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  • Reading a series of input / output in Python

    - by PulpFiction
    Hello everyone. For my app, I need to print out a series of outputs and then accepts inputs from the user. What would be the best way of doing this? Like: print '1' x = raw_input() print '2' y = raw_input() Something like this, but it would go on for at least 10 times. My only concern with doing the above is that it would make up for poor code readability. How should I do it? Should I create a function like this: def printOut(string): print string Or is there a better way?

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  • MySQLDB query not returning all rows

    - by RBK
    I am trying to do a simple fetch using MySQLDB in Python. I have 2 tables(Accounts & Products). I have to look up Accounts table, get acc_id from it & query the Products table using it. The Products tables has more than 10 rows. But when I run this code it randomly returns between 0 & 6 rows each time I run it. Here's the code snippet: # Set up connection con = mdb.connect('db.xxxxx.com', 'user', 'password', 'mydb') # Create cursor cur = con.cursor() # Execute query cur.execute("SELECT acc_id FROM Accounts WHERE ext_acc = '%s'" % account_num ) # account_num is alpha-numberic and is got from preceding part of the program # A tuple is returned, so get the 0th item from it acc_id = cur.fetchone()[0] print "account_id = ", acc_id # Close the cursor - I was not sure if I can reuse it cur.close() # Reopen the cursor cur = con.cursor() # Second query cur.execute("SELECT * FROM Products WHERE account_id = %d" % acc_id) keys = cur.fetchall() print cur.rowcount # This prints incorrect row count for key in keys: # Does not print all rows. Tried to directly print keys instead of iterating - same result :( print key # Closing the cursor & connection cur.close() con.close() The weird part is, I tried to step through the code using a debugger(PyDev on Eclipse) and it correctly gets all rows(both the value stored in the variable 'keys' as well as console output are correct). I am sure my DB has correct data since I ran the same SQL on MySQL console & got the correct result. Just to be sure I was not improperly closing the connection, I tried using with con instead of manually closing the connection and it's the same result. I did RTFM but I couldn't find much in it to help me with this issue. Where am I going wrong? Thank you. EDIT: I noticed another weird thing now. In the line cur.execute("SELECT * FROM Products WHERE account_id = %d" % acc_id), I hard-coded the acc_id value, i.e made it cur.execute("SELECT * FROM Products WHERE account_id = %d" % 322) and it returns all rows

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  • PHP object help -> unexpected T_OBJECT_OPERATOR

    - by php-b-grader
    Please help me understand: print gettype(new CustomerObject()) prints: "object" (so it is an object) BUT print gettype((new CustomerObject())->get_customer()); prints: unexpected T_OBJECT_OPERATOR If I do it over two lines it works fine $object = new Customer($order->customer_id); print gettype($object); prints: object $customer = $object->get_customer(); print gettype($customer); prints: array It appears that the lines cannot be joined into a single call. Is this correct? and what is the logic behind that?

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  • How can I use Awk inside a Perl script?

    - by papoyan
    I'm having trouble using the following code inside my Perl script, any advise is really appreciated, how to correct the syntax? # If I execute in bash, it's working just fine bash$ whois google.com | egrep "\w+([._-]\w)*@\w+([._-]\w)*\.\w{2,4}" |awk ' {for (i=1;i<=NF;i++) {if ( $i ~ /[[:alpha:]]@[[:alpha:]]/ ) { print $i}}}'|head -n1 [email protected] #----------------------------------- #but this doesn't work bash$ ./email.pl google.com awk: {for (i=1;i<=NF;i++) {if ( ~ /[[:alpha:]]@[[:alpha:]]/ ) { print }}} awk: ^ syntax error # Here is my script bash$ cat email.pl ####\#!/usr/bin/perl $input = lc shift @ARGV; $host = $input; my $email = `whois $host | egrep "\w+([._-]\w)*@\w+([._-]\w)*\.\w{2,4}" |awk ' {for (i=1;i<=NF;i++) {if ( $i ~ /[[:alpha:]]@[[:alpha:]]/ ) { print $i}}}'|head -1`; print my $email; bash$

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  • Concatenate, sort and swap array in Java

    - by sblck
    I am trying to concatenate two arrays into new array, sort in order, and swap two values of index. I'm kind of new to java and only use C before so having a hard time handling an Object. In main method it declares two object arrays IntVector vector = new IntVector(3); and IntVector vector2 = new IntVector(3); I can only do this if the types are int[], but I want to use as an object How should I code the concat, sort, and swap method? public class IntVector { private int[] items_; private int itemCount_; private IntVector(int[] data, int n) { items_ = data.clone(); itemCount_ = n; } public IntVector(int itemSize) { itemCount_ =0; if(itemSize<1) itemSize =10; items_ = new int[itemSize]; } public void push(int value) { if(itemCount_ + 1 >= items_.length) overflow(); items_[itemCount_++] = value; } public void log() { for (int i=0 ; i<itemCount_; ++i) { System.out.print(items_[i]); if(i<itemCount_ -1) System.out.println(); } } public void overflow() { int[] newItems = new int[items_.length * 2]; for(int i=0 ; i<itemCount_; ++i) { newItems[i] = items_[i]; } items_=newItems; } public int getValue(int index) { if(index < 0 || index >= itemCount_) { System.out.println("[error][IntVector][setValue] Incorrect index=" + index); return 0; } return items_[index]; } public void setValue(int index, int value) { if(index < 0 || index >= itemCount_) { System.out.println("[error][IntVector][setValue] Incorrect index=" + index); return ; } items_[index] = value; } public IntVector clone() { return new IntVector(items_, itemCount_); } public IntVector concat() { return null; } public IntVector sort() { return null; } public IntVector swap() { return null; } public static void main(String[] args) { IntVector vector = new IntVector(3); IntVector vector2 = new IntVector(3); vector.push(8); vector.push(200); vector.push(3); vector.push(41); IntVector cloneVector = vector.clone(); vector2.push(110); vector2.push(12); vector2.push(7); vector2.push(141); vector2.push(-32); IntVector concatResult = vector.concat(vector2); IntVector sortResult = concatResult.sort(); IntVector swapResult = sortResult.clone(); //swapResult.swap(1,5); System.out.print("vector : "); vector.log(); System.out.print("\n\ncloneVector : "); cloneVector.log(); System.out.print("\n\nvector2 : "); vector2.log(); System.out.print("\n\nconcatvector : "); concatResult.log(); System.out.print("vector : "); vector.log(); System.out.print("vector : "); vector.log(); } }

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  • Updating GeForce 9200 driver on Vista (64-bit) yields installer failed

    - by weka
    OK, so I have a Windows Vista... more specifically this: http://www.newegg.com/Product/Product.aspx?Item=N82E16883103182 a Acer Aspire AX3200-U3600A Desktop. I have DirectX 11 and I am trying to update my drivers... During the update of the latest one: GeForce 306.23 Driver my screen flashes a bit and goes black. This is standard when updating GRAPHIC DRIVERS. Then... my screen shifts 50 pixels or so to the left... OFFSCREEN. Not even Auto Image Adjust will fix the screen back... Then after that happens, I get this: Help, please? I just want to update my graphic drivers....

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  • How to get audio driver for compaq c700 ?

    - by Leena
    Hi, Initially i have audio driver and its works fine.But some times speaker was clear.So one of my friend installed some audio driver,after that totally disabled the volume. For that reason, i also tried to get audio driver and installed many times.Now i don't know many drivers .inf in my laptop.from device manager i have deleted the audio driver's,below i have attached the screen shot yours kind reference. Please help me to get audio drivers.First, i need to remove the unwanted drivers .inf files from laptop then i have to install the new audio driver. Experts,please suggest me to get audio driver without reinstall the OS. Details: Compaq c700 (i don't know model number) windows xp sp2 p/n : KT188PA#ACJ I appreciate your help.

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  • OnClientClick event for keeping track of prints?

    - by Ram
    Hello, I am trying to keep track of prints that are made for a page. The page has Print this page link. And the code for it is like below: This is written in .cs file as there are many conditions for displaying this. And i am appending here using String Builder. sbOutput.AppendFormat("<td align=\"right\" valign=\"bottom\"><div style =\"float:right;text-align:right; valign:bottom;width:200px\"class=\"print_button notPrinted\"><a class=\"notPrinted\" href=\"#\" onclick=\"window.print();\">PRINT THIS COUPON </a><img src=\"images/print-icon-34x34.gif\" class=\"notPrinted\" align=\"absmiddle\" /></div> </td></tr></table>", couponid, Userid, locationid); Do i have to use onclientclick or something else?? Thanks so much in advance.

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  • Error compiling basic java code

    - by Michael Younani
    New to java. Practicing coding by following a book. Heres my code: class Motorcycle { //Three instance variables - make and color are strings. while a boolean refers to TRUE OR FLASE(in this case off or on) String make; String color; boolean engineState; void startEngine() { if (engineState == true) System.out.print("The engine is already on."); else { engineState = true; System.out.print("The engine is now on."); } void showAtts() { System.out.print("This motorcycle is a " + color + " " + make); if (engineState ==true) System.out.print("The engine is on."); else System.out.print("The engine is off."); } } } When I compile I get 2 errors: 1) illegal start of expression 2) ; expected I can't pin point the problem. If anyone can direct me or hint me please do.

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  • Windows 8 freezes on startup when intel VT-d is enabled

    - by John Nevermore
    I don't know what to make of this situation: Windows 8 freezes after about 3 seconds after booting to the log in screen. The only way i have been able to avoid the freeze, is if i set VT-d disabled VT-d enabled, but Nvidia drivers uninstalled (running on integrated graphics) VT-d enabled, Nvidia drivers installed, Hyper-V feature enabled My goal is to get Windows 8 running with VMWare (ie. Hyper-V has to stay disabled), VT-d and the latest NVidia drivers. Specs: 32 GB of ram Intel Core i7-2760QM NVidia Quadro 1000M Intel 520 SSD 480GB Maybe somebody has experience with this kind of a situation ?

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  • Sleeping a thread blocking stdin

    - by Sid
    Hey, I'm running a function which evaluates commands passed in using stdin and another function which runs a bunch of jobs. I need to make the latter function sleep at regular intervals but that seems to be blocking the stdin. Any advice on how to resolve this would be appreciated. The source code for the functions is def runJobs(comps, jobQueue, numRunning, limit, lock): while len(jobQueue) >= 0: print(len(jobQueue)); if len(jobQueue) > 0: comp, tasks = find_computer(comps, 0); #do something time.sleep(5); def manageStdin(): print "Global Stdin Begins Now" for line in fileinput.input(): try: print(eval(line)); except Exception, e: print e; --Thanks

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  • Find all occurrences of a substring in Python

    - by cru3l
    Python has string.find() and string.rfind() to get the index of a substring in string. I wonder, maybe there is something like string.find_all() which can return all founded indexes (not only first from beginning or first from end)? For example: string = "test test test test" print string.find('test') # 0 print string.rfind('test') # 15 #that's the goal print string.find_all('test') # [0,5,10,15]

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  • Login with Google OAuth api and return url with variable

    - by user2833721
    I am using the Google API for login in my site and I appending my variable with URL and I want that variable in the return URL of OAuth API because of update purpose can I return back that variable For example: <a href="<?php echo($authUrl); ?>&kicker"> I append the kicker in $authUrl and when I return back from Oauth api print $me['displayName']; print $user['email']; print $me['gender']; print $me['id']; with this output I also want my variable "kicker" how can I get it

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  • How to test that variable is not equal to multiple things? Python

    - by M830078h
    This is the piece of code I have: choice = "" while choice != "1" and choice != "2" and choice != "3": choice = raw_input("pick 1, 2 or 3") if choice == "1": print "1 it is!" elif choice == "2": print "2 it is!" elif choice == "3": print "3 it is!" else: print "You should choose 1, 2 or 3" While it works, I feel that it's really clumsy, specifically the while clause. What if I have more acceptable choices? Is there a better way to make the clause?

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  • Python lxml - returns null list

    - by Chris Finlayson
    I cannot figure out what is wrong with the XPATH when trying to extract a value from a webpage table. The method seems correct as I can extract the page title and other attributes, but I cannot extract the third value, it always returns an empty list? from lxml import html import requests test_url = 'SC312226' page = ('https://www.opencompany.co.uk/company/'+test_url) print 'Now searching URL: '+page data = requests.get(page) tree = html.fromstring(data.text) print tree.xpath('//title/text()') # Get page title print tree.xpath('//a/@href') # Get href attribute of all links print tree.xpath('//*[@id="financial"]/table/tbody/tr/td[1]/table/tbody/tr[2]/td[1]/div[2]/text()') Unless i'm missing something, it would appear the XPATH is correct: Chrome screenshot I checked Chrome console, appears ok! So i'm at a loss $x ('//*[@id="financial"]/table/tbody/tr/td[1]/table/tbody/tr[2]/td[1]/div[2]/text()') [ "£432,272" ]

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  • Why is the data I am printing not in a table format

    - by udaya
    Hi This is my program .when i submit the print button i can print the datas but they are not aligned in the table formatthe format in which i need the print to be...How can i print in the correct format <html> <head> <script type="text/javascript" src="http://jqueryjs.googlecode.com/files/jquery-1.3.1.min.js" > </script> <script type="text/javascript"> function PrintElem(elem) { //alert('ddd'); Popup($(elem).text()); } function Popup(data) { var mywindow = window.open('', 'mydiv', 'height=400,width=600'); mywindow.document.write('<html><head><title>my div</title>'); /*optional stylesheet*/ //mywindow.document.write('<link rel="stylesheet" href="main.css" type="text/css" />'); mywindow.document.write('</head><body >'); mywindow.document.write(data); mywindow.document.write('</body></html>'); mywindow.document.close(); mywindow.print(); return true; } </script> </head> <body> <div id="mydiv"> <table width="200" border="1"> <tr> <td>sss</td> <td>sssss;</td> <td>snssbsp;</td> </tr> <tr> <td>ssss;</td> <td>sssnbsp;</td> <td>snbsp;</td> </tr> <tr> <td>snbsp;</td> <td>snbsp;</td> <td>snbsp;</td> </tr> </table> </div> <input type="button" value="Print Div" onClick="PrintElem('#mydiv')" /> </body> </html>

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  • How do I get the key of an item when doing a FOR loop through a dictionary or list in Python?

    - by Mike Hayes
    Hi I am new to Python. Say I have a list: list = ['A','B','C','D'] The key for each item respectively here is 0,1,2,3 - right? Now I am going to loop through it with a for loop... for item in list: print item That's great, I can print out my list. How do I get the key here? For example being able to do: print key print item on each loop? If this isn't possible with a list, where keys are not declared myself, is it possible with a Dictionary? Thanks

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  • Python Continue Loop

    - by Rob B.
    I am using the following code from this tutorial (http://jeriwieringa.com/blog/2012/11/04/beautiful-soup-tutorial-part-1/). from bs4 import BeautifulSoup soup = BeautifulSoup (open("43rd-congress.html")) final_link = soup.p.a final_link.decompose() trs = soup.find_all('tr') for tr in trs: for link in tr.find_all('a'): fulllink = link.get ('href') print fulllink #print in terminal to verify results tds = tr.find_all("td") try: #we are using "try" because the table is not well formatted. This allows the program to continue after encountering an error. names = str(tds[0].get_text()) # This structure isolate the item by its column in the table and converts it into a string. years = str(tds[1].get_text()) positions = str(tds[2].get_text()) parties = str(tds[3].get_text()) states = str(tds[4].get_text()) congress = tds[5].get_text() except: print "bad tr string" continue #This tells the computer to move on to the next item after it encounters an error print names, years, positions, parties, states, congress However, I get an error saying that 'continue' is not properly in the loop on line 27. I am using notepad++ and windows powershell. How do I make this code work?

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  • Format a timestamp into text

    - by user1257114
    I want to get the Modify date of a file and then format it into a human readable date. I am running a C program that gets information on when a particular file was last modified. My C Code contains a sytem cmd which contains a number of egreps, awks, seds separated by pipes. Using sed or awk or something similar, how can I convert 06 to June (This can be any month so an array or something is required) What I am trying to achieve is to end up with a string similar to: My C code contains: char string1[100] = ""; #define MAXCHAR 100 FILE *fp; char str[MAXCHAR], str2[MAXCHAR]; char* filename = "newfile"; /* stat: run 'stat' on the dtlName file to display status information. egrep: search for the pattern 'Modify' and print the lines containing it. awk: Get columns 2 & 3 sed: replace the . with a space, leaving 3 columns of output awk: only print cols 1 & 2 to newfile sed: replace '-' with ' ' in newfile awk: format output in newfile */ sprintf(string1, "/bin/stat %s \ | egrep Modify \ | /bin/awk '{print $2, $3}' \ | /bin/sed 's/\\./ /g' \ | /bin/awk '{print $1, $2}' \ | /bin/sed 's/-/ /g' \ | /bin/awk '{print $3,$2\", \"$1,\"at\",$4}' > newfile" , dtlName); system(string1); fp = fopen(filename, "r"); while (fgets(str, MAXCHAR, fp) != NULL) sprintf(str2,"%s", str); /* Write information to file */ DisplayReportFile (report); ReportEntry (report,L"Source file: %s, Created: %s\n\n",dtlName,str2);

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  • Python server open all ports

    - by user1670178
    I am trying to open all ports using this code, why can I not create a loop to perform this function? http://www.kellbot.com/2010/02/tutorial-writing-a-tcp-server-in-python/ #!/usr/bin/python # This is server.py file ##server.py from socket import * #import the socket library n=1025 while n<1050: ##let's set up some constants HOST = '' #we are the host PORT = n #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data ## now we create a new socket object (serv) ## see the python docs for more information on the socket types/flags serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) ##bind our socket to the address serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow print 'listening...' n=n+1 conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') conn.close() How do I make this work so that I can specify input range and have the server open all ports up to 65535? #!/usr/bin/python # This is server.py file from socket import * #import the socket library startingPort=input("\nPlease enter starting port: ") startingPort=int(startingPort) #print startingPort def connection(): ## let's set up some constants HOST = '' #we are the host PORT = startingPort #arbitrary port not currently in use ADDR = (HOST,PORT) #we need a tuple for the address BUFSIZE = 4096 #reasonably sized buffer for data def socketObject(): ## now we create a new socket object (serv) serv = socket( AF_INET,SOCK_STREAM) def bind(): ## bind our socket to the address serv = socket( AF_INET,SOCK_STREAM) serv.bind((ADDR)) #the double parens are to create a tuple with one element serv.listen(5) #5 is the maximum number of queued connections we'll allow serv = socket( AF_INET,SOCK_STREAM) print 'listening...' def accept(): conn,addr = serv.accept() #accept the connection print '...connected!' conn.send('TEST') def close(): conn.close() ## Main while startingPort<65535: connection() socketObject() bind() accept() startingPort=startingPort+1

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