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  • How To Make Hundreds of Complex Photo Edits in Seconds With Photoshop Actions

    - by Eric Z Goodnight
    Have a huge folder of images needing tweaks? A few hundred adjustments may seem like a big, time consuming job—but read one to see how Photoshop can do repetitive tasks automatically, even if you don’t know how to program! Photoshop Actions are a simple way to program simple routines in Photoshop, and are a great time saver, allowing you to re-perform tasks over and over, saving you minutes or hours, depending on the job you have to work on. See how any bunch of images and even some fairly complicated photo tweaking can be done automatically to even hundreds of images at once. When Can I use Photoshop Actions? Photoshop actions are a way of recording the tools, menus, and keys pressed while using the program. Each time you use a tool, adjust a color, or use the brush, it can be recorded and played back over any file Photoshop can open. While it isn’t perfect and can get very confused if not set up correctly, it can automate editing hundreds of images, saving you hours and hours if you have big jobs with complex edits. The image illustrated above is a template for a polaroid-style picture frame. If you had several hundred images, it would actually be a simple matter to use Photoshop Actions to create hundreds of new images inside the frame in almost no time at all. Let’s take a look at how a simple folder of images and some Image editing automation can turn lots of work into a simple and easy job. Creating a New Action Actions is a default part of the “Essentials” panel set Photoshop begins with as a default. If you can’t see the panel button under the “History” button, you can find Actions by going to Window > Actions or pressing Alt + F9. Click the in the Actions Panel, pictured in the previous illustration on the left. Choose to create a “New Set” in order to begin creating your own custom Actions. Name your action set whatever you want. Names are not relevant, you’ll simply want to make it obvious that you have created it. Click OK. Look back in the layers panel. You’ll see your new Set of actions has been added to the list. Click it to highlight it before going on. Click the again to create a “New Action” in your new set. If you care to name your action, go ahead. Name it after whatever it is you’re hoping to do—change the canvas size, tint all your pictures blue, send your image to the printer in high quality, or run multiple filters on images. The name is for your own usage, so do what suits you best. Note that you can simplify your process by creating shortcut keys for your actions. If you plan to do hundreds of edits with your actions, this might be a good idea. If you plan to record an action to use every time you use Photoshop, this might even be an invaluable step. When you create a new Action, Photoshop automatically begins recording everything you do. It does not record the time in between steps, but rather only the data from each step. So take your time when recording and make sure you create your actions the way you want them. The square button stops recording, and the circle button starts recording again. With these basics ready, we can take a look at a sample Action. Recording a Sample Action Photoshop will remember everything you input into it when it is recording, even specific photographs you open. So begin recording your action when your first photo is already open. Once your first image is open, click the record button. If you’re already recording, continue on. Using the File > Place command to insert the polaroid image can be easier for Actions to deal with. Photoshop can record with multiple open files, but it often gets confused when you try it. Keep your recordings as simple as possible to ensure your success. When the image is placed in, simply press enter to render it. Select your background layer in your layers panel. Your recording should be following along with no trouble. Double click this layer. Double clicking your background layer will create a new layer from it. Allow it to be renamed “Layer 0” and press OK. Move the “polaroid” layer to the bottom by selecting it and dragging it down below “Layer 0” in the layers panel. Right click “Layer 0” and select “Create Clipping Mask.” The JPG image is cropped to the layer below it. Coincidentally, all actions described here are being recorded perfectly, and are reproducible. Cursor actions, like the eraser, brush, or bucket fill don’t record well, because the computer uses your mouse movements and coordinates, which may need to change from photo to photo. Click the to set your Photograph layer to a “Screen” blending mode. This will make the image disappear when it runs over the white parts of the polaroid image. With your image layer (Layer 0) still selected, navigate to Edit > Transform > Scale. You can use the mouse to resize your Layer 0, but Actions work better with absolute numbers. Visit the Width and Height adjustments in the top options panel. Click the chain icon to link them together, and adjust them numerically. Depending on your needs, you may need to use more or less than 30%. Your image will resize to your specifications. Press enter to render, or click the check box in the top right of your application. + Click on your bottom layer, or “polaroid” in this case. This creates a selection of the bottom layer. Navigate to Image > Crop in order to crop down to your bottom layer selection Your image is now resized to your bottommost layer, and Photoshop is still recording to that effect. For additional effect, we can navigate to Image > Image Rotation > Arbitrary to rotate our image by a small tilt. Choosing 3 degrees clockwise , we click OK to render our choice. Our image is rotated, and this step is recorded. Photoshop will even record when you save your files. With your recording still going, find File > Save As. You can easily tell Photoshop to save in a new folder, other than the one you have been working in, so that your files aren’t overwritten. Navigate to any folder you wish, but do not change the filename. If you change the filename, Photoshop will record that name, and save all your images under whatever you type. However, you can change your filetype without recording an absolute filename. Use the pulldown tab and select a different filetype—in this instance, PNG. Simply click “Save” to create a new PNG based on your actions. Photoshop will record the destination and the change in filetype. If you didn’t edit the name of your file, it will always use the variable filename of any image you open. (This is very important if you want to edit hundreds of images at once!) Click File > Close or the red “X” in the corner to close your filetype. Photoshop can record that as well. Since we have already saved our image as a JPG, click “NO” to not overwrite your original image. Photoshop will also record your choice of “NO” for subsequent images. In your Actions panel, click the stop button to complete your action. You can always click the record button to add more steps later, if you want. This is how your new action looks with its steps expanded. Curious how to put it into effect? Read on to see how simple it is to use that recording you just made. Editing Lots of Images with Your New Action Open a large number of images—as many as you care to work with. Your action should work immediately with every image on screen, although you may have to test and re-record, depending on how you did. Actions don’t require any programming knowledge, but often can get confused or work in a counter-intuitive way. Record your action until it is perfect. If it works once without errors, it’s likely to work again and again! Find the “Play” button in your Actions Panel. With your custom action selected, click “Play” and your routine will edit, save, and close each file for you. Keep bashing “Play” for each open file, and it will keep saving and creating new files until you run out of work you need to do. And in mere moments, a complicated stack of work is done. Photoshop actions can be very complicated, far beyond what is illustrated here, and can even be combined with scripts and other actions, creating automated creation of potentially very complex files, or applying filters to an entire portfolio of digital photos. Have questions or comments concerning Graphics, Photos, Filetypes, or Photoshop? Send your questions to [email protected], and they may be featured in a future How-To Geek Graphics article. Image Credits: All images copyright Stephanie Pragnell and author Eric Z Goodnight, protected under Creative Commons. 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  • Is it legal to ask photo ID and credit card copy in the U.S

    - by selim
    I regularly order from online shops around the world and I have not see any case where the company asks for photo ID or credit card copy. Yesterday I make an order from linode.com and my order is on hold because of their "fraud check system". Is it common to ask those info in U.S. where I have never asked such info in here (Istanbul, Turkey). And I already asked what is their motive and legal stand and the reason my order is hold by their fraud system. And I also added whether is because I live in Istanbul, Turkey. Their answer was as following: "We would not be able to disclose specific information related to our fraud system." And I'm asked repeatedly whether I want to cancel my order or not. I dont questioning reputation of linode.com if I think so, I did not make an order. I think asking for photo ID is neither legal nor provide any security.

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  • iPhone UIImage upload to web service

    - by user347635
    Hi all, I worked on this for several hours today and I'm pretty close to a solution but clearly need some help from someone who's pulled this off. I'm trying to post an image to a web service from the iPhone. I'll post the code first then explain everything I've tried: NSData *imageData = UIImageJPEGRepresentation(barCodePic, .9); NSString *soapMsg = [NSString stringWithFormat: @"<?xml version=\"1.0\" encoding=\"utf-8\"?><soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\"><soap:Body><WriteImage xmlns=\"http://myserver/imagewebservice/\"><ImgIn>%@</ImgIn></WriteImage></soap:Body></soap:Envelope>", [NSData dataWithData:imageData] ]; NSURL *url = [NSURL URLWithString:@"http://myserver/imagewebservice/service1.asmx"]; NSMutableURLRequest *req = [NSMutableURLRequest requestWithURL:url]; NSString *msgLength = [NSString stringWithFormat:@"%d", [soapMsg length]]; [req addValue:@"text/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"]; [req addValue:@"http://myserver/imagewebservice/WriteImage" forHTTPHeaderField:@"SOAPAction"]; [req addValue:msgLength forHTTPHeaderField:@"Content-Length"]; [req setHTTPMethod:@"POST"]; [req setHTTPBody: [soapMsg dataUsingEncoding:NSUTF8StringEncoding]]; conn = [[NSURLConnection alloc] initWithRequest:req delegate:self]; if (conn) { webData = [[NSMutableData data] retain]; } First thing, this code works fine for anything but an image. The web service is running on my local network and I can change the source code at will and if I change the "ImgIn" parameter to a string and pass a string in, everything works fine, I get a return value no problem. So there are no connectivity issues at all, I'm able to call and get data from this web service on this server no problems. But I need to upload an image to this web service via the ImgIn parameter, so the above code is my best shot so far. I also have didReceiveResponse, didReceiveData, didFailWithError, etc all being handled. The above code fires off didRecieveResponse every time. However didReceiveData is never fired and it's like the web service itself never even runs. When I debug the web service itself, it runs and debugs fine when I use a string parameter, but with the image parameter, it never even debugs when I call it. It's almost like the ImgIn parameter is too long (it's huge when I output it to the screen) and the web service just chokes on it. I've read about having to encode to Base64 when using this method, but I can't find any good links on how that's done. If that's what I'm doing wrong, can you PLEASE provide code as to how to do this, not just "you need to use Base64", I'd really appreciate it as I can find almost nothing on how to implement this with an example. Other than that, I'm kind of lost, it seems like I'm doing everything else right. Please help! Thanks

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  • [c++] upload image to imageshack

    - by cinek1lol
    Hi! I would like to send pictures via a program written in C + +. - OK WinExec("C:\\curl\\curl.exe -H Expect: -F \"fileupload=@C:\\curl\\ok.jpg\" -F \"xml=yes\" -# \"http://www.imageshack.us/index.php\" -o data.txt -A \"Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1\" -e \"http://www.imageshack.us\"", NULL); It works, but I would like to send the pictures from pre-loaded carrier to a variable char (you know what I mean? First off, I load the pictures into a variable and then send the variable), cause now I have to specify the path of the picture on a disk. I wanted to write this program in c++ by using the curl library, not through exe. extension. I have also found such a program (which has been modified by me a bit) #include <stdio.h> #include <string.h> #include <iostream> #include <curl/curl.h> #include <curl/types.h> #include <curl/easy.h> int main(int argc, char *argv[]) { CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the file upload field */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "send", CURLFORM_FILE, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "nowy.jpg", CURLFORM_COPYCONTENTS, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); headerlist = curl_slist_append(headerlist, buf); if(curl) { curl_easy_setopt(curl, CURLOPT_URL, "http://www.imageshack.us/index.php"); if ( (argc == 2) && (!strcmp(argv[1], "xml=yes")) ) curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); curl_easy_cleanup(curl); curl_formfree(formpost); curl_slist_free_all (headerlist); } system("pause"); return 0; }

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  • [c++] upload image to imageshack

    - by cinek1lol
    Hi. I would like to send pictures via a program written in C + + I wrote such a thing using curl.exe WinExec("C:\\curl\\curl.exe -H Expect: -F \"fileupload=@C:\\curl\\ok.jpg\" -F \"xml=yes\" -# \"http://www.imageshack.us/index.php\" -o data.txt -A \"Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1\" -e \"http://www.imageshack.us\"", NULL); This only works that I would like to send pictures to a variable pre-loaded char (you know what I mean? first reads the pictures into a variable and then send that variable), because now I have to specify the path to the images on disk I wanted to make this program was written in C + + using the curl library, and not the exe. I found it such a program (which some have modified) #include <stdio.h> #include <string.h> #include <iostream> #include <curl/curl.h> #include <curl/types.h> #include <curl/easy.h> int main(int argc, char *argv[]) { CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the file upload field */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "send", CURLFORM_FILE, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "nowy.jpg", CURLFORM_COPYCONTENTS, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); headerlist = curl_slist_append(headerlist, buf); if(curl) { curl_easy_setopt(curl, CURLOPT_URL, "http://www.imageshack.us/index.php"); if ( (argc == 2) && (!strcmp(argv[1], "xml=yes")) ) curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); curl_easy_cleanup(curl); curl_formfree(formpost); curl_slist_free_all (headerlist); } system("pause"); return 0; } I will be grateful for any help

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  • jQuery photo carousel (that looks like a real carousel)?

    - by kastru
    I am on the lookout for a jQuery photo carousel that can display 3 images at a time, and circle through x amount of photos (and when reaching the last, starting with the first photo again). I made a quick mock-up of what i am looking fore - see it here. So there is 3 photos vissible, the middle one beeing the 'main' one and a bit bigger than the previous and next (left and right). Upon clicking the next/previous arrows the next or previous photo slides into the middle and thereby becomes the main photo. Any ideas to where i can find such a jQuery plugin/script?

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  • android ftp upload has stopped error

    - by Goxel Arp
    class Asenkron extends AsyncTask<String,Integer,Long> { @Override protected Long doInBackground(String... aurl) { FTPClient con=null; try ` { con = new FTPClient(); con.connect(aurl[0]); if (con.login(aurl[1], aurl[2])) { con.enterLocalPassiveMode(); // important! con.setFileType(http://FTP.BINARY_FILE_TYPE); FileInputStream in = new FileInputStream(new File(aurl[3])); boolean result = con.storeFile(aurl[3], in); in.close(); con.logout(); con.disconnect(); } } catch (Exception e) { Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_LONG).show(); } return null; } protected void onPostExecute(String result) {} } I AM USING THIS CLASS LIKE BELOW.THERE IS BUTTON AND WHENEVER I CLICK THE BUTTON IT SHOULD START FTP UPLOAD PROCESS IN BACKGROUND BUT I GET "PROGRAM HAS STOPPED UNFORTUNATELY" ERROR. Assume that The ftp address and username password pathfile sections are true and I get the internet and network permissions already by the way ... button1.setOnClickListener(new OnClickListener() { public void onClick(View arg0) { new Asenkron().execute("ftpaddress","username","pass","pathfileon telephone"); } }); And here is the logcat for you to analyse the potential error and help me ... 10-13 13:01:25.591: I/dalvikvm(633): threadid=3: reacting to signal 3 10-13 13:01:25.711: I/dalvikvm(633): Wrote stack traces to '/data/anr/traces.txt' 10-13 13:01:25.921: D/gralloc_goldfish(633): Emulator without GPU emulation detected. 10-13 13:01:31.441: W/dalvikvm(633): threadid=11: thread exiting with uncaught exception (group=0x409c01f8) 10-13 13:01:31.461: E/AndroidRuntime(633): FATAL EXCEPTION: AsyncTask #1 10-13 13:01:31.461: E/AndroidRuntime(633): java.lang.RuntimeException: An error occured while executing doInBackground() 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.AsyncTask$3.done(AsyncTask.java:278) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask.setException(FutureTask.java:124) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask.run(FutureTask.java:137) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:208) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.lang.Thread.run(Thread.java:856) 10-13 13:01:31.461: E/AndroidRuntime(633): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare() 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.Handler.<init>(Handler.java:121) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.widget.Toast$TN.<init>(Toast.java:317) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.widget.Toast.<init>(Toast.java:91) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.widget.Toast.makeText(Toast.java:233) 10-13 13:01:31.461: E/AndroidRuntime(633): at com.example.ftpodak.ODAK$Asenkron.doInBackground(ODAK.java:74) 10-13 13:01:31.461: E/AndroidRuntime(633): at com.example.ftpodak.ODAK$Asenkron.doInBackground(ODAK.java:1) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.AsyncTask$2.call(AsyncTask.java:264) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305) 10-13 13:01:31.461: E/AndroidRuntime(633): ... 5 more By the way I changed the relevant code like that ; instead of catch (Exception e) { Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_LONG).show(); } I replaced with this code catch (Exception e) { HATA=e.toString(); } And I added the code to button textview1.setText(HATA); So I can see the error on the textview and it is writing that "Android java.net.UnknownHostException: Host is unresolved" But i know that the ftp server is correct and I check the ftp server from the AndFTP application. With the same address login and pass information ftp server is working.So the problem is in my code I think.Any help will be too much appreciated.Anyone who can help me I can give teamviewer to analyse what is the problem ...

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  • Any way to void document upload when user cancels?

    - by Michael Broschat
    We have developed a set of metadata fields for the user to complete during the file upload process (MOSS). What happens is that the user chooses Upload, then specifies the file on his system. Sometimes, when he sees what metadata data is required, he clicks Cancel, knowing that he cannot supply the data at that time. The file uploads, anyway, and is in the library without any attached metadata. Our client finds this unacceptable, but I haven't found a way to cancel the actual upload when the user tells us he no longer wants to do so.

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  • Windows Photo Viewer can't open this picture because you don't have the correct permissions to access the file location

    - by Software Monkey
    My system in Windows 7 and fully up to date with all patches and options (except for Microsoft Silverlight, which I refuse to install). I get this error whenever I try to open an image using Windows Photo Viewer, such as when previewing from Explorer or when opening an image attachment to an email. I have already verified correct permissions to the file and all folders in the path. The strange thing is that every other program I have seems to open the images fine, including "Slideshow" from Windows Explorer. Even more strange, in WPV there is an "Open" menu that lists the other programs for images including GIMP and MS Paint and they open the very file that WPV is complaining about just fine. That should eliminate permissions as being the problem, especially since (logically at least) they are read/write while WPV is read-only. I have even edited and saved the images that WPV does not open. I am out of ideas, and searching for answer on the Web has resulted only in the same tired repitition of some flavor of "take ownership and reset permissions for the entire drive", which I have already done. And which is counter-indicated by the fact that only Windows Photo Viewer seems to have a problem. The one thing which is slightly unusual is that for normal files they are all on a second HDD mounted into C:, however for email attachments the temporary folder is C:\Temp\, which is directly on that drive.

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • How to test if a user has SELECTED a file to upload ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? edit : maybe i wasn't so clear, i don't want to test if he uploaded a logo, i want to test IF he selected a file to upload, because right now, if he doesn't select a file to upload, php raises an error telling he must upload with the right format. thanks.

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  • Is PhotoBucket a viable solution to host a website's photo galleries

    - by Evan Plaice
    I'm currently working with a lot of photographers and will probably be picking up development on a professional photography site soon. With that in mind, and I can't stop thinking about a way I can implement a user-friendly photo gallery hosting solution where the site owner can upload images themselves without any webmaster intervention. Kind of like a CMS for image hosting. The idea is: - The user can log in to PhotoBucket - Upload their gallery - Visit an admin section of the site - Enter the new gallery name to the listing And... Voila, the gallery automagically gets displayed on the website in a clean lightbox-style presentation format (ie, no iframe nonsense). I took a brief look at the API and it looks promising. Is this a viable solution? Bonus points if you have implemented something like this with Photobucket and/or another 3rd-party image hosting site. Note: Purchasing a premium account is expected if necessary. The limitations on free accounts at most image hosting sites are just too restrictive to be useful.

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  • javascript replace text with images problem

    - by Amit Malhotra
    I'm extremely new to JS and have this code that I'm trying to tweak. WHen I was adding the array, I had tested it with only a couple of items and it was working fine, now it just doesn't work, and I can't figure out what is wrong with it!! Basically, I'm trying to change every instance of a card type with an image on a webpage Here's the code: window.onload = function(){ var cardname = new Array(); cardname[0] = "Ace of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_a.svg/88px-Ornamental_h_a.svg.png' />"; cardname[1] = "2 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_2.svg/88px-Ornamental_h_2.svg.png' />"; cardname[2] = "3 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_3.svg/88px-Ornamental_h_3.svg.png' />"; cardname[3] = "4 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_4.svg/88px-Ornamental_h_4.svg.png' />"; cardname[4] = "5 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_5.svg/88px-Ornamental_h_5.svg.png' />"; cardname[5] = "6 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_6.svg/88px-Ornamental_h_6.svg.png' />"; cardname[6] = "7 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_7.svg/88px-Ornamental_h_7.svg.png' />"; cardname[7] = "8 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_8.svg/88px-Ornamental_h_8.svg.png' />"; cardname[8] = "9 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_9.svg/88px-Ornamental_h_9.svg.png' />"; cardname[9] = "10 of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/9/91/Ornamental_h_10.svg/88px-Ornamental_h_10.svg.png' />"; cardname[10] = "Jack of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_j.svg/88px-Ornamental_h_j.svg.png' />"; cardname[11] = "Queen of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_q.svg/88px-Ornamental_h_q.svg.png' />"; cardname[12] = "King of Hearts^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_h_k.svg/88px-Ornamental_h_k.svg.png' />"; cardname[13] = "Ace of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_a.svg/88px-Ornamental_s_a.svg.png' />"; cardname[14] = "2 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_2.svg/88px-Ornamental_s_2.svg.png' />"; cardname[15] = "3 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_3.svg/88px-Ornamental_s_3.svg.png' />"; cardname[16] = "4 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_4.svg/88px-Ornamental_s_4.svg.png' />"; cardname[17] = "5 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_5.svg/88px-Ornamental_s_5.svg.png' />"; cardname[18] = "6 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_6.svg/88px-Ornamental_s_6.svg.png' />"; cardname[19] = "7 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_7.svg/88px-Ornamental_s_7.svg.png' />"; cardname[20] = "8 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_8.svg/88px-Ornamental_s_8.svg.png' />"; cardname[21] = "9 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_9.svg/88px-Ornamental_s_9.svg.png' />"; cardname[22] = "10 of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_10.svg/88px-Ornamental_s_10.svg.png' />"; cardname[23] = "Jack of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/78/Ornamental_s_j.svg/88px-Ornamental_s_j.svg.png' />"; cardname[24] = "Queen of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_q.svg/88px-Ornamental_s_q.svg.png' />"; cardname[25] = "King of Spades^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_s_k.svg/88px-Ornamental_s_k.svg.png' />"; cardname[26] = "Ace of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_a.svg/88px-Ornamental_c_a.svg.png' />"; cardname[27] = "2 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_2.svg/88px-Ornamental_c_2.svg.png' />"; cardname[28] = "3 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_3.svg/88px-Ornamental_c_3.svg.png' />"; cardname[29] = "4 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_4.svg/88px-Ornamental_c_4.svg.png' />"; cardname[30] = "5 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_5.svg/88px-Ornamental_c_5.svg.png' />"; cardname[31] = "6 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_6.svg/88px-Ornamental_c_6.svg.png' />"; cardname[32] = "7 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_7.svg/88px-Ornamental_c_7.svg.png' />"; cardname[33] = "8 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_8.svg/88px-Ornamental_c_8.svg.png' />"; cardname[34] = "9 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_9.svg/88px-Ornamental_c_9.svg.png' />"; cardname[35] = "10 of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_10.svg/88px-Ornamental_c_10.svg.png' />"; cardname[36] = "Jack of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_j.svg/88px-Ornamental_c_j.svg.png' />"; cardname[37] = "Queen of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_q.svg/88px-Ornamental_c_q.svg.png' />"; cardname[38] = "King of Clubs^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_c_k.svg/88px-Ornamental_c_k.svg.png' />"; cardname[39] = "Ace of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_a.svg/88px-Ornamental_d_a.svg.png' />"; cardname[40] = "2 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_2.svg/88px-Ornamental_d_2.svg.png' />"; cardname[41] = "3 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_3.svg/88px-Ornamental_d_3.svg.png' />"; cardname[42] = "4 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_4.svg/88px-Ornamental_d_4.svg.png' />"; cardname[43] = "5 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_5.svg/88px-Ornamental_d_5.svg.png' />"; cardname[44] = "6 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_6.svg/88px-Ornamental_d_6.svg.png' />"; cardname[45] = "7 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_7.svg/88px-Ornamental_d_7.svg.png' />"; cardname[46] = "8 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_8.svg/88px-Ornamental_d_8.svg.png' />"; cardname[47] = "9 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_9.svg/88px-Ornamental_d_9.svg.png' />"; cardname[48] = "10 of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_10.svg/88px-Ornamental_d_10.svg.png' />"; cardname[49] = "Jack of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_j.svg/88px-Ornamental_d_j.svg.png' />"; cardname[50] = "Queen of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_q.svg/88px-Ornamental_d_q.svg.png' />"; cardname[51] = "King of Diamonds^<img src='http://upload.wikimedia.org/wikipedia/commons/thumb/7/7c/Ornamental_d_k.svg/88px-Ornamental_d_k.svg.png' />"; var j, k, findit, part, page, repl; var page = document.body.innerHTML; for(var i=0; i<cardname.length; i++){ part = cardname[i].split("^"); findit = part[0]; repl = part[1]; while (page.indexOf(findit) >=0){ var j = page.indexOf(findit); var k = findit.length; page = page.substr(0,j) + repl + page.substr(j+k); } } document.body.innerHTML = page; } any help would be appreciated to figure out why this code is not working!

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  • How do I set up ZScreen to upload images to my mediawiki?

    - by Johan
    I've set up a mediawiki with all the correct settings and enabled image uploading. When I do this manually this all works OK. I want to be able to upload screenshots automatically into my mediawiki using ZScreen. There is an option to do this: I press Test..., this work OK, however I'm unable to tell ZScreen to to actually get the picture into my mediawiki. There's no option to select mediawiki as my destination. How do I setup zscreen to upload to my mediawiki?

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  • Why Windows Live Photo Gallery stopped displaying thumbnails, and how to fix it?

    - by Alex R
    I now get this instead, for most (but not all) photos. This is the icon which represents the WLPG application, I think. Some observations: I can see the thumbnails fine in Explorer, which is where a lot of other people have this problem. My C:\ drive may have temporarily filled up at some point recently, but then was cleaned up. Double-clicking on the photo will display it fine, so I know it's not file corruption or permissions issues. Thanks

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  • Increasing Max Upload File Size on IIS7/Win7 Pro

    - by Jay Querido
    I'm setting up a server for a client (something I don't typically do), and I'm running into issues with uploading larger files (11MB). The server is running Windows 7 Professional with IIS added. In web.config I've tried setting <system.web> <httpRuntime maxRequestLength="65536" /> <!-- 64MB --> </system.web> ... and that doesn't work. I've set <system.webSecurity> <security> <requestFiltering> <requestLimits maxAllowedContentLength="68157440" /> </requestFiltering> </security> </system.webSecurity> ... and that doesn't work either. What am I missing here? As I've said, I don't typically set up servers, so I may be missing something obvious... no suggestion will be scoffed at! Thanks in advance.

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  • Django dislaying upload file content

    - by dana
    hello, i have an application that loads different documents to the server, and allows users to read documents' content. i am uploading the documents to the server, and then i try to read the courses by id, like: def view_course(request,id): u = Courses.objects.get(pk=id) etc But i don't find anywhere : how can i actually read the content of a /.doc/.pdf/.txt and display it on a web page? thanks in advance!

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  • Python Post Upload JPEG to Server?

    - by iJames
    It seems like this answer has been provided a bunch of times but in all of it, I'm still getting errors from the server and I'm sure it has to do with my code. I've tried HTTP, and HTTPConnection from httplib and both create quite different terminal outputs in terms of formatting/encoding so I'm not sure where the problem lies. Does anything stand out here? Or is there just a better way? Pieced together from an ancient article because I really needed to understand the basis of creating the post: http://code.activestate.com/recipes/146306-http-client-to-post-using-multipartform-data/ Note, the jpeg is supposed to be "unformatted". The pseudocode: boundary = "somerandomsetofchars" BOUNDARY = '--' + boundary CRLF = '\r\n' fields = [('aspecialkey','thevalueofthekey')] files = [('Image.Data','mypicture.jpg','/users/home/me/mypicture.jpg')] bodylines = [] for (key, value) in fields: bodylines.append(BOUNDARY) bodylines.append('Content-Disposition: form-data; name="%s"' % key) bodylines.append('') bodylines.append(value) for (key, filename, fileloc) in files: bodylines.append(BOUNDARY) bodylines.append('Content-Disposition: form-data; name="%s"; filename="%s"' % (key, filename)) bodylines.append('Content-Type: %s' % self.get_content_type(fileloc)) bodylines.append('') bodylines.append(open(fileloc,'r').read()) bodylines.append(BOUNDARY + '--') bodylines.append('') #print bodylines content_type = 'multipart/form-data; boundary=%s' % BOUNDARY body = CRLF.join(bodylines) #conn = httplib.HTTP("www.ahost.com") # In both this and below, the file part was garbling the rest of the body?!? conn = httplib.HTTPConnection("www.ahost.com") conn.putrequest('POST', "/myuploadlocation/uploadimage") headers = { 'content-length': str(len(body)), 'Content-Type' : content_type, 'User-Agent' : 'myagent' } for headerkey in headers: conn.putheader(headerkey, headers[headerkey]) conn.endheaders() conn.send(body) response = conn.getresponse() result = response.read() responseheaders = response.getheaders() It's interesting in that the real code I've implemented seems to work and is getting back valid responses, but the problem it it's telling me that it can't find the image data. Maybe this is particular to the server, but I'm just trying to rule out that I'm not doing some thing exceptionally stupid here. Or perhaps there's other methodologies for doing this more efficiently. I've not tried poster yet because I want to make sure I'm formatting the POST correctly first. I figure I can upgrade to poster after it's working yes?

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  • Cannot upload media via Wordpress uploader

    - by Justin Johnson
    This has to do with media uploading in Wordpress. Every time WP creates a folder for new uploads (it organizes uploads by year and month: yyyy/mm), it creates it with the "apache:apache' user and group, with full access to all (777 or drwxrwxrwx). However, after that, WP cannot create a folder within that folder (e.g.: mkdir 2011 succeeds, but mkdir 2011/01 fails). Also, uploads cannot be moved into these newly created folders even though the permissions are 777 (rwxrwxrwx). Once a month, I have to chown the newly created folders to be the same as user:group as the rest of the files. Once I do that, uploading works fine (which doesn't make sense to me The really frustrating part is that this problem doesn't exist in other WP installs on other domains on the same server. * I wasn't sure if this should be here or on serverfault. Edit: The containing directory /.../httpdocs/blog/wp-content/uploads has the correct ownership drwxrwxrwx 5 myuser psaserv 4096 Jun 3 18:38 uploads This is a Plesk/CentOS environment hosted by Media Temple (dv). I've written the following test script to simulate the problem <pre><?php $d = "d" . mt_rand(100, 500); var_dump( get_current_user(), $d, mkdir($d), chmod($d, 0777), mkdir("$d/$d"), chmod("$d/$d", 0777), fileowner($d), getmyuid() ); The script always creates the first directory mkdir($d) successfully. On domain A, where the WP problem is, it cannot create the nested directory mkdir("$d/$d"). However, on domain B, both directories are successfully created. I am running each script at /var/www/vhosts/domainA/httpdocs/tmp/t.php and /var/www/vhosts/domainB/httpdocs/tmp/t.php respectively I checked the permissions on tmp, httpdocs, and domain[AB] and they are the same for each path. The only thing that differs is the user.

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  • Upload An Excel File in Classic ASP On Windows 2003 x64 Using Office 2010 Drivers

    - by alphadogg
    So, we are migrating an old web app from a 32-bit server to a newer 64-bit server. The app is basically a Classic ASP app. The pool is set to run in 64-bit and cannot be set to 32-bit due to other components. However, this breaks the old usage of Jet drivers and subsequent parsing of Excel files. After some research, I downloaded the 64-bit version of the new 2010 Office System Driver Beta and installed it. Presumably, this allows one to open and read Excel and CSV files. Here's the snippet of code that errors out. Think I followed the lean guidelines on the download page: Set con = Server.CreateObject("ADODB.Connection") con.ConnectionString = "Provider=Microsoft.ACE.OLEDB.14.0;Data Source=" & strPath & ";Extended Properties=""Excel 14.0;""" con.Open Any ideas why? UPDATE: My apologies. I did forget the important part, the error message: ADODB.Connection error '800a0e7a' Provider cannot be found. It may not be properly installed. /vendor/importZipList2.asp, line 56 I have installed, and uninstalled/reinstalled twice.

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  • Silverlight file upload - file is in use by another process (Excel, Word)

    - by walkor
    Hi, all. I have a problem with uploading of the file in Silverlight application. Here is a code sample. In case when this file is opened in other application (excel or word for example) it fails to open it, otherwise it's working fine. I'm using OpenFileDialog to choose the file and pass it to this function. private byte[] GetFileContent(FileInfo file) { var result = new byte[] {}; try { using (var fs = file.OpenRead()) { result = new byte[file.Length]; fs.Read(result, 0, (int)file.Length); } } catch (Exception e) { // File is in use } return result; } Is there any way i can access this file or should i just notify the user that the file is locked?

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  • Export GridView to TXT, then upload file to server

    Basically what I want to do is export an array (or GridView) to a file called "getpathin.dat". That is easy, but the method I am using downloads the file to my computer, which is what I don't want. I want to write an array to either a PRE-EXISTING file that is on the server OR create a new file on the server in a folder, and this new file will contain either the array or the gridview, which I have stored in the array. i'll be doing this in... Visual Studio 2008/SQL Server using C#

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  • asp code for upload data

    - by vicky
    hello everyone i have this code for uploading an excel file and save the data into database.I m not able to write the code for database entry. someone please help <% if (Request("FileName") <> "") Then Dim objUpload, lngLoop Response.Write(server.MapPath(".")) If Request.TotalBytes > 0 Then Set objUpload = New vbsUpload For lngLoop = 0 to objUpload.Files.Count - 1 'If accessing this page annonymously, 'the internet guest account must have 'write permission to the path below. objUpload.Files.Item(lngLoop).Save "D:\PrismUpdated\prism_latest\Prism\uploadxl\" Response.Write "File Uploaded" Next Dim FSYSObj, folderObj, process_folder process_folder = server.MapPath(".") & "\uploadxl" set FSYSObj = server.CreateObject("Scripting.FileSystemObject") set folderObj = FSYSObj.GetFolder(process_folder) set filCollection = folderObj.Files Dim SQLStr SQLStr = "INSERT ALL INTO TABLENAME " for each file in filCollection file_name = file.name path = folderObj & "\" & file_name Set objExcel_chk = CreateObject("Excel.Application") Set ws1 = objExcel_chk.Workbooks.Open(path).Sheets(1) row_cnt = 1 'for row_cnt = 6 to 7 ' if ws1.Cells(row_cnt,col_cnt).Value <> "" then ' col = col_cnt ' end if 'next While (ws1.Cells(row_cnt, 1).Value <> "") for col_cnt = 1 to 10 SQLStr = SQLStr & "VALUES('" & ws1.Cells(row_cnt, 1).Value & "')" next row_cnt = row_cnt + 1 WEnd 'objExcel_chk.Quit objExcel_chk.Workbooks.Close() set ws1 = nothing objExcel_chk.Quit Response.Write(SQLStr) 'set filobj = FSYSObj.GetFile (sub_fol_path & "\" & file_name) 'filobj.Delete next End if End If plz tell me how to save the following excel data to the oracle databse.any help would be appreciated

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