFile(file); Create the Intent (don't forget the pkg name!) and start the activity private static int TAKE_PICTURE = 22; Intent intent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE ); intent.putExtra("com.droidstogo.boom1." + MediaStore.EXTRA_OUTPUT, fileUri); startActivityForResult( intent, TAKE_PICTURE ); The camera activity starts, and I can take a picture, and approve it. My onActivityResult() then gets called. But my file doesn't get written. The URI is: file:///data/data/com.droidstogo.boom1/files/parked.jpg I can create thumbnail OK (by not putting the extra into the Intent), and can write that file OK, and later read it back). Can anyone see what simple mistake I am making? Nothing obvious shows up in the logcat - the camera is clearly taking the picture. Thanks, Peter

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• Image over a Image

  - by rupesh

  Hi i want to put a Big image over a small Image , condition is the image which is on top has some specific rectangular area where the second image will be displayed. I want the the small Image to be displayed inside the big image not over the big image. i don't no will it possible or not , if it is possible can any one provide me guidance or provide me a sample code or link thanks alot

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• Jquery image blur effect with in a div?

  - by bala3569

  Consider i have three images and one bannerDiv.... On initial page load i should show the first image and after sometimeout say 300ms i must show the second image and vise versa.... I have to blur the first image and show second image .... Any suggestion how it can be done with jquery... <div Id="BannerDiv" style="display:none;"> <img src="mylocation" alt="image1"/> <img src="mylocation" alt="image2"/> <img src="mylocation" alt="image3"/> </div> and my jquery function is, <script type="text/javascript"> $(document).ready(function() { //how to show first image and blur it to show second image after 300 ms }); </script> EDIT: 1st image to fade out after 300ms and show 2nd image 2nd image to fade out after 300ms and show 3rd image 3rd image to fade out after 300ms and show 1st image....

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• Png image processing in .NET.

  - by Oybek

  I have the following task. Take a base image and overlay on it another one. The base image is 8b png as well as overlay. Here are the base (left) and overlay (right) images. Here is a result and how it must look. The picture in the left is a screenshot when one picture is on top of another (html and positioning) and the second is the result of programmatic merging. As you can see in the screenshot the borders of the text is darker. Also here are the sizes of the images Base image 14.9 KB Overlay image 6.87 KB Result image 34.8 KB The size of the resulting image is also huge Here is my code that I use to merge those pictures /*...*/ public Stream Concatinate(Stream baseStream, params Stream[] overlayStreams) { var @base = Image.FromStream(baseStream); var canvas = new Bitmap(@base.Width, @base.Height); using (var g = canvas.ToGraphics()) { g.DrawImage(@base, 0, 0); foreach (var item in overlayStreams) { using (var overlayImage = Image.FromStream(item)) { try { Overlay(@base, overlayImage, g); } catch { } } } } var ms = new MemoryStream(); canvas.Save(ms, ImageFormat.Png); canvas.Dispose(); @base.Dispose(); return ms; } /*...*/ /*Tograpics extension*/ public static Graphics ToGraphics(this Image image, CompositingQuality compositingQuality = CompositingQuality.HighQuality, SmoothingMode smoothingMode = SmoothingMode.HighQuality, InterpolationMode interpolationMode = InterpolationMode.HighQualityBicubic) { var g = Graphics.FromImage(image); g.CompositingQuality = compositingQuality; g.SmoothingMode = smoothingMode; g.InterpolationMode = interpolationMode; return g; } My questions are What should I do in order to merge images to achieve the result as in the screenshot? How can I lower the size of the result image? Is the System.Drawing a suitable tool for this or is there any better tool for working with png for .NET?

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• Indexing community images for google image search

  - by Vittorio Vittori

  Hi, I'm trying to understand how can I do to let my site be reachable from google image search spiders. I like how last.fm solution, and I thought to use a technique like his staff do to let google find artists images on their pages. When I'm looking for an artist and I search it on google image search, as often as not I find an image from last.fm artists page, I make an example: If I search the band Pure Reason Revolution It brings me here, the artist's image page http://www.last.fm/music/Pure+Reason+Revolution/+images/4284073 Now if I take a look to the image file, i can see it's named: http://userserve-ak.last.fm/serve/500/4284073/Pure+Reason+Revolution+4.jpg so if I try to undertand how the service works I can try to say: http://userserve-ak.last.fm/serve/ the server who serve the images 500/ the selected size for the image 4284073/ the image id for database Pure+Reason+Revolution+4.jpg the image name I thought it's difficult to think the real filename for the image is Pure+Reason+Revolution+4.jpg for image overwrite problems when an user upload it, in fact if I digit: http://userserve-ak.last.fm/serve/500/4284073.jpg I probably find the real image location and filename With this tecnique the image is highly reachable from search engines and easily archived. My question is, does exist some guide or tutorial to approach on this kind of tecniques, or something similar?

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• Windows 7 ssh file server.

  - by Siriss

  Hello all- I have looked at the other posts, but have not quite found an answer I have a question about windows file sharing over SSH. I have copssh installed and it is working for Remote desktop connections. I have port 22 forwarded on my router etc. I connect from a Mac or Putty with this address: ssh -l copsshusername 3391:localhost:3389 [external ip] That works fine. I would like to configure Windows 7 to allow my ssh account that I use to login, access to certain shared folders. I have documents and videos and things that I would like to be able to download externally. I have done this before on Linux and a long time ago on XP, but I cannot figure out what I am missing on Windows 7. There is a designated SSH user that copssh uses to run the service and that I use to to login as. I have googled and googled and have not found a solution that does everything I need that is why I am turning here for ideas. I hope I am explaining this correctly. Thank you very much for your help!

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