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  • Javacing code in terminal havivng a Jar in CLASSPATH

    - by Masi
    How can you javac the code in terminal by using google-collections in CLASSPATH? Example of code trying to javac in terminal (works in Eclipse) import com.google.common.collect.BiMap; import com.google.common.collect.HashBiMap; public class Locate { ... BiMap<MyFile, Integer> rankingToResult = HashBiMap.create(); ... } Javacing in terminaling src 288 % javac Locate.java Locate.java:14: package com.google.common.collect does not exist import com.google.common.collect.BiMap; ^ Locate.java:15: package com.google.common.collect does not exist import com.google.common.collect.HashBiMap; ^ Locate.java:153: cannot find symbol symbol : class BiMap location: class Locate BiMap<MyFile, Integer> rankingToResult = HashBiMap.create(); ^ Locate.java:153: cannot find symbol symbol : variable HashBiMap location: class Locate BiMap<MyFile, Integer> rankingToResult = HashBiMap.create(); ^ 4 errors My CLASSPATH src 289 % echo $CLASSPATH /u/1/bin/javaLibraries/google-collect-1.0.jar

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  • .jar why it works only with specigic jdk version???

    - by sadiq
    Hi friends, I have website source code...in which there is a adito.jar file first i extract it ...then make again jar using "jar -cvf adito.jar . and the changed jar file work fine again with that website. above process is only work when i use jdk1.6.0_14 only... BUT..... if i use jdk1.5 or letest jdk1.6.0_18 the same thing is not work..i mean that jar file will not run in my website... So what is the possible reason of this..as i am new kid in java... thanking you, sadiq.

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  • Unable to load directory when using jar [on hold]

    - by user1630359
    I've a directory in my eclipse project, in build path which contains files (txt). Now, when i run the application from eclipse, i can read the files (using #1 below). but, when i export my application to jar and run it from other pc i can't read the files or even check whether the directory exist or not. All the below lines are always return NULL! 1. File dir = new File("files"); 2. File dir = this.getClass().getResourceAsStream("files"); 3. File dir = this.getClass().getClassLoader().getResource("files"); any assistance will be appreciated! Thanks!

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  • LINQ 4 XML - What is the proper way to query deep in the tree structure?

    - by Keith Barrows
    I have an XML structure that is 4 deep: <?xml version="1.0" encoding="utf-8"?> <EmailRuleList xmlns:xsd="EmailRules.xsd"> <TargetPST name="Tech Communities"> <Parse emailAsList="true" useJustDomain="false" fromAddress="false" toAddress="true"> <EmailRule address="@aspadvice.com" folder="Lists, ASP" saveAttachments="false" /> <EmailRule address="@sqladvice.com" folder="Lists, SQL" saveAttachments="false" /> <EmailRule address="@xmladvice.com" folder="Lists, XML" saveAttachments="false" /> </Parse> <Parse emailAsList="false" useJustDomain="false" fromAddress="false" toAddress="true"> <EmailRule address="[email protected]" folder="Special Interest Groups|Northern Colorado Architects Group" saveAttachments="false" /> <EmailRule address="[email protected]" folder="Support|SpamBayes" saveAttachments="false" /> </Parse> <Parse emailAsList="false" useJustDomain="false" fromAddress="true" toAddress="false"> <EmailRule address="[email protected]" folder="Support|GoDaddy" saveAttachments="false" /> <EmailRule address="[email protected]" folder="Support|No-IP.com" saveAttachments="false" /> <EmailRule address="[email protected]" folder="Discussions|Orchard Project" saveAttachments="false" /> </Parse> <Parse emailAsList="false" useJustDomain="true" fromAddress="true" toAddress="false"> <EmailRule address="@agilejournal.com" folder="Newsletters|Agile Journal" saveAttachments="false"/> <EmailRule address="@axosoft.ccsend.com" folder="Newsletters|Axosoft Newsletter" saveAttachments="false"/> <EmailRule address="@axosoft.com" folder="Newsletters|Axosoft Newsletter" saveAttachments="false"/> <EmailRule address="@cmcrossroads.com" folder="Newsletters|CM Crossroads" saveAttachments="false" /> <EmailRule address="@urbancode.com" folder="Newsletters|Urbancode" saveAttachments="false" /> <EmailRule address="@urbancode.ccsend.com" folder="Newsletters|Urbancode" saveAttachments="false" /> <EmailRule address="@Infragistics.com" folder="Newsletters|Infragistics" saveAttachments="false" /> <EmailRule address="@zdnet.online.com" folder="Newsletters|ZDNet Tech Update Today" saveAttachments="false" /> <EmailRule address="@sqlservercentral.com" folder="Newsletters|SQLServerCentral.com" saveAttachments="false" /> <EmailRule address="@simple-talk.com" folder="Newsletters|Simple-Talk Newsletter" saveAttachments="false" /> </Parse> </TargetPST> <TargetPST name="[Sharpen the Saw]"> <Parse emailAsList="false" useJustDomain="false" fromAddress="false" toAddress="true"> <EmailRule address="[email protected]" folder="Head Geek|Job Alerts" saveAttachments="false" /> <EmailRule address="[email protected]" folder="Social|LinkedIn USMC" saveAttachments="false"/> </Parse> <Parse emailAsList="false" useJustDomain="false" fromAddress="true" toAddress="false"> <EmailRule address="[email protected]" folder="Head Geek|Job Alerts" saveAttachments="false" /> <EmailRule address="[email protected]" folder="Head Geek|Job Alerts" saveAttachments="false" /> <EmailRule address="[email protected]" folder="Social|Cruise Critic" saveAttachments="false"/> </Parse> <Parse emailAsList="false" useJustDomain="true" fromAddress="true" toAddress="false"> <EmailRule address="@moody.edu" folder="Social|5 Love Languages" saveAttachments="false" /> <EmailRule address="@postmaster.twitter.com" folder="Social|Twitter" saveAttachments="false"/> <EmailRule address="@diabetes.org" folder="Physical|American Diabetes Association" saveAttachments="false"/> <EmailRule address="@membership.webshots.com" folder="Social|Webshots" saveAttachments="false"/> </Parse> </TargetPST> </EmailRuleList> Now, I have both an FromAddress and a ToAddress that is parsed from an incoming email. I would like to do a LINQ query against a class set that was deserialized from this XML. For instance: ToAddress = [email protected] FromAddress = [email protected] Query: Get EmailRule.Include(Parse).Include(TargetPST) where address == ToAddress AND Parse.ToAddress==true AND Parse.useJustDomain==false Get EmailRule.Include(Parse).Include(TargetPST) where address == [ToAddress Domain Only] AND Parse.ToAddress==true AND Parse.useJustDomain==true Get EmailRule.Include(Parse).Include(TargetPST) where address == FromAddress AND Parse.FromAddress==true AND Parse.useJustDomain==false Get EmailRule.Include(Parse).Include(TargetPST) where address == [FromAddress Domain Only] AND Parse.FromAddress==true AND Parse.useJustDomain==true I am having a hard time figuring this LINQ query out. I can, of course, loop on all the bits in the XML like so (includes deserialization into objects): XmlSerializer s = new XmlSerializer(typeof(EmailRuleList)); TextReader r = new StreamReader(path); _emailRuleList = (EmailRuleList)s.Deserialize(r); TargetPST[] PSTList = _emailRuleList.Items; foreach (TargetPST targetPST in PSTList) { olRoot = GetRootFolder(targetPST.name); if (olRoot != null) { Parse[] ParseList = targetPST.Items; foreach (Parse parseRules in ParseList) { EmailRule[] EmailRuleList = parseRules.Items; foreach (EmailRule targetFolders in EmailRuleList) { } } } } However, this means going through all these loops for each and every address. It makes more sense to me to query against the Objects. Any tips appreciated!

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  • B2B communication using IBM MQ

    - by Dheeraj Kumar M
    Oracle B2B 11g, provides the out-of-the box ability to connect to IBM MQ to exchange the message. This is support is provided via JMS offering of Oracle B2B. This is an addition to the stack of existing communication capabilities of B2B with trading partners. There are 2 ways of connecting to IBM MQ using B2B 1. Credential based connectivity 2. .bindings based connectivity As a pre-requisite to connect to IBM MQ, it is required to provide the following libraries in classpath: a. com.ibm.mqjms.jar b. dhbcore.jar c. com.ibm.mq.jar d. com.ibm.mq.jmqi.jar e. mqcontext.jar f. com.ibm.mq.pcf.jar g. com.ibm.mq.commonservices.jar h. com.ibm.mq.headers.jar i. fscontext.jar j. jms.jar Add the above jars into domain library directory and the directory usually located at $DOMAIN_DIR/lib. The jars located in this($DOMAIN_DIR/lib) directory will be picked up and added dynamically to the end of the server classpath at server startup. For eg. /user_projects/domains//lib/ Alternatively the above jar’s can also be added as part of the setDomainEnv.sh Credential based connectivity : Outbound: : Configure the trading partner delivery channel for using "Generic JMS" protocol Inbound: : Configure the internal delivery channel for using "Generic JMS" protocol with the following details: Parameter NameDescription Destination NameMQ Queue Name Connection FactoryMQ Queue Manager Name Destination Providerjava.naming.factory.initial=com.ibm.mq.jms.context.WMQInitialContextFactory;java.naming.provider.url=<host>:<QM Listen port>/<MQ Channel Name>; User NameMQ User Name passwordMQ password .bindings based connectivity As a pre-requisite, get/generate the .bindings file in MQServer. This can be done by MQ Administrator Set the following values in the respective delivery channel for outbound / inbound Parameter NameDescription Destination NameMQ Queue Name Connection FactoryMQ Queue Manager Name Destination Providerjava.naming.factory.initial=com.ibm.mq.jms.context.WMQInitialContextFactory;java.naming.provider.url=file:///<location of .bindings file>;

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  • How do i modify the XSL to change the xml format.

    - by user323719
    In the below XSL. <xsl:param name="insert-file" as="document-node()" /> <xsl:template match="*"> <xsl:variable name="input">My text</xsl:variable> <xsl:variable name="Myxml" as="element()*"> <xsl:call-template name="populateTag"> <xsl:with-param name="nodeValue" select="$input"/> </xsl:call-template> </xsl:variable> <xsl:copy-of select="$Myxml"></xsl:copy-of> </xsl:template> <xsl:template name="populateTag"> <xsl:param name="nodeValue"/> <xsl:for-each select="$insert-file/insert-data/data"> <xsl:choose> <xsl:when test="@index = 1"> <a><xsl:value-of select="$nodeValue"></xsl:value-of></a> </xsl:when> </xsl:choose> </xsl:for-each> </xsl:template> I am getting the output as: <?xml version="1.0" encoding="UTF-8"? <aMy text</a <aMy text</a <aMy text</a <aMy text</a I want template "populateTag" to retun me the xml in the below format. How do i modify the template "populateTag" to achive the same. Expected output from template "populateTag": <?xml version="1.0" encoding="UTF-8"? <a<a<a<aMy text</a</a</a</a Please give your ideas.

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  • How to deserialize "<MyType><StartDate>01/01/2000</StartDate></MyType>"

    - by afin
    How to deserialize "<MyType><StartDate>01/01/2000</StartDate></MyType>" below is the MyType definition [Serializable] public class MyType { DateTime _StartDate; public DateTime StartDate { set { _StartDate = value; } get { return _StartDate; } } } Got the following error while deserializing {"The string '01/01/2000' is not a valid AllXsd value."} [System.FormatException]: {"The string '01/01/2000' is not a valid AllXsd value."} Data: {System.Collections.ListDictionaryInternal} HelpLink: null InnerException: null Message: "The string '01/01/2000' is not a valid AllXsd value." Source: "System.Xml" StackTrace: " at System.Xml.Schema.XsdDateTime..ctor(String text, XsdDateTimeFlags kinds)\r\n at System.Xml.XmlConvert.ToDateTime(String s, XmlDateTimeSerializationMode dateTimeOption)\r\n at System.Xml.Serialization.XmlCustomFormatter.ToDateTime(String value)\r\n at System.Xml.Serialization.XmlSerializationReader.ToDateTime(String value)\r\n at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderMyType.Read2_MyType(Boolean isNullable, Boolean checkType)\r\n at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderMyType.Read3_MyType()" TargetSite: {Void .ctor(System.String, System.Xml.Schema.XsdDateTimeFlags)}

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  • Can I use a plaintext diff algorithm for tracking XML changes?

    - by rinogo
    Hi all! Interesting question for you here. I'm working in Flex/AS3 on (for simplicity) an XML editor. I need to provide undo/redo functionality. Of course, one solution is to store the entire source text with each edit. However, to conserve memory, I'd like to store the diffs instead (these diffs will also be used to transmit updates to the server for auto-saving). My question is - can I use a plaintext diff algorithm for tracking these XML changes? My research on the internet indicates that I cannot do so. However, I'm obviously missing something. Plaintext diff provides functionality that is purportedly: diff(text, text') - diffs patch(text, diffs) - text' XML is simply text, so why can't I just use diff() and patch() to transform the text reliably? For example: Let's say that I'm a poet. When I write poetry, I use lots of funky punctuation... You know, like <, /, and . (You might see where I'm going with this...) If I'm writing my poetry in an application that uses diffs to provide undo/redo functionality, does my poetry become garbled when I undo/redo my edits? It's just text! Why does it make a difference to the algorithm? I obviously don't get something here...Thanks for explaining! :) -Rich

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  • What is the fastest way to pull a few element values out of XML files in Perl?

    - by Anon Guy
    I have a bunch of XML files that are about 1-2 megabytes in size. Actually, more than a bunch, there are millions. They're all well-formed and many are even validated against their schema (confirmed with libxml2). All were created by the same app, so they're in a consistent format (though this could theoretically change in the future). I want to check the values of one element in each file from within a Perl script. Speed is important (I'd like to take less than a second per file) and as noted I already know the files are well-formed. I am sorely tempted to simply 'open' the files in Perl and scan through until I see the element I am looking for, grab the value (which is near the start of the file), and close the file. On the other hand, I could use an XML parser (which might protect me from future changes to the XML formatting) but I suspect it will be slower than I'd like. Can anyone recommend an appropriate approach and/or parser? Thanks in advance.

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  • Flash gets XML but the values are wrong, as3

    - by VideoDnd
    Flash receives the XML, but the values are wrong. How do I fix this? Problem I can see the XML loaded with no errors, but my output is way off. It's as though it's not receiving any values. Numbers in the output window and animation move rapidly. The Flash file runs as if it's variables where set to zero. I changed the order of my code, but that didn't help with this. Please explain how I can correct this. SWF //load xml var myXML:XML; var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("xml.xml")); myLoader.addEventListener(Event.COMPLETE, processXML); //parse XML function processXML(e:Event):void { myXML = new XML(e.target.data); trace(myXML); //receive values from XML delay = parseInt(myXML.DELAY.text()); trace(delay); repeat = parseInt(myXML.REPEAT.text()); trace(repeat); } //variables var delay:uint = 0; var repeat:uint = 0; //timer and event var timer:Timer = new Timer(uint(delay),uint(repeat)); timer.addEventListener(TimerEvent.TIMER, countdown); //counter function countdown(event:TimerEvent) { myText.text = String(0 + timer.currentCount); trace(0 + timer.currentCount); } timer.start(); XML <?xml version="1.0" encoding="utf-8"?> <SESSION> <DELAY TITLE="starting position">1000</DELAY> <REPEAT TITLE="starting position">60</REPEAT> </SESSION>

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  • How to publish multiple jar files to maven on a clean install

    - by Abhijit Hukkeri
    I have a used the maven assembly plugin to create multiple jar from one jar now the problem is that I have to publish these jar to the local repo, just like other maven jars publish by them self when they are built maven clean install how will I be able to do this here is my pom file <project> <parent> <groupId>parent.common.bundles</groupId> <version>1.0</version> <artifactId>child-bundle</artifactId> </parent> <modelVersion>4.0.0</modelVersion> <groupId>common.dataobject</groupId> <artifactId>common-dataobject</artifactId> <packaging>jar</packaging> <name>common-dataobject</name> <version>1.0</version> <dependencies> </dependencies> <build> <plugins> <plugin> <groupId>org.jibx</groupId> <artifactId>maven-jibx-plugin</artifactId> <version>1.2.1</version> <configuration> <directory>src/main/resources/jibx_mapping</directory> <includes> <includes>binding.xml</includes> </includes> <verbose>false</verbose> </configuration> <executions> <execution> <goals> <goal>bind</goal> </goals> </execution> </executions> </plugin> <plugin> <artifactId>maven-assembly-plugin</artifactId> <executions> <execution> <id>make-business-assembly</id> <phase>package</phase> <goals> <goal>single</goal> </goals> <configuration> <appendAssemblyId>false</appendAssemblyId> <finalName>flight-dto</finalName> <descriptors> <descriptor>src/main/assembly/car-assembly.xml</descriptor> </descriptors> <attach>true</attach> </configuration> </execution> <execution> <id>make-gui-assembly</id> <phase>package</phase> <goals> <goal>single</goal> </goals> <configuration> <appendAssemblyId>false</appendAssemblyId> <finalName>app_gui</finalName> <descriptors> <descriptor>src/main/assembly/bike-assembly.xml</descriptor> </descriptors> <attach>true</attach> </configuration> </execution> </executions> </plugin> </plugins> </build> </project> Here is my assembly file <assembly> <id>app_business</id> <formats> <format>jar</format> </formats> <baseDirectory>target</baseDirectory> <includeBaseDirectory>false</includeBaseDirectory> <fileSets> <fileSet> <directory>${project.build.outputDirectory}</directory> <outputDirectory></outputDirectory> <includes> <include>com/dataobjects/**</include> </includes> </fileSet> </fileSets> </assembly>

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  • Java Application for handling records(CRUD)

    - by LivingThing
    I am new to JavaEE and am faced with a tight situation here. I have to develop a Java application for (CRUD) handling records and saving and loading an XML concerning that record. Obviously, I won't be asking you to do this for me. What I would be asking you is to give me some hints/pointer. Initially I thought JAXB would be enough for this but after putting a lot of time learning it and implementing the program I realized that it just can create the XML and read it but for update, delete I would have to do something else. Even if it wasn't for update and delete features requirement for my project I would still think that by just using JAXB is not a good implementation. I was wondering if "REST with Java (JAX-RS) using Jersey" should do the trick for me. ?

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  • Can't seem to load a webview from xml, why?

    - by Bilthon
    Well, I'm trying to follow the tutorial from http://rapidandroid.org/wiki/Graphing. But I found a problem just in the first part of it. I'll describe the problem here, I just cannot understand how this could be wrong, it's pretty simple stuff. What am I doing wrong here? First I created a xml file called statistics.xml, in it among other things I put this code: <WebView android:id="@+id/webview" android:layout_height="fill_parent" android:layout_width="fill_parent"/> Now in the activity that is supposed to display this webview I'm doing this: public class DisplayStatistics extends Activity { public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); WebView wv = (WebView) findViewById(R.id.webview); The problem arises here, as I seem to be getting null for wv whenever I test for it. Which means of course that findViewById(R.id.webview) couldn't find the view. But again, what am I doing wrong?? Of course I know I could also instantiate the webview directly from code without the need to specify it from the xml, but I was just wondering what was wrong about this way of doing it. Just in case I also added the following line in my android manifest file: <uses-permission android:name="android.permission.INTERNET" /> I'm not really sure if it's necessary for displaying the webview (I think not) but I just put it there to see if that was the problem, and it turned out it isn't. Thanks Nelson

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  • Getting "" at the beginning of my XML File after save()

    - by Remy
    I'm opening an existing XML file with c# and I replace some nodes in there. All works fine. Just after I save it, I get the following characters at the beginning of the file:  (EF BB BF in HEX) The whole first line: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> The rest of the file looks like a normal XML file. The simplified code is here: XmlDocument doc = new XmlDocument(); doc.Load(xmlSourceFile); XmlNode translation = doc.SelectSingleNode("//trans-unit[@id='127']"); translation.InnerText = "testing"; doc.Save(xmlTranslatedFile); I'm using a C# WinForm Application. With .NET 4.0. Any ideas? Why would it do that? Can we disable that somehow? It's for Adobe InCopy and it does not open it like this. UPDATE: Alternative Solution: Saving it with the XmlTextWriter works too: XmlTextWriter writer = new XmlTextWriter(inCopyFilename, null); doc.Save(writer);

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  • How to wrtie a XML License Line(ended with a forward slash '/') in C#?

    - by Nano HE
    I want to write a XML file as below: <?xml version="1.0" encoding="UTF-8"?> <books xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the forward slash / .Thank you.

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  • Deserialize inherited classes into the same list in XNA

    - by M0rgenstern
    I am writing a Gui for a game (for what else ...). Therefor I wrote a class GuiElement which has some serializeable fields. From this class I deflect a Class "Button" which has one serializeable field more. Furthermore, I have a Class GuiWindow, which is as well deflected from "GuiElement". An Object of this Class has a Field "HandledElements" of the type "List". To know the layout of the Menues, I use XML-Files, which look like that (for example): <?xml version="1.0" encoding="utf-8" ?> <XnaContent xmlns:Generic="System.Collections.Generic"> <Asset Type="System.Collections.Generic.List[GUI.GuiWindow]"> <Item> <Position>0 0</Position> <AlternativeImagePath></AlternativeImagePath> <IsActive>true</IsActive> <Name>MainMenu</Name> <HandledElements> <Item> <Position>100 100</Position> <AlternativeImagePath></AlternativeImagePath> <IsActive>true</IsActive> <Name>Optionen</Name> <Caption>Optionen</Caption> </Item> </HandledElements> </Item> <Item> <Position>0 0</Position> <AlternativeImagePath></AlternativeImagePath> <IsActive>false</IsActive> <Name>Options</Name> <HandledElements> </HandledElements> </Item> </Asset> </XnaContent> As you can see, the first window has in its "HandledElements" List an Item with the Field . This is a field which only a Button has. The Problem is now: I can't deserialize this XML file, because GuiElement does not have this Field, it only has the few fields above. I thought it would know automatically which Class to use,but it doesn't. Do I really have to give my windows a list for each child class of GuiElement? Or can I do another workaround?

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  • Oracle: how to use updateXML to update multiple nodes in a document?

    - by Alessandro Vernet
    I can write: update my_table set xml = updateXML(xml, '/a/b', '1') where document_id = 123 Now what if in the same update query I also want to set /a/c to 2 (in addition /a/b to 1)? I am tempted to write: update my_table set xml = updateXML(xml, '/a/b', '1'), xml = updateXML(xml, '/a/c', '2') where document_id = 123 But this give me a "ORA-00957: duplicate column name". Any suggestion on how to do this?

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  • What MS technology to use for HTTP service returning XML?

    - by Borek
    I need to create a service that: accepts HTTP requests (with query string or HTTP POST parameters) does some processing on the requests (checking if the request is valid, authentication etc.) reads data from a custom store (another HTTP call in our case) returns the result as custom XML (defined with XSD) I'm trying to think of various MS technologies that could help me and how good they would be for this scenario (pretty standard one I guess). The tasks above are relatively separate, this is what comes to mind: HTTP front-end: ASP.NET Web Forms ASP.NET MVC (seems more appropriate here as I won't need server controls, view state etc.) WCF? Don't know much about it or how well it would suit my task. Custom logic on the server: this will probably be a generic C# code in all cases (sometimes "plugged into" or called from MVC controllers or some equivalent place in other technologies) Reading data from internal data stores: As said, this is another HTTP server in our case. Options that come to mind: Just read the data using something like WebClient (Just theoretically) implement a LINQ provider (Just even more theoretically) implement an EF provider Output the data as custom XML: Linq2XML Serialization? Is it flexible enough? Does WCF provide some tools for this? Some "OXM" - Object/XML mapper if there is something like that for .NET I may be wrong in many of my assumptions, this is just a quick list that comes to mind after a quick research. Some general notes / questions: Testing is important Solution with a clear domain model would be much preferred over the one without Can Entity Framework actually help somewhere in my scenario? If so, where and how? Would WCF be an appropriate technology for this? I don't know much about it.

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  • Hibernate - Problem in parsing mapping file (.hbm.xml)

    - by Yatendra Goel
    I am new to Hibernate. I have an exception while running an Hibernate-based application. The exception is as follows: 16 [main] INFO org.hibernate.cfg.Environment - Hibernate 3.3.2.GA 16 [main] INFO org.hibernate.cfg.Environment - hibernate.properties not found 16 [main] INFO org.hibernate.cfg.Environment - Bytecode provider name : javassist 31 [main] INFO org.hibernate.cfg.Environment - using JDK 1.4 java.sql.Timestamp handling 94 [main] INFO org.hibernate.cfg.Configuration - configuring from resource: /hibernate.cfg.xml 94 [main] INFO org.hibernate.cfg.Configuration - Configuration resource: /hibernate.cfg.xml 219 [main] INFO org.hibernate.cfg.Configuration - Reading mappings from resource : app/data/City.hbm.xml 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(12) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(13) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(14) Attribute "coloumn" must be declared for element type "property". It seems that it is not finding coloumn attribute of the property element in the mappings file but my mappings file do have the coloumn attribute. Below is the mappings file (City.hbm.xml) <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="app.data"> <class name="City" table="CITY"> <id column="CITY_ID" name="cityId"> <generator class="native"/> </id> <property name="cityDisplyaName" coloumn="CITY_DISPLAY_NAME" /> <property coloumn="CITY_MEANINGFUL_NAME" name="cityMeaningFulName" /> <property coloumn="CITY_URL" name="cityURL" /> </class> </hibernate-mapping>

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  • XML Schema: How to specify an attribute with a custom 'simpleType' type?

    - by mackenir
    In my XML schema definition, I'm trying to restrict the value of an attribute to be an integer between 0 and 100. With reference to the sample schema below, I want attribute 'attr' on element 'root' to have this restriction. To achieve this I define a simpleType 'Percentage' and set this as the 'type' of 'attr'. However, my XML schema editor (VS 2008) flags the attribute up as having a problem: "Type 'Percentage' is not declared or is not a simple type". <?xml version="1.0" encoding="utf-8"?> <xs:schema elementFormDefault="qualified" id="test" xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="http://testtttt"> <xs:simpleType name="Percentage"> <xs:restriction base="xs:integer"> <xs:minInclusive value="0"/> <xs:maxInclusive value="100"/> </xs:restriction> </xs:simpleType> <xs:element name="root"> <xs:complexType> <xs:attribute name="attr" type="Percentage" use="optional" /> </xs:complexType> </xs:element>

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  • How can I create/update an XML node that may or may not exist?

    - by ScottBai
    Is there a method available (i.e. without me creating my own recursive method), for a given xpath (or other method of identifying the hierarchical position) to create/update an XML node, where the node would be created if it does not exist? This would need to create the parent node if it does not exist as well. I do have an XSD which includes all possible nodes. i.e. Before: <employee> <name>John Smith</name> </employee> Would like to call something like this: CoolXmlUpdateMethod("/employee/address/city", "Los Angeles"); After: <employee> <name>John Smith</name> <address> <city>Los Angeles</city> </address> </employee> Or even a method to create a node, given an xpath, wherein it will recursively create the parent node(s) if they do not exist? As far as the application (if it matters), this is taking an existing XML doc that contains only populated nodes, and adding data to it from another system. The new data may or may not already have values populated in the source XML. Surely this is not an uncommon scenario?

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  • Parsing log files in a folder in ColdFusion

    - by Simon Guo
    The problem is there is a folder ./log/ containing the files like: jan2010.xml, feb2010.xml, mar2010.xml, jan2009.xml, feb2009.xml, mar2009.xml ... each xml file would like: <root><record name="bob" spend="20"></record>...(more records)</root> I want to write a piece of ColdFusion code (log.cfm) that simply parsing those xml files. For the front end I would let user to choose a year, then the click submit button. All the content in that year will be show up in separate table by month. Each table shows the total money spent for each person. like: person cost bob 200 mike 300 Total 500 Thanks.

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  • How to define multiple elements in XML Schema with the same name and different attribute value allow

    - by David Skyba
    I would like to create XML Schema for this chunk of xml, I would like to restrict the values of "name" attribute, so that in output document on and only one instance of day is allowed for each week day: <a> <day name="monday" /> <day name="tuesday" /> <day name="wednesday" /> </a> I have tried to use this: <xs:complexType name="a"> <xs:sequence> <xs:element name="day" minOccurs="1" maxOccurs="1"> <xs:complexType> <xs:attribute name="name" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="monday" /> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> </xs:element> <xs:element name="day" minOccurs="1" maxOccurs="1"> <xs:complexType> <xs:attribute name="name" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="tuesday" /> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> but XML Schema validator in eclipse says error "Multiple elements with name 'day', with different types, appear in the model group.". Is there any other way?

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  • How to syntax-highlight XML in CDATA elements in Vim?

    - by Jim Hurne
    Vim's syntax highlighting for XML/XSL is great, except it turns off all syntax highlighting in CDATA regions. Is there a way to turn on syntax highlighting on in CDATA regions? At work, we have a lot of XSL code embedded within other XML documents. It would be great if I could get all of the goodness of XML editing for the embedded XSL code as well without having to temporarily remove the CDATA tags, or copy the CDATA content into a temporary file. Example: <root> <someTag><![CDATA[ <xsl:template match="/"> <!-- XSL content here --> </xsl:template> ]]> </someTag> </root> Note that the name of the tag (in the example, someTag) containing the content could be anything. We also sometimes embed Javascript inside CDATA regions as well, and again, it would be nice to turn on Javascript syntax highlighting for those regions. Again, the tag the data is embedded in is usually arbitrary and can be anything.

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