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  • Why does hiberfil.sys come back from the dead on Windows 7?

    - by Corey White
    I have Windows 7 running on a small (40GB) partition, with 4GB ram. This means that the hiberfil.sys file created by Hibernate takes up a significant portion of the available diskspace. I would like to remove it. I am aware that I can disable Hibernate and remove hiberfil.sys by entering powercfg -h off in an elevated command prompt. This works -- the file is immediately removed, and after doing so, the HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Control\Power\HibernateEnabled key is (correctly) set to 0. However, the next time I reboot the PC, hiberfil.sys returns from the dead, Hibernate is reenabled, and that registry key has returned to 1. I'm pretty much at my wits' end with this. Almost everything I can find online related to removing the hiberfil.sys file simply suggests using powercfg to turn off hibernation, and that appears to work for just about everyone. But it just keeps coming back for me! (Like a vampire, sucking up my disk space.) I did find one other thread from someone who seems to have had the same issue, but none of the suggestions there worked for the original poster (or for me). Still, I have tried everything listed there, including: Disabling hybrid sleep Disabling Hibernate through the command prompt, through the Power Options GUI, and through both (in both orders) Manually changing the HKEY_LOCAL_MACHINE\SYSTEM\ControlSet001\Control\Power\HibernateEnabled key Pretty much everything else I can think of! I do want to reiterate that I have no problem removing the file -- that works great. It just comes back after every reboot. I'm about ready to throw in the towel and just run a script on login to disable Hibernate each time, even though that seems like a crazily hacky "solution" . . . but I was hoping someone here could suggest something else, first. Thanks!

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  • setting up subreport in ireport using XML datasource

    - by shyam
    can anyone explain in detail(if possible with screen shorts) how to add subreport (one to many relation) this being the xml data source <addressbook> <category name="home"> <person id="1"> <LASTNAME>Davolio</LASTNAME> <FIRSTNAME>Nancy</FIRSTNAME> <hobbies> <hobby>Radio Control</hobby> <hobby>R/C Cars</hobby> <hobby>Micro R/C Cars</hobby> <hobby>Die-Cast Models</hobby> </hobbies> <email>[email protected]</email> <email>[email protected]</email> </person> <person id="2"> <LASTNAME>Fuller</LASTNAME> <FIRSTNAME>Andrew</FIRSTNAME> <email>[email protected]</email> <email>[email protected]</email> </person> <person id="3"> <LASTNAME>Leverling</LASTNAME> <FIRSTNAME>Janet</FIRSTNAME> <hobbies> <hobby>Rockets</hobby> <hobby>Puzzles</hobby> <hobby>Science Hobby</hobby> <hobby>Toy Horse</hobby> </hobbies> <email>[email protected]</email> <email>[email protected]</email> </person> </category> <category name="work"> <person id="4"> <LASTNAME>Peacock</LASTNAME> <FIRSTNAME>Margaret</FIRSTNAME> <hobbies> <hobby>Toy Horse</hobby> </hobbies> <email>[email protected]</email> </person> <person id="5"> <LASTNAME>Buchanan</LASTNAME> <FIRSTNAME>Steven</FIRSTNAME> <hobbies> </hobbies> <email>[email protected]</email> </person> <person id="6"> <LASTNAME>Suyama</LASTNAME> <FIRSTNAME>Michael</FIRSTNAME> </person> <person id="7"> <LASTNAME>King</LASTNAME> <FIRSTNAME>Robert</FIRSTNAME> </person> </category> <category name="Other"> <person id="8"> <LASTNAME>Callahan</LASTNAME> <FIRSTNAME>Laura</FIRSTNAME> <email>[email protected]</email> </person> <person id="9"> <LASTNAME>Dodsworth</LASTNAME> <email>[email protected]</email> </person> </category> </addressbook>

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  • Script to reformat XML file

    - by JonS
    Hello all, I am trying to change an XML file from one format to another and have no clue as to how to write a script for it. Can someone help, please? The source file looks like this: <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.037E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_24_100_1_000_0" fieldValueIsNull="false" fieldValueNatural="r_24_100_1_000_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.037E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_24_108_0_000_0" fieldValueIsNull="false" fieldValueNatural="r_24_108_0_000_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.6049E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_06_000_1_010_0" fieldValueIsNull="false" fieldValueNatural="r_06_000_1_010_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> This is the format that I need as a result: <bestand registratienummer="123"> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_24_100_1_000_0" kolom="c_2250_SPU" /> </rapportage> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_24_108_0_000_0" kolom="c_2250_SPU" /> </rapportage> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_06_000_1_010_0" kolom="c_2250_SPU" /> </rapportage> </bestand> Thanks very much!

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  • C# - Parse HTML source as XML

    - by fonix232
    I would like to read in a dynamic URL what contains a HTML file, and read it like an XML file, based on nodes (HTML tags). Is this somehow possible? I mean, there is this HTML code: <table class="bidders" cellpadding="0" cellspacing="0"> <tr class="bidRow4"> <td>kucik (automata)</td> <td class="right">9 374 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow4"> <td>macszaf (automata)</td> <td class="right">9 373 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow2"> <td>kucik (automata)</td> <td class="right">9 372 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow2"> <td>macszaf (automata)</td> <td class="right">9 371 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow0"> <td>kucik (automata)</td> <td class="right">9 370 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow0"> <td>macszaf (automata)</td> <td class="right">9 369 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow8"> <td>kucik (automata)</td> <td class="right">9 368 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow8"> <td>macszaf (automata)</td> <td class="right">9 367 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow6"> <td>kucik (automata)</td> <td class="right">9 366 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> <tr class="bidRow6"> <td>macszaf (automata)</td> <td class="right">9 365 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> </table> I want to parse this into a ListView (or a Grid) to create rows with the data contained. All tr are different row, and all td in a given td is a column in the given row. And also I want it to be as fast as possible, as it would update itself in 5 seconds. Is there any library for this?

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  • How to Generate XML from Database

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • XML and XSD - use element name as replacement of xsi:type for polymorphism

    - by disown
    Taking the W3C vehicle XSD as an example: <schema xmlns="http://www.w3.org/2001/XMLSchema" targetNamespace="http://cars.example.com/schema" xmlns:target="http://cars.example.com/schema"> <complexType name="Vehicle" abstract="true"/> <complexType name="Car"> <complexContent> <extension base="target:Vehicle"/> ... </complexContent> </complexType> <complexType name="Plane"> <complexContent> <extension base="target:Vehicle"/> <sequence> <element name="wingspan" type="integer"/> </sequence> </complexContent> </complexType> </schema> , and the following definition of 'meansOfTravel': <complexType name="MeansOfTravel"> <complexContent> <sequence> <element name="transport" type="target:Vehicle"/> </sequence> </complexContent> </complexType> <element name="meansOfTravel" type="target:MeansOfTravel"/> With this definition you need to specify the type of your instance using xsi:type, like this: <meansOfTravel> <transport xsi:type="Plane"> <wingspan>3</wingspan> </transport> </meansOfTravel> I would just like to acheive a 'name of type' - 'name of element' mapping so that this could be replaced with just <meansOfTravel> <plane> <wingspan>3</wingspan> </plane> </meansOfTravel> The only way I could do this until now is by making it explicit: <complexType name="MeansOfTravel"> <sequence> <choice> <element name="plane" type="target:Plane"/> <element name="car" type="target:Car"/> </choice> </sequence> </complexType> <element name="meansOfTravel" type="target:MeansOfTravel"/> But this means that I have to list all possible sub-types in the 'MeansOfTravel' complex type. Is there no way of making the XML parser assume that you mean a 'Plane' if you call the element 'plane'? Or do I have to make the choice explicit? I would just like to keep my design DRY - if you have any other suggestions (like groups or so) - i would love to hear them.

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  • Control XML serialization of Dictionary<K, T>

    - by Luca
    I'm investigating about XML serialization, and since I use lot of dictionary, I would like to serialize them as well. I found the following solution for that (I'm quite proud of it! :) ). [XmlInclude(typeof(Foo))] public class XmlDictionary<TKey, TValue> { /// <summary> /// Key/value pair. /// </summary> public struct DictionaryItem { /// <summary> /// Dictionary item key. /// </summary> public TKey Key; /// <summary> /// Dictionary item value. /// </summary> public TValue Value; } /// <summary> /// Dictionary items. /// </summary> public DictionaryItem[] Items { get { List<DictionaryItem> items = new List<DictionaryItem>(ItemsDictionary.Count); foreach (KeyValuePair<TKey, TValue> pair in ItemsDictionary) { DictionaryItem item; item.Key = pair.Key; item.Value = pair.Value; items.Add(item); } return (items.ToArray()); } set { ItemsDictionary = new Dictionary<TKey,TValue>(); foreach (DictionaryItem item in value) ItemsDictionary.Add(item.Key, item.Value); } } /// <summary> /// Indexer base on dictionary key. /// </summary> /// <param name="key"></param> /// <returns></returns> public TValue this[TKey key] { get { return (ItemsDictionary[key]); } set { Debug.Assert(value != null); ItemsDictionary[key] = value; } } /// <summary> /// Delegate for get key from a dictionary value. /// </summary> /// <param name="value"></param> /// <returns></returns> public delegate TKey GetItemKeyDelegate(TValue value); /// <summary> /// Add a range of values automatically determining the associated keys. /// </summary> /// <param name="values"></param> /// <param name="keygen"></param> public void AddRange(IEnumerable<TValue> values, GetItemKeyDelegate keygen) { foreach (TValue v in values) ItemsDictionary.Add(keygen(v), v); } /// <summary> /// Items dictionary. /// </summary> [XmlIgnore] public Dictionary<TKey, TValue> ItemsDictionary = new Dictionary<TKey,TValue>(); } The classes deriving from this class are serialized in the following way: <FooDictionary xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Items> <DictionaryItemOfInt32Foo> <Key/> <Value/> </DictionaryItemOfInt32XmlProcess> <Items> This give me a good solution, but: How can I control the name of the element DictionaryItemOfInt32Foo What happens if I define a Dictionary<FooInt32, Int32> and I have the classes Foo and FooInt32? Is it possible to optimize the class above? THank you very much!

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  • Control XML serialization of generic types

    - by Luca
    I'm investigating about XML serialization, and since I use lot of dictionary, I would like to serialize them as well. I found the following solution for that (I'm quite proud of it! :) ). [XmlInclude(typeof(Foo))] public class XmlDictionary<TKey, TValue> { /// <summary> /// Key/value pair. /// </summary> public struct DictionaryItem { /// <summary> /// Dictionary item key. /// </summary> public TKey Key; /// <summary> /// Dictionary item value. /// </summary> public TValue Value; } /// <summary> /// Dictionary items. /// </summary> public DictionaryItem[] Items { get { List<DictionaryItem> items = new List<DictionaryItem>(ItemsDictionary.Count); foreach (KeyValuePair<TKey, TValue> pair in ItemsDictionary) { DictionaryItem item; item.Key = pair.Key; item.Value = pair.Value; items.Add(item); } return (items.ToArray()); } set { ItemsDictionary = new Dictionary<TKey,TValue>(); foreach (DictionaryItem item in value) ItemsDictionary.Add(item.Key, item.Value); } } /// <summary> /// Indexer base on dictionary key. /// </summary> /// <param name="key"></param> /// <returns></returns> public TValue this[TKey key] { get { return (ItemsDictionary[key]); } set { Debug.Assert(value != null); ItemsDictionary[key] = value; } } /// <summary> /// Delegate for get key from a dictionary value. /// </summary> /// <param name="value"></param> /// <returns></returns> public delegate TKey GetItemKeyDelegate(TValue value); /// <summary> /// Add a range of values automatically determining the associated keys. /// </summary> /// <param name="values"></param> /// <param name="keygen"></param> public void AddRange(IEnumerable<TValue> values, GetItemKeyDelegate keygen) { foreach (TValue v in values) ItemsDictionary.Add(keygen(v), v); } /// <summary> /// Items dictionary. /// </summary> [XmlIgnore] public Dictionary<TKey, TValue> ItemsDictionary = new Dictionary<TKey,TValue>(); } The classes deriving from this class are serialized in the following way: <XmlProcessList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Items> <DictionaryItemOfInt32Foo> <Key/> <Value/> </DictionaryItemOfInt32XmlProcess> <Items> This give me a good solution, but: How can I control the name of the element DictionaryItemOfInt32Foo What happens if I define a Dictionary<FooInt32, Int32> and I have the classes Foo and FooInt32? Is it possible to optimize the class above? THank you very much!

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  • Xpath question Xml Xpath

    - by Ibrar Afzal
    I need an xpath expression that would return the value of I need to get the value of this node. the value to extract is my xpath expression is //rates/rate[loantype='30-Year Fixed Rate'] The issue hre is that there are three value each node has a subtype element. Beside fileter for loantype I also need to filter for subtype. I am not sure how to do it in xpath. I have the following xml 40-Year Fixed Rate A 3 5.375 1.000 5.491 0 1 40-Year Fixed Rate B 5.500 0.500 5.579 0 1 40-Year Fixed Rate C 5.625 0.000 5.667 0 1 30-Year Fixed Rate A 3 5.000 1.000 5.134 0 1 30-Year Fixed Rate B 5.125 0.500 5.215 0 1 30-Year Fixed Rate C 5.250 0.000 5.297 0 1 20-Year Fixed Rate A 3 4.875 1.000 5.055 0 1 20-Year Fixed Rate B 5.000 0.500 5.121 0 1 20-Year Fixed Rate C 5.125 0.000 5.187 0 1 15-Year Fixed Rate A 3 4.250 1.000 4.467 0 1 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 15-Year Fixed Rate C 4.500 0.000 4.570 0 1 10-Year Fixed Rate A 3 4.125 1.000 4.435 0 1 10-Year Fixed Rate B 4.250 0.500 4.454 0 1 10-Year Fixed Rate C 4.375 0.000 4.473 0 1 High-Balance 15-Year Fixed Rate D 3 4.250 1.000 4.461 0 1 High-Balance 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 High-Balance 15-Year Fixed Rate C 4.500 0.000 4.563 0 1 High-Balance 30-Year Fixed Rate D 3 5.000 1.000 5.130 0 1 High-Balance 30-Year Fixed Rate B 5.125 0.500 5.211 0 1 High-Balance 30-Year Fixed Rate C 5.250 0.000 5.293 0 1 30-Year Fixed Rate Jumbo A 2 5.125 1.000 5.254 1 1 30-Year Fixed Rate Jumbo B 5.250 0.500 5.336 1 1 30-Year Fixed Rate Jumbo C 5.375 0.000 5.417 1 1 -- 15-Year Fixed Rate Jumbo A 2 5.000 1.000 5.220 1 1 15-Year Fixed Rate Jumbo B 5.125 0.500 5.270 1 1 15-Year Fixed Rate Jumbo C 5.250 0.000 5.320 1 1 -- 3/1 30-Year Adjustable Rate A 3 3.625 1.000 3.431 0 0 3/1 30-Year Adjustable Rate B 3.875 0.500 3.448 0 0 3/1 30-Year Adjustable Rate C 4.125 0.000 3.465 0 0 3/1 40-Year Adjustable Rate A 3 3.875 1.000 3.438 0 0 3/1 40-Year Adjustable Rate B 4.125 0.500 3.453 0 0 3/1 40-Year Adjustable Rate C 4.375 0.000 3.467 0 0 5/1 30-Year Adjustable Rate A 3 3.375 1.000 3.401 0 0 5/1 30-Year Adjustable Rate B 3.625 0.500 3.457 0 0 5/1 30-Year Adjustable Rate C 3.875 0.000 3.514 0 0 5/1 40-Year Adjustable Rate A 3 3.625 1.000 3.441 0 0 5/1 40-Year Adjustable Rate B 3.875 0.500 3.481 0 0 5/1 40-Year Adjustable Rate C 4.125 0.000 3.531 0 0 7/1 30-Year Adjustable Rate A 3 3.875 1.000 3.670 0 0 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 10/1 30-Year Adjustable Rate A 3 4.375 1.000 4.092 0 0 10/1 30-Year Adjustable Rate B 4.625 0.500 4.217 0 0 10/1 30-Year Adjustable Rate C 4.875 0.000 4.342 0 0 -- 2/2 ARM 30-Year (Purchase only) DH 5.250 0.000 3.709 0 0 -- High-Balance 5/1 30-Year Adjustable Rate D 3 3.375 1.000 3.366 0 0 High-Balance 5/1 30-Year Adjustable Rate B 3.625 0.500 3.404 0 0 High-Balance 5/1 30-Year Adjustable Rate C 3.875 0.000 3.454 0 0 High-Balance 7/1 30-Year Adjustable Rate D 3 3.875 1.000 3.670 0 0 High-Balance 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 High-Balance 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 3/1 30-Year Jumbo Adjustable Rate A 2 4.875 1.000 3.719 1 0 3/1 30-Year Jumbo Adjustable Rate B 5.000 0.500 3.708 1 0 3/1 30-Year Jumbo Adjustable Rate C 5.125 0.000 3.704 1 0 -- 3/1 40-Year Jumbo Adjustable Rate A 2 5.250 1.000 3.733 1 0 3/1 40-Year Jumbo Adjustable Rate B 5.375 0.500 3.727 1 0 3/1 40-Year Jumbo Adjustable Rate C 5.500 0.000 3.725 1 0 -- 5/1 30-Year Jumbo Adjustable Rate A 3 4.375 1.000 3.791 1 0 5/1 30-Year Jumbo Adjustable Rate B 4.500 0.500 3.803 1 0 5/1 30-Year Jumbo Adjustable Rate C 4.625 0.000 3.814 1 0 5/1 40-Year Jumbo Adjustable Rate A 2 5.000 1.000 3.922 1 0 5/1 40-Year Jumbo Adjustable Rate B 5.125 0.500 3.925 1 0 5/1 40-Year Jumbo Adjustable Rate C 5.250 0.000 3.936 1 0 -- 7/1 30-Year Jumbo Adjustable Rate A 3 4.950 1.000 4.261 1 0 7/1 30-Year Jumbo Adjustable Rate B 5.075 0.500 4.286 1 0 7/1 30-Year Jumbo Adjustable Rate C 5.200 0.000 4.311 1 0 2/2 ARM 30-Year Jumbo (Purchase only) DH 6.500 0.000 4.260 1 0 -- 30 Due in 7 Fixed Rate JUMBO Balloon A 6.375 1.000 6.613 1 0 30 Due in 7 Fixed Rate JUMBO Balloon B 6.500 0.500 6.625 1 0 40 due in 7 Fixed Rate offer1 5.250 0.000 5.374 0 0 1 40 Due in 7 Fixed Rate JUMBO Balloon offer2 6.500 0.000 6.625 1 0 1 Interest Only HELOC A To 80% LTV 3.250 0 1 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 75% LTV 6.000 6.000 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 75% LTV 6.00 6.153 0 2 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 80% LTV 6.250 6.250 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 80% LTV 6.25 6.403 0 2 Home Equity Loan - 7Yrs B $100,000.01 - $250,000.00 Up to 90% LTV 6.99 7.145 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 75% LTV 6.50 6.612 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 80% LTV 6.75 6.863 0 2 Home Equity Loan - 10,15Yrs D $5,000-$250,000.00 Up to 90% LTV 7.50 7.614 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 75% LTV 7.50 7.566 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 80% LTV 7.75 7.817 0 2 Home Equity Loan - 20Yrs F $5,000-$250,000.00 Up to 90% LTV 8.50 8.569 0 2 Equity Edge $5,000-$25,000.00 Up to 125% LTV 12.00 12.188 Current Index 0.350 Prime Index 3.250 03/26/2010

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  • How to get distinct results in hibernate with joins and row-based limiting?

    - by Daniel Alexiuc
    I'm trying to implement paging using row-based limiting (for example: setFirstResult(5) and setMaxResults(10)) on a Hibernate Criteria query that has joins to other tables. Understandably, data is getting cut off randomly; and the reason for that is explained here. As a solution, the page suggests using a "second sql select" instead of a join. How can I convert my existing criteria query (which has joins using createAlias()) to use a nested select instead?

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  • What other libraries or tools would you add to a Spring/Hibernate stack for improved rapid applicati

    - by CaptainAwesomePants
    My team at work maintains a fairly large webapp written on top of Spring and Hibernate. We're about to start making some fairly large scale changes to the site, and we're enamored with the rapid application development speeds allowed by some other frameworks, like Rails. We haven't really changed our stack much in the last year or two, and I'm wondering what new tools, approaches, and libraries might be out there to help speed up webapp development.

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  • Does Hibernate always need a setter when there is a getter?

    - by Marcus
    We have some Hibernate getter methods annotated with both @Column and @Basic. We get an exception if we don't have the corresponding setter. Why is this? In our case we are deriving the value returned from the getter (to get stored in the DB) and the setter has no functional purpose. So we just have an empty method to get around the error condition..

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  • Different cache concurrent strategies for root entity and its collection (Hibernate with EHCache)?

    - by grigory
    Given example from Hibernate docs and modifying it so that root level entity (Customer) is read-only while one of its collections (tickets) is read-write: @Entity @Cache(usage = CacheConcurrencyStrategy.READ_ONLY) public class Customer { ... @OneToMany(...) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public SortedSet<Ticket> getTickets() { return tickets; } ... } Would collection of tickets get refreshed when accessing customer from cache?

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  • what's the best practice to config Hibernate-Spring for multiple database relationship?

    - by nazila
    We have a main mysql database which all of the applications within our organization need the data within this database. How can I config my java web application to use this database with it's specific database when I use Spring and Hibernate within my application? How can I config JPA annotations for example between CONTRACT table within my database and COUNTRY table within our main database? what's the best practice to do this?

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  • Is there a way to specify wildcarded region names when using ehcache with hibernate?

    - by bkent314
    When using Ehcache with Hibernate, is there a way to specify region names with wildcards in the ehcache.xml file? For example, to allow for cache settings at the package level (with * as a wildcard indicator): <cache name="com.example.my.package1.*" ... /> <cache name="com.example.my.package2.*" ... /> (Note: The package-level distinction is just an example. My question is to wildcards in the general case.)

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  • Need help with a Linq XML conditional grouping query

    - by FiveTools
    I have the following xml fragment: <BANNER ID="Banner 2" ROW_WIDTH="200"> <BANNER_TEXTS ID="BANNER_TEXTS"> <BANNER_TEXT UNDERLINE="false" SPAN_COL="1" WIDTHT="78px"></BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Years In Practice</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Internet Usage</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="4" WIDTHT="312px">Sales Reps Seen / Week</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Prescription Volume</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="222px">Patient Load</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Total</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#60; 11 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">11-20 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">21-30 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Light 1-5 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Medium 6-10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Heavy &#62;10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">0</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-2</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">3-5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">101-150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">101-200</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">&#62;200</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(A)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(B)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(C)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(D)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(E)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(F)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(G)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(H)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(I)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(J)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(K)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(L)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(M)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(N)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(O)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(P)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(Q)</COLUMN_TEXT> </BANNER_TEXTS> </BANNER> I would like to group all the 'BANNER_TEXT' in the second sequence using the first sequence 'BANNER_TEXT' as the key (only include elements where string is not null or empty). The span_col attribute in the first 'BANNER_TEXT' sequence indicates which elements by position in the 2nd sequence are related. An example: 'Years in Practice' would be the first key and the attribute SPAN_COL=3 for that element indicates it would contain '< 11 years', '11-20 years', '21-30 years' (the first grouping of string.empty = Total would be skipped).

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