Search Results

Search found 5493 results on 220 pages for 'boost regex'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 121/220 | < Previous Page | 117 118 119 120 121 122 123 124 125 126 127 128  | Next Page >

  • Explain a block of crazy JS code inside Sizzle(the CSS selector engine)

    - by Andy Li
    So, here is the function for pre-filtering "CHILD": function(match){ if ( match[1] === "nth" ) { // parse equations like 'even', 'odd', '5', '2n', '3n+2', '4n-1', '-n+6' var test = /(-?)(\d*)n((?:\+|-)?\d*)/.exec( match[2] === "even" && "2n" || match[2] === "odd" && "2n+1" || !/\D/.test( match[2] ) && "0n+" + match[2] || match[2]); // calculate the numbers (first)n+(last) including if they are negative match[2] = (test[1] + (test[2] || 1)) - 0; match[3] = test[3] - 0; } // TODO: Move to normal caching system match[0] = done++; return match; } The code is extracted from line 442-458 of sizzle.js. So, why is the line var test = ..., have the exec inputing a boolean? Or is that really a string? Can someone explain it by splitting it into a few more lines of code?

    Read the article

  • perl ENV value avoid escape

    - by Michael
    In my makefile I have command in variable like this substitute := perl -p -e 's/@([^@]+)@/"$(update_url)"/ge' > output.txt update_url := em:updateURL=\"http:\/\/bla\/update.rdf\"\n this works fine when I run command in target and I have newline, quotes however I need to replace $(update_url)" with environment variable, using expression like this #substitute := perl -p -e 's/@([^@]+)@/defined $$ENV{$$1} ? $$ENV{$$1} : $$1/ge' I am exporting those variables from makefile. This gives me literally em:updateURL=\"http:\/\/bla\/update.rdf\"\n on output file... so how to make the second version to give output like first version?

    Read the article

  • regular expression for string in c

    - by darkie15
    Hi All, I am working writing a regular expression used to validate string in C. Here is to what I have gone so far '^"[A-Za-z0-9]*[\t\n]*"$' for rules - A string should begin with double quotes - May not contain a newline character However, I am not able to capture the rule for allowing '\' or '"' in a string if preceded with '\'. Here is what I tried: '^"[A-Za-z0-9]*[\t\n]*[\\\|\\"]?"$' But this doesn't seem to work. What might be wrong with the regular expression here? Regards, darkie15

    Read the article

  • PHP RegExpr error Unkown modifier '('

    - by Anonymous
    I have this regular expression: ([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?) its for extracting links to topics from forum Now when i use it in my script $url = "([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?)"; preg_match_all spits: "Unknown modifier '('" Can anyone help me with this obviously stupid problem

    Read the article

  • Ruby: backslash all non-alphanumeric characters in a string

    - by HBlend
    I have a script where I need to take a user's password and then run a command line using it. I need to backslash all (could be more then one) non-alphanumeric characters in the password. I have tried several things at this point including the below but getting no where. This has to be easy, just missing it. Tried these and several others: password = password.gsub(/(\W)/, '\\1') password = password.gsub(/(\W)/, '\\\1') password = password.gsub(/(\W)/, '\\\\1')

    Read the article

  • What is the MM/DD/YYYY regular expression and how do I use it in php?

    - by zeckdude
    I found the regular expression for MM/DD/YYYY at http://www.regular-expressions.info/regexbuddy/datemmddyyyy.html but I don't think I am using it correctly. Here's my code: $date_regex = '(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d'; $test_date = '03/22/2010'; if(preg_match($date_regex, $test_date)) { echo 'this date is formatted correctly'; } else { echo 'this date is not formatted correctly'; } When I run this, it still echoes 'this date is not formatted correctly', when it should be saying the opposite. How do I set this regular expression up in php?

    Read the article

  • Regular expressions and matching URLs with metacharacters

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions? Edit: The original intent was to match all URLs that could be found after the first semi colon.

    Read the article

  • Extracting a string between specified characters in python

    - by Seth
    I'm a newbie to regular expressions and I have the following string: sequence = ["{\"First\":\"Belyuen,NT,0801\",\"Second\":\"Belyuen,NT,0801\"}","{\"First\":\"Larrakeyah,NT,0801\",\"Second\":\"Larrakeyah,NT,0801\"}"] I am trying to extract the text Belyuen,NT,0801 and Larrakeyah,NT,0801 in python. I have the following code which is not working: re.search('\:\\"...\\', ''.join(sequence)) I.e. I want to get the string between characters :\ and \.

    Read the article

  • How do I create a regular expression to match a word misspelling the original case sensitivity?

    - by Patrick Allaert
    I want to discover wrong spelling of "FooBar" in sentence: "This is a 'FooBar' example where I should match different spelling of fooBar such as: foobar, FOOBAR or even fOoBaR but not foobarS!" In this sentence, I would like to match words (in order): fooBar, foobar, FOOBAR, fOoBaR and not: FooBar (correct spelling), foobarS (not the same word) Is there an existing solution using Perl Regular Expression? This is intended to be used with grep -P Thanks

    Read the article

  • How to validate hostname in perl?

    - by embedded
    Hi, I need to come up with a regular expression to validate hostname against RFC-1123 and RFC-952. Right now I'm using this: ^(?=.{1,255}$)[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?(?:\.[0-9A-Za-z](?:(?:[0-9A-Za-z]|\b-){0,61}[0-9A-Za-z])?)*\.?$/ but this does not do the trick since it does not catch a. as invalid hostname. How do I enhance the reg expression to comply with those RFCs? Thanks

    Read the article

  • combining dynamic text with regular expressions in php

    - by pfunc
    I am experimenting with finding popular keywords using curl, php and regular expressions. I have an array of non-specific nouns that I am matching my keyword search up. So I am looking for words like "the", "and", "that" etc. and taking them out of the keyword search. so I have an array of words like so: $wordArr = [the, and, at,....]; and then running something like: && preg_match('(\bmyword\w*\b)', $key) == false how do I combine these two so it loops through the array finding out if any of the words in the array match the regular expression? I guess I could just do a for loop, but though maybe I could use in_array($wordArr, $key).. or something like that.

    Read the article

  • How do I change the value of a dynamic_bitset?

    - by R S
    I am using C++ boost's dynamic_bitset. I have already allocated a variable and I just want to change its value - to construct it anew from an 'unsigned long' like from the constructor, but I don't want to allocate the memory again or to create a temporary variable. What can I do?

    Read the article

  • Remove duplicate characters using a regular expression

    - by Alex
    I need to Match the second and subsequent occurances of the * character using a regular expression. I'm actually using the Replace method to remove them so here's some examples of before and after: test* -> test* (no change) *test* -> *test test** *e -> test* e Is it possible to do this with a regular expression? Thanks

    Read the article

  • using regular expression in Java

    - by Mrityunjay
    Hi, i need to check a string that should contain only ABCDEFG characters, in any sequence and with only 7 characters. Please let me know the correct way of using regular expression. as corrently i am using String abs = "ABPID"; if(!Pattern.matches("[[ABCDEFG]", abs)) System.out.println("Error"); i am using the following code which works when i use the String abcdefg but for other cases it fails. please help me out.

    Read the article

  • Algorithm to match natural text in mail

    - by snøreven
    I need to separate natural, coherent text/sentences in emails from lists, signatures, greetings and so on before further processing. example: Hi tom, last monday we did bla bla, lore Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. list item 2 list item 3 list item 3 Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid x ea commodi consequat. Quis aute iure reprehenderit in voluptate velit regards, K. ---line-of-funny-characters-####### example inc. 33 evil street, london mobile: 00 234534/234345 Ideally the algorithm would match only the bold parts. Is there any recommended approach - or are there even existing algorithms for that problem? Should I try approximate regular expressions or more statistical stuff based on number of punctation marks, length and so on?

    Read the article

  • need code for search another character

    - by klox
    hi,all..i have this code: var str = "KD-R435MUN2D"; var hasUD; var patt1 = str.match(/U/gi); var patt2 = str.match(/D/gi); if (patt1 && patt2) { hasUD = 'UD'; } else { hasUD = false; } document.write(hasUD); how to modify this code if i want search JD from var str="KD-S35JWD"..i try this but doesn't work: <script type="text/javascript"> var str = "KD-R435jwd"; var hasUD; var hasJD; var patt1 = str.match(/U/gi); var patt2 = str.match(/J/gi); var patt3 = str.match(/D/gi); if (patt1 && patt3) { hasUD = 'UD'; document.write(hasUD); } elseif (patt2 && patt3) { hasJD = 'JD'; document.write(hasJD); } </script>

    Read the article

  • Regular Expression to find the job id in a string

    - by Jamie
    Hi all, Please could someone help me, i will be forever appreciative. I'm trying to create a regular expression which will extract 797 from "Your job 797 ("job_name") has been submitted" or "Your Job 9212 ("another_job_name") has been submitted" etc. Any ideas? Thanks guys!

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 117 118 119 120 121 122 123 124 125 126 127 128  | Next Page >