Search Results

Search found 17468 results on 699 pages for 'expression design'.

Page 121/699 | < Previous Page | 117 118 119 120 121 122 123 124 125 126 127 128  | Next Page >

• How to get a ?High Quality? Custom Logo Design

  Custom Logo Design, are logos designed specifically, uniquely and creatively for a business. The competition between the different logo design service providers is fierce. There is a flood of service... [Author: Claudia Winifred - Web Design and Development - March 20, 2010]

  Read the article

• error_expected_primary expression before in. In functions

  - by user2975402

  Here is my code. I try to fix it and I always obtain the same error: expected primary expression before 'int'. in line 47, 55, 63, 80, 86. And I've already tried this program in small pieces before and it works. It doesn't marked that error. ` #include using namespace std; int add (int a, int b) { int r; r=a+b; return (r); } int ssub (int a, int b) { int r; r=a-b; return (r); } int mult(int a, int b) { int r; r=a*b; return (r); } int menu(int a, int b){ int r; char x; cout <<"What do you want to do: \na.Adding \n s. Substract \n m. Multiply. \n. e. Exit"<<endl; cin>>x; switch (x){ case 'a': cout << "Give a value for a"<<endl; cin>>a; cout <<"Give a value for b"<<endl; cin>>b; add (int a, int b); //aquí y en otras líneas me sale: expected primary expression before int. break; case 's': cout << "Give a value for a"<<endl; cin>>a; cout <<"Give a value for b"<<endl; cin>>b; ssub (int a, int b); break; case 'm': cout << "Give a value for a"<<endl; cin>>a; cout <<"Give a value for b"<<endl; cin>>b; mult (int a, int b); break; case 'e': x='e'; break; default: cout<<"Wrong choice. Run the program again and choose another letter"<<endl; break; } return r; } cout<<"The result is " << menu (int a, int b)<<endl; int main() { menu (int a, int b); return 0; } `

  Read the article

• Table Design for (Currently Viewing Videos)?

  - by Surya sasidhar

  hi, I am doing a project on video portal, in that i am trying to place for currently viewing videos. People who r currently viewing that video. For this i have design the table like this table:(columns) Sno,videoid,sessionid,userid,createddate these are the columns but it is not sufficient i think if possible can u help me how can i design the table. how can we perfectly represent the currently viewing videos. Please help me thank you

  Read the article

• lambda expression based reflection vs normal reflection

  - by bitbonk

  What is the difference between normal reflection and the reflection that can be done with lambda expressions such as this (taken form build your own MVVM): public void NotifyOfPropertyChange<TProperty>(Expression<Func<TProperty>> property) { var lambda = (LambdaExpression)property; MemberExpression memberExpression; if (lambda.Body is UnaryExpression) { var unaryExpression = (UnaryExpression)lambda.Body; memberExpression = (MemberExpression)unaryExpression.Operand; } else memberExpression = (MemberExpression)lambda.Body; NotifyOfPropertyChange(memberExpression.Member.Name); } Is the lambda based reflection just using the normal reflection APIs internally? Or is this something significantly different. What is ther perfomance difference?

  Read the article

• Common lisp error: "should be lambda expression"

  - by Zachary

  I just started learning Common Lisp a few days ago, and I'm trying to build a function that inserts a number into a tree. I'm getting an error, * - SYSTEM::%EXPAND-FORM: (CONS NIL LST) should be a lambda expression From googling around, it seems like this happens when you have too many sets of parenthesis, but after looking at this for an hour or so and changing things around, I can't figure out where I could be doing this. This is the code where it's happening: (defun insert (lst probe) (cond ((null lst) (cons probe lst)) ((equal (length lst) 1) (if (<= probe (first lst)) (cons probe lst) (append lst (list probe)))) ((equal (length lst) 2) ((cons nil lst) (append lst nil) (insertat nil lst 3) (cond ((<= probe (second lst)) (insert (first lst) probe)) ((> probe (fourth lst)) (insert (fifth lst) probe)) (t (insert (third lst) probe))))))) I'm pretty sure it's occurring after the ((equal (length lst) 2), where the idea is to insert an empty list into the existing list, then append an empty list onto the end, then insert an empty list into the middle.

  Read the article

• How to cut a URL with regular expression

  - by AhmadAssaf

  Hello, i am trying to chop a string that contains several information in java .. the text is something like that : <a href="http://www.hootsuite.com" rel="nofollow">HootSuite</a> i am thinking of using the .split method that need regular expression .. what i want it to split this string into the URL without quotes .. http://...... .com and then the text between the tags .. this case HootSuite .. i will appreciate the help Thank you

  Read the article

• HtmlAgilityPack SelectNodes expression to ignore an element with a certain attribute

  - by thaky

  I am trying to select nodes except from script nodes and a ul that has a class called 'relativeNav'. Can someone please direct me to the right path? I have been searching for this for a week and I can't find it anywhere. Currently I have this but it obviously selecting the //ul[@class='relativeNav'] as well. Is there anyway to put an NOT expression of it so that SelectNode will ignore that one? foreach (HtmlNode node in doc.DocumentNode.SelectNodes("//body//*[not(self::script)]/text()")) { Console.WriteLine("Node: " + node); singleString += node.InnerText.Trim() + "\n"; }

  Read the article

• Missing Java error on conditional expression?

  - by Federico Cristina

  With methods test1() and test2(), I get a Type Mismatch Error: Cannot convert from null to int, which is correct; but why am I not getting the same in method test3()? How does Java evaluates the conditional expression differently in that case? (obviusly, a NullPointerException will rise in runtime). Is it a missing error? public class Test { public int test1(int param) { return null; } public int test2(int param) { if (param > 0) return param; return null; } public int test3(int param) { return (param > 0 ? return param : return null); } } Thanks in advance!

  Read the article

• LINQ Expression not evaluating correctly

  - by WedTM

  I have the following LINQ expression that's not returning the appropriate response var query = from quote in db.Quotes where quote.QuoteStatus == "Estimating" || quote.QuoteStatus == "Rejected" from emp in db.Employees where emp.EmployeeID == quote.EmployeeID orderby quote.QuoteID descending select new { quote.QuoteID, quote.DateDue, Company = quote.Company.CompanyName, Attachments = quote.Attachments.Count, Employee = emp.FullName, Estimator = (quote.EstimatorID != null && quote.EstimatorID != String.Empty) ? db.Employees.Single (c => c.EmployeeID == quote.EstimatorID).FullName : "Unassigned", Status = quote.QuoteStatus, Priority = quote.Priority }; The problem lies in the Estimator = (quote.EstimatorID != null && quote.EstimatorID != String.Empty) ? db.Employees.Single(c => c.EmployeeID == quote.EstimatorID).FullName : "Unassigned" part. I NEVER get it to evalueate to "Unassigned", on the ones that are supposed to, it just returns null. Have I written this wrong?

  Read the article

• help converting sql to linq expression with count

  - by Philip

  I am trying to convert the following SQL into a LINQ expression SELECT COUNT(ID) AS Count, MyCode FROM dbo.Archive WHERE DateSent=@DateStartMonth AND DateSent<=@DateEndMonth GROUP BY MyCode and I have been trying to follow this webpage as an example http://stackoverflow.com/questions/606124/converting-sql-containing-top-count-group-and-order-to-linq-2-entities I got this so far but I am stuck on understanding the new part var res=(from p in db.Archives where (p.DateSent>= dateStartMonth) && (p.DateSent< dateToday) group p by p.MyCode into g select new { ??????MyCode = g.something?, MonthlyCount= g.Count() }); Thanks in advance for helping greatly appreciated Philip

  Read the article

• entity framework, loadproperty not working - The selector expression for LoadProperty must be a Memb

  - by SLC

  The selector expression for LoadProperty must be a MemberAccess for the property. I'm converting some C# to VB, this is the C# line: entities.LoadProperty((MyType)MyTargetObject, c => c.MyProperty); I convert it to VB like so: entities.LoadProperty(DirectCast(MyTargetObject, MyType), Function(c) c.MyProperty) However I get the error above. I don't understand what the code is doing, or anything at all, I am simply converting it line by line into Visual Basic. When I run the project, the error I get is the one above. All I can see is that Entities is a class that inherits ObjectContext, which might mean something. Any help would be soooo good because I am stressing out big time. Thanks.

  Read the article

• Use of "setTimeout()" in my jQuery Expression

  - by Aaron Salazar

  I'm trying to add the JavaScript function setTimeout() to my jQuery expression. Without the setTimeout() my function loads a partial view with updated information when I enter text into my textbox. But, it loads the information with every keystroke. My logic is that if I can put in a timer then when the user stops typing, a second later the data is updated. As you can see I tried to put a setTimer() in but it doesn't seem to be working. $(function() { $('#DocId').live('keyup', function() { setTimeout(var styleValue = $(this).val(); $('#tableContent').load( '/CurReport/TableResults', { style: $(this).val()}), 1000); }), }); Thank you, Aaron

  Read the article

• php regex expression to get title

  - by 55skidoo

  I'm trying to strip content titles out of the middle of text strings. Could I use regex to strip everything out of this string except for the title (in italics) in these strings? Or is there a better way? Joe User wrote a blog post called The 10 Best Regex Expressions in the category Regex. Jane User wrote a blog post called Regex is Hard! in the category TechProblems. I've tried to come up with a regex expression to cover this, but I think it might need two. The trick is that the text in bold is always the same, so you could search for that, like this: regex: delete everything before and including wrote a blog post called regex: delete in the category and everything after it.

  Read the article

• regular expression to read the string between <title> and </title>

  - by user262325

  Hello every one I hope to read the contents between and in a html string. I think it should be in objective-c @"<title([\\s\\S]*)</title>" below are the codes that rewrited for regular expression //source of NSStringCategory.h #import <Foundation/Foundation.h> #import <regex.h> @interface NSStringCategory:NSObject { regex_t preg; } -(id)initWithPattern:(NSString *)pattern options:(int)options; -(void)dealloc; -(BOOL)matchesString:(NSString *)string; -(NSString *)matchedSubstringOfString:(NSString *)string; -(NSArray *)capturedSubstringsOfString:(NSString *)string; +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options; +(NSStringCategory *)regexWithPattern:(NSString *)pattern; +(NSString *)null; +(void)initialize; @end @interface NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options; -(BOOL)matchedByPattern:(NSString *)pattern; -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options; -(NSString *)substringMatchedByPattern:(NSString *)pattern; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern; -(NSString *)escapedPattern; @end and .m file #import "NSStringCategory.h" static NSString *nullstring=nil; @implementation NSStringCategory -(id)initWithPattern:(NSString *)pattern options:(int)options { if(self=[super init]) { int err=regcomp(&preg,[pattern UTF8String],options|REG_EXTENDED); if(err) { char errbuf[256]; regerror(err,&preg,errbuf,sizeof(errbuf)); [NSException raise:@"CSRegexException" format:@"Could not compile regex \"%@\": %s",pattern,errbuf]; } } return self; } -(void)dealloc { regfree(&preg); [super dealloc]; } -(BOOL)matchesString:(NSString *)string { if(regexec(&preg,[string UTF8String],0,NULL,0)==0) return YES; return NO; } -(NSString *)matchedSubstringOfString:(NSString *)string { const char *cstr=[string UTF8String]; regmatch_t match; if(regexec(&preg,cstr,1,&match,0)==0) { return [[[NSString alloc] initWithBytes:cstr+match.rm_so length:match.rm_eo-match.rm_so encoding:NSUTF8StringEncoding] autorelease]; } return nil; } -(NSArray *)capturedSubstringsOfString:(NSString *)string { const char *cstr=[string UTF8String]; int num=preg.re_nsub+1; regmatch_t *matches=calloc(sizeof(regmatch_t),num); if(regexec(&preg,cstr,num,matches,0)==0) { NSMutableArray *array=[NSMutableArray arrayWithCapacity:num]; int i; for(i=0;i<num;i++) { NSString *str; if(matches[i].rm_so==-1&&matches[i].rm_eo==-1) str=nullstring; else str=[[[NSString alloc] initWithBytes:cstr+matches[i].rm_so length:matches[i].rm_eo-matches[i].rm_so encoding:NSUTF8StringEncoding] autorelease]; [array addObject:str]; } free(matches); return [NSArray arrayWithArray:array]; } free(matches); return nil; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options { return [[[NSStringCategory alloc] initWithPattern:pattern options:options] autorelease]; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern { return [[[NSStringCategory alloc] initWithPattern:pattern options:0] autorelease]; } +(NSString *)null { return nullstring; } +(void)initialize { if(!nullstring) nullstring=[[NSString alloc] initWithString:@""]; } @end @implementation NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options|REG_NOSUB]; return [re matchesString:self]; } -(BOOL)matchedByPattern:(NSString *)pattern { return [self matchedByPattern:pattern options:0]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re matchedSubstringOfString:self]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern { return [self substringMatchedByPattern:pattern options:0]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re capturedSubstringsOfString:self]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern { return [self substringsCapturedByPattern:pattern options:0]; } -(NSString *)escapedPattern { int len=[self length]; NSMutableString *escaped=[NSMutableString stringWithCapacity:len]; for(int i=0;i<len;i++) { unichar c=[self characterAtIndex:i]; if(c=='^'||c=='.'||c=='['||c=='$'||c=='('||c==')' ||c=='|'||c=='*'||c=='+'||c=='?'||c=='{'||c=='\\') [escaped appendFormat:@"\\%C",c]; else [escaped appendFormat:@"%C",c]; } return [NSString stringWithString:escaped]; } @end I use the codes below to get the string between "" and "" NSStringCategory *a=[[NSStringCategory alloc] initWithPattern:@"<title([\s\S]*)</title>" options:0];// Unfortunately [a matchedSubstringOfString:response]] always returns nil I do not if the regular expression is wrong or any other reason. Welcome any comment Thanks interdev

  Read the article

• Regular expression replace in PL/pgSQL

  - by dreamlax

  If I have the following input (excluding quotes): "The ancestral territorial imperatives of the trumpeter swan" How can I collapse all multiple spaces to a single space so that the input is transformed to: "The ancestral territorial imperatives of the trumpeter swan" This is going to be used in a trigger function on insert/update (which already trims leading/trailing spaces). Currently, it raises an exception if the input contains multiple adjacent spaces, but I would rather it simply transforms it into something valid before inserting. What is the best approach? I can't seem to find a regular-expression replace function for PL/pgSQL. There is a text_replace function, but this will only collapse at most two spaces down to one (meaning three consecutive spaces will collapse to two). Calling this function over and over is not ideal.

  Read the article

• Regular expression in C#

  - by user340015

  i have text something like this. @@MMIVLoader@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@MMIVLib@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@HuaweFGDLDrv@[email protected]@7324@PRODUCT@Aug 20 2009@ @@ProtectVer@[email protected] @BCM_SDE5.03@PRODUCT@Aug 4 2009 06:56:19@ @@KernelSw@[email protected]@BCM-7454@PRODUCT@ Dec 19 2007@ @@ReceiverSw@[email protected]@HWBC01ZS@PRODUCT@May 3 2010@ i want the out put in an array like MMIVLoader 4.1.2 MMIVLib 4.1.2 HuaweFGDLDrv 01.00.09 ProtectVer 127.8.1 KernelSw 0.0.1 ReceiverSw E.5.6.001 Can any one suggest me how to do this in c# using regular expression or is there a any sophisticated way to do this thanks in advance

  Read the article

• OSLO, ANTLR or other parser grammar, for parsing QUERY EXPRESSION

  - by Jay Allard

  Greetings I'm working on a project that requires me to write queries in text form, then convert them to some easily processed nodes to be processed by some abiguous repository. Of everything there, the part I'm least interested is the part that converts the text to nodes. I'm hoping it's already done somewhere. Because I'm making stuff up as I go, I chose to use a LINQish expression syntax. from m in Movie select m.A, m.B I started parsing it manually and got the basics, but it's pretty cheesy. I'm looking for the better solution. I made some progress using MGrammar, but it would be nice if such a thing already existed. Does anyone know of anything that already does this? I looked for existing ANTLR templates, but no luck. Thanks for the help.

  Read the article

• PHP Form Validation Regular Expression, no symbols or numbers

  - by MrEnder

  Ok I am trying to get the users First Name the form gets their name perfectly fine and posts it into a variable. Now I am trying to do error checking else if(!preg_match("/^[\w-]+$/", $firstNameSignup)) { $firstNameSignupError = "Your first name cannot contain numbers or symbols, you entered " . $firstNameSignup; $firstNameSignup = ""; } I tried the above code and it does not like me but my if statement if(!isset($firstNameSignup) || $firstNameSignup == "") { $firstNameSignupError = "You must enter your first name"; } works fine so I know that the error is in that else if statement... most likely in my regular expression any help??? I'm totally at a loss (really new to PHP and regular expressions) Thanks Shelby

  Read the article

• JavaScript String Replace with a tricky regular expression

  - by Juri

  Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

  Read the article

• How to use a variable in an awk expression

  - by lugte098

  I'm trying to make this command: sed bla bla filename | awk '{printf "%s %s_entry_%.3f %.3f %.3f %.3f",$1,$3,$4,$5,$6,$7}' But the thing is, i want the %.3f part to be variable. So in one case it could be %.3f and in another it could be %.3f %.3f %.3f. So i'll just use a static one in my example code for clarity. So if i want 4 of these %.3f and put them in variable $values like so: values="%.3f %.3f %.3f %.3f" Then how can i put this string in the awk expression, without making awk to just put literally "${values}" in there. The following is my non-working-attempt: sed bla bla filename | awk '{printf "%s %s_entry_${values}",$1,$3,$4,$5,$6,$7}'

  Read the article

• C# Lambda Expression Speed

  - by Nathan

  I have not used many lambda expressions before and I ran into a case where I thought I could make slick use of one. I have a custom list of ~19,000 records and I need to find out if a record exists or not in the list so instead of writing a bunch of loops or using linq to go through the list I decided to try this: for (int i = MinX; i <= MaxX; ++i) { tempY = MinY; while (tempY <= MaxY) { bool exists = myList.Exists(item => item.XCoord == i && item.YCoord == tempY); ++tempY; } } Only problem is it take ~9 - 11 seconds to execute. Am I doing something wrong is this just a case of where I shouldn't be using an expression like this? Thanks.

  Read the article

• Evaluating a regular expression range

  - by Dan Atkinson

  Hi there! Is there a nice way to evaluate a regular expression range, say, for a url such as http://example.com/[a-z]/[0-9].htm This would be converted into: http://example.com/a/0.htm http://example.com/a/1.htm http://example.com/a/2.htm ... http://example.com/a/9.htm ... http://example.com/z/0.htm http://example.com/z/1.htm http://example.com/z/2.htm ... http://example.com/z/9.htm I've been scratching my head about this, and there's no pretty way of doing it without going through the alphabet and looping through numbers. Thanks in advance!

  Read the article

• A regular expression that will allow a string with only one Capital Letter

  - by Phoenix

  The string should be 6 - 20 characters in length. And it should contain 1 Capital letter. I can do this in code using C# string st = "SomeString" Regex rg = new Regex("[A-Z]"); MatchCollection mc = rg.Matches(st); Console.WriteLine("Total Capital Letters: " + mc.Count); if (mc.Count > 1) { return false; } But what i really want is a Regular expression that will match my string if it only contains one capital. The string can start with a common letter and should have only letters. Thanks In advance. (I did look at some of the other RegEx questions but they did not help).

  Read the article

• Regex-expression with danish characters

  - by timkl

  I'm currently trying to wrap my head around regex, I have a validation snippet that tests an input box against a regex-expression: $.validator.addMethod("customerName", function(value, element){ return (/^[a-zA-Z]*$/).test(value); }, "Some text"); That works well, but when I try to add a space and some special danish characters, it doesn't filter the danish characters, only the space. $.validator.addMethod("customerName", function(value, element){ return (/^[a-zA-Z æøåÆØÅ]*$/).test(value); }, "Some text"); Any ideas to what could be wrong?

  Read the article

• Racket regular-expression matching

  - by Inaimathi

  I'm trying to create a regex that matches the inverse of a certain string type (so, strings not ending in ".js", for example). According to the documentation, that should be the expression #rx"(?!\\.js$)", but it doesn't seem to work. To test it out, I have this function: (define (match-test regex) (map (lambda (text) (regexp-match? regex text)) '("foo.js" "bar.css" "baz.html" "mumble.gif" "foobar"))) (match-test #rx"\\.js$") returns (#t #f #f #f #f) as expected, but (match-test #rx"(?!\\.js$)") returns (#t #t #t #t #t), where I would expect (#f #t #t #t #t). What am I doing wrong, and how do I actually get a regex in Racket to express the idea "match anything which does not contain [x]"?

  Read the article

< Previous Page | 117 118 119 120 121 122 123 124 125 126 127 128  | Next Page >