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  • Unable to SSH into ESXi 4.1 host - "Access Denied"

    - by Andrew White
    I am unable to SSH into an existing ESXi server. I have a user which is in the "root" and "users" group and is able to connect via vSphere. However after enabling "Remote support (SSH)", attempting to connect by putty and entering my username/password when prompted I am presented with an "Access Denied" message. I have run through the options presented at this KB article to no avail. I have taken down the firewall on the machine (it is remote) temporarily to check if this helped - no change. The username/password are definitely correct and I can obviously get connectivity if I am presented with the username/password prompt. I am at a bit of a loss what else I can try. Thanks all

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  • Cannot access Nagios Web Interface

    - by Dominiqs
    After successfully installing Nagios core 3.4.1 (i also installed plug-in1.4.11) on our linux rhel 5.3 server i cannot login to the nagios web interface.I am running apache 2.2.3 I am using internet explorer 8 and also firefox 3.6.3 When i try to enter the url http//localhost/nagios/ on a desktop (on the same network as the Nagios server)it does seem to like it but if i try http//x.x.x.x/nagios/ (where x.x.x.x is the IP address of my nagios server) it likes it but then the authentication popup appears after entering the password and username(nagiosadmin) it throws the errors below The server x.x.x.x at Nagios access requires a username and password Warning this server is requesting that your username and password be sent in an insecure manner(basic authentication without a secure connection) After a few attempts i get error 401 authentication required error from internet explorer ;this server could not verify that you are authorized to access the document requested. Either you supplied the wrong credentials or your browser doesnt understand how to supply the credentials required. Help Please anyone..seems like an authentication issue

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  • Ubuntu reset network configuration

    - by user1103294
    When I boot up my ubuntu server, it cannot connect to my wireless network anymore. It says "waiting for network configuration" for 60 seconds, boots up, but no wireless. I suspect it's because of the following reasons. I used to connect to a wireless connection named 2WIRE555, password: 123abc But then I upgraded my connection and my new wireless connection was named 2WIRE444, password:111111 Being lazy, I simply renamed 2WIRE555 to 2WIRE444 and changed the password accordingly. I was hoping this would work but ever since then my network configurations is messed up. So back to the issue, how do I reset my network configurations for my Ubuntu 11.10 server?

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  • How to transer/execute a script on remote unix server from Linux machine

    - by Jagadeesh
    I am trying to deploy an executable and execute it on remote Unix machine(Linux/Solaris) from Linux without entering the password manually. I tried scp and also SSH key-gen utility to interact with remote server but in either way i couldn't avoid providing the password manually. Since I need to run this command/utility from Java code, I should completely avoid prompting for the password at run time. I have gone through many topics in google but nothing has been materialized. Your help would really be appreciated if i could proceed further on this issue. Thanks in advance. -Jagadeesh

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  • Fedora: "Login Incorrect"

    - by darkblackcorner
    I've just set up a minimal install on my netbook (the default was too resource hungry, so I figured I'd customize the install and learn something about linux at the same time!) No problems logging in as root, but when I create a new user and try to login as them I just get the "Login incorrect" error. I'm certain the password is correct, though the secure log displays an authentication error. Am I missing a permission somewhere? useradd test usermod -p [pwd] test Shell is added automatically I think (checking password file says shell is /bin/bash) I've tried adding the user to the sudo-ers group usermod -a -G wheel which doesn't help. I've kept the password simple in order to rule out human error.

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  • Citrix XenApp application does not have keyboard focus when launched

    - by Jason Pearce
    On new or existing Citrix XenApp 4.5 servers, I am having problems streaming the Allscripts Pro EHR application via the XenApp web interface. When users launch the application via the Citrix XenApp web interface, the application does not have focus, preventing users from typing in their username and password. If they use their mouse to select either the username or password fields, they still cannot enter any text. However, if they do any of the following actions, they can then enter in their username and password and the application runs without problems: Click on the Login button with empty fields. Logon fails but they can then enter their credentials. Minimize the login window and then maximize it. They can then gain keyboard focus to enter their credentials. What might be preventing this particular application from having focus when it launches?

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  • How to copy a file to a remote server using the command line?

    - by cool_cs
    I am trying to copy a file from my desktop to my remote server using the sudo command. I am doing this from the remote machine since I know the password for this machine and I do not have a password for my local machine. sudo scp donj@localhost:/Desktop/my.cnf user@remotemachine:/app/MySQL/my.cnf This does not work however. I want to overwrite the my.cnf file in the MySQL directory. I tried the su command but I do not have the password to become a super user.

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  • Prompt for credentials in a batch script

    - by Inteladu
    I am trying to perform a network copy of files via a batch script. However, as usual there are some networks where the 'copy' command fails saying 'Bad username or password'. And when I try using xcopy, it never works. I have also tried using, net use \\server\ password /user:domain\username net use \\server\ipc$ /user:domain\username password But none of these work. Any ideas on how I can accomplish this? I was also wondering if it is possible to prompt the ususal Windows login dialog for this...(just an idea) Any leads on this would be highly appreciated. Thanks & Regards, inteladu

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  • Chef: Load Attributes from encrypted databag in json role

    - by jcvj
    I'm want to use the postfix cookbook for chef. The sasl password is expected to be in an attribute. So usually you would do this: "default_attributes": { "postfix": { "sasl": { "smtp_sasl_passwd": "somepassword" } } } The thing is: I don't want to have the password in the repository in plain text. So I put it in an encrypted data bag. Now I want to access it. This can be done with this: Chef::EncryptedDataBagItem.load("passwords", "postfix")['password'] The problem: This only works in a .rb file, but my role is in json; all my roles are in json! I don't want to change that just for this purpose. Does anybody have an idea what to do here? Help is very appreciated.

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  • VPN on PC vs Mac

    - by allstar
    I am trying to connect to a VPN from my home computer, as opposed to my work computer which already has the network info set up. I have received instructions on connecting from a mac, but since I don't have that I'm trying to do the equivalent on my PC. I know the: server group name secret and my own login account and password Using the Windows 7 VPN, there's space for: Internet address destination name user name password domain (optional) I'm trying to determine what's what. I assume the internet address is the server. I've tried using the "secret" as the Password, b/c i'd think the first part is connecting to the VPN as opposed to logging in. It still wants a user name though. I tried mine, I tried the "group name". I would appreciate your help with this. Thanks!

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  • disbale ssh for bnroot as root account

    - by user2916639
    i am beginner with centos - Linux i have dedicated server . my root username is bnroot . now i am taking ssh using this user. i want to disable ssh for bnroot. i have created user user name welcome i want take ssh login by welcome user then i ll use su - bnroot to get root privileges. i have set PermitRootLogin no , AllowUsers welcome IN /etc/sshd_config and after restarting sshd service . i take ssh login by welcome use then it is ok. but when i use su bnroot its prompt to password and i enter right passowrd it show su: incorrect password , i dont know where i am wrong . please help me here. changes i done - /etc/ssh/sshd_confid PermitRootLogin no AllowUsers welcome /etc/sudoers welcome ALL=(ALL) ALL getting error in /var/log/secure unix_chkpwd[666]: password check failed for user (bnroot) su: pam_unix(su:auth): authentication failure; logname=ewalletssh uid=503 euid=500 tty=pts/1 ruser=ewalletssh rhost= user=bnroot please let me know where i am wrong

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  • Windows 7: Shared folder over wifi working for ONLY "Guests"

    - by James_Smith
    Hi, I have a desktop and a laptop connected to same wifi router. Desktop is connected with wire and laptop with wifi. Both the system runs windows 7 and are on the same workgroup. I have shared some folders on desktop and can view the shared folder list on laptop under "network places". But when I try to open a folder, a prompt appears for username and password. When I enter BOTH username and password, It does not authenticate when I enter ONLY username, I get:- "Windows cannot access \WIn71\Setups you do not have permission to access ..." Now to get around this message I have to give access to "Guests" group on my desktop shared folder. Cant seem to figure out why It cant authenticate username with password. And giving access to "Guests" does not sounds safe!

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  • What happens internally in a router when LAN is configured? [closed]

    - by vindhya
    This week I was trying to setup LAN to my home. I couldn't login to the router webpage even though I tried all the username and password like admin etc... I want to ask: Why username and password is required to access modem/router webpage because its always usually admin and admin? What exactly happens inside router when you type correct username and password. Does the router store it internally or does it ask some ISP servers about it? Could someone explain what exactly happens internally in the router right from the configuration phase?

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  • Can I change the user that is the default choice in UAC?

    - by Will
    Windows 7 install. I RANU, so I have to hit the UAC every once in awhile. The problem is that it asks me to enter my password to elevate, but I need to enter the domain\username of the box admin (I'm on a domain) and the password. Instead of UAC popping up with my username entered and the caret in the password box, I'd like it to pop up with the domain\username of a different user, specifically the local admin account, entered. This would save me a click and some typing. Sue me, I'm lazy. Is this possible?

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  • "(401)Authorization Required" when making a web service call using Axis

    - by Arun P Johny
    Hi, I'm using apache axis to connect to my sugar crm instance. When I'm trying to connect to the instance it is throwing the following exception Exception in thread "main" AxisFault faultCode: {http://xml.apache.org/axis/}HTTP faultSubcode: faultString: (401)Authorization Required faultActor: faultNode: faultDetail: {}:return code: 401 &lt;!DOCTYPE HTML PUBLIC &quot;-//IETF//DTD HTML 2.0//EN&quot;&gt; &lt;html&gt;&lt;head&gt; &lt;title&gt;401 Authorization Required&lt;/title&gt; &lt;/head&gt;&lt;body&gt; &lt;h1&gt;Authorization Required&lt;/h1&gt; &lt;p&gt;This server could not verify that you are authorized to access the document requested. Either you supplied the wrong credentials (e.g., bad password), or your browser doesn't understand how to supply the credentials required.&lt;/p&gt; &lt;/body&gt;&lt;/html&gt; {http://xml.apache.org/axis/}HttpErrorCode:401 (401)Authorization Required at org.apache.axis.transport.http.HTTPSender.readFromSocket(HTTPSender.java:744) at org.apache.axis.transport.http.HTTPSender.invoke(HTTPSender.java:144) at org.apache.axis.strategies.InvocationStrategy.visit(InvocationStrategy.java:32) at org.apache.axis.SimpleChain.doVisiting(SimpleChain.java:118) at org.apache.axis.SimpleChain.invoke(SimpleChain.java:83) at org.apache.axis.client.AxisClient.invoke(AxisClient.java:165) at org.apache.axis.client.Call.invokeEngine(Call.java:2784) at org.apache.axis.client.Call.invoke(Call.java:2767) at org.apache.axis.client.Call.invoke(Call.java:2443) at org.apache.axis.client.Call.invoke(Call.java:2366) at org.apache.axis.client.Call.invoke(Call.java:1812) at org.beanizer.sugarcrm.SugarsoapBindingStub.get_server_info(SugarsoapBindingStub.java:1115) at com.greytip.sugarcrm.GreytipCrm.main(GreytipCrm.java:42) This basically says that I do not have the authorization to the resource. The same code is working fine in my testing environment. Sugarsoap service = new SugarsoapLocator(); SugarsoapPortType port = service.getsugarsoapPort(new java.net.URL( SUGAR_CRM_LOCATION + "/soap.php")); System.out.println(port.get_server_info().getVersion()); User_auth userAuth = new User_auth(); userAuth.setUser_name("user_name"); MessageDigest md = MessageDigest.getInstance("MD5"); String password = getHexString(md.digest("password".getBytes())); userAuth.setPassword(password); // userAuth.setVersion("0.1"); Entry_value login = port.login(userAuth, "myAppName", null); String sessionID = login.getId(); Above code is used to connect to the Sugar CRM installation. here line "System.out.println(port.get_server_info().getVersion());" is throwing the exception. One difference I noticed between the test and production environment is when I used the soap url in the browser the production site pops up a 'Authentication Required' popup. When I gives my proxy username and password in this popup, it shows the soap request details. The same is applicable for the login url also. First it will ask for the 'Authentication' then it will take to the sugar crm login page? Is it a server security setting? If it is then how to set this user name and password using java in a web service call. The authentication required popup is same as the one which comes when we try to access the tomcat manager through a browser. Thanks

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  • ASP.NET MVC 2 - ViewModel Prefix

    - by Cosmo
    I want to use RenderPartial twice in my view with different models associated. The problem is that some properties are present in both models (nickname, password). They have no prefix, so even the id's or names are equal in the output. Now, if I have model errors for nickname or password, both fields get highlighted. Main View: <div> <% Html.RenderPartial("Register", Model.RegisterModel); %> </div> <div> <% Html.RenderPartial("Login", Model.LoginModel); %> </div> Login PartialView: <% using (Html.BeginForm("Login", "Member")) { %> <fieldset> <legend>Login</legend> <p> <%= Html.LabelFor(x => x.Nickname) %> <%= Html.TextBoxFor(x => x.Nickname) %> </p> <p> <%= Html.LabelFor(x => x.Password) %> <%= Html.PasswordFor(x => x.Password) %> </p> <input type="submit" value="Login" /> </fieldset> <% } % Register PartialView: <% using (Html.BeginForm("Register", "Member")) { %> <fieldset> <legend>Register</legend> <p> <%= Html.LabelFor(x => x.Nickname) %> <%= Html.TextBoxFor(x => x.Nickname) %> </p> <p> <%= Html.LabelFor(x => x.Email) %> <%= Html.TextBoxFor(x => x.Email) %> </p> <p> <%= Html.LabelFor(x => x.Password) %> <%= Html.PasswordFor(x => x.Password) %> </p> <p> <%= Html.LabelFor(x => x.PasswordRepeat) %> <%= Html.PasswordFor(x => x.PasswordRepeat) %> </p> <input type="submit" value="Register" /> </fieldset> <% } % How can I change this?

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  • How to read registry correctly for multiple values in c?

    - by kampi
    Hi! I created a .dll which should work like the RunAs command. The only difference is, that it should read from registry. My problem is, that i need to reed 3 values from the registry, but i can't. It reads the first, than it fails at the second one (Password) with error code 2, which means "The system cannot find the file specified". If i query only for domain and username then it is ok, if i query only for password then it it still succeeds, but if i want to query all three then it fails. Can someone tell me, what i am doing wrong? Heres my code: HKEY hKey = 0; DWORD dwType = REG_SZ; DWORD dwBufSize = sizeof(buf); TCHAR szMsg [MAX_PATH + 32]; HANDLE handle; LPVOID lpMsgBuf; if( RegOpenKeyEx( HKEY_CURRENT_USER, TEXT("SOFTWARE\\Kampi Corporation\\RunAs!"), 0, KEY_QUERY_VALUE, &hKey ) == ERROR_SUCCESS ) { if( RegQueryValueEx( hKey, TEXT("Username"), 0, &dwType, (LPBYTE)buf, &dwBufSize ) == ERROR_SUCCESS ) { memset( szMsg, 0, sizeof( szMsg ) ); wsprintf ( szMsg, _T("%s"), buf ); mbstowcs( wuser, szMsg, 255 ); RegCloseKey( hKey ); } else { MessageBox ( pCmdInfo->hwnd, "Can not query for Username key value!", _T("RunAs!"), MB_ICONERROR ); RegCloseKey( hKey ); return -1; } } else { CSimpleShlExt::showerror( GetLastError(), pCmdInfo->hwnd, "RegOpenKeyEx failed for Username with error code :: " ); return -1; } if( RegOpenKeyEx( HKEY_CURRENT_USER, TEXT("SOFTWARE\\Kampi Corporation\\RunAs!"), 0, KEY_QUERY_VALUE ,&hKey ) == ERROR_SUCCESS ) { if( RegQueryValueEx( hKey, TEXT("Password"), 0, &dwType, (LPBYTE)buf, &dwBufSize ) == ERROR_SUCCESS ) { memset( szMsg, 0, sizeof( szMsg ) ); wsprintf ( szMsg, _T("%s"), buf ); mbstowcs( wpass, szMsg, 255 ); RegCloseKey( hKey ); } else { char test[200]; sprintf(test,"Can not query for Password key value! EC: %d",GetLastError() ); MessageBox ( pCmdInfo->hwnd, test, _T("RunAs!"), MB_ICONERROR ); RegCloseKey( hKey ); return -1; } } else { CSimpleShlExt::showerror( GetLastError(), pCmdInfo->hwnd, "RegOpenKeyEx failed for Password with error code :: " ); return -1; } if( RegOpenKeyEx( HKEY_CURRENT_USER, TEXT("SOFTWARE\\Kampi Corporation\\RunAs!"), 0, KEY_QUERY_VALUE ,&hKey ) == ERROR_SUCCESS ) { if( RegQueryValueEx( hKey, TEXT("Domain"), 0, &dwType, (LPBYTE)buf, &dwBufSize ) == ERROR_SUCCESS ) { memset( szMsg, 0, sizeof( szMsg ) ); wsprintf ( szMsg, _T("%s"), buf ); mbstowcs( wdomain, szMsg, 255 ); RegCloseKey( hKey ); } else { char test[200]; sprintf(test,"Can not query for Password key value! EC: %d",GetLastError() ); MessageBox ( pCmdInfo->hwnd, test, _T("RunAs!"), MB_ICONERROR ); RegCloseKey( hKey ); return -1; } } else { CSimpleShlExt::showerror( GetLastError(), pCmdInfo->hwnd, "RegOpenKeyEx failed for Domain with error code :: " ); return -1; }

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  • Is this PHP/MySQL login script secure?

    - by NightMICU
    Greetings, A site I designed was compromised today, working on damage control at the moment. Two user accounts, including the primary administrator, were accessed without authorization. Please take a look at the log-in script that was in use, any insight on security holes would be appreciated. I am not sure if this was an SQL injection or possibly breach on a computer that had been used to access this area in the past. Thanks <?php //Start session session_start(); //Include DB config require_once('config.php'); //Error message array $errmsg_arr = array(); $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } //Create query $qry="SELECT * FROM user_control WHERE username='$login' AND password='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); //Collect details about user and assign session details $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['user_id']; $_SESSION['SESS_USERNAME'] = $member['username']; $_SESSION['SESS_FIRST_NAME'] = $member['name_f']; $_SESSION['SESS_LAST_NAME'] = $member['name_l']; $_SESSION['SESS_STATUS'] = $member['status']; $_SESSION['SESS_LEVEL'] = $member['level']; //Get Last Login $_SESSION['SESS_LAST_LOGIN'] = $member['lastLogin']; //Set Last Login info $qry = "UPDATE user_control SET lastLogin = DATE_ADD(NOW(), INTERVAL 1 HOUR) WHERE user_id = $member[user_id]"; $login = mysql_query($qry) or die(mysql_error()); session_write_close(); if ($member['level'] != "3" || $member['status'] == "Suspended") { header("location: http://members.tapp-essexvfd.org"); //CHANGE!!! } else { header("location: http://tapp-essexvfd.org/admin/admin_main.php"); } exit(); }else { //Login failed header("location: http://tapp-essexvfd.org/admin/index.php"); exit(); } }else { die("Query failed"); } ?>

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  • Android: HttpURLConnection not working properly

    - by giorgiline
    I'm trying to get the cookies from a website after sending user credentials through a POST Request an it seems that it doesn't work in android this way. ¿Am I doing something bad?. Please help. I've searched here in different posts but there's no useful answer. It's curious that this run in a desktop Java implementation it works perfect but it crashes in Android platform. And it is exactly the same code, specifically when calling HttpURLConnection.getHeaderFields(), it also happens with other member methods. It's a simple code and I don't know why the hell isn't working. DESKTOP CODE: This goes just in the main() HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ System.out.println("Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ System.out.println(cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } So the output is: login_key=20ad8177db4eca3f057c14a64bafc2c9 FASID=cabf20cc471fcacacdc7dc7e83768880 track=30c8183e4ebbe8b3a57b583166326c77 client-data=%7B%22ism%22%3Afalse%2C%22showm%22%3Afalse%2C%22ts%22%3A1349189669%7D ANDROID CODE: This goes inside doInBackground AsyncTask body HttpURLConnection connection = null; OutputStream out = null; try { URL url = new URL("http://www.XXXXXXXXXXXXXX.php"); String charset = "UTF-8"; String postback = "1"; String user = "XXXXXXXXX"; String password = "XXXXXXXX"; String rememberme = "on"; String query = String.format("postback=%s&user=%s&password=%s&rememberme=%s" , URLEncoder.encode(postback, charset) , URLEncoder.encode(user,charset) , URLEncoder.encode(password, charset) , URLEncoder.encode(rememberme, charset)); connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Accept-Charset", charset); connection.setDoOutput(true); connection.setFixedLengthStreamingMode(query.length()); out = connection.getOutputStream (); out.write(query.getBytes(charset)); if (connection.getHeaderFields() == null){ Log.v(TAG, "Header null"); }else{ for (String cookie: connection.getHeaderFields().get("Set-Cookie")){ Log.v(TAG, cookie.split(";", 2)[0]); } } } catch (IOException e){ e.printStackTrace(); } finally { try { out.close();} catch (IOException e) { e.printStackTrace();} connection.disconnect(); } And here there is no output, it seems that connection.getHeaderFields() doesn't return result. It takes al least 30 seconds to show the Log: 10-02 16:56:25.918: V/class com.giorgi.myproject.activities.HomeActivity(2596): Header null

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  • Using jQuery to call a web service

    - by Matt
    I have created a web service which takes a username and password as parameters and returns a list of children in JSON (the user is a Social Worker). The web service is hosted locally with IIS7. I am attempting to access the web service using javascript/jquery because it will eventually need to run as a mobile app. I'm not really experienced with web services, or javascript for that matter, but the following two links seemed to point me in the right direction: http://williamsportwebdeveloper.com/cgi/wp/?p=494 http://encosia.com/using-jquery-to-consume-aspnet-json-web-services/ This is my html page: <%@ Page Title="" Language="C#" MasterPageFile="~/MasterPage.Master" AutoEventWireup="true" CodeBehind="TestWebService.aspx.cs" Inherits="Sponsor_A_Child.TestWebService" %> <asp:Content ID="Content1" ContentPlaceHolderID="stylesPlaceHolder" runat="server"> <script type="text/javascript" src="Scripts/jquery-1.7.1.js"> $(document).ready(function () { }); function LoginClientClick() { $("#query_results").empty(); $("#query_results").append('<table id="ResultsTable" class="ChildrenTable"><tr><th>Child_ID</th><th>Child_Name</th><th>Child_Surname</th></tr>'); $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "http://localhost/PhoneWebServices/GetChildren.asmx/GetMyChildren", data: '{ "email" : "' + $("#EmailBox").val() + '", "password": "' + $("#PasswordBox").val() + '" }', dataType: "json", success: function (msg) { var c = eval(msg.d); alert("" + c); for (var i in c) { $("#ResultsTable tr:last").after("<tr><td>" + c[i][0] + "</td><td>" + c[i][1] + "</td><td>" + c[i][2] + "</td></tr>"); } } }); } </script> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="contentPlaceHolder" runat="server"> <div id="LoginDiv"> Email: <input id="EmailBox" type="text" /><br /> Password: <input id="PasswordBox" type="password" /><br /> <input id="LoginButton" type="button" value="Submit" onclick="LoginClientClick()" /> </div> <div id="query_results"> </div> </asp:Content> And this is my web service code: [WebMethod (Description="Returns the list of children for whom the social worker is responsible.")] public String GetMyChildren(String email,String password) { DataSet MyChildren=new DataSet(); int ID=SocialWorkerLogin(email, password); if (ID > 0) { MyChildren = FillChildrenTable(ID); } MyChildren.DataSetName = "My Children"; //To prevent 'DataTable name not set' error string[][] JaggedArray = new string[MyChildren.Tables[0].Rows.Count][]; int i = 0; foreach (DataRow rs in MyChildren.Tables[0].Rows) { JaggedArray[i] = new string[] { rs["Child_ID"].ToString(), rs["Child_Name"].ToString(), rs["Child_Surname"].ToString() }; i = i + 1; } // Return JSON data JavaScriptSerializer js = new JavaScriptSerializer(); string strJSON = js.Serialize(JaggedArray); return strJSON; } I followed the examples in the provided links, but when I press submit, only the table headers appear but not the list of children. When I test the web service on it's own though, it does return a JSON string so that part seems to be working. Any help is greatly appreciated :)

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  • php curl http 405 error mind body online api

    - by K_G
    I am trying to connect to the Mind Body Online API (their forum is down currently, so I came here). Below is the code I am using. I am receiving this: SERVER ERROR 405 - HTTP verb used to access this page is not allowed. The page you are looking for cannot be displayed because an invalid method (HTTP verb) was used to attempt to access. code: //Data, connection, auth $soapUrl = "http://clients.mindbodyonline.com/api/0_5"; // xml post structure $xml_post_string = '<?xml version="1.0" encoding="utf-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns="http://clients.mindbodyonline.com/api/0_5"> <soapenv:Header/> <soapenv:Body> <GetClasses> <Request> <SourceCredentials> <SourceName>username</SourceName> <Password>password</Password> <SiteIDs> <int>site id</int> </SiteIDs> </SourceCredentials> <UserCredentials> <Username>username</Username> <Password>password</Password> <SiteIDs> <int></int> </SiteIDs> </UserCredentials> <Fields> <string>Classes.Resource</string> </Fields> <XMLDetail>Basic</XMLDetail> <PageSize>10</PageSize> <CurrentPageIndex>0</CurrentPageIndex> </Request> </GetClasses> </soapenv:Body> </soapenv:Envelope>'; $headers = array( "Content-type: text/xml;charset=\"utf-8\"", "Accept: text/xml", "Cache-Control: no-cache", "Pragma: no-cache", "SOAPAction: http://clients.mindbodyonline.com/api/0_5", "Content-length: ".strlen($xml_post_string), ); //SOAPAction: your op URL $url = $soapUrl; // PHP cURL for https connection with auth $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_ANY); curl_setopt($ch, CURLOPT_TIMEOUT, 10); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $xml_post_string); // the SOAP request curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); // converting $response = curl_exec($ch); curl_close($ch); var_dump($response); // converting //$response1 = str_replace("<soap:Body>","",$response); //$response2 = str_replace("</soap:Body>","",$response1); // convertingc to XML //$parser = simplexml_load_string($response2); // user $parser to get your data out of XML response and to display it. Any help would be great and if anyone has any experience working with their API, my first time ;) Here is the post on stack I am going off of: SOAP request in PHP

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  • upload video to youtube via iphone application ----ServiceForbiddenException

    - by user577670
    Hey,I use GData try to upload my video to youtube, but meet these error: serviceBase:<GDataServiceGoogleYouTube: 0x2435f0> objectFetcher:<GDataHTTPUploadFetcher: 0x26dca0> failedWithStatus:403 data:<errors xmlns='http://schemas.google.com/g/2005'> <error> <domain>GData</domain> <code>ServiceForbiddenException</code> <internalReason>Currently authenticated user does not have write access to desrender&apos;s videos.</internalReason> </error> </errors> * is my youtube account. Following is the code: - (GDataServiceGoogleYouTube *)youTubeService { static GDataServiceGoogleYouTube* service = nil; if (!service) { service = [[GDataServiceGoogleYouTube alloc] init]; [service setShouldCacheDatedData:YES]; [service setServiceShouldFollowNextLinks:YES]; [service setIsServiceRetryEnabled:YES]; } // update the username/password each time the service is requested NSString *username = [mUsernameField text]; NSString *password = [mPasswordField text]; if ([username length] > 0 && [password length] > 0) { [service setUserCredentialsWithUsername:username password:password]; } else { // fetch unauthenticated [service setUserCredentialsWithUsername:nil password:nil]; } NSString *devKey = [mDeveloperKeyField text]; [service setYouTubeDeveloperKey:devKey]; return service; } - (IBAction)uploadPressed:(id)sender { NSString *devKey = [mDeveloperKeyField text]; GDataServiceGoogleYouTube *service = [self youTubeService]; [service setYouTubeDeveloperKey:devKey]; NSString *username = [mUsernameField text]; NSString *clientID = [mClientIDField text]; NSURL *url = [GDataServiceGoogleYouTube youTubeUploadURLForUserID:username clientID:clientID]; // load the file data NSString *path = [[NSBundle mainBundle] pathForResource:@"YouTubeTest" ofType:@"m4v"]; NSData *data = [NSData dataWithContentsOfFile:path]; NSString *filename = [path lastPathComponent]; // gather all the metadata needed for the mediaGroup NSString *titleStr = [mTitleField text]; GDataMediaTitle *title = [GDataMediaTitle textConstructWithString:titleStr]; NSString *categoryStr = [mCategoryField text]; GDataMediaCategory *category = [GDataMediaCategory mediaCategoryWithString:categoryStr]; [category setScheme:kGDataSchemeYouTubeCategory]; NSString *descStr = [mDescriptionField text]; GDataMediaDescription *desc = [GDataMediaDescription textConstructWithString:descStr]; NSString *keywordsStr = [mKeywordsField text]; GDataMediaKeywords *keywords = [GDataMediaKeywords keywordsWithString:keywordsStr]; BOOL isPrivate = mIsPrivate; GDataYouTubeMediaGroup *mediaGroup = [GDataYouTubeMediaGroup mediaGroup]; [mediaGroup setMediaTitle:title]; [mediaGroup setMediaDescription:desc]; [mediaGroup addMediaCategory:category]; [mediaGroup setMediaKeywords:keywords]; [mediaGroup setIsPrivate:isPrivate]; NSString *mimeType = [GDataUtilities MIMETypeForFileAtPath:path defaultMIMEType:@"video/mp4"]; // create the upload entry with the mediaGroup and the file data GDataEntryYouTubeUpload *entry; entry = [GDataEntryYouTubeUpload uploadEntryWithMediaGroup:mediaGroup data:data MIMEType:mimeType slug:filename]; SEL progressSel = @selector(ticket:hasDeliveredByteCount:ofTotalByteCount:); [service setServiceUploadProgressSelector:progressSel]; GDataServiceTicket *ticket; ticket = [service fetchEntryByInsertingEntry:entry forFeedURL:url delegate:self didFinishSelector:@selector(uploadTicket:finishedWithEntry:error:)]; [self setUploadTicket:ticket]; } It almost same as GData's YouTubeSample.. Someone help me!!!!

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  • ASP.Net MVC 2 is it possible to get the same instance of model(with slight changes) in HttpPost meth

    - by jjjjj
    Hi I have a complex entity User: public class User : BaseEntity { public virtual Taxi Taxi { get; set; } --> That is why i call it "complex" public virtual string Login { get; set; } public virtual string Password { get; set; } } where Taxi is a parent of User (Taxi has-many Users): public class Taxi : BaseEntity { public virtual string Name { get; set; } public virtual string ClientIp { get; set; } } BaseEntity consists of public virtual int Id { get; private set; } The problem occurs while trying to edit User [Authorize] public ActionResult ChangeAccountInfo() { var user = UserRepository.GetUser(User.Identity.Name); return View(user); } My ChangeAccountInfo.aspx <fieldset> <legend>Fields</legend> <% %> <div class="editor-label"> <%: Html.LabelFor(model => model.Login) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Login) %> <%: Html.ValidationMessageFor(model => model.Login) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Password) %> <%: Html.ValidationMessageFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.HiddenFor(model => model.Taxi.Name)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> Post changes: [Authorize] [HttpPost] public ActionResult ChangeAccountInfo(User model) { if (ModelState.IsValid) { UserRepository.UpdateUser(model); return RedirectToAction("ChangeAccountInfoSuccess", "Account"); } return View(model); } But, the (User model) parameter has User.Id == 0 -- User entity had 5 before edit User.Login == "my new login" User.Password == "my new password" User.Taxi.Id == 0 -- User.Taxi entity had 3 before edit User.Taxi.Name == "old hidden name" User.Taxi.ClientIp == null -- User entity had 192.168.0.1 before edit Q: Is it possible not to mark all the fields of an entity (that should be in my UpdateUser) with tag "hidden" but still have them unchanged in my HttpPost method? e.g. not User.Taxi.ClientIp = null, but User.Taxi.ClientIp = 192.168.0.1 I'm using nhibernate, if it matters.

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  • Java, LDAP: Make it not ignore blank passwords?

    - by Steve
    I'm maintaining some legacy Java LDAP code. I know next to nothing about LDAP. The program below basically just sends the userid and password to the LDAP server, receives notification back if the credentials are good. If so, it prints out the LDAP attributes received from the LDAP server, if not it prints out an exception. All works well if a bad password is given. An "invalid credentials" exception gets thrown. However, if a blank password is sent to the LDAP Server, authentication will still happen, LDAP attributes will still be returned. Is this unhappy situation due to the LDAP server allowing blank passwords, or does the code below need to be adjusted such a blank password will get fed to the LDAP server in such a way so it will get rejected? I do have data validation in place. I took it off in a testing environment to solve another issue and noticed this problem. I would prefer not to have this problem underneath the data validation. Thanks much in advance for any information import javax.naming.*; import javax.naming.directory.*; import java.util.*; import java.sql.*; public class LDAPTEST { public static void main(String args[]) { String lcf = "com.sun.jndi.ldap.LdapCtxFactory"; String ldapurl = "ldaps://ldap-cit.smew.acme.com:636/o=acme.com"; String loginid = "George.Jetson"; String password = ""; DirContext ctx = null; Hashtable env = new Hashtable(); Attributes attr = null; Attributes resultsAttrs = null; SearchResult result = null; NamingEnumeration results = null; int iResults = 0; int iAttributes = 0; env.put(Context.INITIAL_CONTEXT_FACTORY, lcf); env.put(Context.PROVIDER_URL, ldapurl); env.put(Context.SECURITY_PROTOCOL, "ssl"); env.put(Context.SECURITY_AUTHENTICATION, "simple"); env.put(Context.SECURITY_PRINCIPAL, "uid=" + loginid + ",ou=People,o=acme.com"); env.put(Context.SECURITY_CREDENTIALS, password); try { ctx = new InitialDirContext(env); attr = new BasicAttributes(true); attr.put(new BasicAttribute("uid",loginid)); results = ctx.search("ou=People",attr); while (results.hasMore()) { result = (SearchResult)results.next(); resultsAttrs = result.getAttributes(); for (NamingEnumeration enumAttributes = resultsAttrs.getAll(); enumAttributes.hasMore();) { Attribute a = (Attribute)enumAttributes.next(); System.out.println("attribute: " + a.getID() + " : " + a.get().toString()); iAttributes++; }// end for loop iResults++; }// end while loop System.out.println("Records == " + iResults + " Attributes: " + iAttributes); }// end try catch (Exception e) { e.printStackTrace(); } }// end function main() }// end class LDAPTEST

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  • User welcome message in php

    - by user225269
    How do I create a user welcome message in php. So that the user who has been logged on will be able to see his username. I have this code, but it doesn't seem to work. <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM users WHERE Username='$username'"); while($row = mysql_fetch_array($result)) { echo $row['Username']; echo "<br />"; } ?> I'm trying to make use of the data that is inputted in this login form: <form name="form1" method="post" action="verifylogin.php"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="myusername" type="text" id="idnum" maxlength="5"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="mypassword" type="password" id="lname" maxlength="15"></td> </tr> <td align="right" width="30"><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td align="right" width="30"><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> But this, verifylogin.php, seems to be in the way. <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:userpage.php"); } else { echo "Wrong Username or Password"; } ?> How do I do it? I always get this error when I run it: Notice: Undefined variable: username in C:\wamp\www\exp\userpage.php on line 53 Can you recommend of an easier on how I can achieve the same thing?

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