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  • Spring HandlerInterceptor or Spring Security to protect resource

    - by richever
    I've got a basic Spring Security 3 set up using my own login page. My configuration is below. I have the login and sign up page accessible to all as well as most everything else. I'm new to Spring Security and understand that if a user is trying to access a protected resource they will be taken to the defined login page. And upon successful login they are taken to some other page, home in my case. I want to keep the latter behavior; however, I'd like specify that if a user tries to access certain resources they are taken to the sign up page, not the login page. Currently, in my annotated controllers I check the security context to see if the user is logged in and if not I redirect them to the sign up page. I only do this currently with two urls and no others. This seemed redundant so I tried creating a HandlerInterceptor to redirect for these requests but realized that with annotations, you can't specify specific requests to be handled - they all are. So I'm wondering if there is some way to implement this type of specific url handling in Spring Security, or is going the HandlerInterceptor route my only option? Thanks! <http auto-config="true" use-expressions="true"> <intercept-url pattern="/login*" access="permitAll"/> <intercept-url pattern="/signup*" access="permitAll"/> <intercept-url pattern="/static/**" filters="none" /> <intercept-url pattern="/" access="permitAll"/> <form-login login-page="/login" default-target-url="/home"/> <logout logout-success-url="/home"/> <anonymous/> <remember-me/> </http>

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  • authlogic in Rails

    - by Adnan
    Hello, I am using the authlogic gem for authentication. I have followed the steps at: http://railscasts.com/episodes/160-authlogic I have the following code: # config/environment.rb config.gem "authlogic" # models/user.rb acts_as_authentic # users_controller.rb def create @user = User.new(params[:user]) if @user.save flash[:notice] = "Registration successful." redirect_to root_url else render :action => 'new' end end def edit @user = current_user end def update @user = current_user if @user.update_attributes(params[:user]) flash[:notice] = "Successfully updated profile." redirect_to root_url else render :action => 'edit' end end # user_sessions_controller.rb def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Successfully logged in." redirect_to root_url else render :action => 'new' end end def destroy @user_session = UserSession.find @user_session.destroy flash[:notice] = "Successfully logged out." redirect_to root_url end # application_controller.rb filter_parameter_logging :password helper_method :current_user private def current_user_session return @current_user_session if defined?(@current_user_session) @current_user_session = UserSession.find end def current_user return @current_user if defined?(@current_user) @current_user = current_user_session && current_user_session.record end # config/routes.rb map.login "login", :controller => "user_sessions", :action => "new" map.logout "logout", :controller => "user_sessions", :action => "destroy" I got it all working, except I would like to have a user_id in session so I can track which user posted which post, where should I set it?

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  • UINavigationBar is getting buttons from another view

    - by Rafael Oliveira
    I have three Views, Splash, Login and List. From Splash I just wait and then Push Login View, with the Navigation Bar hidden. In Login I Show the NavigationBar, hide the BackButton1 and add a new RightButton1, then I check if Settings.bundle "login" and "pass" are set. If so, I push List View. Otherwise I stay in the Login view waiting for the user to fill the form and press a button. In List View I add a new RightButton2 and a new BackButton2. The problem is that if Settings.bundle data is not null, and in Login View I quickly push List View the RightButton1 appears in List View, or no buttons appear at all, or only BackButton2 doesn't appear... The most strange thing of all is that everything was OK and all of sudden it started to get messy. Login View: // Making the Navigation Bar Visible [self.navigationController setNavigationBarHidden:NO animated:NO]; // Hiding the Back Button in THIS view (Login) [self.navigationItem setHidesBackButton:YES]; // Inserting the Logout Button for the Next View (List) UIBarButtonItem *backButton = [[UIBarButtonItem alloc] initWithTitle:@"Logout" style:UIBarButtonItemStylePlain target:nil action:nil]; self.navigationItem.backBarButtonItem = backButton; [backButton release]; UIBarButtonItem* newAccountButton = [[UIBarButtonItem alloc] initWithTitle:@"New Account" style:UIBarButtonItemStylePlain target:self action:@selector(newAccountButtonPressed)]; self.navigationItem.rightBarButtonItem = newAccountButton; [newAccountButton release]; List View // Making the Navigation Bar Visible [self.navigationController setNavigationBarHidden:NO animated:NO]; UIBarButtonItem* aboutButton = [[UIBarButtonItem alloc] initWithTitle:@"About" style:UIBarButtonItemStylePlain target:self action:@selector(aboutButtonPressed)]; self.navigationItem.rightBarButtonItem = aboutButton; [aboutButton release]; Any ideas ?

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  • IE6 background-position(?) issue

    - by turezky
    I apply to stackoverflow as my last resort. I got this ie6 bug while using the image at the background of the link. It seems that ie6 scrolls the background. How can I avoid it? At some width it shows like this: And at some other it shows like that: IE7 & FF show this just like I expect: The links are placed inside the div which is floating to the right. <a href="/tr" class="menuLink" style="background-image:url(/img/tr.png);">TR</a> <a href="/eng" class="menuLink" style="background-image:url(/img/eng.png); margin-right:30px;">ENG</a> <a href="/logout" class="menuLink" style="background-image:url(/img/logout.png);"><?=$ui["exit"];?></a> .menuLink { font-family:"Tahoma"; font-size:11px; color:#003300; text-decoration:underline; font-weight: bold; background-position:0% 50%; background-repeat:no-repeat; } .menuLink:hover { font-size:11px; color:#047307; text-decoration:underline; font-weight: bold; } Any hints how can I avoid this?

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  • USE case to Class Diagram - How do I?

    - by 01010011
    Hi, I would like your guidance on how to create classes and their relationships (generalization, association, aggregation and composition) accurately from my USE case diagram (please see below). I am trying to create this class diagram so I can use it to create a simple online PHP application that allows the user to register an account, login and logout, and store, search and retrieve data from a MySQL database. Are my classes correct? Or should I create more classes? And if so, what classes are missing? What relationships should I use when connecting the register, login, logout, search_database and add_to_database to the users? I'm new to design patterns and UML class diagrams but from my understanding, the association relationship relates one object with another object; the aggregation relationship is a special kind of association that allows "a part" to belong to more than one "whole" (e.g. a credit card and its PIN - the PIN class can also be used in a debit card class); and a composition relationship is a special form of aggregation that allows each part to belong to only one whole at a time. I feel like I have left out some classes or something because I just can't seem to find the relationships from my understanding of relationships. Any assistance will be really appreciated. Thanks in advance. USE CASE DIAGRAM CLASS DIAGRAM

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  • how to retrive pK using spring security

    - by aditya
    i implement this method of the UserDetailService interface, public UserDetails loadUserByUsername(final String username) throws UsernameNotFoundException, DataAccessException { final EmailCredential userDetails = persistentEmailCredential .getUniqueEmailCredential(username); if (userDetails == null) { throw new UsernameNotFoundException(username + "is not registered"); } final HashSet<GrantedAuthority> authorities = new HashSet<GrantedAuthority>(); authorities.add(new GrantedAuthorityImpl("ROLE_USER")); for (UserRole role:userDetails.getAccount().getRoles()) { authorities.add(new GrantedAuthorityImpl(role.getRole())); } return new User(userDetails.getEmailAddress(), userDetails .getPassword(), true, true, true, true, authorities); } in the security context i do some thing like this <!-- Login Info --> <form-login default-target-url='/dashboard.htm' login-page="/login.htm" authentication-failure-url="/login.htm?authfailed=true" always-use-default-target='false' /> <logout logout-success-url="/login.htm" invalidate-session="true" /> <remember-me user-service-ref="emailAccountService" key="fuellingsport" /> <session-management> <concurrency-control max-sessions="1" /> </session-management> </http> now i want to pop out the Pk of the logged in user, how can i show it in my jsp pages, any idea thanks in advance

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  • Ghost activity in android

    - by Ari
    My application works as follow: On start I have some AppStartActivity which does something, finishes itself and starts MainActivity if user is logged in or LoginActivity otherwise. LoginActivity finishes itself and starts MainActivity when user log in successfully. On MainActivity I have SomeActivity from which user can logout. Activity stack for this situation is MainActivity > SomeActivity. It is correct, back button works well. When user click LogOut button there is a problem. I need to show LoginActivity but I don't want to have MainActivity and SomeActivity on activity stack anymore. I could resolve this problem if I wouldn't finish AppStartActivity. I could go back then with flag FLAG_ACTIVITY_CLEAR_TOP and it would work well. But here is a problem with back button. I don't want user to come back to this activity with back button. I want it to exit app instead. UPDATED: Flags FLAG_ACTIVITY_NEW_TASK and FLAG_ACTIVITY_CLEAR_TASK would be best, but I need it working in API level 9.

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  • How to use sessions in PDO?

    - by Byakugan
    I am still redoing and getting rid of old mysql_* commands in my code. I tried to transfer my session login form old code and this is what I got so far: public function login($user, $password) { if (!empty($user) && !empty($password)) { $password = $web->doHash($user, $password); // in this function is (return sha1(strtoupper($user).':'.strtoupper($password)) $stmt = $db_login->prepare("SELECT * FROM account WHERE username=:user AND pass_hash=:password"); $stmt->bindValue(':user', $user, PDO::PARAM_STR); $stmt->bindValue(':password', $password, PDO::PARAM_STR); $stmt->execute(); $rows = $stmt->rowCount(); if ($rows > 0) { $results_login = $stmt->fetch(PDO::FETCH_ASSOC); $_SESSION['user_name'] = $results_login['username']; $_SESSION['user_id'] = $results_login['id']; return true; } else { return false; } } else { return false; } } After that I am using checks if user logged on site: public function isLogged() { return (!empty($_SESSION['user_id']) && !empty($_SESSION['user_name'])); } But it seems - this function returns always empty because $_SESSION does not exists in PDO? And of course logout is used in this form on my sites: public function logout() { unset($_SESSION['user_id']); unset($_SESSION['user_name']); } But I think PDO has different way of handling session? I did not find any so what is it can i somehow add $_SESSION in PDO withou changing code much? I am using variables $_SESSION['user_name'] and $_SESSION['user_id'] in all over my web project. Summary: 1) How to use sessions in PDO correctly? 2) What is difference between using $stmt->fetch(PDO::FETCH_ASSOC); and $stmt->fetchAll(); Thank you.

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  • setting default value of superglobal

    - by Prasoon Saurav
    I have been working on a Timesheet Management website. I have my home page as index.php //index.php <?php session_start(); if($_SESSION['logged']=='set') { $x=$_SESSION['username']; echo '<div align="right">'; echo 'Welcome ' .$x.'<br/>'; echo'<a href="logout.php" class="links">&nbsp;<b><u>Logout</u></b></a>' ; } else if($_SESSION['logged']='unset') { echo'<form id="searchform" method="post" action="processing.php"> <div> <div align="right"> Username&nbsp;<input type="text" name="username" id="s" size="15" value="" /> &nbsp;Password&nbsp;<input type="password" name="pass" id="s" size="15" value="" /> <input type="submit" name="submit" value="submit" /> </div> <br /> </div> </form> '; } ?> The problem I am facing is that during the first run of this script I get an error Notice: Undefined index: logged in C:\wamp\www\ps\index.php but after refreshing the page the error vanishes. How can I correct this problem? logged is a variable which helps determine whether the user is logged in or not. When the user is logged in $_SESSION['logged'] is set, otherwise unset. I want the default value of $_SESSION['logged'] to be unset prior to the execution of the script. How can I solve this problem?

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  • AJAX Post Not Sending Data?

    - by Jascha
    I can't for the life of me figure out why this is happening. This is kind of a repost, so forgive me, but I have new data. I am running a javascript log out function called logOut() that has make a jQuery ajax call to a php script... function logOut(){ var data = new Object; data.log_out = true; $.ajax({ type: 'POST', url: 'http://www.mydomain.com/functions.php', data: data, success: function() { alert('done'); } }); } the php function it calls is here: if(isset($_POST['log_out'])){ $query = "INSERT INTO `token_manager` (`ip_address`) VALUES('logOutSuccess')"; $connection->runQuery($query); // <-- my own database class... // omitted code that clears session etc... die(); } Now, 18 hours out of the day this works, but for some reason, every once in a while, the POST data will not trigger my query. (this will last about an hour or so). I figured out the post data is not being set by adding this at the end of my script... $query = "INSERT INTO `token_manager` (`ip_address`) VALUES('POST FAIL')"; $connection->runQuery($query); So, now I know for certain my log out function is being skipped because in my database is the following data: if it were NOT being skipped, my data would show up like this: I know it is being skipped for two reasons, one the die() at the end of my first function, and two, if it were a success a "logOutSuccess" would be registered in the table. Any thoughts? One friend says it's a janky hosting company (hostgator.com). I personally like them because they are cheap and I'm a fan of cpanel. But, if that's the case??? Thanks in advance. -J

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  • PHP: Making my code simpler/shorter welcome message

    - by Karem
    Any suggestion to make this welcome message shorter: <?php if(isset($_SESSION['user_id'])) { if(isSet($_SESSION['1stTime'])){ ?> <strong id="welcome" style="font-size: 10px;"> <a href="logout.php"> Logga ut </a> </strong> <?php }else{ $_SESSION['1stTime'] = time(); ?> <script> $(document).ready(function() { $("#welcome").fadeIn("slow"); setTimeout(function(){ $("#welcome").fadeOut("slow"); setTimeout(function(){ $("#welcome").html("<a href='logout.php'>Logga ut</a>"); $("#welcome").fadeIn(); }, 800); }, 5000); }); </script> <strong id="welcome" style="display: none; color: #FFF; font-size: 10px;">Hej, <?php echo $FULL; ?>!</strong> <?php } } ?> First it checks if you are signed in. Next if 1stTime is set, if it is then show "Log out" in swedish, if it isnt, then introduce with "Hi, NAME", and then change to "Log out" after 5 seconds(jquery) + set the session How can i make this simpler?

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  • ReWriteRule is redirecting rather rewriting

    - by James Doc
    At the moment I have two machines that I do web development on; an iMac for work at the office and a MacBook for when I have to work on the move. They both running OS X 10.6 have the same version of PHP, Apache, etc running on them. Both computers have the same files of the website, including the .htaccess file (see below). On the MacBook the URLs are rewritten nicely, masking the URL they are pointing to (eg site/page/page-name), however on the iMac they simply redirect to the page (eg site/index.php?method=page&value=page-name) which is making switching back and forth between machines a bit of a pain! I'm sure it must be a config setting somewhere, but I can't for the life of me find it. Has anyone got a remedy? Many thanks. I'm fairly convinced there is a much nice way of writing this htaccess file without loosing access several key folders as well! Options +FollowSymlinks RewriteEngine on RewriteBase /In%20Progress/Vila%20Maninga/ RewriteRule ^page/([a-z|0-9_&;=-]+) index.php?method=page&value=$1 [NC] RewriteRule ^tag/([a-z|0-9_]+) index.php?method=tag&value=$1 [NC] RewriteRule ^search/([a-z|0-9_"]+) index.php?method=search&value=$1 [NC] RewriteRule ^modpage/([con0-9-]+) index.php?method=modpage&value=$1 [NC] RewriteRule ^login index.php?method=login [NC] RewriteRule ^logout index.php?method=logout [NC] RewriteRule ^useraccounts index.php?method=useraccounts [NC]

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  • Is there a better way to change user password in cakephp using Auth?

    - by sipiatti
    Hi, I am learning cakephp by myself. I tried to create a user controller with a changepassword function. It works, but I am not sure if this is the best way, and I could not googled up useful tutorials on this. Here is my code: class UsersController extends AppController { var $name = 'Users'; function login() { } function logout() { $this->redirect($this->Auth->logout()); } function changepassword() { $session=$this->Session->read(); $id=$session['Auth']['User']['id']; $user=$this->User->find('first',array('conditions' => array('id' => $id))); $this->set('user',$user); if (!empty($this->data)) { if ($this->Auth->password($this->data['User']['password'])==$user['User']['password']) { if ($this->data['User']['passwordn']==$this->data['User']['password2']) { // Passwords match, continue processing $data=$this->data; $this->data=$user; $this->data['User']['password']=$this->Auth->password($data['User']['passwordn']); $this->User->id=$id; $this->User->save($this->data); $this->Session->setFlash('Password changed.'); $this->redirect(array('controller'=>'Toners','action' => 'index')); } else { $this->Session->setFlash('New passwords differ.'); } } else { $this->Session->setFlash('Typed passwords did not match.'); } } } } password is the old password, passwordn is the new one, password2 is the new one retyped. Is there any other, more coomon way to do it in cake?

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  • Namespaced controller redirect urls

    - by bajki
    Hello, i have probably a simple question. I have created a namespace panel with categories controller. After creating or editing a category, rails redirects me to website.com/categories/:id instead of website.com/panel/categories/:id. I've noticed that in the _form view, the @panel_categories argument of form_for() function points to /categories nor /panel/categories and that's causing this behaviour. Offcourse i can add a :url => '/panel/categories' param but i feel that it's not the best solution... Can you provide me any better solution? Thanks in advance Files: routes.rb: Photowall::Application.routes.draw do resources :photos resources :categories resources :fields resources :users, :user_sessions match 'login' => 'user_sessions#new', :as => :login match 'logout' => 'user_sessions#destroy', :as => :logout namespace :panel do root :to => "photos#index" resources :users, :photos, :categories, :fields end namespace :admin do root :to => "users#index" resources :users, :photos, :categories, :fields end end categories_controller.rb: http://pastebin.com/rWJykCCF model is the default one form: http://pastebin.com/HGmkZZHM

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  • RoR routing problem. Calling custom action, but getting redirected to show action

    - by conorgil
    I am working on a project in ruby on rails and I am having a very difficult time with a basic problem. I am trying to call a custom action in one of my controllers, but the request is somehow getting redirected to the default 'show' action and I cannot figure out why. link in edit.html.erb: <%= link_to 'Mass Text Entry', :action=>"create_or_add_food_item_from_text" %> Error from development.log: ActiveRecord::RecordNotFound (Couldn't find Menu with ID=create_or_add_food_item_from_text): app/controllers/menus_controller.rb:20:in `show' routes.rb file: ActionController::Routing::Routes.draw do |map| map.resources :nutrition_objects map.resources :preference_objects map.resources :institutions map.resources :locations map.resources :menus map.resources :food_items map.resources :napkins map.resources :users map.resource :session, :controller => 'session' map.root :controller=>'pages', :action=>'index' map.about '/about', :controller=>'pages', :action=>'about' map.contact '/contact', :controller=>'pages', :action=>'contact' map.home '/home', :controller=>'pages', :action=>'index' map.user_home '/user/home', :controller=>'rater', :action=>'index' map.user_napkins '/user/napkins', :controller=>'rater', :action=>'view_napkins' map.user_preferences '/user/preferences',:controller=>'rater', :action=>'preferences' map.blog '/blog', :controller=>'pages', :action=>'blog' map.signup '/signup', :controller=>'users', :action=>'new' map.login '/login', :controller=>'session', :action=>'new' map.logout '/logout', :controller=>'session', :action=>'destroy' # Install the default routes as the lowest priority. map.connect ':controller/:action' map.connect ':controller/:action/:id' map.connect ':controller/:action/:id.:format' end Menus_controller.rb: class MenusController < ApplicationController ... def create_or_add_food_item_from_text end ... end create_or_add_food_item_from_text.html.erb simply has a div to show a form with a text box in it. I have the rest of my app working fine, but this is stumping me. Any help is appreciated.

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  • OOP + MVC advice on Member Controller

    - by dan727
    Hi, I am trying to follow good practices as much as possible while I'm learning using OOP in an MVC structure, so i'm turning to you guys for a bit of advice on something which is bothering me a little here. I am writing a site where I will have a number of different forms for members to fill in (mainly data about themselves), so i've decided to set up a Member controller where all of the forms relating to the member are represented as individual methods. This includes login/logout methods, as well as editing profile data etc. In addition to these methods, i also have a method to generate the member's control panel widget, which is a constant on every page on the site while the member is logged in. The only thing is, all of the other methods in this controller all have the same dependencies and form templates, so it would be great to generate all this in the constructor, but as the control_panel method does not have the same dependencies etc, I cannot use the constructor for this purpose, and instead I have to redeclare the dependencies and same template snippets in each method. This obviously isn't ideal and doesn't follow DRY principle, but I'm wondering what I should do with the control_panel method, as it is related to the member and that's why I put it in that controller in the first place. Am I just over-complicating things here and does it make sense to just move the control_panel method into a simple helper class? Here are the basic methods of the controller: class Member_Controller extends Website_Controller { public function __construct() { parent::__construct(); if (request::is_ajax()) { $this->auto_render = FALSE; // disable auto render } } public static function control_panel() { //load control panel view $panel = new View('user/control_panel'); return $panel; } public function login() { } public function register() { } public function profile() { } public function household() { } public function edit_profile() { } public function logout() { } }

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  • xterm window gets stuck after some time

    - by eSKay
    I am using xterm on RHEL with KDE. Usually after a couple of days, the xterm terminals get stuck i.e. I am not able to resize or relocate them. After this, even if I open a new terminal, it is stuck the same way. What I do is logout and login again. Is this a bug with xterm? Is there a known solution?

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  • how to run a program using command line with parameters on mac os x

    - by user36089
    Hello everyone I try to use APIKit http://ericasadun.com/2009/12/apikit-goes-beta/ to scan my codes to detect if there is private api. apiscanner should run as apiscanner ~/Desktop/MyPath/myapp.app I used command 'cd' go to the directory where apiscanner is. But if I call apiscanner ~/Desktop/MyPath/MyApp.app Last login: Sun Jun 13 07:22:07 on ttys002 unknown required load command 0x80000022 Trace/BPT trap logout Even I copy file 'apiscanner' and 'doit' to MyPath, the execute same problem I think there is somethin wrong when I run apiscanner under mac osx Welcome any comment Thanks interdev

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  • "tshark: There are no interfaces on which a capture can be done" in Amazon Linux AMI

    - by user1264304
    My goal is to capture packets with tshark in Amazon Linux AMI. While typing tshark in the command line there's an error: "tshark: There are no interfaces on which a capture can be done" How to implement the solution from Wireshark setup Linux for nonroot user $ sudo apt-get install wireshark $ sudo dpkg-reconfigure wireshark-common $ sudo usermod -a -G wireshark $USER $ gnome-session-quit --logout --no-prompt in Amazon Linux AMI (it's not Ubuntu)? Thanks.

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  • SSH Advanced Logging

    - by Radek Šimko
    I've installed OpenSUSE on my server and want to set ssh to log every command, which is send to system over it. I've found this in my sshd_config: # Logging # obsoletes QuietMode and FascistLogging #SyslogFacility AUTH #LogLevel INFO I guess that both of those directives has to be uncommented, but I'd like to log every command, not only authorization (login/logout via SSH). I just want to know, if someone breaks into my system, what did he do.

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  • NetBeans remote synchronization : failed to save file

    - by yoda
    Hi, I'm using NetBeans in a project, making use of remote sync to save both locally and to a FTP server. This feature works in other projects, but this time is failing when trying to save the file to the remote server. The IDE log tells me that had occurred a unknown error, as well as this : Upload failed: org.netbeans.modules.php.project.connections.TransferInfo [transfered: [], failed: {index.php=Cannot upload file index.php (unknown reason).}, partially failed: {}, ignored: {}, runtime: 61136 ms] Cannot logout from server The version of the IDE is 6.8. Cheers

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  • Leave bash script running on remote terminal while not logged in?

    - by mechko
    I have a bash script that takes several hours to run. While it's running, I would like to do other things, which may involve logging out or disconnecting from the internet (my script runs network tests on various computers). I understand that there is a command that would allow me to run my tests from a remote terminal and logout of the terminal while it runs. Does anyone know what this command is? Thanks

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