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  • Ways to ensure unique instances of a class?

    - by Peanut
    I'm looking for different ways to ensure that each instance of a given class is a uniquely identifiable instance. For example, I have a Name class with the field name. Once I have a Name object with name initialised to John Smith I don't want to be able to instantiate a different Name object also with the name as John Smith, or if instantiation does take place I want a reference to the orginal object to be passed back rather than a new object. I'm aware that one way of doing this is to have a static factory that holds a Map of all the current Name objects and the factory checks that an object with John Smith as the name doesn't already exist before passing back a reference to a Name object. Another way I could think of off the top of my head is having a static Map in the Name class and when the constructor is called throwing an exception if the value passed in for name is already in use in another object, however I'm aware throwing exceptions in a constructor is generally a bad idea. Are there other ways of achieving this?

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  • Installing Command-T breaks MacVim

    - by Mark Szymanski
    I am trying to install Command-T on MacVim. I followed the installation instructions exactly but I get this error when trying to start MacVim (from a terminal via the mvim command line utility). dyld: lazy symbol binding failed: Symbol not found: _rb_intern2 Referenced from: /Users/mark/.vim/ruby/command-t/ext.bundle Expected in: flat namespace dyld: Symbol not found: _rb_intern2 Referenced from: /Users/mark/.vim/ruby/command-t/ext.bundle Expected in: flat namespace Vim: Caught deadly signal TRAP Vim: Finished.

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  • replace symbol in javascript

    - by Jin Yong
    Does anyone know how can I replace this 2 symbol below from the string into code? ' left single quotation mark into ‘ ' right single quotation mark into ’ " left double quotation mark into “ " right double quotation mark into ”

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  • Carolina Code Camp 2010

    - by Mark A. Wilson
    "Grow your skills in 2010" The Enterprise Developers Guild in Charlotte, the Greenville-Spartanburg Enterprise Developers Guild and the Triad Developers Guild have joined with Microsoft and Central Piedmont Community College (CPCC) Association for Computing Machinery (ACM) to present the 10th MSDN Code Camp to be held in Charlotte. Please join me and fellow developers and code enthusiasts on Saturday, May 15, 2010, at the CPCC Levine Campus in Matthews, NC. The focus this year is Microsoft Visual Studio 2010 and Windows Phone 7. Everyone is invited to attend and/or speak! Get in-depth exposure to Visual Studio 2010 and other exciting new Microsoft technologies. Sessions will range from presentations, to hands on labs, to informal "chalk talks". We will have a mix of speakers including Microsoft MVPs, authors, and most importantly, local developers just like you! And thanks to the generosity of our contributors, we will be able to provide breakfast, lunch, snacks, and lots of swag. Registration is open and there are a limited number of seats left. For more information or to register, visit the Carolina Code Camp 2010 event website. I encourage you to "give back" by registering as a volunteer or a proctor. This will be the only Carolina Code Camp held this year – no event is schedule for the fall – so register today before it’s too late! Thanks for visiting and till next time, Mark A. Wilson      Mark's Geekswithblogs Blog Enterprise Developers Guild Technorati Tags: Community

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  • Unable to install Dockmanager

    - by Mark Rooney
    I have Docky installed on Ubuntu 10.10 64bit and noticed after a recent upgrade my 'Helpers' are no longer available. After some research I found that Dockmanager is no longer installed either. I am unable to install it via the Software centre or via terminal using apt-get, the following error is returned; mark@Sonata:~$ sudo apt-get install dockmanager Reading package lists... Done Building dependency tree Reading state information... Done The following NEW packages will be installed: dockmanager 0 upgraded, 1 newly installed, 0 to remove and 0 not upgraded. Need to get 0B/94.4kB of archives. After this operation, 430kB of additional disk space will be used. (Reading database ... 162015 files and directories currently installed.) Unpacking dockmanager (from .../dockmanager_0.1.0~bzr83-0ubuntu1~10.10~dockers1_amd64.deb) ... dpkg: error processing /var/cache/apt/archives/dockmanager_0.1.0~bzr83-0ubuntu1~10.10~dockers1_amd64.deb (--unpack): trying to overwrite '/usr/share/dockmanager/data/skype_invisible.svg', which is also in package faenza-icon-theme 0.8 dpkg-deb: subprocess paste killed by signal (Broken pipe) Errors were encountered while processing: /var/cache/apt/archives/dockmanager_0.1.0~bzr83-0ubuntu1~10.10~dockers1_amd64.deb E: Sub-process /usr/bin/dpkg returned an error code (1) mark@Sonata:~$ Can anyone advise on how to fix this?

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  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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  • Tricky SQL query involving consecutive values

    - by Gabriel
    I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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  • Crontab: cut line to many lines?

    - by Heoa
    Hard-to-read-line @daily export sunshine="~/logs/Sunshine-`date '+\%F'`" && export sunshineUrl="http://www.sunshine.net/main/search_results.asp?currency_id=1&min_price=&max_price=50000&country_id=241&region_id=&Submit=Search" && mkdir -p $sunshine && cd $sunshine && wget --mirror -l 1 $sunshineUrl Which mark do I need to have it on many lines? @daily <SOME MARK HERE> export sunshine="~/logs/Sunshine-`date '+\%F'`" && <SOME MARK HERE> export sunshineUrl="http://www.sunshine.net/main/search_results.asp?currency_id=1&min_price=&max_price=50000&country_id=241&region_id=&Submit=Search" && <SOME MARK HERE> mkdir -p $sunshine && <SOME MARK HERE> cd $sunshine && wget --mirror -l 1 $sunshineUrl No success by appending \, //, \n or /n.

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  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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  • Draw polygon using mouse on google maps

    - by Kunal
    I need to draw polygon using mouse and mark a particular area on google maps. The purpose is to mark an area on google maps and then showing hotels and attractions on that area. The user will mark the hotels on google map while creating them so the db will have their latitude and longitudes. How can I draw the polygon and fill it with a color as background to mark the area in Google Maps? I have read the API Manual “how to draw polygons?” basically you would need to mark multiple points and then combine them into a polygon. But I will need to do this using mouse drag, just like drawing a shape. Kindly help me out how to achieve this. Thanks in advance.

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  • Creating an excel macro to sum lines with duplicate values

    - by john
    I need a macro to look at the list of data below, provide a number of instances it appears and sum the value of each of them. I know a pivot table or series of forumlas could work but i'm doing this for a coworker and it has to be a 'one click here' kinda deal. The data is as follows. A B Smith 200.00 Dean 100.00 Smith 100.00 Smith 50.00 Wilson 25.00 Dean 25.00 Barry 100.00 The end result would look like this Smith 3 350.00 Dean 2 125.00 Wilson 1 25.00 Barry 1 100.00 Thanks in advance for any help you can offer!

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  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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  • Is it possible to use ContainsTable to get results for more than one column?

    - by LockeCJ
    Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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  • I thought this parsing would be simple...

    - by Rebol Tutorial
    ... and I'm hitting the wall, I don't understand why this doesn't work (I need to be able to parse either the single tag version (terminated with /) or the 2 tag versions (terminated with ) ): Rebol[] content: {<pre:myTag attr1="helloworld" attr2="hello"/> <pre:myTag attr1="helloworld" attr2="hello"> </pre:myTag> <pre:myTag attr3="helloworld" attr4="hello"/> } spacer: charset reduce [#" " newline] letter: charset reduce ["ABCDEFGHIJKLMNOPQRSTUabcdefghijklmnopqrstuvwxyz1234567890="] rule: [ any [ {<pre:myTag} any [any letter {"} any letter {"}] mark: (print {clipboard... after any letter {"} any letter {"}} write clipboard:// mark input) any spacer mark: (print "clipboard..." write clipboard:// mark input) ["/>" | ">" any spacer </pre:myTag> ] any spacer (insert mark { Visible="false"}) ] to end ] parse content rule write clipboard:// content print "The end" input

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  • Parsing complex string using regex

    - by wojtek_z
    My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

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  • More Quick Interview Tips

    - by Ajarn Mark Caldwell
    In the last couple of years I have conducted a lot of interviews for application and database developers for my company, and I can tell you that the little things can mean a lot.  Here are a few quick tips to help you make a good first impression. A year ago I gave you my #1 interview tip: Do some basic research!  And a year later, I am still stunned by how few technical people do the most basic of research.  I can only guess that it is because it is so engrained in our psyche that technical competence is everything (see How to Manage Technical Employees for more on this idea) that we forget or ignore the importance of soft skills and the art of the interview.  Or maybe it is because we have heard the stories of the uber-geek who has zero personal skills but still makes a fortune working for Microsoft.  Well, here’s another quick tip:  You’re probably not as good as he is; and a large number of companies actually run small to medium sized teams and can’t really afford to have the social outcast in the group.  In a small team, everyone has to get along well, and that’s an important part of what I’m evaluating during the interview process. My #2 tip is to act alive!  I typically conduct screening interviews by phone before I bring someone in for an in-person.  I don’t care how laid-back you are or if you have a “quiet personality”, when we are talking, ACT like you are happy I called and you are interested in getting the job.  If you sound like you are bored-to-death and that you would be perfectly happy to never work again, I am perfectly happy to help you attain that goal, and I’ll move on to the next candidate. And closely related to #2, perhaps we’ll call it #2.1 is this tip:  When I call you on the phone for the interview, don’t answer your phone by just saying, “Hello”.  You know that the odds are about 999-to-1 that it is me calling for the interview because we have specifically arranged this time slot for the call.  And you can see on the caller ID that it is not one of your buddies calling, so identify yourself.  Don’t make me question whether I dialed the right number.  Answer your phone with a, “Hello, this is ___<your full name preferred, but at least your first name>___.”.  And when I say, “Hi, <your name>, this is Mark from <my company>” it would be really nice to hear you say, “Hi, Mark, I have been expecting your call.”  This sets the perfect tone for our conversation.  I know I have the right person; you are professional enough and interested enough in the job or contract to remember your appointments; and now we can move on to a little intro segment and get on with the reason for our call. As crazy as it sounds, I’ve actually had phone interviews that went like this: <Ring…> You:  “Hello?” Me:  “Hi, this is Mark from _______” You:  “Yeah?” Me:  “Is this <your name>?” You:  “Yeah.” Me:  “I had this time in my calendar for us to talk…were you expecting my call?” You:  “Oh, yeah, sure…” I used to be nice and would try to go ahead with the interview even after this bad start, thinking I was giving the candidate the benefit of the doubt…a second chance…but more often than not it was a struggle and 10 minutes into what was supposed to be a 45-minute call, I’m looking for a way to hang up without being rude myself.  It never worked out.  I never brought that person in for an in-person interview, much less offered them the job or contract.  Who knows, maybe they were some sort of wunderkind that we missed out on.  What I know is that they would never fit in with the rest of the team, and around here that is absolutely critical. So, in conclusion… Act alive!  Identify yourself!  And do at least the very basic of research.

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  • Are there any well known algorithms to detect the presence of names?

    - by Rhubarb
    For example, given a string: "Bob went fishing with his friend Jim Smith." Bob and Jim Smith are both names, but bob and smith are both words. Weren't for them being uppercase, there would be less indication of this outside of our knowledge of the sentence. Without doing grammar analysis, are there any well known algorithms for detecting the presence of names, at least Western names?

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  • How to Extract Properties for Refactoring

    - by Ngu Soon Hui
    I have this property public List<PointK> LineList {get;set;} Where PointK consists of the following structure: string Mark{get;set;} double X{get;set;} doible Y{get;set;} Now, I have the following code: private static Dictionary<string , double > GetY(List<PointK> points) { var invertedDictResult = new Dictionary<string, double>(); foreach (var point in points) { if (!invertedDictResult.ContainsKey(point.Mark)) { invertedDictResult.Add(point .Mark, Math.Round(point.Y, 4)); } } return invertedDictResult; } private static Dictionary<string , double > GetX(List<PointK> points) { var invertedDictResult = new Dictionary<string, double>(); foreach (var point in points) { if (!invertedDictResult.ContainsKey(point.Mark)) { invertedDictResult.Add(point .Mark, Math.Round(point.X, 4)); } } return invertedDictResult; } How to restructure the above code?

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  • Need help joining tables...

    - by yuudachi
    I am a MySQL newbie, so sorry if this is a dumb question.. These are my tables. student table: SID (primary) student_name advisor (foreign key to faculty.facultyID) requested_advisor (foreign key to faculty.facultyID) faculty table: facultyID (primary key) advisor_name I want to query a table that shows everything in the student table, but I want advisor and requested_advisor to show up as names, not the ID numbers. so like it displays like this on the webpage: Student Name: Jane Smith SID: 860123456 Current Advisor: John Smith Requested advisor: James Smith not like this Student Name: Jane Smith SID: 860123456 Current Advisor: 1 Requested advisor: 2 SELECT student.student_name, SID, student_email, faculty.advisor_name FROM student INNER JOIN faculty ON student.advisor = faculty.facultyID; this comes out close, but I don't know how to get the requested_advisor to show up as a name.

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  • Setting variables in shell script by running commands

    - by rajya vardhan
    >cat /tmp/list1 john jack >cat /tmp/list2 smith taylor It is guaranteed that list1 and list2 will have equal number of lines. f(){ i=1 while read line do var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` echo $i,$var1,$var2 i=`expr $i+1` echo $i,$var1,$var2 done < $INFILE } So output of f() should be: 1,john,smith 2,jack,taylor But getting 1,p,p 1+1,p,p If i replace following: var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` with this: var1=`head -$i /tmp/vip_list|tail -1` var2=`head -$i /tmp/lb_list|tail -1` Then output: 1,john,smith 1,john,smith Not an expert of shell, so please excuse if sounds childish :)

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  • Creating one row of information in excel using a unique value

    - by user1426513
    This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

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  • Ubuntu-one syncs single files, but not directories [closed]

    - by Luiz Cláudio Duarte
    I'm using Ubuntu 10.10, fully updated. I have tried to sync my ~/Documents and ~/Pictures folders; U1 replicates the directory structure, but no files are uploaded. Next I tried to sync a single file inside ~/Ubuntu One and it was synced. Then I tried to put a directory inside ~/Ubuntu One and, again, the directory structure was replicated, but no files were synced. All the files have the "syncing" icon, however. The latest syncdaemon.log is below: 2011-03-30 07:41:50,752 - ubuntuone.SyncDaemon.fsm - INFO - loading updated metadata 2011-03-30 07:41:55,081 - ubuntuone.SyncDaemon.fsm - INFO - initialized: idx_path: 266, idx_node_id: 266, shares: 1 2011-03-30 07:41:55,082 - ubuntuone.SyncDaemon.GeneralINotProc - INFO - Ignoring files: ['\\A#.*\\Z', '\\A.*~\\Z', '\\A.*\\.py[oc]\\Z', '\\A.*\\.sw[nopx]\\Z', '\\A.*\\.swpx\\Z', '\\A\\..*\\.tmp\\Z'] 2011-03-30 07:41:55,083 - ubuntuone.SyncDaemon.HQ - INFO - HashQueue: _hasher started 2011-03-30 07:41:55,902 - ubuntuone.SyncDaemon.DBus - INFO - DBusInterface initialized. 2011-03-30 07:41:55,903 - ubuntuone.SyncDaemon.Main - INFO - Using '/home/l_claudius/Ubuntu One' as root dir 2011-03-30 07:41:55,903 - ubuntuone.SyncDaemon.Main - INFO - Using '/home/l_claudius/.local/share/ubuntuone/syncdaemon' as data dir 2011-03-30 07:41:55,903 - ubuntuone.SyncDaemon.Main - INFO - Using '/home/l_claudius/.local/share/ubuntuone/shares' as shares root dir 2011-03-30 07:41:55,903 - ubuntuone.SyncDaemon.Main - NOTE - ---- MARK (state: <State: 'INIT' (queues IDLE connection 'Not User Not Network')>; queues: metadata: 0; content: 0; hash: 0, fsm-cache: hit=1 miss=266) ---- 2011-03-30 07:41:55,904 - ubuntuone.SyncDaemon.Main - NOTE - Local rescan starting... 2011-03-30 07:41:55,904 - ubuntuone.SyncDaemon.local_rescan - INFO - start scan all volumes 2011-03-30 07:41:55,906 - ubuntuone.SyncDaemon.local_rescan - INFO - processing trash 2011-03-30 07:41:56,044 - ubuntuone.SyncDaemon.local_rescan - INFO - processing move limbo 2011-03-30 07:41:56,491 - ubuntuone.SyncDaemon.Main - NOTE - Local rescan finished! 2011-03-30 07:41:56,492 - ubuntuone.SyncDaemon.Main - INFO - hash queue empty. We are ready! 2011-03-30 07:42:15,583 - ubuntuone.SyncDaemon.DBus - INFO - u'CredentialsFound': callbacking with credentials (token_name: None). 2011-03-30 07:42:15,584 - ubuntuone.SyncDaemon.DBus - INFO - connect: credential request was successful, pushing SYS_USER_CONNECT. 2011-03-30 07:42:15,617 - ubuntuone.SyncDaemon.ActionQueue - INFO - Connection started to host fs-1.one.ubuntu.com, port 443. 2011-03-30 07:42:15,977 - ubuntuone.SyncDaemon.ActionQueue - INFO - Connection made. 2011-03-30 07:42:15,978 - ubuntuone.SyncDaemon.StorageClient - INFO - Connection made. 2011-03-30 07:42:16,581 - ubuntuone.SyncDaemon.ActionQueue - INFO - The request 'protocol_version' finished OK. 2011-03-30 07:42:16,774 - ubuntuone.SyncDaemon.ActionQueue - INFO - The request 'caps_raising_if_not_accepted' finished OK. 2011-03-30 07:42:16,966 - ubuntuone.SyncDaemon.ActionQueue - INFO - The request 'caps_raising_if_not_accepted' finished OK. 2011-03-30 07:42:17,722 - ubuntuone.SyncDaemon.ActionQueue - INFO - The request 'oauth_authenticate' finished OK. 2011-03-30 07:42:17,723 - ubuntuone.SyncDaemon.ActionQueue - NOTE - Session ID: '563bc960-35fa-4f44-b9b6-125819656dc3' 2011-03-30 07:42:19,258 - ubuntuone.SyncDaemon.ActionQueue - INFO - The request 'list_volumes' finished OK. 2011-03-30 07:43:55,903 - ubuntuone.SyncDaemon.Main - NOTE - ---- MARK (state: <State: 'QUEUE_MANAGER' (queues IDLE connection 'With User With Network')>; queues: metadata: 0; content: 0; hash: 0, fsm-cache: hit=1059 miss=266) ---- 2011-03-30 07:45:55,903 - ubuntuone.SyncDaemon.Main - NOTE - ---- MARK (state: <State: 'QUEUE_MANAGER' (queues IDLE connection 'With User With Network')>; queues: metadata: 0; content: 0; hash: 0, fsm-cache: hit=1059 miss=266) ---- 2011-03-30 07:47:55,903 - ubuntuone.SyncDaemon.Main - NOTE - ---- MARK (state: <State: 'QUEUE_MANAGER' (queues IDLE connection 'With User With Network')>; queues: metadata: 0; content: 0; hash: 0, fsm-cache: hit=1059 miss=266) ---- 2011-03-30 07:49:55,903 - ubuntuone.SyncDaemon.Main - NOTE - ---- MARK (state: <State: 'QUEUE_MANAGER' (queues IDLE connection 'With User With Network')>; queues: metadata: 0; content: 0; hash: 0, fsm-cache: hit=1059 miss=266) ---- 2011-03-30 07:51:55,903 - ubuntuone.SyncDaemon.Main - NOTE - ---- MARK (state: <State: 'QUEUE_MANAGER' (queues IDLE connection 'With User With Network')>; queues: metadata: 0; content: 0; hash: 0, fsm-cache: hit=1059 miss=266) ----

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  • JPedal Action for Converting PDF to JavaFX

    - by Geertjan
    The question of the day comes from Mark Stephens, from JPedal (JPedal is the leading 100% Java PDF library, providing a Java PDF viewer, PDF to image conversion, PDF printing or adding PDF search and PDF extraction features), in the form of a screenshot: The question is clear. By looking at the annotations above, you can see that Mark has an ActionListener that has been bound to the right-click popup menu on PDF files. Now he needs to get hold of the file to which the Action has been bound. How, oh  how, can one get hold of that file? Well, it's simple. Leave everything you see above exactly as it is but change the Java code section to this: public final class PDF2JavaFXContext implements ActionListener {     private final DataObject context;     public PDF2JavaFXContext(DataObject context) {         this.context = context;     }     public void actionPerformed(ActionEvent ev) {         FileObject fo = context.getPrimaryFile();         File theFile = FileUtil.toFile(fo);         //do something with your file...     } } The point is that the annotations at the top of the class bind the Action to either Actions.alwaysEnabled, which is a factory method for creating always-enabled Actions, or Actions.context, which is a factory method for creating context-sensitive Actions. How does the Action get bound to the factory method? The annotations are converted, when the module is compiled, into XML registration entries in the "generated-layer.xml", which you can find in your "build" folder, in the Files window, after building the module. In Mark's case, since the Action should be context-sensitive to PDF files, he needs to bind his PDF2JavaFXContext ActionListener (which should probably be named "PDF2JavaFXActionListener", since the class is an ActionListener) to Actions.context. All he needs to do that is pass in the object he wants to work with into the constructor of the ActionListener. Now, when the module is built, the annotation processor is going to take the annotations and convert them to XML registration entries, but the constructor will also be checked to see whether it is empty or not. In this case, the constructor isn't empty, hence the Action should be context-sensitive and so the ActionListener is bound to Actions.context. The Actions.context will do all the enablement work for Mark, so that he will not need to provide any code for enabling/disabling the Action. The Action will be enabled whenever a DataObject is selected. Since his Action is bound to Nodes in the Projects window that represent PDF files, the Action will always be enabled whenever Mark right-clicks on a PDF Node, since the Node exposes its own DataObject. Once Mark has access to the DataObject, he can get the underlying FileObject via getPrimaryFile and he can then convert the FileObject to a java.io.File via FileUtil.getConfigFile. Once he's got the java.io.File, he can do with it whatever he needs. Further reading: http://bits.netbeans.org/dev/javadoc/

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