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  • SCJP Book, IO section: Is this a typo or is there a reason it would look like this?

    - by iamchuckb
    My question is about line 4, where the new PrintWriter is created with the constructor taking the FileWriter fw as a parameter. I don't understand the use of chaining the BufferedWriter bw to FileWriter if it isn't used later on in the actual writing. Can Java apply chaining in a way that bw still somehow affects the rest of the program? 16. try { 17. FileWriter fw = new FileWriter(test); 18. BufferedWriter bw = new BufferedWriter(fw, 1024); 19. PrintWriter out = new PrintWriter(fw); 20. out.println("<html><body><h1>"); 21. out.println(args[0]); 22. out.println("</h1></body></html>"); 23. out.close(); 24. bw.close(); 25. fw.close(); 26. }catch(IOException e) { 27. e.printStackTrace(); 28. } I think it is probably a typo and they meant to use bw as the parameter for PrintWriter out but like the title says, I'm new to this. Thanks to all in advance.

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  • Algorithm for finding similar users through a join table

    - by Gdeglin
    I have an application where users can select a variety of interests from around 300 possible interests. Each selected interest is stored in a join table containing the columns user_id and interest_id. Typical users select around 50 interests out of the 300. I would like to build a system where users can find the top 20 users that have the most interests in common with them. Right now I am able to accomplish this using the following query: SELECT i2.user_id, count(i2.interest_id) AS count FROM interests_users as i1, interests_users as i2 WHERE i1.interest_id = i2.interest_id AND i1.user_id = 35 GROUP BY i2.user_id ORDER BY count DESC LIMIT 20; However, this query takes approximately 500 milliseconds to execute with 10,000 users and 500,000 rows in the join table. All indexes and database configuration settings have been tuned to the best of my ability. I have also tried avoiding the use of joins altogether using the following query: select user_id,count(interest_id) count from interests_users where interest_id in (13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,508) group by user_id order by count desc limit 20; But this one is even slower (~800 milliseconds). How could I best lower the time that I can gather this kind of data to below 100 milliseconds? I have considered putting this data into a graph database like Neo4j, but I am not sure if that is the easiest solution or if it would even be faster than what I am currently doing.

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  • Why ntp settle time toe long?

    - by fercis
    I simply try to set-up NTP to my system. Both server and clients will run on my computer which are linked together with local link. One of them will have the reference clock. Both the server and Client are linux Ubuntu. I install ntp daemon to both sides. In clients, I enter the ip address of the server to /etc/ntp.conf. Everything works fine. However, the setting of the time to correct time in client side takes too long time (around 17 minutes). Is it possible to gather correct time just at startup. I write some code that regularly calls "ntpdate " by system call and the problem is solved but there has to be something that allows me to decrease the poll time of the client to 1-2 minutes. There are some settings as maxpoll - minpoll in ntp.conf, but I couldn't manage to understand their function, because with the best configuration (minpoll 4? 16 seconds?) I also cannot see that client side corrects its time before 10 minutes. In addition, in some cases my client is an embedded system (ARM - IGEP board) and it always opens with an irrelevant date (2-3 years ago). So the time that takes to correct the time should not depend on the time difference also.

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  • Print an array elements

    - by 1ace1
    Hello guys, this is my first post and im still a beginner in the programming world so bare with me. I just created an array with 100 initialized values and i want to print out 10 elements on each line so it would be somthing like this 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 ...26 this is the code i used and i managed to do it for the first 10 elements but i couldnt figure out how to do it for the rest public static void main(String[] args) { int[] numbers = { 0,1,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17}; int i, count = 0; for (i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); count++; if (count == 9) for (i = 9; i < numbers.length; i++) System.out.println(numbers[i] + " "); } } thanks!

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  • postgresql help with php loop....

    - by KnockKnockWhosThere
    I keep getting an "Notice: Undefined index: did" error with this query, and I'm not understanding why... I'm much more used to mysql, so, maybe the syntax is wrong? This is the php query code: function get_demos() { global $session; $demo = array(); $result = pg_query("SELECT DISTINCT(did,vid,iid,value) FROM dv"); if(pg_num_rows($result) > 0) { while($r = pg_fetch_array($result)) { switch($r['did']) { case 1: $demo['a'][$r['vid']] = $r['value']; break; case 2: $demo['b'][$r['vid']] = $r['value']; break; case 3: $demo['c'][$r['vid']] = $r['value']; break; } } } else { $session->session_setMessage(2); } return $demo; } When I run that query at the pg prompt, I get results: "(1,1,1,"A")" "(1,2,2,"B")" "(1,3,3,"C")" "(1,4,4,"D")" "(1,5,5,"E")" "(1,6,6,"F")" "(1,7,7,"G")" "(1,8,8,"H")" "(1,9,9,"I")" "(1,10,A,"J")" "(1,11,B,"K")" "(1,12,C,"L")" "(1,13,D,"M")" "(2,14,1,"A")" "(2,15,2,"B")" "(2,16,0,"C")" "(3,17,1,"A")" "(3,18,2,"B")" "(3,19,3,"C")" "(3,20,4,"D")" "(3,21,5,"E")" "(3,22,6,"F")" "(3,23,7,"G")"

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  • How to select the first property with unknown name from JSON and how to select first item from array

    - by Oscar Godson
    I actually have two questions, both are probably simple, but for some odd reason I cant figure it out... I've worked with JSON 100s of times before too! but here is the JSON in question: {"69256":{"streaminfo":{"stream_ID":"1025","sourceowner_ID":"2","sourceowner_avatar":"http:\/\/content.nozzlmedia.com\/images\/sourceowner_avatar2.jpg","sourceownertype_ID":"1","stream_name":"Twitter","streamtype":"Social media","appsarray":[]},"item":{"headline":"Charboy","main_image":"http:\/\/content.nozzlmedia.com\/images\/author_avatar173212.jpg","summary":"ate a tomato and avocado for dinner...","nozzl_captured":"2010-05-12 23:02:12","geoarray":[{"state":"OR","county":"Multnomah","city":"Portland","neighborhood":"Downtown","zip":"97205","street":"462 SW 11th Ave","latitude":"45.5219","longitude":"-122.682"}],"full_content":"ate a tomato and avocado for dinner tonight. such tasty foods. just enjoyable.","body_text":"ate a tomato and avocado for dinner tonight. such tasty foods. just enjoyable.","author_name":"Charboy","author_avatar":"http:\/\/content.nozzlmedia.com\/images\/author_avatar173212.jpg","fulltext_url":"http:\/\/twitter.com\/charboy\/statuses\/13889868936","leftovers":{"twitter_id":"tag:search.twitter.com,2005:13889868936","date":"2010-05-13T02:59:59Z","location":"iPhone: 45.521866,-122.682262"},"wordarray":{"0":"ate","1":"tomato","2":"avocado","3":"dinner","4":"tonight","5":"tasty","6":"foods","7":"just","8":"enjoyable","9":"Charboy","11":"Twitter","13":"state:OR","14":"county:Multnomah, OR","15":"city:Portland, OR","16":"neighborhood:Downtown","17":"zip:97205"}}}} Question 1: How do I loop through each item (69256) when the number is random? e.g. item 1 is 123, item2 is 646? Like, for example, a normal JSON feed would have something like: {'item':{'blah':'lorem'},'item':{'blah':'ipsum'}} the JS would be like console.log(item.blah) to return lorem then ipsum in a loop How do I do it when i dont know the first item of the object? Question 2: How do I select items from the geoarray object? I tried: json.test.item.geoarray.latitude and json.test.item.geoarray['latitude']

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  • Using JRE 1.5, still maven says annotation not supported in -source 1.3

    - by Abhijeet
    Hi, I am using JRE 1.5. Still when I try to compile my code it fails by saying to use JRE 1.5 instead of 1.3 C:\temp\SpringExamplemvn -e clean install + Error stacktraces are turned on. [INFO] Scanning for projects... [INFO] ------------------------------------------------------------------------ [INFO] Building SpringExample [INFO] task-segment: [clean, install] [INFO] ------------------------------------------------------------------------ [INFO] [clean:clean {execution: default-clean}] [INFO] Deleting directory C:\temp\SpringExample\target [INFO] [resources:resources {execution: default-resources}] [WARNING] Using platform encoding (Cp1252 actually) to copy filtered resources, i.e. build is platform dependent! [INFO] Copying 6 resources [INFO] [compiler:compile {execution: default-compile}] [INFO] Compiling 6 source files to C:\temp\SpringExample\target\classes [INFO] ------------------------------------------------------------------------ [ERROR] BUILD FAILURE [INFO] ------------------------------------------------------------------------ [INFO] Compilation failure C:\temp\SpringExample\src\main\java\com\mkyong\stock\model\Stock.java:[45,9] annotations are not supported in -source 1.3 (try -source 1.5 to enable annotations) @Override [INFO] ------------------------------------------------------------------------ [INFO] Trace org.apache.maven.BuildFailureException: Compilation failure C:\temp\SpringExample\src\main\java\com\mkyong\stock\model\Stock.java:[45,9] annotations are not supported in -source 1.3 (try -source 1.5 to enable annotations) @Override at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoals(DefaultLifecycleExecutor.java:715) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoalWithLifecycle(DefaultLifecycleExecutor.java:556) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoal(DefaultLifecycleExecutor.java:535) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoalAndHandleFailures(DefaultLifecycleExecutor.java:387) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeTaskSegments(DefaultLifecycleExecutor.java:348) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.execute(DefaultLifecycleExecutor.java:180) at org.apache.maven.DefaultMaven.doExecute(DefaultMaven.java:328) at org.apache.maven.DefaultMaven.execute(DefaultMaven.java:138) at org.apache.maven.cli.MavenCli.main(MavenCli.java:362) at org.apache.maven.cli.compat.CompatibleMain.main(CompatibleMain.java:60) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:585) at org.codehaus.classworlds.Launcher.launchEnhanced(Launcher.java:315) at org.codehaus.classworlds.Launcher.launch(Launcher.java:255) at org.codehaus.classworlds.Launcher.mainWithExitCode(Launcher.java:430) at org.codehaus.classworlds.Launcher.main(Launcher.java:375) Caused by: org.apache.maven.plugin.CompilationFailureException: Compilation failure C:\temp\SpringExample\src\main\java\com\mkyong\stock\model\Stock.java:[45,9] annotations are not supported in -source 1.3 (try -source 1.5 to enable annotations) @Override at org.apache.maven.plugin.AbstractCompilerMojo.execute(AbstractCompilerMojo.java:516) at org.apache.maven.plugin.CompilerMojo.execute(CompilerMojo.java:114) at org.apache.maven.plugin.DefaultPluginManager.executeMojo(DefaultPluginManager.java:490) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoals(DefaultLifecycleExecutor.java:694) ... 17 more [INFO] ------------------------------------------------------------------------ [INFO] Total time: 2 seconds [INFO] Finished at: Wed Dec 22 10:04:53 IST 2010 [INFO] Final Memory: 9M/16M [INFO] ------------------------------------------------------------------------ C:\temp\SpringExamplejavac -version javac 1.5.0_08 javac: no source files

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  • Android AES and init vector

    - by Donald_W
    I have an issue with AES encryptio and decryption: I can change my IV entirely and still I'm able to decode my data. public static final byte[] IV = { 65, 1, 2, 23, 4, 5, 6, 7, 32, 21, 10, 11, 12, 13, 84, 45 }; public static final byte[] IV2 = { 65, 1, 2, 23, 45, 54, 61, 81, 32, 21, 10, 121, 12, 13, 84, 45 }; public static final byte[] KEY = { 0, 42, 2, 54, 4, 45, 6, 7, 65, 9, 54, 11, 12, 13, 60, 15 }; public static final byte[] KEY2 = { 0, 42, 2, 54, 43, 45, 16, 17, 65, 9, 54, 11, 12, 13, 60, 15 }; //public static final int BITS = 256; public static void test() { try { // encryption Cipher c = Cipher.getInstance("AES"); SecretKeySpec keySpec = new SecretKeySpec(KEY, "AES"); c.init(Cipher.ENCRYPT_MODE, keySpec, new IvParameterSpec(IV)); String s = "Secret message"; byte[] data = s.getBytes(); byte[] encrypted = c.doFinal(data); String encryptedStr = ""; for (int i = 0; i < encrypted.length; i++) encryptedStr += (char) encrypted[i]; //decryoption Cipher d_c = Cipher.getInstance("AES"); SecretKeySpec d_keySpec = new SecretKeySpec(KEY, "AES"); d_c.init(Cipher.DECRYPT_MODE, d_keySpec, new IvParameterSpec(IV2)); byte[] decrypted = d_c.doFinal(encrypted); String decryptedStr = ""; for (int i = 0; i < decrypted.length; i++) decryptedStr += (char) decrypted[i]; Log.d("", decryptedStr); } catch (Exception ex) { Log.d("", ex.getMessage()); } } Any ideas what I'm doing wrong? How can I get 256 bit AES encryption (only change key to 32-byte long array?) Encryption is a new topic for me so please for newbie friendly answers.

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  • CEIL is one too high for exact integer divisions

    - by Synetech
    This morning I lost a bunch of files, but because the volume they were one was both internally and externally defragmented, all of the information necessary for a 100% recovery is available; I just need to fill in the FAT where required. I wrote a program to do this and tested it on a copy of the FAT that I dumped to a file and it works perfectly except that for a few of the files (17 out of 526), the FAT chain is one single cluster too long, and thus cross-linked with the next file. Fortunately I know exactly what the problem is. I used ceil in my EOF calculation because even a single byte over will require a whole extra cluster: //Cluster is the starting cluster of the file //Size is the size (in bytes) of the file //BPC is the number of bytes per cluster //NumClust is the number of clusters in the file //EOF is the last cluster of the file’s FAT chain DWORD NumClust = ceil( (float)(Size / BPC) ) DWORD EOF = Cluster + NumClust; This algorithm works fine for everything except files whose size happens to be exactly a multiple of the cluster size, in which case they end up being one cluster too much. I thought about it for a while but am at a loss as to a way to do this. It seems like it should be simple but somehow it is surprisingly tricky. What formula would work for files of any size?

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  • Postgres error with Sinatra/Haml/DataMapper on Heroku

    - by sevennineteen
    I'm trying to move a simple Sinatra app over to Heroku. Migration of the Ruby app code and existing MySQL database using Taps went smoothly, but I'm getting the following Postgres error: PostgresError - ERROR: operator does not exist: text = integer LINE 1: ...d_at", "post_id" FROM "comments" WHERE ("post_id" IN (4, 17,... ^ HINT: No operator matches the given name and argument type(s). You might need to add explicit type casts. It's evident that the problem is related to a type mismatch in the query, but this is being issued from a Haml template by the DataMapper ORM at a very high level of abstraction, so I'm not sure how I'd go about controlling this... Specifically, this seems to be throwing up on a call of p.comments from my Haml template, where p represents a given post. The Datamapper models are related as follows: class Post property :id, Serial ... has n, :comments end class Comment property :id, Serial ... belongs_to :post end This works fine on my local and current hosted environment using MySQL, but Postgres is clearly more strict. There must be hundreds of Datamapper & Haml apps running on Postgres DBs, and this model relationship is super-conventional, so hopefully someone has seen (and determined how to fix) this. Thanks!

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  • DBD::Oracle and utf8 issue

    - by goe
    Hi All, I have a problem where my perl code using the latest DBD::Oracle on perl v5.8.8 throws an exception on me when I try to insert characters like 'ñ'. Exception: DBD::Oracle::db do failed: ORA-01756: quoted string not properly terminated (DBD ERROR: OCIStmtPrepare) My $ENV{NLS_LANG} is set to 'AMERICAN_AMERICA.AL32UTF8' These are the DB params based on "SELECT * from NLS_DATABASE_PARAMETERS" 1 NLS_LANGUAGE AMERICAN 2 NLS_TERRITORY AMERICA 3 NLS_CURRENCY $ 4 NLS_ISO_CURRENCY AMERICA 5 NLS_NUMERIC_CHARACTERS ., 6 NLS_CHARACTERSET AL32UTF8 7 NLS_CALENDAR GREGORIAN 8 NLS_DATE_FORMAT DD-MON-RR 9 NLS_DATE_LANGUAGE AMERICAN 10 NLS_SORT BINARY 11 NLS_TIME_FORMAT HH.MI.SSXFF AM 12 NLS_TIMESTAMP_FORMAT DD-MON-RR HH.MI.SSXFF AM 13 NLS_TIME_TZ_FORMAT HH.MI.SSXFF AM TZR 14 NLS_TIMESTAMP_TZ_FORMAT DD-MON-RR HH.MI.SSXFF AM TZR 15 NLS_DUAL_CURRENCY $ 16 NLS_COMP BINARY 17 NLS_LENGTH_SEMANTICS BYTE These are perl params based on "$db-ora_nls_parameters()" $VAR1 = { 'NLS_LANGUAGE' => 'AMERICAN', 'NLS_TIME_TZ_FORMAT' => 'HH.MI.SSXFF AM TZR', 'NLS_SORT' => 'BINARY', 'NLS_NUMERIC_CHARACTERS' => '.,', 'NLS_TIME_FORMAT' => 'HH.MI.SSXFF AM', 'NLS_ISO_CURRENCY' => 'AMERICA', 'NLS_COMP' => 'BINARY', 'NLS_CALENDAR' => 'GREGORIAN', 'NLS_DATE_FORMAT' => 'DD-MON-RR', 'NLS_DATE_LANGUAGE' => 'AMERICAN', 'NLS_TIMESTAMP_FORMAT' => 'DD-MON-RR HH.MI.SSXFF AM', 'NLS_TERRITORY' => 'AMERICA', 'NLS_LENGTH_SEMANTICS' => 'BYTE', 'NLS_NCHAR_CHARACTERSET' => 'AL16UTF16', 'NLS_DUAL_CURRENCY' => '$', 'NLS_TIMESTAMP_TZ_FORMAT' => 'DD-MON-RR HH.MI.SSXFF AM TZR', 'NLS_NCHAR_CONV_EXCP' => 'FALSE', 'NLS_CHARACTERSET' => 'AL32UTF8', 'NLS_CURRENCY' => '$' }; Here are some other strange facts: If I set NLS_LANG to ‘'AMERICAN_AMERICA.UTF8’ the insert executes fine with ‘ñ’ character. If I leave NLS_LANG as ‘'AMERICAN_AMERICA.AL32UTF8' but use ‘Ñ’ the insert will run fine as well.

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  • populate checkboxes with database.

    - by amby
    Hi, I have to poulate checkboxes with data coming from database but no checkbox is showing on my page. please give me correct way to do that. in C# file page_load method i m doing this: public partial class dbTest1 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { string Server = "al2222"; string Username = "hshshshsh"; string Password = "sjjssjs"; string Database = "database1"; string ConnectionString = "Data Source=" + Server + ";"; ConnectionString += "User ID=" + Username + ";"; ConnectionString += "Password=" + Password + ";"; ConnectionString += "Initial Catalog=" + Database; string query = "Select * from Customer_Order where orderNumber = 17"; using (SqlConnection conn = new SqlConnection(ConnectionString)) { using (SqlCommand cmd = new SqlCommand(query, conn)) { conn.Open(); SqlDataReader dr = cmd.ExecuteReader(); while (dr.Read()) { if (!IsPostBack) { Interests.DataSource = dr; Interests.DataTextField = "OptionName"; Interests.DataValueField = "OptionName"; Interests.DataBind(); } } conn.Close(); conn.Dispose(); } } } } and in .aspx using this: <asp:CheckBoxList ID="Interests" runat="server"></asp:CheckBoxList> please tell me correct way to do that.

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  • How to make placeholder varablies in jquery validate 1.7?

    - by chobo2
    Hi I am using jquery 1.4.2 and jquery validate 1.7(http://bassistance.de/jquery-plugins/jquery-plugin-validation/) Say I have this example that I just grabbed off some random site(http://www.webreference.com/programming/javascript/jquery/form_validation/) 8 <script type="text/javascript"> 9 $(document).ready(function() { 10 $("#form1").validate({ 11 rules: { 12 name: "required",// simple rule, converted to {required:true} 13 email: {// compound rule 14 required: true, 15 email: true 16 }, 17 url: { 18 url: true 19 }, 20 comment: { 21 required: true 22 } 23 }, 24 messages: { 25 comment: "Please enter a comment." 26 } 27 }); 28 }); 29 </script> now is it possible to do something like this 10 $("#form1").validate({ var NameHolder = "name" 11 rules: { 12 NameHolder: "required",// simple rule, converted to {required:true} 13 email: {// compound rule 14 required: true, 15 email: true So basically I want to make sort of a global variable to hold theses rule names( what correspond to the names on that html control). My concern is the names of html controls can change and it kinda sucks that I will have to go around and change it in many places of my code to make it work again. So basically I am wondering is there away to make a global variable to store this name. So if I need to change the name I only have to change it in one spot in my javascript file sort of the way stopping magic numbers ?

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  • Timer takes 10 ms more then interval

    - by Praveen
    Hi All, I am using a timer with interval 50 miliseconds. But in the timer's tick event when I print the time it's always 62 or 65 ms. I don't understand why it's taking 10 ms more. Please can some one have look into this. Here is the code I am using. static int _counter; System.Timers.Timer _timer = new System.Timers.Timer(1000); public Form1() { InitializeComponent(); _timer.Elapsed += new ElapsedEventHandler(_timer_Elapsed); _timer.Start(); } void _timer_Elapsed(object sender, ElapsedEventArgs e) { Console.WriteLine(DateTime.Now.ToString("{hh:mm:ss.fff}")); _counter++; if (_counter == 20) _timer.Stop(); } And this the output: {01:59:08.381} {01:59:09.393} {01:59:10.407} {01:59:11.421} {01:59:12.435} {01:59:13.449} {01:59:14.463} {01:59:15.477} {01:59:16.491} {01:59:17.505} {01:59:18.519} {01:59:19.533} {01:59:20.547} {01:59:21.561} {01:59:22.575} {01:59:23.589} {01:59:24.603} {01:59:25.615} {01:59:26.629} {01:59:27.643}

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  • Why does iOS 5 fail to connect to a server running JDK 1.6, but not JDK 1.5

    - by KC Baltz
    We have a Java Socket Server listening on an SSLSocket (port 443) and an iOS application that connects with it. When running on iOS 5.1, the application stopped working when we upgraded the Java version of the server from JDK 1.5 to 1.6 (or 1.7). The app connects just fine to JDK 5 and 6 when running on iOS 6. The iOS app is reporting an error: -9809 = errSSLCrypto. On the Java side, we get javax.net.ssl.SSLException: Received fatal alert: close_notify. On the Java server side, we have enabled all the available cipher suites. On the client side we have tested enabling several different suites, although we have yet to complete a test involving each one individually enabled. Right now, it is failing when we use TLS_DH_anon_WITH_AES_128_CBC_SHA although it has failed with others and we are starting to think it's not the suite. Here is the debug output. It makes it all the way to ServerHelloDone and then fails shortly thereafter: Is secure renegotiation: false [Raw read]: length = 5 0000: 16 03 03 00 41 ....A [Raw read]: length = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . URT-, READ: Unknown-3.3 Handshake, length = 65 *** ClientHello, Unknown-3.3 RandomCookie: GMT: 1333992971 bytes = { 86, 25, 37, 101, 200, 242, 175, 2, 173, 72, 254, 226, 146, 207, 184, 215, 166, 163, 234, 197, 255, 93, 116, 15, 27, 193, 153, 24 } Session ID: {} Cipher Suites: [TLS_EMPTY_RENEGOTIATION_INFO_SCSV, TLS_DH_anon_WITH_AES_128_CBC_SHA, SSL_DH_anon_WITH_3DES_EDE_CBC_SHA, SSL_DH_anon_WITH_RC4_128_MD5] Compression Methods: { 0 } Unsupported extension signature_algorithms, data: 00:06:05:01:04:01:02:01 *** [read] MD5 and SHA1 hashes: len = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . %% Created: [Session-1, TLS_DH_anon_WITH_AES_128_CBC_SHA] *** ServerHello, TLSv1 RandomCookie: GMT: 1333992972 bytes = { 100, 3, 56, 153, 7, 2, 251, 64, 41, 32, 66, 240, 227, 181, 55, 190, 2, 237, 146, 0, 73, 119, 70, 0, 160, 9, 28, 207 } Session ID: {80, 131, 30, 12, 241, 73, 52, 38, 46, 41, 237, 226, 199, 246, 156, 45, 3, 247, 182, 43, 223, 8, 49, 169, 188, 63, 160, 41, 102, 199, 50, 190} Cipher Suite: TLS_DH_anon_WITH_AES_128_CBC_SHA Compression Method: 0 Extension renegotiation_info, renegotiated_connection: <empty> *** Cipher suite: TLS_DH_anon_WITH_AES_128_CBC_SHA *** Diffie-Hellman ServerKeyExchange DH Modulus: { 233, 230, 66, 89, 157, 53, 95, 55, 201, 127, 253, 53, 103, 18, 11, 142, 37, 201, 205, 67, 233, 39, 179, 169, 103, 15, 190, 197, 216, 144, 20, 25, 34, 210, 195, 179, 173, 36, 128, 9, 55, 153, 134, 157, 30, 132, 106, 171, 73, 250, 176, 173, 38, 210, 206, 106, 34, 33, 157, 71, 11, 206, 125, 119, 125, 74, 33, 251, 233, 194, 112, 181, 127, 96, 112, 2, 243, 206, 248, 57, 54, 148, 207, 69, 238, 54, 136, 193, 26, 140, 86, 171, 18, 122, 61, 175 } DH Base: { 48, 71, 10, 213, 160, 5, 251, 20, 206, 45, 157, 205, 135, 227, 139, 199, 209, 177, 197, 250, 203, 174, 203, 233, 95, 25, 10, 167, 163, 29, 35, 196, 219, 188, 190, 6, 23, 69, 68, 64, 26, 91, 44, 2, 9, 101, 216, 194, 189, 33, 113, 211, 102, 132, 69, 119, 31, 116, 186, 8, 77, 32, 41, 216, 60, 28, 21, 133, 71, 243, 169, 241, 162, 113, 91, 226, 61, 81, 174, 77, 62, 90, 31, 106, 112, 100, 243, 22, 147, 58, 52, 109, 63, 82, 146, 82 } Server DH Public Key: { 8, 60, 59, 13, 224, 110, 32, 168, 116, 139, 246, 146, 15, 12, 216, 107, 82, 182, 140, 80, 193, 237, 159, 189, 87, 34, 18, 197, 181, 252, 26, 27, 94, 160, 188, 162, 30, 29, 165, 165, 68, 152, 11, 204, 251, 187, 14, 233, 239, 103, 134, 168, 181, 173, 206, 151, 197, 128, 65, 239, 233, 191, 29, 196, 93, 80, 217, 55, 81, 240, 101, 31, 119, 98, 188, 211, 52, 146, 168, 127, 127, 66, 63, 111, 198, 134, 70, 213, 31, 162, 146, 25, 178, 79, 56, 116 } Anonymous *** ServerHelloDone [write] MD5 and SHA1 hashes: len = 383 0000: 02 00 00 4D 03 01 50 83 1E 0C 64 03 38 99 07 02 ...M..P...d.8... 0010: FB 40 29 20 42 F0 E3 B5 37 BE 02 ED 92 00 49 77 .@) B...7.....Iw 0020: 46 00 A0 09 1C CF 20 50 83 1E 0C F1 49 34 26 2E F..... P....I4&. 0030: 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B DF 08 31 A9 BC ).....-...+..1.. 0040: 3F A0 29 66 C7 32 BE 00 34 00 00 05 FF 01 00 01 ?.)f.2..4....... 0050: 00 0C 00 01 26 00 60 E9 E6 42 59 9D 35 5F 37 C9 ....&.`..BY.5_7. 0060: 7F FD 35 67 12 0B 8E 25 C9 CD 43 E9 27 B3 A9 67 ..5g...%..C.'..g 0070: 0F BE C5 D8 90 14 19 22 D2 C3 B3 AD 24 80 09 37 ......."....$..7 0080: 99 86 9D 1E 84 6A AB 49 FA B0 AD 26 D2 CE 6A 22 .....j.I...&..j" 0090: 21 9D 47 0B CE 7D 77 7D 4A 21 FB E9 C2 70 B5 7F !.G...w.J!...p.. 00A0: 60 70 02 F3 CE F8 39 36 94 CF 45 EE 36 88 C1 1A `p....96..E.6... 00B0: 8C 56 AB 12 7A 3D AF 00 60 30 47 0A D5 A0 05 FB .V..z=..`0G..... 00C0: 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 C5 FA CB AE CB ..-............. 00D0: E9 5F 19 0A A7 A3 1D 23 C4 DB BC BE 06 17 45 44 ._.....#......ED 00E0: 40 1A 5B 2C 02 09 65 D8 C2 BD 21 71 D3 66 84 45 @.[,..e...!q.f.E 00F0: 77 1F 74 BA 08 4D 20 29 D8 3C 1C 15 85 47 F3 A9 w.t..M ).<...G.. 0100: F1 A2 71 5B E2 3D 51 AE 4D 3E 5A 1F 6A 70 64 F3 ..q[.=Q.M>Z.jpd. 0110: 16 93 3A 34 6D 3F 52 92 52 00 60 08 3C 3B 0D E0 ..:4m?R.R.`.<;.. 0120: 6E 20 A8 74 8B F6 92 0F 0C D8 6B 52 B6 8C 50 C1 n .t......kR..P. 0130: ED 9F BD 57 22 12 C5 B5 FC 1A 1B 5E A0 BC A2 1E ...W"......^.... 0140: 1D A5 A5 44 98 0B CC FB BB 0E E9 EF 67 86 A8 B5 ...D........g... 0150: AD CE 97 C5 80 41 EF E9 BF 1D C4 5D 50 D9 37 51 .....A.....]P.7Q 0160: F0 65 1F 77 62 BC D3 34 92 A8 7F 7F 42 3F 6F C6 .e.wb..4....B?o. 0170: 86 46 D5 1F A2 92 19 B2 4F 38 74 0E 00 00 00 .F......O8t.... URT-, WRITE: TLSv1 Handshake, length = 383 [Raw write]: length = 388 0000: 16 03 01 01 7F 02 00 00 4D 03 01 50 83 1E 0C 64 ........M..P...d 0010: 03 38 99 07 02 FB 40 29 20 42 F0 E3 B5 37 BE 02 .8....@) B...7.. 0020: ED 92 00 49 77 46 00 A0 09 1C CF 20 50 83 1E 0C ...IwF..... P... 0030: F1 49 34 26 2E 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B .I4&.).....-...+ 0040: DF 08 31 A9 BC 3F A0 29 66 C7 32 BE 00 34 00 00 ..1..?.)f.2..4.. 0050: 05 FF 01 00 01 00 0C 00 01 26 00 60 E9 E6 42 59 .........&.`..BY 0060: 9D 35 5F 37 C9 7F FD 35 67 12 0B 8E 25 C9 CD 43 .5_7...5g...%..C 0070: E9 27 B3 A9 67 0F BE C5 D8 90 14 19 22 D2 C3 B3 .'..g......."... 0080: AD 24 80 09 37 99 86 9D 1E 84 6A AB 49 FA B0 AD .$..7.....j.I... 0090: 26 D2 CE 6A 22 21 9D 47 0B CE 7D 77 7D 4A 21 FB &..j"!.G...w.J!. 00A0: E9 C2 70 B5 7F 60 70 02 F3 CE F8 39 36 94 CF 45 ..p..`p....96..E 00B0: EE 36 88 C1 1A 8C 56 AB 12 7A 3D AF 00 60 30 47 .6....V..z=..`0G 00C0: 0A D5 A0 05 FB 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 .......-........ 00D0: C5 FA CB AE CB E9 5F 19 0A A7 A3 1D 23 C4 DB BC ......_.....#... 00E0: BE 06 17 45 44 40 1A 5B 2C 02 09 65 D8 C2 BD 21 ...ED@.[,..e...! 00F0: 71 D3 66 84 45 77 1F 74 BA 08 4D 20 29 D8 3C 1C q.f.Ew.t..M ).<. 0100: 15 85 47 F3 A9 F1 A2 71 5B E2 3D 51 AE 4D 3E 5A ..G....q[.=Q.M>Z 0110: 1F 6A 70 64 F3 16 93 3A 34 6D 3F 52 92 52 00 60 .jpd...:4m?R.R.` 0120: 08 3C 3B 0D E0 6E 20 A8 74 8B F6 92 0F 0C D8 6B .<;..n .t......k 0130: 52 B6 8C 50 C1 ED 9F BD 57 22 12 C5 B5 FC 1A 1B R..P....W"...... 0140: 5E A0 BC A2 1E 1D A5 A5 44 98 0B CC FB BB 0E E9 ^.......D....... 0150: EF 67 86 A8 B5 AD CE 97 C5 80 41 EF E9 BF 1D C4 .g........A..... 0160: 5D 50 D9 37 51 F0 65 1F 77 62 BC D3 34 92 A8 7F ]P.7Q.e.wb..4... 0170: 7F 42 3F 6F C6 86 46 D5 1F A2 92 19 B2 4F 38 74 .B?o..F......O8t 0180: 0E 00 00 00 .... [Raw read]: length = 5 0000: 15 03 01 00 02 ..... [Raw read]: length = 2 0000: 02 00 .. URT-, READ: TLSv1 Alert, length = 2 URT-, RECV TLSv1 ALERT: fatal, close_notify URT-, called closeSocket() URT-, handling exception: javax.net.ssl.SSLException: Received fatal alert: close_notify FYI, this works in iOS 6.0

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  • Project Euler, Problem 10 java solution not working

    - by Dennis S
    Hi, I'm trying to find the sum of the prime numbers < 2'000'000. This is my solution in java but I can't seem get the correct answer. Please give some input on what could be wrong and general advice on the code is appreciated. Printing 'sum' gives: 1308111344, which is incorrect. /* The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. */ class Helper{ public void run(){ Integer sum = 0; for(int i = 2; i < 2000000; i++){ if(isPrime(i)) sum += i; } System.out.println(sum); } private boolean isPrime(int nr){ if(nr == 2) return true; else if(nr == 1) return false; if(nr % 2 == 0) return false; for(int i = 3; i < Math.sqrt(nr); i += 2){ if(nr % i == 0) return false; } return true; } } class Problem{ public static void main(String[] args){ Helper p = new Helper(); p.run(); } }

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  • How to modify a xml file using PHP? use a node to retrieve the value of new child nodes and add them

    - by Avinash Sonee
    I have pasted the example of what I need here : http://pastie.org/1005178 I have a xml file with say the following info <state> <info> <name>hello</name> <zip>51678</zip> </info> <info> <name>world</name> <zip>54678</zip> </info> </state> Now I need to create a new xml file which has the following <state> <info> <name>hello</name> <zip>51678</zip> <lat>17.89</lat> <lon>78.90</lon> </info> <info> <name>world</name> <zip>54678</zip> <lat>16.89</lat> <lon>83.45</lon> </info> </state> So, basically I need to add lat and lon nodes to each info element. these lat and lon correspond to the zip code which are stored in a mysql file which contains 3 fields - pin, lat and lon How do i do this recursively. I have say 1000 info elements in a file Please give me a sample code because I have already tried using simplexml and read the documentation but doesn't see to understand it properly

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  • Browser freezes when try to call a JS function along with submission of a form.

    - by Waseem
    I have form in my view like following 1 <div> 2 <% form_tag facebook_user_path do %> 3 <label>Use my photo and name from facebook?</label><br /> 4 <%= check_box_tag 'use_name_and_photo', 'yes', true %> 5 <img src="<%= @user.pic %>" /><% @user.name %> 6 7 <%= submit_tag "Finish", :id => "use_name_and_photo_submit" %> 8 <% end %> 9 </div> I have attached some JS handlers using Jquery to this form. 1 var fb = { 2 extendedPermissions: function () { 3 $("#use_name_and_photo_submit").click(function (event) { 4 FB.Connect.showPermissionDialog("email,read_stream,publish_stream", function (perms) { 5 if (!perms) { 6 alert("You have to grant facebook extended permissions to further browse the application."); 7 } else { 8 $("form").submit(function () { 9 $.post($(this).attr("action"), $(this).serialize(), null, "script"); 10 }); 11 } 12 }); 13 event.preventDefault(); 14 return false; 15 }); 16 } 17 }; 18 19 $(document).ready(function () { 20 fb.extendedPermissions(); 21 }); What I want is that when the user clicks on the "Finish" button, he is prompted for the facebook permissions dialogue and when he gives the permissions, the form is submitted to FacebookUsersController. Right now when I click the "Finish" button, facebook permissions dialogue is initiated but before I am prompted for the actual permission submission window, the browser freezes. Just like I have pressed Esc during the process. In fact status bar of the browser says "Stopped". Any help is highly appreciated.

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  • Core Data: migrating entities with self-referential properties

    - by Dan
    My Core Data model contains an entity, Shape, that has two self-referential relationships, which means four properties. One pair is a one-to-many relationship (Shape.containedBy <- Shape.contains) and the another is a many-to-many relationship (Shape.nextShapes <<- Shape.previousShapes). It all works perfectly in the application, so I don't think self-referencing relationships is a problem in general. However, when it comes to migrating the model to a new version, then Xcode fails to compile the automatically generated mapping model, with this error message: 2009-10-30 17:10:09.387 mapc[18619:607] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Unable to parse the format string "FUNCTION($manager ,'destinationInstancesForSourceRelationshipNamed:sourceInstances:' , 'contains' , $source.contains) == 1"' *** Call stack at first throw: ( 0 CoreFoundation 0x00007fff80d735a4 __exceptionPreprocess + 180 1 libobjc.A.dylib 0x00007fff83f0a313 objc_exception_throw + 45 2 Foundation 0x00007fff819bc8d4 _qfqp2_performParsing + 8412 3 Foundation 0x00007fff819ba79d +[NSPredicate predicateWithFormat:arguments:] + 59 4 Foundation 0x00007fff81a482ef +[NSExpression expressionWithFormat:arguments:] + 68 5 Foundation 0x00007fff81a48843 +[NSExpression expressionWithFormat:] + 155 6 XDBase 0x0000000100038e94 -[XDDevRelationshipMapping valueExpressionAsString] + 260 7 XDBase 0x000000010003ae5c -[XDMappingCompilerSupport generateCompileResultForMappingModel:] + 2828 8 XDBase 0x000000010003b135 -[XDMappingCompilerSupport compileSourcePath:options:] + 309 9 mapc 0x0000000100001a1c 0x0 + 4294973980 10 mapc 0x0000000100001794 0x0 + 4294973332 ) terminate called after throwing an instance of 'NSException' Command /Developer/usr/bin/mapc failed with exit code 6 The 'contains' is the name of one of the self-referential properties. Anyway, the really big problem is that I can't even look at this Mapping Property as Xcode crashes as soon as I select the entity mapping when viewing the mapping model. So I'm a bit lost really where to go from here. I really can't remove the self-referential properties, so I'm thinking I've got manually create a mapping model that compiles? Any ideas? Cheers

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  • Differences between Assembly Code output of the same program

    - by ultrajohn
    I have been trying to replicate the buffer overflow example3 from this article aleph one I'm doing this as a practice for a project in a computer security course i'm taking so please, I badly need your help. I've been the following the example, performing the tasks as I go along. My problem is the assembly code dumped by gdb in my computer (i'm doing this on a debian linux image running on VM Ware) is different from that of the example in the article. There are some constructs which I find confusing. Here is the one from my computer: here is the one from the article... Dump of assembler code for function main: 0x8000490 <main>: pushl %ebp 0x8000491 <main+1>: movl %esp,%ebp 0x8000493 <main+3>: subl $0x4,%esp 0x8000496 <main+6>: movl $0x0,0xfffffffc(%ebp) 0x800049d <main+13>: pushl $0x3 0x800049f <main+15>: pushl $0x2 0x80004a1 <main+17>: pushl $0x1 0x80004a3 <main+19>: call 0x8000470 <function> 0x80004a8 <main+24>: addl $0xc,%esp 0x80004ab <main+27>: movl $0x1,0xfffffffc(%ebp) 0x80004b2 <main+34>: movl 0xfffffffc(%ebp),%eax 0x80004b5 <main+37>: pushl %eax 0x80004b6 <main+38>: pushl $0x80004f8 0x80004bb <main+43>: call 0x8000378 <printf> 0x80004c0 <main+48>: addl $0x8,%esp 0x80004c3 <main+51>: movl %ebp,%esp 0x80004c5 <main+53>: popl %ebp 0x80004c6 <main+54>: ret 0x80004c7 <main+55>: nop As you can see, there are differences between the two. I'm confuse and I can't understand totally the assembly code from my computer. I would like to know the differences between the two. How is pushl different from push, mov vs movl , and so on... what does the expression 0xhexavalue(%register) means? I am sorry If I'm asking a lot, But I badly need your help. Thanks for the help really...

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  • How can I define a verb in J that applies a different verb alternately to each atom in a list?

    - by Gregory Higley
    Imagine I've defined the following name in J: m =: >: i. 2 4 5 This looks like the following: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 I want to create a monadic verb of rank 1 that applies to each list in this list of lists. It will double (+:) or add 1 (>:) to each alternate item in the list. If we were to apply this verb to the first row, we'd get 2 3 6 5 10. It's fairly easy to get a list of booleans which alternate with each item, e.g., 0 1 $~{:$ m gives us 0 1 0 1 0. I thought, aha! I'll use something like +:`>: @. followed by some expression, but I could never quite get it to work. Any suggestions? UPDATE The following appears to work, but perhaps it can be refactored into something more elegant by a J pro. poop =: monad define (($ y) $ 0 1 $~{:$ y) ((]+:)`(]:) @. [)"0 y )

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  • Re-order list in Python to ensure it starts with check values.

    - by S_Swede
    Dear all, I'm reading in serial data using Pyserial, to populate a list of 17 values (1byte each) at a sampling rate of 256Hz. The bytes I ultimately want to use are the 5th to 8th in the list. Providing no bytes are dropped, the first two values of the stream are always the same ('165','90'). I'm getting quite a few dropped values though, and my list values are shifting, so when I read the 5th-8th bytes, they aren't the correct values. I've partially combatted this by ensuring that before the wanted segement is captured, the first few values are checked against what they should be (i.e. if mylist[0]==165 &....). This is crude but ok since the chances of these two values appearing adjacent to each other in the list elsewhere is small. The problem is that this means as soon as the bytes shift, I'm losing a load of values, until it eventually realigns. My question is: what code can I use to either: a) Force the list to realign once it has been detected that it no longer starts with 165,90. (elif....). b) Detect where '165' & '90' are (next to each other) in the list and extract the values I want in relation to their position (next but one, onwards). Thanks in advance S_S Just noticed from the related Qs that I could use mylist.append(mylist.pop(0)) multiple times until they are in the right place. Is there a better way that anyone can suggest?

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  • Question about memory allocation when initializing char arrays in C/C++.

    - by Carlos Nunez
    Before anything, I apologize if this question has been asked before. I am programming a simple packet sniffer for a class project. For a little while, I ran into the issue where the source and destination of a packet appeared to be the same. For example, the source and destination of an Ethernet frame would be the same MAC address all of the time. I custom-made ether_ntoa(char *) because Windows does not seem to have ethernet.h like Linux does. Code snippet is below: char *ether_ntoa(u_char etheraddr[ETHER_ADDR_LEN]) { int i, j; char eout[32]; for(i = 0, j = 0; i < 5; i++) { eout[j++] = etheraddr[i] >> 4; eout[j++] = etheraddr[i] & 0xF; eout[j++] = ':'; } eout[j++] = etheraddr[i] >> 4; eout[j++] = etheraddr[i] & 0xF; eout[j++] = '\0'; for(i = 0; i < 17; i++) { if(eout[i] < 10) eout[i] += 0x30; else if(eout[i] < 16) eout[i] += 0x57; } return(eout); } I solved the problem by using malloc() to have the compiler assign memory (i.e. instead of char eout[32], I used char * eout; eout = (char *) malloc (32);). However, I thought that the compiler assigned different memory locations when one sized a char-array at compile time. Is this incorrect? Thanks! Carlos Nunez

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  • I need to Loop an a formula with the Offset function until the cell is blank

    - by CEMG
    I need to Loop the formula below until Column "B" which contains dates is empty. I am stuck and I just can't seem to write the VBA Code to do the Loop until there is no more Dates in Column "B". The formula is smoothing out the yields by using those dates that have a yield. I hope anyone would be able to help me. Thanks in advance A B C D 5 Factor Date Yield Input 6 3 May-10 .25 7 1 Jun-10 8 2 Jul-10 9 3 Aug-10 0.2000 10 1 Sep-10 11 2 Oct-10 12 3 Nov-10 0.2418 13 1 Dec-10 14 2 Jan-11 15 3 Feb-11 0.3156 16 1 Mar-11 17 2 Apr-11 . Sub IsNumeric() 'IF(ISNUMBER(C6),C6, If Application.IsNumber(range("c6").Value) Then range("d6").Value = range("c6") 'IF(C6<C5,((OFFSET(C6,2,0)-OFFSET(C6,-1,0))*A6/3+OFFSET(C6,-1,0)), If range("c6").Select < range("c5").Select Then range("d6").Value = range("c6").Offset(2, 0).Select - range("c6").Offset(-1, 0).Select * (range("a6").Select / 3) + range("c6").Offset(-1, 0).Select 'IF(C6<>C7,((OFFSET(C6,1,0)-OFFSET(C6,-2,0))*(A6/3)+OFFSET(C6,-2,0)),""))) If range("c6").Select <> range("c7").Select Then range("d6").Value = (range("c6").Offset(1, 0).Select) - range("c6").Offset(-2, 0).Select * (range("a6").Select / 3) + range("c6").Offset(-2, 0).Select Else range("d6").Value = "" End If End If End If End Sub

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  • What are the attributes that are need to Send with this FEDEX shipping script?

    - by Fero
    could any one please tell me what are the attributes that are send with $ship_data ? I am too confused about it. I know that ORIGIN ADDRESS, DESTINATION ADDRESS, NAME etc.. need to be send. But how the data should be aligned. Like name is FIRST, address is SECOND etc... Any help will be useful ** // create new fedex object $fed = new FedExDC('#########','#########'); $ship_data = array( 75= 'LBS', 16= 'Ma' , 13= '44 Main street' , 5= '312 stuart st', 1273= '01', 1274= '01', 18= '6173335555', 15= 'Boston', 23= '1', 9= '02134', 183= '6175556985', 8= 'MA', 117= 'US', 17= '02116', 50= 'US', 4= 'Vermonster LLC', 7= 'Boston', 1369= '1', 12= 'Jay Powers', 1333= '1', 1401= '1.0', 116= 1, 68= 'USD', 1368= 1, 1369= 1, 1370= 5 ); // Ship example $ship_Ret = $fed-ship_express($ship_data); if ($error = $fed-getError()) { echo "ERROR :". $error; } else { // Save the label to disk $fed-label('mylabel.png'); } /* tracking example $track_Ret = $fed-track( array( 29 = 790344664540, )); echo $fed-debug_str. "\n"; echo "Price ".$ship_Ret[1419];*/ echo ""; if ($error = $fed-getError()) { die("ERROR: ". $error); } else { // decode and save label $fed-label('myLabel.png'); echo $fed-debug_str. "\n"; echo "\n\n"; echo "Price $".$ship_Ret[1419]; echo "\n"; echo "Tracking# ".$ship_Ret[29]; } echo ""; ?** Thanks Fero

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