How to grep 2 or 3 lines, one containing the text I want, and the others just below it?
- by Kaustubh P
This is a snapshot of error log:
06:16:29,933 ERROR EmailRMManager$:45 - Exception In get Message
com.rabbitmq.client.AlreadyClosedException: clean connection shutdown; reason: Attempt to use closed channel
at com.rabbitmq.client.impl.AMQChannel.ensureIsOpen(AMQChannel.java:195)
at com.rabbitmq.client.impl.AMQChannel.rpc(AMQChannel.java:222)
at com.rabbitmq.client.impl.AMQChannel.rpc(AMQChannel.java:208)
at com.rabbitmq.client.impl.AMQChannel.exnWrappingRpc(AMQChannel.java:139)
at com.rabbitmq.client.impl.ChannelN.basicGet(ChannelN.java:645)
I do the following command:
cat foo.log | grep ERROR to get an OP as:
06:16:29,933 ERROR EmailRMManager$:45 - Exception In get Message
What command should I execute to get the output as
06:16:29,933 ERROR EmailRMManager$:45 - Exception In get Message
com.rabbitmq.client.AlreadyClosedException: clean connection shutdown; reason: Attempt to use closed channel
ie, also grep the line(s) after the pattern?