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  • How do I overlay an icon/image onto another image on form submission?

    - by marcamillion
    So I am trying to add an icon to an image, once someone has 'tagged' a portion of the image - i.e. they have submitted the form. How do I do that in jQuery? Just to be clear...imagine you are on flickr and you see an image. You want to add an annotation, you click on the image where you want, and it shows you a form field. You enter the information you want to, then after you have done so, there is a small image left on top of the picture that shows where you have left a comment. Any ideas?

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  • WPF TreeView PreviewMouseDown on TreeViewItem

    - by imekon
    If I handle the PreviewMouseDown event on TreeViewItem, I get events for everything I click on that TreeViewItem include the little +/- box to the left (Windows XP). How can I distinguish that? I tried the following: // We've had a single click on a tree view item // Unfortunately this is the WHOLE tree item, including the +/- // symbol to the left. The tree doesn't do a selection, so we // have to filter this out... MouseDevice device = e.Device as MouseDevice; // This is bad. The whole point of WPF is for the code // not to know what the UI has - yet here we are testing for // it as a workaround. Sigh... // This is broken - if you click on the +/- on a item, it shouldn't // go on to be processed by OnTreeSingleClick... ho hum! if (device.DirectlyOver.GetType() != typeof(Path)) { OnTreeSingleClick(sender); } What I'm after is just single click on the tree view item excluding the extra bits it seems to include.

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  • X11: How do I REALLY grab the mouse pointer?

    - by Drew Hall
    I've implemented a horizontal splitter widget in Xlib. I'm trying to grab the mouse when the user clicks & drags on the splitter bar (so that the user can dynamically move the split & thus resize the windows on either side of the splitter bar). I've used XGrabPointer() after receiving a left click, in hopes that all future mouse motion (dragging) will be diverted to the splitter window until the left button is released. Unfortuntately, it doesn't seem to work like that. If the user drags too quickly and the mouse pointer enters one of the windows on either side of the split, the MotionEvent messages are diverted to that (child) window rather than the splitter window. What have I done wrong? My XGrabPointer() call is as follows: ::XGrabPointer(mDisplay, window, True, ButtonPressMask | ButtonReleaseMask | PointerMotionMask | FocusChangeMask | EnterWindowMask | LeaveWindowMask, GrabModeAsync, GrabModeAsync, RootWindow(mDisplay, DefaultScreen(mDisplay)), None, CurrentTime);

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  • Query joining in sql server 2005

    - by Domnic
    I have two queries like: SELECT PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO ACCOUNT, COUNT(PC_CHEQUE_NO) CHQS, SUM(CONVERT(FLOAT, PC_AMOUNT)) CHQ_AMT FROM GLAS_PDC_CHEQUES WHERE PC_COMP_CODE = '1' AND PC_DISCD IS NULL GROUP BY PC_SL_LDGR_CODE, PC_SL_ACNO ,PC_COMP_CODE ORDER BY PC_SL_ACNO -------------------------------------------------- SELECT COAD_PTY_FULL_NAME,PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO, PC_DEPT_NO, PC_DOC_TYPE, PC_CHEQUE_NO, PC_BANK_AC_NO FROM GLAS_PTY_ADDRESS,GLAS_SBLGR_MASTERS,GLAS_PDC_CHEQUES WHERE COAD_COMP_CODE = '1' AND SLMA_COMP_CODE = COAD_COMP_CODE AND SLMA_ADDR_ID = COAD_ADDR_ID AND SLMA_LDGRCTL_CODE = PC_SL_LDGR_CODE AND PC_COMP_CODE=SLMA_COMP_CODE AND SLMA_ACNO = PC_SL_ACNO AND SLMA_LDGRCTL_YEAR = DBO.GLAS_VALIDATIONS_GET_OPEN_YEAR(PC_COMP_CODE) If I execute first query alone I get 5 records... If I join the above two query like: SELECT PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO ACCOUNT, COUNT(PC_CHEQUE_NO) CHQS, SUM(CONVERT(FLOAT, PC_AMOUNT)) CHQ_AMT, COAD_PTY_FULL_NAME FROM GLAS_PDC_CHEQUES LEFT OUTER JOIN GLAS_SBLGR_MASTERS ON( SLMA_COMP_CODE=PC_COMP_CODE AND SLMA_LDGRCTL_CODE = PC_SL_LDGR_CODE AND SLMA_ACNO = PC_SL_ACNO ) LEFT OUTER JOIN GLAS_PTY_ADDRESS ON( SLMA_COMP_CODE = COAD_COMP_CODE AND SLMA_ADDR_ID = COAD_ADDR_ID) WHERE PC_COMP_CODE = '1' AND PC_DISCD IS NULL AND SLMA_LDGRCTL_YEAR = DBO.GLAS_VALIDATIONS_GET_OPEN_YEAR(PC_COMP_CODE) GROUP BY PC_SL_LDGR_CODE, PC_SL_ACNO ,PC_COMP_CODE,COAD_PTY_FULL_NAME ORDER BY PC_SL_ACNO then I just get 2 records.... I need that 5 records to display after join..... How can I do it?

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  • Implementing rounded corners on slide down navigation menu

    - by Nick
    I am working on the slide down menu you can see here. I have rounded corners on both ul#navigation and ul.subnavigation. When the submenu slides down it is possible to see the border at the bottom of ul.subnavigation overlap with the content of ul#navigation, when I would like it to slide down smoothly, without the 'flicker'. I am aware that this issue is caused by the rounded corners. I need ul.subnavigation to cover the rounded corners at the bottom of ul#navigation when the menu drops down, without seeing the double border-bottom issue. I hope this is clear! Code is below. Thanks, Nick HTML <ul id="navigation"> <li class="dropdown"><a href="#">menu</a> <ul class="sub_navigation"> <li><a href="#">home</a></li> <li><a href="#">help</a></li> <li><a href="#">disable tips</a></li> </ul> </li> </ul> JQUERY $('.dropdown').hover(function() { $(this).find('.sub_navigation').slideToggle(); });? CSS ul#navigation, ul.sub_navigation { margin:0; padding:0; list-style-type:none; min-width:100px; background-color: white; font-size:15px; font-family: Trebuchet MS; text-align: center; -khtml-border-radius: 0 0 5px 5px; -moz-border-radius: 0 0 5px 5px; -webkit-border-radius: 0 0 5px 5px; border-radius: 0 0 5px 5px; border:1px black solid; border-top:none; } ul.sub_navigation { margin-left:-1px; position: absolute; top:28px; } ul#navigation { float:left; position:absolute; top:0; } ul#navigation li { float:left; min-width:100px; } ul.sub_navigation { position:absolute; display:none; } ul.sub_navigation li { clear:both; } a, a:active, a:visited { display:block; padding:7px; }

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  • How can give third child div within one parent div

    - by Mubeen
    I have one Parent div. Top of the Parent div contains two child divs. How can i give third child div below the first child div <div class=parent1> <div class=child1>some text</div> /*this is in top left of the parent div */ <div class=child2>some text</div> /*this is in top right of the parent div */ <div class=child3>some text</div> /*how can i write css for this div come as left bottom*/

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  • WindowStartupLocation.CenterScreen is opening my window on the wrong display

    - by chaiguy
    According to the documentation, CenterScreen should open the window in the center of the screen that contains the mouse cursor, however this is not happening. I have a dual monitor setup, with my secondary monitor appearing to the left of my primary monitor (the one with the task bar). When the user clicks a link in my interface on the primary (right-most) monitor, and I open a new window with WindowStartupLocation set to CenterScreen, the window appears in the center of the screen of the left monitor. This is not where the mouse is and I am lost as to why it is picking that display. Has anyone experienced this before or have any ideas for a workaround? If I can't get the proper behavior using WindowStartupLocation, I will just manually move the window to the proper display (I still have to figure that out though).

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  • Optimize MySQL query (ngrams, COUNT(), GROUP BY, ORDER BY)

    - by Gerardo
    I have a database with thousands of companies and their locations. I have implemented n-grams to optimize search. I am making one query to retrieve all the companies that match with the search query and another one to get a list with their locations and the number of companies in each location. The query I am trying to optimize is the latter. Maybe the problem is this: Every company ('anunciante') has a field ('estado') to make logical deletes. So, if 'estado' equals 1, the company should be retrieved. When I run the EXPLAIN command, it shows that it goes through almost 40k rows, when the actual result (the reality matching companies) are 80. How can I optimize this? This is my query (XXX represent the n-grams for the search query): SELECT provincias.provincia AS provincia, provincias.id, COUNT(*) AS cantidad FROM anunciantes JOIN anunciante_invertido AS a_i0 ON anunciantes.id = a_i0.id_anunciante JOIN indice_invertido AS indice0 ON a_i0.id_invertido = indice0.id LEFT OUTER JOIN domicilios ON anunciantes.id = domicilios.id_anunciante LEFT OUTER JOIN localidades ON domicilios.id_localidad = localidades.id LEFT OUTER JOIN provincias ON provincias.id = localidades.id_provincia WHERE anunciantes.estado = 1 AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') GROUP BY provincias.id ORDER BY cantidad DESC And this is the query explained (hope it can be read in this format): id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY anunciantes ref PRIMARY,estado estado 1 const 36669 Using index; Using temporary; Using filesort 1 PRIMARY domicilios ref id_anunciante id_anunciante 4 db84771_viaempresas.anunciantes.id 1 1 PRIMARY localidades eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.domicilios.id_localidad 1 1 PRIMARY provincias eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.localidades.id_provincia 1 1 PRIMARY a_i0 ref PRIMARY,id_anunciante,id_invertido PRIMARY 4 db84771_viaempresas.anunciantes.id 1 Using where; Using index 1 PRIMARY indice0 eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.a_i0.id_invertido 1 Using index 6 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 6 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 5 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 5 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 4 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 4 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 3 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 3 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 2 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 2 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index

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  • Positioning a tooltip relative to another div in JQuery

    - by James P
    Here's my tooltips markup and CSS: <div class="tooltip">Click here to like it</div> .tooltip { position: absolute; display: none; background: url('images/tooltip.gif') no-repeat; width: 100%; height: 40px; font-size: 0.8em; line-height: 40px; padding: 0px 0px 0px 8px; } Now, I have a div on my page called #button_container. I would like to place this .tooltip div 150px to the right of that div via JQuery. I understand I need to set this tooltips top and left attributes, but not sure how. Idealy the tooltips top attribute should be the same as #button_container (although #button_container isn't positioned absolutely) and 150 less than #button_container's left attribute. I don't really know where to get started on this so any help would be very much appreciated. Thanks.

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  • XSL file handling through javascript

    - by Zaid Iqbal
    i want to handle my xsl file through my javascript code. I made my XSL file but i want to dynamically change my XSL file at run time.As in add more attributes in header or data. My javascript code as follow` <script> function loadXMLDoc(dname) { if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest(); } else { xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.open("GET",dname,false); xhttp.send(""); return xhttp.responseXML; } function displayResult() { xml=loadXMLDoc("cdcatalog.xml"); xsl=loadXMLDoc("cdcatalog.xsl"); // code for IE if (window.ActiveXObject) { ex=xml.transformNode(xsl); document.getElementById("example").innerHTML=ex; } // code for Mozilla, Firefox, Opera, etc. else if (document.implementation && document.implementation.createDocument) { xsltProcessor=new XSLTProcessor(); xsltProcessor.importStylesheet(xsl); resultDocument = xsltProcessor.transformToFragment(xml,document); document.getElementById("example").appendChild(resultDocument); } } </script> My XSL file code: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <h2>My CD Collection</h2> <table border="1"> <tr bgcolor="#9acd32"> <th align="left">Title</th> <th align="left">Artist</th> <th align="left">Country</th> </tr> <xsl:for-each select="catalog/cd"> <tr> <td><xsl:value-of select="title" /></td> <td><xsl:value-of select="artist" /></td> <td><xsl:value-of select="country" /></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> `

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  • Thinking of an Inner Join as a Cross Join and then satisfying some condition(s)?

    - by Jian Lin
    It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then satisfying some condition(s)? Because the equi-join can be obvious, but the non-equi-join can be a bit confusing. But if we always use the Cross Join, and then filter out the ones satisfying the condition, then we get the resulting table. In other words, we can always analyze it by using the first record on the left table, and then go through every single records on the right, and then repeat that for 2nd record on the left, and for the 3rd, 4th, ... etc. So in our mind, we can analyze it using this way, and it is like O(n^2), although what happens in the DBMS maybe that it is a lot faster (when an index is present). Is there another good way to think of it besides this method?

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  • Binary Tree operator overloading and recursion

    - by furious.snail
    I was wondering how to overload the == operator for a binary tree to compare if two trees have identical data at same nodes. So far this is what I have: bool TreeType::operator==(const TreeType& otherTree) const { if((root == NULL) && (otherTree.root == NULL)) return true; //two null trees are equal else if((root != NULL) && (otherTree.root != NULL)) { return((root-info == otherTree.root-info) && //this part doesn't actually do anything recursively... //(root-left == otherTree.root-left) && //(root-right == otherTree.root-right)) } else return false; //one tree is null the other is not } I have a similar function that takes two TreeNode pointers as parameters but I've been stuck on how to convert it to this function.

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  • hibernate createSQL how to cache it?

    - by cometta
    If i use Criteria statement, i able to use cache easily. but when i using custom CREATESQL, like below, how do i cache it? Query query = getHibernateTemplate().getSessionFactory().getCurrentSession().createSQLQuery( " select company_keysupplier.ddiv as ddiv, company_division.name as DIVISION, company_keysupplier.ddep as ddep,company_department.name as DEPARTMENT"+ " from company_keysupplier "+ " left join company_division on "+ " (company_keysupplier.ddiv= company_division.division_code and company_keysupplier.survey_num=company_division.survey_num) "+ " left join company_department on "+ " (company_keysupplier.ddep= company_department.department_code and company_keysupplier.survey_num=company_department.survey_num) "+ " where company_keysupplier.sdiv = :sdiv and company_keysupplier.sdep = :sdep and company_keysupplier.survey_num= :surveyNum " + " order by company_division.name, company_keysupplier.ddep " ) .addScalar("ddiv") .addScalar("ddep") .addScalar("DIVISION") .addScalar("DEPARTMENT") .setResultTransformer(Transformers.aliasToBean(IssKeysupplier.class)); query.setString("sdiv", sdiv); query.setString("sdep", sdepartment); query.setBigInteger("surveyNum", survey_num); //i tried query.setCachable(true) fail...... List result= (List<IssKeysupplier>)query.list(); return result;

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  • It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then sa

    - by Jian Lin
    It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then satisfying some condition(s)? Because the equi-join can be obvious, but the non-equi-join can be a bit confusing. But if we always use the Cross Join, and then filter out the ones satisfying the condition, then we get the resulting table. In other words, we can always analyze it by using the first record on the left table, and then go through every single records on the right, and then repeat that for 2nd record on the left, and for the 3rd, 4th, ... etc. So in our mind, we can analyze it using this way, and it is like O(n^2), although what happens in the DBMS maybe that it is a lot faster (when an index is present). Is there another good way to think of it besides this method?

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  • how to drag a 'div' element to the google maps ,that be changed to a 'marker'..use jquery

    - by zjm1126
    this is my code : <!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mobile 1.0//EN" "http://www.wapforum.org/DTD/xhtml-mobile10.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width,minimum-scale=1.0,maximum-scale=1.0,user-scalable=no"> </head> <body onload="initialize()" onunload="GUnload()"> <style type="text/css"> </style> <div id="map_canvas" style="width: 500px; height: 300px;float:left;"></div> <div id=b style="width: 50px; height: 50px;background:red;float:left;margin-left:300px;"></div> <script src="jquery-1.4.2.js" type="text/javascript"></script> <script src="jquery-ui-1.8rc3.custom.min.js" type="text/javascript"></script> <script src="http://ditu.google.cn/maps?file=api&amp;v=2&amp;key=ABQIAAAA-7cuV3vqp7w6zUNiN_F4uBRi_j0U6kJrkFvY4-OX2XYmEAa76BSNz0ifabgugotzJgrxyodPDmheRA&sensor=false"type="text/javascript"></script> <script type="text/javascript"> //********** function initialize() { if (GBrowserIsCompatible()) { // function createMarker(point, number) { var marker = new GMarker(point); var message = ["?","?","?","??","??"]; marker.value = number; GEvent.addListener(marker, "click", function() { var myHtml = "<b>#" + number + "</b><br/>" + message[number -1]; map.openInfoWindowHtml(point, myHtml); }); return marker; } // var map = new GMap2(document.getElementById("map_canvas")); map.setCenter(new GLatLng(39.9493, 116.3975), 13); // Add 5 markers to the map at random locations var bounds = map.getBounds(); var southWest = bounds.getSouthWest(); var northEast = bounds.getNorthEast(); var lngSpan = northEast.lng() - southWest.lng(); var latSpan = northEast.lat() - southWest.lat(); for (var i = 0; i < 5; i++) { var point = new GLatLng(southWest.lat() + latSpan * Math.random(), southWest.lng() + lngSpan * Math.random()); map.addOverlay(createMarker(point, i + 1)); } } } //************* $("#b").draggable(); </script> </body> </html>

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  • Class not overwriting with addClass

    - by scatteredbomb
    I'm using jQuery's addClass to add a class to an tab so when clicked it'll change the class so it's obvious the tab is highlighted. My HTML <div id="mainNav"> <ul> <li id="LinktheBand" onclick="nav('theBand')">The Band</li> <li id="linkTheMusic" onclick="nav('theMusic')">The Music</li> My CSS #mainNav li { float:left; margin-right:5px; color:white; font-family:Tahoma; font-weight:bold; padding: 10px 8px 0px 8px; background:url('../images/transparent-65.png'); height:40px; height: 25px !important; border:1px solid #000; } #mainNav li:hover { float:left; margin-right:5px; color:white; font-family:Tahoma; font-weight:bold; padding: 10px 8px 0px 8px; background: #660000; height:40px; height: 25px !important; border:1px solid #660000; } .mainNavSelected { float:left; margin-right:5px; color:white; font-family:Tahoma; font-weight:bold; padding: 10px 8px 0px 8px; background: #660000; height:40px; height: 25px !important; border:1px solid #660000; } My Javascript function nav(a) { $('#'+a).show(); $('#Link'+a).addClass('mainNavSelected'); } This works properly, I check firebug and can see the class="mainNavSelected" is added, but the list element doesn't take any properties of the new class. Firebug lists all the class items for mainNavSelected, but has them all crossed out. What am i missing to replace the class of this element?

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  • Measure width() with jQuery after DOM refresh

    - by o_O Tync
    My script dynamically creates a <ul> width left-floating <li>s inside: it's a paginator. Afterwards, the script measures width of all <li>s and summs them up. The problem is that after the nodes are injected into the document — the browser refreshed DOM and applies CSS styles which takes a while. It has a negative effect on my script: when these operations are not complete before I measure the width — my script gets a wrong value. If I perform the measure in a second — everything is ok. The thing I'm looking for is a way to detect the moment when the <ul> is fully drawn, styles applied and the width has stabilizes. Or at least a way to detect every dimensions changes. Of course I can use setTimeout(..., 100) but it's ugly and I guess — not a solution at all. If there's a way to detect width stabilization — I would do the measuring right after it to get the correct values. HTML code generated by the DOM <div> <ul> <li><a href="...">1</a></li> <li><a href="...">2</a></li> .... </ul> </div> P.S. Why I need this. My paginator's left-floating <li> items tend to move to the next line when the <ul> tries to become wider than the page itself. Even though most of <li>s are invisible because of parent <div>'s width restriction: div { width: 500px; overflow: hidden; } div ul { width: 100%; white-space: nowrap; } div ul li { display: block; float: left; } they still go down unless I specify the actual summed width of the <ul> with the script.

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  • Box Shadow on only 3 sides

    - by Connor
    I have two overlapping divs that have css3 box shadows. The trouble is that even when I set the z-index I will still need to eliminate one of the div's box-shadow. I have seen cases where negative spreads and zero values are used but I don't think that would work here. The code I have now is: #bulb-top { position: relative; width: 280px; height: 280px; background-color: #E5F7A3; -webkit-border-radius: 280px; -moz-border-radius: 280px; border-radius: 280px; border: 8px solid #FFF40C; top: -430px; margin-left: auto; margin-right: auto; -webkit-box-shadow: 0px 0px 15px 1px #FFF40C; -moz-box-shadow: 0px 0px 15px 1px #FFF40C; box-shadow: 0px 0px 15px 1px #FFF40C; z-index: 4; } #bulb-bottom { position: relative; width: 140px; height: 120px; background-color: #E5F7A3; -moz-border-radius-topleft: 0px; -moz-border-radius-topright: 0px; -moz-border-radius-bottomright: 30px; -moz-border-radius-bottomleft: 30px; -webkit-border-radius: 0px 0px 30px 30px; border-radius: 0px 0px 30px 30px; border-left: 8px solid #FFF40C; border-right: 8px solid #FFF40C; border-bottom: 8px solid #FFF40C; top: -455px; margin-left: auto; margin-right: auto; -webkit-box-shadow: 0px 0px 15px 1px #FFF40C; -moz-box-shadow: 0px 0px 15px 1px #FFF40C; box-shadow: 0px 0px 15px 1px #FFF40C; z-index: 5; } http://jsfiddle.net/minitech/g42vq/3/

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  • Get the position of a div/span tag

    - by schmoopy
    Can someone show me how to get the .top & .left position of a div or span tag when one is not specified? ie: <span id='11a' style='top:55px;' onmouseover="GetPos(this);">stuff</span> <span id='12a' onmouseover="GetPos(this);">stuff</span> In the above, if i do: document.getElementById('11a').style.top The the value of 55px is returned. However if i try that for span '12a', then nothing gets returned. I have a bunch of div/spans on a page that i cannot specify the top/left properties for, but i need to display a div directly under that element. Thanks for lookin :-)

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  • OpenGL Projection matrix won't allow displaying anything

    - by user272973
    I'm trying to get some basic OpenGL-ES with Shaders to run on the iPhone, based on some examples. For some reason my projection matrix refuses to result in something on the screen. It feels like a clipping plane is set very near but that contradicts with the values I supply. If I render the same scene with an Orthogonal projection matrix I see my object just no perspective obviously. Here's the code that generates the projection matrix: esPerspective(&proj, 45.f, 768.0/1024.0, 1.f, 10000.f); void esPerspective(ESMatrix *result, float fovy, float aspect, float nearZ, float farZ) { float frustumW, frustumH; frustumH = tanf( fovy / 360.0f * PI ) * nearZ; frustumW = frustumH * aspect; esFrustum( result, -frustumW, frustumW, -frustumH, frustumH, nearZ, farZ ); } void esFrustum(ESMatrix *result, float left, float right, float bottom, float top, float nearZ, float farZ) { float deltaX = right - left; float deltaY = top - bottom; float deltaZ = farZ - nearZ; ESMatrix frust; if ( (nearZ <= 0.0f) || (farZ <= 0.0f) || (deltaX <= 0.0f) || (deltaY <= 0.0f) || (deltaZ <= 0.0f) ) return; frust.m[0][0] = 2.0f * nearZ / deltaX; frust.m[0][1] = frust.m[0][2] = frust.m[0][3] = 0.0f; frust.m[1][1] = 2.0f * nearZ / deltaY; frust.m[1][0] = frust.m[1][2] = frust.m[1][3] = 0.0f; frust.m[2][0] = (right + left) / deltaX; frust.m[2][1] = (top + bottom) / deltaY; frust.m[2][2] = -(nearZ + farZ) / deltaZ; frust.m[2][3] = -1.0f; frust.m[3][2] = -2.0f * nearZ * farZ / deltaZ; frust.m[3][0] = frust.m[3][1] = frust.m[3][3] = 0.0f; esMatrixMultiply(result, &frust, result); } My projection matrix comes out as: [3.21, 0, 0, 0] [0, 2.41, 0, 0] [0, 0, -1, -1] [0, 0, -2, 0] Even if I manually set the [3][3] cell to 1 I still don't see anything. Any ideas?

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  • Using jQuery's animate(), if the clicked on element is "<a href="#" ...> </a>", the fucntion should

    - by Jian Lin
    I was reading jQuery's page for animate() http://api.jquery.com/animate/ Its examples don't mention about if using <a href="#" id="clickme">click me</a> ... $('#clickme').click(function() { $('#someDiv').animate({left: "+=60"}); }) we actually still have to return false like in the old days? $('#clickme').click(function() { $('#someDiv').animate({left: "+=60"}); return false; }) (but then, those examples didn't use a <a> for the "click me"... but used something else. Otherwise the page will jump back to the beginning of the page? Does jQuery have a more elegant or magical way of doing it?

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  • What are the Options for Storing Hierarchical Data in a Relational Database?

    - by orangepips
    Good Overviews One more Nested Intervals vs. Adjacency List comparison: the best comparison of Adjacency List, Materialized Path, Nested Set and Nested Interval I've found. Models for hierarchical data: slides with good explanations of tradeoffs and example usage Representing hierarchies in MySQL: very good overview of Nested Set in particular Hierarchical data in RDBMSs: most comprehensive and well organized set of links I've seen, but not much in the way on explanation Options Ones I am aware of and general features: Adjacency List: Columns: ID, ParentID Easy to implement. Cheap node moves, inserts, and deletes. Expensive to find level (can store as a computed column), ancestry & descendants (Bridge Hierarchy combined with level column can solve), path (Lineage Column can solve). Use Common Table Expressions in those databases that support them to traverse. Nested Set (a.k.a Modified Preorder Tree Traversal) First described by Joe Celko - covered in depth in his book Trees and Hierarchies in SQL for Smarties Columns: Left, Right Cheap level, ancestry, descendants Compared to Adjacency List, moves, inserts, deletes more expensive. Requires a specific sort order (e.g. created). So sorting all descendants in a different order requires additional work. Nested Intervals Combination of Nested Sets and Materialized Path where left/right columns are floating point decimals instead of integers and encode the path information. Bridge Table (a.k.a. Closure Table: some good ideas about how to use triggers for maintaining this approach) Columns: ancestor, descendant Stands apart from table it describes. Can include some nodes in more than one hierarchy. Cheap ancestry and descendants (albeit not in what order) For complete knowledge of a hierarchy needs to be combined with another option. Flat Table A modification of the Adjacency List that adds a Level and Rank (e.g. ordering) column to each record. Expensive move and delete Cheap ancestry and descendants Good Use: threaded discussion - forums / blog comments Lineage Column (a.k.a. Materialized Path, Path Enumeration) Column: lineage (e.g. /parent/child/grandchild/etc...) Limit to how deep the hierarchy can be. Descendants cheap (e.g. LEFT(lineage, #) = '/enumerated/path') Ancestry tricky (database specific queries) Database Specific Notes MySQL Use session variables for Adjacency List Oracle Use CONNECT BY to traverse Adjacency Lists PostgreSQL ltree datatype for Materialized Path SQL Server General summary 2008 offers HierarchyId data type appears to help with Lineage Column approach and expand the depth that can be represented.

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  • How to redirect to a page using a button tag in html?

    - by Vlad Radulescu
    When I Click a button I want to get redirected to a page. The problem is...if I use the normal sintax , the button works fine, but If I apply some css to id by ussing # and .(classes) ,the button it`s not working any more ?! How can I keep my css and functionality at the same time ?! This is my code: <body> <input id="buttonrain" class="classname" type="button" onClick="window.location.href='rain.html'" value="Rain" /> <!--or <a href="rain.html" id="buttonrain" class="classname">Rain</a> still not working--> </body> CSS FILE html { min-width: 100%; min-height: 100%; } body{ width: 1024px; height:600px; background:white; margin:0px; padding:0px 0px; display:block; overflow:hidden; } .classname { -moz-box-shadow:inset 0px 1px 0px 0px #ffffff; -webkit-box-shadow:inset 0px 1px 0px 0px #ffffff; box-shadow:inset 0px 1px 0px 0px #ffffff; background:-webkit-gradient( linear, left top, left bottom, color-stop(0.05, #f0ea3c), color-stop(1, #dfdfdf) ); background:-moz-linear-gradient( center top, #f0ea3c 5%, #dfdfdf 100% ); filter:progid:DXImageTransform.Microsoft.gradient(startColorstr='#f0ea3c', endColorstr='#dfdfdf'); background-color:#f0ea3c; -moz-border-radius:6px; -webkit-border-radius:6px; border-radius:6px; border:1px solid #dcdcdc; display:inline-block; color:#0f000f; font-family:Verdana; font-size:15px; font-weight:bold; padding:18px 9px; text-decoration:none; text-shadow:1px 1px 0px #ffffff; position:relative; bottom:250px; }.classname:active { position:relative; top:1px; } #buttonrain{ left:80px; }

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  • Javascript string syntax to write SQL

    - by sebastien leblanc
    I am writing an SQL query as a Javascript string like that: SQLdetail = 'SELECT [Avis SAP], Avis.[Ordre SAP], [Date Appel], [Heur Appel], Client_List![Code Client], [Numero Passerelle], [Designation Appel], Ordre![Metier], Ordre!Repercussion, Ordre!Objet, Ordre![Profil Panne], Ordre!Cause, Ordre![Sommaire Correctif], Ordre![Statut]' SQLdetail += ' FROM (Avis' SQLdetail += ' LEFT JOIN Client_List ON Avis.[Numero Client] = Client_List.[Numero Client])' SQLdetail += ' LEFT JOIN Ordre ON Avis.[Ordre SAP] = Ordre.[Ordre SAP] WHERE Avis.[Date Appel] BETWEEN #' & DateOne & '# AND #' & DateTwo & '#;' alert('SQLdetail:' + SQLdetail) and the last SQLdetail += somehow returns "0". Am I missing something in the syntax that just turns the whole string to a 0?

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