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  • Explain a block of crazy JS code inside Sizzle(the CSS selector engine)

    - by Andy Li
    So, here is the function for pre-filtering "CHILD": function(match){ if ( match[1] === "nth" ) { // parse equations like 'even', 'odd', '5', '2n', '3n+2', '4n-1', '-n+6' var test = /(-?)(\d*)n((?:\+|-)?\d*)/.exec( match[2] === "even" && "2n" || match[2] === "odd" && "2n+1" || !/\D/.test( match[2] ) && "0n+" + match[2] || match[2]); // calculate the numbers (first)n+(last) including if they are negative match[2] = (test[1] + (test[2] || 1)) - 0; match[3] = test[3] - 0; } // TODO: Move to normal caching system match[0] = done++; return match; } The code is extracted from line 442-458 of sizzle.js. So, why is the line var test = ..., have the exec inputing a boolean? Or is that really a string? Can someone explain it by splitting it into a few more lines of code?

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  • perl ENV value avoid escape

    - by Michael
    In my makefile I have command in variable like this substitute := perl -p -e 's/@([^@]+)@/"$(update_url)"/ge' > output.txt update_url := em:updateURL=\"http:\/\/bla\/update.rdf\"\n this works fine when I run command in target and I have newline, quotes however I need to replace $(update_url)" with environment variable, using expression like this #substitute := perl -p -e 's/@([^@]+)@/defined $$ENV{$$1} ? $$ENV{$$1} : $$1/ge' I am exporting those variables from makefile. This gives me literally em:updateURL=\"http:\/\/bla\/update.rdf\"\n on output file... so how to make the second version to give output like first version?

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  • regular expression for string in c

    - by darkie15
    Hi All, I am working writing a regular expression used to validate string in C. Here is to what I have gone so far '^"[A-Za-z0-9]*[\t\n]*"$' for rules - A string should begin with double quotes - May not contain a newline character However, I am not able to capture the rule for allowing '\' or '"' in a string if preceded with '\'. Here is what I tried: '^"[A-Za-z0-9]*[\t\n]*[\\\|\\"]?"$' But this doesn't seem to work. What might be wrong with the regular expression here? Regards, darkie15

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  • PHP RegExpr error Unkown modifier '('

    - by Anonymous
    I have this regular expression: ([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?) its for extracting links to topics from forum Now when i use it in my script $url = "([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?)"; preg_match_all spits: "Unknown modifier '('" Can anyone help me with this obviously stupid problem

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  • Ruby: backslash all non-alphanumeric characters in a string

    - by HBlend
    I have a script where I need to take a user's password and then run a command line using it. I need to backslash all (could be more then one) non-alphanumeric characters in the password. I have tried several things at this point including the below but getting no where. This has to be easy, just missing it. Tried these and several others: password = password.gsub(/(\W)/, '\\1') password = password.gsub(/(\W)/, '\\\1') password = password.gsub(/(\W)/, '\\\\1')

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  • What is the MM/DD/YYYY regular expression and how do I use it in php?

    - by zeckdude
    I found the regular expression for MM/DD/YYYY at http://www.regular-expressions.info/regexbuddy/datemmddyyyy.html but I don't think I am using it correctly. Here's my code: $date_regex = '(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d'; $test_date = '03/22/2010'; if(preg_match($date_regex, $test_date)) { echo 'this date is formatted correctly'; } else { echo 'this date is not formatted correctly'; } When I run this, it still echoes 'this date is not formatted correctly', when it should be saying the opposite. How do I set this regular expression up in php?

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  • Regular expressions and matching URLs with metacharacters

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions? Edit: The original intent was to match all URLs that could be found after the first semi colon.

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  • Extracting a string between specified characters in python

    - by Seth
    I'm a newbie to regular expressions and I have the following string: sequence = ["{\"First\":\"Belyuen,NT,0801\",\"Second\":\"Belyuen,NT,0801\"}","{\"First\":\"Larrakeyah,NT,0801\",\"Second\":\"Larrakeyah,NT,0801\"}"] I am trying to extract the text Belyuen,NT,0801 and Larrakeyah,NT,0801 in python. I have the following code which is not working: re.search('\:\\"...\\', ''.join(sequence)) I.e. I want to get the string between characters :\ and \.

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  • How do I create a regular expression to match a word misspelling the original case sensitivity?

    - by Patrick Allaert
    I want to discover wrong spelling of "FooBar" in sentence: "This is a 'FooBar' example where I should match different spelling of fooBar such as: foobar, FOOBAR or even fOoBaR but not foobarS!" In this sentence, I would like to match words (in order): fooBar, foobar, FOOBAR, fOoBaR and not: FooBar (correct spelling), foobarS (not the same word) Is there an existing solution using Perl Regular Expression? This is intended to be used with grep -P Thanks

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  • How to validate hostname in perl?

    - by embedded
    Hi, I need to come up with a regular expression to validate hostname against RFC-1123 and RFC-952. Right now I'm using this: ^(?=.{1,255}$)[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?(?:\.[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?)*\.?$/ but this does not do the trick since it does not catch a. as invalid hostname. How do I enhance the reg expression to comply with those RFCs? Thanks

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  • combining dynamic text with regular expressions in php

    - by pfunc
    I am experimenting with finding popular keywords using curl, php and regular expressions. I have an array of non-specific nouns that I am matching my keyword search up. So I am looking for words like "the", "and", "that" etc. and taking them out of the keyword search. so I have an array of words like so: $wordArr = [the, and, at,....]; and then running something like: && preg_match('(\bmyword\w*\b)', $key) == false how do I combine these two so it loops through the array finding out if any of the words in the array match the regular expression? I guess I could just do a for loop, but though maybe I could use in_array($wordArr, $key).. or something like that.

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  • How do I change the value of a dynamic_bitset?

    - by R S
    I am using C++ boost's dynamic_bitset. I have already allocated a variable and I just want to change its value - to construct it anew from an 'unsigned long' like from the constructor, but I don't want to allocate the memory again or to create a temporary variable. What can I do?

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  • Remove duplicate characters using a regular expression

    - by Alex
    I need to Match the second and subsequent occurances of the * character using a regular expression. I'm actually using the Replace method to remove them so here's some examples of before and after: test* -> test* (no change) *test* -> *test test** *e -> test* e Is it possible to do this with a regular expression? Thanks

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  • using regular expression in Java

    - by Mrityunjay
    Hi, i need to check a string that should contain only ABCDEFG characters, in any sequence and with only 7 characters. Please let me know the correct way of using regular expression. as corrently i am using String abs = "ABPID"; if(!Pattern.matches("[[ABCDEFG]", abs)) System.out.println("Error"); i am using the following code which works when i use the String abcdefg but for other cases it fails. please help me out.

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  • Algorithm to match natural text in mail

    - by snøreven
    I need to separate natural, coherent text/sentences in emails from lists, signatures, greetings and so on before further processing. example: Hi tom, last monday we did bla bla, lore Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. list item 2 list item 3 list item 3 Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid x ea commodi consequat. Quis aute iure reprehenderit in voluptate velit regards, K. ---line-of-funny-characters-####### example inc. 33 evil street, london mobile: 00 234534/234345 Ideally the algorithm would match only the bold parts. Is there any recommended approach - or are there even existing algorithms for that problem? Should I try approximate regular expressions or more statistical stuff based on number of punctation marks, length and so on?

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  • need code for search another character

    - by klox
    hi,all..i have this code: var str = "KD-R435MUN2D"; var hasUD; var patt1 = str.match(/U/gi); var patt2 = str.match(/D/gi); if (patt1 && patt2) { hasUD = 'UD'; } else { hasUD = false; } document.write(hasUD); how to modify this code if i want search JD from var str="KD-S35JWD"..i try this but doesn't work: <script type="text/javascript"> var str = "KD-R435jwd"; var hasUD; var hasJD; var patt1 = str.match(/U/gi); var patt2 = str.match(/J/gi); var patt3 = str.match(/D/gi); if (patt1 && patt3) { hasUD = 'UD'; document.write(hasUD); } elseif (patt2 && patt3) { hasJD = 'JD'; document.write(hasJD); } </script>

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  • Regular Expression to find the job id in a string

    - by Jamie
    Hi all, Please could someone help me, i will be forever appreciative. I'm trying to create a regular expression which will extract 797 from "Your job 797 ("job_name") has been submitted" or "Your Job 9212 ("another_job_name") has been submitted" etc. Any ideas? Thanks guys!

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