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  • Replace underscore between words (reg.exp)

    - by lasseespeholt
    Hey, I need a regular expression to solve the following problem (links to similar problems is also appreciated, related tutorials etc.): __some_words_a_b___ => __some words a b___ ____ => ____ So I want underscores between words to be replaced with space and keep leading and trailing underscores. I found this: ^[ \t]+|[ \t]+$ and I guess it most be something like that. I will use it in jQuery, Java (stdlibs) and maybe XSLT. Addition: The sentences do not necessarily start with underscores or ends with underscores. It is also possible that a sentence ain't containing underscores at all. Best regards Lasse Espeholt

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  • Regular expression to remove all text except...

    - by Barryman9000
    There may be an easier way, and if there is I'm all for it. However - my ASP.NET page has a TON of controls on it, and I've given them all ID's that start with underscore. I copied all the markup into Notepad++ and I'm trying to find a regular expression that will find everything but the controls and replace it with whitespace. that way I'll have a text file that has all my control names which I'll probably throw into Excel and do some string manipulation to add ".Text = " etc. Any suggestions?

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  • Strange JavaScript Regular Expression Behavior

    - by Kiwi
    I'm getting different behavior from a regular expression in JavaScript depending on whether or not I declare it using literal syntax. Using a extremely simple test HTML file: <html> <head> <script type="text/javascript"> var s = '3'; var regex1 = /\d/; var regex2 = new RegExp('\d'); alert(s.search(regex1)); // 0 (matches) alert(s.search(regex2)); // -1 (does not match) </script> </head> <body></body> </html> The regular expression declared with literal syntax (/\d/) works correctly, while the other (new RegExp('\d')) does not. Why on earth is this happening? I'm using Google Chrome 5.0.375.70 on Windows Vista Home Premium, if that's at all helpful.

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  • Regular expression only for website

    - by Katie
    HI, I'm new to Regular Expression. I need to find just website in some text and I'm looking for a regular expression able to find out strings like: www.my.home, http://my.site.it But this regular expression should not find strings like: [email protected] or if the website is already inside html tag <a href="http://www.my.site.com/"><span style="font-style: normal;">www.mambo-test.org</span></a> I tried with this one: \b((https?://[^ ])|(www.[^ ])) but it also finds the website in the href and between the tag: <a href="http://www.my.site.com/"><span style="font-style: normal;">www.mambo-test.org</span></a> and I don't know how except this case.

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  • Regular Expressions in PHP

    - by kelly
    Sorry for unclear description, my English is not good. My problem is that I want to decode a string, and this string has nested content delimited by {}. For example: The string: {any string0{any string 00{any string 000....}}}{any string1}any string. The result I want to get: array[0] = {any string0{any string 00{any string 000....}}} array[1] = {any string1} I hope it's clear enough.

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  • Python regular expressions assigning to named groups

    - by None
    When you use variables (is that the correct word?) in python regular expressions like this: "blah (?P\w+)" ("value" would be the variable), how could you make the variable's value be the text after "blah " to the end of the line or to a certain character not paying any attention to the actual content of the variable. For example, this is pseudo-code for what I want: >>> import re >>> p = re.compile("say (?P<value>continue_until_text_after_assignment_is_recognized) endsay") >>> m = p.match("say Hello hi yo endsay") >>> m.group('value') 'Hello hi yo' Note: The title is probably not understandable. That is because I didn't know how to say it. Sorry if I caused any confusion.

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  • classic asp ignore comma within speach marks CSV

    - by user2968227
    I Have a CSV File that looks like this 1,HELLO,ENGLISH 2,HELLO1,ENGLISH 3,HELLO2,ENGLISH 4,HELLO3,ENGLISH 5,HELLO4,ENGLISH 6,HELLO5,ENGLISH 7,HELLO6,ENGLISH 8,"HELLO7, HELLO7 ...",ENGLISH 9,HELLO7,ENGLISH 10,HELLO7,ENGLISH I want to step loop through the lines and write to a table using split classic asp function by comma. When Speech marks are present to ignore the comma within those speech marks and take the string. Please help. <% dim csv_to_import,counter,line,fso,objFile csv_to_import="uploads/testLang.csv" set fso = createobject("scripting.filesystemobject") set objFile = fso.opentextfile(server.mappath(csv_to_import)) str_imported_data="<table cellpadding='3' cellspacing='1' border='1'>" Do Until objFile.AtEndOfStream line = split(objFile.ReadLine,",") str_imported_data=str_imported_data&"<tr>" total_records=ubound(line) for i=0 to total_records if i>0 then str_imported_data=str_imported_data&"<td>"&line(i)&"</td>" else str_imported_data=str_imported_data&"<th>"&line(i)&"</th>" end if next str_imported_data=str_imported_data&"</tr>" & chr(13) Loop str_imported_data=str_imported_data&"<caption>Total Number of Records: "&total_records&"</caption></table>" objFile.Close response.Write str_imported_data %>

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  • Is the JavaScript RegExp implicit method deprecated?

    - by Eric
    So everyone knows what I mean by "implicit methods"? They're like those default properties from the Windows COM days of yore, where you could type something like val = obj(arguments) and it would be interpreted as val = obj.defaultMethod(arguments) I just found out JavaScript has the same thing: the default method of a RegExp object appears to be 'exec', as in /(\w{4})/('yip jump man')[1] ==> jump This even works when the RegExp object is assigned to a variable, and even when it's created with the RegExp constructor, instead of /.../, which is good news to us fans of referential transparency. Where is this documented, and/or is it deprecated?

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  • How to get everything in the string, but a particular pattern

    - by José Leal
    Yet another regexp question: I have a string as the following, "This is a string, and I have a priority !1" So I want to build a regexp that extracts my priority, which is this number 1 preceded by the "!". To extract it is very easy, "!([1-4])". But now I want to extract the text, leaving it out! How can I do that? DETAIL: The !1 can be anywhere in the string, so this is also perfectly fine: "This is a string, !1 and I have a priority" Thanks! UPDATE: I'm using scala

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  • Ruby: backslash all non-alphanumeric characters in a string

    - by HBlend
    I have a script where I need to take a user's password and then run a command line using it. I need to backslash all (could be more then one) non-alphanumeric characters in the password. I have tried several things at this point including the below but getting no where. This has to be easy, just missing it. Tried these and several others: password = password.gsub(/(\W)/, '\\1') password = password.gsub(/(\W)/, '\\\1') password = password.gsub(/(\W)/, '\\\\1')

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  • replacing text within quotes until next quote

    - by Jordan Trainor
    String input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; This is my current code that works but iv added some code that has to run before this which makes some '"' split onto another line thus making the code below obsolute unless under certain cirumstances the '"' is not put onto the next line. firstQuote = input.IndexOf("\""); lastQuote = input.LastIndexOf("\""); input = input.Substring(0, firstQuote) + "<span>quote" + input.Substring(firstQuote + 1, lastQuote - (firstQuote + 1) + "quote</span>" + input.Substring(lastQuote + 1, lines.Length - (lastQuote + 1); How could I change the input string from input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; to input = "helloj(<span>quoteiojgeio\r\ngsk\\"jopriquote</span>gj\r\negjoijisgoe<span>quotejoijsofeijquote</span>quote<span>quote</span>ojgsoij<span>quote</span>";

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  • Removing text within parentheses (parentheses within parentheses prob)

    - by TenJack
    Hi, I am trying to remove text that is within parentheses (along with the parentheses themselves) but am having trouble with the scenario where there are parentheses within parentheses. This is the method I am using (in Ruby): sentence.gsub(/\(.*?\)/, "") and that works fine until I have a sentence such as: "This is (a test (string))" Then the above chokes. Anyone have any idea how to do this? I am completely stumped.

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  • How to Redirect Subdomains to Other Domain

    - by Codex73
    What I'm trying to accomplish with htaccess mod-rewrite: Redirect all sub-domains to new domain name w rewrite rule. e.g. test1.olddomain.com === test1.newdomain.com test2.olddomain.com === test2.newdomain.com test3.olddomain.com === test3.newdomain.com This is what I have so far which of course is wrong: Options +FollowSymLinks RewriteEngine on RewriteCond %{HTTP_HOST} ^olddomain\.com$ [NC] RewriteRule ^(.*)$ http://www.newdomain.com/$1 [R=301,L] RewriteCond %{HTTP_HOST} ^www\.olddomain\.com$ [NC] RewriteRule ^(.*) http://www.newdomain.com/$1 [R=301,L] RewriteRule [a-zA-Z]+\.olddomain.com$ http://$1.newdomain.com/ [R=301,L] Since I'm not a Regular Expression junkie just yet, I need your help... Thanks for any help you can give here. I know also we can compile these first two conditions into one. Note: The reason I don't redirect all domain using DNS is that a lot of directories need special rewrite rules in order to maintain positions on SEO.

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  • Automatically hyper-link URL's and Email's using C#, whilst leaving bespoke tags in place

    - by marcusstarnes
    I have a site that enables users to post messages to a forum. At present, if a user types a web address or email address and posts it, it's treated the same as any other piece of text. There are tools that enable the user to supply hyper-linked web and email addresses (via some bespoke tags/markup) - these are sometimes used, but not always. In addition, a bespoke 'Image' tag can also be used to reference images that are hosted on the web. My objective is to both cater for those that use these existing tools to generate hyper-linked addresses, but to also cater for those that simply type a web or email address in, and to then automatically convert this to a hyper-linked address for them (as soon as they submit their post). I've found one or two regular expressions that convert a plain string web or email address, however, I obviously don't want to perform any manipulation on addresses that are already being handled via the sites bespoke tagging, and that's where I'm stuck - how to EXCLUDE any web or email addresses that are already catered for via the bespoke tagging - I wan't to leave them as is. Here are some examples of bespoke tagging for the variations that I need to be left alone: [URL=www.msn.com]www.msn.com[/URL] [URL=http://www.msn.com]http://www.msn.com[/URL] [[email protected]][email protected][/EMAIL] [IMG]www.msn.com/images/test.jpg[/IMG] [IMG]http://www.msn.com/images/test.jpg[/IMG] The following examples would however ideally need to be automatically converted into web & email links respectively: www.msn.com http://www.msn.com [email protected] Ideally, the 'converted' links would just have the appropriate bespoke tags applied to them as per the initial examples earlier in this post, so rather than: <a href="..." etc. they'd become: [URL=http://www.. etc.) Unfortunately, we have a LOT of historic data stored with this bespoke tagging throughout, so for now, we'd like to retain that rather than implementing an entirely new way of storing our users posts. Any help would be much appreciated. Thanks.

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  • What is the MM/DD/YYYY regular expression and how do I use it in php?

    - by zeckdude
    I found the regular expression for MM/DD/YYYY at http://www.regular-expressions.info/regexbuddy/datemmddyyyy.html but I don't think I am using it correctly. Here's my code: $date_regex = '(0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])[- /.](19|20)\d\d'; $test_date = '03/22/2010'; if(preg_match($date_regex, $test_date)) { echo 'this date is formatted correctly'; } else { echo 'this date is not formatted correctly'; } When I run this, it still echoes 'this date is not formatted correctly', when it should be saying the opposite. How do I set this regular expression up in php?

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  • Extract domain from body of email

    - by iman453
    Hi, I was wondering if there is any way I could extract domain names from the body of email messages in python. I was thinking of using regular expressions, but I am not too great in writing them, and was wondering if someone could help me out. Here's a sample email body: <tr><td colspan="5"><font face="verdana" size="4" color="#999999"><b>Resource Links - </b></font><span class="snv"><a href="http://clk.about.com/?zi=4/RZ">Get Listed Here</a></span></td><td class="snv" valign="bottom" align="right"><a href="http://sprinks.about.com/faq/index.htm">What Is This?</a></td></tr><tr><td colspan="6" bgcolor="#999999"><img height="1" width="1"></td></tr><tr><td colspan="6"><map name="sgmap"><area href="http://x.about.com/sg/r/3412.htm?p=0&amp;ref=fooddrinksl_sg" shape="rect" coords="0, 0, 600, 20"><area href="http://x.about.com/sg/r/3412.htm?p=1&amp;ref=fooddrinksl_sg" shape="rect" coords="0, 55, 600, 75"><area href="http://x.about.com/sg/r/3412.htm?p=2&amp;ref=fooddrinksl_sg" shape="rect" coords="0, 110, 600, 130"></map><img border="0" src="http://z.about.com/sg/sg.gif?cuni=3412" usemap="#sgmap" width="600" height="160"></td></tr><tr><td colspan="6">&nbsp;</td></tr> <tr><td colspan="6"><a name="d"><font face="verdana" size="4" color="#cc0000"><b>Top Picks - </b></font></a><a href="http://slclk.about.com/?zi=1/BAO" class="srvb">Fun Gift Ideas</a><span class="snv"> from your <a href="http://chinesefood.about.com">Chinese Cuisine</a> Guide</span></td></tr><tr><td colspan="6" bgcolor="cc0000"><img height="1" width="1"></td></tr><tr><td colspan="6" class="snv"> So I would need "clk.about.com" etc. Thanks!

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  • Regular Expression for finding phone numbers

    - by Rocky
    Hello Everyone, I am new to Stackoverflow and I have a quick question. Let's assume we are given a large number of HTML files (large as in theoretically infinite). How can I use Regular Expressions to extract the list of Phone Numbers from all those files? Explanation/expression will be really appreciated. The Phone numbers can be any of the following formats: (123) 456 7899 (123).456.7899 (123)-456-7899 123-456-7899 123 456 7899 1234567899 Thanks a lot for all your help and have a good one!

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  • php replace regular expression

    - by Enkay
    I need to use php to add a space between a period and the next word/letter when there's none. For example, "This is a sentence.This is the next one." needs to become "This is a sentence. This is the next one." Notice the added space after the first period. My problem is that even if I'm able to make a regular expression that finds every dot followed by a letter, how do I then replace that dot with a "dot + space" and keep the letter? Also it needs to keep the case of the letter, lower or upper. Thanks for your input.

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  • PHP regular expression

    - by Ferol
    such text: $text = ' href="http://yahoo.com" target="_blank"> link text </a> text... text... <br> text...'; // $text = ' text... <a href="http://yahoo.com" target="_blank"> link text </a> text... text... <br> text...'; and such regular expression: preg_match_all('/^(.*)(<.+>)(.*)(<\/.+>)(.*)$/',$text,$matches); what I want, - to check if text matches the regular expression. If yes, then $matches should contain parts of string above, if not (as I guess) it should contain four zero-length arrays. something is wrong, but I can't find, what actually is?

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  • Regular Expression: back references

    - by sixtyfootersdude
    sed 's/^\(\h*\)\(.*\)$/\1<!-- \2 -->/' web.xml I think that this should take this xml: <a> <d> bla </d> </a> And turn it into: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> --> But what is doing is this: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> -->

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  • Search for a String and replace it with a variable

    - by chrissygormley
    Hello, I am trying to use regular expression to search a document fo a UUID number and replace the end of it with a new number. The code I have so far is: read_file = open('test.txt', 'r+') write_file = open('test.txt', 'w') r = re.compile(r'(self.uid\s*=\s*5EFF837F-EFC2-4c32-A3D4\s*)(\S+)') for l in read_file: m1 = r.match(l) if m1: new=(str,m1.group(2)) new?????? This where I get stuck. The file test.txt has the below UUID stored in it: self.uid = '5EFF837F-EFC2-4c32-A3D4-D15C7F9E1F22' I want to replace the part D15C7F9E1F22. I have also tried this: r = re.compile(r'(self.uid\s*=\s*)(\S+)') for l in fp: m1 = r.match(l) new=map(int,m1.group(2).split("-") new[4]='RHUI5345JO' But I cannot seem to match the string. Thanks in advance for any help.

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  • How do I best do balanced quoting with Perl's Regexp::Grammars?

    - by Evan Carroll
    Using Damian Conway's Regexp::Grammars, I'm trying to match different balanced quoting ('foo', "foo", but not 'foo") mechanisms -- such as parens, quotes, double quotes, and double dollars. This is the code I'm currently using. <token: pair> \'<literal>\'|\"<literal>\"|\$\$<literal>\$\$ <token: literal> [\S]+ This generally works fine and allows me to say something like: <rule: quote> QUOTE <.as>? <pair> My question is how do I reform the output, to exclude the needles notation for the pair token? { '' => 'QUOTE AS \',\'', 'quote' => { '' => 'QUOTE AS \',\'', 'pair' => { 'literal' => ',', '' => '\',\'' } } }, Here, there is obviously no desire to have pair in between, quote, and the literal value of it. Is there a better way to match 'foo', "foo", and $$foo$$, and maybe sometimes ( foo ) without each time creating a needless pair token? Can I preprocess-out that token or fold it into the above? Or, write a better construct entirely that eliminates the need for it?

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