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• How to know that a php project is using Zend framework?

  - by Wing C. Chen

  I am writing a piece of small software to go through the folders and files of all the php projects that are passed in and detect if any of them is actually also a Zend project. Is there any particular file that I can immediately read and tell that the current project is a Zend project? or is there any convenient way to tell?

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• Static content not displayed with Zend FW

  - by shin

  I am trying to display a static content with Zend framework. When I go to http://square.localhost/content/services, I get an error message. Could anyone tell me how to fix this please? Thanks in advance. application.ini .... .... resources.layout.layoutPath = APPLICATION_PATH "/layouts" resources.layout.layout = "master" resources.router.routes.home.route = /home resources.router.routes.home.defaults.module = default resources.router.routes.home.defaults.controller = index resources.router.routes.home.defaults.action = index resources.router.routes.static-content.route = /content/:page resources.router.routes.static-content.defaults.module = default resources.router.routes.static-content.defaults.controller = static-content resources.router.routes.static-content.defaults.action = display application/modules/default/controllers/StaticContentController.php class StaticContentController extends Zend_Controller_Action { public function init() { } // display static views public function displayAction() { $page = $this->getRequest()->getParam('page'); if (file_exists($this->view->getScriptPath(null) . "/" . $this->getRequest()->getControllerName() . "/$page." . $this->viewSuffix)) { $this->render($page); } else { throw new Zend_Controller_Action_Exception('Page not found', 404); } } } application/modules/default/views/scripts/static-content/services.phtml some html ... ... Error message An error occurred Page not found Exception information: Message: Page not found Stack trace: #0 /var/www/square/library/Zend/Controller/Action.php(513): StaticContentController->displayAction() #1 /var/www/square/library/Zend/Controller/Dispatcher/Standard.php(295): Zend_Controller_Action->dispatch('displayAction') #2 /var/www/square/library/Zend/Controller/Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #3 /var/www/square/library/Zend/Application/Bootstrap/Bootstrap.php(97): Zend_Controller_Front->dispatch() #4 /var/www/square/library/Zend/Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #5 /var/www/square/public/index.php(26): Zend_Application->run() #6 {main} Request Parameters: array ( 'page' => 'services', 'module' => 'default', 'controller' => 'static-content', 'action' => 'display', )

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• Android -- SDK/IDE Layout Bug (w/Custom Layouts)??

  - by borg17of20

  Hello all, Can someone tell me if this is a bug in the SDK/IDE: Any custom or extended layout I add to my layout XML causes the IDE to ignore the fact that there are any child views of that layout (they just disappear from the outline view/window), thus making them uneditable via the properties view/window. (I need to extend a layout to make onSetAlpha() public) FYI: I'm developing for Android 1.5 and up, using all the latest plug-ins/updates in Eclipse Here is a simple example of a layout XML and the extended Layout that causes this error. [Extended Layout] package com.test; public class CustomLinearLayout extends LinearLayout { public CustomLinearLayout(Context context, AttributeSet attrs) { super(context, attrs); } public CustomLinearLayout(Context context) { super(context); } } [Simple layout XML] <?xml version="1.0" encoding="utf-8"?> <com.test.CustomLinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ImageView android:id="@+id/ImageView01" android:layout_width="wrap_content" android:layout_height="wrap_content"></ImageView> </com.test.CustomLinearLayout> ImageView01 is not visible or editable in the properties or outline views/windows. Thanks.

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• Remote Desktop to home server: From mac gives english keyboard layout, from pc gives norwegian layou

  - by format71

  I'm trying to connect to my home server from my mac, but struggle with typing the password, which contains a plus sign. I have a norwegian keyboard layout, and when I log in from windows (via wmware), I get a norwegian keyboard at the logon screen, but when I connect directly from the mac, I get a english keyboard layout, which makes it impossible to type my password... Why does it give me a different layout for the mac? How can I type a plus sign? The key that should give me a plus sign if the keyboard was english, is the key that contains the ´ and `, and using this button doesn't give me anything in the login prompt... regards, -Vegar

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• Problem connecting to MySQL with zend

  - by wheresrhys

  I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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• Problem connecting to MySQL with zend

  - by wheresrhys

  I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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• phpmyadmin throws a blank page after installing Zend CE server

  - by infotoknowledge

  I installed LAMP on Ubuntu 12.0.4 LTE. Then I installed phpmyadmin. Everything was good. I used phpadmin to do lots of DB administration.... Then I installed Zend CE server. Now, phpmyadmin throws a blank page. No login screen. So, I reinstalled my VPS in the same sequence again. No luck. Same behavior. This time, I installed Apache, Mysql, PHP and Zend server in that order. Then I installed phpmyadmin....Unfortunately, still blank page on phpmyadmin. Any help?...Thanks in advance.

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• Display subform after validate main form

  - by bahamut100

  Hi, I want to display a new form after the validation of a form. I use Zend_Form_SubForm to do it (I Try to Zend_Form too), but this new form is not displaying. Why ?? This is the code in question : if ($this->_request->isPost()) { $formData = $this->_request->getPost(); if ($form->isValid($formData)) { $subForm = new Zend_Form_SubForm(); $subForm ->setAction('') ->setMethod('post'); $nom=new Zend_Form_Element_Text('nom'); $submit = new Zend_Form_Element_Submit('submit'); $submit->setLabel('OK'); $subForm->addElements(array($nom,$submit)); } else { $form->populate($formData); } }

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• zend_form ViewScript decorator / passing arguments

  - by timpone

  I have a form that is extend from Zend_Form. I am placing the form into a ViewScript decorator like this: $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml')))); I'd like to pass in a variable to this ViewScript but am not sure how this could be done. Since the partial renders out as a Zend_View (allowing $this-app_store_icon for rendering), it seems like there should be a way to pass variables to be rendered. I tried the following but to no avail. $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml'),array('app_store_picon'=>$current_app_store_picon)))); Any help on how to get this done would be appreciated. thanks

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• How to add CSS classes to Zend_Form_Element_Select option

  - by Jah Selassie

  Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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• Setting the inner html text of a < span > element using Zend_Form_Decorators

  - by Mallika Iyer

  I'm trying to set the inner html of the < span tag here , so it looks like: Group this is what i have so far: $form->addDisplayGroup( array( ................ ), 'maingroup1', array( 'legend'=>'', 'disableDefaultDecorators'=> true, 'decorators'=> array('FormElements', array('FieldSet',array('class'=>'dashed-outline2')), array(array('SpanTag' => 'HtmlTag'), array('tag'=>'span','class' => 'group',)), array('HtmlTag',array('tag'=>'div','id'=>'group1','class'=>'group','openOnly'=> true)) ) ) ); Is there a setter / property that I can use to set the inner text of the < span element using Zend_form_decorators? Thanks.

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• management users with Zend_Auth and Zend_Session

  - by user1400

  I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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• Linear Layout Issue at Runtime

  - by George

  Hi all, I am trying to build a layout dynamically which display some text and image for the most part, but has a series of buttons placed next to each other in the bottom. I have a linear layout that carries the text, another linear layout that carries the image. And yet another linear layout that carries the buttons that get created in a for loop. I have a main layout aligned vertical that adds the text, image and buttons layout, in that order. To finally generate something like this: Text .... Image ... Button1 Button2 Button3.... The problem is the number of buttons get decided at runtime, so if there are more than 4 buttons, the 5th button gets displayed really tiny. Also, when I tilt the phone, I get only the text and image showing, but no buttons coz the image covers the entire screen. Layoutting seems to be pretty complicated to me, any help is appreciated! Thanks George

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• How can I append a description to a Zend_Form_Element?

  - by Mallika Iyer

  I have the following Zend_Form_Element: $imginstructions = "Some description"; $img = $this->createElement('select','img'); $img->setAttrib('class', 'image-select'); $imgdecorator = $img->getDecorator('Description'); $imgdecorator->setOption('escape', false); $img->setLabel('Image:') ->setRequired(true) ->addMultiOptions($images) ->setValue('') ->setDescription($imginstructions) ->addErrorMessage('You must select an image'); $img->size = 5; $this->addElement($img); The description should appear next to the select box. The problem is : When an error is thrown, the html rendered changes so the description shows up below the select box, instead of beside it. HTML rendered before error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p></dd> HTML rendered after error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <ul class="errors"><li>You must select an image</li></ul> <p class="description">Some Description</p></dd> Is there a way to force the error message to be appended as the last element in the DOM tree for the dd element? Something like: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p> <ul class="errors"><li>You must select an image</li></ul></dd> so the 'ul' is at the end of the dd DOM tree. Thanks, I appreciate your taking the time to respond to this question!

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• Some question about Zend_Auth and Zend_Session

  - by user1400

  I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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• What's the simplest way to create a Zend_Form tabular display with each row having a radio button?

  - by RenderIn

  I've seen simple examples of rendering a Zend_Form using decorators, but I'm not sure they are able to handle the issue I'm facing very well. I query the database and get an array of user objects. I want to display these users as a form, with a radio button next to each of them and a submit button at the bottom of the page. Here's roughly what the form will look like: [user id] [email] [full name] ( ) 1 [email protected] Test user 1 (*) 2 [email protected] Test user 2 [SUBMIT] Is this something achievable in a reasonably straightforward way or do I need to use the ViewScript partial?

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• row specific class

  - by stimpie

  How do I create a Zend_Db_Table which returns a different class for each row.? Example UserTable has id,name and type Type contains class names (admin,client,etc...) The classes admin, client are all subclasses of user If I call fetch I need to get a admin or client object depending on the corresponding value in the db.

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• Inject filter into Zend_View

  - by chelmertz

  Hi! I wish to set some properties in MyFilter with constructor injection but it seems impossible with Zend_View::addFilter(string $filter_class_name) since it loads a new instance upon usage. MyFilter implements Zend_Filter_Interface. Can I somehow inject an instance of a filter to an instance of Zend_View?

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• PHPUnit+ZendFramework ::How I can test multu users session in the same time?

  - by Yosef

  Hi, How I can create test for testing multi users sessions in the same time? (PHPUnit+ZendFramework) basic tests examples that I thinking to do (I am not QA - I soory if i wrong): users logins in the same time users buy process - only 1 user can write and the rest only read. How much session the server can handle in the same time. etc.. Thanks

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• how to decorate the error message

  - by ulduz114

  this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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• XML configuration of Zend_Form: child nodes and attributes not always equal?

  - by Cez

  A set of forms (using Zend_Form) that I have been working on were causing me some headaches trying to figure out what was wrong with my XML configuration, as I kept getting unexpected HTML output for a particular INPUT element. It was supposed to be getting a default value, but nothing appeared. It appears that the following 2 pieces of XML are not equal when used to instantiate Zend_Form: Snippet #1: <form> <elements> <test type="hidden"> <options ignore="true" value="foo"/> </test> </elements> </form> Snippet #2: <form> <elements> <test type="hidden"> <options ignore="true"> <value>foo</value> </options> </test> </elements> </form> The type of the element doesn't appear to make a difference, so it doesn't appear to be related to hidden fields. Is this expected or not?

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• Zend_Db_Select where() and Zend_Db_Adapter quoteInto()

  - by Chris

  Are Zend_Db_Select's where() method, when including the optional value to quite into, and Zend_Db_Adapte's quoteInto() methods basically the same as far as escaping SQL? In other words, are these two pieces of quote identical and equally secure? $select->where($this->getAdapter()->quoteInto('id = ?', 3)); $select->where(id = ?, 3); Thanks!

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• How do I restore the layout on Expression Editor in Powercenter

  - by Charmiane

  I am using Powercenter 8 and I am not sure how I did it, but I have messed up the Expression Editor Layout, so now I am unable to see the expression that I am building. Does anyone know how to restore the screen back to its normal layout. Thank you

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• http://localhost does not work, http://127.0.0.1 works

  - by dskanth

  Iam running Zend with Apache and got to see a strange behaviour.... If i type http://127.0.0.1 in my browser url, it works fine, but after typing: http://localhost, i will get a file download window, saying file type as: application/x-httpd-php And in my httpd.conf file, i have the following under VirtualHost *:80 definition: ServerName localhost DocumentRoot E:\zend\Apache2\htdocs\my_project\public Directory E:\zend\Apache2\htdocs\my_project\public Perhaps some configuration problem... can anyone guide me..

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• Is there any advantages to integrate Smarty with Zend?

  - by keisimone

  Hi, i am quite familiar with Smarty and recently decided to use Zend framework in implementation. because i am aware of the various advantages of Smarty, i insisted my contractor to integrate Smarty in. But now, i am questioning my assumptions. Should I integrate Smarty in with Zend framework? simply because I am familiar with Smarty syntax? I am also involved with the programming. I got the contractor to help in the architecture and with the prototype.

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