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• No flow definition found. Spring web flow

  - by user184794

  Hi, I am new to Spring webflow and now I am trying the example in Spring recipes book and I know this is a basic question. I am getting the error as follows, org.springframework.webflow.definition.registry.NoSuchFlowDefinitionException: No flow definition '${flowExecutionUrl}&_eventId=next' found at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinitionHolder(FlowDefinitionRegistryImpl.java:126) at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinition(FlowDefinitionRegistryImpl.java:61) at org.springframework.webflow.executor.FlowExecutorImpl.launchExecution(FlowExecutorImpl.java:138) at org.springframework.webflow.mvc.servlet.FlowHandlerAdapter.handle(FlowHandlerAdapter.java:193).... Shown below is my configurations, <bean name="flowController" class="org.springframework.webflow.mvc.servlet.FlowController"> <property name="flowExecutor" ref="flowExecutor"></property> </bean> <webflow:flow-executor id="flowExecutor" /> <webflow:flow-registry id="flowRegistry" > <webflow:flow-location path="/WEB-INF/flows/welcome/welcome.xml"></webflow:flow-location> </webflow:flow-registry> /WEB-INF/flows/welcome/welcome.xml, <view-state id="welcome"> <transition on="next" to="introduction" /> <transition on="skip" to="menu" /> </view-state> <view-state id="introduction"> <on-render> <evaluate expression="libraryService.getHolidays()" result="requestScope.holidays" /> </on-render> <transition on="next" to="menu" /> </view-state> <view-state id="menu"></view-state> In welcome.jsp, <a href="${flowExecutionUrl}&_eventId=next">Next</a> <a href="${flowExecutionUrl}&_eventId=skip">Skip</a> Please let me know what is going wrong. I am using 2.0.9 Release. Thanks in advance, SD

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• JSF in jetty-equinox, Cannot find Bean classes in other bundles!

  - by Arnold

  Hi I have problems running JSF in an OSGi environment. I am using jetty web container and equinox to provide the OSGi functionality. The structure of my application is as follows: The first bundle has all the JSF libs, web.xml and a config.xml. It looks as the following: bundle1 ----src/main/java -------de/package ----------Activator.java ----------JSFResolver.java ----src/main/resource ------ WebContent ----------META-INF -------------face-config.xml --------------web.xhtml ----------start.xhtml -----------include.xhtml ----libs (containing all JSF required Jars) The structure of the second bundle is as follows: bundle2 ---src/main/java ------de/package ----------Bean.java ---src/main/resource ------META-INF ---------face-config.xml ------WebContent ---------index.xhtml When running the application of equinox, the bundle1 is the main bundle where all the browser requests are sent to. In the second bundle, the 'index.xhtml' file can be retrieved the by first bundle upon request. The 'index.xhtml' in bundle 2 gets its values and properties from the 'Bean.java' in bundle 2. The problem comes when i request the 'index.xhtml', the Bean.java class is not found. I think this is because the class loader of bundle1 cannot find it, it has no knowledge of it. So i would like to ask if anyone knows how to solve this problem. If so please do assist me, i have tried all the possibilities i had.. Is it infact possible to have JSF run on multiple bundles using the same FaceletsContex? Can i be able to have seperate faces-config.xml files in each bundle, which can all be connected other faces-config.xml in other bundles? Can anyone please provide me a solution. Sample code would help. thanks workspace_current.rar Arnold

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• Sysdeo Tomcat DevLoader - Hot deploy of java class causes whole application to restart

  - by Gala101

  Hi, I am using sysdeo tomcat plugin 3.2.1 with eclipse 3.5.1 (Galileo) and tomcat 5.5.23 on windows XP. I can get tomcat plugin working in eclipse, and have extracted devloader.zip into [tomcat]\server\classes. I have also updated the context and now it has this entry: <Context path="/myapp1" reloadable="true" docBase="F:\Work\eclipse_workspace\myapp1" workDir="F:\Work\eclipse_workspace\myapp1\work" > <Logger className="org.apache.catalina.logger.SystemOutLogger" verbosity="4" timestamp="true"/> <Loader className="org.apache.catalina.loader.DevLoader" reloadable="true" debug="1" useSystemClassLoaderAsParent="false" /> </Context> I have activated devloader (in Project Properties Tomcat Devloader Classpath) and have 'checked' all my classes and jars, I haven't 'checked' commons-loggin.jar jsp-api.jar, servlet-api.jar. So on launching tomcat via the plugin, I can get it running with devloader as shown in eclipse console view [DevLoader] Starting DevLoader [DevLoader] projectdir=F:\Work\eclipse_workspace\myapp1 [DevLoader] added file:/F:/Work/eclipse_workspace/myapp1/WEB-INF/classes/ [DevLoader] added file:/F:/Work/eclipse_workspace/myapp1/WEB-INF/lib/activation.jar However, if I even add a single System.out.println into any java file and save it, the whole application gets reloaded (takes ~80 sec) which is as good as stopping/starting tomcat itself. I've tried adding -Xdebug in JAVA_OPTS in the catalina.bat but no luck :( Can you please guide where I may be doing it wrong.. Please note that I can 'redeploy' the whole application on tomcat but that's not what I need, I am looking to be able to make small changes in java classes 'on-the-fly' while coding/debugging without having to wait for complete app restart. Another annoyance is that restarting tomcat/application causes the session/debug progress to be lost.. Can you please guide me how to go about it. PS: I am not using any ant/maven scripts explicitly, just relying on eclipse to do the build for me (which it does).

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• How to resolve a java.security.AccessControlException?

  - by thisisananth

  I have written an SAX parser in my Google App Engine Web application. in that I try to validate my xml file with an xsd. But I am getting an access control exception when my code is tyring to access that xsd. java.security.AccessControlException: access denied (java.io.FilePermission \WEB-INF\ApplicationResponse.xsd read) at java.security.AccessControlContext.checkPermission(AccessControlContext.java:264) at java.security.AccessController.checkPermission(AccessController.java:427) at java.lang.SecurityManager.checkPermission(SecurityManager.java:532) at com.google.appengine.tools.development.DevAppServerFactory$CustomSecurityManager.checkPermission(DevAppServerFactory.java:166) at java.lang.SecurityManager.checkRead(SecurityManager.java:871) at java.io.FileInputStream.(FileInputStream.java:100) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.xsdToXMLInputSource(XMLSchemaLoader.java:830) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.processJAXPSchemaSource(XMLSchemaLoader.java:708) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaLoader.loadSchema(XMLSchemaLoader.java:554) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.findSchemaGrammar(XMLSchemaValidator.java:2459) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.handleStartElement(XMLSchemaValidator.java:1807) at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.startElement(XMLSchemaValidator.java:705) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:330) at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl$NSContentDispatcher.scanRootElementHook(XMLNSDocumentScannerImpl.java:779) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(XMLDocumentFragmentScannerImpl.java:1794) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:368) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:834) at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:764) at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:148) at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1242) at sax.SAXLocalNameCount.parse(SAXLocalNameCount.java:220) at com.sms2mint.InterfaceServlet.doGet(InterfaceServlet.java:54) Please let me know how to debug this? I have tried to place the xsd in classes, webcontent, /WEB-INF but didn't help. Also declared this as a resource file in appengine-web.xml also but no avail.

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• Hudson plugin, Java error "... disagree on InnerClasses attribute"

  - by StackedCrooked

  I am trying to be able to step through the code of a Hudson plugin called SVNPublisher. I checked out the code for SVNPublisher, used Netbeans to open the project, and clicked "Debug Main project". This results in a Firefox window opening address http://localhost:8080 which shows the Hudson main page. Clicking the "New Job" link results in an error page: HTTP ERROR: 500 jar:file:/home/francis/svn/svnpublisher/target/work/webapp/WEB-INF/lib/hudson-core-1.319.jar!/lib/hudson/newFromList/form.jelly:43:47: <j:forEach> hudson.scm.SubversionTagAction and hudson.scm.SubversionTagAction$DescriptorImpl disagree on InnerClasses attribute RequestURI=/newJob Caused by: org.apache.commons.jelly.JellyTagException: jar:file:/home/francis/svn/svnpublisher/target/work/webapp/WEB-INF/lib/hudson-core-1.319.jar!/lib/hudson/newFromList/form.jelly:43:47: hudson.scm.SubversionTagAction and hudson.scm.SubversionTagAction$DescriptorImpl disagree on InnerClasses attribute at org.apache.commons.jelly.impl.TagScript.handleException(TagScript.java:713) at org.apache.commons.jelly.impl.TagScript.run(TagScript.java:282) at org.apache.commons.jelly.impl.ScriptBlock.run(ScriptBlock.java:95) ... I am very new to Hudson and not very experienced with Java so I'm pretty much clueless on the meaning of this error. Can anyone help?

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• Steps in creating a web service using Axis2 - The client code

  - by zengr

  I am trying to create a web service, my tools of trade are: ** Axis2, Eclipse, Tomcat, Ant ** I need to create a web service from Code, i.e. Write a basic java class which will have the methods to be declared in the WSDL. Then use java2WSDL.sh to create my WSDL. So, is this approach correct: Write my Java class with actual business logic package packageNamel; public class Hello{ public void World(String name) { SOP("Hello" + name); } } Now, when I pass this Hello.java to java2WSDL.sh, this will give me the WSDL. Finally, I will write the services.xml file, and create the Hello.aar with following dir structure: Hello.aar packageName Hello.class META-INF services.xml MANIFEST.MF Hello.WSDL Now, I assume, my service will be deployed when I put the aar in tomcat1/webapps/axis2/WEB-INF/services But, here comes my problem, HOW DO I ACCESS THE METHOD World(String name)???!!, i.e. I am clueless about the client code! Please enlighten me on making a very basic web service and calling the method. The above described 3 steps might be wrong. It's a community wiki, feel free to edit. Thanks

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• Common JNDI resources in Tomcat

  - by Lehane

  Hi, I’m running a couple of servlet applications in Tomcat (5.5). All of the servlets use a common factory resource that is shared out using JNDI. At the moment, I can get everything working by including the factory resource as a GlobalNamingResource in the /conf/server.xml file, and then having each servlet’s META-INF/context.xml file include a ResourceLink to the resource. Snippets from the XML files are included below. NOTE: I’m not that familiar with tomcat, so I’m not saying that this is a good configuration!!! However, I now want to be able install these servlets into multiple tomcat instances automatically using an RPM. The RPM will firstly copy the WARs to the webapps directory, and the jars for the factory into the common/lib directory (which is fine). But it will also need to make sure that the factory resource is included as a resource for all of the servlets. What is the best way add the resource globally? I’m not too keen on writing a script that goes into the server.xml file and adds in the resource that way. Is there any way for me to add in multiple server.xml files so that I can write a new server-app.xml file and it will concatenate my settings to server.xml? Or, better still to add this JNDI resource to all the servlets without using server.xml at all? p.s. Restarting the server will not be an issue, so I don’t mind if the changes don’t get picked up automatically. Thanks Snippet from server.xml <!-- Global JNDI resources --> <GlobalNamingResources> <Resource name="bean/MyFactory" auth="Container" type="com.somewhere.Connection" factory="com.somewhere.MyFactory"/> </GlobalNamingResources> The entire servlet’s META-INF/context.xml file <?xml version="1.0" encoding="UTF-8"?> <Context> <ResourceLink global="bean/MyFactory" name="bean/MyFactory" type="com.somewhere.MyFactory"/> </Context>

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• Curve fitting: Find the smoothest function that satisfies a list of constraints.

  - by dreeves

  Consider the set of non-decreasing surjective (onto) functions from (-inf,inf) to [0,1]. (Typical CDFs satisfy this property.) In other words, for any real number x, 0 <= f(x) <= 1. The logistic function is perhaps the most well-known example. We are now given some constraints in the form of a list of x-values and for each x-value, a pair of y-values that the function must lie between. We can represent that as a list of {x,ymin,ymax} triples such as constraints = {{0, 0, 0}, {1, 0.00311936, 0.00416369}, {2, 0.0847077, 0.109064}, {3, 0.272142, 0.354692}, {4, 0.53198, 0.646113}, {5, 0.623413, 0.743102}, {6, 0.744714, 0.905966}} Graphically that looks like this: We now seek a curve that respects those constraints. For example: Let's first try a simple interpolation through the midpoints of the constraints: mids = ({#1, Mean[{#2,#3}]}&) @@@ constraints f = Interpolation[mids, InterpolationOrder->0] Plotted, f looks like this: That function is not surjective. Also, we'd like it to be smoother. We can increase the interpolation order but now it violates the constraint that its range is [0,1]: The goal, then, is to find the smoothest function that satisfies the constraints: Non-decreasing. Tends to 0 as x approaches negative infinity and tends to 1 as x approaches infinity. Passes through a given list of y-error-bars. The first example I plotted above seems to be a good candidate but I did that with Mathematica's FindFit function assuming a lognormal CDF. That works well in this specific example but in general there need not be a lognormal CDF that satisfies the constraints.

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• Actual long double precision does not agree with std::numeric_limits

  - by dmb

  Working on Mac OS X 10.6.2, Intel, with i686-apple-darwin10-g++-4.2.1, and compiling with the -arch x86_64 flag, I just noticed that while... std::numeric_limits<long double>::max_exponent10 = 4932 ...as is expected, when a long double is actually set to a value with exponent greater than 308, it becomes inf--ie in reality it only has 64bit precision instead of 80bit. Also, sizeof() is showing long doubles to be 16 bytes, which they should be. Finally, using gives the same results as . Does anyone know where the discrepancy might be? long double x = 1e308, y = 1e309; cout << std::numeric_limits::max_exponent10 << endl; cout << x << '\t' << y << endl; cout << sizeof(x) << endl; gives 4932 1e+308 inf 16

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• How to run an app in Tomcat?

  - by artaxerxe

  Hi! I have put my project in tomcat_home/webapps/ directory. The structure is : project_name/WEB-INF/classes. in WEB-INF i have put my web.xml descriptor. The problem is that when i try to run the application, it doesn't find the files. The error is: The requested resource () is not available. My web.xml content is: <?xml version="1.0" encoding="ISO-8859-1"?> <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> <servlet> <servlet-name>Chapter1 Servlet</servlet-name> <servlet-class>Ch1Servlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Chapter1 Servlet</servlet-name> <servlet-url>/Serv1</servlet-url> </servlet-mapping> </web-app> I have also restarted the server, but it doesn't want to work. Any suggestions?

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• Where does Tomcat append / to directory paths?

  - by Anonymouse

  Suppose my Tomcat webapps directory looks like this: webapps/ webapps/fooapp/ webapps/fooapp/WEB-INF/ webapps/fooapp/WEB-INF/web.xml webapps/fooapp/bardir/ When I make a GET request for /fooapp/bardir, Tomcat sees that webapps/fooapp/bardir is a directory and sends back a 302 to /fooapp/bardir/ (with a slash at the end). Here is my question: Where in the Tomcat source code does this take place? (I'm looking at 6.0.x but a correct answer for any version would be a great starting point.) The only reference material I can find on this subject is in the Catalina Functional Specifications which states, regarding the Default Servlet: On each HTTP GET request processed by this servlet, the following processing shall be performed: [...] If the requested resource is a directory: If the request path does not end with "/", redirect to a corresponding path with "/" appended so that relative references in welcome files are resolved correctly. However, this functionality does not appear to be in org.apache.catalina.servlets.DefaultServlet; or at least, it's not there exclusively: if I replace the default servlet in web.xml with a servlet whose servlet-class does not exist, directory paths still come back 302 to add the slash, while every other request comes back with an error as expected.

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• Error while splitting application context file in spring

  - by Krupal

  I am trying to split the ApplicationContext file in Spring. For ex. the file is testproject-servlet.xml having all the entries. Now I want to split this single file into multiple files according to logical groups like : group1-services.xml, group2-services.xml I have created following entries in web.xml : <servlet> <servlet-name>testproject</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/group1-services.xml, /WEB-INF/group2-services.xml </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> I am using SimpleUrlHandlerMapping as: RegisterController PayrollServicesController I also have the controller defined as : .. .. The problem is that I have splitted the ApplicationContext file "testproject-servlet.xml" into two different files and I have kept the above entries in "group1-services.xml". Is it fine? I want to group things logically based on their use in seperate .xml files. But I am getting the following error when I try to access a page inside the application : org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping for [/TestProject/payroll_services.htm] in DispatcherServlet with name 'testproject' Please tell me how to resolve it. Thanks in Advance !

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• Spring factory beans not always initialised before being used.

  - by aos

  Hi, I am using spring to initialise my beans. I have configured a bean which I intend to use as a factory bean. <bean id="jsServicesFactory" class="x.y.z.JSServicesFactory" /> It is a very basic class - which has 4 getter methods. One example is public final PortletRegistry getPortletRegistry() { PortletRegistry registry = (PortletRegistry) JetspeedPortletServices .getSingleton().getService("PortletRegistryComponent"); return registry; } I have a 2nd bean which uses this factory beans to set one of its properties <bean id="batchManagerService" class="x.y.z.BatchManagerService"> ... <property name="portletRegistry"> <bean factory-bean="jsServicesFactory" factory-method="getPortletRegistry" /> </property> ... When I start my server in RAD, this all works perfectly. However when I deploy to Linux I sometimes get the following error ERROR org.springframework.web.context.ContextLoader - Context initialization failed org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'batchManagerService' defined in ServletContext resource [/WEB-INF/context/root/batchManagerContext.xml]: Cannot create inner bean 'jsServicesFactory$created#70be70be' while setting bean property 'portletRegistry'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'jsServicesFactory$created#70be70be' defined in ServletContext resource [/WEB-INF/context/root/batchManagerContext.xml]: Instantiation of bean failed; nested exception is org.springframework.beans.factory.BeanDefinitionStoreException: Factory method [public final org.apache.jetspeed.components.portletregistry.PortletRegistry x.y.z.JSServicesFactory.getPortletRegistry()] threw exception; nested exception is java.lang.NullPointerException I have tried adding depends-on="jsServicesFactory" to my bean batchManagerService but it didn't work. Any ideas? Thanks

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• How to develop JSP/Servlets Web App using MVC pattern?

  - by A.S al-shammari

  I'm developing a JSP/Servlets web app (no frameworks). I want to use MVC pattern. I designed my project like this : Controller :a servlet that reads a request, extracts the values,communicates with model objects and gives information to a JSP page. View : JSP Pages. Model : Java Classes / Java Beans .. etc . The problem : Index.jsp is the starting point (default page) in my web site. So, the Index.jsp becomes the controller to parse the request! .For example , the following request : index.jsp?section=article&id=10 parsed in index.jsp as following : <div class="midcol"> <!-- Which section? --> <%String fileName = request.getParameter("section"); if (fileName == null) { fileName = "WEB-INF/jspf/frontpage.jsp"; } else { fileName = "WEB-INF/jspf/" + fileName + ".jsp"; } %> <jsp:include page='<%= fileName%>' /> </div> Here, I can't force the servlet to be a controller .. because the index.jsp is the controller here since it's the starting point! Is there any solution to forward the request from index.jsp to the servlet and then go back to index.jsp ? Or any solution that achieves the MVC goal - the servlet should be the controller - ? I'm thinking of making a FrontPageController servlet as default page instead of index.jsp ! but I don't know if it's a perfect idea ?!

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• Spring MVC: How to resolve the path to subdirectories of the root 'JSP' folder in a web application

  - by chrisjleu

  What is a simple way to resolve the path to a JSP file that is not located in the root JSP directory of a web application using SpringMVCs viewResolvers? For example, suppose we have the following web application structure: web-app |-WEB-INF |-jsp |-secure |-admin.jsp |-admin2.jsp index.jsp login.jsp I would like to use some out-of-the-box components to resolve the JSP files within the jsp root folder and the secure subdirectory. I have a *-servlet.xml file that defines: an out-of-the-box, InternalResourceViewResolver: <bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> a handler mapping: <bean id="handlerMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <props> <prop key="/index.htm">urlFilenameViewController</prop> <prop key="/login.htm">urlFilenameViewController</prop> <prop key="/secure/**">urlFilenameViewController</prop> </props> </property> </bean> an out-of-the-box UrlFilenameViewController controller: <bean id="urlFilenameViewController" class="org.springframework.web.servlet.mvc.UrlFilenameViewController"> </bean> The problem I have is that requests to the JSPs in the secure directory cannot be resolved, as the jspViewResolver only has a prefix defined as /jsp/ and not /jsp/secure/. Is there a way to handle subdirectories like this? I would prefer to keep this structure because I'm also trying to make use of Spring Security and having all secure pages in a subdirectory is a nice way to do this. There's probably a simple way to acheive this but I'm new to Spring and the Spring MVC framework so any pointers would be appreciated.

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• Trying to use Rhino, getEngineByName("JavaScript") returns null in OpenJDK 7

  - by Yuval

  When I run the following piece of code, the engine variable is set to null when I'm using OepnJDK 7 (java-7-openjdk-i386). import javax.script.ScriptEngine; import javax.script.ScriptEngineManager; import javax.script.ScriptException; public class TestRhino { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub ScriptEngineManager factory = new ScriptEngineManager(); ScriptEngine engine = factory.getEngineByName("JavaScript"); try { System.out.println(engine.eval("1+1")); } catch (ScriptException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } It runs fine with java-6-openjdk and Oracle's jre1.7.0. Any idea why? I'm using Ubuntu 11.10. All JVMs are installed under /usr/lib/jvm. I noticed OpenJDK 7 has a different directory structure. Perhaps something is not installed right? $ locate rhino.jar /usr/lib/jvm/java-6-openjdk/jre/lib/rhino.jar /usr/lib/jvm/java-7-openjdk-common/jre/lib/rhino.jar /usr/lib/jvm/java-7-openjdk-i386/jre/lib/rhino.jar Edit Since ScriptEngineManager uses a ServiceProvider to find the available script engines, I snooped around resources.jar's META-INF/services. I noticed that in OpenJDK 6, resources.jar has a META-INF/services/javax.script.ScriptEngineFactory entry which is missing from OpenJDK 7. Any idea why? I suspect this is a bug? Here is the contents of that entry (from OpenJDK 6): #script engines supported com.sun.script.javascript.RhinoScriptEngineFactory #javascript Another edit Apparently, according to this thread, the code simply isn't there, perhaps because of merging issues between Sun and Mozilla code. I still don't understand why it was present in OpenJDK 6 and not 7. The class com.sun.script.javascript.RhinoScriptEngineFactory exists in 6's rt.jar but not in 7's. If it was not meant to be included, why is there a OpenJDK 7 rhino.jar then; and why is the source still in the OpenJDK source tree (here)?

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• Java JSP/Servlet: controller servlet throwing the famous stack overflow

  - by NoozNooz42

  I've read several docs and I don't get it: I know I'm doing something wrong but I don't understand what. I've got a website that is entirely dynamically generated: there's hardly any static content at all. So, trying to understand JSP/Servlet, I've written my own "front controller" intercepting every single query, it looks like this: <servlet-mapping> <servlet-name>defaultservlet</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> Basically I want any user request, like: example.org example.org/bar example.org/foo.html to all go through a default servlet which I've written. The servlet then examines the URI and find to which .jsp the request must be dispatched, and then does, after having set all the attributes correctly, a: RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/WEB-INF/jsp/index.jsp"); dispatcher.forward(req, resp); When I'm using a url-pattern (in web.xml) like, say, *.html, everything works fine. But when I change it to /* (to really intercept everything), I enter an endless loop and it ends up with a... StackOverflow :) When the request is dispatched, is the URI ".../WEB-INF/jsp/index.jsp" itself matched by the web.xml filter /* that I set? How should I do if I want to intercept everything using a /* url-pattern and yet be able to dispatch/forward/? I'm not asking about specs/Javadocs here: I'm really confused about the bigger picture and I'd need some explanation as to what could be going on. Am I not supposed to intercept really everything? If I can intercept everything, what should I be aware of regarding forwarding/dispatching?

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• Javascript "this" variable confusion

  - by Assaf M

  Hi I am currently reading the book "Javascript: The Good Parts" and was playing with Functions. I produced a test script to test some properties and I am somewhat confused by the results. Here is the code: <h3>Object</h3> <div style="padding-left: 10px;"> <script type="text/javascript"> function outterF() { document.writeln("outterF.this = " + this + "<br>"); function innerF() { document.writeln("innerF.this = " + this + "<br>"); return this; }; var inner = innerF(); return this; } document.writeln("<b>From Inside:</b><br>"); var outF = outterF(); var inF = outF.inner; document.writeln("<br>"); document.writeln("<b>From Outside:</b><br>"); document.writeln("outterF.this = " + outF + "<br>"); document.writeln("innerF.this = " + inF + "<br>"); </script> </div> Result is: Object From Inside: outterF.this = [object Window] innerF.this = [object Window] From Outside: outterF.this = [object Window] innerF.this = undefined Notice that outF.inner returns "undefined", is that some kind of a language bug? Obviously, outF.inner points to Window object that has nothing to do with my object but shouldn't it be at least pointing to a Function object instead? Thanks -Assaf

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• Different ways to use properties file in j2ee app

  - by Omnipresent

  I have a j2ee app using Struts2. I have a gloabl properties file which is declared in struts.properties which resides in WEB-INF/classes. It has the following setting: struts.custom.i18n.resources=mypropertyfile mypropertyfile also resides in WEB-INF/classes Say for example it contains the following: pdf.test.title=PDF Test then on jsp I use the following to make use of the property file <s:text name="pdf.test.title"/> This setup was working on Sun App server 8.2 but is not working on GlassFish App Server (I see pdf.test.title on the browser rather than PDF Test). I do not have access to GlassFish App server to try and tweak the setting to make it work. So I want to make changes to the code and see if that will help. My question is: What are some other ways to use properties file in a J2EE app? (using Struts2 or not). I'm also open to ways suggested to make changes on glassfish to make this work? Build/version #'s GlassFish = 9.1_02 (build b04-fcs) Struts2 = 2.0.6 JRE6

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• Why can't I wrap the ServletRequest when trying to capture JSP Output

  - by Patrick Cornelissen

  I am trying to dispatch in a servlet request handler to the JSP processor and capture the content of it. I am providing wrapper instances for the ServletRequest and ServletResponse, they implement the corresponding HTTPServletRequest/-Response interfaces, so they should be drop-in replacements. All methods are currently passed to the original Servlet Request object (I am planning to modify some of them soon). Additionally I have introduced some new methods. (If you want to see the code: http://code.google.com/p/gloudy/source/browse/trunk/gloudyPortal/src/java/org/gloudy/gloudlet/impl/RenderResponseImpl.java) The HttpServletResponse uses it's own output streams to capture the output. When I try to call request.getRequestDispatcher("/WEB-INF/views/test.jsp").include(request, response); With my request and response wrappers the method returns and no content has been captured. When I tried to pass the original request object it worked! But that's not what I need in the long run... request.getRequestDispatcher("/WEB-INF/views/test.jsp").include(request.getServletRequest(), response); This works. getservletRequest() returns the original Request, given by the servlet container. Does anyone know why this is not working with my wrappers?

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• Where do I put jar files in Tomcat 6?

  - by Simon

  I am having trouble getting my JSP page to load a Java class which is in a jar file. The message I get appears to indicate a class not found exception: Jan 6, 2011 12:21:45 PM org.apache.catalina.core.StandardWrapperValve invoke SEVERE: Servlet.service() for servlet jsp threw exception org.apache.jasper.JasperException: Unable to compile class for JSP: An error occurred at line: 72 in the jsp file: /xmlloader.jsp FactArray cannot be resolved to a type 69: sourceType = "1"; 70: } 71: 72: FactArray fa = new FactArray(); 73: Fact f; 74: 75: /***********************/ The Type FactArray is one of my classes in a package com.mypackage.fact.FactArray which exists in myjar.jar. myjar.jar is a separate Java project (using NetBeans, but I don't think that's relevant). I include the package in my JSP as follows: <%@ page import="com.mypackage.fact.*" %> I deploy my web site and JSPs into Tomcat 6 as a WAR file. I include myjar.jar in that WAR in WEB-INF/lib but that doesn't work. I tried putting myjar.jar in my tomcat/lib folder, but that doesn't work either. I have bounced the server several times between changes. I have read a whole bunch of questions on here which say "put it in WEB-INF/lib" but that isn't working, so I'm asking my own question. Where do I need to put common JAR files so they get picked up by Tomcat?

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• java.lang.ClassNotFoundException: org.springframework.ui.ModelMap

  - by aelshereay

  I create a simple webapp using tomcat 6, spring 2.5.6 and maven. The problem is when I boot up tomcat, I am getting the following errors: SEVERE: StandardWrapper.Throwable java.lang.NoClassDefFoundError: org/springframework/ui/ModelMap ... Caused by: java.lang.ClassNotFoundException: org.springframework.ui.ModelMap The ModelMap class does exist in spring-2.5.6.jar and spring-context-2.5.6.jar, I also have some other spring jars. All of them are being deployed to tomcat correctly, when I check the application WEB-INF (deployed to tomcat) I found all those jars there! I have only one @Controller that has a @RequestMapping("/home.htm") showForm(ModelMap model) method. My applicationContext is quite simple: <?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.directwebremoting.org/schema/spring-dwr http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd" default-autowire="byName"> <context:component-scan base-package="org.myapp"/> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/view/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans>

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• Memory Leak Looping cfmodule inside cffunction

  - by orangepips

  Hoping someone else can confirm or tell me what I'm doing wrong. I am able to consistently reproduce an OOM running by calling the file oom.cfm (shown below). Using jconsole I am able to see the request consumes memory and never releases it until complete. The issue appears to be calling <cfmodule> inside of <cffunction>, where if I comment out the <cfmodule> call things are garbage collected while the request is running. ColdFusion version: 9,0,1,274733 JVM Arguments java.home=C:/Program Files/Java/jdk1.6.0_18 java.args=-server -Xms768m -Xmx768m -Dsun.io.useCanonCaches=false -XX:MaxPermSize=512m -XX:+UseParallelGC -Xbatch -Dcoldfusion.rootDir={application.home}/ -Djava.security.policy={application.home}/servers/41ep8/cfusion.ear/cfusion.war/WEB-INF/cfusion/lib/coldfusion.policy -Djava.security.auth.policy={application.home}/servers/41ep8/cfusion.ear/cfusion.war/WEB-INF/cfusion/lib/neo_jaas.policy -Xdebug -Xrunjdwp:transport=dt_socket,server=y,suspend=n,address=56033 Test Case oom.cfm (this calls template.cfm below) <cffunction name="fun" output="false" access="public" returntype="any" hint=""> <cfset var local = structNew()/> <!--- comment out cfmodule and no OOM ---> <cfmodule template="template.cfm"> </cffunction> <cfset size = 1000 * 200> <cfloop from="1" to="#size#" index="idx"> <cfset fun()> <cfif NOT idx mod 1000> <cflog file="se-err" text="#idx# of #size#"> </cfif> </cfloop> template.cfm <!--- I am empty! --->

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• Is JPA persistence.xml classpath located?

  - by Vinnie

  Here's what I'm trying to do. I'm using JPA persistence in a web application, but I have a set of unit tests that I want to run outside of a container. I have my primary persistence.xml in the META_INF folder of my main app and it works great in the container (Glassfish). I placed a second persistence.xml in the META-INF folder of my test-classes directory. This contains a separate persistence unit that I want to use for test only. In eclipse, I placed this folder higher in the classpath than the default folder and it seems to work. Now when I run the maven build directly from the command line and it attempts to run the unit tests, the persistence.xml override is ignored. I can see the override in the META-INF folder of the maven generated test-classes directory and I expected the maven tests to use this file, but it isn't. My Spring test configuration overrides, achieved in a similar fashion are working. I'm confused at to whether the persistence.xml is located through the classpath. If it were, my override should work like the spring override since the maven surefire plugin explains "[The test class directory] will be included at the beginning the test classpath". Did I wrongly anticipate how the persistence.xml file is located? I could (and have) create a second persistence unit in the production persistence.xml file, but it feels dirty to place test configuration into this production file. Any other ideas on how to achieve my goal is welcome.

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• tomcat resource missing, servlet not running

  - by user2837260

  import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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