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  • C: socket connection timeout

    - by The.Anti.9
    I have a simple program to check if a port is open, but I want to shorten the timeout length on the socket connection because the default is far too long. I'm not sure how to do this though. Here's the code: #include <sys/socket.h> #include <sys/time.h> #include <sys/types.h> #include <arpa/inet.h> #include <netinet/in.h> #include <errno.h> #include <fcntl.h> #include <stdio.h> #include <netdb.h> #include <stdlib.h> #include <string.h> #include <unistd.h> int main(int argc, char **argv) { u_short port; /* user specified port number */ char addr[1023]; /* will be a copy of the address entered by u */ struct sockaddr_in address; /* the libc network address data structure */ short int sock = -1; /* file descriptor for the network socket */ if (argc != 3) { fprintf(stderr, "Usage %s <port_num> <address>", argv[0]); return EXIT_FAILURE; } address.sin_addr.s_addr = inet_addr(argv[2]); /* assign the address */ address.sin_port = htons(atoi(argv[2])); /* translate int2port num */ sock = socket(AF_INET, SOCK_STREAM, 0); if (connect(sock,(struct sockaddr *)&address,sizeof(address)) == 0) { printf("%i is open\n", port); } close(sock); return 0; }

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  • iPhone: TabBarController as second level of Navigation Controller

    - by Nebs
    I'm new to iphone development. I've read tutorials about implementing a tab bar controller on the window (eg as the main controller for the app). But how can I create a tab bar controller as a 'standalone' UIViewController that can be called by a navigation bar controller? Basically my navigation bar controller has an array of UIViewControllers that it displays in the table and then loads the appropriate view/controller when a user selects an item. Now I want one of these loaded views/controllers to be a tab bar controller. How can I do this? I'm not sure how to create a tab bar controller on its own without having an outlet/instance in the application delegate. Hope that made sense. Thanks.

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  • How do I splice into a list outside of a macro in Common Lisp?

    - by derefed
    Say I have a function foo: (defun foo (x y &rest args) ...) And I later want to wrap it with a function bar: (defun bar (x &rest args) (foo x 100 args)) Assume bar was then called like this: (bar 50 1 2 3) With this setup, args is a list within the body of bar that holds the trailing parameters, so when I pass it to foo, instead of getting the equivalent of (foo 50 100 1 2 3) I of course get (foo 50 100 '(1 2 3)). If these were macros, I would use `(foo ,x 100 ,@args) within the body of bar to splice args into the function call. ,@ only works inside a backtick-quoted list, however. How can I do this same sort of splicing within a regular function?

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  • When I Add <DIV> Bottom Scroll Bar Appears, Even Though It Is Not Greater Than The Page Width

    - by Clay Dempsey
    I have searched for this with no answer. My page loads up perfectly when I load the header, navigation and then center image...all 3 different divs. However I have more I need to add and the div tags change the size of the page even though the css I'm using isn't larger than the page. I have no idea what is happening. Here's the code page where everything is fine: http://www.thehdmgroup.com/midwaymissionary/test.php When I add the below div tag with the below css I get a bottom scrollbar on the page and I don't know why. Can someone please explain it to me? #middleTextBox1 { position: absolute; top:507px; left:172px; width:180px; height:180px; background-color:#411b42; border: 1px solid #434343; padding:10px; color: #FFFFFF; font-size: 10px; font-family: Arial, Helvetica, sans-serif; } <div id="middleTextBox1"> <h3 align="center">Mission:</h3> Words </div> I really have no idea why this is happening, could someone please help me out? Thanks for your time.

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  • error: polymorphic expression with default arguments

    - by 0__
    This following bugs me: trait Foo[ A ] class Bar[ A ]( set: Set[ Foo[ A ]] = Set.empty ) This yields <console>:8: error: polymorphic expression cannot be instantiated to expected type; found : [A]scala.collection.immutable.Set[A] required: Set[Foo[?]] class Bar[ A ]( set: Set[ Foo[ A ]] = Set.empty ) ^ It is quite annoying that I have to repeat the type parameter in Set.empty. Why does the type inference fail with this default argument? The following works: class Bar[ A ]( set: Set[ Foo[ A ]] = { Set.empty: Set[ Foo[ A ]]}) Please note that this has nothing to do with Set in particular: case class Hallo[ A ]() class Bar[ A ]( hallo: Hallo[ A ] = Hallo.apply ) // nope Strangely not only this works: class Bar[ A ]( hallo: Hallo[ A ] = Hallo.apply[ A ]) ...but also this: class Bar[ A ]( hallo: Hallo[ A ] = Hallo() ) // ???

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  • MySQL - Join as zero if record Not IN

    - by Zurahn
    To explain by example, take two tables, A and B Table A id foo 1 x 2 y 3 z Table B id aid bar 1 3 50 2 1 100 An example join SELECT foo, bar FROM a, b WHERE a.id = b.aid; Garners a result of foo bar z 50 x 100 What I would like to do is get all values of foo and for any instances where there isn't a corresponding bar value, return 0 for that column. My best guess was something along the lines of SELECT foo, bar AS br FROM a, b WHERE a.id = b.aid OR a.id NOT IN (SELECT aid FROM b); But that returns duplicates and non-zero values for bar. Possible?

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  • How to validate an array in a PHP form?

    - by SlAcKeR
    I'm fairly new to php and was wondering how do I validate the array for the states and where do I place the php code at? I already did the address part but I'm stuck at the states part. Here is the validation code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. $address = mysqli_real_escape_string(htmlentities($_POST['address'])); } Here is the form code. <li><label for="address-1">Address 1: </label><input type="text" name="address-1" id="address-1" size="25" class="input-size" value="<?php if (isset($_POST['address'])) echo $_POST['address']; ?>" /></li> <li><label for="state-province">State/Province: </label> <?php echo '<select name="state-province" id="state-province">' . "\n"; foreach($state_options as $option) { if ($option == $state) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li>

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  • PHP5: restrict access to function to certain classes

    - by Tim
    Is there a way in PHP5 to only allow a certain class or set of classes to call a particular function? For example, let's say I have three classes ("Foo", "Bar", and "Baz"), all with similarly-named methods, and I want Bar to be able to call Foo::foo() but deny Baz the ability to make that call: class Foo { static function foo() { print "foo"; } } class Bar { static function bar() { Foo::foo(); print "bar"; } // Should work } class Baz { static function baz() { Foo::foo; print "baz"; } // Should fail } Foo::foo(); // Should also fail There's not necessarily inheritance between Foo, Bar, and Baz, so the use of protected or similar modifiers won't help; however, the methods aren't necessarily static (I made them so here for the simplicity of the example).

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  • CouchDB Lucene How to URL Encode Query containing Minus (-)

    - by Peter
    I'd like to query text containing a minus (-) Sign, e.g. foo-bar with a couchdb lucene fulltext query. Following lucene rules I'd have to escape the minus, resulting in foo\-bar Last I'd have to urlencode the backslash resulting in foo%5C-bar So the complete url would be: http://127.0.0.1:5984/_fti/local/db/_design/foo/by_subject?q=foo%5C-bar Neither works. The result is always split in two phrases "q":"default:foo default:bar" Leading to documents containing only foo or bar being found also. Thanks for your help!

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  • Hot to get rid of memory allocations/deallocations in swig wrappers?

    - by Dmitriy Matveev
    I want to use swig for generation of read-only wrappers for a complex object. The object which I want to wrap will always be existent while I will read it. And also I will only use my wrappers at the time that object is existent, thus I don't need any memory management from SWIG. For following swig interface: %module test %immutable; %inline %{ struct Foo { int a; }; struct Bar { int b; Foo f; }; %} I will have a wrappers which will have a lot of garbage in generated interfaces and do useless work which will reduce performance in my case. Generated java wrapper for Bar class will be like this: public class Bar { private long swigCPtr; protected boolean swigCMemOwn; protected Bar(long cPtr, boolean cMemoryOwn) { swigCMemOwn = cMemoryOwn; swigCPtr = cPtr; } protected static long getCPtr(Bar obj) { return (obj == null) ? 0 : obj.swigCPtr; } protected void finalize() { delete(); } public synchronized void delete() { if (swigCPtr != 0) { if (swigCMemOwn) { swigCMemOwn = false; testJNI.delete_Bar(swigCPtr); } swigCPtr = 0; } } public int getB() { return testJNI.Bar_b_get(swigCPtr, this); } public Foo getF() { return new Foo(testJNI.Bar_f_get(swigCPtr, this), true); } public Bar() { this(testJNI.new_Bar(), true); } } I don't need 'swigCMemOwn' field in my wrapper since it always will be false. All code related to this field will also be useless. There are also unnecessary logic in native code: SWIGEXPORT jlong JNICALL Java_some_testJNI_Bar_1f_1get(JNIEnv *jenv, jclass jcls, jlong jarg1, jobject jarg1_) { jlong jresult = 0 ; struct Bar *arg1 = (struct Bar *) 0 ; Foo result; (void)jenv; (void)jcls; (void)jarg1_; arg1 = *(struct Bar **)&jarg1; result = ((arg1)->f); { Foo * resultptr = (Foo *) malloc(sizeof(Foo)); memmove(resultptr, &result, sizeof(Foo)); *(Foo **)&jresult = resultptr; } return jresult; } I don't need these calls to malloc and memmove. I want to force swig to resolve both of these problems, but don't know how. Is it possible?

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  • Can I use string concatenation to define a class CONST in PHP?

    - by selfsimilar
    I know that you can create global constants in terms of each other using string concatenation: define('FOO', 'foo'); define('BAR', FOO.'bar'); echo BAR; will print 'foobar'. However, I'm getting an error trying to do the same using class constants. class foobar { const foo = 'foo'; const foo2 = self::foo; const bar = self::foo.'bar'; } foo2 is defined without issue, but declaring const bar will error out Parse error: syntax error, unexpected '.', expecting ',' or ';' I've also tried using functions like sprintf() but it doesn't like the left paren any more than the string concatenator '.'. So is there any way to create class constants in terms of each other in anything more than a trivial set case like foo2?

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  • Apache/PHP is determined to serve the wrong file

    - by Lucas
    I have a page that is called with a url like http://testserver/path/to/foo/bar/ but apache is serving the wrong file altogether. /path/to/ is a real directory where all the code and .htaccess file is. foo/bar/ is supposed to redirect to foo_bar.php with a RewriteRule, but it never gets there. It's not a mod_rewrite issue as I have commented out all the rules that could be interfering, which should give me 404s for that request, but the same problem occurs: the file that is served is /path/to/foo.php, so in it I var_dump $_SERVER and get: REQUEST_URI = /path/to/foo/bar/ SCRIPT_NAME = /path/to/foo.php SCRIPT_FILENAME = /real/path/to/foo.php PATH_INFO = /bar/ PATH_TRANSLATED = /real/bar/ PHP_SELF = /path/to/foo.php/bar/ Why is this request being routed to this file at all?

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  • AttributeError in my Python program regarding classes

    - by Axel Finkel
    I'm doing an exercise out of the Python book that involves creating a class and a subclass. I am getting the following error when I try to run the program: AttributeError: 'Customer' object has no attribute 'name', when it tries to go through this bit of code: self.name.append(name) As this is my first time dealing with classes and objects in Python, I'm sure I am making some overt mistake somewhere, but I can't seem to figure it out. I've looked over the documentation for creating classes and writing member functions, and it looks correct, but it is obviously not. I want the Customer subclass to inherit the name, address, and telephone attributes from the Person superclass, but it doesn't seem to be doing so? Here is my code: class Person: def __init__(self): self.name = None self.address = None self.telephone = None def changeName(self, name): self.name.append(name) def changeAddress(self, address): self.address.append(address) def changeTelephone(self, telephone): self.telephone.append(telephone) class Customer(Person): def __init__(self): self.customerNumber = None self.onMailingList = False def changeCustomerNumber(self, customerNumber): self.customerNumber.append(customerNumber) def changeOnMailingList(): if onMailingList == False: onMailingList == True else: onMailingList == False def main(): customer1 = Customer() name = 'Bob Smith' address = '123 Somewhere Road' telephone = '111 222 3333' customerNumber = '12345' customer1.changeName(name) customer1.changeAddress(address) customer1.changeTelephone(telephone) customer1.changeCustomerNumber(customerNumber) print("Customer name: " + customer1.name) print("Customer address: " + customer1.address) print("Customer telephone number: " + customer1.telephone) print("Customer number: " + customer1.customerNumber) print("On mailing list: " + customer1.OnMailingList) customer1.changeOnMailingList() print("On mailing list: " + customer1.OnMailingList) main()

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  • How can I add two models in one form, where one model is a has_many :through?

    - by Angela
    How do I model having multiple Addresses for a Company and assign a single Address to a Contact? Contacts belong_to a Company. A Company has_many Contacts. A Company also has_many Addresses. And each Contact has_one Address. I want to be able, whenever I create a New Contact, to access all the addresses in all Contacts that belong to the Company. Here is are my Models: class Company < ActiveRecord::Base attr_accessible :name, :phone, :addresses has_many :contacts has_many :addresses, :through => :contacts end class Contact < ActiveRecord::Base attr_accessible :first_name, :last_name, :title, :phone, :fax, :email, :company, :date_entered, :campaign_id, :company_name, :address belongs_to :company has_one :address accepts_nested_attributes_for :address end class Address < ActiveRecord::Base attr_accessible :street1 has_many :contacts end How do I create the View in the _form for Contacts so that I can 1) Add an Address when creating a Contact; 2) Display the options of the Address. Here is how I am doing step 1, which is just to add a new address for a new contact: <% f.fields_for :addresses do |builder| %> <p> <%= builder.label :street1, "Street 1" %> </br> <%= builder.text_field :street1 %> <p> Right now, what I have doesn't work. The console says I cannot mass-assign addresses when I hit "submit" on this New contact form.

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  • Does the order of conditions in a WHERE clause affect MySQL performance?

    - by Greg
    Say that I have a long, expensive query, packed with conditions, searching a large number of rows. I also have one particular condition, like a company id, that will limit the number of rows that need to be searched considerably, narrowing it down to dozens from hundreds of thousands. Does make any difference to MySQL performance whether I do this: SELECT * FROM clients WHERE (firstname LIKE :foo OR lastname LIKE :foo OR phone LIKE :foo) AND (firstname LIKE :bar OR lastname LIKE :bar OR phone LIKE :bar) AND company = :ugh or this: SELECT * FROM clients WHERE company = :ugh AND (firstname LIKE :foo OR lastname LIKE :foo OR phone LIKE :foo) AND (firstname LIKE :bar OR lastname LIKE :bar OR phone LIKE :bar)

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  • Inner or Outer left Join

    - by user1557856
    I'm having difficulty modifying a script for this situation and wondering if someone maybe able to help: I have an address table and a phone table both sharing the same column called id_number. So id_number = 2 on both tables refers to the same entity. Address and phone information used to be stored in one table (the address table) but it is now split into address and phone tables since we moved to Oracle 11g. There is a 3rd table called both_ids. This table also has an id_number column in addition to an other_ids column storing SSN and some other ids. Before the table was split into address and phone tables, I had this script: (Written in Sybase) INSERT INTO sometable_3 ( SELECT a.id_number, a.other_id, NVL(a1.addr_type_code,0) home_addr_type_code, NVL(a1.addr_status_code,0) home_addr_status_code, NVL(a1.addr_pref_ind,0) home_addr_pref_ind, NVL(a1.street1,0) home_street1, NVL(a1.street2,0) home_street2, NVL(a1.street3,0) home_street3, NVL(a1.city,0) home_city, NVL(a1.state_code,0) home_state_code, NVL(a1.zipcode,0) home_zipcode, NVL(a1.zip_suffix,0) home_zip_suffix, NVL(a1.telephone_status_code,0) home_phone_status, NVL(a1.area_code,0) home_area_code, NVL(a1.telephone_number,0) home_phone_number, NVL(a1.extension,0) home_phone_extension, NVL(a1.date_modified,'') home_date_modified FROM both_ids a, address a1 WHERE a.id_number = a1.id_number(+) AND a1.addr_type_code = 'H'); Now that we moved to Oracle 11g, the address and phone information are split. How can I modify the above script to generate the same result in Oracle 11g? Do I have to first do INNER JOIN between address and phone tables and then do a LEFT OUTER JOIN to both_ids? I tried the following and it did not work: Insert Into.. select ... FROM a1. address INNER JOIN t.Phone ON a1.id_number = t.id_number LEFT OUTER JOIN both_ids a ON a.id_number = a1.id_number WHERE a1.adrr_type_code = 'H'

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  • Does std::vector change its address? How to avoid

    - by kunigami
    Since vector elements are stored contiguously, I guess it may not have the same address after some push_back's , because the initial allocated space could not suffice. I'm working on a code where I need a reference to an element in a vector, like: int main(){ vector<int> v; v.push_back(1); int *ptr = &v[0]; for(int i=2; i<100; i++) v.push_back(i); cout << *ptr << endl; //? return 0; } But it's not necessarily true that ptr contains a reference to v[0], right? How would be a good way to guarantee it? My first idea would be to use a vector of pointers and dynamic allocation. I'm wondering if there's an easier way to do that? PS.: Actually I'm using a vector of a class instead of int, but I think the issues are the same.

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  • Manipulating Directory Paths in Python

    - by G Ullman
    Basically I've got this current url and this other key that I want to merge into a new url, but there are three different cases. Suppose the current url is localhost:32401/A/B/foo if key is bar then I want to return localhost:32401/A/B/bar if key starts with a slash and is /A/bar then I want to return localhost:32401/A/bar finally if key is its own independent url then I just want to return that key = htt p://foo.com/bar - http://foo.com/bar I assume there is a way to do at least the first two cases without manipulating the strings manually, but nothing jumped out at me immediately in the os.path module.

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  • How to extract the current state of the registry? (in C/C++, XP)

    - by Doori Bar
    I was wondering how one might extract the current state of the registry, of Windows XP, in C or C++? (While the OS is active). I been trying to use BackupRead() on the registry-files, but it is impossible to CreateFile() them. I managed to create a Shadow Copy of the registry-files, but it wasn't the current state of the registry. Would appreciate any hint... (I know ERUNT is able to do it) Thanks, Doori Bar

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  • Are conditional subqueries optimized out, if the condition is false?

    - by Tobias Schulte
    I have a table foo and a table bar, where each foo might have a bar (and a bar might belong to multiple foos). Now I need to select all foos with a bar. My sql looks like this SELECT * FROM foo f WHERE [...] AND ($param IS NULL OR (SELECT ((COUNT(*))>0) FROM bar b WHERE f.bar = b.id)) with $param being replaced at runtime. The question is: Will the subquery be executed even if param is null, or will the dbms optimize the subquery out? We are using mysql, mssql and oracle. Is there a difference between these regarding the above?

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  • How do I center my navigation bar and background?

    - by user2892958
    nav-wrap { background:url(nav-bg-blue.png) no-repeat top center; height:39px; padding-top:3px; } .no-header-page #nav-wrap { background:url(nav-bg-nobanner-blue.png) no-repeat top center; height:43px; padding-top:4px; margin-bottom:30px; } #nav-wrap .container { clear: both; overflow: hidden; position:center; width:100%; } #nav-wrap .container ul { list-style: none; float: center; } #nav-wrap .container ul li { list-style: none; float: left; background:url(nav-right-last.png) no-repeat top right; padding-right:20px; margin-left:-10px; position:auto; } #nav-wrap .container ul span li { background:url(nav-right-last.png) no-repeat top right; } #nav-wrap .container ul li a { float: center; display: block; font-family: 'News Cycle', sans-serif; color: #fff; text-decoration: none; padding: 5px 10px 8px 20px; border: 0; outline: 0; list-style-type: none; font-size: 14px; text-transform:uppercase; letter-spacing:2px; background:url(nav-left-first.png) no-repeat top left; line-height:25px; text-shadow:0 -1px 2px rgba(0,0,0,0.3); } #nav-wrap .container ul li#active, #nav-wrap .container ul li:hover{ background:url(nav-hover-right-last-brown-red.png) no-repeat topright; z-index:1; } #nav-wrap .container ul li:hover a, #nav-wrap .container ul li#active a, #nav-wrap .container ul li a:hover { border: 0; background:url(nav-hover-left-brown-red.png) no-repeat top left; } .wsite-nav-0 { margin-left:0 !important`` }

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  • solution for different tab bars in other screen

    - by haicnpmk44
    Hi Guys I am finding the solution for my application. I create an iphone application have 3 screen: First screen not contain any tab bar. Second screen have 2 tab bar item. Third screen have 3 tab bar item. http://c.upanh.com/upload/7/719/L50.11932623_1_1.jpg If i create a UITabBarController - the tab bar will be appeared from first screen. So I have to hide tab bar in first screen. But second and third screen have different tab bar - not good idea. Do you have solution for this issue, please help me. Thank you !!!

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