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  • Please help on multiple match replacement

    - by duenguyen
    I have a perl code: my $s = "The+quick+brown+fox+jumps+over+the+lazy+dog+that+is+my+dog"; what I want is to replace every + with space and dog with cat i have this regular expression $s =~ s/+(.*)dog/ ${1}cat/g; But it only match first occurrence of + and last dog. Please help

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  • How to do a NotEqual to in NHibernate

    - by Blankman
    I have an enumeration of type int in my entity, UserStatus. I want to get all users where the UserStatus < Cancelled. So: Session.CreateCriteria(typeof(User)) .Add(Expression.Eq("UserStatus", (int)UserStatus.Cancelled) .UniqueResult<User>(); The above is fore equal, I need to get not equal.

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  • preg_match_all image source

    - by David
    I have the following regex expression which is to extract the source of any img tag in HTML. /(<img).*(src\s*=\s*"([a-zA-Z0-9\.;:\/\?&=\-_|\r|\n]{1,})")/isxmU However, it doesn't appear to be matching the following: <IMG SRC='http://www.mysite.com/pix/lens/mtf/CAEF8512L.gif'> How can I build it to match this as well?

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  • regex breaks on \n

    - by Sourabh
    hi segmentText = <input from textarea>; testRgx = [/( \d+\.| [^\W\d_]\.|.)+?([!?.?](?= |$)|$)/g]; arrSegments = segmentText.match(testRgx); This expression fails if segmentText has \n or other white spaces in it.I want to add \n in to the list of chars that the above pattern use [!?.?] = [!?.?\n] so that the segment is separated based on the \n character

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  • Haskell type classes and type families (cont'd)

    - by Giuseppe Maggiore
    I need some help in figuring a compiler error which is really driving me nuts... I have the following type class: infixl 7 --> class Selectable a s b where type Res a s b :: * (-->) :: (CNum n) => (Reference s a) -> (n,(a->b),(a->b->a)) -> Res a s b which I instance twice. First time goes like a charm: instance Selectable a s b where type Res a s b = Reference s b (-->) (Reference get set) (_,read,write) = (Reference (\s -> let (v,s') = get s in (read v,s')) (\s -> \x -> let (v,s') = get s v' = write v x (_,s'') = set s' v' in (x,s''))) since the type checker infers (-->) :: Reference s a -> (n,a->b,a->b->a) -> Reference s b and this signature matches with the class signature for (--) since Res a s b = Reference s b Now I add a second instance and everything breaks: instance (Recursive a, Rec a ~ reca) => Selectable a s (Method reca b c) where type Res a s (Method reca b c) = b -> Reference s c (-->) (Reference get set) (_,read,write) = \(x :: b) -> from_constant( Constant(\(s :: s)-> let (v,s') = get s :: (a,s) m = read v ry = m x :: Reference (reca) c (y,v') = getter ry (cons v) :: (c,reca) v'' = elim v' (_,s'') = set s' v'' in (y,s''))) :: Reference s c the compiler complains that Couldn't match expected type `Res a s (Method reca b c)' against inferred type `b -> Reference s c' The lambda expression `\ (x :: b) -> ...' has one argument, which does not match its type In the expression: \ (x :: b) -> from_constant (Constant (\ (s :: s) -> let ... in ...)) :: Reference s c In the definition of `-->': --> (Reference get set) (_, read, write) = \ (x :: b) -> from_constant (Constant (\ (s :: s) -> ...)) :: Reference s c reading carefully the compiler is telling me that it has inferred the type of (--) thusly: (-->) :: Reference s a -> (n,a->(Method reca b c),a->(Method reca b c)->a) -> (b -> Reference s c) which is correct since Res a s (Method reca b c) = b -> Reference s c but why can't it match the two definitions? Sorry for not offering a more succint and standalone example, but in this case I cannot figure how to do it...

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  • RegEx to reverse order of list?

    - by quantomcat
    Is there a singular regular expression that can be used in, say, a text editor's search/replace dialog to reverse the order of the items in a list? For instance, take this list: First item Second item Third item Select it in a text editor like EditPad, bring up the search and replace box, apply a regex (run as a loop or not) and turn it into: Third item Second item First item Can this be done?

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  • Haskell: Gluing a char and a list together?

    - by Vincent
    So I have this code here: toWords :: String - [a] toWords "" = [] toWords (nr1 : rest) | nr1 == ' ' = toWords rest | otherwise = nr1 : toWords rest The "toWords" function should simply remove all spaces and return a list with all the words. But I keep getting this error: test.hs:5:18: Couldn't match expected type a' against inferred typeChar' `a' is a rigid type variable bound by the type signature for `toWords' at test.hs:1:22 In the first argument of `(:)', namely `nr1' In the expression: nr1 : toWords rest In the definition of `toWords': toWords (nr1 : rest) | nr1 == ' ' = toWords rest | otherwise = nr1 : toWords rest Failed, modules loaded: none.

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  • How can I match a phone number with a regex? [closed]

    - by Zerobu
    Possible Duplicate: A comprehensive regex for phone number validation I would like a regular expression in this format. It Must match one of the following formats: (###)###-#### ###-###-#### ###.###.#### ########## Strip all whitespace. Make sure it's a valid phone number, then (if necessary) translate it to the first format listed above.

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  • Using RegEx to Identify parts of a Database Connection String

    - by David_Jarrett
    I'm trying to get to grips with regular expressions: I have a database connection string and I'd like to use a regular expression to identify specific Keys and Values within it. For example server=foo;database=bar;uid=foo;pwd=bar I'd like something to return "database=bar;" using the 'database' key to identify it, ideally it would be case insensitive. I can do this using normal code, but I think that this is exactly the sort of thing for which regular expressions were designed.

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  • eregi replace replacement

    - by apis17
    hi, since eregi replace was deprecated on version 5.3 i want to make my program compatible with new version of php http://php.net/manual/en/function.eregi-replace.php so, i'm trying to use preg_replace like this preg_replace(",",'','20,000.00'); but come with error i'm familiar with eregi_replace(',','','20,000.00'); i'm not familiar with regex expression. what is the best replacement for eregi_replace?

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  • Regex for Eclipse/Flash Builder File Search for comments?

    - by Brian Bishop
    In Eclipse (and Flash/Flex Builder) you get the option with Ctrl+Shift+F to do a file search and look for a regular expression. Would be a real handy thing to know. I want to find the word negate if it appears in a Flex/java comment like the following: // It was negated because or /* The negate option was.... */ or /** * We have to negate the value */ Any ideas? Will test them out at http://www.regexplanet.com/simple/index.html

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  • How to replace only part of the match with python re.sub

    - by Arty
    I need to match two cases by one reg expression and do replacement 'long.file.name.jpg' - 'long.file.name_suff.jpg' 'long.file.name_a.jpg' - 'long.file.name_suff.jpg' I'm trying to do the following re.sub('(\_a)?\.[^\.]*$' , '_suff.',"long.file.name.jpg") But this is cut the extension '.jpg' and I'm getting long.file.name_suff. instead of long.file.name_suff.jpg I understand that this is because of [^.]*$ part, but I can't exclude it, because I have to find last occurance of '_a' to replace or last '.' Is there a way to replace only part of the match?

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  • Reading a line backwards

    - by Jimmy
    Hi, I'm using regular expression to count the total spaces in a line (first occurrence). match(/^\s*/)[0].length; However this reads it from the start to end, How can I read it from end to start. Thanks

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  • validation of special characters

    - by jpallavi
    I want to validate login name with special characters !@#S%^*()+_-?/<:"';. space using regular expression in ruby on rails. These special characters should not be acceptable. What is the code for that? Thanks, Pallavi

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  • Checking an empty Core Data relationship (SQLite)

    - by rwat
    I have a to-many relationship in my data model, and I'd like to get all the objects that have no corresponding objects in the relationship. For example: Customer - Purchases I want to get all Customers that have 0 Purchases. I've read somewhere that I could use "Purchases[SIZE] = 0", but this gives me an unsupported function expression error, which I think means it doesn't work with a SQLite backing store (which I don't want to switch from, due to some performance constraints). Any ideas?

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  • Way to partialy match a Ruby string using Regexp

    - by Fabiano PS
    I'm working on 2 cases: assume I have those var: a = "hello" b = "hello-SP" b = "not_hello" 1 - Any partial matches I want to accept any string that has the var a inside, so b and c would match. 2 - Patterned match I want to match a string that has a inside, followed by '-', so b would match, c does not. I am having problem, because I always used the syntax /expression/ to define Regexp, so how dinamicaly define an RegExp on Ruby??

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  • whats the best way to parse and replace the string with its values ?

    - by shahjapan
    I may have string like, """Hello, %(name)s, how are you today, here is amount needed: %(partner_id.account_id.debit_amount)d """ what would be the best solution for such template may i need to combine regular expression and eval, input string may differ like $partner_id.account_id.debit_amount$ - for the moment I've kept as python string format - just for testing.

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  • i tried to implement tde in sql2008...n got the error below.....plz help me to resolve...

    - by mahima
    while using USE mssqltips_tde; CREATE DATABASE ENCRYPTION KEY with ALGORITHM = AES_256 ENCRYPTION BY SERVER CERTIFICATE TDECert GO getting error Msg 156, Level 15, State 1, Line 2 Incorrect syntax near the keyword 'KEY'. Msg 319, Level 15, State 1, Line 3 Incorrect syntax near the keyword 'with'. If this statement is a common table expression or an xmlnamespaces clause, the previous statement must be terminated with a semicolon. please help in resolving the same as i need to implement Encryption on my DB

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  • Explicitly accessing banked registers on ARM

    - by Demiurg
    According to the ARM manual, it should be possible to access the banked registers for a specific CPU mode as, for instance, "r13_svc". When I try to do this gcc yells at me with the following error: immediate expression requires a # prefix -- `mov r2,sp_svc' What's wrong?

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