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• htmlspecialchars() - How and when to use and avoid multiple use

  - by naescent

  Hi, I'm building a PHP intranet for my boss. A simple customer, order, quote system. It will be denied access from the Internet and only used by 3 people. I'm not so concerned with security as I am with validation. Javascript is disables on all machines. The problem I have is this: Employee enters valid data into a form containing any of the following :;[]"' etc. Form $_POSTS this data to a validationAndProcessing.php page, and determines whether the employee entered data or not in to the fields. If they didn't they are redirected back to the data input page and the field they missed out is highlighted in red. htmlspecialchars() is applied to all data being re-populated to the form from what they entered earlier. Form is then resubmitted to validationAndProcessing.php page, if successful data is entered into the database and employee is taken to display data page. My question is this: If an employee repeatedly enters no data in step 1, they will keep moving between step 1 and 4 each time having htmlspecialchars() applied to the data. So that:- & becomes:- &amp; becomes:- &amp;amp; becomes:- &amp;amp;amp; etc.. How can I stop htmlspecialchars() being applied multiple times to data that is already cleaned? Thanks, Adam

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• PHP: Making my code simpler/shorter welcome message

  - by Karem

  Any suggestion to make this welcome message shorter: <?php if(isset($_SESSION['user_id'])) { if(isSet($_SESSION['1stTime'])){ ?> <strong id="welcome" style="font-size: 10px;"> <a href="logout.php"> Logga ut </a> </strong> <?php }else{ $_SESSION['1stTime'] = time(); ?> <script> $(document).ready(function() { $("#welcome").fadeIn("slow"); setTimeout(function(){ $("#welcome").fadeOut("slow"); setTimeout(function(){ $("#welcome").html("<a href='logout.php'>Logga ut</a>"); $("#welcome").fadeIn(); }, 800); }, 5000); }); </script> <strong id="welcome" style="display: none; color: #FFF; font-size: 10px;">Hej, <?php echo $FULL; ?>!</strong> <?php } } ?> First it checks if you are signed in. Next if 1stTime is set, if it is then show "Log out" in swedish, if it isnt, then introduce with "Hi, NAME", and then change to "Log out" after 5 seconds(jquery) + set the session How can i make this simpler?

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• Producing a static HTML site from XML content

  - by Skilldrick

  I have a long document in XML from which I need to produce static HTML pages (for distribution via CD). I know (to varying degrees) JavaScript, PHP and Python. The current options I've considered are listed here: I'm not ruling out JavaScript, so one option would be to use ajax to dynamically load the XML content into HTML pages. Learn some basic XSLT and produce HTML to the correct spec this way. Produce the site with PHP (for example) and then generate a static site. Write a script (in Python for example) to convert the XML into HTML. This is similar to the XSLT option but without having to learn XSLT. Useful information: The XML will likely change at some point, so I'd like to be able to easily regenerate the site. I'll have to produce some kind of menu for jumping around the document (so I'll need to produce some kind of index of the content). I'd like to know if anyone has any better ideas that I haven't thought of. If not, I'd like you to tell me which of my options seems the most sensible. I think I know what I'm going to do, but I'd like a second opinion. Thanks.

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• PHP Sessions and Passing Session ID

  - by Jason McCreary

  I have an API where I am passing the session id back and forth between calls. I set up the session like so: // start API session session_name('apikey'); session_id($data['apikey']); // required to link session session_start(); Although I named my session and am passing the session id via GET and POST using the name, PHP does not automatically resume that session. It always creates a new one unless I set the explicitly set the session id. I found some old user comments on www.php.net that said unless the session id is the first parameter PHP won't set it automatically. This seems odd, but even when I call tried it still didn't work: rest_services.php?apikey=sdr6d3subaofcav53cpf71j4v3&q=testing I have used PHP for years, but am a little confused on why I needed to explicitly set the session with session_id() when I am naming the session and passing it's key accordingly. UPDATE It seems I wasn't clear. My question is why is setting the session ID with session_id() required when I am passing the id, using the session name apikey, via $_GET or $_POST. Theoretically this is no different than PHP's SID when cookies are disabled. But for me it doesn't work unless I explicitly set the session ID. Why?

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• CSS Table Formatting to a HTML Table

  - by Rurigok

  I am attempting to provide CSS formating to two HTML tables, but I cannot. I am setting up a webpage in HTML & CSS (with the CSS in an external sheet) and the layout of the website depends on the tables. There are 2 tables, one for the head and another for the body. They are set up whereas content is situated in one middle column of 60% width, with one column on each side of the center with 20% width each, along with other table formatting. My question is - how can I format the tables in CSS? I successfully formatted them in HTML, but this will not do. This is the CSS code for the tables - each table has the id layouttable: #layouttable{border:0px;width:100%;} #layouttable td{width:20%;vertical-align:top;} #layouttable td{width:60%;vertical-align:top;background-color:#E8E8E8;} #layouttable td{width:20%;vertical-align:top;} The tables in the html document both each have, in respective order, these elements (with content inside not shown): <table id="layouttable"><tr><td></td><td></td><td></td></tr></table> Does anyone have any idea why this CSS is not working, or can write some code to fix it? If further explanation is needed, please, ask.

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• Forcing user to new page in php. (PHP newbie)

  - by JohnC

  Hello I'm a newbie web programmer. My background is writing Windows applications with sql. I'm putting together my 1st data entry screens in Php. I have a search form that links to a form that displays records in a grid. On each row of the grid I have a delete url to allow the user to remove a record. This links to a form delete.php (which calls the sql to remove the record). Ideally I would like to automatically take the user back to the search form rather than forcing the user to click on a link to do so. I have used ob_start with the header to do this elsewhere but cannot get it to work on this page. Is there another way to do it? (Using php 5 as part of LAMP) file delete.php <?php $id = $_GET['recordID']; //ob_start(); require_once('connections/local.php'); mysql_select_db($database_local, $local); mysql_query("DELETE FROM user_access WHERE id = {$id}") or die(mysql_error()); echo("Record ".$id." deleted"); echo("<br>"); //header("location:http://localhost/search7.htm); //ob_flush(); echo("<a href=\"http://localhost/search7.htm\">Search for Members</a>"); ?>

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• HTML not appearing in Emails

  - by John

  My website sends out html emails but most of my recipients are receiving them as HTML marked up source pages instead of the nice table layouts. The problem doesn't appear to be an email client issue since the emails display properly in web mail clients like gmail, yahoo, hotmail etc... They also display properly when viewed through outlook or thunderbird that are connected to gmail, yahoo, hotmail etc... However, I have one domain name that I registered with a shared hosting provider called 1and1.com. I tried viewing my emails through their webmail client, thunderbird and outlook, but in all three cases, only the html mark up showed up. Also, I assume most of my recipients use MS Outlook with MS Exchange Server because they are business/finance people. Unfortunately, I don't know how to get an email that's managed by an MS Exchange Server. I made sure I'm sending my emails with the following headers: MIME-Version: 1.0 Content-type: text/html; charset=iso-8859-1 Does anyone know what might be wrong? can anyone recommend a solution?

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• php: autoload exception handling.

  - by YuriKolovsky

  Hello again, I'm extending my previous question (Handling exceptions within exception handle) to address my bad coding practice. I'm trying to delegate autoload errors to a exception handler. <?php function __autoload($class_name) { $file = $class_name.'.php'; try { if (file_exists($file)) { include $file; }else{ throw new loadException("File $file is missing"); } if(!class_exists($class_name,false)){ throw new loadException("Class $class_name missing in $file"); } }catch(loadException $e){ header("HTTP/1.0 500 Internal Server Error"); $e->loadErrorPage('500'); exit; } return true; } class loadException extends Exception { public function __toString() { return get_class($this) . " in {$this->file}({$this->line})".PHP_EOL ."'{$this->message}'".PHP_EOL . "{$this->getTraceAsString()}"; } public function loadErrorPage($code){ try { $page = new pageClass(); echo $page->showPage($code); }catch(Exception $e){ echo 'fatal error: ', $code; } } } $test = new testClass(); ?> the above script is supposed to load a 404 page if the testClass.php file is missing, and it works fine, UNLESS the pageClass.php file is missing as well, in which case I see a "Fatal error: Class 'pageClass' not found in D:\xampp\htdocs\Test\PHP\errorhandle\index.php on line 29" instead of the "fatal error: 500" message I do not want to add a try/catch block to each and every class autoload (object creation), so i tried this. What is the proper way of handling this?

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• Why NOT use POST method here?

  - by Camran

  I have a classifieds website. In the main page (index) I have several form fields which the user may or may not fill in, in order to specify a detailed search of classifieds. Ex: Category: Cars Price from: 3000 Price to: 10000 Color: Red Area: California The forms' action is set to a php page: <form action='query_sql.php' method='post'> In query_sql.php I fetch the variables like this: category=$_POST['category']; etc etc... Then query MySql: $query="SELECT........WHERE category='$category' etc etc.... $results = mysql_query($query); Then I simply display the results of the query to the user by creating a table which is filled in dynamically depending on the results set. However, according to an answer by Col. Shrapnel in my previous Q I shouldn't use POST here: http://stackoverflow.com/questions/3004754/how-to-hide-url-from-users-when-submitting-this-form The reason I use post is simply to hide the "one-page-word-document" long URL in the browsers adress bar. I am very confused, is it okay to use POST or not? It is working fine both when I use GET or POST now... And it is already on a production server... Btw, in the linked question, I wasn't referring to make URL invisible (or hide it) I just wanted it too look better (which I have accomplished with mod_rewrite). UPDATE: If I use GET, then how should I make the url better looking (beautiful)? Check this previous Q out: http://stackoverflow.com/questions/3000524/how-to-make-this-very-long-url-appear-short

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• How to update child iFrame's entire html (header+body) inside jQuery's post

  - by knappy

  I have a chat webpage for Firefox that is structured like this ..... Outer HTML -----|......Frameset Frame ------------|...... header: contains jQuery post has returned data: rdata = new_iFrame_html_str, the entire html string of the iFrame that should be updated ------------|...... iFrame --------------------|...... header: contains jQuery --------------------|...... body: chat messages that depends on the header jQuery to behave properly QUESTION: I can't this jQuery post to work, i.e. I can't find a way for this post to update the ENTIRE iFrame (header + body). Things I've tried and FAILED with javascript and jQuery: top.frames['framesetFrame_name'].document.getElementById('iframe_id').contentDocument.body.innerHTML = new_iFrame_html_str; I don't like this because it's only changing the body, not the header, so the behavior generated from jQuery can't be shown top.frames['framesetFrame_name'].document.getElementById('iframe_bucinid').contentWindow.location.reload(); I do not want to reload because a reload makes the iFrame flicker, bad for a chat program top.frames['framesetFrame_name'].document.getElementById('iframe_id').contents().html = new_iFrame_html_str; Not updating anything that shows :( top.frames['framesetFrame_name'].document.getElementById('iframe_id').contentWindow.location.href = new_iFrame_html_str; This is actually the wrong form here, because it should be = url_of_new_content $( top.frames['framesetFrame_name'].document.getElementById('iframe_id') ).html( new_iFrame_html_str ) ; Not updating anything that shows :(

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• Trouble decoding JSON string with PHP

  - by Anthony

  I'm trying to send an array of objects from JS to PHP using JSON. I have an array of players as follows: var player; var players = new Array(); //loop for number of players player = new Object(); player.id = theID; players[i] = player; Then my AJAX call looks like this: JSONplayers = JSON.stringify(players); $.ajax({ type: "POST", url: "php/ajax_send_players.php", data: { "players" : JSONplayers } On the PHP side the decode function looks like this $players = $_REQUEST['players']; echo var_dump($players); $players = json_decode($players); echo 'players: ' .$players. '--'. $players[0] . '--'. $players[0]->id; Debugging in chrome, the JSON players var looks like this before it is sent: JSONplayers: "[{"id":"Percipient"},{"id":"4"}]" And when I vardump in PHP it looks OK, giving this: string(40) "[{\"id\":\"Percipient\"},{\"id\":\"4\"}]" But I can't access the PHP array, and the echo statement about starting with players: outputs this: players: ---- Nothing across the board...maybe it has something to do with the \'s in the array, I am new to this and might be missing something very simple. Any help would be greatly appreciated. note I've also tried json_decode($players, true) to get it as an assoc array but get similar results.

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• PHP JQuery: Where to specify uploadify destination folder

  - by Eamonn

  I have an uploadify script running, basic setup. Works fine when I hard code the destination folder for the images into uploadify.php - now I want to make that folder dynamic. How do I do this? I have a PHP variable $uploadify_path which contains the path to the folder I want. I have switched out my hard coded $targetPath = path/to/directory for $targetPath = $uploadify_path in both uploadify.php and check_exists.php, but it does not work. The file upload animation runs, says it is complete, yet the directory remains empty. The file is not hiding out somewhere else either. I see there is an option in the Javascript to specify a folder. I tried this also, but to no avail. If anyone could educate me on how to pass this variable destination to uploadify, I'd be very grateful. I include my current code for checking (basically default): The Javascript <script type="text/javascript"> $(function() { $('#file_upload').uploadify({ 'swf' : 'uploadify/uploadify.swf', 'uploader' : 'uploadify/uploadify.php', // Put your options here }); }); </script> uploadify.php $targetPath = $_SERVER['DOCUMENT_ROOT'] . $uploadify_path; // Relative to the root if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetFile = $targetPath . $_FILES['Filedata']['name']; // Validate the file type $fileTypes = array('jpg','jpeg','gif','png'); // File extensions $fileParts = pathinfo($_FILES['Filedata']['name']); if (in_array($fileParts['extension'],$fileTypes)) { move_uploaded_file($tempFile,$targetFile); echo '1'; } else { echo 'Invalid file type.'; } }

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• Variable not implementing correctly from if statement

  - by swiftsly

  I have an if statement that is supposed to set the variable $pc162v to a link specified in the MySQL table if content exists in the $vid column of the row. The problem is, the PHP is detecting that there's a link in the MySQL, but isn't setting the $pc162v variable correctly. Here's the variable declarations: $pc162v = ""; $vid162 = '<embed width="420" height="236" src="'.$pc162v.'" type="application/x-shockwave-flash"></embed>'; Here's the section of the if statement: if (empty($row[7])) { $vid162 = ''; } else { $pc162v = $row[7]; } In my web browsers, the part of the code where the variable $vid162 is used, shows up as the following: <embed width="420" height="236" src="" type="application/x-shockwave-flash"> I have also tried setting $vid162 to: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"></embed> and that just makes the code in my web browser: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"> Hope someone has a solution! Thanks in advance.

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• Somewhat lost with jquery + php + json

  - by Luis Armando

  I am starting to use the jquery $.ajax() but I can't get back what I want to...I send this: $(function(){ $.ajax({ url: "graph_data.php", type: "POST", data: "casi=56&nada=48&nuevo=98&perfecto=100&vales=50&apenas=70&yeah=60", dataType: "json", error: function (xhr, desc, exceptionobj) { document.writeln("El error de XMLHTTPRequest dice: " + xhr.responseText); }, success: function (json) { if (json.error) { alert(json.error); return; } var output = ""; for (p in json) { output += p + " : " + json[p] + "\n"; } document.writeln("Results: \n\n" + output); } }); }); and my php is: <?php $data = $_POST['data']; function array2json($data){ $json = $data; return json_encode($json); } ?> and when I execute this I come out with: Results: just like that I used to have in the php a echo array2json statement but it just gave back gibberish...I really don't know what am I doing wrong and I've googled for about 3 hours just getting basically the same stuff. Also I don't know how to pass parameters to the "data:" in the $.ajax function in another way like getting info from the web page, can anyone please help me? Edit I did what you suggested and it prints the data now thank you very much =) however, I was wondering, how can I send the data to the "data:" part in jQuery so it takes it from let's say user input, also I was checking the php documentation and it says I'm allowed to write something like: json_encode($a,JSON_HEX_TAG|JSON_HEX_APOS|JSON_HEX_QUOT|JSON_HEX_AMP) however, if I do that I get an error saying that json_encode accepts 1 parameter and I'm giving 2...any idea why? I'm using php 5.2

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• how to use a PHP Constant that gets pulled from a database

  - by Ronedog

  Can you read out the name of a PHP constant from a database and use it inside of a php variable, to display the value of the constant for use in a menu? For example here's what I'm trying to accomplish In SQL: select menu_name AS php_CONSTANT where menu_id=1 the value returned would be L_HOME which is the name of a CONSTANT in a php config page. The php config page looks like this define('L_HOME','Home'); and gets loaded before the database call. The php usage would be $db_returned_constant which has a value of L_HOME that came from the db call, then I would place this into a string such as $string = '<ul><li>' . $db_returned_constant . '</li></ul>' and thus return a string that looks like $string = '<ul><li><a href="#" onclick="path_from_db">Home</a></li></ul>'. To sum up what I'm trying to do Load a config file based on the language preference query the db to return the menu name, which is the name of a CONSTANT in the config file loaded in step one, and also retrieve the menu_link which is used in the "onclick" event. Use a php variable to hold the name of the CONSTANT Place the variable into a string that gets echo'd out to create the menu displaying the value of the CONSTANT. I hope this makes enough sense...is it even possible to use a constant like this? Thanks.

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• Flex + PHP + ValueObjects

  - by Tempname

  I have a php/flex value object that I am using to transmit data to/from in my application. Everything works great php-flex, but I am having an issue with flex-php. In my MergeTemplateService.php service I have the following code. This is the method that flex hits directly: function updateTemplate($valueObject){ $object = DAOFactory::getMergeTemplateDAO()->update($valueObject); return $object; } I am passing a value object that from flex looks like this: (com.rottmanj.vo::MergeTemplateVO)#0 communityID = 0 creationDate = (null) enterpriseID = 0 lastModifyDate = (null) templateID = 2 templateName = "My New Test Template" userID = 0 The issue I am having is that my updateTemplate method sees the value object as an array and not an object. In my amfphp globals.php I have set my voPath as: $voPath = "services/class/dto/"; Any help with this is greatly appreciated Here are my two value objects: AS3 VO: package com.rottmanj.vo { [RemoteClass(alias="MergeTemplate")] public class MergeTemplateVO { public var templateID:int; public var templateName:String; public var communityID:int; public var enterpriseID:int; public var userID:int; public var creationDate:String; public var lastModifyDate:String public function MergeTemplateVO(data:Object = null):void { if(data != null) { templateID = data.templateID; templateName = data.templateName; communityID = data.communityID; enterpriseID = data.enterpriseID; userID = data.userID; creationDate = data.creationDate; lastModifyDate = data.lastModifyDate; } } } } PHPVO: <?php class MergeTemplate{ var $templateID; var $templateName; var $communityID; var $enterpriseID; var $userID; var $creationDate; var $lastModifyDate; var $_explictType = 'MergeTemplate'; } ?>

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• .NET HttpModule does not send form variables to PHP file on RewritePath()

  - by jammus

  Hello friends. We have an application running on IIS 6 which uses a custom HttpModule to rewrite urls. This works great (well done us) except in the case where the Context.RewritePath destination is a .php file. The php file is executed as expected, however the $_POST collection is empty meaning it cannot access any forms which are submitted to rewritten urls. The problem does not exist when rewriting to .aspx files as the Request.Form collection is fine. My question therefore has two parts: Why is the $_POST collection not being populated? Is there a way to ensure that the .php $_POST collection is correctly populated after a rewrite? I don't have much to show in the way of code. There's just a simple: context.RewritePath(newPath); once the HttpModule has figured out where to send the request. Edit: Interestingly, if I do var_dump(file_get_contents('php://input')); in the PHP file (method described here) the contents of the form is displayed. So the data is reaching the PHP script but not the $_POST array.

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• PHP IDE with Integrated Web Server

  - by seth

  Note: This is not another "What is the best PHP IDE?" question. I'm looking for a PHP IDE with a specific feature, namely an integrated / embedded (php enabled) web server; ideally with xdebug pre-bundled. I already know that Aptana 1.5 has this functionality (and some older versions of Zend Studio as well), but Aptana 1.5 hasn't been supported for quite some time and as we make the transition to PHP 5.3 and beyond, it's usefulness will diminish significantly. I've looked at some options including Eclipse PDT and NetBeans, but it seems every PHP IDE relies on a separate local/remote web server to actually interpret the code. I know installing a web server locally is fairly trivial, but this is for a classroom solution, where installing, configuring, and maintaining a web server on 1000 machines is simply not feasible. A remote server solution will also not work due to the need to use debugging functionality (xdebug currently requires a hardcoded IP for the debug client). This seems like such an obvious feature/plugin for a PHP IDE, but my research thus far has turned up no results.

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• URL routing in an MVC framework - PHP

  - by Walderman

  I'm developing an MVC framework in PHP from scratch; mostly for the learning experience but this could easily end up in a live project. I went through this tutorial as a base and I've expanded from there. Requests are made like this: examplesite.com/controller/action/param1/param2/ and so on... And this is my .htaccess file: RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php?rt=$1 [L,QSA] So all requests go to index.php and they are routed to the correct controller and action from there. If no controller or action is given, then the default 'index' is assumed for both. I have an index controller with an index action, which is supposed to be the home page of my site. I can access it by going to examplesite.com (since the index part is assumed). It has some images, a link to a stylesheet, and some scripts. They are linked with paths relative to index.php. I thought this would be fine since all request go to index.php and all content is simply included in this page using php. This works if I go to examplesite.com. I will see all of the images and styles, and scripts will run. However, if I go to examplesite.com/index, I am routed to the correct part of the site, but all of the links don't work. Does the browser think I am in a different folder? I would like to be able to use relative paths for all of the content in my site, because otherwise I need to use absolute paths everywhere to make sure things will show up. Is this possible?

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• trouble connecting to MySql DB (PHP)

  - by user332817

  Hi I have the following PHP code to connect to my db. <?php ob_start(); $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); ?> however I get the following error: Warning: mysql_connect() [function.mysql-connect]: [2002] A connection attempt failed because the connected party did not (trying to connect via tcp://localhost:3306) in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Warning: mysql_connect() [function.mysql-connect]: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond. in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Fatal error: Maximum execution time of 30 seconds exceeded in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 I am able to add a db/tables via phpmyadmin but I cant connect using php. here is a screenshot of my phpmyadmin page: http://img294.imageshack.us/img294/1589/sqls.jpg any help would be appreciated, thanks in advance.

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• protect form hijacking hack

  - by Karem

  Yes hello today I discovered a hack for my site. When you write a msg on a users wall (in my communitysite) it runs a ajax call, to insert the msg to the db and will then on success slide down and show it. Works fine with no problem. So I was rethinking alittle, I am using POST methods for this and if it was GET method you could easily do ?msg=haxmsg&usr=12345679. But what could you do to come around the POST method? I made a new html document, made a form and on action i set "site.com/insertwall.php" (the file that normally are being used in ajax), i made some input fields with names exactly like i am doing with the ajaxcall (msg, uID (userid), BuID (by userid) ) and made a submit button. I know I have a page_protect() function on which requires you to login and if you arent you will be header to index.php. So i logged in (started session on my site.com) and then I pressed on this submit button. And then wops I saw on my site that it has made a new message. I was like wow, was it so easy to hijack POST method i thought maybe it was little more secure or something. I would like to know what could I do to prevent this hijacking? As i wouldnt even want to know what real hackers could do with this "hole". The page_protect secures that the sessions are from the same http user agent and so, and this works fine (tried to run the form without logging in, and it just headers me to startpage) but yea wouldnt take long time to figure out to log in first and then run it. Any advices are appreciated alot. I would like to keep my ajax calls most secure as possible and all of them are running on the POST method. What could I do to the insertwall.php, to check that it comes from the server or something.. Thank you

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• Mimic Coldfusion's debug output in PHP?

  - by TekiusFanatikus

  I'm trying to mimic Coldfusion's debug output in PHP. Here's an example of what it looks like (ie. Execution Time section): I've turned to XDebug. Ideally, the exception stack error output would be what I'd be looking for. However, it only shows up when an exception occurs. I also tried something like (in our CMS-ish app) this (original question here): $content.= "<?php xdebug_start_trace('e:/xdebug/trace');?>"; $content.= "<?php require('".$page['file_'.LG]."'); ?>"; $content.= "<?php xdebug_stop_trace();?>"; ... $content.= "<?php echo readfile('e:/xdebug/trace.xt');?>"; However, I get an insane, browser crashing HTML table dropped at the bottom of page. Not very efficient. My php.ini config: xdebug.trace_format = 2 xdebug.collect_vars = 1 xdebug.collect_params = 4 xdebug.dump_globals = 1 xdebug.dump.SERVER = 'REQUEST_URI' xdebug.show_local_vars = 1 xdebug.show_mem_delta = 1 I'm just wondering if someone has already done something similar?

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• minifying final html output using regex with codeigniter

  - by Aman

  Google pages suggest you to minify html i.e. remove all the un-necessary spaces. Codeigniter does have feature of giziping output or it can be done via .htaccess. But still I also would like to remove un-necessary spaces from final html output as well. I played a bit with this peace of code to do it, and it seem to work. This does indeed result in html that is without excess spaces and removes other tab formatting. class Welcome extends CI_Controller { function _output() { echo preg_replace('!\s+!', ' ', $output); } function index(){ ... } } Now the problem with this is there may be tag like <pre>,<textarea>, etc.. which may have space in it and regx should remove them. So, how do I remove excess space from final html, without effecting spaces or formatting for these certain tags using regx? Thanks to @Alan Moore got the answer, this worked for me echo preg_replace('#(?ix)(?>[^\S ]\s*|\s{2,})(?=(?:(?:[^<]++|<(?!/?(?:textarea|pre)\b))*+)(?:<(?>textarea|pre)\b|\z))#', ' ', $output); @ridgerunner here did very good job of analyzing this regx, ended up using his solution. Cheers to ridgerunner.

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• PHP active page code - I can't figure out parse error

  - by dmschenk

  I'm trying to build an active page menu with PHP and MySQL and am having a difficult time fixing the error. In the while statement I have an if statement that is giving me fits. Basically I think I'm saying that "thispage" is equal to the "title" based on pageID and as the menu is looped through if "thispage" is equal to "title" then echo id="active". Thanks <?php mysql_select_db($database_db_connection, $db_connection); $query_rsDaTa = "SELECT * FROM pages WHERE pagesID = 4"; $rsDaTa = mysql_query($query_rsDaTa, $db_connection) or die(mysql_error()); $row_rsDaTa = mysql_fetch_assoc($rsDaTa); $totalRows_rsDaTa = mysql_num_rows($rsDaTa); $query_rsMenu = "SELECT * FROM menu WHERE online = 1 ORDER BY menuPos ASC"; $rsMenu = mysql_query($query_rsMenu, $db_connection) or die(mysql_error()); $thisPage = ($row_rsDaTa['title']); ?> <link href="../css/MainStyle.css" rel="stylesheet" type="text/css" /> <h2><?php echo $thisPage; ?></h2> <div id="footcontainer"> <ul id="footlist"> <?php while($row_rsMenu = mysql_fetch_assoc($rsMenu)) { echo (" <li" . <?php if ($thisPage==$row_rsDaTa['title']) echo id="active"; ?> . "<a href=\"../" . $row_rsMenu['menuURL'] . "\">" . $row_rsMenu['menuName'] . "</a></li>\n"); } echo "</ul>\n"; ?> </div> <?php mysql_free_result($rsMenu); mysql_free_result($rsDaTa); ?>

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• PHP While loop seperating unique categories from multiple 'Joined' tables

  - by Hob

  I'm pretty new to Joins so hope this all makes sense. I'm joining 4 tables and want to create a while loop that spits out results nested under different categories. My Tables categories id | category_name pages id | page_name | category *page_content* id | page_id | image_id images id | thumb_path My current SQL join <?php $all_photos = mysql_query(" SELECT * FROM categories JOIN pages ON pages.category = categories.id JOIN image_pages ON image_pages.page_id = pages.id JOIN images ON images.id = image_pages.image_id ");?> The result I want from a while loop I would like to get something like this.... Category 1 page 1 Image 1, image 2, image 3 page 2 Image 2, image 4 Category 2 page 3 image 1 page 4 image 1, image 2, image 3 I hope that makes sense. Each image can fall under multiple pages and each page can fall under multiple categories. at the moment I have 2 solutions, one which lists each category several times according to the the amount of pages inside them: eg. category 1, page 1, image 1 - category 1, page 1, image 2 etc One that uses a while loop inside another while loop inside another while loop, resulting in 3 sql queries. <?php while($all_page = mysql_fetch_array($all_pages)) { ?> <p><?=$all_page['page_name']?></p> <?php $all_images = mysql_query("SELECT * FROM images JOIN image_pages ON image_pages.page_id = " . $all_page['id'] . " AND image_pages.image_id = images.id"); ?> <div class="admin-images-block clearfix"> <?php while($all_image = mysql_fetch_array($all_images)) { ?> <img src="<?=$all_image['thumb_path']?>" alt="<?=$all_image['title']?>"/> <?php } ?> </div> <?php } } ?

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