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  • Game of life in F# with accelerator

    - by jpalmer
    I'm trying to write life in F# using accelerator v2, but for some odd reason my output isn't square despite all my arrays being square - It appears that everything but a rectangular area in the top left of the matrix is being set to false. I've got no idea how this could be happening as all my operations should treat the entire array equally. Any ideas? open Microsoft.ParallelArrays open System.Windows.Forms open System.Drawing type IPA = IntParallelArray type BPA = BoolParallelArray type PAops = ParallelArrays let RNG = new System.Random() let size = 1024 let arrinit i = Array2D.init size size (fun x y -> i) let target = new DX9Target() let threearr = new IPA(arrinit 3) let twoarr = new IPA(arrinit 2) let onearr = new IPA(arrinit 1) let zeroarr = new IPA(arrinit 0) let shifts = [|-1;-1|]::[|-1;0|]::[|-1;1|]::[|0;-1|]::[|0;1|]::[|1;-1|]::[|1;0|]::[|1;1|]::[] let progress (arr:BPA) = let sums = shifts //adds up whether a neighbor is on or not |> List.fold (fun (state:IPA) t ->PAops.Add(PAops.Cond(PAops.Rotate(arr,t),onearr,zeroarr),state)) zeroarr PAops.Or(PAops.CompareEqual(sums,threearr),PAops.And(PAops.CompareEqual(sums,twoarr),arr)) //rule for life let initrandom () = Array2D.init size size (fun x y -> if RNG.NextDouble() > 0.5 then true else false) type meform () as self= inherit Form() let mutable array = new BoolParallelArray(initrandom()) let timer = new System.Timers.Timer(1.0) //redrawing timer do base.DoubleBuffered <- true do base.Size <- Size(size,size) do timer.Elapsed.Add(fun _ -> self.Invalidate()) do timer.Start() let draw (t:Graphics) = array <- array |> progress let bmap = new System.Drawing.Bitmap(size,size) target.ToArray2D array |> Array2D.iteri (fun x y t -> if not t then bmap.SetPixel(x,y,Color.Black)) t.DrawImageUnscaled(bmap,0,0) do self.Paint.Add(fun t -> draw t.Graphics) do Application.Run(new meform())

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  • How can I determine the sector size on an external hard drive?

    - by sigint
    Hard drives are transitioning from 512 byte to 4096 byte sector sizes, and it looks like Windows XP won't support these newer drives without additional software (such as WDalign from Western Digital) My question is: how does this affect external hard drives? I'll be buying a 1TB USB external drive, and it'll be plugged into a mix of Windows 7 and XP machines. Is there an easy way to tell what the sector size on an external hard drive is?

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  • how to initialize and implement the matrix inside the function in objective-C?

    - by Rajendra Bhole
    Hi, I want to develop an application in which i want to be initialize the matrix for manipulation. The code as follows, struct pixel { Byte r, g, b,a; int count; }; (NSInteger) processImage1: (UIImage*) image { struct pixel* pixels = (struct pixel*) calloc(1, image.size.width * image.size.height * sizeof(struct pixel)); if (pixels != nil) { // Create a new bitmap CGContextRef context = CGBitmapContextCreate( (void*) pixels, image.size.width, image.size.height, 8, image.size.width * 4, CGImageGetColorSpace(image.CGImage), kCGImageAlphaPremultipliedLast ); if (context != NULL) { // Draw the image in the bitmap CGContextDrawImage(context, CGRectMake(0.0f, 0.0f, image.size.width, image.size.height), image.CGImage); NSUInteger numberOfPixels = image.size.width * image.size.height; while (numberOfPixels &gt; 0) { if (pixels->r == 254 || pixels->g == 77 || pixels->b==254) { numberOfRedPixels++; } pixels++; numberOfPixels--; } CGContextRelease(context); } free(pixels); } return 1; } I want to implement the matrix inside the function of - (NSInteger) processImage1: (UIImage*) image {} The matrix should have be row = image.size.width and column = image.size.height.

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  • How I can determine the sector size on an external hard drive?

    - by sigint
    Hard drives are transitioning from 512 byte to 4096 byte sector sizes, and it looks like Windows XP won't support these newer drives without additional software (such as WDalign from Western Digital) My question is: how does this affect external hard drives? I'll be buying a 1TB USB external drive, and it'll be plugged into a mix of Windows 7 and XP machines. Is there an easy way to tell what the sector size on an external hard drive is?

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  • How do I reliably get the size of my iPhone view taking rotations into consideration?

    - by Sebastian Celis
    My application uses a UITabBarController, multiple UINavigationControllers, and supports autorotation. In order to properly layout the subviews within each UIViewController's main view, I really need to know the size available to the UIViewContoller. I need this size to take the UINavigationBar, the UITabBar, and the status bar all into account, and thus only return the size available to the content view. I thought for sure I could use the following from within the UIViewController's code: CGRect viewControllerBounds = [[self view] bounds]; However, there are a couple of issues with this approach: The first time the view is loaded, viewControllerBounds reports the view as being 320 pixels wide by 460 pixels tall. This is wrong. With a status bar and a navigation bar showing, the height should only be 416 pixels. However, if I rotate the simulator to landscape and then rotate back, the height of viewControllerBounds changes to 416. If I rotate the first view in the navigation controller to landscape mode and then push another view controller onto the stack, viewControllerBounds for the new view reports a width of 300 pixels and a height of 480 pixels. So the view's bounds didn't even take the rotation into account. Is there a better way to do this? I really don't want to have to start hardcoding the widths and heights of all the various UI elements the iPhone OS provides. I have tried setting the autoresizing mask of the UIViewController's view, but that doesn't seem to change anything. The views definitely seem to be displaying properly. When I set a background color that view looks like it takes up all of the space available to it. Any pointers would be greatly appreciated.

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  • How to compress / reduce the size of JPEG photos for archiving?

    - by Timo Huovinen
    I have 50,000 high resolution JPEG photos, where a couple of them might occasionally be needed, about once a year. I wanted to zip them to save disk space, except that zipping gives no space benefit - so trying to reduce the images disk usage using winzip, winrar or 7zip was not successful. Is there any software or algorithm similar to zip to compress image size on hard disk for storage without loosing any image information?

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  • Inconsistent Frame / Bounds of UIImage and UIScrollView

    - by iFloh
    this one puzzles me. I have an Image with a width of 1600 pixels and height of 1819 pixels. I load the image as UIImageView into an UIScrollView and set the "contentsize parameter" iKarteScrollView.contentSize = CGSizeMake(iKarteImageView.bounds.size.width, iKarteImageView.bounds.size.height); NSLog(@"Frame - width %.6f, height %.6f - Bounds - width %.6f, height %.6f", myImageView.frame.size.width, myView.frame.size.height, myImageView.bounds.size.width, myImageView.bounds.size.height); NSLog(@"Content size width %.6f, height %.6f", myScrollView.contentSize.width, myScrollView.contentSize.height); The NSLog shows the following: Frame - width 1600.000000, height 1819.000000 - Bounds - width 1600.000000, height 1819.000000 Content size width 1600.000000, height 1819.000000 Now comes the miracle, in a subsequent method of the same object I call the same NSLog again. But this time the result is Frame - width 405.000000, height 411.000000 - Bounds - width 1601.510864, height 1625.236938 Content size width 404.617920, height 460.000000 Why is the frame size suddely 405 by 411 pixels? How can the Bounds be 1601 by 1625 where 1625 is roughly 200 pixels less than the original size? When Positioning a further UIImageView at the coordinates of 20 by 1625, the UIImageView is displayed an estimated 200 pixels above the bottom of the content of the UIScrollView. I'm lost ...

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  • The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs

    - by Matthew Chambers
    Hello I am getting the below message on a table i am trying to create The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs Anyone know the answer to this please -- Table warrington_central.job -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS warrington_central.job ( id MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT , alias_title VARCHAR(255) NOT NULL , reference_number VARCHAR(100) NOT NULL , title VARCHAR(255) NOT NULL , primary_category SMALLINT(5) UNSIGNED NOT NULL , secondary_category SMALLINT(5) UNSIGNED NOT NULL , tertiary_category SMALLINT(5) UNSIGNED NULL , address_id BIGINT(20) UNSIGNED NOT NULL , geolocation_id BIGINT(20) UNSIGNED NULL , company VARCHAR(255) NOT NULL , description VARCHAR(10000) NOT NULL , skills_required VARCHAR(10000) NOT NULL , job_type TINYINT(2) UNSIGNED NOT NULL , experience_months_required TINYINT(2) UNSIGNED NOT NULL , experience_years_required TINYINT(2) UNSIGNED NOT NULL , salary_range VARCHAR(30) NOT NULL , extra_benefits_above_salary VARCHAR(500) NOT NULL , available_from DATE NULL , available_to DATE NULL , extra_location_details VARCHAR(1000) NOT NULL , contact_email VARCHAR(100) NOT NULL , contact_phone_number VARCHAR(20) NOT NULL , contact_mobile_number VARCHAR(20) NOT NULL , terms_conditions_application VARCHAR(5000) NOT NULL , link_to_profile ENUM('0','1') NOT NULL , created_on DATETIME NOT NULL , updated_on DATETIME NOT NULL , updated_by BIGINT(20) UNSIGNED NOT NULL , add_contact_form ENUM('0','1') NOT NULL , admin_package_id TINYINT(1) UNSIGNED NOT NULL , package_start_date DATETIME NOT NULL , package_end_date DATETIME NULL , package_comment VARCHAR(500) NOT NULL , viewable_to_members_only ENUM('0','1') NOT NULL , advertise_to DATETIME NULL , show_comment ENUM('0','1') NOT NULL , hits BIGINT(20) UNSIGNED NOT NULL DEFAULT 0 , visible ENUM('0','1') NOT NULL DEFAULT '0' , approved ENUM('I/* large SQL query (3.9 KB), snipped at 2,000 characters / / SQL Error (1118): Row size too large. The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs */ SHOW WARNINGS;

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  • Why do C# containers and GUI classes use int and not uint for size related members ?

    - by smerlin
    I usually program in C++, but for school i have to do a project in C#. So i went ahead and coded like i was used to in C++, but was surprised when the compiler complained about code like the following: const uint size = 10; ArrayList myarray = new ArrayList(size); //Arg 1: cannot convert from 'uint' to 'int Ok they expect int as argument type, but why ? I would feel much more comfortable with uint as argument type, because uint fits much better in this case. Why do they use int as argument type pretty much everywhere in the .NET library even if though for many cases negative numbers dont make any sense (since no container nor gui element can have a negative size). If the reason that they used int is, that they didnt expect that the average user cares about signedness, why didnt they add overloads for uint additonally ? Is this just MS not caring about sign correctness or are there cases where negative values make some sense/ carry some information (error code ????) for container/gui widget/... sizes ?

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  • Splitting a set of object into several subsets of 'similar' objects

    - by doublep
    Suppose I have a set of objects, S. There is an algorithm f that, given a set S builds certain data structure D on it: f(S) = D. If S is large and/or contains vastly different objects, D becomes large, to the point of being unusable (i.e. not fitting in allotted memory). To overcome this, I split S into several non-intersecting subsets: S = S1 + S2 + ... + Sn and build Di for each subset. Using n structures is less efficient than using one, but at least this way I can fit into memory constraints. Since size of f(S) grows faster than S itself, combined size of Di is much less than size of D. However, it is still desirable to reduce n, i.e. the number of subsets; or reduce the combined size of Di. For this, I need to split S in such a way that each Si contains "similar" objects, because then f will produce a smaller output structure if input objects are "similar enough" to each other. The problems is that while "similarity" of objects in S and size of f(S) do correlate, there is no way to compute the latter other than just evaluating f(S), and f is not quite fast. Algorithm I have currently is to iteratively add each next object from S into one of Si, so that this results in the least possible (at this stage) increase in combined Di size: for x in S: i = such i that size(f(Si + {x})) - size(f(Si)) is min Si = Si + {x} This gives practically useful results, but certainly pretty far from optimum (i.e. the minimal possible combined size). Also, this is slow. To speed up somewhat, I compute size(f(Si + {x})) - size(f(Si)) only for those i where x is "similar enough" to objects already in Si. Is there any standard approach to such kinds of problems? I know of branch and bounds algorithm family, but it cannot be applied here because it would be prohibitively slow. My guess is that it is simply not possible to compute optimal distribution of S into Si in reasonable time. But is there some common iteratively improving algorithm?

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  • How to get the size of a binary tree ?

    - by Andrei Ciobanu
    I have a very simple binary tree structure, something like: struct nmbintree_s { unsigned int size; int (*cmp)(const void *e1, const void *e2); void (*destructor)(void *data); nmbintree_node *root; }; struct nmbintree_node_s { void *data; struct nmbintree_node_s *right; struct nmbintree_node_s *left; }; Sometimes i need to extract a 'tree' from another and i need to get the size to the 'extracted tree' in order to update the size of the initial 'tree' . I was thinking on two approaches: 1) Using a recursive function, something like: unsigned int nmbintree_size(struct nmbintree_node* node) { if (node==NULL) { return(0); } return( nmbintree_size(node->left) + nmbintree_size(node->right) + 1 ); } 2) A preorder / inorder / postorder traversal done in an iterative way (using stack / queue) + counting the nodes. What approach do you think is more 'memory failure proof' / performant ? Any other suggestions / tips ? NOTE: I am probably going to use this implementation in the future for small projects of mine. So I don't want to unexpectedly fail :).

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  • Which software is used to publish a book of size A5.

    - by Mirage
    I have some text and i want to make book of A5 size. The fonts is also not english its in my own language. Which software should i use to make a soft copy. And how can i give them to print shop so that they can print with some images and required fonts which will not be in their computer

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  • How can I determine the sector size on an external hard drive?

    - by sigint
    Hard drives are transitioning from 512 byte to 4096 byte sector sizes, and it looks like Windows XP won't support these newer drives without additional software (such as WDalign from Western Digital) My question is: how does this affect external hard drives? I'll be buying a 1TB USB external drive, and it'll be plugged into a mix of Windows 7 and XP machines. Is there an easy way to tell what the sector size on an external hard drive is?

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  • How do i return a template class from a template function?

    - by LoudNPossiblyRight
    It looks logical but for some reason when i uncomment the last cout line, this code does not compile. How do i return a template class? What do i have to do to this code to make it work? #include<iostream> using namespace std; template <int x> class someclass{ public: int size; int intarr[x]; someclass():size(x){} }; template<int x, int y> int somefunc(someclass<x> A, someclass<y> B){ return ( A.size > B.size ? A.size : B.size); } template<int x, int y, int z> someclass<x> anotherfunc(someclass<y> A, someclass<z> B){ return ( A.size > B.size ? A : B); } int main(){ someclass<5> A; someclass<10> B; cout << "SIZE = " << somefunc(A,B) << endl; //cout << "SIZE = " << (anotherfunc(A,B)).size << endl; //THIS DOES NOT COMPILE return 0; }

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  • C++ Array vs vector

    - by blue_river
    when using C++ vector, time spent is 718 milliseconds, while when I use Array, time is almost 0 milliseconds. Why so much performance difference? int _tmain(int argc, _TCHAR* argv[]) { const int size = 10000; clock_t start, end; start = clock(); vector<int> v(size*size); for(int i = 0; i < size; i++) { for(int j = 0; j < size; j++) { v[i*size+j] = 1; } } end = clock(); cout<< (end - start) <<" milliseconds."<<endl; // 718 milliseconds int f = 0; start = clock(); int arr[size*size]; for(int i = 0; i < size; i++) { for(int j = 0; j < size; j++) { arr[i*size+j] = 1; } } end = clock(); cout<< ( end - start) <<" milliseconds."<<endl; // 0 milliseconds return 0; }

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  • How can I set a minimum thumbnail size with ImageMagick?

    - by Zilk
    I'm trying to create thumbnails of JPG photos using ImageMagick's convert tool. The thumbnails need to have a defined size (210x159), no blank areas, and the image can be cropped if necessary. Unfortunately, I only have ImageMagick 6.3.7 available, which doesn't support the '^' geometry modifier (added in v6.3.8-3). Is there another way to achieve this in earlier versions of ImageMagick? Thanks in advance.

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  • Update on: How to model random non-overlapping spheres of non-uniform size in a cube using Matlab?

    - by user3838079
    I am trying to use MATLAB for generating random locations for non-uniform size spheres (non-overlapping) in a cube. The for loop in the code below never seems to end. I don't know what am missing in the code. I have ran the code for no. of spheres (n) = 10; dims = [ 10 10 10 ] function [ c r ] = randomSphere( dims ) % creating one sphere at random inside [0..dims(1)]x[0..dims(2)]x... % radius and center coordinates are sampled from a uniform distribution % over the relevant domain. % output: c - center of sphere (vector cx, cy,... ) % r - radius of sphere (scalar) r = rand(1); % you might want to scale this w.r.t dims or other consideration c = r + rand( size(dims) )./( dims - 2*r ); % make sure sphere does not exceed boundaries function ovlp = nonOverlapping( centers, rads ) % check if several spheres with centers and rads overlap or not ovlp = false; if numel( rads ) == 1 return; % nothing to check for a single sphere end dst = sqrt( sum( bsxfun( @minus, permute( centers, [1 3 2] ),... permute( centers, [3 1 2] ) ).^2, 3) ); ovlp = dst >= bsxfun( @plus, rads, rads.' ); %' all distances must be smaller than r1+r2 ovlp = any( ovlp(:) ); % all must not overlap function [centers rads] = sampleSpheres( dims, n ) % dims is assumed to be a row vector of size 1-by-ndim % preallocate ndim = numel(dims); centers = zeros( n, ndim ); rads = zeros( n, 1 ); ii = 1; while ii <= n [centers(ii,:), rads(ii) ] = randomSphere( dims ); if nonOverlapping( centers(1:ii,:), rads(1:ii) ) ii = ii + 1; % accept and move on end end

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  • Is it possible to change the Raid5 chunk size of an existing device?

    - by AlexCombas
    I have an existing raid5 device which I created using mdadm on Linux. When I created the device I set the chunk size to 64 but I would like to test the performance of various sizes but I don't want to have to rebuild my entire system to do so. If it is not possible to do it live then is it possible to do this by booting with a rescue disk? Any advice on the steps how to do this, either live or with a rescue disk, will be greatly appreciated.

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