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  • PHP FTP Upload thousands of files

    - by user275074
    Hi, I've written a small FTP class which I used to move files from a local server to a remote server. It does this by checking an array of local files with an array of files on the remote server. If the file exists on the remote server, it won't bother uploading it. The script works fine for small amounts of files, but I've noticed that the local server can have as many as 3000+ image files to transfer, this seems to cause the script to flop and only transfer a 100 or so. How can I modify the script to handle potentially thousands of image transfer files?

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  • Nginx: check content-length before file upload takes place

    - by robw
    I'm trying to prevent users from uploading (accidentally or maliciously) very large files to my website. I have nginx max_client_body_size set to 4M, but if a file larger than this is uploaded, then it uploads the entire file before returning 413 (entity too large). I want to make nginx check the Content-Length header, so that it rejects the request before it's uploaded. Alternatively, a Rails solution would also be acceptable. Any help appreciated.

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  • Ajax -jquery image upload to iFrame resize problem

    - by DMort59
    I'm modifiying an ajax like jquery image uploader from /www.atwebresults.com/php_ajax_image_upload/ to see image on screen in iframe. I need the image to come in at 100% so I can use jquery resize. filename=name&maxSize=9999999999&maxW=200&fullPath=http://localhost/nyb/uploads/&relPath=../uploads/&colorR=255&colorG=255&colorB=255&maxH=300"

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  • ASP.NET Image Upload Parameter Not Valid. Exception

    - by pennylane
    Hi Guys, Im just trying to save a file to disk using a posted stream from jquery uploadify I'm also getting Parameter not valid. On adding to the error message so i can tell where it blew up in production im seeing it blow up on: var postedBitmap = new Bitmap(postedFileStream) any help would be most appreciated public string SaveImageFile(Stream postedFileStream, string fileDirectory, string fileName, int imageWidth, int imageHeight) { string result = ""; string fullFilePath = Path.Combine(fileDirectory, fileName); string exhelp = ""; if (!File.Exists(fullFilePath)) { try { using (var postedBitmap = new Bitmap(postedFileStream)) { exhelp += "got past bmp creation" + fullFilePath; using (var imageToSave = ImageHandler.ResizeImage(postedBitmap, imageWidth, imageHeight)) { exhelp += "got past resize"; if (!Directory.Exists(fileDirectory)) { Directory.CreateDirectory(fileDirectory); } result = "Success"; postedBitmap.Dispose(); imageToSave.Save(fullFilePath, GetImageFormatForFile(fileName)); } exhelp += "got past save"; } } catch (Exception ex) { result = "Save Image File Failed " + ex.Message + ex.StackTrace; Global.SendExceptionEmail("Save Image File Failed " + exhelp, ex); } } return result; }

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  • Detecting file upload size on the client side?

    - by DisgruntledGoat
    I'm using PHP for file uploads. In the PHP manual it shows an example using a MAX_FILE_SIZE hidden field, saying that it will detect on the client side (i.e. the browser) whether the file is too large or not. I've just tried the example in Firefox, Chrome and IE and it doesn't work. The file is always uploaded, even if it is way larger than the specified hidden field. Incidentally, if the file is larger than MAX_FILE_SIZE then calling move_uploaded_file doesn't work, so it seems the variable is having an effect server-side, but not client-side.

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  • posting form with file upload

    - by Jan
    I am having trouble with uploading a file when using jquery. I have the following HTML in a form. <fieldset> <ul> <li> <div class="field"><input size="35" type="file" name="formFile" id="formFile"/></div> </li> <li> <div class="field"><input size="35" type="text" name="formFileName" id="formFileName" /></div> </li> </ul> </fieldset> To post the data I am using $('#myForm').ajaxForm( When I post the data and the recieved data contains some javascript, the javascript is not recognised. I expected the javscriptcode to run when the data is recieved, but it happens to early. The results indicates that $ or jquery could not be found. If I remove the name attribute from the input type=file element, there are no errors, but that is not the correct solution. How could this happen?

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  • Upload files from website

    - by Andrew
    All I want to do is allow the user to browse through their folders to look for a file, select it and then press submit which saves the file to my server as well as the path to the saved file. How would someone do this? (Some sort of tutorial website would help a lot)

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  • jQuery ajax form and Zend_Form file upload

    - by Sinisa Valentic
    If i submit my ajax form from jQuery, and do print_r($_FILES); i get a list of files uploaded, but if i do something like this $add_form->sound_file->isUploaded(); or $params = $this->_getAllParams(); print_r($params); i don't get my file in zend parametars, and i don't get it uploaded!? Mayb the problem is with he context beng ajax?!

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  • Image upload - Return URL

    - by Qmal
    Hello I build a script that does image uploading and resizing and it all works well, but how can I get the URL from image afterwards? I don't want my Image Source in HTML be like "../img/cat/1.png/" I want it to be like "http://MyIP/img/cat/1.png" I understand that I can just make a variable like $myHost = "http://blabla.com"; and add strip the ".." at the beginning but then it's not so good if I want to use it on other site because I need to replace this all the time. Maybe there is any other way?

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  • Java - Display % of upload done

    - by tr-raziel
    I have a java applet for uploading files to server. I want to display the % of data sent but when I use ObjectOutputStream.write() it just writes to the buffer, does not wait until the data has actually been sent. How can I achieve this. Perhaps I need to use thread synchronization or something. Any clues would be most helpful. This is the code I'm using right now: try{ for(File file : ficheiros){ FileInputStream stream = new FileInputStream (file); int bytesRead1 = 0;; int off1 = 0; int len1 = 100000; if(file.length() < 100000) len1 = new Long(file.length()).intValue(); byte[] bytes1 = new byte[len1]; while (off1 < file.length()) { bytes1 = new byte[len1]; if((file.length() - off1) < len1){ len1 = (new Long(file.length()).intValue() - off1); bytes1 = new byte[len1]; } if((bytesRead1 = stream.read(bytes1)) != -1){ //I want this to block until all data has been sent outputToServlet.write(bytes1, 0, bytesRead1 ); System.out.println("off1: " + off1); off1 = off1 + len1; outputToServlet.flush(); } sent += len1; if(sent>totalLength) sent = (int)totalLength; updateFeedback(sent,totalLength,false);//calls method to display % } updateFeedback(-1,-1,true); } }catch(Exception e){ e.printStackTrace(); } Thanks

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  • How to Create Quality Photo Prints With Free Software

    - by Eric Z Goodnight
    Photoshop may be the professional standard for high quality photo prints, but that doesn’t mean you have to pay hundreds of dollars for printing software. Freeware program Google Picasa can create excellent quality photo prints that’ll only cost you a download. Picasa and other freeware graphics programs are hardly news to savvy geeks, although with a little patience, they can produce quality prints few could tell apart from thousand dollar graphics suites. Stay tuned for links to various graphics programs, and a simple how-to on getting the perfect print settings for your photos Latest Features How-To Geek ETC The Complete List of iPad Tips, Tricks, and Tutorials The 50 Best Registry Hacks that Make Windows Better The How-To Geek Holiday Gift Guide (Geeky Stuff We Like) LCD? LED? Plasma? The How-To Geek Guide to HDTV Technology The How-To Geek Guide to Learning Photoshop, Part 8: Filters Improve Digital Photography by Calibrating Your Monitor Deathwing the Destroyer – WoW Cataclysm Dragon Wallpaper Drag2Up Lets You Drag and Drop Files to the Web With Ease The Spam Police Parts 1 and 2 – Goodbye Spammers [Videos] Snow Angels Theme for Windows 7 Exploring the Jungle Ruins Wallpaper Protect Your Privacy When Browsing with Chrome and Iron Browser

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  • How to Recover that Photo, Picture or File You Deleted Accidentally

    - by The Geek
    Have you ever accidentally deleted a photo on your camera, computer, USB drive, or anywhere else? What you might not know is that you can usually restore those pictures—even from your camera’s memory stick. Windows tries to prevent you from making a big mistake by providing the Recycle Bin, where deleted files hang around for a while—but unfortunately it doesn’t work for external USB drives, USB flash drives, memory sticks, or mapped drives. Luckily there’s another way to recover deleted files. Note: we originally wrote this article a year ago, but we’ve received this question so many times from readers, friends, and families that we’ve polished it up and are republishing it for everybody. So far, everybody has reported success! Latest Features How-To Geek ETC How to Recover that Photo, Picture or File You Deleted Accidentally How To Colorize Black and White Vintage Photographs in Photoshop How To Get SSH Command-Line Access to Windows 7 Using Cygwin The How-To Geek Video Guide to Using Windows 7 Speech Recognition How To Create Your Own Custom ASCII Art from Any Image How To Process Camera Raw Without Paying for Adobe Photoshop What is the Internet? From the Today Show January 1994 [Historical Video] Take Screenshots and Edit Them in Chrome and Iron Using Aviary Screen Capture Run Android 3.0 on a Hacked Nook Google Art Project Takes You Inside World Famous Museums Emerald Waves and Moody Skies Wallpaper Change Your MAC Address to Avoid Free Internet Restrictions

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  • i get error when i try to upload a file?

    - by getaway
    I keep getting an error:Notice: Undefined index: on line 35 line 35: $handle = new Upload($_FILES['my_field']); this is my input field <input type="file" size="32" name="my_field" value="" /> I do not understand this error, thanks!!! EDIT: <form name="upload" id="upload" enctype="multipart/form-data" method="post" action="actions/upload.php" /> <p><input type="file" size="32" name="my_field" value="" /></p> <p class="button"><input type="hidden" name="action" value="image" /> <br> <input style="margin-left:224px;" type="submit" name="submit" value="upload" />

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  • Creando un File Upload

    - by jaullo
    Para iniciar hablaremos un poco sobre el control File Upload, de esta forma daremos una idea general de que es y como trabaja. El File Upload es un control de asp.net que permite que los usuarios seleccionen un archivo de cualquier ubicación en el equipo y lo suban a un directorio predeterminado a traves de una página asp.net. En principio este control esta limitado para no permitir subir archivos de mas de 4 MB. Sin embargo, desde el webconfig de nuestra aplicacón podremos cambiar ese valor, ya sea para aumentarlo o bien para disminuirlo. Nuestro ejemplo, se enfocará en crear un webcontrol que permita seleccionar un archivo y guardarlo, asi que empecemos. Lo primero será agregar a nuestra página un webcontrol que llamaremos Upload.ascx Posteriormente en nuestro webcontrol, agregamos el siguiente código: <table style="width: 100%">         <tr>             <td colspan="3">             <div align="center">                  <asp:Label ID="Label1" runat="server" Text="File Upload"></asp:Label>              </div>             </td>                    </tr>         <tr>             <td style="width: 456px" rowspan="2">                                                             &nbsp;</td>             <td style="width: 386px">                                <div align="center">                         <asp:FileUpload ID="FileUpload1" runat="server" Height="24px" Width="243px" />                         <span id="Span1" runat="server" />                            </div>                      </td>             <td rowspan="2">                                                             </td>         </tr>         <tr>             <td style="width: 386px">                 <div align="center">                      <asp:ImageButton Id="btnupload" runat="server" OnClick="btnupload_Click"                     ImageUrl="~/Styles/img/upload.png" style="text-align: center" />           </div>                  </td>         </tr>         <tr>             <td colspan="3">                 &nbsp;</td>         </tr>     </table>  De esta forma nuestro control deberá verse algo así   Por último en el code behin de nuestro control agregamos el código a nuestro boton, el cual será el encargado de leer el archivo que se encuentra en el File Upload y guardarlo en la ruta especificada.  Protected Sub btnupload_Click(ByVal sender As Object, ByVal e As System.Web.UI.ImageClickEventArgs) Handles btnupload.Click         If FileUpload1.HasFile Then             Dim fileExt As String             fileExt = System.IO.Path.GetExtension(FileUpload1.FileName)             If (fileExt = ".exe") Then                 Label1.Text = "You can´t upload .exe file!"             Else                 Try                     FileUpload1.SaveAs(decrpath & _                        FileUpload1.FileName)                     Label1.Text = "File name: " & _                       FileUpload1.PostedFile.FileName & "<br>" & _                       "File Size: " & _                       FileUpload1.PostedFile.ContentLength & " kb<br>" & _                       "Content type: " & _                       FileUpload1.PostedFile.ContentType                 Catch ex As Exception                     Label1.Text = "ERROR: " & ex.Message.ToString()                 End Try             End If         Else             Label1.Text = "You have not specified a file!"         End If            End Sub   Como vemos en el código anterior tambien hemos agregado otros elementos los cuales nos dirán el nombre del archivo, el tipo de contenido y el tamaño en kb una vez que el archivo ha sido súbido al servidor. Por último deben tomar en cuenta que decrpath es la ruta en donde será subido el archivo, la cual deben variar a su gusto.

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  • php image upload library

    - by Tchalvak
    I'm looking to NOT reinvent the wheel with an image upload system in php. Is there a good standalone library that allows for: Creating the system for uploading, renaming, and perhaps resizing images. Creating the front-end, html and/or javascript for the form upload parts of image upload. I've found a lot of image gallery systems, but no promising standalone system & ui libraries, ready for insertion into custom php.

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  • How to Implement Complex Form Data?

    - by SoulBeaver
    I'm supposed to implement a relatively complex form that looks like follows, but has at least four more pages requiring the user to fill in all necessary information for the tracks: This data will need to be sent to the server, which is implemented using Dropwizard. I'm looking for best practices on how to upload and send such a complex form with potentially dozens of songs to the server. The simplest available solution I have seen is a simple multipart/form-data request with the following form schema (Source): Client <html> <body> <h1>File Upload with Jersey</h1> <form action="rest/file/upload" method="post" enctype="multipart/form-data"> <p> Select a file : <input type="file" name="file" size="45" /> </p> <input type="submit" value="Upload It" /> </form> </body> </html> Server @POST @Path("/upload") @Consumes(MediaType.MULTIPART_FORM_DATA) public Response uploadTrack(final FormDataMultiPart multiPart) { List<FormDataBodyPart> artists = multiPart.getFields("artist"); StringBuffer output = new StringBuffer(); for (FormDataBodyPart artist : artists) output.append(artist.getValueAs(String.class)); List<FormDataBodyPart> tracks = multiPart.getFields("track"); for (FormDataBodyPart track : tracks) writeToFile(track.getValueAs(InputStream.class), "Foo"); return Response.status(200).entity(output.toString()).build(); } Then I have also read about file uploads via Ajax or Formdata (Mozilla HttpRequest) which allows for Posts in the formats application/x-www-form-urlencoded, multipart/form-data, or text/plain. I don't know which approach, if any, is best. An ideal solution would be to utilize Jackson to convert a json string into my data objects, but I don't get the impression that this is possible with binary data.

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  • how to upload & preview multiple images at single input and store in to php mysql [closed]

    - by Nilesh Sonawane
    This is nilesh , i am newcomer in this field , i need the script for when i click the upload button then uploaded images it should preview and store into db like wise i want to upload 10 images at same page using php mysql . #div { border:3px dashed #CCC; width:500px; min-height:100px; height:auto; text-align:center: } Multi-Images Uploader '.$f.''; } } } ? </div> <br> <font color='#3d3d3d' size='small'>By: Ahmed Hussein</font> this script select multiple images and then uplod , but i need to upload at a time only one image which preview and store into database like wise min 10 image user can upload .......

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  • Upload File From URL

    - by Ryan Naddy
    I have been using Windows for a while, and with it there is a feature when you want to upload a photo (for example) to a website, you click on the "Choose File" in Chrome to upload a photo, a "File Explorer" opens, and instead of selecting a file from the hard drive you can paste a URL into the "File Explorer" and press open and it will download the file from the web to your temporary files, and use it to be uploaded. Is there any way I can do that in Ubuntu 12.10? Here is the windows example:Upload from url via File Explorer

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