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  • how do I insert an hidden token in my form to prevent double posts? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit.

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  • PHP .htaccess issue, specific/dynamic keywords

    - by Kunal
    Here goes my .htaccess file's content. Options +FollowSymLinks RewriteEngine On RewriteRule ^online-products$ products.php?type=online RewriteRule ^land-products$ products.php?type=land RewriteRule ^payment-methods$ payment-methods.php RewriteRule ^withdrawal-methods$ withdrawal-methods.php RewriteRule ^deposit-methods$ deposit-methods.php RewriteRule ^product-bonuses$ product-bonuses.php RewriteRule ^law-and-regulations$ law-and-regulations.php RewriteRule ^product-news$ product-news.php RewriteRule ^product-games$ product-games.php RewriteRule ^no-products$ no-products.php RewriteRule ^page-not-found$ notfound.php RewriteCond %{SCRIPT_FILENAME} !-f RewriteCond %{SCRIPT_FILENAME} !-d RewriteRule ^casinos/(.*)$ product.php?id=$1 RewriteCond %{SCRIPT_FILENAME} !-f RewriteCond %{SCRIPT_FILENAME} !-d RewriteRule ^(.*)$ cms.php?link=$1 ErrorDocument 404 /notfound.php What I am trying to achive here is that the first set of rules apply to some specific keywords which should redirect to specific hard coded pages. But anything else parat from those keywords should redirect to cms.php as a parameter as you can see. But the problem is that every keyword is getting redirected to cms.php. Whereas I want any other keyword apart from which are already hard coded in .htaccess file should go cms.php. Not just every keyword. Example: www.sitename.com/online-products -> www.sitename.com/products.php?type=online www.sitename.com/about-the-website -> www.sitename.com/cms.php?id=about-the-website www.sitename.com/product-news -> www.sitename.com/product-news.php Also another issue I am facing is I can not use any keyword with space. Like "online-products" is fine, but I can't use "online products". Please help me out with your expert knowledge. Many thanks in advance for your kind help. Appreciate it.

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  • need help about process........

    - by adeel amin
    when i start process like process= Runtime.getRuntime().exec("gnome-terminal");, it start shell execution, i want to stop shell execution and want to redirect I/O from process, can anybody tell how i can do this? my code is: public void start_process() { try { process= Runtime.getRuntime().exec("bash"); pw= new PrintWriter(process.getOutputStream(),true); br=new BufferedReader(new InputStreamReader(process.getInputStream())); err=new BufferedReader(new InputStreamReader(process.getErrorStream())); } catch (Exception ioe) { System.out.println("IO Exception-> " + ioe); } } public void execution_command() { if(check==2) { try { boolean flag=thread.isAlive(); if(flag==true) thread.stop(); Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } else { try { Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); check=2; }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } } private void jButton3ActionPerformed(java.awt.event.ActionEvent evt) { // TODO add your handling code here: command=tfCmd.getText().toString().trim(); pw.println(command); execution_command(); } when i enter some command in textfield and press execute button, nothing displayed on my output textarea, how i can stop shellexecution and can redirect Input and output?

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  • Passing a URL as a URL parameter

    - by Andrea
    I am implementing OpenId login in a CakePHP application. At a certain point, I need to redirect to another action, while preserving the information about the OpenId identity, which is itself a URL (with GET parameters), for instance https://www.google.com/accounts/o8/id?id=31g2iy321i3y1idh43q7tyYgdsjhd863Es How do I pass this data? The first attempt would be function openid() { ... $this->redirect(array('controller' => 'users', 'action' => 'openid_create', $openid)); } but the obvious problem is that this completely messes up the way CakePHP parses URL parameters. I'd need to do either of the following: 1) encode the URL in a CakePHP friendly manner for passing it, and decoding it after that, or 2) pass the URL as a POST parameter but I don't know how to do this. EDIT: In response to comments, I should be more clear. I am using the OpenId component, and I have a working OpenId implementation. What I need to do is to link OpenId with an existing user system. When a new user logs in via OpenId, I ask for more details, and then create a new user with this data. The problem is that I have to keep the OpenId URL throughout this process.

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  • Get email address from OpenID provider (Janrain openid library)

    - by Moak
    When signing in to stackoverflow with google I get this message Stackoverflow.com is asking for some information from your Google Account [email protected] • Email address: [email protected] However on my site I can log in with openid but I can't ask for the email address. I get this message You are signing in to example.com with your Google Account [email protected] Also I'm finding it hard to know at what step I need to ask for it, here's some code where I think that step should be built into. /** * Authenticates the given OpenId identity. * Defined by Zend_Auth_Adapter_Interface. * * @throws Zend_Auth_Adapter_Exception If answering the authentication query is impossible * @return Zend_Auth_Result */ public function authenticate() { $id = $this->_id; $consumer = new Auth_OpenID_Consumer($this->_storage); if (!empty($id)) { $authRequest = $consumer->begin($id); if (is_null($authRequest)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", 'Unknown error')); } if (Auth_OpenID::isFailure($authRequest)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", "Could not redirect to server: " . $authRequest->message)); } $redirectUrl = $authRequest->redirectUrl($this->_root, $this->_returnTo); if (Auth_OpenID::isFailure($redirectUrl)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", $redirectUrl->message)); } Zend_OpenId::redirect($redirectUrl); } else { $response = $consumer->complete(Zend_OpenId::selfUrl()); switch($response->status) { case Auth_OpenID_CANCEL: case Auth_OpenID_FAILURE: return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, null, array("Authentication failed. " . @$response->message)); break; case Auth_OpenID_SUCCESS: return $this->_constructSuccessfulResult($response); break; } } } It seems like such an obvious thing but I'm having a hard time googling and combing through the code just to find this. Thanks!

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  • Devise routes to only use custom sign in page

    - by eblume
    I am trying to learn Devise and seem to have hit a problem that is nearly the same as many, many questions here on SO but just slightly different enough that I am not getting much traction following those questions' threads. I have a very simple application. Users can sign in and sign out (and also the devise 'forgot password' stuff is enabled - I am not concerned about it at this time) and that is it. They can't register, they can't edit their profile other than to change their password, they can't do anything except sign in and sign out. (Account creation will, for now, be handled manually at the command line.) I would vastly prefer that the only page that users can log in from was "/" (root_path). I already have it working where you can log in from "/", and that is great. The problem I am having is that if you type in your user/password combination incorrectly from the root_path login page, it automatically sends you to the Devise sign-in page to continue trying to sign in. How can I make Devise redirect to root_path on sign-in failure? Here are my routes - they are probably not optimal or correctly configured and I would appreciate pointers on fixing them: root to: "core_pages#splash" devise_for :users, skip: [:sessions] as :user do # get 'signin' => 'devise/sessions#new', as: :new_user_session post 'signin' => 'devise/sessions#create', as: :user_session delete 'signout' => 'devise/sessions#destroy', as: :destroy_user_session, via: Devise.mappings[:user].sign_out_via end match '/home' => 'core_pages#home' Note the commented-out 'get signin' line. The system works without this line but, surprisingly (to me), "GET /signin" results in a HTTP 400 (OK) response and renders the Devise login template. I would prefer it return some sort of 'invalid request' or just silently redirect the user to root_path. Running rake routes on these routes gives: root / core_pages#splash user_password POST /users/password(.:format) devise/passwords#create new_user_password GET /users/password/new(.:format) devise/passwords#new edit_user_password GET /users/password/edit(.:format) devise/passwords#edit PUT /users/password(.:format) devise/passwords#update user_session POST /signin(.:format) devise/sessions#create destroy_user_session DELETE /signout(.:format) devise/sessions#destroy home /home(.:format) core_pages#home Thanks!

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  • Httaccess Rewriting URL issue: how to distinguish Listing and detail page

    - by Asad kamran
    I am developing an commerce site, Where users can post items in any categories( categories can be 2 to 4 levels) I want to generate URL for listing and details pages: Listing page will show list of items in inner category Detail Page will show all information for item in inner category (Inner category means Last Category in hierarchic i.e. in classified/autos4x4s/mitsubishi/lancer/ inner mean "lancer" Here are the Links i want to generate 1) www.example.com/classified/autos4x4s/mitsubishi/lancer/ (for Listing) 2) www.example.com/classified/autos4x4s/mitsubishi/lancer/2011/3/12/lanc er-2002-in-good-condition-14/ (for detail) I want to redirect to ads.php if just 4 categories exist in url and to detail.php if 6 items are passed(4 category name + 2 date and title) I write these rules: listing ads RewriteRule ^(.)/(.)/(.)/(.)/?$ ads.php?c1=$1&c2=$2&c3=$3&c4=$4 [NC,L] Detail pages RewriteRule ^(.)/(.)/(.)/(.)/(.)/(.)/?$ detail.php?c1=$1&c2=$2&c3=$3&c4=$4&dt=$5&at=$6 [NC,L] But all the sites page redirect to ads.php (Listing page) even home page. I changes the rules as follow: (Even though i donot want to Use Listing and Detail in start of url Why as i see on some site as i want:: dubai.dubizzle.com/classified/autos4x4s/mitsubishi/lancer/2011/3/12/l ancer-2002-in-good-condition-14/) Listing pages RewriteRule ^Listing/(.)/(.)/(.)/(.)/?$ ads.php?c1=$1&c2=$2&c3=$3&c4=$4 [NC,L] Detail pages RewriteRule ^Detail/(.)/(.)/(.)/(.)/(.)/(.)/?$ detail.php?c1=$1&c2=$2&c3=$3&c4=$4&dt=$5&at=$6 [NC,L] Now all other pages are fine, but when i pass www.example.com/classified/autos4x4s/mitsubishi/lancer/2011/3/12/lanc er-2002-in-good-condition-14/ it always goes to Listing page (ads.php) not to detail page. Any help would be appreciated.

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  • inserting a form to session raises picklingerror - django

    - by shanyu
    I receive an exception when I add a form to the session: PicklingError: Can't pickle <class 'django.utils.functional.__proxy__'>: attribute lookup django.utils.functional.__proxy__ failed The form includes a few simple fields and has some javascript attached to a widget. It might be that Django forms cannot be pickled at all, but the exception seems to point to unicode lazy translation. To test further, I have also tried to insert only the form errors (an errordict) to the session and received the same error. I appreciate some help here, thanks in advance. EDIT: Here's why I insert a form into the session: I have an app that has a form. This form is rendered by a template tag in another app. When posted, if the form is valid, no problem, I do stuff and redirect to "next". However if it is not valid, I want to go back to the posting page to show errors. Recall that the comments app in this case redirects to an intermediate "hey, please fix the errors" page. I am trying to avoid this, and hence redirect back to the posting page with the form and its errors in the session that the template tag will render.

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  • Redirecting users after destroy

    - by mathee
    I have 3 models: Questions, Answers, and Profiles (I know, it should be called "Users"). When you view a question Q, I query the database for the answers to Q. (They are linked by id.) In the view, the current user has the option to delete his answer by clicking on the destroy link displayed next to his answer: %table %tr %td Answers: - @answers.each do |a| %tr %td - @provider = Profile.find(a.provider) %i #{h @provider.username} said: %br #{h a.description} %td = link_to 'View full answer', a %td - if a.provider == @profile.id #{link_to 'Delete my answer', a, :confirm => 'Are you sure?', :method => :delete} The problem is that when the user clicks on the destroy link, it redirects to the /answers/index. I want it to redirect to /questions/Q. What's the best way to do this? I know that there's a redirect_to method, but I don't know how to implement it when I want to redirect to an action for a different controller. It also needs to remember the question from which the answer is being deleted. I tried passing something like :question_id in link_to as: #{link_to 'Delete my answer', a, :confirm => 'Are you sure?', :question_id => @question.id, :method => :delete} In AnswersController#destroy: def destroy @answer = Answer.find(params[:id]) @answer.destroy respond_to do |format| format.html { redirect_to(answers_url) } format.xml { head :ok } end @question = Question.find(params[:question_id]) redirect_to question_path(@question) end The :question_id information is not passed to the destroy method, so I get this error: Couldn't find Question without an ID To confirm, I added a puts call before Question.find, and it returned nil.

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  • Javascript ended event when video playback ends on android

    - by Tjofras
    I have been trying to create a web page that will redirect the user after he has watched a video (or if he aborted the playback). I've got this working on the iphone but can't really figure out how it works on the android. On the Iphone i have found two ways of doing this. using the tag to embed the quicktime plugin and then adding a event listener with javascript to listen to the 'qt_ended' event. This does obviously not work on android because there is no quicktime plugin. The second thing i tried was using the html5 -tag and listening to the 'ended' event, again this worked on the iphone but to my surprise not on android. In this case i got the video playing on the android phone but no redirect occurred after the video had reached the end. So my guess is that the android browser does not fully support the video-tag and that it does not fire the event. So at this time i don't really know how to proceed. I'm guessing i could do something similar to the quicktime embed solution but using a plugin available on android. But i cant find any information on what plugins is available on the android and if they support some kind of 'ended'-event.

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  • My android tests don't get internet access!

    - by Malachii
    The subject says it all. My application gets internet access thanks to the android.permission.INTERNET permission, but my test cases don't while using the instrumentation test runner. This means I can't test my server IO routines in my test cases. What's up? Here's my manifest in case it helps you. Thanks! Sorry about the lack of indents - could not get it working on short notice with this site. Thanks! <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.example.helloandroid" android:versionCode="1" android:versionName="1.0"> <uses-permission android:name="android.permission.INTERNET"></uses-permission> <application android:icon="@drawable/icon" android:label="@string/app_name"> <uses-library android:name="android.test.runner" /> <activity android:name=".HelloAndroid" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <uses-sdk android:minSdkVersion="2" /> <instrumentation android:name="android.test.InstrumentationTestRunner" android:targetPackage="qnext.mobile.redirect" android:label="Qnext Redirect Tests" /> </manifest>

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  • jQuery AJAX request (Rails 3) gets redirected and returns empty message body!

    - by elsurudo
    I'm trying to do a manual jQuery AJAX request the following way: $("#user_plan_id").change(function() { $("#plan_container").load('/plans/' + this.value); }); I have the "rails.js" file included in my header, and a "<%= csrf_meta_tag %". I see from my log that the request IS getting to the server (although without the authenticity token... does rails.js even do this?), but the response is a 302 (Found) rather than 200, and no data actually gets rendered. Any ideas? Edit: I now see that the first request redirects, and the proper partial gets rendered on the redirect. However, the 2nd response's body (on the client-side) is still empty. I'm guessing jQuery uses the first response and doesn't have a listener set up for the redirect. How do I get around this? Also, another note: the page doing the requesting is an HTTPS page. Here is what my log says: Started GET "/plans/221168073" for 127.0.0.1 at Tue Jun 15 01:24:06 -0400 2010 Processing by PlansController#show as HTML Parameters: {"id"=>"221168073"} DEPRECATION WARNING: Using #request_uri is deprecated. Use fullpath instead. (called from ensure_proper_protocol at /Users/ernestsurudo/Sites/vidfolia/vendor/plugins/ssl_requirement/lib/ssl_requirement.rb:57) Redirected to http://vidfolia.com/plans/221168073 Completed 302 Found in 1ms Perhaps it has something to do with the deprecation warning?

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  • URL with no query parameters - How to distinguish.

    - by Broken Link
    Env: .NET 1.1 I got into this situation. Where I need to give a URL that someone could redirect them to our page. When they redirect they also need to tell us, what message I need to display on the page. Initially I thought of something like this. http://example.com/a.aspx?reason=100 http://example.com/a.aspx?reason=101 ... http://example.com/a.aspx?reason=115 So when we get this url based on 'reason' we can display different message. But the problem turns out to be that they can not send any query parameters at all. They want 15 difference URL's since they can't send query params. It doesn't make any sense to me to created 15 pages just to display a message. Any smart ideas,that have one URL and pass the 'reason' thru some means? EDIT: Options I'm thinking based on Answers Try HttpRequest.PathInfo or Second option I was thinking was to have a httphanlder read read the path like this - HttpContext.Request.Path based on path act. Ofcourse I will have some 15 entries like this in web.config. <add verb="*" path="reason1.ashx" type="WebApplication1.Class1, WebApplication1" /> <add verb="*" path="reason2.ashx" type="WebApplication1.Class1, WebApplication1" /> Does that look clean?

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  • Android : Handle OAuth callback using intent-filter

    - by Dave Allison
    I am building an Android application that requires OAuth. I have all the OAuth functionality working except for handling the callback from Yahoo. I have the following in my AndroidManifest.xml : <intent-filter> <action android:name="android.intent.action.VIEW"></action> <category android:name="android.intent.category.DEFAULT"></category> <category android:name="android.intent.category.BROWSABLE"></category> <data android:host="www.test.com" android:scheme="http"></data> </intent-filter> Where www.test.com will be substituted with a domain that I own. It seems : This filter is triggered when I click on a link on a page. It is not triggered on the redirect by Yahoo, the browser opens the website at www.test.com It is not triggered when I enter the domain name directly in the browser. So can anybody help me with When exactly this intent-filter will be triggered? Any changes to the intent-filter or permissions that will widen the filter to apply to redirect requests? Any other approaches I could use? Thanks for your help.

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  • Help a Beginner with a PHP based Login System

    - by Brian Lang
    I'm a bit embarrassed to say, but I've run into issue with creating a PHP based login system. I'm using a site template to handle the looks of the the login process, so I will spare you the code. Here is my thought process on how to handle the login: Create a simple login.php file. On there will be a form whose action is set to itself. It will check to see if the submit has been clicked, and if so validate to make sure the user entered a valid password / username. If they do, set a session variable save some login info (username, NOT password), and redirect them to a restricted area. If the login info isn't valid, save an error message in a session variable, display error message giving further instruction, and wait for the user to resubmit. Here is a chunk of what I have - hopefully one of you experts can see where I've gone wrong, and give me some insight: if(isset($_POST['submit'])) { if(!empty($_POST['username']) AND !empty(!$_POST['password'])) { header("Location: http://www.google.com"); } else { $err = 'All the fields must be filled in!'; } } if($err) { $_SESSION['msg']['login-err'] = $err; } ? Now the above is just an example - the intent of the above code is to process user input, with the script validating simply that the user has given input for username and password. If they have, I would like them, in this case, to be redirected to google.com (for the sake of this example). If not, save an error message. Given my current code, the error message will display perfectly, however if the user submits and has something entered for the username and password, the page simply doesn't redirect. I'm sure this is a silly question, but I am a beginner, and well, to be honest, a bit buzzed right now. Thanks so much!

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  • Rackspace Cloud rewrite jpg causes Session reset

    - by willoller
    This may be the .Net version of this question. I have an image script with the following: ... Response.WriteFile(filename); Response.End(); I am rewriting .jpg files using the following rewrite rule in web.config: <rule name="Image Redirect" stopProcessing="true"> <match url="^product-images/(.*).jpg" /> <conditions> <add input="{REQUEST_URI}" pattern="\.(jp?g|JP?G)$" /> </conditions> <action type="Redirect" redirectType="SeeOther" url="/product-images/ProductImage.aspx?path=product-images/{tolower:{R:1}}.jpg" /> </rule> It basically just rewrites the image path into a query parameter. The problem is that (intermittently of course) Mosso returns a new Asp Session cookie which breaks the whole world. Directly accessing a static .jpg file does not cause this problem. Directly accessing the image script does not cause it either. Only rewriting a .jpg file to the .aspx script causes the Session loss. Things I have tried (From the Rackspace doc How can I bypass the cache?) I added Private cacheability to the image script itself: Response.Cache.SetCacheability(HttpCacheability.Private); I tried adding these cache-disabling nodes to web.config: <staticContent> <clientCache cacheControlMode="DisableCache" /> </staticContent> and <httpProtocol> <customHeaders> <add name="Cache-Control private" value="Cache-Control private" </customHeaders> </httpProtocol> The Solution I need The browser cache cannot be disabled. This means potential solutions involving Cache.SetNoStore() or HttpCacheability.NoCache will not work.

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  • How to avoid shell execution of a Process?

    - by adeel amin
    When I start a process like process = Runtime.getRuntime().exec("gnome-terminal");, it starts shell execution. I want to stop shell execution and want to redirect I/O from process, can anybody tell how I can do this? My code is: public void start_process() { try { process= Runtime.getRuntime().exec("gnome-terminal"); pw= new PrintWriter(process.getOutputStream(),true); br=new BufferedReader(new InputStreamReader(process.getInputStream())); err=new BufferedReader(new InputStreamReader(process.getErrorStream())); } catch (Exception ioe) { System.out.println("IO Exception-> " + ioe); } } public void execution_command() { if(check==2) { try { boolean flag=thread.isAlive(); if(flag==true) thread.stop(); Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } else { try { Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); check=2; }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } } private void jButton3ActionPerformed(java.awt.event.ActionEvent evt) { // TODO add your handling code here: command=tfCmd.getText().toString().trim(); pw.println(command); execution_command(); } When I enter some command in textfield and press execute button, nothing is displayed on my output textarea, how I can stop shell execution and redirect input and output?

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  • In my cakephp project the save function is not working?

    - by Faheem
    My controller action is: function add() { if (!empty($this-data)) { $this-Customer-create(); if ($this-Customer-save($this-data)) { $this-Session-setFlash('A new Customer has been added'); $this-redirect(array('action'='index')); } else { $this-Session-setFlash('The customer cannot be added this time. Try again later.'); $this-redirect(array('action'='index')); } } } My model is: class Customer extends AppModel { var $name = 'Customer'; var $validate = array( 'name' = array( 'length'= array( 'rule' = array('between', 4,50), 'message' = 'Name must be minimum 4 and maximum 50 characters long.' ), 'checkUnique'= array( 'rule' = 'isUnique', 'message' = 'This Name is already registered' ) )); and this is my view: create('Customer',array('action'='add'));? input('Customer.name'); echo $form-input('Customer.balance',array('type'='hidden','default'=0)); ? end('Submit');? every time I submit the form it splashes: The customer cannot be added this time. Try again later.

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  • django-social-auth for Facebook is redirecting home and not logging in

    - by Scott Rogowski
    I have had django-social-auth working for Google for quite some time now but am having problems with Facebook. I am at the point where clicking on the /login/facebook/ link will take me to the Facebook authorization page. I then click "go to app" and it redirects me to my home page but does not log in or create a user but does put some strange "#=" onto the back of my URL. Reading up on that, here https://developers.facebook.com/blog/post/552/, and here https://github.com/omab/django-social-auth/issues/199, it seems that would be happening if the redirect uri was not defined. However, on my facebook app settings, I have the following (replacing my site with example.com): + App Namespace: "example" + Site URL: "http://example.com/complete/facebook/" + Site Domain: "example.com" + Sandbox Mode: "On" + Post-Authorize Redirect URL: "http://apps.facebook.com/example/" + Deauthorize URL: "http://www.example.com/" + Post-Authorize URL: "http://example.com/complete/facebook/" The request that django-social-auth is sending to facebook is (replacing my info again): "https://www.facebook.com/dialog/oauth?scope=email&state=*&redirect_uri=http%3A%2F%2Fexample.com%2Fcomplete%2Ffacebook%2F%3Fredirect_state%3D***&client_id=*" The /complete/facebook/ is what is in the documentation and google works as /complete/google/ What am I missing here?

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  • cakephp phone number validation

    - by hellosheikh
    i am new to cakephp 2.x so i dont know how to do this .. i want to login the user from his email address and phone number..what my intention is if the number in database is this "12345" and the user is trying to login through this number "+12345" he can be login into the system.. i have written a code but i dont know how can i use this or to adjust my code within the auth component as the auth component is autometically logging the user .. here is my controller public function beforeFilter() { parent::beforeFilter(); $this->Auth->authenticate = array( 'Authenticate.Cookie' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'userModel' => 'User', 'scope' => array('User.active' => 1) ), 'Authenticate.MultiColumn' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'columns' => array('email', 'mobileNo'), 'userModel' => 'User', ) ); } public function login() { if ($this->Auth->login() || $this->Auth->loggedIn()) { $this->redirect('/users/dashboard'); }else{ $this->layout='logindefault'; $this->set('title_for_layout', 'Account Login'); /*$this->Auth->logout(); $cookie = $this->Cookie->read('Auth.User'); */ if ($this->request->is('post')) { if ($this->Auth->login() || $this->Auth->loggedIn()) { if ($this->Session->check('Auth.User')){ $this->_setCookie($this->Auth->user('idUser')); $this->redirect('/users/dashboard'); } }else { $this->Session->setFlash('Incorrect Email/Password Combination'); } }} } here is the code which i am trying to add .. $mobileNo='+123456789'; if (strpos($mobileNo,'+') !== false) { $mobileNo=str_replace("+", "",$mobileNo); } ?

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  • Rewrite a URL that's already been redirected?

    - by Jack
    Hi guys, I'm running an Apache2 web server with a dynamic IP address. I bought exampledomain.net, and I use no-ip.com's domain-update service to redirect any visitors to my current ip address (endnote #1). For example, someone visits exampledomain.net and they get redirected to 73.181.57.34. It works like a charm. However, it isn't all that user-friendly. Can I rewrite the redirected, ip-address URL? I tried these rewrite rules in the root folder's .htaccess... RewriteEngine On RewriteCond %{HTTP_HOST} ^73\.181\.57\.34:88 RewriteRule ^(.*)$ http://www.exampledomain.net/$1 [L,NC] # I simplified the RewriteCond. I would use regex in a real situation. Of course, this creates an infinite loop. The user visits www.exampledomain.net. They're redirected to 73.181.57.34:88 by no-ip. Apache redirects them to www.exampledomain.net which redirects them back to 73.181.57.34:88... so on and so forth. I'm a noob when it comes to rewriting, but is there a way to rewrite a URL without redirecting? I tried these rewrite rules too (a shot in the dark)... RewriteEngine On RewriteCond %{HTTP_HOST} ^73\.181\.57\.34:88 RewriteRule ^(.*)$ my.exampledomain.net/$1 [L,NC] # I'd read that Apache replied with a redirect header when you include http Thanks! (1) No-IP works like this: You download and install their dynamic update client on your server. Every couple of minutes it polls your server for its current external ip address. If it's changed, it updates your server's ip address in no-ip's records.

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  • cakephp read and display from more than one related table

    - by z22
    I have 2 tables Users and Artists. User: id name password city_id state_id country_id Artist: id user_id description I wish to create add and edit form(single form acts as add and edit). But on click of edit link, I wish to fill in the form fields from user as well as artist table. How do i do that? Below is my controller code: public function artist_register() { $this->country_list(); if ($this->request->is('post')) { $this->request->data['User']['group_id'] = 2; if ($this->{$this->modelClass}->saveAll($this->request->data)) { $this->redirect(array('controller' => 'Users', 'action' => 'login')); } } $this->render('artist_update'); } public function artist_update($id) { $artist = $this->{$this->modelClass}->findByuser_id($id); $artist_id = $artist[$this->modelClass]['id']; if($this->request->is('get')) { $this->request->data = $this->{$this->modelClass}->read(null, $artist_id); $this->request->data = $this->{$this->modelClass}->User->read(null, $id); } else { if($this->{$this->modelClass}->save($this->request->data)) { $this->Session->setFlash('Your Profile has been updated'); $this->redirect(array('action' => 'index')); } } } The code doesnt work. how do i solve it?

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  • Clicking on MenuItem without clicking on the text

    - by pringlesinn
    I've got a Menu, and I want to click on the menu, but not on the text if you guys know what i mean. The MenuItem has a border, or something like this, but when I click on it it won't redirect to the page I want unless I click on text. Is it possible to click on the whole "Button" and redirect or do what is need to do? My menu is like this: <rich:dropDownMenu showDelay="250" hideDelay="0" submitMode="none"> <f:facet name="label">Tools</f:facet> <rich:menuItem> <s:link view="/pages/tools/ppaParameters/PpaParametersEdit.xhtml" value="Parameters" id="PpaParametersId" includePageParams="false" propagation="none"/> </rich:menuItem> <rich:menuGroup value="Security"> <rich:menuItem> <s:link view="/pages/tools/security/ppaModule/PpaModuleEdit.xhtml" value="Module" id="PpaModuleId" includePageParams="false" propagation="none" /> </rich:menuItem> </rich:menuGroup> </rich:dropDownMenu> There's an example. I need to click on text to make it work out.

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  • How to Access value of dynamically created control?

    - by sharad
    i have asp.net web application in which i need to create form dynamically depend upon table which user selected.however,i created form dynamically with it's control like text box,drop downlist etc. but not able to access those controls at particular button click event. My form scenario is like this: i have dropdownlist in which i display list of tables,button control say display( on click event which i redirect page with some addition in querystring so that at page init it dynamically genrate controls) and another button control which used to access this controls value say Submit and store in database. This is my code: At Display button Click event: Response.Redirect("dynamic_main.aspx?mode=edit&tablename=" + CMBTableList.SelectedItem.ToString()); This is code For page.Init level if (Request.QueryString["mode"] != null) { if (Request.QueryString["mode"].ToString() == "edit") { Session["tablename"] = Request.QueryString["tablename"].ToString(); // if (Session["tablename"].ToString() == CMBTableList.SelectedItem.ToString()) //{ createcontrol(Session["tablename"].ToString()); // } } } i have used createcontrol() which genrate controls Code For Submit Button: string[] contid=controlid.Value.Split(','); MasterPage ctl00 = FindControl("ctl00") as MasterPage; ContentPlaceHolder cplacehld = ctl00.FindControl("ContentPlaceHolder2") as ContentPlaceHolder; Panel panel1 = cplacehld.FindControl("plnall") as Panel; Table tabl1 = panel1.FindControl("id1") as Table; foreach (string sin in contid) { string splitcvalu = sin.Split('_')[0].ToString(); ControlsAccess contaccess = new ControlsAccess(); if (splitcvalu.ToString() == "txt") { TextBox txt = (TextBox)tabl1.FindControl(sin.ToString()); //TextBox txt = cplacehld.FindControl(sin.ToString()) as TextBox; val = txt.ID; } else { DropDownList DDL = cplacehld.FindControl(sin.ToString()) as DropDownList; } } Here i am no able to access this textbox or drop downlist.i am getting id of particular control from hidden field controlid in which i have stored it during genrating controls. i have used findcontrol() it works in case of finding masterpage,contentplaceholder,table etc. but in case of textbox or other control it doesnt work it shows it returns null. Anyone can help me. Thanks

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  • What are some methods to prevent double posting in a form? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit. METHODS: someone suggested using sessions. I would set the random token to $_SESSION['_token'] and check if that session token is equal to the $_POST['_token'], but how do I do that? When I tried, it still doesn't check

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