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  • phpmyadmin throws a blank page after installing Zend CE server

    - by infotoknowledge
    I installed LAMP on Ubuntu 12.0.4 LTE. Then I installed phpmyadmin. Everything was good. I used phpadmin to do lots of DB administration.... Then I installed Zend CE server. Now, phpmyadmin throws a blank page. No login screen. So, I reinstalled my VPS in the same sequence again. No luck. Same behavior. This time, I installed Apache, Mysql, PHP and Zend server in that order. Then I installed phpmyadmin....Unfortunately, still blank page on phpmyadmin. Any help?...Thanks in advance.

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  • Xammp and Zend Library Conflicts

    - by Kieran
    Im trying to use the Zend Frameworks ACL library in my code (in codeigniter) and after including the library in my controller I get this error: Fatal error: Cannot redeclare class Zend_Acl in C:\xampp\php\PEAR\Zend\Acl.php on line 48 If I remove the include to the Zend library I get this error instead Fatal error: Class 'Zend_Acl' not found in C:\xampp\htdocs\ISU-Cart\system\application\libraries\acl.php on line 3 Any help on this?

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  • Display subform after validate main form

    - by bahamut100
    Hi, I want to display a new form after the validation of a form. I use Zend_Form_SubForm to do it (I Try to Zend_Form too), but this new form is not displaying. Why ?? This is the code in question : if ($this->_request->isPost()) { $formData = $this->_request->getPost(); if ($form->isValid($formData)) { $subForm = new Zend_Form_SubForm(); $subForm ->setAction('') ->setMethod('post'); $nom=new Zend_Form_Element_Text('nom'); $submit = new Zend_Form_Element_Submit('submit'); $submit->setLabel('OK'); $subForm->addElements(array($nom,$submit)); } else { $form->populate($formData); } }

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  • zend_form ViewScript decorator / passing arguments

    - by timpone
    I have a form that is extend from Zend_Form. I am placing the form into a ViewScript decorator like this: $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml')))); I'd like to pass in a variable to this ViewScript but am not sure how this could be done. Since the partial renders out as a Zend_View (allowing $this-app_store_icon for rendering), it seems like there should be a way to pass variables to be rendered. I tried the following but to no avail. $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml'),array('app_store_picon'=>$current_app_store_picon)))); Any help on how to get this done would be appreciated. thanks

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  • How to add CSS classes to Zend_Form_Element_Select option

    - by Jah Selassie
    Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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  • Setting the inner html text of a < span > element using Zend_Form_Decorators

    - by Mallika Iyer
    I'm trying to set the inner html of the < span tag here , so it looks like: Group this is what i have so far: $form->addDisplayGroup( array( ................ ), 'maingroup1', array( 'legend'=>'', 'disableDefaultDecorators'=> true, 'decorators'=> array('FormElements', array('FieldSet',array('class'=>'dashed-outline2')), array(array('SpanTag' => 'HtmlTag'), array('tag'=>'span','class' => 'group',)), array('HtmlTag',array('tag'=>'div','id'=>'group1','class'=>'group','openOnly'=> true)) ) ) ); Is there a setter / property that I can use to set the inner text of the < span element using Zend_form_decorators? Thanks.

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  • management users with Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • Xampp and Zend Library Conflicts

    - by Kieran
    Im trying to use the Zend Frameworks ACL library in my code (in codeigniter) and after including the library in my controller I get this error: Fatal error: Cannot redeclare class Zend_Acl in C:\xampp\php\PEAR\Zend\Acl.php on line 48 If I remove the include to the Zend library I get this error instead Fatal error: Class 'Zend_Acl' not found in C:\xampp\htdocs\ISU-Cart\system\application\libraries\acl.php on line 3 Any help on this?

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  • How can I append a description to a Zend_Form_Element?

    - by Mallika Iyer
    I have the following Zend_Form_Element: $imginstructions = "Some description"; $img = $this->createElement('select','img'); $img->setAttrib('class', 'image-select'); $imgdecorator = $img->getDecorator('Description'); $imgdecorator->setOption('escape', false); $img->setLabel('Image:') ->setRequired(true) ->addMultiOptions($images) ->setValue('') ->setDescription($imginstructions) ->addErrorMessage('You must select an image'); $img->size = 5; $this->addElement($img); The description should appear next to the select box. The problem is : When an error is thrown, the html rendered changes so the description shows up below the select box, instead of beside it. HTML rendered before error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p></dd> HTML rendered after error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <ul class="errors"><li>You must select an image</li></ul> <p class="description">Some Description</p></dd> Is there a way to force the error message to be appended as the last element in the DOM tree for the dd element? Something like: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p> <ul class="errors"><li>You must select an image</li></ul></dd> so the 'ul' is at the end of the dd DOM tree. Thanks, I appreciate your taking the time to respond to this question!

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  • Some question about Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • What's the simplest way to create a Zend_Form tabular display with each row having a radio button?

    - by RenderIn
    I've seen simple examples of rendering a Zend_Form using decorators, but I'm not sure they are able to handle the issue I'm facing very well. I query the database and get an array of user objects. I want to display these users as a form, with a radio button next to each of them and a submit button at the bottom of the page. Here's roughly what the form will look like: [user id] [email] [full name] ( ) 1 [email protected] Test user 1 (*) 2 [email protected] Test user 2 [SUBMIT] Is this something achievable in a reasonably straightforward way or do I need to use the ViewScript partial?

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  • row specific class

    - by stimpie
    How do I create a Zend_Db_Table which returns a different class for each row.? Example UserTable has id,name and type Type contains class names (admin,client,etc...) The classes admin, client are all subclasses of user If I call fetch I need to get a admin or client object depending on the corresponding value in the db.

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  • Inject filter into Zend_View

    - by chelmertz
    Hi! I wish to set some properties in MyFilter with constructor injection but it seems impossible with Zend_View::addFilter(string $filter_class_name) since it loads a new instance upon usage. MyFilter implements Zend_Filter_Interface. Can I somehow inject an instance of a filter to an instance of Zend_View?

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  • how to decorate the error message

    - by ulduz114
    this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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  • XML configuration of Zend_Form: child nodes and attributes not always equal?

    - by Cez
    A set of forms (using Zend_Form) that I have been working on were causing me some headaches trying to figure out what was wrong with my XML configuration, as I kept getting unexpected HTML output for a particular INPUT element. It was supposed to be getting a default value, but nothing appeared. It appears that the following 2 pieces of XML are not equal when used to instantiate Zend_Form: Snippet #1: <form> <elements> <test type="hidden"> <options ignore="true" value="foo"/> </test> </elements> </form> Snippet #2: <form> <elements> <test type="hidden"> <options ignore="true"> <value>foo</value> </options> </test> </elements> </form> The type of the element doesn't appear to make a difference, so it doesn't appear to be related to hidden fields. Is this expected or not?

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  • Zend_Db_Select where() and Zend_Db_Adapter quoteInto()

    - by Chris
    Are Zend_Db_Select's where() method, when including the optional value to quite into, and Zend_Db_Adapte's quoteInto() methods basically the same as far as escaping SQL? In other words, are these two pieces of quote identical and equally secure? $select->where($this->getAdapter()->quoteInto('id = ?', 3)); $select->where(id = ?, 3); Thanks!

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  • http://localhost does not work, http://127.0.0.1 works

    - by dskanth
    Iam running Zend with Apache and got to see a strange behaviour.... If i type http://127.0.0.1 in my browser url, it works fine, but after typing: http://localhost, i will get a file download window, saying file type as: application/x-httpd-php And in my httpd.conf file, i have the following under VirtualHost *:80 definition: ServerName localhost DocumentRoot E:\zend\Apache2\htdocs\my_project\public Directory E:\zend\Apache2\htdocs\my_project\public Perhaps some configuration problem... can anyone guide me..

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  • Is there any advantages to integrate Smarty with Zend?

    - by keisimone
    Hi, i am quite familiar with Smarty and recently decided to use Zend framework in implementation. because i am aware of the various advantages of Smarty, i insisted my contractor to integrate Smarty in. But now, i am questioning my assumptions. Should I integrate Smarty in with Zend framework? simply because I am familiar with Smarty syntax? I am also involved with the programming. I got the contractor to help in the architecture and with the prototype.

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  • How do I remove any SELinux context or ACL?

    - by polemon
    HI, I have some files, that I'd like to remove the SELinux context or ACLs from (denoted by a '.' or a '+' respectively when using ls -alZ). I don't have too much time on my hands to read on the , etc on how to use chcon etc., so I just want to quickly know how to disable them all. Also, if someone knows a SELinux/ACL Cheat-Sheet, that would be terrific. Here's a screen shot: Notice the dots right after the permission symbols: drwxr-xr-x., etc.

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  • haproxy: Is there a way to group acls for greater efficiency?

    - by user41356
    I have some logic in a frontend that routes to different backends based on both the host and the url. Logically it looks like this: if hdr(host) ends with 'a.domain.com': if url starts with '/dir1/': use backend domain.com/dir1/ elif url starts with '/dir2/': use backend domain.com/dir2/ # ... else if ladder repeats on different dirs elif hdr(host) ends with 'b.domain.com': # another else if ladder exactly the same as above # ... # ... else if ladder repeats like this on different domains Is there a way to group acls to avoid having to repeatedly check the domain acl? Obviously there needs to be a use backend statement for each possibility, but I don't want to have to check the domain over and over because it's very inefficient. In other words, I want to avoid this: use backend domain.com/url1/ if acl-domain.com and acl-url1 use backend domain.com/url2/ if acl-domain.com and acl-url2 use backend domain.com/url3/ if acl-domain.com and acl-url3 # tons more possibilities below because it has to keep checking acl-domain.com. This is particularly an issue because I have specific rules for subdomains such as a.domain.com and b.domain.com, but I want to fall back on the most common case of *.domain.com. That means every single rule that uses a specific subdomain must be checked prior to *.domain.com which makes it even more inefficient for the common case.

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  • Do you use zend tool if using xampp?

    - by Joel
    Like the question asks-I'm getting started with XAMPP, and I'm wanting to do some Zend tutorials, but I'm confused about whether you still use Zend tool to create the file structure as described here: http://akrabat.com/wp-content/uploads/Getting-Started-with-Zend-Framework.pdf or if you do something different in XAMPP? Any ideas or links anyone can point me to? Thanks!

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  • Zend framework controller action helper

    - by guptanikhilchandra
    I am getting fatal error after adding the action helper class. I am trying to load layout corresponding to called layout. Following is my code snippet: First of all i added a helper class under application/controller/helpers: class Zend_Controller_Action_Helper_Layout extends Zend_Controller_Action_Helper_Abstract { public $pluginLoader; public function __construct() { // TODO Auto-generated Constructor $this->pluginLoader = new Zend_Loader_PluginLoader (); } public function preDispatch() { $bootstrap = $this->getActionController()->getInvokeArg('bootstrap'); $config = $bootstrap->getOptions(); $module = $this->getRequest()->getModuleName(); if (isset($config[$module]['resources']['layout']['layout'])) { $layoutScript = $config[$module]['resources']['layout']['layout']; $this->getActionController()->getHelper('layout')->setLayout($layoutScript); } } } Then i added a loader in bootstrap.php: protected function _initLayoutHelper() { $this->bootstrap('frontController'); Zend_Controller_Action_HelperBroker::addPath(APPLICATION_PATH .'/controllers/helpers'); $layout = Zend_Controller_Action_HelperBroker::addHelper(new Zend_Controller_Action_Helper_Layout()); } Following is my application.ini: [production] autoloaderNamespaces.tree = "Tree_" phpSettings.display_startup_errors = 0 phpSettings.display_errors = 0 includePaths.library = APPLICATION_PATH "/../library" bootstrap.path = APPLICATION_PATH "/Bootstrap.php" bootstrap.class = "Bootstrap" resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" resources.frontController.helperDirectory = APPLICATION_PATH "/controllers/helpers" resources.modules[] = "" contact.resources.frontController.defaultControllerName = "index" resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.layout.layout = layout admin.resources.layout.layout = admin admin.resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.view[] = [staging : production] [testing : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 While running this code i am getting following errors: Warning: include(Zend\Controller\Action\Helper\LayoutLoader.php) [function.include]: failed to open stream: No such file or directory in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Warning: include() [function.include]: Failed opening 'Zend\Controller\Action\Helper\LayoutLoader.php' for inclusion (include_path='D:\personal\proj\renovate\application/../library;D:\personal\proj\renovate\library;.;C:\php5\pear') in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Fatal error: Class 'Zend_Controller_Action_Helper_LayoutLoader' not found in D:\personal\proj\renovate\application\Bootstrap.php on line 33 Kindly let me know, how can i come out from this issue. I am beginner in Zend Framework. Thanks Nikhil

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